what is 5.73 as a mixed number​

Answer:

x = 3, x = -5

Step-by-step explanation:

A perfect square trinomial is represented in the form a^2 + 2ab + b^2. We are already given the a^2 term, x^2, and the 2ab term, 2x. From this we can say:

a^2 = x^2

a = x

Now, we can substitute x for a in the other expression to create the equation:

2ab = 2x

2(x)b=2x

b = 1

From this, b^2 is one, so, to get our trinomial all on one side, we add 1 to both sides:

x^2 + 2x = 15

x^2 + 2x + 1 = 16

Now, we can factor. The perfect square trinomial factors into (a + b)^2. In this case, a is x, and b is one. We can factor and get:

(x + 1)^2 = 16

Now, we take the square root of both sides:

x + 1 = ± 4

We can separate this into two equations and solve:

x + 1 = 4

x = 3

x + 1 = -4

x = -5

Answer:

Step-by-step explanation:

x^2 + 2x = 15

x^2 + 2x + [1/2(2)]^2 = 15 +  [1/2(2)]^2

(x + 1/2(2) )^2 = 15 + [(1/2)(2)]^2

(x + 1)^2 = 15 + 1^2

(x + 1)^2 = 15 + 1

(x+1)^2 = 16                       Take the square root of both sides.

sqrt( (x + 1)^2 ) = sqrt(16)

x + 1 = +/- 4

x + 1 = 4

x = 4 - 1 = 3

x + 1 = -4

x = -4 - 1

x = - 5

So the roots are 3 and - 5

Answer:

the answer is c

Step-by-step explanation:

Answer:

z (max)  =  1250 $

x₁  = 25    x₂  =  0   x₃  =  25

Step-by-step explanation:

                                Profit $    mach. 1      mach. 2

Product 1     ( x₁ )       30             0.5              1

Product 2    ( x₂ )       50             2                  1

Product 3    ( x₃ )       20             0.75             0.5

Machinne 1 require  2 operators

Machine   2 require  1  operator

Amaximum of  100 hours of labor available

Then Objective Function:

z  =  30*x₁  +  50*x₂  +  20*x₃      to maximize

Constraints:

1.-Machine 1 hours available  40

In machine 1    L-H  we will need

0.5*x₁  +  2*x₂  + 0.75*x₃  ≤  40

2.-Machine 2   hours available  40

1*x₁  +  1*x₂   + 0.5*x₃   ≤  40

3.-Labor-hours available   100

Machine 1     2*( 0.5*x₁ +  2*x₂  +  0.75*x₃ )

Machine  2       x₁   +   x₂   +  0.5*x₃  

Total labor-hours   :  

2*x₁  +  5*x₂  +  2*x₃  ≤  100

4.- Production requirement:

x₁  ≤  0.5 *( x₁ +  x₂  +  x₃ )     or   0.5*x₁  -  0.5*x₂  -  0.5*x₃  ≤ 0

5.-Production requirement:

x₃  ≥  0,2 * ( x₁  +  x₂   +  x₃ )  or    -0.2*x₁  - 0.2*x₂ + 0.8*x₃   ≥  0

General constraints:

x₁  ≥   0       x₂    ≥   0       x₃     ≥   0           all integers

The model is:

z  =  30*x₁  +  50*x₂  +  20*x₃      to maximize

Subject to:

0.5*x₁  +  2*x₂  + 0.75*x₃  ≤  40

1*x₁  +  1*x₂   + 0.5*x₃       ≤  40

2*x₁  +  5*x₂  +  2*x₃        ≤  100

0.5*x₁  -  0.5*x₂  -  0.5*x₃  ≤ 0

-0.2*x₁  - 0.2*x₂ + 0.8*x₃   ≥  0

x₁  ≥   0       x₂    ≥   0       x₃     ≥   0           all integers

After 6 iterations with the help of the on-line solver AtomZmaths we find

z (max)  =  1250 $

x₁  = 25    x₂  =  0   x₃  =  25

Step-by-step explanation:

Consider Similarity and enlargement

To get the enlargement factor,

Take the ratio result of any two similar sides. i.e

PQ/AB = 3.6/2 = 1.8

The enlargement factor is 1.8

To get ST, consider ED then multiply it by the enlargement factor. i.e

= 5 x 1.8

= 9

Answer:

In 2 2/5 hours, he will cover 20 km.

Step-by-step explanation:

Given that,

Ahmed can 8 1/3 km in one hour.

We need to find the distance he cover in 2 2/5 h.

In 1 hour = 8 1/3 km = 25/3 km

2 2/5 hour means 12/5 hour

In 12/5 hour = 12/5 × 25/3 km

= 20 km

So, in 2 2/5 hours, he will cover 20 km.

Answer:

1.019 is the answer

Answer:

197 in^2

Step-by-step explanation:

Add the areas of each face:

2 trapezoid faces:

(5+9) ÷ 2 x 5 = 35

2(35) = 70 in^2

2 squares:

5 x 5 = 25

2(25) = 50 in^2

Rectangular base:

5 x 9 = 45 in^2

Area of slanted rectangle:

6.4 x 5 = 32 in^2

Add:

32 + 45 + 50 + 70 = 197

Answer:

f(-2) = g(-2) this is the answer

Answer:

C. (5,1)

Step-by-step explanation:

10x+5y=55 equation 1

y-2x=-9 equation 2

y=-9+2x isolate y in equation 2

10x+5(-9+2x)=55 substitute value of y from equation 2 into equation 1

10x-45+10x=55

20x=100

x=5

solve for y by using x value (5) in either equation

y-2x=-9

y-2(5)=-9

y-10=-9

y=1

Answer:

What’s the numbers? Or the question?

Step-by-step explanation:

Answer:

Dependent Equations

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Algebra I

Step-by-step explanation:

Step 1: Define Systems

y = 5x

20x - 4y = 0

Step 2: Solve for x

Substitution

Here we see 0 does indeed equal 0.

∴ our systems has an infinite amount of solutions.

Answer:

0

Step-by-step explanation:

y = 5x

substitute the value of y in equation

multiply to get 20x

collect like terms

we can see here that 0 indeed equal 0.

so, system has an infinite solutions.

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

The attachment shows the table of point values and the graph.

Answer:

-2

Step-by-step explanation:

Slope formula for any given two points

(y2 - y1 / x2 - x1)

The points chosen may vary but the points I chose were (0,1) and (2,-3)

Our next step is to identify the variables

y2 = -3

y1 = 1

x2 = 2

x1 = 0

We then plug in the values into the slope formula

slope = ( -3 - 1 ) / ( 2 - 0 )

Simply

Slope = -4 / 2

Simply even further

Slope = -2

the slope of each line is -2.

Answer:

Solution Given:

let's find out the given points.

1st point[tex] (x_1,y_1)=(0,1)[/tex]

another point is:

[tex](x_2,y_2)=(2,-3)[/tex]

now

By using slope formula

[tex] \green{\boxed{m=\frac{y_2-y_1}{x_2-x_1}}}[/tex]

now

substituting value

we get

m=[tex]\frac{-3-1}{2-0}=\frac{-4}{2}=-2[/tex]

Answer:

x = 2

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Distributive Property

Equality Properties

Algebra I

Step-by-step explanation:

Step 1: Define

Identify

2(x + -5) + x = x + (-6)

Step 2: Solve for x

Answer:

x=2 ( see Image below)

Step-by-step explanation:

cancel equal terms on both sides of the equation

2(x-5)=-6

move the constant to the right -hand side and change its sign

2x= -6 +10

Calculate the sum

2x=4

divide both sides of the equation by 2

x=2

Answer:

[tex]\frac{4}{15}[/tex] of a gallon per bottle

Step-by-step explanation:

1 - [tex]\frac{1}{5}[/tex] = [tex]\frac{4}{5}[/tex]

[tex]\frac{4}{5}[/tex] / 3 = [tex]\frac{4}{5}[/tex] x [tex]\frac{1}{3}[/tex] = [tex]\frac{4}{15}[/tex]

Answer:

Problem 20)

[tex]\displaystyle \frac{dy}{dx}=(\cos x)^x\left(\ln \cos x-x\tan x\right)[/tex]

Problem 21)

A)

The velocity function is:

[tex]\displaystyle v(t) =2\pi(\cos(2\pi t)-\sin(\pi t))[/tex]

The acceleration function is:

[tex]\displaystyle a(t)=-2\pi^2(2\sin(2\pi t)+\cos(\pi t))[/tex]

B)

[tex]s(0)=2\text{, }v(0) = 2\pi \text{ m/s}\text{, and } a(0) = -2\pi^2\text{ m/s$^2$}[/tex]

Step-by-step explanation:

Problem 20)

We want to differentiate the equation:

[tex]\displaystyle y=\left(\cos x\right)^x[/tex]

We can take the natural log of both sides. This yields:

[tex]\displaystyle \ln y = \ln((\cos x)^x)[/tex]

Since ln(aᵇ) = bln(a):

[tex]\displaystyle \ln y =x\ln \cos x[/tex]

Take the derivative of both sides with respect to x:

[tex]\displaystyle \frac{d}{dx}\left[\ln y \right]=\frac{d}{dx}\left[x \ln \cos x\right][/tex]

Implicitly differentiate the left and use the product rule on the right. Therefore:

[tex]\displaystyle \frac{1}{y}\frac{dy}{dx}=\ln \cos x+x\left(\frac{1}{\cos x}\cdot -\sin(x)\right)[/tex]

Simplify:

[tex]\displaystyle \frac{1}{y}\frac{dy}{dx}=\ln \cos x-\frac{x\sin x}{\cos x}[/tex]

Simplify and multiply both sides by y:

[tex]\displaystyle \frac{dy}{dx}=y\left(\ln \cos x-x \tan x\right)[/tex]

Since y = (cos x)ˣ:

[tex]\displaystyle \frac{dy}{dx}=(\cos x)^x\left(\ln \cos x-x\tan x\right)[/tex]

Problem 21)

We are given the position function of a particle:

[tex]\displaystyle s(t)= \sin (2\pi t)+2\cos(\pi t)[/tex]

A)

Recall that the velocity function is the derivative of the position function. Hence:

[tex]\displaystyle v(t)=s'(t)=\frac{d}{dt}[\sin(2\pi t)+2\cos(\pi t)][/tex]

Differentiate:

[tex]\displaystyle \begin{aligned} v(t) &= 2\pi \cos(2\pi t)-2\pi \sin(\pi t)\\&=2\pi(\cos(2\pi t)-\sin(\pi t))\end{aligned}[/tex]

The acceleration function is the derivative of the velocity function. Hence:

[tex]\displaystyle a(t)=v'(t)=\frac{d}{dt}[2\pi(\cos(2\pi t)-\sin(\pi t))][/tex]

Differentiate:

[tex]\displaystyle \begin{aligned} a(t)&=2\pi[-2\pi\sin(2\pi t)-\pi\cos(\pi t)]\\&=-2\pi^2(2\sin(2\pi t)+\cos(\pi t))\end{aligned}[/tex]

B)

The position at t = 0 will be:

[tex]\displaystyle \begin{aligned} s(0)&=\sin(2\pi(0))+2\cos(\pi(0))\\&=\sin(0)+2\cos(0)\\&=(1)+2(1)\\&=2\end{aligned}[/tex]

The velocity at t = 0 will be:

[tex]\displaystyle \begin{aligned} v(0)&=2\pi(\cos(2\pi (0)-\sin(\pi(0))\\&=2\pi(\cos(0)-\sin(0))\\&=2\pi((1)-(0))\\&=2\pi \text{ m/s}\end{aligned}[/tex]

And the acceleration at t = 0 will be:

[tex]\displaystyle \begin{aligned} a(0) &= -2\pi ^2(2\sin(2\pi(0))+\cos(\pi(0)) \\ & = -2\pi ^2(2\sin(0)+\cos(0)) \\ &= -2\pi ^2(2(0)+(1)) \\ &= -2\pi^2(1) \\ &= -2\pi^2\text{ m/s$^2$} \end{aligned}[/tex]

Answer:

82.31

Step-by-step explanation:

I believe this is correct, if it isn't feel free to let me know and I will fix it. I'm sorry in advance if this is incorrect.

Answer:

The probability of obtaining a sample mean less than or equal to $8.85 per hour=0.0082

Step-by-step explanation:

We are given that

Average wage, [tex]\mu=[/tex]$9.00/hour

Standard deviation,[tex]\sigma=[/tex]$0.50

n=64

We have to find the  probability of obtaining a sample mean less than or equal to $8.85 per hour.

[tex]P(\bar{x} \leq 8.85)=P(Z\leq \frac{\bar{x}-\mu}{\frac{\sigma}{\sqrt{n}}})[/tex]

Using the values

[tex]P(\bar{x}\leq 8.85)=P(Z\leq \frac{8.85-9}{\frac{0.50}{\sqrt{64}}})[/tex]

[tex]P(\bar{x}\leq 8.85)=P(Z\leq \frac{-0.15}{\frac{0.50}{8}})[/tex]

[tex]P(\bar{x}\leq 8.85)=P(Z\leq -2.4)[/tex]

[tex]P(\bar{x}\leq 8.85)=0.0082[/tex]

Hence, the probability of obtaining a sample mean less than or equal to $8.85 per hour=0.0082

The median penguin height is greater at Cityview Zoo than at Park

Zoo, Option C is correct.

Mode is the most occuring number.

The range is the difference of the highest value and the lowest value.

The median is the middle value in a set of data

After finding the range and medians of the given data.

The median penguin at Cityview Zoo is 42 cm tall,

The median penguin at Park Zoo is barely 41 cm tall.

Cityview Zoo's median penguin height is higher than that of Park Zoo.

Hence, the median penguin height is greater at Cityview Zoo than at Park Zoo.

To learn more on Statistics click:

https://brainly.com/question/30218856

#SPJ7

Answer:

zinc is 20grams

Step-by-step explanation:

Given data

Ratio copper :zinc = 3:2

Copper =30 grams

Applying the ratio

3/2=30/x

Cross multiply

3x=30*2

3x=60

Divide both sides by 3

x=60/3

x=20

Hence zinc is 20grams

Answer:

if they are parallel it would almost be opposite but they would be negative instead of positive

f=3s

f = the amount of flour

Hope this helps! :)

Answer:

The gain percent is 33.3 %

Step-by-step explanation:

Let the selling price of 1 m cloth is p.

Cost of 33 m = 33 p

gain = cost of 11 m = 11 p  

The gain percentage is given by

[tex]\frac{11 p}{33 p}\times 100\\\\= 33.3 %[/tex]

The gain percent is 33.3 %.

Answer:

SAS

Step-by-step explanation:

AC ≅ EC (Given), ∠ACB ≅∠ECD ( Vertical Angles), and BC ≅ DC

Answer:

B and C are the same angles so if B is 60 so is C

Answer:

b= 60

c= 60

Step-by-step explanation:

<b and 120 form a straight line so the add to 180

b+120 =180

b = 180-120

b = 60

angles b and c are alternate interior angles so they are equal

b = c= 60

9514 1404 393

Answer:

Step-by-step explanation:

An angle can be found using the Law of Cosines.

  c² = a² +b² -2ab·cos(C)

  C = arccos((a² +b² -c²)/(2ab)) = arccos((16² +30² -35²)/(2·16·30))

  C = arccos(-69/960) ≈ 94.1217°

Then another angle can be found using the Law of Sines:

  sin(B)/b = sin(C)/c

  B = arcsin(b/c·sin(C)) ≈ 57.7516°

The third angle can be found from the sum of angles of a triangle.

  A = 180° -94.1217° -58.7516° = 27.1267°

The angles of the triangle are about (A, B, C) = (27.1°, 57.8°, 94.1°).

Answer:

Step-by-step explanation:

1 . Sphere :

    [tex]Surface \ Area = 4\pi r^2\\\\ Volume = \frac{4}{3} \pi r^3[/tex]

  Variable is ' r '

  Others Constants.

2. Cone :

   [tex]Surface \ Area = \p r^2 + \pi rs[/tex]          [tex][ \ s = \sqrt { r^2 + h^2 } \ , r = base \ radius, h = height \ ][/tex]

    [tex]Volume = \frac{1}{3} \pi r^2 h[/tex]

   Variables are ' r ' and ' h '

   Others constants.

3. Cuboid ( Rectangular Prism )

   [tex]Surface \ Area = 2 ((l\times b) + ( b \times h) + ( l \times h)) \\\\Volume = l \times \ b \times \ h[/tex]

   Variables : l , b , h

   Constant is 2

4.  Cylinder

     [tex]Surface \ Area = 2 \pi r h + 2 \pi r^2 \\\\Volume = \pi r^2 h[/tex]

    Variables : ' r  ' and ' h '

   Others constants..

Answer:

shapes. cuboid. cube. cylinder. prism. sphere. pyramid. rightcircularcone. volumeformula. l×w×h. v=a . 3. v=πr . 2. h. v=b×h. v=( 3. 4)πr . 3. v=( 3. 1)×h×b. v=( 3. 1)πr . 2. h. variables. l=length,w=width,h=height. a=side. r=radius,h=height. b=base,h=height. r=radiusofthesphere. b=areaofthebase,h=heightofthepyramid. r=radiusofthecircularbase,h=height

Step-by-step explanation: