Help please ............
Answer:
Explanation:
Electrical current is the movement of charge. The units are Amperes (Amps)
The cart travels the track again and now experiences a constant tangential acceleration from point A to point C. The speeds of the cart are 13.2 ft/s at point A and 17.4 ft/s at point C. The cart takes 3.00 s to go from point A to point C, and the cart takes 1.20 s to go from point B to point C. What is the cart's speed at point B
Answer:
the cart's speed at point B is 15.72 ft/s
Explanation:
Given the data in the question;
The car travels from point A to C in 3.00 s, its average acceleration [tex]a_{avg}[/tex] will be;
[tex]a_{avg}[/tex] = [[tex]V_{c}[/tex] - [tex]V_{A}[/tex]] / Δt
[tex]V_{c}[/tex] is 17.4 ft/s, [tex]V_{A}[/tex] is 13.2 ft/s and Δt is 3.00 s
so we substitute
[tex]a_{avg}[/tex] = [17.4 - 13.2] / 3
[tex]a_{avg}[/tex] = 4.2 / 3
[tex]a_{avg}[/tex] = 1.4 ft/s²
so average acceleration of the cart between the points A and B is 1.4 ft/s²
The instantaneous value of the velocity of the cart at point B will be;
[tex]a_{avg}[/tex] = Δv / Δt
now substitute [[tex]V_{c}[/tex] - [tex]V_{B}[/tex]] for Δv and t' for Δt
[tex]a_{avg}[/tex] = [[tex]V_{c}[/tex] - [tex]V_{B}[/tex]] / t'
[tex]V_{B}[/tex] = [tex]V_{c}[/tex] - [tex]a_{avg}[/tex]( t' )
so we substitute 17.4 ft/s for [tex]V_{c}[/tex], 1.20 s for t' and [tex]a_{avg}[/tex] = 1.4 ft/s²
[tex]V_{B}[/tex] = 17.4 - (1.4 × 1.20)
[tex]V_{B}[/tex] = 17.4 - 1.68
[tex]V_{B}[/tex] = 15.72 ft/s
Therefore, the cart's speed at point B is 15.72 ft/s
A 1.0 C charged object and a 2.0 C charged object are separated by 100 m. Where should a -1.0x10-3 C charged object be placed on a line between the positively charged objects so that the net electrical force exerted on the negatively charged object is zero
Answer:
x = 41.2 m
Explanation:
The electric force is a vector magnitude, so it must be added as vectors, remember that the force for charges of the same sign is repulsive and for charges of different sign it is negative.
In this case the fixed charges (q₁ and q₂) are positive and separated by a distance (d = 100m), the charge (q₃ = -1.0 10⁻³ C)) is negative so the forces are attractive, such as loads q₃ must be placed between the other two forces subtract
F = F₁₃ - F₂₃
let's write the expression for each force, let's set a reference frame on the charge q1
F₁₃ = [tex]k \frac{q_1 q_3}{x^2}[/tex]
F₂₃ = [tex]k \frac{q_2 q_3}{(d-x)^2}[/tex]
they ask us that the net force be zero
F = 0
0 = F₁₃ - F₂₃
F₁₃ = F₂₃
k \frac{q_1 q_3}{x^2} =k \frac{q_2 q_3}{(d-x)^2}
[tex]\frac{q_1}{x^2} = \frac{q_2}{(d-x)^2 }[/tex]q1 / x2 = q2 / (d-x) 2
(d-x)² = [tex]\frac{q_2}{q_1}[/tex] x²
we substitute
(100 - x)² = 2/1 x²
100- x = √2 x
100 = 2.41 x
x = 41.2 m
1pt If the room is the frame of reference for the study of an object moving in three dimensions, from where should distances be measured?
O A. one wall and the floor
OB. two walls and the floor
O c. the floor and the ceiling
O D. the door
Answer:
Option B, two walls and the floor
Explanation:
The distance should be measured from the point where at least the three axed meet.
Two walls and the floor are equivalent to three axes.
Vertical wall 1 = Y Axis
Horizontal wall2 = X Axis
Floor = Z Axis
Thus, the distance should be measured from the point where two walls and one floor meet.
