Newton's Third Law of Motion states "To every action, there is an equal and opposite reaction; action and reaction forces act on different bodies".
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I NEED HELP ASAP
Answer:
In order to find average velocity we use the equation: [tex]avg = \frac{change \: in \: x}{change \: in \: time} [/tex]She went from 4.0m to 16.0 m making her delta x = 12.0 m She did that in 4sHence 12/4 = 3 m/sThe sun shines equally on both hemispheres during the summer and winter solstices.
True
False
Two go-carts, A and B, race each other around a 1.0 track. Go-cart A travels at a constant speed of 20.0 /. Go-cart B accelerates uniformly from rest at a rate of 0.333 / ଶ . Which go-cart wins the race and by how much time?
Complete Question
Q. Two go-carts, A and B, race each other around a 1.0km track. Go-cart A travels at a constant speed of 20m/s. Go-cart B accelerates uniformly from rest at a rate of 0.333m/s^2. Which go-cart wins the race and by how much time?
Answer:
Go-cart A is faster
Explanation:
From the question we are told that
The length of the track is [tex]l = 1.0 \ km = 1000 \ m[/tex]
The speed of A is [tex]v__{A}} = 20 \ m/s[/tex]
The uniform acceleration of B is [tex]a__{B}} = 0.333 \ m/s^2[/tex]
Generally the time taken by go-cart A is mathematically represented as
[tex]t__{A}} = \frac{l}{v__{A}}}[/tex]
=> [tex]t__{A}} = \frac{1000}{20}[/tex]
=> [tex]t__{A}} = 50 \ s[/tex]
Generally from kinematic equation we can evaluate the time taken by go-cart B as
[tex]l = ut__{B}} + \frac{1}{2} a__{B}} * t__{B}}^2[/tex]
given that go-cart B starts from rest u = 0 m/s
So
[tex]1000 = 0 *t__{B}} + \frac{1}{2} * 0.333 * t__{B}}^2[/tex]
=> [tex]1000 = 0 *t__{B}} + \frac{1}{2} 0.333 * t__{B}}^2[/tex]
=> [tex]t__{B}} = 77.5 \ seconds[/tex]
Comparing [tex]t__{A}} \ and \ t__{B}}[/tex] we see that [tex]t__{A}}[/tex] is smaller so go-cart A is faster
You have a cup full of water and a bathtub full of water. Both samples of water have a temperature of 30°C. Which sample has greater amount of heat?
Answer:
temperature is -10
Explanation:
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Identify the structure that separates the nuclear contents from the cytoplasm.
Answer:nuclear membrane
Explanation:
Answer:
Nuclear envelope. Hope this helps.
The negatively charged particle in an atom is a(n):
Answer: Electron
Explanation:A negatively charged particle found circling or orbiting an atomic nucleus. An electron, like a proton is a charged particle, although opposite in sign, but unlike a proton, an electron has negligible atomic mass. Electrons contribute no atomic mass units to the total atomic weight of an atom.
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Explain how newtons firdt law of motion follows the second law
Answer:
Newton's second law says that F=ma, so if the force applied is zero, then the acceleration must also be zero.
Explanation:
Let's set the equation to 0 = ma. If mass is a nonzero value, then the acceleration must be zero to solve the equation. Therefore, if the force applied to an object is zero, then it will not accelerate (i.e. change speed or direction).
Answer:
It might help u
Explanation:
Newton's First Law states that an object with no net force acting on it remains at rest or moves with constant velocity in a straight line.
Newton's Second Law states that the acceleration of an object is directly proportional to the net force on the object and inversely proportional to the mass of the object
F=ma
So both show relation between force and acceleration that's why we can say both are inter-related
The Newton 2nd law is Basically introduce so that we can obtain a specific relation ship between force and acceleration.
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Outline the cell cycle
Answer:
The cell cycle has four stages: during the first three, the cell is in interphase, and in the last one, the cell is dividing itself. Also, there is a resting stage when the cell is not preparing itself for the division.
G0: the cell is not in the cell cycle. It is resting and not preparing itself for the division.
G1: the cell grows and synthesizes proteins and other elements that the cell will need for the next stage.
S: In this phase, which is called Synthesis, the cell synthesizes the DNA.
G2: the cell continues to grow. It synthesizes more proteins, RNA, and other elements that it will need for mitosis.
Mitosis: the division of the cell takes place, and as a result, there are two daughter cells. This phase has four stages, prophase, metaphase, anaphase, and telophase.
