What are exercises to strengthen the upper body?

Answers

Answer 1

Answer:

Banded Lat Stretch. The range of motion in the shoulders is directly connected to how well the muscles of the upper back allow them to move.

Banded Pull Aparts.

Banded Pass Through.

Pull Ups

Push Ups

Step-by-step explanation:

Answer 2

Some exercises to strengthen the upper body include:

1. Chest Press.

2. Bench Dip.

3. Bicep Curl.

4. Pull Ups.

5. Push Ups.

6. Arm Raise


Related Questions

A line intersepts the point (3,-4) and has a slope of 17 . What is the slope-intersept equation for this line?

Answers

Answer:

y=17x-55

Step-by-step explanation:

y-(-4)=17(x-3)

y+4=17x-51

y=17x-55

what is the standard form of the equation? y=(x+2)^2-3

Answers

Y= -x -2

2-3 is -1 and when it’s in parentheses it makes it negative

Answer:

Find the asymptotes.

Vertical Asymptotes:

x

=

2

Horizontal Asymptotes:

y

=

0

No Oblique Asymptotes

what is the result ​

Answers

Answer:

(3)     [tex]  \dfrac{P_1V_1}{V_2} [/tex]

Step-by-step explanation:

[tex] P_1V_1 = P_2V_2 [/tex]

Divide both sides by V2.

[tex] \dfrac{P_1V_1}{V_2} = P_2 [/tex]

[tex]P_2 =\dfrac{P_1V_1}{V_2}[/tex]

How do i solve 4x+3=35?

(I really appreciate everyones help )

Answers

Answer:

x=8

Step-by-step explanation:

1. Subtract the 3 from both side so the new equation states 4x=32

2. Divide both sides by 4 for the final answer of x=8

Answer:

That is the answer.

Step-by-step explanation:

l hope it helps ❤❤❤

-2.49 = -5 + x
please solve for x ;)

Answers

It’s 0.498 just divide -2.49 and -5

Answer:

x=2.51

Step-by-step explanation:

-2.49=-5+x

-5+x=-2.49

-5+x+5=-2.49+5

x=2.51

Becky is writing a coordinate proof to show that the diagonals of a parallelogram bisect each other. She starts by assigning coordinates as given.

A parallelogram graphed on a coordinate plane. The parallelogram is labeled A B C D. The coordinates of vertex A are 0 comma 0. The coordinates of vertex B a comma 0. The coordinates of vertex C are not labeled. The coordinates of vertex D are b comma c. Diagonals A C and B D intersect at point E whose coordinates are not labeled.

Drag and drop the correct answer into each box to complete the proof.

The coordinates of point C are (Response area, c).

The coordinates of the midpoint of diagonal AC¯¯¯¯¯ are ​(a+b2, c2)​ .

The coordinates of the midpoint of diagonal BD¯¯¯¯¯ are (Response area, c2).

AC¯¯¯¯¯ and BD¯¯¯¯¯ intersect at point E with coordinates (a+b2,Response area)..

By the definition of midpoint, AE¯¯¯¯¯≅Response area and Response area≅DE¯¯¯¯¯.

Therefore, diagonals AC¯¯¯¯¯ and BD¯¯¯¯¯ bisect each other.

Give actual answer will give brainliest

Answers

Answer:

Read Under

Step-by-step explanation:

Just did the quiz. First one is "a + b"

Second spot put "a+b/2"

Third put "c/2"

Finally put "CE" and then "BE"

A parallelogram is a quadrilateral , In which opposite sided are equal and parallel to each other.

The coordinate of point C are (a + b , c)

The coordinates of the midpoint of diagonal BD are [tex](\frac{a+b}{2},\frac{c}{2} )[/tex]

AC and BD intersect at point E with coordinates [tex](\frac{a+b}{2},\frac{c}{2} )[/tex]

By the definition of midpoint, AE ≅ CE  and BE ≅ DE.

Therefore, diagonals AC and BD bisect each other.

Properties of Parallelogram shown below,

Opposites sides of a parallelogram are equal and parallel to each other. Opposite angles are equal.Diagonals of a parallelogram bisect each other.    Each diagonal divides the parallelogram into two congruent triangles.

Since, Diagonals of a parallelogram bisect each other. Therefore, point E is the mid point of both diagonal AC and BD.

Let us consider , coordinate of point C are (x, y)

By using mid point formula,

                Coordinate of point E =  [tex](\frac{x}{2},\frac{y}{2} )[/tex]

                        [tex](\frac{a+b}{2},\frac{c}{2} )=(\frac{x}{2},\frac{y}{2} )[/tex]

  So,     [tex]C(x,y)=(a+b,c)[/tex]

E is the point at which both diagonal bisect to each other. Therefore, E is the mid point of both diagonal AC and BD.

So, coordinate of point E are [tex](\frac{a+b}{2},\frac{c}{2} )[/tex]

Thus, By the definition of midpoint, AE ≅ CE  and BE ≅ DE.

Therefore, diagonals AC and BD bisect each other.

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without using mathematical tables or calculators, evaluate (0.09×1.21)÷(3.3×0.00025)​

Answers

Answer:

132

Step-by-step explanation:

you have to reduce the expression by solving 0.09 divided by 1.21 bc of the PEMDAS rule you do 1st parentheses first which is 0.1089 then do the second set of () which is 0.000825 then divide the 2 answers for 132

What else is produced during the replacement reaction of magnesium and hydrochloric acid? Mg + 2HCl H2 + ________ MgCl2 Mg2Cl2 Mg2Cl MgCl

Answers

Step-by-step explanation:

Magnesium chloride (MgCl2).

Answer:a

A

Step-by-step explanation:

Edge 2021

Christian burns 4 1/2 calories in 2/3 if a minutes riding his bike. HOW MANY CALORIES WILL CHRISTAN BURN IN 1 MINUTE OF BIKE RIDING? SELECT THE CORRECT ANSWER.

Answers

Answer:

The answer is 6.75 calories or [tex]6 \frac{3}{4}[/tex]

Step-by-step explanation:

First, we need to find out how many calories per 1/3 minute.

4 1/2 divided by 2 = 2 1/4 or 2.25

2 1/4 or 2.25 x 3 = [tex]6 \frac{3}{4}[/tex] or 6.75 calories

Mark as Brainliest!

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is -7+9y+7=2x a direct variation and if so what is the constant?

Answers

Answer:

yes constant; 65

Step-by-step explanation:

Select the correct answer.
Sean used cross multiplication to correctly solve a rational equation. He found one valid solution and one extraneous solution. If 1 is the extraneous solution, which equation could he have solved?

Answers

Answer:

Answer A

Step-by-step explanation:

In the equation [tex]\dfrac{10}{x^2-1}=\dfrac{15}{3x-3}[/tex], 1 makes the denominator zero and 1 is the solution of the equation derived from cross multiplication.

Given :

Sean used cross multiplication to correctly solve a rational equation. He found one valid solution and one extraneous solution. 1 is the extraneous solution.

Option A)

Given :

[tex]\dfrac{10}{x^2-1}=\dfrac{15}{3x-3}[/tex]

The above expression is not defined for x equal to 1 so, 1 is an extraneous solution.

Simplify the above equation by doing the cross multiplication.

[tex]10(3x-3)=15(x^2-1)[/tex]

[tex]30(x-1)=15(x-1)(x+1)[/tex]

2 = x + 1

x = 1

In the given equation 1 makes the denominator zero and 1 is the solution of the equation derived from cross multiplication.

Therefore, the correct option is A) and therefore, no need to check the other options.

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The measurement of the “ridge” of your new house on blueprints is 24 inches. If the scale is 1/4 = 1ft how long is the wall in real life

Answers

Answer:

In real the wall will be: 96 ft

Step-by-step explanation:

Given that the scale is

1/4 = 1ft

It means 1 inch will represent 4 ft.

so

1 inch = 4ft

Given that the measurement of the “ridge” of your new house on blueprints is 24 inches.

Thus,

24 inches = 24 × 4ft           ∵ 1 inch = 4ft

                = 96 ft              

Therefore, in real the wall will be: 96 ft

5x - 25 < 15 solve plz

Answers

Answer:

8

Step-by-step explanation:

you have to add 25 on both sides then you get 5x<40 then you divide 40 by 5 and you get 8

hope this helps dont 4get to like and star

-mercury

Given the quadratic equation ax2 + 10x + 2 = 0, determine all values of a that will result in this equation having non-real solutions. Show all work that leads to your answer.

Answers

Answer:

a>12.5.

Step-by-step explanation:

you need to look at the discriminant in the quadratic formula:

[tex]b^{2} -4ac[/tex]

coming from the quadratic polynomial

[tex]ax^{2} +bx+c=0[/tex]

In our case, b=10 and c=2, hence, the discriminant is

[tex]10^2-4*a*2 \\100-8a[/tex]

We will obtain non-real values if the discriminant is less than zero.

Therefore, this condition is written as

[tex]100-8a<0[/tex]

and we must solve for a. It yields

[tex]100<8a\\a>\frac{100}{8} \\a>12.5[/tex]

Hence, the answer is a>12.5.

The values of a that will result in this equation having non-real solutions must e greater than 12.5

Given the quadratic equation  ax^2 + 10x + 2 = 0

For the equation to have non-real solutions, then b^2 - 4ac < 0

From the given equation;

a = a

b = 10

c = 2

Substitute the given parameters into the formula;

10^2 - 4a(2) < 0

100 - 8a < 0

-8a < -100

8a > 100

a > 12.5

Hence the values of a that will result in this equation having non-real solutions must e greater than 12.5

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WILL MARK BRAINLIEST

Find three consecutive even integers such that the sum of the second and third is 3 times the first integer.

Answers

Answer:

3, 4, and 5

Step-by-step explanation:

Given: We're looking for x, x+1, and x+2

Requirements: (x+1)+(x+2)=3(x)

Solve equation:

x+1+x+2=3x

2x+3=3x

3=x

This means the three consecutive integers are 3, 3+1, and 3+2 which is the same as 3, 4, and 5

i’ll answer so you can mark the person above brainliest. have a good day!

-78 = -5a = 7
solve for a lol

Answers

87 i think Step-by-step explanation:

The length of a rectangle is 9cm more than four times the width. If the perimeter of the rectangle is 78 cm, what are its dimensions

Answers

Answer:

Length is 32. 6 cm and width is 5.9 cm

Step-by-step explanation:

width(w)=w

perimeter(p)=78 cm

length(L) = 4w+9

p=2L+2w

78=2(4w+9)+2w

78=8w + 19 + 2w

10w=59

w=5.9 cm

L=4w+9

L=4(5.9)+9

L=32.6 cm

Therefore length is 32.6 cm and width is 5.9 cm

The density of a substance is 3.4 g cm-3. Its relative density relative to another substance is 2.0. what is the density of the second substance?​

Answers

Answer:  The density of the second substance = [tex]1.7\text{ g cm}^{-3}[/tex]

Step-by-step explanation:

[tex]\text{Relative density }=\dfrac{\text{Density of substance}}{\text{Density of reference}}[/tex]

Given: Density of a substance is [tex]3.4 \text{ g cm}^{-3}[/tex] .

Its relative density relation to another substance = 2.0

Substitute all values in the formula , we get

[tex]2=\dfrac{3.4}{\text{Density of reference}}\\\\\Rightarrow\ {\text{Density of reference}=\dfrac{3.4}{2}\\\\\Rightarrow\ {\text{Density of reference}=1.7 \text{ g cm}^{-3}[/tex]

Hence, the density of the second substance = [tex]1.7\text{ g cm}^{-3}[/tex]

this is a rational equation i don't understand lol

-2 1/4 = 2w

Answers

Answer:

[tex]w=-9/8[/tex]

Step-by-step explanation:

We are given the equation [tex]-2 \frac{1}{4} = 2w[/tex]. To solve this equation, we can divide both sides by 2 to get that [tex]w = -2\frac{1}{4} \div 2 = -\frac{9}{8}[/tex].

Answer:

w = - [tex]\frac{9}{8}[/tex]

Step-by-step explanation:

Given

- 2 [tex]\frac{1}{4}[/tex] = 2w ( change the mixed number to an improper fraction )

- [tex]\frac{9}{4}[/tex] = 2w ( multiply both sides by 4 to clear the fraction )

- 9 = 8w ( divide both sides by 8 )

- [tex]\frac{9}{8}[/tex] = w

What is the height of the flagpole in the diagram below

Answers

Answer: The height of the flagpole is 12 feet.

Step-by-step explanation:

Let the height of the flagpole be 'H'.

So, from the figure, we can conclude that, the height and shadow of the flagpole is in proportion to the height and shadow of the stick.

Given:

Height of stick is,

Shadow of the stick is,

Shadow of the flagpole is,

Now, as these are in proportion, we have

Plug in the given values and solve for 'H'. This gives,

Hence, the height of the flagpole is 12 feet.

Estimate 183 to the nearest integer.

Answers

Answer:

Step-by-step explanation:

1,83 x 10^2

What is the median?
59
65
56
60
55
54
62
66
68

Answers

Answer:

The answer is 60

Step-by-step explanation

54

55

56

59

60 The middle number

62

65

66

68

Answer:

60

Step-by-step explanation:

"Median in the middle"

put the set of numbers in order from least to greatest. If you end up having an even amount of numbers in the set, you add the two numbers in the middle then divide by 2 to find the median.

54, 55, 56, 59, 60, 62, 65, 66, 68

55, 56, 59, 60, 62, 65, 66

56, 59, 60, 62, 65

59, 60, 62

60

I need help, please​

Answers

Answer:

C

Step-by-step explanation:

12^2 = 144, 9^2 = 81, and 15^2 = 225.

144 + 81 = 225, therefore a^2 + b^2 = c^2.

Has to be C. The other answers are wrong

A submarine started at the surface of the water and was moving at -15 meters per minute. The submarine traveled at this rate for 48 minutes before coming to rest on the ocean floor. What is the change in the submarine position?

Answers

Given :

A submarine started at the surface of the water and was moving at -15 meters per minute.

The submarine traveled at this rate for 48 minutes before coming to rest on the ocean floor.

To Find :

The change in the submarine position.

Solution :

We need to find the position of submarine position from the surface of water.

Distance travelled =  Speed × Time

Distance travelled = -15 m/min × 48 min

Distance travelled = 720 m

Therefore, the position of submarine is 720 m below the surface of ocean.

Solve -x > 8 or -x < 4.

{x | -12 < x < -6}
{x | x < -12 or x > -6}
{x | x > -12 or x < -6}

Answers

Answer:

-4 < x < -8

Step-by-step explanation:

Given solve -x > 8 or -x < 4.

Solve each inequality first

-x > 8

Divide both sides by -1

-x/-1 > 8/-1

x < -8

Also if -x < 4

Divide both sides by -1

-x/-1 < 4/-1

x > -4

Combine both inequality x < -8 and x > -4

-4 < x < -8

Hence the solution set is -4 < x < -8

What are the answers to these aswell mb?

Answers

Answer:

4 is D = 23

Step-by-step explanation:

the coefficient is the number before the letter

What are the coordinates of point F? On a coordinate plane, point F is 4 units to the right and 2.5 units down.

Answers

Answer:

(4,-2.5)

Step-by-step explanation:

because you move to the right it is a positive x-axis point and since you are moving down it is a negative y- axis point

Answer:

-3,-4.5

Step-by-step explanation:

Give the coordinates of one point that is 5 units from point C in the​ x-direction?

Answers

The answer is fifteen then subtract 21

Adam says that to find the total cost of the rice, you should multiply 3.5 by $1.89. Do you agree? Explain your reasoning.

Answers

Answer:

$6.615

Step-by-step explanation:

Okay, does the value 3.5 represent the quantity of rice bought?

Let us assume this answer is yes, then we can go ahead and estimate the cost of the rice as

Total Cost =1.89*3.5

Total Cost =$6.615

Find each Of change. Round to the nearest whole percent if necessary. State whether the percent Of change is an increase or 1. Original; 5. Original: Cm • Chqter 2. Original: new: 1.3 6. Original; 160 new: 136 g. Original; 15 new : 12 7. Original: 7, 7 new: 10 , 5 4. Original: $30 new: $18 8. Original: 9.6 new: 5.9 31

Answers

Answer:

1. The percentage change is 74% and it is a percentage decrease

2. The percentage change is 15% and it is a percentage decrease

3. The percentage change is 20% and it is a percentage decrease

4. The percentage change is 43% and it is a percentage increase

5. The percentage change is 40% and it is a percentage decrease

6. The percentage change is 39% and it is a percentage decrease

Step-by-step explanation:

Given

[tex]1.\ Original = 5; New = 1.3[/tex]

[tex]2.\ Original = 160; New = 136[/tex]

[tex]3.\ Original = 15; New = 12[/tex]

[tex]4.\ Original = 7; New = 10[/tex]

[tex]5.\ Original = $30; New = $18[/tex]

[tex]6.\ Original = 9.6; New = 5.9[/tex]

Required

Determine the percentage change and state whether it's an increase or decrease

Percentage change is calculated as:

[tex]\%Change = \frac{New - Original}{Original} * 100\%[/tex]

[tex]1.\ Original = 5; New = 1.3[/tex]

[tex]\%Change = \frac{1.3 - 5}{1.3} * 100\%[/tex]

[tex]\%Change = \frac{-3.7}5} * 100\%[/tex]

[tex]\%Change = \frac{-3.7 * 100\%}{5}[/tex]

[tex]\%Change = \frac{-370\%}{5}[/tex]

[tex]\%Change = -74\%[/tex]

The percentage change is 74% and it is a percentage decrease

[tex]2.\ Original = 160; New = 136[/tex]

[tex]\%Change = \frac{136 - 160}{160} * 100\%[/tex]

[tex]\%Change = \frac{-24}{160} * 100\%[/tex]

[tex]\%Change = \frac{-24 * 100\%}{160}[/tex]

[tex]\%Change = \frac{-2400\%}{160}[/tex]

[tex]\%Change = -15\%[/tex]

The percentage change is 15% and it is a percentage decrease

[tex]3.\ Original = 15; New = 12[/tex]

[tex]\%Change = \frac{12- 15}{15} * 100\%[/tex]

[tex]\%Change = \frac{-3}{15} * 100\%[/tex]

[tex]\%Change = \frac{-3* 100\%}{15}[/tex]

[tex]\%Change = \frac{-300\%}{15}[/tex]

[tex]\%Change = -20\%[/tex]

The percentage change is 20% and it is a percentage decrease

[tex]4.\ Original = 7; New = 10[/tex]

[tex]\%Change = \frac{10- 7}{7} * 100\%[/tex]

[tex]\%Change = \frac{3}{7} * 100\%[/tex]

[tex]\%Change = \frac{3* 100\%}{7}[/tex]

[tex]\%Change = \frac{300\%}{7}[/tex]

[tex]\%Change = 43\%[/tex] -- (approximated)

The percentage change is 43% and it is a percentage increase

[tex]5.\ Original = $30; New = $18[/tex]

[tex]\%Change = \frac{18- 30}{30} * 100\%[/tex]

[tex]\%Change = \frac{-12}{30} * 100\%[/tex]

[tex]\%Change = \frac{-12* 100\%}{30}[/tex]

[tex]\%Change = \frac{-1200\%}{30}[/tex]

[tex]\%Change = -40\%}[/tex]

The percentage change is 40% and it is a percentage decrease

[tex]6.\ Original = 9.6; New = 5.9[/tex]

[tex]\%Change = \frac{5.9- 9.6}{9.6} * 100\%[/tex]

[tex]\%Change = \frac{-3.7}{9.6} * 100\%[/tex]

[tex]\%Change = \frac{-3.7* 100\%}{9.6}[/tex]

[tex]\%Change = \frac{-370\%}{9.6}[/tex]

[tex]\%Change = -39\%[/tex] -- (approximated)

The percentage change is 39% and it is a percentage decrease

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