Option , B is correct
Which would have more kinetic energy a dog walking or the same dog running?
Answer:
dog walking
Explanation:
Two trucks are traveling east on I-40 when the Walmart truck (61 mph, 57 ft long) decides to pass the FedEx truck (53 mph, 60 ft long). A 'pass' starts when the front of the Walmart truck is 45 ft behind the rear of the FedEx truck and ends when the rear of the Walmart truck is 45 ft in front of the front of the FedEx truck.
How long does it take for the Walmart truck to pass the FedEx truck?
How far does the Walmart truck travel while passing the FedEx truck?
Answer:
The answer is below
Explanation:
Let us assume that the slower truck which is the FedEx truck travels d mile. The pass started when the Walmart truck was 45 ft behind the FedEx truck and ended when the Walmart truck is 45 ft in front of the FedEx truck.
The additional distance covered by the truck Walmart = 45 ft + 60 ft (length of FedEx truck) + 45 ft = 150 ft
1 mile = 5280 ft
150 ft = 150 ft * 1 mile/5280 ft = 0.0284 mile
Therefore the Walmart truck covered an additional 0.0284 mile. Hence the distance covered by the walmart truck = d + 0.0284
Let us say it took t hours for the pass to be completed. Hence:
For FedEx; 53 mph = d / t. t =d / 53
For Walmart; 61 mph = (d + 0.0284) / t. t = (d + 0.0284) / 61
Since it took the trucks the same time. Hence:
d / 53 = (d + 0.0284) / 61
61d = 53d + 1.506
8d = 1.506
d = 1.506/8
d = 0.1882 mile = 993.75 ft
The FedEx truck traveled 993.75 mile while the Walmart truck traveled 1143.75 ft (993.75 + 150 ft)
The time (t) = d / 53 = 0.1882 / 53
t=0.00355 h = 12.8 seconds
A cat runs in a straight line. Which of the following statements about the cat's motion must be true?
Answer:
I would think it's A cat runs in a straight line.
Explanation:
The correct statement regarding the motion of the cat is option c. The speed of the cat is zero at the points a and c. Where the position meets 0 m.
What is position -time graph ?A position - time graph is really helpful to determine the position of an object with respect to time. Thus, we can clearly calculate how much distance is covered within a given time. Similarly if the velocity of motion can be easily determined from this graph.
From the given graph, the cat starts walking from the point a. Then from a to b it walks in a straight line with an increasing velocity with time. At the point b, it reaches to its maximum displacement.
Then the cat starts walking down where the distance in m is decreasing with time, At the point c, it stops walking and it has zero speed as it is in point a. Therefore, the correct statement about the motion of the cat is option c.
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The complete question is attached below.
What is the mass of an object if it is moving at a speed of 10 m/s and has 400 J of kinetic energy?
Answers:
8 kg
Explanation:
Kinetic Energy = (mass × velocity × velocity) ÷ 2
We know that Kinetic Energy = 400 J and velocity = 10 m/s.
KE = (m × v × v) ÷ 2
400 J = (m × 10 m/s × 10 m/s) ÷ 2
400 J = m × 50 m^2/s^2
To find the mass you will divide 400 J and 50 m^2/s^2.
m = 8 kg
You can also check it if it gives you 400 J.
KE = (m × v × v) ÷ 2
KE = (8 kg × 10 m/s × 10 m/s) ÷ 2
KE = 400 J
So this means that the mass is 8 kg. I know that it is a bit confusing, but when you do J (joules) ÷ m^2/s^2 = kg (kilograms). Hope this helps, thank you !!
a student that just received their driver's license decides to buy a new car. he remembers from physics class that heat engines have thermal efficiency that can be calculated. he asks the car dealer for a car that has a high thermal efficiency rating. the car dealer say he has a car that is 100% efficient. which law of thermodynamics best describes why the car cannot be 100% efficient?
Answer: the first law of thermodynamics
Explanation:
The second law of thermodynamics is the best description for the car to cannot be having 100% efficient engine.
What is the second law of thermodynamics?Thermodynamics is the branch of science which deals with the study of heat. Heat is a form of energy which exists as a result of the change in the temperature between the two bodies or objects under study.
The second law of thermodynamics is a physical law, which is based up on the universal experience concerning with the heat and energy interconversions between bodies present in the system and surrounding. One simple statement of this law is that, the heat energy always moves from the hotter objects to the colder objects, unless the energy in some form is supplied to the object to reverse the direction of heat flow between the objects.
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what is the cost to run a single 100 w light bulb for 30 days if the electric company charges $0.18 for every KW-hr?
Explanation:
power of the bulb = 100w=0.1kw
power consumption when the bulb is used for 30 days ( 30 *24 = 720 hours) =0.1*720=72kwh
cost to run the bulb for 30 days = 72*0.18
= $12.96
Answer is $12.96..................
An offshore oil platform houses a drill for drilling oil. The drill descends from the platform and enters the ocean. At the bottom of the ocean, the drill starts to dig into the rock. It continues drilling into the rock for another 7,000 feet and then stops. Where does the drill stop?
Answer:
Geosphere
Explanation:
I did it and got the answer right.
Answer:
in the geosphere
Explanation:
You are driving up a long, inclined road. After 1.50mi you notice that signs along the roadside indicate that your elevation has increased by 510ft . b) How far do you have to drive to gain an additional 110ft of elevation
Answer:
1.825 miles
Explanation:
Given that :
Distance driven = hypotenus = 1.5 miles
Elevation at distance of 1.5 miles = 510 feets
Converting miles to feets for the hypotenus :
1 mile = 5280 feets
1.5 miles = (5280 * 1.5) = 7920 feets
To obtain the angle of inclination :
Using Pythagoras rule :
Sinθ = opposite / hypotenus
θ = Sin^-1(510 / 7920)
θ = 3.692°
For an additional elevation of 110 ft ; new height = 110 + 510 = 620 feets
Distance driven, d =?
Sin 3.69 = (620 / d)
0.0643581 * d = 620
d = 620 / 0.0643581
d = 9633.5970 feets
Converting to feets :
9633.5970 / 5280 = 1.8245448
= 1.825 miles
Secondly, a man is rock climbing when suddenly the rock face he grabs breaks away and he is left with a 1200 lb. rock on his chest. How do scientists say he was able to lift this incredible weight and save himself
Answer:
rush of adrenaline
Explanation:
This is believed to have been possible due to the rush of adrenaline that the individual was experiencing. This has happened a couple times in moments of extreme distress where an individual's body is flooded with adrenaline. This adrenaline allows for super human like strength as well as increased senses. The individual that has lifted the most amount of weight in such a scenario, lifted a total of 3000 lbs. Therefore, it is fair to say that 1200 lb. rock was lifted due to adrenaline.
What is the net power needed to change the speed of a 1600-kg sport utility vehicle from 15.0 m/s to 40.0 m/s in 4.00 seconds
Answer:
The net power needed to change the speed of the vehicle is 275,000 W
Explanation:
Given;
mass of the sport vehicle, m = 1600 kg
initial velocity of the vehicle, u = 15 m/s
final velocity of the vehicle, v = 40 m/s
time of motion, t = 4 s
The force needed to change the speed of the sport vehicle;
[tex]F = \frac{m(v-u)}{t} \\\\F = \frac{1600(40-15)}{4} \\\\F = 10,000 \ N[/tex]
The net power needed to change the speed of the vehicle is calculated as;
[tex]P_{net} = \frac{1}{2} F[u + v]\\\\P_{net} = \frac{1}{2} \times 10,000[15 + 40]\\\\P_{net} = 275,000 \ W[/tex]
The net power needed to change the speed of the vehicle is 275.000Watts
Power is the ratio of workdone with respect to the time taken.
Power = workdone/timeWorkdone = force * distance/timeWorkdone = Force * speedGet the required force:
F = m(v-u)/t
F = 1600(40-15)/4
F = 1600(25)/4
F = 400 * 25
F = 10,000N
The required net power will be calculated as shown:
P = 1/2*F(u+v)
P = 1/2(10000)*(15+40)
P = 5000(55)
P = 275,000Watts
Hence the net power needed to change the speed of the vehicle is 275.000Watts
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A tennis player hit a .057-kg ball with a force of 40 N. The duration of the force was .05 s.
36.0 g of water is to be heated through a temperature change of 9.00 C. How much energy will be required?
36.0 g water is to be heated through a
As per specific heat capacity ,42,638 J/Kg°C energy is required to raise the temperature by 9°C.
What is specific heat capacity?Specific heat capacity is defined as the amount of energy required to raise the temperature of one gram of substance by one degree Celsius. It has units of calories or joules per gram per degree Celsius.
It varies with temperature and is different for each state of matter. Water in the liquid form has the highest specific heat capacity among all common substances .Specific heat capacity of a substance is infinite as it undergoes phase transition ,it is highest for gases and can rise if the gas is allowed to expand.
It is given by the formula ,
Q=mcΔT
For the given question, it is calculated by substituting the values in the given formula,
Q=30×4.2×282
=42,638 J/Kg°C
Thus, 42,638 J/Kg°C of energy is required for raising the temperature by 9°C.
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A friend comments to you that there was a beautiful, thin sliver of a Moon visible in the early morning just before sunrise. Which phase of the Moon would this be, and in what direction would you look to see the Moon (in the southern sky, on the eastern horizon, on the western horizon, high in the sky, etc.)?
Answer: Waning Crescent
Explanation:
Help on this question ‼️
Answer:
I think the option b
Is the answer
Answer:
C
Explanation:
after a CCW rotation it would become a waning gibbous, so after a Clockwise rotation it would be a waxing gibbous (opposite)
A copper atom has an atomic number of 29 and an atomic mass of 64. What is the structure of this atom?
A. It has a central nucleus composed of 29 protons and 35 neutrons,
surrounded by an electron cloud containing 29 electrons.
B. It has a central nucleus composed of 29 protons and 64 neutrons,
surrounded by an electron cloud containing 29 electrons.
C. It has a central nucleus composed of 35 protons and 29 neutrons,
surrounded by an electron cloud containing 29 electrons.
D. It has a central nucleus composed of 29 protons and 29 neutrons,
surrounded by an electron cloud containing 35 electrons.
Answer:
Explanation:
Atomic mass is nuetrons + protons.
Basically it's
? nuetrons + protons = 64
I did process of elimination:
b) It cannot be "b" because 29 + 64 doesn't equal 64.
c) It cannot be "c" because in a regular molecule the amount of protons equals to amount of electron(s).
d) 29 + 29 doesn't = 64.
Therefore, the answer is "A"
Answer: A
Explanation: Just took the test on a.pex
A car traveling at 55 MPH North is an example velocity vector.
O True
O False
Answer:
false
Explanation:
A laser is placed at the point $(3,5)$. The laser beam travels in a straight line. Larry wants the beam to hit and bounce off the $y$-axis, then hit and bounce off the $x$-axis, then hit the point $(7,5)$. What is the total distance the beam will travel along this path
Answer:
4units
Explanation:
To calculate the total distance the beam will travel along this path, you will use the formula for calculating the distance between two coordinates expressed as;
D = √(x2-x1)²+(y2-y1)²
Given the coordinate points
(3,5) and (7,5)
Substitute
D = √(7-3)²+(5-5)²
D = √(7-3)²+0²
D = √4²
D = √16
D = 4
Hence the total distance the beam will travel along this path is 4units
Using the graph, when (in seconds) would you expect the object to have the highest velocity? Explain your answer.
Answer:
blue
Explanation:
nswer the following about two objects, A and B, whose motion produced ihe following ... "A" starts with a greater (t) position. Since they ... since you are moving away from the origin
Consider a plastic rod that is being charged up by rubbing a wool cloth. It is then brought to an initially neutral metallic sphere, and allowed to touch the sphere for a few seconds. The rod is then separated from the sphere by a small distance. After becoming separated, the rod:________.
A) is repelled by the sphere.B) is attracted to the sphere.C) feels no force due to the sphere.
Answer:
A) is repelled by the sphere
Explanation:
When a piece of plastic is rubbed with a wooden cloth, it sinks negativelyLet it change Q. So it is now allowed to touch the neutral zone. Therefore, there is a difference in the surface capacity of the two bodies, so that charge transfer takes placeSome of its negative charge is transferred to the metal sphere, now both the rod and the sphere are negatively charged and the same chargers as we know are repelled by each other.so correct answer is A) is repelled by sphereAt 10 seconds, you used 55 Joules. Can you tell me the power?
Answer:
5.5
Explanation:
power =energy÷time
power=55÷10
power=5.5
A 0.20 kg mass is oscillating on Planet X at a small angle from a light string of length 0.15 m with a period of
0.75 s.
What is the acceleration of gravity on Planet X?
Round answer to two significant digits.
Answer:
11 m/s^2
Explanation:
We can determine the acceleration of gravity from the pendulum’s period and length.
Let’s use the equation for the period of a pendulum and solve for the acceleration of gravity:
Points A, B, and C lie along a line from left to right, respectively. Point B is at a lower electric potential than point A. Point C is at a lower electric potential than point B. What would best describes the subsequent motion, if any, of a positively-charged particle released from rest at point B?
Answer:
Please see below as the answer is self-explanatory.
Explanation:
If the potential at B is lower than A, and the potential at C is lower than B, this means that there is an electric field, directed from A to C.If a positively-charged particle is released at rest at point B, it will be accelerated by the electric field (which is a force per unit charge, so it produces an acceleration) in the same direction than the field (because it is a positive charge) towards point C.Donuts are a simple or complex carbohydrate? *
Ok
Answer:
simple carbohydrate
Explanation:
Simple carbs are like cakes, donuts, and candy, etc.
Hope this helps :D
a ball is thrown upward with a beginning speed of 40m/s. The graph below shows how the speed of the ball changes until it reaches its maximum height.
use the graph to find
a) the time when the ball reaches its maximum height
b) the acceleration of the ball
c) the maximum height the ball went
Answer:
a) 4.0816s
b) -9.8 ms^-1
c) 81.63265m
An object of mass 8kg moved around the circle of radius 4m. with a constant speed of 15m/s.
calculate the angular velocity. and calculate the acceleration.
Answer:
a. Angular velocity = 0.267rad/s.
b. Centripetal acceleration = 56.25m/s.
Explanation:
Given the following data;
Mass, m = 8kg
Radius, r = 4m
Constant speed, V = 15m/s
a. To find the angular velocity
Angular velocity = radius/speed
Substituting into the equation, we have;
Angular velocity = 4/15
Angular velocity = 0.267rad/s
b. To find the acceleration;
Centripetal acceleration = V²/r
Substituting into the equation, we have;
Centripetal acceleration = 15²/4
Centripetal acceleration = 225/4
Centripetal acceleration = 56.25m/s.
Please could you guys help me. When an object falls from a height, the maximum energy transferred to its kinetic energy store is
equal to... *
. the energy transferred to its gravitational energy store
. the energy transferred away from its gravitational potential energy store
Answer:
the energy transferred away from its gravitational potential energy store
Explanation:
Kinetic energy can be defined as an energy possessed by an object or body due to its motion.
Mathematically, kinetic energy is given by the formula;
[tex] K.E = \frac{1}{2}MV^{2}[/tex]
Where, K.E represents kinetic energy measured in Joules.
M represents mass measured in kilograms.
V represents velocity measured in metres per seconds square.
Potential energy can be defined as an energy possessed by an object or body due to its position.
Mathematically, potential energy is given by the formula;
[tex] P.E = mgh[/tex]
Where,
P.E represents potential energy measured in Joules.
m represents the mass of an object.
g represents acceleration due to gravity measured in meters per seconds square.
h represents the height measured in meters.
When an object falls from a height, the maximum energy transferred to its kinetic energy store is equal to the energy transferred away from its gravitational potential energy store.
This ultimately implies that, while the object was at rest it possessed potential energy, which is then transformed into motion when it starts to fall.