Explanation:
The cell cycle has four stages. Each of them has a role in the division of the cell. The first one is Gap 1 or G1, then the Synthesis or S phase follows, after S, Gap 2 takes place, and finally, Mitosis.
We can divide the cell cycle into two big groups: interphase, which includes G1, S, and G2, and the changes that the cell suffer can not be appreciated. The other group is the One where the cell division happens, and it includes Mitosis.
G0 is not part of the cell cycle. It is a state where the cell doe not prepares itself for the division. It is resting.
Bernoulli's principle is responsible for most of the lift produced by an airplane wing.
True
False
Answer:
huiiiiuuu beautiful...
1.
A car is moving in a circle or radius r = 25 meters, in a parking lot at 10 m/s. What is the car's
centripetal acceleration?
what is the correct answer?
Answer:
The value of k is -4. Third choice
Explanation:
The Polynomial Remainder Theorem
It states that the remainder of the division of a polynomial f(x) by (x-a) is equal to f(a).
We are given the polynomial:
[tex]p(x)= x^3+kx^2+x+6[/tex]
And we also know x+1 is a factor of p(x). If x+1 is a factor of p(x), then the remainder of the division of p(x) by x+1 is zero.
Applying the remainder theorem for a = -1:
[tex]p(-1)= (-1)^3+k(-1)^2+(-1)+6=0[/tex][tex]-1 + k - 1 + 6 = 0[/tex]
Solving for k:
[tex]k = 1 + 1 - 6[/tex]
[tex]\boxed{k = -4}[/tex]
The value of k is -4. Third choice
how does a plane mirror work
Answer:
Plane mirrors work because the light rays create a virtual image behind the mirror. Light rays from the object strike the mirror and reflect according to the law of reflection. ... Therefore, our eye and brain track the light rays backward to a position from which they appear to have come.
4) Bunny pushes on Monkey to the right with a 95N force while Deer pushes on Monkey Tom Lee
with a 75N force. Monkey weighs
50N.
Answer:
-30N to the left
Explanation:
Step one:
Given data
the mass of the monkey is 50N
Step two:
Required is the net force acting on the monkey
Now to the right Bunny is applying 95N,
Deer pushes on Monkey Tom Lee
with a 75N the net force acting on the monkey to move it is
= 95-50-75= -30N to the left
the other user said:
-30N to the left URGENT )If you drive your 1,000 kg car from sea level up to the mountain, which is 366 m above sea level, how much will you have increased your car's potential energy?(consider : g=10m/s2)
1 point
a) 366,000 J
b) 3,660,000 J
c) 2.73 J
d) 20.73 J
Answer:
(B) the increase in the car's potential energy is 3,660,000 J
Explanation:
Given;
mass of the car, m = 1,000 kg
height through the car was drove, h = 366 m
acceleration due to gravity, g = 10 m/s²
The increase in the car's potential energy is calculated as;
P.E = mgh
P.E = 1000 x 10 x 366
P.E = 3,660,000 J
Therefore, the increase in the car's potential energy is 3,660,000 J
Anyone.... help with this two questions...
A 2.0 kg block is released from rest at the top of a curved incline in the shape of a quarter of a circle of radius R = 3.0 m. The block then slides onto a horizontal plane where it finally comes to rest a distance D from the beginning of the plane. The curved incline is frictionless, but there is a coefficient of friction, μ = 0.5, on the horizontal plane. Determine the velocity of the box at maximum kinetic energy
The block has maximum kinetic energy at the bottom of the curved incline. Since its radius is 3.0 m, this is also the block's starting height. Find the block's potential energy PE :
PE = m g h
PE = (2.0 kg) (9.8 m/s²) (3.0 m)
PE = 58.8 J
Energy is conserved throughout the block's descent, so that PE at the top of the curve is equal to kinetic energy KE at the bottom. Solve for the velocity v :
PE = KE
58.8 J = 1/2 m v ²
117.6 J = (2.0 kg) v ²
v = √((117.6 J) / (2.0 kg))
v ≈ 7.668 m/s ≈ 7.7 m/s
The velocity of the block at maximum kinetic energy is 7.668 m/s.
From potential energy formula,
PE = m g h
Where,
m = mass = 2 kg
g -gravitational acceleration = 9.8 m/s²
h - height = 3 m
Put the values in the formula,
PE = (2.0 kg) (9.8 m/s²) (3.0 m)
PE = 58.8 J
Since,
PE = KE
Thus,
58.8 J = 1/2 m v ²
117.6 J = (2.0 kg) v ²
v = √((117.6 J) / (2.0 kg))
v = 7.668 m/s
Therefore, the velocity of the block at maximum kinetic energy is 7.668 m/s.
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This is a two part question:
What is the magnitude net force acting on an object that is pushed by a 430N and experiences 120N force?
430N
120N
310N
550N
If a net force of 375N is acting on a crate and there is 65N of friction
created, what is the magnitude net force the crate experiences?
375N
65N
310N
440N
Answer:
1. 310 N
2. 310 N
Explanation:
1. Determination of the net force.
Force applied (Fₐ) = 430 N
Force experience (Fₑ) = 120 N
Net force (Fₙ) =?
Fₙ = Fₐ – Fₑ
Fₙ = 430 – 120
Fₙ = 310 N
Hence, the net force acting on the crate is 310 N
2. Determination of the net force.
Force applied (Fₐ) = 375 N
Force of friction (Fբ) = 65 N
Net force (Fₙ) =?
Fₙ = Fₐ – Fբ
Fₙ = 375 – 65
Fₙ = 310 N
Hence, the net force acting on the crate is 310 N.
What is the acceleration of a car initially traveling at -5m/s and
reaching -22m/s in 3s.
Answer:
[tex]a=-5.67\ m/s^2[/tex]
Explanation:
Given that,
Initial velocity, u = -5 m/s
Final velocity, v = -22 m/s
Time, t = 3s
We need to find the acceleration of the car. The formula of it is given by :
Acceleration,
[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{(-22)-(-5)}{3}\\\\a=-5.67\ m/s^2[/tex]
So, the acceleration of the car is [tex]-5.67\ m/s^2[/tex].
A meter stick of uniform density is pivoted at the 75 cm mark and a 250 g mass is placed at the 90.0 cm mark. If it balances the meter stick, what is the mass of the meter stick
Answer:
The mass of the meter stick is 50 g.
Explanation:
make a sketch of the problem statement;
0-------------------------------------------------75cm------90cm-----100cm
↓ Δ ↓
W 250 g
where;
W is the mass of the meter stick
Apply the principle of moment; take moment about the pivot.
sum of the anticlockwise moment = sum of the clockwise moment
W(75 - 0) = 250(90 - 75)
W(75) = 250(15)
W(75) = 3750
W = 3750 / 75
W = 50 g
Therefore, the mass of the meter rule is 50 g.
What is the general equation for a double-displacement reaction?
Ab -> A+B
A + BX -> B + AX
AX + BY -> AY + BX
A + B -> AB
Explanation:
I know its AX+BY--->AY+BX
1 point
Which will hit the ground first, if both objects are dropped from the same
height at the same time IN AIR?*
O an icicle
O a snow flake
O both hit the ground at the same time
Answer:
an icicle
Explanation:
and icicle has less air resistance compared to that of a snow flake
how can 23.78 x 10 to the power of negative 6 metre cube per mole changed to meter cube?
Answer:
We multiply [tex]x = 23.78\times 10^{-6}\,\frac{m^{3}}{mol}[/tex] by the amount of mole to change units to cubic meters.
Explanation:
Let [tex]x = 23.78\times 10^{-6}\,\frac{m^{3}}{mol}[/tex], we change the unit to cubic meters by multiplying this number by the amount of moles of the sample. For instance, let [tex]n = 1\,mol[/tex], then the obtain the following result:
[tex]m = x\cdot n[/tex] (1)
[tex]m = \left(23.78\times 10^{-6}\,\frac{m^{3}}{mol} \right)\cdot (1\,mol)[/tex]
[tex]m = 23.78\times 10^{-6}\,m^{3}[/tex]
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Lila is a track and field athlete. She has to complete four laps around the track, which is 400 meters. The race took her 6 minutes to complete. What is her average speed to the first decimal point in m/s?
Answer:
4.44m/s
Explanation:
Given parameters:
Number of laps = 4
Length of track = 400m
Time taken = 6min
Unknown:
Average speed = ?
Solution:
The average speed is the total distance covered divided by the time taken.
It is mathematically expressed as;
Average speed = [tex]\frac{total distance}{time taken}[/tex]
Total distance = number of laps x length of track = 4 x 400 = 1600m
Now convert the time to seconds;
60s = 1 min
6 minutes will be 6 x 60 = 360s
So;
Average speed = [tex]\frac{1600}{360}[/tex] = 4.44m/s
Assume that 10 waves pass a fixed point in 5 seconds. What is the frequency of the waves in hertz?
Answer:
2 hz
Explanation:
Hertz is cps or cycles per second. 10/5= 2 cps
The frequency of the waves when 10 waves pass a fixed point in 5 seconds is 2Hz.
What is wave ?Wave is a disturbance in a medium that carries energy as well as momentum . wave is characterized by amplitude, wavelength and phase. Amplitude is the greatest distance that the particles are vibrating. especially a sound or radio wave, moves up and down. Amplitude is a measure of loudness of a sound wave. More amplitude means more loud is the sound wave.
Wavelength is the distance between two points on the wave which are in same phase.
Phase is the position of a wave at a point at time t on a waveform.
There are two types of the wave longitudinal wave and transverse wave.
Longitudinal wave : in which, vibration of the medium (particle) is parallel to propagation of the wave. Sound wave is a longitudinal wave.
Transverse wave : in which, vibration of the medium (particle) is perpendicular to propagation of the wave. Light wave is a transverse wave.
Frequency is nothing but numbers of revolution or number of cycles or number of waves in one second. its is expressed in Hertz (Hz) in SI unit.
Given,
Number waves = 10 waves
time = 5 seconds
Frequency = ?
Frequency = No of waves ÷ time
Frequency = 10 ÷ 5
Frequency = 2 Hz
Hence frequency of the wave is 2 Hz.
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help!!!! please!!! i’m not sure what the answer is for both questions please
Answer:
a.) 600N
b.) 2 m/s^2
Explanation:
a.)
In order to solve for the needed force, you must use Newton's 2nd law which states that a force is equal to mass multiplied by acceleration.
Basically: Force = mass * acceleration ; F = ma
Since both mass and acceleration are already given, just plug them into the formula and solve for force:
Mass = 200kg
Acceleration = 3m/s^2
F = m * a = 200 * 3 = 600kg * m/s^2 = 600N
b.)
In order to find the acceleration, like the hint already says, you need to find the net force first and then use Newton's 2nd law.
To calculate net force:
Since both forces are parallel (affect the same axis) and in opposite directions, you can subtract the two in order to find resultant magnitude. The resultant direction is the direction of the force with the large magnitude.
Net Force: 8N - 4N = 4N
Net Force Direction: since 8N > 4N, the direction is in the same direciton as the 8N force = Left
Finally, you find acceleration using newton's 2nd law, F = ma.
Since you already know mass and net force, plug in to solve for acceleration:
4N = 2kg * a
a = 4 N / 2kg = 2m/s^2
How does music affect our brain ?
Answer:
it makes us less stressful and more calm so we can do things easier
Explanation:
A bucket of water experiencing a gravitational force of 525 N is pulled from a water well. Net force in the Y direction is 45 N therefore the magnitude of the force of tension is__ newtons.
Answer:
T = 570 N
Explanation:
Given that,
The gravitational force acting on a bucket of water = 525 N
Net force in the Y direction is 45 N
We need to find the magnitude of the force of tension. It can be calculated as :
45 = T - 525
T = 525 + 45
T = 570 N
Hence, the force of tension is 570 N.
Answer:
570N
Explanation:
How many hydrogen and carbon atoms in a diamond
Answer:
Explanation:
Thus, total 4+4=8 C atoms are present per unit cell of diamond. Carbon has an electronic arrangement of 2,4. In diamond, each carbon shares electrons with four other carbon atoms - forming four single bonds.
derive formula of kinetic energy of particular having mass volume and velocity of dimensional analysis
Answer:
E=1/2kmv^2
Explanation:
To get the formula...
The dimension of energy is [ M^1 L^2 T^-2]
The dimension of mass [M]=[M^1 L ^0T ^0]
Dimension of velocity[V]=[M ^0 L ^1 T ^−1]
Let [E]=k[M] ^x[V] ^y
K is constant and it remain a dimensionless quantity.
Therefore, M ^1L ^2T ^−2]=k[M ^1L ^0T ^0] x[M ^0L ^1 T ^−1] y
So, x=1,y=2
E= Kmv^2
K=1/2
Therefore E is 1/2kmv^2.
Radioisotopes often emit one or more types of radiation, including alpha particles, beta particles, and gamma rays. The distance the radiation travels through matter before being absorbed increases in order from alpha to gamma. Which statement describes the best radioisotope that can be used for radioisotope imaging and for radionuclide therapy?
It emits only gamma rays.
It emits only alpha particles.
It emits alpha and beta particles.
It emits beta particles and gamma rays.
Answer:
The most correct option is the last option
Explanation:
During radioisotope/nuclear imaging in diagnosis, the radioisotope must emit gamma rays from within the body. However, in the case of radionuclide therapy, most radionuclides emit beta particles while some others also emit gamma rays.
Answer:
D
Explanation: