What is an embedded computer? explanation

Answer:

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Answer:

1) Video Games

2) Gunpei Yokoi

Explanation:

1) Video games are electronic games played off electronic consoles which are connected to Visual Display Units such as desktops or laptops and flat=screen televisions. The games are created in such a way that images can be manipulated using a pad and controlled by the computer program.

2) Gunpei Yokoi person who made the "game boy" and "game and watch" hand-held games.

He was recognized posthumously for his achievements in 2003 when he was offered a lifetime achievement award from the international game developers association.

Cheers

Answer:inpossible !889

Explanation: I npossible !889

Explanation:

The main computer case containing the central components of a personal computer is CPU.

The central processing unit (CPU) can be defined as the brain of the computer, it also takes the raw data and turns it into information.

Answer:

checking e-mail from a remote location  

receiving voicemail messages while away from the office

sending and receiving graphics and video to coworkers

sending data from outside the office

Explanation:

Wireless networks have proved to be more beneficial and accessible as compared to the wired networks. Wireless networks have helped in increasing the efficiency of transferring the data. It is also very accessible and easy to operate. It helps a person be connected even during travelling. It saves the cost and helps in better execution of the work. The speed at which the data is transferred helps in saving the cost and time. The maintenance cost is reduced in wireless communication as that of wired one. It also helps during the times of emergency situations.

Answer:

checking e-mail from a remote location  

receiving voicemail messages while away from the office

sending and receiving graphics and video to coworkers

sending data from outside the office

Explanation:

EDGE 2021

1, 3,4,5

Answer:

#include <stdio.h>

void main()

{

int j, sum = 0;

printf("The first 10 natural number is :\n");

for (j = 1; j <= 10; j++)

{

sum = sum + j;

printf("%d ",j);

}

printf("\nThe Sum is : %d\n", sum);

}

Within a loop

Step 1: Initialize a variable to 1 (say x=1)

Step 2: Specifiy the condition

In this case x<=10

Step 3: Increment the variable by 1

using increment operator x++

OR

simply x+=1(x=x+1)

Step 4: Print the value of variable

Terminate the loop

Explanation:

Answer:

Get his sheild

Explanation:

Answer:

Ares wants Percy to retrieve his shield

Explanation:

Answer:

Explanation:

The following code was fixed but it is impossible to fix the entirety of the code without adjusting the Main method as well. This is because the information is being saved in an ArrayList that is saved within the main method. This means that either we need to move the Arraylist outside of the main method or adjust something inside the main method as well to make the code run. In this iteration, I have added an IF statement to the Point method so that it deletes a point if it is being added for a second time. In order to accomplish this, I had to add an extra argument when calling the Point Method in the Main method which would be the ArrayList in which the information is saved.

import java.util.ArrayList;

import java.util.List;

class PointTest {

   static final class Point {

       private double x, y;

       Point(double x, double y, List<Point> points) {

           this.x = x;

           this.y = y;

           for (int i = 0; i < points.size(); i = i+1) {

               if ((points.get(i).x == x) && (points.get(i).y == y)) {

                   points.remove(i);

               }

           }

       }

   }

   public static void main(final String[] args) {

       List<Point> pointList = new ArrayList<>();

       pointList.add(new Point(1, 2, pointList));

       pointList.add(new Point(3, 4, pointList));

       System.out.println(pointList.size());

// remove the second Point

       pointList.remove(new Point(3, 4, pointList));

       System.out.println(pointList.size());

// REMOVED!!!!!

   }

}

Answer:

huh

Explanation:

what do you mean? the question doesn't make any sense

Answer:

def GPAcalc(g):

   if g == "a" or g == "A":

       return 4

   elif g == "B" or g == "b":

       return 3

   elif g == "C" or g == "c":

       return 2

   elif g == "D" or g == "d":

       return 1

   elif g == "F" or g == "f":

       return 0

   else:

       return "Invalid"

grade = input("Enter your Letter Grade: ")

gpa = GPAcalc(grade)

print("Your GPA score is: " + str(gpa))

Explanation:

Answer: $help

Explanation:

Not sure which terminal you are using, but "help" in the terminal outputs available internal commands.

