Using the figure below, identify the sum of the angles. Then identify the measurement of the missing angles.

The steps in Mia's method were smaller than in Jenna's, which was an advantage.

The same result will be obtained by adding the products of multiplying the sum of two or more addends by a number as opposed to multiplying each addend separately by the number.

The direct algorithm process suggested in this paper is known as the direct calculation method (DCM), and it can deal with using confinement loss as an incremental step to simulate the effect of moving tunnel face excavation, calculating the stresses and displacements in each step, and drawing the results.

Jenna's technique:

[tex]\begin{aligned}&5(30+4) \\&=(5)(30)+(5)(4) \\&=150+20 \\&=170\end{aligned}[/tex]

Mia's technique:

[tex]\begin{aligned}&5(30+4) \\&=(5)(34) \\&=170\end{aligned}[/tex]

Both used the right approach, albeit in different ways.

One uses the distributive property, whereas the other uses direct calculation.

Consequently, Jenna and Mia came to the same conclusion.

However, Mia's approach has one advantage over Jenna's: it requires fewer steps.

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Answer:

x=-2, 2

Step-by-step explanation:

Aighty check this out

[tex]f(x) = \frac{ {x}^{2} + 3x + 6 }{ {x}^{2} - 4 } = = = > \\(x + 2)(x - 2) \\ so \: x = - 2 \: and \: x = 2 \: are \: not \: defined \: \\ and \: are \: the \: candidates [/tex]

if non of the root give out 0/0 both can be the asymptotes:

[tex]f(2) = \frac{{2}^{2} + 3(2) + 6 }{ { - 2}^{2} + 4 } = = = > \\ f(2) = \frac{16}{0} [/tex]

this one is OK

[tex]f( - 2) = \frac{ { - 2}^{2} + 3( - 2) + 6}{ { - 2}^{2} + 4 } = = = > \\ f( - 2) = \frac{4}{0} [/tex]

so is this one

so the asymptotes are x=-2, 2

The median number of computers owned by the 17 students is 2.

A dataset's median represents the midpoint; half of the data points are smaller and half are greater than the median.

Identifying the median: The data points should be arranged from smallest to largest. The median is the middle data point in the list if the number of data points is odd.

The total number of students are 17.

The data can be arranged in the following table

number of students        number of computers

             6                                         1

             3                                         2

             3                                         3

             2                                         4

             3                                         5

Arrange the given frequencies in the increasing order-

1 1 1 1 1 1 2 2 2 3 3 3 4 4 5 5 5

The middle term of the arrange frequencies is 17/2 = 8.5

Median = (8 term + 9 term)/2

            = (2 + 2)/2

            = 2

Therefore, the median number of computers owned by the 17 students is 2.

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The correct question is -

Of the 17 students in a programming class, 6 own 1 computer, 3 own 2 computers, 3 own 3 computers, 2 own 4

computers, and 3 own 5 computers. What is the median number of computers owned by the 17 students?

Answer:

C

Step-by-step explanation:

using the addition formula for sine

sin(A + B) = sinAcosB + cosAsinB

note that [tex]\frac{7\pi }{12}[/tex] = [tex]\frac{\pi }{3}[/tex] + [tex]\frac{\pi }{4}[/tex] , then

sin [tex]\frac{7\pi }{12}[/tex]

= sin([tex]\frac{\pi }{3}[/tex] + [tex]\frac{\pi }{4}[/tex] )

= sin[tex]\frac{\pi }{3}[/tex]cos[tex]\frac{\pi }{4}[/tex] + cos[tex]\frac{\pi }{3}[/tex]sin[tex]\frac{\pi }{4}[/tex]

= ( [tex]\frac{\sqrt{3} }{2}[/tex] × [tex]\frac{\sqrt{2} }{2}[/tex] ) + ([tex]\frac{1}{2}[/tex] × [tex]\frac{\sqrt{2} }{2}[/tex] )

= [tex]\frac{\sqrt{6} }{4}[/tex] + [tex]\frac{\sqrt{2} }{4}[/tex]

= [tex]\frac{\sqrt{2}+\sqrt{6} }{4}[/tex]

Using a trigonometric identity, the cosine of the angle is given as follows:

[tex]\cos{\theta} = \frac{60}{61}[/tex]

It is given by:

[tex]\sin^2{\theta} + \cos^2{\theta} = 1[/tex]

In this problem, the sine is:

[tex]\sin{\theta} = \frac{11}{61}[/tex]

Then:

[tex]\cos^2{\theta} = 1 - \sin^2{\theta}[/tex]

[tex]\cos^2{\theta} = 1 - \left(\frac{11}{61}\right)^2[/tex]

[tex]\cos^2{\theta} = \frac{3600}{3721}[/tex]

[tex]\cos{\theta} = \pm \sqrt{\frac{3600}{3721}}[/tex]

On quadrant I, the cosine is positive, hence:

[tex]\cos{\theta} = \frac{60}{61}[/tex]

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Answer: 10

Step-by-step explanation:

If [tex]-5 < x < 5[/tex], then [tex]|x-5|=5-x[/tex] and [tex]|x+5|=x+5[/tex].

So, the expression is equal to 10.

Answer:

48

Step-by-step explanation:

So I attached an image explaining how I solved the problem, but essentially you use the Pythagorean Theorem to define the two other sides, which I named "a" and "b", and then defined them in terms of x, using the Pythagorean Theorem. I finally defined the hypotenuse of the entire triangle which is 36+64 in terms of these two equations. Once that entire thing was set up it was a matter of solving for x, to get 48

Answer:

127°

Step-by-step explanation:

180°-53°=127°

Angle on a straight line is equal to 180°

Answer:160ft^3

Step-by-step explanation:

Volume=(bh/2)h

V=(5ftx8ft/2)8ft

V=20x8=160

Volume=160ft^3

HOPE YOU GET IT RIGHT:)!

Answer:

0.4 pages per minute

Step-by-step explanation:

40/100 = .4

Answer:

y =2

Step-by-step explanation:

Substitute -10 for x:

2(-10)-9y = -38

-20-9y = -38

-9y = -18

9y = 18

y = 2

Mark and Don have 18  and 92 marbles respectively.

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side. It demonstrates the equality of the relationship between the expressions printed on the left and right sides. We have LHS = RHS (left hand side = right hand side) in every mathematical equation. To determine the value of an unknown variable that represents an unknown quantity, equations can be solved.

Let the number of marbles Mark has be x.

According to the question,

Don has (5x+2) marbles.

Total number of marbles=110

Thus, the required equation is:

x+5x+2=110

6x=108

x=108/6

x=18

Mark has 18 marbles.

Don has (5*18+2)=92 marbles.

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Answer:

yes

no

yes

Step-by-step explanation:

sin C = opp/hyp = 9/15 yes

tan B = opp/adj = 12/9 no

tan B = 12/9; B = tan^-1 12/9 = 53.13°

The area of the circle is 78.5 unit square.

A circle is a closed, two-dimensional object where every point in the plane is equally spaced from a central point.

The line of reflection symmetry is formed by all lines that traverse the circle. Additionally, every angle has rotational symmetry around the centre.

The formula for area of circle is;

Area = [tex]\pi[/tex](radius)²

The distance between the two points are calculated by distance formula.

[tex]\begin{aligned}&d=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}} \\&d=\text { distance } \\&\left(x_{1}, y_{1}\right)=\text { coordinates of the first point } \\&\left(x_{2}, y_{2}\right)=\text { coordinates of the second point }\end{aligned}[/tex]

Calculation for the area of the circle;

As, the radius of the circle is xy.

The distance between x and y points will be calculated by the distance formula.

x=(0,3)  y=(-3,-1)

[tex]\begin{aligned}&d=\sqrt{\left(-3-0\right)^{2}+\left(-1-3\right)^{2}} \\\end{aligned}[/tex]

[tex]\begin{aligned}&d=\sqrt{\left(-3\right)^{2}+\left(-4\right)^{2}} \\\end{aligned}[/tex]

[tex]\begin{aligned}&d=\sqrt{25} \\\end{aligned}[/tex]

[tex]d=5[/tex]

As, distance between x and y point is 5 units which is the radius of the circle.

Area of circle = [tex]\pi[/tex](radius)²

                      = 3.14×(5)²

                      = 78.5

Therefore, the area of the circle is 78.5 unit square.

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The value of sample size n in this statement according to a confidence interval is 350.

According to the statement

we have a given that the value of error and population proportion and we have to find the value of sample size.

So, we know that the

confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Here

p represent the real population proportion of interest

ρ represent the estimated proportion for the sample

n is the sample size required (variable of interest)

z represent the critical value for the margin of error

So, The population proportion have the following distribution  

P≈n ( p, ([p (1-p)]/n)^1/2)

Here In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by  α = 1 - 0.95 = 0.05

and α/2 = 0.025 And the critical value would be given by:  

z = 1.96

And on this case we have that ME = ±0.05 and we are interested in order to find the value of n, if we solve n from equation (a) we got the value

n = 0.35(1-0.35) / (0.05/1.96)^2

so, the value becomes

n = 350.

So, The value of sample size n in this statement is 350.

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Question:

In a survey, the planning value for the population proportion is p* = 0.35. How large a sample should be taken to provide a 95% confidence interval with a margin of error of 0.05?

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Nani could purchase her pineapple from stores A, D, and E.

Given Information

It is given that Nani needs to purchase  8 cups of pineapple.

The unit prices of pineapple at each store is as follows,

Store A : 0.49

Store B : 0.51

Store C : 0.55

Store D : 0.48

Store E : 0.45

Amount that Nani has = $4

Reason Behind Purchasing From Either A, D, or E

Since Nani has amount of $4, she can purchase pineapple only from the stores where the total cost of 8 pineapple cups adds up to less than $4. The purchase of 8 pineapple cups at each store would be given as,

Store A : 0.49(8) = $3.92

Store B : 0.51(8) = $4.08

Store C : 0.55(8) = $4.40

Store D : 0.48(8) = $3.84

Store E : 0.45(8) = $3.60

As it can be seen, Nani can purchase from the store A, D, and E as it falls within her budget of $4.

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The solutions to the given system of equations are x = 6 and y = -5

From the question, we are to solve the given system of equations

The given system of equation is

4x+5y=-1

-5x-8y=10

Multiply the first equation by 5 and the second equation by 4

5× (4x+5y=-1)

4× (-5x-8y=10)

20x + 25y = -5

-20x - 32y = 40

------------------------

0x + (-7y) = 35

-7y = 35

y = 35/-7

y = -5

Substitute the value of y into the first equation to find x

4x + 5y = -1

4x + 5(-5) = -1

4x -25 = -1

4x = -1 +25

4x = 24

x = 24/4

x = 6

Hence, the solutions to the given system of equations are x = 6 and y = -5

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Answer:

Federal tax

Step-by-step explanation:

It is used for tax returns, given out by federal govt

Answer:

C. federal Tax.

Step-by-step explanation:

/     \

/      \

Let the missing number x

So, ATQ

[tex] \frac{3}{14} \times x = 6[/tex]

[tex] \frac{14}{3} \times \frac{3}{14} x = 6 \times \frac{14}{3} [/tex]

[tex] \frac{1}{3} \times 3x = \frac{14}{3} \times 6[/tex]

[tex]x = \frac{14}{3} \times 6[/tex]

[tex]x = 14 \times 2[/tex]

[tex]x = 28[/tex]

Therefore, 3/14 of 28 is 6...

Answer:

28

Step-by-step explanation:

Let the number we are looking for = [tex]x[/tex]

∴ [tex]\frac{3}{14}[/tex] of [tex]x[/tex] is 6

⇒  [tex]\frac{3}{14}[/tex]   ×  [tex]x = 6[/tex]

• Divide both sides of equation by  [tex]\frac{3}{14}[/tex] :

⇒  [tex]x = 6 \div \frac{3}{14}[/tex]

⇒ [tex]x = 28[/tex]

∴ The missing part is 28.

Pedro can sell enough by combining the sales of 40 plates of garlic shrimp and 80 dishes of spicy shrimp to reach his objective.

Near the shore, Pedro runs a shrimp delivery business.

He offers spicy shrimp for $6 a plate and garlic shrimp for $8 per plate.

Pedro wants to make at least $800 per day but only stocks enough shrimp to sell a maximum of 120 plates.

We need to ascertain,

Which dish combining hot shrimp and garlicky shrimp can Pedro sell to reach his objective?

In response to the query,

Let's sell the x dishes of garlic shrimp.

And plates of hot shrimp were sold.

Pedro has 120 dishes' worth of shrimp in stock each day.

Then,

Shrimp sold daily total is equal to the sum of plates of garlic shrimp and spicy shrimp.

                           X + Y = 120

Furthermore, He offers $6spicy and $8garlic shrimp, per plate.

To make at least $800 is what he wants to do.

Then,

the sum of the price of the spicy shrimp per plate and the price of the garlic shrimp per plate,

                             8X + 6Y = 800

When the two equations are solved,

                              X + Y = 120

                           8X + 6Y = 800

From equation 1,

                             Y = 120 - X

In equation 2, replace x with its value.

8X + 6Y = 800

8(120 - Y) + 6Y = 800

960 - 8Y + 6Y = 800

- 2Y = - 160

Y = 160/2

Y = 80

In equation 1, replace y with its value.

X + Y = 120

X + 80 = 120

X = 120 - 80

X = 40

In order to achieve his objective, Pedro sold a combination of 40 plates of garlic shrimp and 80 dishes of spicy shrimp.

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Answer:

Step-by-step explanation:

Make equations

8x+6y≥800

x+y≤120

Graph the system of equations and see which answer falls in the shaded area

Answer: 90 Garlic, 25 Spicy

The probability that the number of tested rafts that develop cracks is no more than 3 is .00006.

The true proportion, p for the population is given to 0.12.

Thus, the mean, μ, for the sample = np = 27*0.12 = 3.24.

The sample size, n, given to us is 27.

Thus, the standard deviation, s, for the sample can be calculated using the formula, s = √{p(1 - p)}/n.

s = √{0.12(1 - 0.12)}/27 = √0.003911 = 0.0625389.

We are asked to calculate the probability that the number of tested rafts that develop cracks is no more than 3, that is, we need to calculate P(X ≤3).

P(X ≤ 3)

= P(Z ≤ {(3 - 3.24)/0.0625389) {Using the formula z = (x - μ)/s}

= P(Z ≤ -3.8376114706)

= .00006 {From table}.

Thus, the probability that the number of tested rafts that develop cracks is no more than 3 is .00006.

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Part 1: Correct.

Part 2

[tex]\sqrt{(-52)^2 + 48^2} \approx 70.77[/tex]

In quadrant IV, [tex]\sin(A)[/tex] is negative. So

[tex]\sin^2(A) + \cos^2(A) = 1 \implies \sin(A) = -\sqrt{1-\cos^2(A)} = -\dfrac35 = \boxed{-0.6000}[/tex]

Answer:

Let the number be a.

==: a + (5x³-2x²+3x+7) = (7x³+7x-5)

==: a = (7x³+7x-5) - (5x³-2x²+3x+7)

==: a = 7x³ + 7x - 5 - 5x³+ 2x² - 3x - 7

==: a = 2x³ + 2x² + 4x - 12

i guess this is the process if you don't understand i can explain more

Answer:

a(b+c) = a into b + a*c

So, 79(457+35) = 79*457 + 79*35

Step-by-step explanation:

The total amount of money Levi spent on renting movie and buying candy is $5.75

Total = Amount Levi rented movie + A package of candy

= $3.20 + $2.55

= $5.75

Therefore, the total money spent by Levi is $5.75

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Answer:

B. 4^15*5^10

Step-by-step explanation:

First you can take the out-out-outside exponent and "pass it out" to both the numerator and the denominator. When you have a power raised to a power, you MULTIPLY the exponents. See image.

Next you can "fix" a negative exponent by pushing it across the fraction bar. As it passes across the fraction bar, the exponent changes sign. So the -10 exponent on the bottom, becomes a positive 10 exponent on top. See image.

Answer: The answer is D

Step-by-step explanation:

Due to length restrictions, we cannot summarize the results of the three parts about the quadratic equations of the form x² + b · x + c = 0. We kindly invite to check the explanation for further details.

In this question we have several exercises with quadratic equations of the form x² + b · x + c = 0 and, to be more exactly, quadratic equations with the following characteristics:

x² - (r₁ + r₂) · x + r₁ · r₂ = 0      (1)

Please notice that the first grade coefficient is equal to the inverse of the sum of the two roots and the zero grade coefficient is the product of the two coefficients.

Now we proceed to resolve all the points:

Part I

a) (x + 17) · (x + 1) = x² + 18 · x + 18, r₁ = - 17, r₂ = - 1

b) (x + 5) · (x + 4) = x² + 9 · x + 20, r₁ = - 5, r₂ = - 4

c) (x - 11) · (x - 1) = x² - 12 · x + 11, r₁ = 11, r₂ = 1

d) (x - 18) · (x - 2) = x² - 20 · x + 36, r₁ = 18, r₂ = 2

Part II

a) x² - 12 · x + 27

b) (x + 4) · (x + 8)

c) (x - 5) · (x - 7)

d) (x - 4) · (x - 5)

Part III

a) (x - 18) · (x + 3) = x² - 15 · x - 54

b) (x + 18) · (x + 3) = x² + 21 · x + 54

c) (x + 18) · (x - 3) = x² + 15 · x - 54

d) (x - 18) · (x - 3) = x² - 21 · x + 54

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