When the universe was 380,000 years old, its thermal radiation spectrum was mostly composed of microwaves.
What is radiation?Radiation is the emission of energy from any source that is capable of producing electromagnetic radiation such as light, X-rays, gamma rays and radio waves. Radiation is a form of energy that can be beneficial or harmful depending on the type and dose.
This is because at this point in its history, the universe had cooled enough that its thermal radiation spectrum was mostly in the microwave region of the spectrum. These microwaves are known as the Cosmic Microwave Background Radiation (CMBR). This radiation is believed to have been emitted by the hot, dense early universe shortly after the Big Bang.
The CMBR is one of the most important pieces of evidence for the Big Bang theory. It is uniform across the sky and is detected in all directions. Its temperature is approximately 2.7 Kelvin, which is about -270.45 degrees Celsius. This radiation is also believed to be the oldest light in the universe, as it has been travelling through space for billions of years.
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A jet of water squirts out horizontally from a hole near the bottom of the tank, as seen in the figure.
If the hole has a diameter of 3.13 mm, what is the height, h, of the water level in the tank? Assume that x = 1.33 m and y = 1.72 m.
The height, h, of the water level in the tank is mathematically given as
h=1.3675
What is the height, h, of the water level in the tank?Generally, the equation for kinematics is mathematically given as
S=v_o t+(1/2)at^2
Therefore
y=0+(1/2)gt^2
Where
t=(2y/g)^{1/2}
t=(2*1.72/9.8)^{1/2}
t=0.5925s
The horizontal exit velocity will be given as
[tex]Vx=x/t[/tex]
Therefore
[tex]Vx=\frac{0.3.13}{0.5925}[/tex]
Vx=0.5283
In conclusion, applying Bernoulli's Law the tank bottom and tank surface
P+(1/2)pv0^2+pgh=P+(1/2)pvx^2+pgh
(1/2)(p)(0m/s)^2+pgh=(1/2)pvx^2+pg(0m)
gh=(1/2)vx^2
h=(0.5283m/s)^2/(2)(9.8)
h=1.3675
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The Lunar Module could make a safe landing if its vertical velocity at impact is 2.8 m/s or less. Use conservation of energy to determine h in each case. The acceleration due to gravity at the surface of the Moon is 1.62 m/s2.
Suppose that you want to determine the greatest height h at which the pilot could shut off the engine if the velocity of the lander relative to the surface at that moment is zero.
Express your answer to two significant figures and include the appropriate units.
Suppose that you want to determine the greatest height h at which the pilot could shut off the engine if the velocity of the lander relative to the surface at that moment is 1.7 m/s downward.
Express your answer to two significant figures and include the appropriate units.
Suppose that you want to determine the greatest height h at which the pilot could shut off the engine if the velocity of the lander relative to the surface at that moment is 1.7 m/s upward.
Express your answer to two significant figures and include the appropriate units.
(1) The greatest height h at which the pilot could shut off the engine if the velocity of the lander relative to the surface at that moment is zero is 0.4 m.
(2) The greatest height h at which the pilot could shut off the engine if the velocity of the lander relative to the surface at that moment is 1.7 m/s downward is 0.25 m.
(3) The greatest height h at which the pilot could shut off the engine if the velocity of the lander relative to the surface at that moment is 1.7 m/s upward is 0.25 m.
Maximum height
v² = u² - 2gh
where;
v is final velocityu is initial velocitywhen the lander's velocity = 0
0 = u² - 2gh
u² = 2gh
h = u²/2g
h = (2.8²)/(2 x 9.8)
h = 0.4 m
when the velocity of the lander is 1.7 m/s downwardh = (u² - v²)/2g
h = (2.8² - 1.7²)/(2 x 9.8)
h = 0.25 m
when the velocity of the lander is 1.7 m/s upwardh = (u² - v²)/2g
h = (2.8² - 1.7²)/(2 x 9.8)
h = 0.25 m
Thus, the greatest height h at which the pilot could shut off the engine if the velocity of the lander relative to the surface at that moment is zero is 0.4 m.
The greatest height h at which the pilot could shut off the engine if the velocity of the lander relative to the surface at that moment is 1.7 m/s downward is 0.25 m.
The greatest height h at which the pilot could shut off the engine if the velocity of the lander relative to the surface at that moment is 1.7 m/s upward is 0.25 m.
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A shot-putter accelerates a 7.5 kg shot from rest to 12 m/s .
If this motion takes 1.6 s , what average power was developed?
Express your answer using two significant figures.
From the calculations, the power developed is 337.5 W.
What is the power developed?First we must obtain the acceleration from;
v = u + at
u = 0 m/s because the motion started rom rest
v = at
a = v/t
a = 12 m/s/ 1.6 s
a= 7.5 m/s^2
The force is obtained from;
F = ma = 7.5 kg * 7.5 m/s^2 = 56.25 N
Now the distance covered is obtained from';
v^2 = u^2 + 2as
v^2 = 2as
s = v^2/2a
s = (12)^2/2 * 7.5
s = 9.6 m
Now;
Work = Fs = 56.25 N * 9.6 m = 540 J
Power expended = 540 J/ 1.6 s = 337.5 W
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Earth travels around the Sun each year in sn elliptical path, as opposed to a perfect curcle. This means that the speed if earth and its dustance from the Sun change over rhe course if a year. What does this sayabout the magnitude of the centripetal acceleration if earth over the course of a year
A change in the linear speed of the Earth around the sun will cause a change in the magnitude of the centripetal acceleration.
What is centripetal acceleration ?
Centripetal acceleration is the acceleration of a body moving a circular path.
The relationship between centripetal acceleration and speed;
a = v²/r
where;
v is linear speeda is centripetal accelerationr is radius of the pathSince the centripetal acceleration is directly proportional to square of linear speed, a change in the linear speed of the Earth around the sun will cause a change in the magnitude of the centripetal acceleration.
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A rocket takes off from Earth's surface, accelerating straight up at 69.2 m/s2. Calculate the normal force (in N) acting on an astronaut of mass 87.4 kg, including his space suit. (Assume the rocket's initial motion parallel to the +y-direction. Indicate the direction with the sign of your answer.)
According to Newton's 3rd law, there will be equal and opposite force on the astronaut which is -6048 N
What does Newton's third law say ?The law state that in every action, there will be equal and opposite reaction.
Given that a rocket takes off from Earth's surface, accelerating straight up at 69.2 m/s2. We are to calculate the normal force (in N) acting on an astronaut of mass 87.4 kg, including his space suit.
Let us first calculate the force involved in the acceleration of the rocket by using the formula
F = ma
Where mass m = 87.4 kg, acceleration a = 69.2 m/s2
Substitute the two parameters into the formula
F = 87.4 x 69.2
F = 6048.08 N
According to the Newton's 3rd law, there will be equal and opposite force on the astronaut.
Therefore, the normal force acting on the astronaut is -6048 N approximately
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A toroidal solenoid has 600 turns, cross-sectional area 6.90 cm2, and mean radius 4.30 cm.
a) Calculate the coil's self-inductance.
b) If the current decreases uniformly from 5.00 A to 2.00 A in 3.00 ms , calculate the self-induced emf in the coil.
c) The current is directed from terminal a of the coil to terminal b. Is the direction of the induced emf from a to b or from b to a?
(a) The coil's self-inductance is 7.26 mH.
(b) The self-induced emf in the coil is 7.26 V
(c) The direction of the induced emf is from b to a.
Coil's self-inductance
L = N²μA/I
L = (600² x 4π x 10⁻⁷ x 6.9 x 10⁻⁴)/(0.043)
L = 7.26 x 10⁻³ H
L = 7.26 mH
Self-induced emf in the coilemf = N(ΔBA)/t
where;
B is magnetic fieldA is area N is number of turnst is timeB = μNI/L
B1 = (4π x 10⁻⁷ x 600 x 5)/0.043
B1 = 0.0876 T
B2 = (4π x 10⁻⁷ x 600 x 2)/0.043
B2 = 0.035 T
emf = NΔBA/t
emf = (600)(0.0876 - 0.035)(6.9 x 10⁻⁴) / (3 x 10⁻³)
emf = 7.26 V
The direction of the induced emf is always opposite to the direction of the applied current.
Thus, the direction of the induced emf is from b to a.
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An object of height 8.50 cm is placed 20.0 cm to the left of a converging lens with a focal length of 12.0 cm. Determine the image location in cm, the magnification, and the image height in cm.
The image distance is 33.3 cm while the image height is 14.2 cm.
What is a converging lens?A converging lens will always have a positive focal length hence, we have to find the object distance as follows;
1/f = 1/v + 1/u
1/12 = 1/v + 1/20
1/v = 1/12 - 1/20
1/v = 0.08 - 0.05
v =33.3 cm
Now;
Magnification = 33.3 cm/20.0 cm =1.67
M = Image height/Object height
1.67 = Image height/8.50 cm
Image height = 1.67 * 8.50 cm
Image height = 14.2 cm
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The mass of Saturn is 5.68 x 1026 kg, and use an orbital radius of 3.00 x 105 km. (G = 6.67 × 10-11 N ∙ m2/kg2). Find the orbital speed of an ice cube in the rings of Saturn.
The orbital speed of an ice cube in the rings of Saturn is determined as 355,366.5 m/s.
What is orbital speed?
The orbital speed of an astronomical body or object is the speed at which it orbits around the center of mass of the most massive body.
Orbital speed of ice cube in the rings of SaturnThe orbital speed of ice cube in the rings of Saturn is calculated as follows;
v = √GM/r
where;
G is universal gravitation constantM is mass of Saturnr is the distance of the ice cubev = √(6.67 x 10⁻¹¹ x 5.68 x 10²⁶)/(3 x 10⁵)
v = 355,366.5 m/s
Thus, the orbital speed of an ice cube in the rings of Saturn is determined as 355,366.5 m/s.
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How big is this restoring force compared with the tensile force stretching the spring?
A. Bigger
B. Not enough info
C. Smaller
D. Same size
The restoring force on the spring is found to have exactly the same magnitude as the stretching force. Option D
What is the restoring force?The restoring force is the force that seeks to restore the spring to its equilibrium position. It has the same magnitude as the stretching force but acts in opposite direction.
Thus, the restoring force on the spring is found to have exactly the same magnitude as the stretching force.
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ATTA-KAY PHYSICS 121 3. A ball A is left to roll down an inclined plane of inclination 30º. Just at the moment a second ball B is pushed up the plane with a velocity of 45ms¹. The balls met at a point where the velocity of B is 1.8 times the velocity of A. Calculate (a) the velocities of A and B when they meet. (b) when the two balls meet. (c) where the two ball meet. (g = 10 ms²)
vr>vs because the rolling ball acquires rotational as well as translational kinetic energy.
The accelerating force acting on the ball as it goes along a smooth plane is mgsin. Its acceleration is therefore equal to gsin. The mgsin acts down the plane as the ball travels down the rough inclined plane, but friction develops that acts up the plane.
Since both balls' potential energy is lost at the same rate, their KEs are actually equal at the base of the planes. However, a ball sliding down a smooth plane has only translational kinetic energy, but a ball rolling down a rough plane contains both translational and rotational kinetic energy at the bottom of the plane. As a result, the ball's translational KE will be lower than its translational Kinetic energy.
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What is the x-component of a vector with a magnitude of 115 km at an angle of 22°?
The x-component of a vector are < 106.6, 43.07 >
Depending on the angle we are provided, the x-component of a vector can either be cos or sin. Cos always corresponds to the right triangle's side that contacts the specified angle.
If a vector v with magnitude ||v|| makes an angle θ with the positive x-axis then,
v = ||v|| cos θi + ||v|| sin θj
= < ||v|| cos θ , ||v|| sin θ >
Magnitude p = 115 km
Angle = 22°
p = ||p|| < cos θ, sin θ >
p = 115 < cos 22°, sin 22° >
p = 115 < 0.927, 0.3746 >
p = < 106.6, 43.07 >
Therefore, the x-component of a vector are < 106.6, 43.07 >
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Using a schematic diagram, explain the steps of the laser technique.
The steps of the use of the laser technique is explained below:
A laser beam is emitted from the diode in the unit and spread into a laser plane (1). The laser plane, appearing as a line on the sphere (2), is reflected and collected by dual CCD arrays (1). The resulting 2D profile is digitized and as the unit travels along the x-axis of the object, multiple profiles are collected yielding a 3D coordinate point cloud of the surface (3). What is a Laser Technique?This refers to the type of surgery that makes use of special light beams in order to cut open the human body in a surgical procedure.
Hence, we can see that the laser technique is considered safer than conventional surgical methods.
Laser techniques include:
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when a branding iron gets heated in a fire the handle becomes hot, how is the energy transferred to the handle
Conduction is a process through which energy is transferred from the branding iron to the handle.
When two objects with different surface temperatures come into close touch with one another, conduction happens. Up until they reach thermal equilibrium, or the point at which they are at the same temperature, the heat energy moves from the hotter to the cooler object.
The metal tip of the branding iron, which makes contact with the branded surface, becomes extremely hot when it is placed in the fire because of the high fire temperature.
Hence, conduction is a process through which energy is transferred from the branding iron to the handle.
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Thanks to the direction finding feature in gmaps application, which most of us use, we can find our way. Here, the maps application offers us alternative routes. Among these suggestions, I want to choose the path that will have the least fuel and do this based on calculations. For example, one of the two directions may be short, but if that short route is also uphill, it will not be an economical route. In my opinion the most important factor is elevation. If we take elevation into account other factors such as friction, where assuming the same asphalt type is often used in the same area for friction, I think the correct result will be achieved. In your opinion, what are the input data required to find the least energy path, what assumptions can be made and what are the necessary formulations and calculations?
In my opinion, I think that the input data that are required to find the least energy path are:
ElevationDistanceWhat is a Map?This refers to the use of a diagram to represent the features of a place that shows its physical landforms to help in navigation.
Hence, we can see that when using maps like gmaps, it is important to consider both elevation and distance to be able to find the path that uses the least energy.
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Two spheres with uniform surface charge density, one with a radius of 7.4 cm and the
other with a radius of 5.0 cm, are separated by a center-to-center distance of 38 cm. The
spheres have a combined charge of +55μC and repel one another with a force of 0.62 N.
Assume that the charge of the first sphere is greater than the charge of the second sphere.
Question 1.
What is the surface charge density in the sphere of radius 7.4?
Question 2
What is the surface density on the 2nd sphere?
EXPRESS ANSWER USING TWO SIGNIFICANT FIGURES.
(a) The surface charge density in the sphere of radius 7.4 is 0.0322 C/m³.
(b) The surface density on the 2nd sphere is 3.48 x 10⁻⁴ C/m³.
Total charge of the spheresF = kq₁q₂/r²
Fr² = kq₁q₂
q₁q₂ = Fr²/k
where;
r is distance between the chargesk is Coulomb's constantq₁q₂ = (0.62 x 0.38²) / (9 x 10⁹)
q₁q₂ = 9.95 x 10⁻¹² C
q₂ = 9.95 x 10⁻¹² C/q₁
From the question;
q₁ + q₂ = 55 x 10⁻⁶
q₁ + 9.95 x 10⁻¹² /q₁ = 55 x 10⁻⁶
q₁² + 9.95 x 10⁻¹² = 55 x 10⁻⁶q₁
q₁² - 55 x 10⁻⁶q₁ + 9.95 x 10⁻¹² = 0
solve the quadratic equation using formula method;
q₁ = 5.48 x 10⁻⁵ C
q₂ = 55 x 10⁻⁶ C - 5.48 x 10⁻⁵ = 1.82 x 10⁻⁷ C
Volume of the first sphereV1 = ⁴/₃πr³
V1 = (⁴/₃ π)(0.074)³ = 1.7 x 10⁻³ m³
Surface charge density = (5.48 x 10⁻⁵ C) / (1.7 x 10⁻³ m³) = 0.0322 C/m³
Volume of the second sphereV2 = (⁴/₃ π)(0.05)³ = 5.236 x 10⁻⁴ m³
Surface charge density = ( 1.82 x 10⁻⁷ C) / (5.236 x 10⁻⁴ m³) = 3.48 x 10⁻⁴ C/m³
Thus, the surface charge density in the sphere of radius 7.4 is 0.0322 C/m³.
The surface density on the 2nd sphere is 3.48 x 10⁻⁴ C/m³.
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What is the minimum work needed to push a 950- kg car 700 m up along a 8.5 ∘ incline? Ignore friction.
Express your answer with the appropriate units.
The minimum work needed to pus the cart up the inclined plane is 960000 J.
What is work done on a inclined plane?The work done on a inclined plane is given below as:
Work done = force * distanceDistance = 700 m
The force on an inclined plane, F = mgsinθ
where;
m is mass in kg
g = 9.81 m/s²
θ = 8.5°
Work done = 950 * 9.81 * sin 8.5 * 700
Work done = 960000 J
Therefore, minimum work needed is 960000 J.
In conclusion, the work done is a product of force and distance.
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(b) The particle displacement y of air molecules due to a sound wave is given by y 4m and w = = 0.008 cos wt sin kz. Where k - m 50m rad/s. calculate i. The distance between two consecutive nodes ii. The amplitude after 0.56s
The distance between two consecutive nodes and the amplitude after 0.56s are m/2 and 1.75×10^(-4) m respectively.
What's the distance between consecutive nodes of the displacement of air molecules?Wavelength is the distance between two consecutive nodes or toughs or crests or anti-nodes.So, distance between consecutive nodes = wavelength = 2π÷k= 2π/(4π÷m)
= m/2
What's the amplitude after 0.56s of the displacement of air molecules?Displacement after 0.56 s = 0.008×cos(50π×0.56s)
=1.75×10^(-4) m
Thus, we can conclude that the distance between consecutive nodes and displacement after 0.56 s are m/2 and 1.75×10^(-4) m respectively.
Disclaimer: The question was given incomplete on the portal. Here is the complete question.
Question: The particle displacement y of air molecules due to a sound wave is given by y=0.008coswtsinkz where k=4π÷m and w=50π rads/s.
Calculate:
I) the distance between 2 consecutive nodes
ii) the amplitude after 0.565s
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A 850-kg sports car accelerates from rest to 95 km/h in 6.8 s .
What is the average power delivered by the engine?
Express your answer to two significant figures and include the appropriate units.
From the calculations, the power expended is 43650 W.
What is the power expended?Now we can find the acceleration from;
v = u + at
u = 0 m/s
v = 95 km/h or 26.4 m/s
t = 6.8 s
a = ?
Now
v = at
a = v/t
a = 26.4 m/s/ 6.8 s
a = 3.88 m/s^2
Force = ma = 850-kg * 3.88 m/s^2 = 3298 N
The distance covered is obtained from;
v^2 = u^2 + 2as
v^2 = 2as
s = v^2/2a
s = (26.4)^2/2 * 3.88
s = 696.96/7.76
s = 90 m
Now;
Work = Fs
Work = 3298 N * 90 m = 296820 J
Power = 296820 J/ 6.8 s
= 43650 W
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what do u mean by the velocity ratio of lever is four
Answer:
VR = Velocity of effort / Velocity of Load
Explanation:
The ratio of the out-lever to the in-lever (length of the resistance arm to effort arm) is known as the velocity ratio (VR). It indicates that the distance covered by effort is four times that covered by the load.
The load-to-effort ratio of a machine, or alternatively, the output-to-input ratio of a machine, is known as its mechanical advantage. Another definition of velocity ratio is the ratio of the velocity of effort to the velocity of load.
When a machine has a force ratio of 4 and a velocity ratio of 4, this indicates that the weight moved is multiplied by 4 and the distance moved by the effort is multiplied by 4 at the same time.
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How many bytes of memory space are there in an 80 GB hard disk and 256 GB card?
Answer:
80GB= 80000000000 bytes
256GB= 274877906944 bytes
Explanation:80GB= 80000000000 bytes
256GB= 274877906944 bytes
A 41-kg pole vaulter running at 10 m/s vaults over the bar. Her speed when she is above the bar is 1.5 m/s. Neglect air resistance, as well as any energy absorbed by the pole, and determine her altitude as she crosses the bar.
Answer:
___________m
The altitude of the pole vaulter as she crosses the bar is 5 m.
The altitude of the barv² = u² - 2gh
where;
v is final velocity of the pole vaulteru is the initial velocity of the pole vaulterh is altitude of the barh = (u² - v²)/2g
h = (10² - 1.5²)/(2 x 9.8)
h = 5 m
Thus, the altitude of the pole vaulter as she crosses the bar is 5 m.
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In the given figure, weight of stone inside water
is 9N and water displaced by stone is 2N then,
i)What is the actual weight of stone?
ii) Which principle is the
experiment based on?
The actual weight of the stone is 11 N. It is based on the Archimedes principles.
What is Archimedes principle?Archimedes principle states that the up thrust by water on an object is equal to the weight of water displaced.Upthrust by water on an object= actual weight of object - weight inside waterWhat is the actual weight of the object, if its weight inside water is 9N and weight of water displaced is 2N?Actual weight= weight inside water+ weight of water displaced
= 9N + 2N = 11N
Thus, we can conclude that the actual weight of the object is 11N.
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What is formed when 2 or more elements combine chemically
Answer:
compound
Explanation:
a substance made from two or more different elements that have been chemically joined. Examples of compounds include water (H2O), which is made from the elements hydrogen and oxygen, and table salt (NaCl), which is made from the elements sodium and chloride.
Help me please.
A
B
C
D
I will go to school tomorrow .....is this present tense or past tense or future tense
Answer:
D
Explanation:
The given vector can be broken down into two components (as shown in the figure).
Which results ; vector (s) = 3x + 4y.
in a motor, what do the combined effect of electric currents and magnetic forced turn electrical energy into?
mechanical energy
a battery
electromagnetic energy
a generator
(please explain too)
A lead weight falls from a height of 6 m onto a muddy surface. It comes to rest after penetrating 0.4 cm into the surface. What was the magnitude of the average acceleration during the impact? How long did it take to stop?
(Also can I have like a little explanation :))
The the magnitude of the average acceleration during the impact is 9.8 m/s² and the time of motion is 1.11 s.
Average acceleration of the lead weight during the impactThe lead weight will fall under the influence of gravity with magnitude of 9.8 m/s².
Time of motion of the lead weightt = √2h/g
where;
h is the total height of fall, h = 6 m + 0.4 cm = 6.004 mg is acceleration due to gravityt = √((2 x 6.004)/9.8)
t = 1.11 s
Thus, the the magnitude of the average acceleration during the impact is 9.8 m/s² and the time of motion is 1.11 s.
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In 1656, the Burgmeister (mayor) of the town of Magdeburg, Germany, Otto Von Guericke, carried out a dramatic demonstration of the effect resulting from evacuating air from a container. It is the basis for this problem. Two steel hemispheres of radius 0.430 m (1.41 feet) with a rubber seal in between are placed together and air pumped out so that the pressure inside is 15.00 millibar. The atmospheric pressure outside is 940 millibar.
1. Calculate the force required to pull the two hemispheres apart. [Note: 1 millibar=100 N/m2. One atmosphere is 1013 millibar = 1.013×105 N/m2 ]
2. Two equal teams of horses, are attached to the hemispheres to pull it apart. If each horse can pull with a force of 1450N (i.e., about 326 lbs), what is the minimum number of horses required?
The force required to pull the two hemispheres apart 53696.25N and the minimum number of horses required is 37 .
( Note: 1 millibar=100 N/m2. One atmosphere is 1013 millibar = 1.013×105 N/m2 )
(1)The contact area between the hemispheres is (π x 0.430²) = 0.5805m²
Pressure difference = (940 - 15) = 925millibars.
(925 x 100) = 92,500N/m^2.
(92500 x 0.5805) = 53696.25N. is the force required to part the hemispheres.
(2)[tex]\frac{53696.25N}{1450N}[/tex] = 37 horses for each side .
37 + 37 = 74 horses will be required.
Force is something which can change the motion of an object, stop it or move it, change its shape or size with it. There are two types of forces, contact forces and non-contact forces. Here, it is a contact force at first, then when the horses come it becomes non-contact force.
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If the voltage between 2 plates is 30 V and the electric field strength is 10 V/m, what is the separation distance between the plates?
A. 10 m
B. 2 m
C. 3 m
D. 30 m
A particle with a mass of 1.98×10^−4 kg carries a negative charge of -3.50×10^−8 C. The particle is given an initial horizontal velocity that is due north and has a magnitude of 3.78×10^4 m/s.
a) What is the magnitude of the minimum magnetic field that will keep the particle moving in the earth's gravitational field in the same horizontal, northward direction?
b) What is the direction of the minimum magnetic field?
(a) The magnitude of the minimum magnetic field is 1.467 T.
(b) The direction of the minimum magnetic field will be eastwards.
Minimum magnetic fieldF = qvB
mg = qvB
B = mg/qv
where;
B is magnetic fieldv is velocitym is mass of the particleq is charge of the particleB = (1.98 x 10⁻⁴ x 9.8) / (3.5 x 10⁻⁸ x 3.78 x 10⁴)
B = 1.467 T
Direction of the magnetic fieldThe magnetic field will be directed towards the negative charge. Thus, the direction of the minimum magnetic field will be eastwards.
Thus, the magnitude of the minimum magnetic field is 1.467 T and the direction is eastwards.
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Why is infinity the zero point for electric potential energy true?
A. Electric field strength is zero at the charge
B. Electric field strength is zero at infinity
C. Not enough info
D. Electric field strength is zero somewhere in the middle
Infinity is the zero point for electric potential energy because Electric field strength is zero at infinity.
This conclusion is not "derived" from anything else; the electrostatic potential is zero at infinity because that is how we define it.
Define electric field and electric field strength.
The physical field that contains electrically charged particles and pulls or attracts all other charged particles in the vicinity is known as an electric field. Additionally, it describes the physical environment of a system of charged particles.
The intensity of an electric field at a specific location is expressed quantitatively as "electric field strength." The volt per meter (v/m or v m-1) is the common unit.
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