Answer:

Explanation:

Question One

He could have read other sites with other points of view and summarized that. Most importantly he could have used footnotes that gave credit to every idea that he used.

He could have put the material down and begin to write. The words would have come out in his awkward style. He would still need to footnote the ideas. That is most important.

Question Two

It is both. Plagiarism is a serious crime if it involves many people being affected by what he wrote.

But it is totally unethical at any level. Trying to pass off something that isn't yours is totally unethical. It should never be done. It shames the subject which is shown to be unimportant and it shames the instructor (he knew enough to catch the plagiarism), and it shames the person getting caught.

Answer:

a user interface is the thing that apears after the login

Explanation:

go to goolge and type microsoft flight simulator user intr=erface

Answer:

The answer is below

Explanation:

The inverse fourth power law states that the intensity varies inversely to the fourth power of the distance from the source. That is as the distance increases, the intensity decreases.

Let I represent the intensity and let d represent the distance from the source, hence:

I ∝ 1 / d⁴

I = k / d⁴

Where k is the constant of proportionality.

Given that at a power of 25W = 25*10⁻⁶ W, the distance (d) = 225 m. We can find the value of k.

25*10⁻⁶  = k / 225⁴

k = 225⁴ * 25*10⁻⁶ = 64072.27

Hence:

I = 64072.27 / d⁴

At a distance (d) = 0.9km = 900 m, we can find the corresponding power:

I = 64072.27 / 900⁴

I = 9.77 * 10⁻⁸ W

Answer:

In Python:

def calcCost(length,width,quality):

   if quality == 1:

       cost = length * width * 3.50

   if quality == 2:

       cost = length * width * 2.50

   else:

       cost = length * width * 1.50

   return cost

length = float(input("Room Length: "))

width = float(input("Room Width: "))

print("Quality:\n1 - Best\n2 - Moderate\n3 and others - Worst")

quality = int(input("Quality: "))

print("Calculate: "+str(calcCost(length,width,quality)))

Explanation:

This defines the function calcCost to calculate the carpeting cost

def calcCost(length,width,quality):

If quality is 1, the total cost is calculated by area * 3.50

   if quality == 1:

       cost = length * width * 3.50

If quality is 2, the total cost is calculated by area * 2.50

   if quality == 2:

       cost = length * width * 2.50

For other values of quality, the total cost is calculated by area * 1.50

   else:

       cost = length * width * 1.50

This returns the calculated carpeting cost    

   return cost

The main begins here

This prompts the user for the length of the room

length = float(input("Room Length: "))

This prompts the user for the width of the room

width = float(input("Room Width: "))

This gives instruction on how to select quality

print("Quality:\n1 - Best\n2 - Moderate\n3 and others - Worst")

This prompts the user for the quality of the carpet

quality = int(input("Quality: "))

This calls the calcCost method and also printst the calculated carpeting cost

print("Calculate: "+str(calcCost(length,width,quality)))

Answer: True

Explanation:

We start at 0 for lists

[item, item, item, item, item]

  0         1       2     3        4

true on edge2020/2021

Answer:

volume mount points

Explanation:

The best thing to do would be to use volume mount points. This is a feature that allows you to mount/target (from a single partition) another folder or storage disk that is connected to the system. This will easily allow the user in this scenario to access the different files located in the D: and E: drive from the C:\ drive itself. Without having to go and find each file in their own separate physical drive on the computer.

Answer:

#include<iostream>

using namespace std;

int main() {

cout<<"Enter The Size Of Array: ";

int size;

bool isBestCase=false;

cin>>size;

if(size<=0){

cout<<"Error: You entered an incorrect value of the array size!"<<endl;

return(0);

}

int array[size], key;

cout<<"Enter the numbers in the array, separated by a space, and press enter:";

// Taking Input In Array

for(int j=0;j<size;j++){

cin>>array[j];

}

//Your Entered Array Is

for(int a=0;a<size;a++){

cout<<"array[ "<<a<<" ] = ";

cout<<array[a]<<endl;

}

cout<<"Enter a number to search for in the array:";

cin>>key;

for(i=0;i<size;i++){

 if(key==array[i]){

   if(i==0){

     isBestCase=true; // best case scenario when key found in 1st iteration

     break;

   }

 }

}

if(i != size){

 cout<<"Found value "<<key<<" at index "<<i<<", which took " <<++i<<" checks."<<endl;

}  else{

 cout<<"The value "<<key<<" was not found in array!"<<endl;

 cout<<"We ran into the worst-case scenario!"; // worst-case scenario when key not found

}

if(isBestCase){

cout<<"We ran into the best case scenario!";

}

return 0;

}

Explanation:

The C++ source dynamically generates an array by prompting the user for the size of the array and fills the array with inputs from the user. A search term is used to determine the best and worst-case scenario of the created array and the index and search time is displayed.

Answer:

Kenny should consider cloud storage.

Answer:

To be eligible for an award of statutory damages and attorneys' fees in a copyright infringement case, the copyrighted work must be registered before infringement commences, or, if the work is published, within 3 months of publication.

Answer:

The answer is 3 months.

Explanation:

Answer:

import java.util.Scanner;

public class Swap

{

public static void main(String[] args) {

    Scanner input = new Scanner(System.in);

    int x, y, t;

 System.out.print("Enter the first variable: ");

 x = input.nextInt();

 System.out.print("Enter the second variable: ");

 y = input.nextInt();

 System.out.printf("Values before the swap -> x = %d, y = %d\n", x, y);

 t = x;

 x = y;

 y = t;

 System.out.printf("Values after the swap -> x = %d, y = %d\n", x, y);

}

}

Explanation:

Import the Scanner class

Create a Scanner object to be able to get input from the user

Declare the variables, x, y, and t - the variable t will be used as temporary variable that will hold the value of x

Ask the user to enter the first and second variables

Print the values before swap

Assign the value of x to the t

Assign the value of y to the x (Now, x will have the value of y)

Assign the value of the t to the y (Since t holds the value of x, y will have the value of x)

Print the values after the swap

Answer:

In Python:

bin = int(input("Binary Number: "))

num = str(bin)

dec = 0

for i in range(len(num)):

   dec = dec + int(num[i]) * 2**int(len(num)-i-1)

print("Decimal Equivalent: "+str(dec))

Explanation:

Note that the program assumes that the user input will be valid. So, error check was done in the program

This line gets the binary number from the user

bin = int(input("Binary Number: "))

This converts the inputted number to string

num = str(bin)

This initializes decimal number to 0

dec = 0

This iterates through the string number

for i in range(len(num)):

This converts the number to decimal

   dec = dec + int(num[i]) * 2**int(len(num)-i-1)

This prints the result of the conversion    

print("Decimal Equivalent: "+str(dec))

See attachment for screenshots

Answer:

Follows are the code to this question:

#include <iostream>//header file

using namespace std;

int main()//main method

{

int day,month,year;//defining integer variable

cout<<"please enter last two digit of the year: "; //print message

cin>>year;//input year value

cout<<"enter day: "; //print message

cin>>day;//input day value

cout<<"enter month: ";//print message

cin>>month;//print month message

if(month*day==year)//check magic date condition  

{

cout<<"its magic programology year";//print message

}

else

{

cout<<"its not magic year";//print message

}

return 0;

}

Output:

please enter last two digit of the year: 98

enter day: 14

enter month: 7

its magic programology year

Explanation:

In the given code, three integer variable "day, month, and year" is declared, that uses the input method "cin" to input the value from the user-end.

In the next step, an if block statement is used that check month and day value multiple is equal to year value, if the condition is true it will print "magic programology year" otherwise it will print "not the magic year".

here because brainly sucks I hate this website stop censoring litteraly everything, can't get away with calling someone a poopy head on here

Answer:

To be like his dad maybe I don't a 100%