Using only -vc,where v is the galaxy's speed and c is the speed of light, then this would imply that the speed of the galaxy is agalaxy's redshift is z-1.3, the wavelength of the light Trom an absorption line in the galaxy's spectrum has O increased by a factor of 0.3 O decreased by a factor of 2.3 O increased by a factor of 100. O increased by a factor of 2.3 O O O O zero; the galaxy is not moving. 1.3 times the speed of light. 0.77 times the speed of light. 2.3 times the speed of light. What is the best explanation for a galaxy having a redshift with this value? O O O O The galaxy is moving faster than the speed of light away from the Milky Way. The galaxy is moving faster than the speed of light toward the Milky Way. The expansion of the Universe causes light from the galaxy to change in wavelength. The light escaping from the galaxy is redshifted by the galaxy's gravitational field.

a metaphor for generosity and joy and joy and joy and joy organised a large wedding guests had to choose their meal from beef chicken tikka and a kind young women in the streets of St

The number of excess electrons needed to be distributed uniformly in the sphere to produce the given electric field is 1.69*10^(10).

What is an electric field?

The electric force exerted on a unit charge is called the electric field.

For a sphere of uniform charge density, the magnitude of the electric field on its surface is given by,

E=k*q/r^2

where E is the magnitude of the electric field, k is the coulomb's constant which has a value of 9*10^9 N m^(2) C^(-2), and q is the total charge of the sphere, and r is the radius of the sphere.

The radius of the sphere is half of the diameter. Given the diameter of the sphere is 26.0 m, the radius of the sphere r=26.0/2 cm or r=13.0 cm.

It is given that E=1440 N/C, r=13.0 cm, and the value of k is 9*10^9 N m^(2) C^(-2). Substitute these values in the formula of the electric field and solve it to get the value of the total charge on the sphere.

Note: 1 cm = 0.01 m.

1440 (N/C)= (9*10^9 N m^(2) C^(-2))*q/( 13 cm)^2

1440 (N/C)= (9*10^9 N m^(2) C^(-2))*q/( 13*0.01 m)^2

1440 ( N/C)= (532.54*10^(9) N C^(-2))*q

q=1440/(532.54*10^(9)) C

q=2.704*10^(-9) C

Since the charge is quantized, the total charge inside the sphere is the integral multiple of an elementary charge. In the given case, the value of that elementary charge is 1.6*10^(-19) C. The total charge is then given by,

q=ne

where q is the total charge, n is the number of elementary charges and e is the value of the elementary charge.

The value of q is 2.704*10^(-9) C and the value of e is 1.6*10^(-19) C.

Substitute these values in the formula of total charge and solve it to get the number of elementary charges.

2.704*10^(-9) C =n*1.6*10^(-19) C

n=2.704*10^(-9)/ 1.6*10^(-19)

n=1.69*10^(10)

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Answer: Interstellar dust is effective at blocking visible light because dust grains are so small.

Explanation: To find the answer, we need to know more about the interstellar dust.

Thus, we can conclude that, Interstellar dust is effective at blocking visible light because dust grains are so small.

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Relation can you state about the acceleration of the charge and it mass is they are inversely proportional .

According to the question

Newton's second law :

Newton's second law is a quantitative description of the changes that a force can produce on the motion of a body. It states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it.

F = m * a

a = [tex]\frac{F}{m}[/tex]  

Relation can you state about the acceleration of the charge and it mass is

According to Newton's second law of motion, acceleration is inversely proportional to the mass when the force is a constant.

The acceleration is directly proportional to the force when the mass remains constant.

Hence, Relation can you state about the acceleration of the charge and it mass is they are inversely proportional .

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Answer:

Mass is a base unit, acceleration is a derived unit calculated as a function of length and time which are both base units. Any unit definition that is a function of more basic units is considered a derived unit.

An astronomer that discovers a new star and wants to measure its temperature would typically do this by means of a blackbody curve to find the maximum wavelength.

The maximum wavelength peak is the portion of the wave where a given chemical substance/object exhibits its maximum strongest value of photon absorption.

On the other hand, the blackbody curve of an object is the graphical diagram that shows the distribution of the radiation emitted by this particular substance.

In conclusion, An astronomer that discovers a new star and wants to measure its temperature would typically do this by means of a blackbody curve to find the maximum wavelength.

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Time for which box will remain in contact with spring is 1.1 sec

Given:

mass of box = 8 kg

initial speed of box = 1.5 m/s

spring constant = 69 N/m

To Find:

time for which box will remain in contact with spring

Solution: The time taken to complete one oscillation is called the time period. where m is the mass, and k is the spring constant.

Time period is given as

t = π √m/k

t = 3.14 √8/69

t = 1.1 sec

So time for which box will remain in contact with spring is 1.1 sec

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The buoyant force acting on the block is 58.8 N.

The dimensions of the block are given as 0.10 m, 0.20 m and 0.30 m.

The volume of the block will be = 0.10 × 0.20 × 0.30 m³

                                                     = 0.006 m³

We know that,

W = mg                                 .....(1)

where,

W = weight of the block

m = mass of the block

g = acceleration due to gravity = 9.8 m/s²

We also know that mass is proportional to density and volume

m = ρ.V                                  .....(2)

Substituting the equation (2) in (1)

W = ρ.V.g                               .....(3)

Density of water, ρ = 1000 kg/m³

Force is the net weight acting on the block

F = W = ρ.V.g

F = 1000 × 0.006 × 9.8

F = 58.8 N

Therefore, the buoyant force acting on the block is 58.8 N.

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True statements that reflect why infants experience more fluid and electrolyte changes are that dehydration can upset the  balance of electrolytes in an infant or child and the newborn is at risk of excessive water loss and hypernatremia as the result of high evaporative water loss through the skin.

As infants are not used to the environment around , they are more sensible towards problems such as Dehydration because of fast metabolism.

Dehydration can upset the  balance of electrolytes in an infant or child. Children are especially vulnerable to dehydration due to their small size and fast metabolism, which causes them to replace water and electrolytes at a faster rate than adults.

Infants are particularly prone to the effects of dehydration because of their greater baseline fluid requirements (due to a higher metabolic rate), higher evaporative losses (due to a higher ratio of surface area to volume), and inability to communicate thirst or seek fluid.

The newborn is at risk of excessive water loss and hypernatremia as the result of high evaporative water loss through the skin, insensible water loss (IWL), as well as decreased capacity to concentrate the urine.

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3, 1, 2, 4 is the arrangement according to their comet's tail.

The length of a comet's tail depends primarily on the comet's distance from the sun. It is longer when the comet is closer to the sun and shorter or (Negligible) when the comet is farther from the sun.

Due to sunlight's radiation pressure, the comet's tail will always point away from the sun. Small dust particles are pushed away from the sun by sunlight with a stronger force than by gravity pulling them in the opposite direction. As a result, a comet's tail streams behind the nucleus during its inbound transit, but it streams in front of the nucleus during its outbound passage back to the outer solar system. Typically, gas jets produced by thawing frozen volatiles expel dust particles from a comet's surface.

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Answer:

The quadriceps consists of four muscles: the skinny rectus femoris and the three huge “vasti” — vastus lateralis/intermedius/medialis. The vasti are only elongated by knee flexion, which is limited to about 120˚ when the calf hits the hamstrings. The vasti cannot be stretched strongly.

Answer:Masseter and temporalis

Why it’s unstretchable: The jaw can only open so far.

Why it’s a dang shame: Jaw tension is epidemic, and trigger points in these muscles cause a wide array of strange face and head pains, including toothaches, headaches, and earaches.

Answer:

4P + 502 → 2P205

Explanation:

Hence the above equation is balanced.

Explanation:

[tex] \underline{ \underline{ \large{ \text{Given \: chemical \: equation}}}} : [/tex]

Here , Multiply P2O5 by 2 and O2 by 5 to equalize oxygen :

[tex] \tt{P+ 5O_{2} \: \: ➞\: \: 2P_{2} \:O_{5}}[/tex]

Now , To equalize P atoms , Multiply P by 4

[tex] \boxed{ \large{\tt{ 4P + 5O _{2} \: ➞ \: \: \: \: 2P_{2} \: O_{5}}}}[/tex]

Here , On the left side we have 4P and On the right side ,we have 4P. Again , On the left side , we have 10 O and On the right side , we have 10 O. And yippie , we got the balanced chemical equation !!!

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Walt and Mary are my Customers at this point.

To construct proper client relationships you need to: greet clients and approach them in a way that is herbal and suits the character scenario. show customers that you recognize what their desires are. be given that a few humans may not want your merchandise and concentrate on constructing relationships with people who do.

Use the time period clients, with an apostrophe before the “s” to expose a possessive form for a single consumer. Use the time period clients', with an apostrophe after the “s” to show the possessive plural shape of a couple of patrons. Do now not use an apostrophe if there's no possessive indication needed.

The definition of a consumer is a person who buys services or products from a store, restaurant, or different retail vendor. An example of a patron is someone who is going to an electronics save and buys a tv. (Casual) a person, mainly one engaging in a few types of interaction with others.

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188m - 556m is the wavelength range for AM radio.

2.77 - 3.40m is the wavelength range for FM radio.

1) For AM radio

f(max) = 1600 × 10³ Hz

f(min) = 540 ×10³Hz

c = fλ

λ = c/f where,

c = speed of light

f = frequency

λ= wavelength

So,

λ(min) = 3 × [tex]10^{8}[/tex] / 1600 × 10³ = 188 m

λ(max) = 3 × 10⁸/540 ×10³ = 556 m

So wavelength range of AM radio is 188 m - 556m

2) For FM radio

f(max) = 108 × 10⁶ Hz

f(min) = 88 × 10⁶ Hz

λ(min)  = 3 × 10⁸ / 108 × 10⁶ = 2.77 m

λ(max) = 3 × 10⁸ / 88 × 10⁶ = 3.40 m

So wavelength range of FM radio is 2.77m - 3.40m

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Latitude of the line will be = 1436.033

Departure of the line will be   = 28.152

Given

let line be = a = 1436. 32

azimuthal be = x = 178° 52' 13''

This line must have two components , one is horizontal component which is its latitude and other will be vertical component which is departure . Resolving both the components we get,

latitude = a*cos(178° 52' 13'')

             = 1436. 32 * cos(178° 52' 13'')

             = 1436. 32 * (- 0.9998)                              

latitude = 1436.033

departure  =  a * sin (178° 52' 13'')

                  = 1436. 32  *  0.0197

  departure  = 28.152

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My day is alright! I just finished school for the day.. and I’m excited for the weekend! How was your day?

Answer:

A: 2.8 * 10^(-14) J

Explanation:

Formula to find the energy is;

E = hc/λ

Where;

E is energy of a photon (E)

λ is wavelength of the light

c is speed of light

Thus;

E = (1.99 *10^(-25))/(7 * 10^(-12))

E = 2.8 * 10^(-14) J

[tex]\displaystyle F_n = 9.8 \ N[/tex]

Math

Pre-Algebra

Order of Operations: BPEMDAS

Physics

Forces

SI Unit: Newtons N

Free Body Diagrams

Gravitational Force: [tex]\displaystyle F_g = mg[/tex]

Normal Force: [tex]\displaystyle F_n[/tex]

Newton's Law of Motions

Step 1: Define

1 kg book at rest

Step 2: FBD

See Attachment

Draw a free body diagram to label the forces acting upon the book. We see that we would have gravitational force from Earth pointing downwards and normal force from the surface of the desk pointing upwards.

Since the book is not moving, we know that ∑F = 0 (sum of forces equal to 0).

Step 4: Find Normal Force

Answer:

Highest.

Explanation:

This is because, in a state of unstable equilibrium, the center of gravity is at highest which as a result of when the body topples at it's base, there is a shift in the centre of gravity, and the centre of gravity shift position by moving towards the lower position and it does not return to it's former position again.

Answer:

+ 140

Explanation:

You can show the natural growth rate by subtracting the death rate from the birth rate during one year and converting this into a percentage.

Here it would be:

240 - 100 = + 140

// if you want to convert it to percentage, you need to know the size of the population

it would be

140 / (population size) * 100 %

// s - displacement, t - time, v - velocity

Known:

s = 542 meters;

v = 10m/s

Unknown:

t - ?

Formula:

t = s / v

Solution:

t = 542 / 10 = 54,2 (s)

Answer:

54,2 s

Make me the brainliest, please

Answer:

The heating element of the heater is made up of alloy which has very high resistance so when current flows through the heating element, it becomes too hot and glows red. But the resistance of cord which is usually of copper or aluminum is very low so it does not glow.

Answer:modeled as an electromagnetic wave. In this model, a changing electric field creates a changing magnetic field.

Explanation:

She is going at a velocity of 20.63m/s to the bottom.

Friction is a resistive force between a body and the surface it is moving over in mechanics. It is computed mathematically using the friction coefficient and normal force product.

The mass is:  m = 65kg

The coefficient of friction is:  μk = 0.107

The angle is:  θ = 37.2°

W = mg

W₁ = W sin θ = mg sin θ

W = W cos θ = mg cos θ

[tex]F_{N} = W = mgcos[/tex]θ

[tex]F_{f} =[/tex] µ[tex]F_{N}[/tex] = µmg cosθ

[tex]F_{net} = W_{1} - F_{f}[/tex]

       [tex]= mg sin[/tex]θ - µmg cosθ

[tex]F_{net} = ma[/tex]

[tex]ma =[/tex] mg sinθ - µmg cosθ

a = g sinθ - µmg cosθ

  = 9.8 sin (37.2) - (0.107) 9.8 cos(37.2)

  = 9.8 × 0.605 - 0.107 × 9.8 × 0.796

  = 5.929 - 0.834

  = 5.095 [tex]m^2/s[/tex]

∴ Δd = [tex]\frac{1}{2} a ([/tex][tex]t^2[/tex][tex])[/tex]

  [tex]t^2[/tex] = 2Δd / a

  [tex]t^2=[/tex] 2 × 42.0 / 5.095

  [tex]t^2 =[/tex] 16.48

  [tex]t=4.05[/tex]

∴ [tex]v_{2} = v_{1} + at[/tex]

      [tex]= 0+ 5.095 (4.05)[/tex]

      [tex]= 20.63 m/s[/tex]

Therefore, she is going at a velocity of  20.63m/s to the bottom.

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The wavelength of the ultrasound wave in 20 °c air is 1.715 * 10⁻⁵ m.

The frequency of sound is the number of complete oscillations per second.

The wavelength is the distance between successive positions in the wave.

Velocity of sound is the distance covered per second.

The frequency and wavelength of a wave are related by the formula given below:

The velocity of sound in 20°C air = 343 m/s

frequency of the sound wave = 2.00 × 10⁷ hz or 2.00 × 10⁷ s⁻¹

wavelength = velocity/frequency

wavelength = 343 /  2.00 × 10⁷

wavelength = 1.715 * 10⁻⁵ m

In conclusion, the wavelength of the ultrasound wave is determined from the ratio of the velocity and the frequency of the sound.

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Dirt that you can not burn typically does no longer have any materials that are flammable at decrease temperatures. Mostly due to the fact it is full of water and non-burnable minerals. But a lot of what's in grime can certainly burn if it is dried. Dirt is made of many unique things.

yes

Explanation:

since they are extremely dense they lack the ability to trap air due to its structure

==================================================

Work Shown:

We have these variables

Solving for the mass gets us...

p = m*v

25 = m*2.5

25/2.5 = m

10 = m

m = 10

The mass of the horse is 10 kg.

The chief factor that determines what type of electromagnetic radiation that objects give off in the absence of a strong magnetic field is their temperature.

The radioactive activity refers to the energy that a atomic nucleus can release in a given period of time due to the emission of different types of radiation.

This activity (radioactive activity) increases as temperature rises due to a higher collision of subatomic particles that form molecules.

In conclusion, the chief factor that determines what type of electromagnetic radiation in the absence of a magnetic field is temperature.

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The magnitude is 5.69 × 10^4  N/C and the direction is  opposite to the acceleration of electron.

Equation of force on a charge is -

                F = ma

→             qE = ma

The acceleration of an electron is 1.201016 m/s².

→         E =  ma/q

  plug in the values

          E = 9.11 × 10^-31 kg × 1×10^16 m/s² i / -1.6 × 10^-19 C

          E = 5.69 × 10^4  N/C   (-i)

so, magnitude is 5.69 × 10^4  N/C  and field is along negative x-axis

Thus, it has opposite direction to the acceleration of electron.

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I know most of the answers will say infinity, but still this needs deeper look about its physical meaning and does it consider a practical logic?

Infinity usually used for something we could not measure, however the reality may be different!

The denominator of the equation would become 0 and the mass would become infinite if the mass's velocity ever surpassed the speed of light.

The amount of energy needed to accelerate an infinite mass would be infinite as well. The fact that light travels at the speed of c indicates that it has no rest mass.

When a mass particle approaches the speed of light, its energy grows and becomes infinite at that speed, which is why it can never be accelerated to that speed.

Experiments have confirmed this, and it has been demonstrated that nothing goes faster than the speed of light.

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A radar receiver indicates that a pulse return as an echo in 20 μs after it was sent. The reflecting object would be 3000 m away .

Phenomenon of hearing back our own sound is called an echo. It is due to successive reflection of sound waves from the surfaces or obstacles of large size. To hear an echo, there must be a time gap of 0.1 second in original sound and the reflected sound.

Given

time =  20 μs = 20 * [tex]10^{-6}[/tex] s

let distance to the reflecting surface be = x

total distance travelled by pulse will be  = 2x

speed = 3.0 × [tex]10^{8}[/tex] m/s

distance = speed * time

2x = 3.0 × [tex]10^{8}[/tex] * 20 * [tex]10^{-6}[/tex]

   x = 3000 m

The reflecting object would be 3000 m away

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