what constant acceleration (in ft/s2) is required to increase the speed of a car from 21 mi/h to 54 mi/h in 5 seconds? (round your answer to two decimal places.)

My day is alright! I just finished school for the day.. and I’m excited for the weekend! How was your day?

Answer:

+ 140

Explanation:

You can show the natural growth rate by subtracting the death rate from the birth rate during one year and converting this into a percentage.

Here it would be:

240 - 100 = + 140

// if you want to convert it to percentage, you need to know the size of the population

it would be

140 / (population size) * 100 %

Answer:

The water in a reservoir behind a hydropower dam is another example of potential energy. The stored energy in the reservoir is converted into kinetic energy as the water flows down a large pipe called a penstock and spins a turbine.

Explanation:

Hope this helps :))

A concrete dam holds back a large reservoir of water potential energy, the stored potential energy is converted into the kinetic energy which is converted into mechanical energy and then further converted into electrical energy.

A dam or other construction that alters the natural flow of a river or other body of water is used to generate hydropower, often known as hydroelectric power.

In order to generate energy, hydropower uses the perpetual, never-ending water cycle, which uses water as a fuel and leaves no waste products behind. Although there are many different kinds of hydropower plants, they are always propelled by the kinetic energy of water moving downstream.

Thus, a concrete dam holds back a large reservoir of water potential energy.

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Answer:

and there is no friction

Explanation:

An object at rest has zero velocity - and (in the absence of an unbalanced force) will remain with a zero velocity. Such an object will not change its state of motion (i.e., velocity) unless acted upon by an unbalanced force. An object in motion with a velocity of 2 m/s, East will (in the absence of an unbalanced force) remain in motion with a velocity of 2 m/s, East. Such an object will not change its state of motion (i.e., velocity) unless acted upon by an unbalanced force. Objects resist changes in their velocity.

Answer:

D

Explanation:

I hope you get a good grade!

Explanation:

Frequency is the number of occurrences of a repeating event per unit of time.

It is also referred to as temporal frequency, which emphasizes the contrast to spatial frequency and angular frequency.

The period is the duration of time of one cycle in a repeating event, so the period is the reciprocal of the frequency.

Relationship between Period and frequency is as under :

The frequency of a wave describes the number of complete cycles which are completed during a given period of time.

As such, frequency is a rate quantity which describes the rate of oscillations or vibrations or cycles or waves on a per second basis.

A common unit of frequency is the Hertz, abbreviated as Hz.

Frequency

=

1

Period

f = c / λ = wave speed c (m/s) / wavelength λ (m).

http://www.sengpielaudio.com/calculator-period.htm

http://www.sengpielaudio.com/calculator-period.htm

https://study.com/academy/lesson/wave-period-definition-formula-quiz.html

Answer:

The electrostatic force that will result if both charges are doubled and the distance remains the same is 6.0 * 10⁻⁶ N

Explanation:

Coulomb's law of  electricity states that the magnitude of the force of attraction or repulsion between two charges is directly proportional to the product of their charges and inversely proportional to the square of the distance of of separation between them.

In formula; F = KQ₁Q₂/d²

Using the formula for electrostatic force of attraction above to determine the force of between the two charged spheres

Let the charges be Q₁ and Q₂; distance of separation be d, K is a constant

Initially, F₁ = KQ₁Q₂/d² ---- (1)

F₁ = 3.0 * 10⁻⁶ N

when the charges are doubled, Q₁ = 2Q₁; Q₂ = 2Q₂; K and d remains constant

F₂ = 2KQ₁Q₂/d² ----(2)

Dividing equation (2) by (1) to find the ratio of their forces

F₂/F₁ = (2KQ₁Q₂/d²) / KQ₁Q₂/d²

F₂/F₁ = 2

Thus, F₂ is twice F₁.

Since F₁ = 3.0 * 10⁻⁶ N; F₂ = 2 * 3.0 * 10⁻⁶ N

F₂ = 6.0 * 10⁻⁶ N

Therefore, the electrostatic force that will result if both charges are doubled and the distance remains the same is 6.0 * 10⁻⁶ N

Electrostatic force is a force imposed by one charge on another as a result of the field.Electrostatic force will  be 12.0 x 10⁻⁶ N if both charges are doubled and the distance remains the same.

It is a force imposed by one charge on another as a result of the field.

The electrostatic force produced by one line charge on another line charge separated by distance d is determined by the charge potency of each charge as well as the separation distance between them.

