Use the diagram shown. Lines p and q are parallel.

Select all the correct measures for ∠1, ∠2,
and ∠3.

Answer:

the value of x is approximately 0.382 cm.

Step-by-step explanation:

The number of toy soldiers Leo has is 48.

To solve this problem, we need to find a number that satisfies the three given conditions:

The number is between 27 and 54.

When the number is divided by 4, there is no remainder.

When the number is divided by 7, the remainder is 6.

When the number is divided by 5, the remainder is 3.

Let's start by finding a number that satisfies the first two conditions. We can do this by listing the multiples of 4 between 27 and 54:

28, 32, 36, 40, 44, 48, 52

Next, we need to find which of these numbers also satisfies the third condition, that is, leaves a remainder of 6 when divided by 7. We can go through each of these numbers and check:

28 divided by 7 leaves a remainder of 0.

32 divided by 7 leaves a remainder of 4.

36 divided by 7 leaves a remainder of 1.

40 divided by 7 leaves a remainder of 5.

44 divided by 7 leaves a remainder of 2.

48 divided by 7 leaves a remainder of 6.

52 divided by 7 leaves a remainder of 3.

So, the only number that satisfies the first three conditions is 48.

Finally, we need to check if 48 also satisfies the fourth condition, that is, leaves a remainder of 3 when divided by 5. Indeed, 48 divided by 5 leaves a remainder of 3.

Therefore, the number of toy soldiers Leo has is 48.

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Answer: 36% passed the science test, while 25% passed the history test.

In order to find a percentage we divide our two know numbers

Science Class- 9/25 is a fraction with / standing for divided by. 9 divided by 25 is .36   This means 36% of the class passed the science test.

History Class- 4/16 is a fraction with / standing for divided by. 4 divided by 16 is .25   This means 25% of the class passed the science test.

I hope this helped & Good Luck <3!!!!

Answer:

Step-by-step explanation:

To find the probability of choosing a random number that starts with 2, we need to find two things:

1. The total number of valid four-digit numbers that can be created from the digits 0-9 where the first and last digits are even and no digit can repeat.

2. The number of valid four-digit numbers that start with 2 and meet the other criteria.

Let's begin by calculating the total number of valid four-digit numbers.

There are 5 even digits (0, 2, 4, 6, 8) to choose from for the first and last digits. For the second digit, there are 9 digits to choose from (since 0 cannot be repeated), for the third digit there are 8 digits to choose from (since we used one digit already and neither the first nor last digit can be repeated), and for the last digit there are only 4 choices left (since we used 5 for the first digit, and one more can’t be repeated). Therefore, the total number of valid four-digit numbers is:

5 * 9 * 8 * 4 = 1,440

Now we need to calculate the number of valid four-digit numbers that start with 2.

We already determined that there are 5 even digits to choose from for the last digit, leaving 8 digits for the second and 7 for the third digit (since the first digit is fixed). So the number of valid four-digit numbers that start with 2 is:

5 * 8 * 7 * 1 = 280

Therefore, the probability of choosing a random number that starts with 2 is:

280 / 1,440 = 0.1944 rounded to 4 decimal places.

So the answer to the problem is 97/500, which simplifies to 0.1940 when rounded to 4 decimal places.

The proportion of students who can roll their tongues will be estimated and the margin of error for a 95 percent confidence interval for the true proportion of tongue rollers among students will be determined. There were 317 tongue rollers out of a sample of 400 students.

      As a result, the sample proportion is 317/400 = 0.7925.

      We'll compute the margin of error next. The margin of error (E) for a 95 percent confidence interval is:

                E = zα/2 * sqrt[p(1 - p) / n]

                              where zα/2 is the z-score that corresponds to the level of confidence α/2, p is the sample proportion, and n is the sample size.

               E = 1.96 * sqrt[0.7925 * (1 - 0.7925) / 400]E

                  = 1.96 * sqrt[0.7925 * 0.2075 / 400]E

                  = 1.96 * sqrt(0.00040875)E

                  = 1.96 * 0.0202E

                  = 0.0395

    The margin of error is approximately 0.04 or 4 percent. Hence, the correct option is 0.04.

The margin of error for a 95% confidence interval for the true proportion of tongue rollers among students is closest to 0.04

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Answer:

Step-by-step explanation:

kernel composition rules 2 1 point possible (graded) let and be two vectors of the same dimension. use the the definition of kernels and the kernel composition rules from the video above to decide which of the following are kernels. (note that you can use feature vectors that are not polynomial.) (choose all those apply. )

Answer:

D

Step-by-step explanation:

sub y into the 2nd equation and find x

Answer:

Step-by-step explanation:

number of eggs in 2 boxes = 12

Total number of eggs = 20 x 6 = 120

12:120

Simplify

2:20

Simplify

1:10

pls mark me brainiest

The number of times the experiment is run affects the experimental probability.

Probability is the concept that describes the likelihood of an event occurring.

In real life, we frequently have to make predictions about how things will turn out.

We may be aware of the result of an occurrence or not.

When this occurs, we state that there is a possibility that the event will occur.

In general, probability has many excellent applications in games, commerce, and this newly growing area of artificial intelligence

The chance of an event can be calculated using the probability formula by only dividing the favourable number of possibilities by the total number of potential outcomes.

According to our question-

multiply that percentage by 25 to get the experimental probability percentage.

16%25

Hence, The number of times the experiment is run affects the experimental probability.

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Answer:

25 computers per hour

Step-by-step explanation:

look ate the point 2 hours corresponding to 50 computers

50/2 = 25/1 or 25 computers per hour

The total amount of paint Aubrey used is more than 1/2 liter but less than 1 liter

To estimate the total amount of paint that Aubrey used for both the mural and the wall, we can add the fractions of paint used

So, we have

Total = 4/7 + 2/10

Evaluate the sum in decimals

This gives

Total = 0.77 (approximated)

This value is between 0.5 liters and 1 liter

Hence, the estimate is between 0.5 liters and 1 liter

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Complete question

Aubrey used 4/7 liter of paint for a mural in her room and 2/10 for a wall in her bathroom.

Determine a reasonable estimate for the total amount of paint Aubrey used

Answer: B or the one that is more than 1/2 but it is less than 1

Step-by-step explanation: Took quiz on khan

So,To prove that △STU∼△WVU, we need to show that the two triangles are similar, which means that their corresponding angles are equal, and their corresponding sides are proportional.

A polygon with three sides and three angles is termed as triangle.

Triangles can be classified based on the length of their sides and the size of their angles, and they have a variety of properties and theorems associated with them in mathematics.

Angles: Since line VS is the bisecting line on line WT, angles VST and TSU are equal. Similarly, angles UVW and WVU are equal since U is the bisecting point on the line. Therefore, angle VUS is equal to angle WUV since they are vertically opposite angles.

Sides: We need to show that the corresponding sides are proportional.

Using the angle bisector theorem, we know that US/UT = VS/VT, which can be written as:

9/6 = VS/VT

Simplifying this, we get:

3/2 = VS/VT

Using the segment bisector theorem, we know that UW/WV = UT/TV, which can be written as:

6/4 = UT/TV

Simplifying this, we get:

3/2 = UT/TV

Since both ratios are equal to 3/2, we can say that:

VS/VT = UW/WV

Therefore, we can conclude that △STU∼△WVU by the angle-angle similarity theorem.

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Lin's statement is correct. The incorrect answer is obtained due to inaccurate calculations of the new area of triangle.

A geometric modification called a dilation alters a figure's size. Each coordinate in the graphic is multiplied by a preset scale factor k to obtain it. The same element causes the figure to be stretched or contracted in all directions, creating a new figure that resembles the original but is smaller. Both two-dimensional (2D) and three-dimensional (3D) dilations are possible (3D). They are frequently employed in geometry to generate analogous figures and compute scale factors.

Mai's statement is incorrect. When a triangle is dilated by a factor of k, its area is multiplied by k².

When the given area of 100 square inches is dilated by a factor of 0.25 the new area is 6.25.

Hence, Lin's statement is correct. The incorrect answer is obtained due to inaccurate calculations of the new area.

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Answer:

The perimeter of the shape is 53km.

Answer : 53km

Step-by-step explanation: To find the perimeter you need to add all the sides so 8+18+18+9=53 and dont forget the unit km! Have a great day! And good luck!

Total number of seats that remain unsold are 168.

What is statistics?

The branch of mathematics dealing with data collection, organization, analysis, interpretation and presentation.

Let's start by defining some variables to represent the unknowns in the problem:

From the problem, we know that:

We also know that the total revenue collected is $34,650:

27x + 45y = 34650

Now we can substitute y = 0.5x from the second equation into the third equation and simplify:

27x + 45(0.5x) = 34650

27x + 22.5x = 34650

49.5x = 34650

x = 700

So there were 700 $30-seats and 350 $50-seats.

The number of sold $30-seats is 0.9(30x) = 567, and the number of sold $50-seats is 0.9(50y) = 315.

Therefore, the total number of seats sold is 882, and the number of unsold seats is:

1050 - 882 = 168

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Answer:

b = [tex]\frac{S-2la}{h+l}[/tex]

Step-by-step explanation:

S = bh + lb + 2la ( reversing the equation )

bh + lb + 2la = S ( subtract 2la from both sides )

bh + lb = S - 2la ← factor out b from each term on the left side

b(h + l) = S - 2la ← divide both sides by (h + l)

b = [tex]\frac{S-2la}{h+l}[/tex]

According to the solving  function f could describe the bacteria population d days after the scientists first measured it, assuming it grows exponentially F(d) = 10000 - a[tex]^\frac{d}{5}[/tex].

A mathematical expression, rule, or law known as a function defines the relationship between two independent variables and a dependent variable (the dependent variable). In mathematics, functions are often utilised, and they are essential for creating physical connections in the sciences.

Substituting d = 5 and f(d)

Solution: fid) = 10000⋅ ad

{substitute d=5 and fid)=20000 into fid=10000. ady

10000- a⁵ =20000

a⁵ =2[tex]^\frac{1}{5}[/tex]

a = 2

F(d) = 10000 - a[tex]^\frac{d}{5}[/tex]

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Answer:

Step-by-step explanation:

only the 1st and 5th statements are true

Answer:

The solution set is (13,− 32). A quadratic equation of the form x 2= k can be solved by factoring with the following sequence of equivalent equations.

Step-by-step explanation:

Answer:

D) $28,224.00

Step-by-step explanation:

1st hour: 480 ticket sales

2nd hour: 480 + 40% of 480 = 480 + 0.4 × 480 = 480 + 192 = 672

Total ticket sales in first 2 hours: 480 + 672 = 1152

Ticket price: $24.50

Total sales: 1152 × $24.50 = $28,224

Step-by-step explanation:

You are given miles ( 546) and gallons (14)  and you

   want miles / gal     this is just     546 miles / 14 gallons  = 39  mpg

Answer:

39

Step-by-step explanation:

14 is the main number here.

assuming 1 tank = 14gallons. / 546 miles

a = gallons

b = miles

b / a = mpg (miles per gallon)

so: 546 / 14 = 39

The upper bound for the rate at which the water could have flowed into lake is 8.2 liters per second.

An upper limit is a value that is larger than or equal to all the values in a set. In mathematics, it is used to specify a cap or a maximum value for a collection of data. For instance, an upper bound is frequently employed in optimization issues to place a cap on the highest value that a function or variable may take. Upper limits are used in statistics to specify a data set's maximum range which may be used to spot outliers or other abnormalities in the data. In calculus, upper bounds are used to specify a sequence's or series' limit, or the highest number that it may possibly approach.

Given that, 400 liters of water flowed into the lake in 1 minute.

The upper bound of water flow will be the maximum amount of water.

For the nearest measures taken by Grace the amount of water needs to ne more than 400, while the time must be less than 10 seconds from the recorded 1 min.

That is time must be 60 - 10 = 50 seconds.

Approximating the values we have:

410/50 = 8.2 liters per second.

Hence, the upper bound for the rate at which the water could have flowed into lake is 8.2 liters per second.

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The null hypothesis is that the average speed of motorists on a highway with a speed limit of 55 mph is equal to 55 mph.Given statement is false.

A statistical hypothesis test is a technique for determining whether the available data are adequate to support a specific hypothesis. We can make probabilistic claims about demographic parameters through hypothesis testing.

The null hypothesis should be a statement of no difference or no effect. In this case, the null hypothesis would be that the average speed of motorists on the highway is equal to 55 mph.

So the correct statement would be:

The null hypothesis is that the average speed of motorists on a highway with a speed limit of 55 mph is equal to 55 mph.

Thus, Given statement is false.

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The height of water in the tank in feet after t seconds can be expressed as h(t) = H - (Aw/Ah) 2gh t2, where Aw and Ah are the cross-sectional areas of the water and the hole in square feet respectively,

and g is the gravitational acceleration (32 ft/s2). The interval of definition for h(t) is 0 ≤ t ≤ H/2gh.

The graph of h(t) is a parabola with its vertex at (H/2gh, H) and is symmetric about the line t = H/2gh. It starts at (0, H) and gradually decreases to (H/2gh, 0).

Given the tank is 11 ft high, has radius 2 ft and the circular hole has radius in, and it is initially full, the time it will take to empty can be calculated as: t = √(2H/gAh) = √(22/(32 x π(0.52))) = 3.87 seconds. Therefore, it will take approximately 3.87 seconds to empty.

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Answer:

can you give me the answer to this question sin y minus cos (y + 20), sin theta minus cos theta equals to 0 cos theta equals to sin theta - 10​

Step-by-step explanation:

To solve sin y - cos (y + 20) = 0, we can rearrange it as sin y = cos (y + 20).

Then, we can use the identity sin (90 - x) = cos x to rewrite the right side as cos (y + 20) = sin (70 - y).

Substituting this into the equation, we get sin y = sin (70 - y).

Now, there are two possibilities:

y = 70 - y, which gives y = 35 degrees.

y = 180 - (70 - y), which gives y = 105 degrees.

To solve cos theta = sin theta - 10, we can rearrange it as cos theta - sin theta = -10 and then use the identity cos (x - 90) = sin x to rewrite it as -sin (theta - 90) = -10.

Taking the inverse sine of both

Answer: 10.2 cm

Step-by-step explanation:

We can use the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.

Let's call the unknown length of the other leg "x". Then we can set up the following equation:

4^2 + x^2 = 11^2

Simplifying this equation, we get:

16 + x^2 = 121

Subtracting 16 from both sides, we get:

x^2 = 105

Taking the square root of both sides, we get:

x = sqrt(105)

x ≈ 10.2 cm (rounded to the nearest tenth)

Therefore, the measure of the other leg is approximately 10.2 cm.

a) The relative risk of having satisfied the university mathematics requirement for sophomores as compared to freshmen is 2.222.

b) The increased risk of having satisfied the university mathematics requirement for sophomores as compared to freshmen is 122.2%.

Relative Risk is defined as the ratio of the risk of an event in the exposed group and the risk of the event in the unexposed group. The formula for relative risk is

RR = [a / (a + b)] / [c / (c + d)].

where, a = the number of individuals in the exposed group with the event,

b = the number of individuals in the exposed group without the event,

c = the number of individuals in the unexposed group with the event, and

d = the number of individuals in the unexposed group without the event.

Now, in this question, we have to calculate the relative risk and the increased risk for sophomores as compared to freshmen.

Given that,

Sample size of freshman = 100

Number of freshman who have satisfied the mathematics requirement = 9

Sample size of sophomores = 50

Number of sophomores who have satisfied the mathematics requirement = 10

a = 10, b = 40, c = 9, and d = 91

Relative risk for sophomores as compared to freshmen = (10 / (10 + 40)) / (9 / (9 + 91)) = 2.222

Therefore, the relative risk of having satisfied the university mathematics requirement for sophomores as compared to freshmen is 2.222.

Increased risk = (RR - 1) × 100% = (2.222 - 1) × 100% = 122.2%

Therefore, the increased risk of having satisfied the university mathematics requirement for sophomores as compared to freshmen is 122.2%.

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Answer:

Step-by-step explanation:

Let P be the point C with position vector 2i + 3j and Q be the point D with position vector 7i + 5j. We want to find the position vector of point H which divides PQ in the ratio 2:3.

Let the position vector of point H be r. Then we have:

PH/PQ = 2/3

(P - r)/(Q - r) = 2/3

Multiplying both sides by (Q - r), we get:

P - r = (2/3)(Q - r)

Expanding the brackets and rearranging, we get:

r = (2Q + 3P)/5

Substituting the position vectors of P and Q, we get:

r = (2(7i + 5j) + 3(2i + 3j))/5

= (14i + 10j + 6i + 9j)/5

= (20i + 19j)/5

= 4i + 3.8j

Therefore, the position vector of point H is 4i + 3.8j.

D: "[tex]c_{1} = 10[/tex] and [tex]c_{2} = 2[/tex]" are programmer-defined constants for quadratic probing that cannot be used in a quadratic probing equation. Option D is correct answer.

The quadratic probing equation is defined as:

h (k, i) = (h′(k) + [tex]c_{1}[/tex] * i + [tex]c_{2}[/tex] * i^2) mod m,

where h′(k) is the hash value of key

k and m is the size of the hash table.

The constants [tex]c_{1}[/tex] and [tex]c_{2}[/tex] are programmer-defined constants that are used to compute the new hash index when a collision occurs in the hash table.

The given hash function is h(k) = k % 10.

Therefore, the hash value of any key will be between `0` and `9`.Now, let's check which of the given programmer-defined constants for quadratic probing cannot be used in a quadratic probing equation:

Option A: `c1 = 1 and c2 = 0`This option can be used in the quadratic probing equation. It means that linear probing is being used.

Option B: [tex]c_1 = 5[/tex] and [tex]c_2 = 1[/tex] This option can be used in the quadratic probing equation. It means that the new index is being computed as `h(k, i) = (h′(k) + 5i + i^2) mod m`.

Option C: [tex]c_1 = 1[/tex] and [tex]c_2 = 5[/tex] This option can be used in the quadratic probing equation. It means that the new index is being computed as `h(k, i) = (h′(k) + i + 5i^2) mod m`.

Option D: [tex]c_1 = 10[/tex] and [tex]c_2 = 2[/tex] This option cannot be used in the quadratic probing equation. It means that the new index is being computed as `h(k, i) = (h′(k) + 10i + 2i^2) mod m`.

Since [tex]c_{1}[/tex] is greater than or equal to `m`, this equation will always result in a hash index that is greater than or equal to `m`. Therefore, it is not possible to use `[tex]c_{1}[/tex]= 10` in the quadratic probing equation. Hence, the correct option is D.

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Most correlational studies use d)relative data, which compares two variables.

This means that one variable is being measured against another, often in the form of ratios or percentages. For example, one might compare the number of people who smoke cigarettes with the number of people who develop lung cancer, in order to determine whether there is a correlation between the two.

Relative data allows researchers to examine the relationship between variables, allowing them to assess the strength of the relationship between them.

In order to compare variables, correlational studies rely on either primary or secondary data. Primary data is collected through direct observation and experimentation, while secondary data is obtained from existing sources.

In most cases, correlational studies use secondary data, such as survey results or statistics from public databases. This data is often in the form of relative data, such as percentages or ratios.

By using relative data, correlational studies can determine the strength of the relationship between two variables. This information can be used to better understand how the variables are related, as well as to draw conclusions about their relationship. For example, the relationship between smoking and lung cancer can be examined using relative data, allowing researchers to identify patterns and draw conclusions about the correlation between the two variables.

Hence Option D is correct.

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