Answer:
the system of electrons surrounding the nucleus of an atom
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A cable pulls a car up a mountain with a force of 4 × 103 N at a vertical constant velocity of 5 m.s-1. It takes 5 minutes to reach the top.
(a)How much work is done in getting the car to the top?
(b)How much work would have been done if the vertical speed was 2,5 m.s-1?
(c)Calculate the power exerted on the cable car in those 5 minutes.
Answer:
(a) 6,000,000J
(b) 3,000,000J
(c) For A 20,000W
But for B 10,000W
The work done in getting the car to the top is equal to 6 ×10⁶ J. If the vertical speed is 2.5 m/s then, the work done will be 3 ×10⁶ J. The power exerted on the car is in 5 minutes is 20000 J/s.
What is work done ?In physics, work done is the dot product of force and displacement. Let w be the work done and F and ds be the force and displacement. Then
W = F.ds
It is given that the, the force of the cable is 4 × 10³ N. The velocity is 5 m/s and time is 5 minutes or 300 seconds. Now, the displacement is the product of time and velocity.
ds = velocity × time
= 300 s × 5 m/s
= 1500 m.
Thus the work done = F × ds
= 4 × 10³ N × 1500 m
= 6 ×10⁶ J .
If the velocity is reduced to half 2.5 m/s , then work done will be reduced to half as 3 ×10⁶ J.
Power is the rate of work done. Thus it is the ratio of work done to time. The power exerted on the car in 5 minutes = 6 ×10⁶ J /300s
= 20000 J/s
Hence, the power exerted on the cable car in 5 minutes is 20000 J/s.
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Emma travels at a speed of 23 miles per hour for 3.5 hours. How far has she travelled?
Answer: 80.5 miles
Explanation:
3.5 x 23 = 80.5
What is a milliliter.
A milliliter, abbreviated as ml or mL, is a unit of volume in the metric system. One milliliter is equal to one thousandth of a liter, or 1 cubic centimeter. In the imperial system, that's a small amount: . 004 of a cup
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Answer:
Where is the picture send again please
Explanation:
what metaphor most closely describes the nature of space-time?
a. chemistry formula
b.fabric
c. sine wave
d. moebius strip
Answer:
b.fabric
Explanation:
Nowadays, when people talk about space-time, they often describe it as resembling a sheet of rubber. This, too, comes from Einstein, who realized as he developed his theory of general relativity that the force of gravity was due to curves in the fabric of space-time.
Answer:
B. fabric
Explanation:
Which of the following is NOT an indicator of a chemical reaction?
OPTIONS
A. A phase change
B. A temperature change
C. A color change
D. A gas being created
Answer:
c
Explanation:
The changing of color of a substance is not necessarily an indicator of a chemical change. For example, changing the color of a metal does not change its physical properties. However, in a chemical reaction, a color change is usually an indicator that a reaction is occurring.
When is there no atmospheric pressure pjysics.
What would be the extension of the spring for a 3 N weight if the extension of the spring was 4 mm for a 50 g mass?
А 4 mm B)8 mm C)12mm D)24 mm
Answer:
24mm
Explanation:
3 N to g is 305.9 g
50g ---- 4 mm
305.9 ----- 4×305.9/50 = 24 mm
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Imagine that a car is speeding down the highway and it hits a large bump in the road that forces it off the road. What would Newton call that object?
A.
a physical object
B.
a course interrupter
C.
an unbalanced force
D.
an unfortunate event
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Answer:
C. unbalanced force
Explanation:
it is called unbalanced force because it has changed direction of the moving object
I need help in question 7, a and b.
Answer:
The graph for 7a is shown in the attachment. For question 7b she walks a distance of 16 meters. (m)
Explanation:
A copper (Young's modulus 1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to end, as in the drawing. Each cylinder has a radius of 0.24 cm. A compressive force of F = 7900 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack decreases.
We have that for the Question, it can be said that the amount by which the length of the stack decreases is
[tex]dl'=3.621*10^{-4}m[/tex]
From the question we are told
A copper (Young's modulus 1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to end, as in the drawing. Each cylinder has a radius of 0.24 cm.
