Answer:
when the valence (outermost) electrons of one atom are transferred permanently to another atom
Compare the change in pH with the addition of acid and base to deionized water and to a buffer.
Answer:
case1.
The addition of acid and base leads to a change in pH of the water when adding to deionized water due to fact that acid and bases dissociated in dissolving in water. If the H+ ion increases in the water as acid addition hikes it, it will result in decreasing the pH value. The intensity of the acid also affects the dissociation of the ions.
case2
Buffers are normally formed by weak acid and its conjugate base, and adding acid to the buffer it absorbs the H+ ions so the pH will be lower and adding base or increase of OH- conjugate base resists the pH value to increase.
PLS HELP THIS IS DUE IN 10 MINS!
Compare and contrast floods and droughts. Give two examples of how they are the same and two examples of how they are different.
An empty steel container is filled with 2.0 atm of H₂ and 1.0 atm of F₂. The system is allowed to reach equilibrium according to the reaction below. If Kp = 0.45 for this reaction, what is the equilibrium partial pressure of HF?
The equilibrium partial pressure of HF is 0.55 atm.
The equation of the reaction is;
H2(g) + F2(g) ⇄ 2HF
I 2 1 0
C -x -x +x
E 2 - x 1 - x x
We know that;
pH2 = 2.0 atm
PF2 = 1.0 atm
pHF = ??
Kp = 0.45
So;
Kp = (pHF)^2/pH2. pF2
0.45 = x^2/(2 - x) (1 - x)
0.45 = x^2/x^2 - 3x + 2
0.45(x^2 - 3x + 2) = x^2
0.45x^2 - 1.35x + 0.9 = x^2
0.55 x^2 + 1.35x - 0.9 = 0
x = 0.55 atm
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A severe storm would be most likely to damage a coastal area by causing
A.
volcanoes.
B.
pollution.
C.
erosion.
D.
earthquakes.
A severe storm would be most likely to damage a coastal area by causing pollution. Therefore, the correct option is option B.
What is coastal area?The region where land joins the ocean, or even as a line defining the border between the land as well as the shoreline, is known as the coast, sometimes referred as the coastline and seashore. The terrain of the area's surroundings has an impact on shorelines, as do water-induced erosion processes like wave action.
The length of the shoreline on Earth is about 620,000 kilometers. Natural ecosystems' coasts are significant zones and frequently the site of a diverse range of biodiversity. They are home to significant ecosystems on land, such as freshwater and estuarine wetlands, that are crucial for the survival of bird populations or other land animals. A severe storm would be most likely to damage a coastal area by causing pollution.
Therefore, the correct option is option B.
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plz help :(
In a high-pressure system,
a.
air molecules are far apart and pressing on Earth’s surface.
b.
air molecules are far apart and rising away from Earth’s surface.
c.
air molecules are close together and pressing on Earth’s surface.
d.
air molecules are close together and rising away from Earth’s surface.
Answer:
c.
air molecules are close together and pressing on Earth’s surface.
Explanation:
i hope this helps!
help please guys i need it
Answer:
Amplitude
Explanation:
Hope I helped :)
Astronauts go to live on the International Space Station for a period of ________ month(s). A one B three C six D nine
Answer:
The answer is C. six months
Explanation:
I hope this helps you bestie:))
Balance the chemical equation
C2H6+O2 = CO2 +H2O
A vitamin C (ascorbic acid) tablet was dissolved in approximately 50 mL of distilled water and titrated with the standardized NaOH solution. From the results of this titration, the mg of ascorbic acid in the tablet was calculated. Molecular formula of ascorbic acid: C6H8O6 Volume of NaOH required to neutralize ascorbic acid in Vitamin C tablet (mL) 20.74 Concentration of NaOH in mol/L, 0.201 Calculate the amount of ascorbic acid in the Vitamin C tablet in (mg).
Answer:
The correct answer is - 733.69 mg.
Explanation:
given:
The volume of ascorbic acid = 50 ml
The volume of NaOH = 20.74 ml
Molarity of NaOH = 0.201 M
formula = C6H8O6
Solution:
moles of NaOH for titration = molarity of NaOH × The volume of NaOH
= 0.201 × 20.74 × 10^-3
=4.16874 × 10^-3
then molecular weight of ascorbic acid
= 6 × 12+ 8×1+ 6× 16
=176g/mol
the molecular mass would be
= 4.16874 × 10^-3 × 176
= 733.69 × 10^-3 g
=733.69 mg
A gas takes
up a volume of 17 L, has a
pressure of 2.3 atm, and a temperature
of 299 K. If I raise the temperature to
350 K and lower the pressure to 1140
mmHg, what is the new volume?
Answer:
V₂ = 25.065 L
Explanation:
Given data:
Initial volume = 15L
Initial pressure = 1500 mmHg (1500/760 = 1.97 atm)
Initial temperature = 299 K
Final temperature = 350 K
Final volume = ?
Final pressure = 1050 mmHg (1050/760 = 1.38 atm)
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 1.97 atm × 15 L × 350 K / 299 K × 1.38 atm
V₂ = 10342.5 atm .L. K / 412.62 K.atm
V₂ = 25.065 L
What is the final volume?
Answer:
Option A. 9.4 L
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 8 L
Initial temperature (T₁) = 293 K
Final temperature (T₂) = 343 K
Final volume (V₂) =?
V₁ / T₁ = V₂ / T₂
8 / 293 = V₂ / 343
Cross multiply
293 × V₂ = 8 × 343
293 × V₂ = 2744
Divide both side by 293
V₂ = 2744 / 293
V₂ = 9.4 L
Therefore, the final volume of the gas is 9.4 L
If 280.4 g of KOH react with an excess of FeCl3, how many grams of Fe(OH)3 will be produced?
FeCl3 + 3 KOH — Fe(OH)3 + 3 KCI
How many grams will be produced?
Answer:
From 00:11
Balance the Molecular Equation
From 01:35
Ions for the Complete Ionic Equation
From 03:04
Net Ionic EquationExplanation:
The subscript represents the number of ____________ in a chemical equation.
Does the magnetic field lines of repelling magnets always combine. True or False?
Answer:
True
Explanation:
yes magnetic feild lines is always combined
oil has a density of 8.5kg/L. what is the volume of 5.4kg oil
Answer:
0.64 L
Explanation:
Step 1: Given data
Density of oil (ρ): 8.5 kg/LMass of oil (m): 5.4 kgVolume of oil (V): ?Step 2: Calculate the volume corresponding to 5.4 kg of oil
Density is an intrinsic property and it is equal to the quotient between the mass and the volume.
ρ = m/V
V = m/ρ
V = 5.4 kg/(8.5 kg/L) = 0.64 L
hi, if your looking for extra points (50+) and br ainiest here is ur chance, answer this question correctly plz
HELP and give brainlys out to ppl who actually know the answer please help
Answer:
b. snake and earthworm
Explanation:
embryos are different from each other in early stages- all the others look similar
1) Calculate the percent composition of each element in ammonia (NH).
Answer:
[tex]\% N=82.2\% \\\\\% H=17.8\%[/tex]
Explanation:
Hello there!
In this case, since ammonia is NH₃, we can see nitrogen weights 14.01 g/mol and hydrogen 3.03 g/mol as there is one only nitrogen atom and three hydrogen atoms; thus, the total mass is 17.04 g/mol. In such a way, the percent composition of each element turns out to be:
[tex]\% N=\frac{14.01}{17.04}*100\%=82.2\% \\\\\% H=\frac{3.03}{17.04}*100\%=17.8\%[/tex]
Best regards!
what is derived from sheep and goats that is used in break fluid
A bones and horns
B Fats and Fattys acids
C Manure
D Wool and Lanolin
the answer is A I took the test
Please help ASAP! Please and thank you have a great and blessed day!,
What is the atomic mass of element XX if 3.6 moles of the substance has a mass of 192 grams?
Answer:
53.3g/mol
Explanation
Moles=mass/molar mass
Molar mass= mass/moles
Molar mass= 192/3.6
= 53.3
Calculate the mass, in grams, of 0.540 mol of manganese (Mn).
Report your answer with three significant figures.
Answer:
m = 29.6 grams
Explanation:
Given that,
Number of moles = 0.540
The molar mass of manganese = 54.93 g/mol
We know that,
Number of moles = given mass/molar mass
[tex]m=n\times M\\\\m=0.540 \times 54.93\\\\m=29.6\ g[/tex]
So, the required mass of the Manganese is equal to 29.6 grams.
How many atoms are in 90.43 moles of copper
Mole measure the number of elementary entities of a given substance that are present in a given sample. Therefore, 8.12×10²³ atoms are in 90.43 mole of copper.
What is mole?
The SI unit of amount of substance in chemistry is mole. The mole is used to measure the quantity of amount of substance. It measure the number of elementary entities of a given substance that are present in a given sample. There are so many formula for calculating mole.
we know one mole of any element contains 6.022×10²³ atoms which is also called Avogadro number
number of atoms/molecules=number of moles × 6.022×10²³(Avogadro number)
number of moles of copper=90.43 moles
Substituting all the given values in the above equation, we get
number of atoms/molecules= 90.43 × 6.022×10²³
number of atoms/molecules=8.12×10²³ molecules
Therefore, 8.12×10²³ atoms are in 90.43 mole of copper.
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Who knows how to do this please help
Answer: You forgot to zero the balance
Explanation:
what is the mass of 1.25 L of ammonia gas at STP
Answer:
mass 1.25 Liters NH₃(gas) = 0.949 grams (3 sig-figs)
Explanation:
At STP (Standard Temperature-Pressure conditions => 0°C(=273K) and 1atm pressure, 1 mole any gas will occupy 22.4 Liters.
So, given 1.25 Liters ammonia gas at STP, convert to moles then multiply by formula wt. (17g/mole gives mass of NH₃.
moles NH₃(gas) = 1.25L NH₃(gas)/22.4L NH₄(gas)· NH₃(gas)mole⁻¹ = 0.0558 mole NH₃(gas).
Converting to grams NH₃(gas) = 0.0558 mole NH₃(gas) x 17 g·mol⁻¹ = 0.949 grams NH₃(gas).
Which postmortem parameter is fixed by 8 hours?
1)cloudiness of the eyes
2)rigor mortis
3)livor mortis
4)putrefaction
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Who among, Amit and Saaketh, is correct? Explain.
Answer:
What is their question answers exactly? I won't be able to explain who is correct.
Explanation:
Answer:
Not a lot to draw from this question if im going to be honest
Explanation
Balance Ca + HCI +CaCl2 + H2
Answer:
Ca + 2 HCl -- CaCl2 + H2
Explanation:
There are two hydrogen on the right side, so we multiply the left side( HCl) by 2 to get 2 hydrogen on the left. This automatically gives you 2 Cl on left side and there are already 2 cl on the right side, so now this equation is balanced.
How many moles are in 2.5L of 1.75 M Na2CO3
Answer: There are 4.375 moles in 2.5 L of 1.75 M [tex]Na_2CO_3[/tex]
Explanation:
To calculate the number of moles for given molarity, we use the equation:
[tex]\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}[/tex]
Molarity of solution = 1.75 M
Volume of solution = 2.5 L
Putting values in equation , we get:
[tex]1.75M=\frac{\text{Moles of} Na_2CO_3}{2.5L}\\\\\text{Moles of }Na_2CO_3=1.75mol/L\times 2.5L=4.375mol[/tex]