Hence the electrostatic force is given by  

[tex]\rm F=\frac{Kq_1q_2}{d^2}[/tex]

The given data in the question ,

d is the distance between the charge

F₁ is the electric force for case 1= 3.0 x 10⁻⁶ N

F₂ is the  electric force for case 2= ?

Conditions for case 2;

(q₁=2q₁),(q₂=2q₂),d₂=d₁

For case 1,

[tex]\rm F_1=\frac{Kq_1q_2}{d_1^2}[/tex]

For case 2,

[tex]\rm F_2=\frac{K(2q_1)(2q_2)}{d_1^2}[/tex]

[tex]\rm F_2=4\times\frac{Kq_1q_2}{d_1^2}\\\\\rm F_2=4F_1[/tex]

[tex]\rm F_2=4\times\frac{Kq_1q_2}{d_1^2}\\\\\rm F_2=4\times3.0\times 10^{-6}\\\\\rm F_2=12.0\times10^{-6}[/tex]

Hence electrostatic force will be 12.0 x 10⁻⁶ N.  if both charges are doubled and the distance remains the same.

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Answer:

The object will travel at the speed of 16 m/s.

Explanation:

Given

To determine

How fast is the object traveling?

Important Tip:

The product of the mass and velocity of an object —  momentum.

Using the formula

[tex]p = mv[/tex]

where

Thus, in order to determine the speed of the object, all we need to do is to substitute p = 64 and m = 4 in the formula

[tex]p = mv[/tex]

[tex]64\:=\:4\times v[/tex]

switch the equation

[tex]\:4\times \:v\:=64[/tex]

divide both sides by 4

[tex]\frac{4v}{4}=\frac{64}{4}[/tex]

simplify

[tex]v=16[/tex] m/s

Therefore, the object will travel at the speed of 16 m/s.

Answer:modeled as an electromagnetic wave. In this model, a changing electric field creates a changing magnetic field.

Explanation:

Answer:

[tex]E=1.62\times 10^{14}\ J[/tex]

Explanation:

Given that,

The mass of the paperclip, m = 1.8 g = 0.0018 kg

We need to find the energy obtained. The relation between mass and energy is given by :

[tex]E=mc^2[/tex]

Where

c is the speed of light

So,

[tex]E=0.0018\times (3\times 10^8)^2\\\\E=1.62\times 10^{14}\ J[/tex]

So, the energy obtained is [tex]1.62\times 10^{14}\ J[/tex].

Answer:

Explanation:

Initial velocity of the ball = 27 m /s .

Its vertical component = 27 sin 35 = 15.48 m /s

Considering vertical displacement to the top point ,

initial velocity u = 15.48 m /s

acceleration due to gravity g = 9.8 ,

velocity at the top v = 0

v = u - gt  

0 = 15.48 - 9.8 t

t = 15.48 / 9.8 = 1.579 s

So time of ascent = 1.579 s

Similarly , time of descent = 1.579

Total time of flight = 2 x 1.579

= 3.16 s

Answer:

when a car transforms...

Explanation:

Explanation:

Vivimos en un puente en lo que el diseño de coches se refiere, consecuencia de la gran disrupción de la automación que ocurriría en los próximos años.

Answer:

 W = -1400 J

Explanation:

Let's use the relationship between work and kinetic energy

           W = ΔK

kinetic energy is

            K = ½ m v²

therefore in this case

             K₀ = 1400 J

Thus

            W = 0 -1400

            W = -1400 J

The negative sign indicates that the work is done against the energy, that is, in the opposite direction to the movement

Answer:

Net force = 5N

Explanation:

Jay = 20N to the right

Bradley = 15N to the left

To find the net force;

Since the forces are being applied to the box in opposite direction i.e acting in opposite direction, we would subtract them.

Net force = 20 - 15

Net force = 5N

Therefore, the net force on the box is 5 Newton.

[tex]\displaystyle F_n = 9.8 \ N[/tex]

Math

Pre-Algebra

Order of Operations: BPEMDAS

Physics

Forces

SI Unit: Newtons N

Free Body Diagrams

Gravitational Force: [tex]\displaystyle F_g = mg[/tex]

Normal Force: [tex]\displaystyle F_n[/tex]

Newton's Law of Motions

Step 1: Define

1 kg book at rest

Step 2: FBD

See Attachment

Draw a free body diagram to label the forces acting upon the book. We see that we would have gravitational force from Earth pointing downwards and normal force from the surface of the desk pointing upwards.

Since the book is not moving, we know that ∑F = 0 (sum of forces equal to 0).

Step 4: Find Normal Force

Answer:

A

Explanation

The diagram in A. contain a variable resistor which can be use to vary the pd from the 6v battery

Answer:

a = 32 m/s sq

Explanation:

Answer:

The quadriceps consists of four muscles: the skinny rectus femoris and the three huge “vasti” — vastus lateralis/intermedius/medialis. The vasti are only elongated by knee flexion, which is limited to about 120˚ when the calf hits the hamstrings. The vasti cannot be stretched strongly.

Answer:Masseter and temporalis

Why it’s unstretchable: The jaw can only open so far.

Why it’s a dang shame: Jaw tension is epidemic, and trigger points in these muscles cause a wide array of strange face and head pains, including toothaches, headaches, and earaches.

Answer:

C. The distance traveled by an object at a certain velocity.

Explanation:

YW!

Answer:

third option is the most accurate

Answer:

 a = 40.937 m / s²

Explanation:

For this exercise let's use the relationship between momentum and momentum variation

          I  = Δp

          F t = m v_f - mv₀

          F = m (v_f -v₀) / t

let's reduce the magnitudes to the SI system

          v_f = 47 km / h (1000m / 1 km) (1h / 3600 s) = 13.056 m / s

          v₀ = - 65 km / h = -18.056 m / s

the negative sign is bearing the speed is west

let's calculate

          F = m (13.056 + 18.056) / 0.76

          F = m 40.937

now we can use Newton's second law

          F = m a

          m 40.937 = m a

          a = 40.937 m / s²

Answer:

larger than object

Explanation:

the image formed will be on the opposite side of lens and magnified

Answer:

C

Explanation:

Answer:

1s2,2s2,2p6 or (He) 2s2 2p6

Answer:

12

Explanation:

Answer:

114 minutes

Explanation:

hope this helps. I just divided 950 by 500 that is 1.9 and 1.9 in minutes is 114. gl

Answer:

The electrical energy needed is 8.415*10⁻³ N

Explanation:

Energy is the ability of a body to make changes or work.

By separating or joining two electric charges a distance (for example, a radius r) within their electric fields, you are taking away or giving the electric charges energetic potentials, relative to each other. By releasing these charges, they will attract or repel each other, releasing that acquired electrical energy.

In other words, electric potential energy is linked to the particular configuration of a conglomerate of point charges in a defined system.

That is, it calculates the capacity of an electrical system to carry out a task based exclusively on its position or configuration. So, it is a kind of energy stored in the system, or the amount of energy that it is capable of delivering.

Thus, a charge will exert a force on any other charge and the potential energy is the result of the set of charges.

The electric potential energy that has a point charge q in the presence of another point charge Q that are separated by a certain distance r is:

[tex]Ep=K*\frac{Q1*Q2}{r^{2} }[/tex]

where:

In this case:

Replacing:

[tex]Ep=9*10^{9}\frac{N*m^{2} }{C^{2} } *\frac{5.5*10^{-7}C *1.7*10^{-6}C }{(1m)^{2} }[/tex]

Solving:

Ep= 8.415*10⁻³ N

The electrical energy needed is 8.415*10⁻³ N

The electrical energy is needed to bring two charges Q1 and Q2 from infinity to where they are 1 meter apart is 8.415 x 10⁻³ N.

An electric potential can be defined as the amount of work or energy needed to move a charge from one point to another against the electrical field.

We know that in order to know electrical energy is needed to bring two charges Q1= 5.5 x 10⁻⁷C and Q2= 1.7 x 10⁻⁶ C from infinity to where they are 1 meter apart, we need to calculate electric potential energy between the two charged particles,

[tex]E_P = k\dfrac{Q_1Q_2}{d^2}[/tex]

Substitute the values,

[tex]E_P = 9 \times 10^9 \dfrac{5.5 \times 10^{-7} \times 1.7 \times 10^{-6}}{1^2}\\\\E_P = 8.415 \times 10^{-3}\rm\ N[/tex]

Hence, the electrical energy is needed to bring two charges Q1 and Q2 from infinity to where they are 1 meter apart is 8.415 x 10⁻³ N.

Learn more about Electrical Potential:

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Work Shown:

We have these variables

Solving for the mass gets us...

p = m*v

25 = m*2.5

25/2.5 = m

10 = m

m = 10

The mass of the horse is 10 kg.