A compressive force of F = 7900 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack decreases.
Generally the equation for copper cylinder is mathematically given as
[tex]dl=\frac{Flo}{yA}[/tex]
[tex]dl=\frac{7900*3*10^-^2}{1.1*10^{11}*\pi(0.24*10^{-2})^2}[/tex]
[tex]dl=1.19064778*10^-^4[/tex]
Generally the equation for brass cylinder is mathematically given as
[tex]dl=\frac{7900*5*10^-^2}{9*10^{10}*\pi(0.24*10^{-2})^2}[/tex]
[tex]dl=2.43*10^{-4}[/tex]
Therefore Total change in length
[tex]dl'=1.191*10^-^4+(2.43*10^{-4})[/tex]
[tex]dl'=3.621*10^{-4}m[/tex]
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a 1200-kg pick-up truck traveling south at 15 m/s suddenly collides with a 750-kg car that is traveling east. the two vehicles stick together and slide along the road after colliding. a highway patrol officer investigating the accident determines that the final position of the wreckage after the collision is 25 m, at an angle of 50° south of east, from the point of impact. she also determines that the coefficient of kinetic friction between the tires and the road at that location was 0.40. what was the speed of the car just before the collision?
The conservation of momentum, Newton's second law and kinematics allows to find the result for the initial speed of the car is:
The speed of the car is 40 m/s at the East direction.
Given parameters
Mass of the truck M = 1200 kg. Truck speed v₀₁ = 15 m / s towards the South. Mass of the car m = 750 kg. Travel east The two vehicles unite. The braking distance d = 25m at 50º SE The friction coefficient μ = 0.40To find
The initial speed of the car.
The momentum is defined by the product of the mass and the velocity of the body, so it is a vector quantity. In the case of an isolated system the momentum is conserved.
In the attachment we see a diagram of the vehicle crash, let's write the moment for each axis.
y-axis
Initial instant. Before the shock.
[tex]p_{oy}[/tex] = M v₀₁
Final moment. After the crash
[tex]p_{fy}[/tex] = (M + m) [tex]v_{fy}[/tex]
The system is formed by the two vehicles for which during the crash it is isolated and the momentum is conserved.
[tex]p_{oy} = p_{fy} \\\\M v_{o1} = (M+m) v_{fy} \\v_{fy} = \frac{M}{M+m} \ v_{o1}[/tex]
Calculate us
[tex]v_{fy} = \frac{1200}{1200+750} \ 15[/tex]
vfx = 9.23 m / s
x-axis
Initial instant. Before the crash.
p₀ₓ = m v₀₂
Final moment. After the crash.
[tex]p_{fx}[/tex] = (M + m) [tex]v_{fx}[/tex]
The momentum is preserved.
[tex]p_{ox}= p_{fx} \\m v_{o2) = (M+m) \ v_{fx}[/tex]
Let's find the velocity just after the collision, let's use Newton's second law,
y-axis
N-W = 0
N = W = (M + m) g
x-axis
fr = (M + m) a
The friction force is the macroscopic manifestation of the interactions between the two bodies.
fr = μ N
We substitute.
μ g = a
Now we can use kinematics.
v² = v₀² - 2a d
When the vehicles stop their speed is zero.
v₀² = 2 a x
v₀ = [tex]\sqrt{2\ \mu \ g \ d}[/tex]
Let's calculate.
v₀ = [tex]\sqrt{2 \ 0.40 \ 9.8 25 }[/tex]
v₀ = 14 m / s
This is the speed of the two vehicles just after the collision, that is, let's use trigonometry to find their components.
cos 25 = [tex]\frac{v_{ox}}{v_o}[/tex]
v₀ₓ = v₀ cos 25
v₀ₓ = 14 cos 25
v₀ₓ = 12.69 m / s
We substitute in the expression of the conservation of the momentum in the x-axis.
m v₀₂ = (M + m) [tex]v_{fx}[/tex]
[tex]v_{o2} = \frac{M+m}{m} v_{fx}[/tex]
Let's calculate.
[tex]v_{o2} = \frac{1200+750}{750} \ 12.69[/tex]
vfy = 32.99 m / s = 40 m / s
In conclusion using the conservation of momentum, Newton's second law and kinematics we can find the result for the initial speed of the car is:
The speed of the car is 40 m/s at the East direction.
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what third force must be added to the two forces 30 Newton at 30 degree and 80 Newton at 135 degree the resolution for equal to zero
Answer:
Resolve the vectors:
F1 = 30 cos 30 i + 30 sin 30 j = 26 i + 15 j
F2 = 80 cos 135 i + 80 sin 135 j = -56.6 i + 56,6 j
F1 + F2 = (26 - 56.6) i + (15 + 56.6) j = -30.6 i + 71.6 j
The offsetting force would be
F3 = 30.6 i - 71.6 j
The magnitude of this vector is (30.6^2 + 71.6^2)^1/2 = 77.9
cos theta 3 = 30.6 / 77.9 = 66.9 deg
Check:
77.9 * sin 66.9 = 71.6 agreeing in magnitude with F3
Now we need the quadrant of the offsetting vector
sin theta 3 = - cos theta 3 = +
This occurs in the fourth quadrant and theta 3 = 360 - 66.9 = 293.1 deg
Change.
Wax melting is an example of a chemical reaction.
True or false
State the universal law of gravitation.
Answer in detail
Answer:
Explanation:
Newton's law of universal gravitation is that every particle attracts every other particle in the universe with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.
what kind of frog species is this
Answer: i think its a bullfrog forgive me if im wrong i dont exactly know
Explanation:
Answer:
that is an African bullfrog
What acceleration occurs if the friction force in #4 is now 4N?
The acceleration of the 20 N force is 6.67 m/s^2. The acceleration of the 4N force is 1.33 m/s^2.
What is force?We define the force that acts on a body as that which is able to cause an acceleration or that which is able to change the direction of an object. Recall that from the Newton first law, an object would continue in its state of rest or uniform motion unless the object is acted upon by an external force.
Now the frictional force is the force that tends to resist the motion of two surfaces that are in contact. Owing to the fact that it is a resistive force its direction is always opposite the force that seeks to move the object forward.
Now;
F = ma
a = F/m
a = 20 N/3Kg
a = 6.67 m/s^2
If the force is 4N;
a = F/m
a = 4N/3Kg
a = 1.33 m/s^2
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Missing parts;
How would you calculate the acceleration if you push with a 20 N horizontal force on a 3 kg block on a horizontal friction-free air table? What is the acceleration if the friction force is 4 N?
Which of the following will require most developed countries to
decrease emissions of carbon dioxide and other greenhouse gases?
a. Montreal Protocol c. Emissions Reduction Act
b. Kyoto Protocol d. Reforestation Project
Answer:
Kyoto Protocol
Explanation:
Waves can be refracted.
Explain this term.
HELP PLSSS
Answer: By "waves can be refracted" they mean that refraction can occur with waves. To better explain, refraction is the "change in direction of a wave passing from one medium to another or from a gradual change in the medium." You probably know this best when you put a pencil inside a glass of water where the pencil bends a bit. The same can happen with sound or water waves as well!
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What is occurring in the umbra?
A. a total solar eclipse
B. a total lunar eclipse
C. a partial lunar eclipse
D. a partial solar eclipse
Answer:
A. a total solar eclipse
Explanation:
During a solar eclipse,the moon comes between the sun and Earth, casting its shadow over the Earth
If 40 N force is exerted by a box covering 2 metre square area, calculate pressure.
[tex]\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}[/tex]
[tex]\\ \sf\longmapsto Pressure=\dfrac{40}{2}[/tex]
[tex]\\ \sf\longmapsto Pressure=20Pa[/tex]
[tex] \sf \huge \red {\dag} Given[/tex]
[tex]\sf \longmapsto \: Force \: = 40 \: Newtons[/tex]
[tex]\sf \longmapsto \: Area \: = \: 2m \: Square \: ( {2m}^{2} )[/tex]
We know that the formula of Pressure is
[tex]\sf \longmapsto \: Force/Area[/tex]
Let's start.
Put the values[tex]\sf \longmapsto \: \: P = 40 \: newtons(force)/2(Area)[/tex]
[tex]\sf \longmapsto Pressure \: 20 \: N/m^2[/tex]
[tex]\boxed{\sf\red{\boxed{ \sf Pressure ≈ \: 20 \: N/m^2}}}[/tex]
What is the given formula for acceleration?.
Answer:
a=v/t (searched)
Explanation:
a=acceleration
v=change in velocity
t=time
(searched)
sports photographers often use large aperture, long focal length lenses. what limitations do these lenses impose on the photographs?
Answer:
The depth of focus achievable with those lenses is small.
Explanation:
A larger aperture makes it much harder to focus on more than one object. When using a telephoto lens (the ones the question is referring to), the depth of focus is very small. For example, using a telephoto lens to take a photo of a runner might get the runner in focus, but certainly not the track, or the audience behind them. If you look at photos, especially older photos, of Olympians in almost any sport you can see this.
Hope this helps!
A 2kg water balloon is flying at a rate of 4m/s^2. With what force will it hit its target?
Explanation:
F=m×a
m=2kg
a=4m/s^2
F=2kg×4m/s^2
F=8N
A 2 kg water balloon is flying at a rate of 4 m/s². Force with which balloon will hit its target is 8 Newton.
What is force?A force is a push or pull upon an object resulting from the object's interaction with another object. Whenever there is body with some mass than there is force.
Given in the question mass and acceleration of balloon, force is given as
F = m*a
m = 2 kg
a = 4 m/s²
F = 2 kg×4 m/s²
F = 8 N
A 2 kg water balloon is flying at a rate of 4 m/s². Force with which balloon will hit its target is 8 Newton.
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A new tube is used each time a blood sample is tested.Explain why valid results are only obtained if each tube is identical
Valid results are only obtained if each tube is identical because; effective comparison of the tested blood each time can only be achieved if the testing model is constant in which case each tube is identical.
Discussion:
During scientific tests such as that described in the question; it is important to keep all parameters of testing constant.
This is so because, the utmost motive of the testing model is to draw comparison. It is on this note that valid results are only obtained if each tube is identical.
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A scientist fills a container with sea water. The container has dimensions 30 cm x 30 cm x 40 cm The density of sea water is 1020 kg/mº. Calculate the mass of the sea water in the container.
Answer:
30600kg
Explanation:
density=m/v make v subject of the formula
Define displacement in your own word
Answer:
Displacement is a vector quantity that refers to "how far out of place an object is"; it is the object's overall change in position.
Explanation:
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Walter has a paper due on a novel that he has not read. He knows that his teacher will expect detailed references to the novel in his paper. He is thinking that he can listen to it while he is lifting weights and multi-task. What is the BEST response to Walter?
A.
He does not really need to concentrate on exercise, so it is fine.
B.
He would be better off focusing on his workout and then turning to the novel.
C.
If he is doing a type of exercise that allows him to stop and take notes, it is fine.
D.
Doing as many tasks as possible is generally a good idea and promotes efficiency.
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Answer:
I'm no expert, but multitasking is a no bueno. Because multitasking reduces your efficiency and performance because your brain can only focus on one thing at a time. When you try to do two things at once, your brain lacks the capacity to perform both tasks successfully.
Therefore I would choose A, considering he could easily workout another time, whilst the test is a one time thing. He can't redo the test, but he can workout again. So my answer is A.
If he HAS to workout and study at the same time, then C would be appropriate.
I hope this helps!
How many sulfur atoms are there in 25 molecules c4h4s2?.
I need help quickly pls
Answer:
Ok I'm not 100% on this one but, try 3 lifes sorry if u get it wrong D:
Explanation: