What is one of the major conclusions made from the study of line spectra of various elements?
A)
the movement of electrons outside the nucleus
B)
absorption and emission of energy is quantized
C)
the presence of energy beyond the visible spectrum
D)
the presence of electrons outside the nucleus of an atom

Answers

Answer 1

Answer:

B

Explanation:


Related Questions

The volume of a sample of gas (4.32 g) was 752 mL at 1.98 ATM and 62°C. The gas is​

Answers

Answer:

Bromine

Explanation:

To identify the gas, you first need to find the moles of the gas. You can do this using the Ideal Gas Law:

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = moles

-----> R = Ideal Gas Constant (0.08206 atm*L/mol *K)

-----> T = temperature (K)

After converting mL to L and Celsius to Kelvin, you can plug the values into the equation and simplify to find the moles.

P = 1.98 atm                                            R = 0.08206 atm*L/mol *K

V = 752 mL / 1,000 = 0.752 L                T = 62 °C + 273.15 = 335.15 K

n = ? moles

PV = nRT

(1.98 atm)(0.752 L) = n(0.08206 atm*L/mol *K)(335.15 K)

1.48896 = n(27.5024)

0.0541 = n

You can identify the gas by determining the molar mass of the gas, which is specific to each element. The molar mass exists as a ratio that compares the mass per 1 mole.

Molar Mass = mass / moles

Molar Mass = 4.32 g / 0.0541 moles

Molar Mass = 79.8 g/mol

This molar mass is closest to the molar mass of bromine (79.904 g/mol).

Do the following statement describe physical or chemical property!
Uranium is a radioactive element

Answers

This is a chemical property due to radioactivity being a chemical characteristic of uranium. This fact describes its chemical structure.

which best describes the source of radiation heat
A.two molecules colliding with each other
B.Objects having kinetic energy because of their motion
C.Liquid or gas circulating to move the heat
D.The Sun sending out electromagnetic waves

Answers

The sun sending out electromagnetic waves is best describes the source of radiation heat.

Radiation heat is the form of electromagnetic waves.

Radiation heat, commonly referred to as thermal radiation, is the electromagnetic radiation that defines how photons exchange heat. The technique of heat transfer known as radiant heat does not require a medium to be propagated in.

Two molecules colliding with each other produce kinetic energy, moving objects have kinetic energy. Radiation heat is thermal energy. Sun directly sends thermal radiation through electromagnetic waves.

Hence , The sun sends out electromagnetic waves directly is best describes the source of radiation heat.

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Baking soda (NaHCO3) can be added to a fruit mix solution to create a carbonated drink. An example is the reaction between baking soda and citric acid below.

C6H8O7 + 3NaHCO3 → Na3C6H5O7 + 3H2O + 3CO2

a. What is the molar mass of citric acid (C6H8O7) and baking soda (NaHCO3)?
b. How many milliliters of a 0.8 M solution of citric acid would be needed to react with 15 grams of baking soda?

I already have a done I just need b.

Answers

74.4 mL of a 0.8 M solution of citric acid would be needed to react with 15 grams of baking soda.

Equation that demonstrates reaction;

C6H8O7 + 3NaHCO3 → Na3C6H5O7 + 3H2O + 3CO2

Molar mass of citric acid (C6H8O7) =  12×6 + 1.008×8 + 16×7

                                                           =  192.064 g/mol

Molar mass of baking soda (NaHCO3) = 23 + 1 + 12 + 3×16

                                                                = 84 g/mol

[tex]^c C_6H_8O_7 = 0.8 M = 0.8 mol/L\\^m NaHCO_3 =15g[/tex]

From the reaction equation:

[tex]3[/tex] × [tex]^n C_6H_8O_7 = ^n NaHCO_3[/tex]

Molar mass of baking soda (NaHCO3) = 84 g/mol

So,

[tex]^n NaHCO_3 = ^m NaHCO_3/ ^MNaHCO_3[/tex]

And;

[tex]^n C_6H_8O_7 = ^nNaHCO_3/ 3[/tex]

From the definition of Molarity,

[tex]^V C_6H_8O_7 =\frac{^n C_6H_8O_7}{^cC_6H_8O_7 } =\frac{^n NaHCO_3}{^3*n^cC_6H_8O_7 } = \frac{^m NaHCO_3 / ^M NaHCO^3}{3*^cC_6H_8O_7 }[/tex]

Calculating;

[tex]^V C_6H_8O_7 = \frac{15/84}{3*0.8} \\[/tex]

               [tex]= 0.0744L\\= 74.4 mL[/tex]

Therefore, 74.4 mL of a 0.8 M solution of citric acid would be needed to react with 15 grams of baking soda.

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A soil test recommends applying 193 lbs N per acre. Using a 36-6-18 fertilizer, how much fertilizer is needed to meet the recommendation? Round your answer to nearest whole number.

Answers

The mass of 36-6-18 fertilizer fertilizer required is 536 lb.

What mass of nitrogen fertilizer is required for the acre of land?

The mass of nitrogen fertilizer required for the acre of land is determined as follows:

Percentage of Nitrogen in the fertilizer = 36% by weight of the fertilizer.

Mass of Nitrogen required per acre = 193 lbs

Mass of fertilizer required = 193 * 100/36

Mass of fertilizer required  = 536 lb of fertilizer.

In conclusion, the amount of fertilizer required is determined from the percent of nitrogen in the fertilizer.

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2NaN3 → 2Na + 3N2. Calculate the mass of sodium azide required to decompose and produce the number of moles of nitrogen you calculated to get 0.016

Answers

The mass of sodium azide required to decompose and produce the number of moles of nitrogen calculated to get 0.016 is 0.011moles.

How to calculate number of moles?

The number of moles of a substance can be calculated stoichiometrically as follows:

According to this question, sodium azide decomposes to produce sodium and nitrogen gas as follows:

2NaN3 → 2Na + 3N2

2 moles of sodium azide produces 3 moles of N2

This means that 0.016 moles of N2 will be produced by 0.016 × 2/3 = 0.011moles of NaN3.

Therefore, the mass of sodium azide required to decompose and produce the number of moles of nitrogen calculated to get 0.016 is 0.011moles.

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9. Predict the full Robinson Annulation product (including all intermediates) and 10. Show the stepwise mechanism for the following reaction.

Answers

The Robinson Annulation is the name for a process that combines two key reactions you've learned previously into one longer sequence. The reaction begins with a Michael reaction, followed by an intramolecular aldol condensation to give a new six-membered ring containing an alpha, beta unsaturated ketone.10-Dec-2018

1. A 4.0-g sample of glass was heated from 274K to 314 K. a temperature increase of 40 K, and was
found to have absorbed 32J of energy as heat.
a. What is the specific heat of this type of glass?
b. How much energy will the same glass sample gain when it is heated from 314 K to 344 K?

Answers

Answer:

See below

Explanation:

Q = m c T      c = specific heat   T = temp change  Q = heat joules

32 = 4 c 40     c = .2 J/g-C

314 to 344 k is a change of 30 K  

Q = m c T

  = 4 * .2 * 30 = 24 Joules

Answer:

(a) 0.2 J/g°K

(b) 24 J

Explanation:

(a)

To find the specific heat capacity, you need to use the following equation:

Q = mcΔT

In this formula,

-----> Q = heat energy (J)

-----> m = mass (g)

-----> c = specific heat capacity (J/g°K)

-----> ΔT = change in temperature (K)

You can plug the given values into the equations and simplify to find the missing value.

Q = 32 J                          c = ? J/g°K

m = 4.0 g                        ΔT = 40 K

Q = mcΔT                                              <----- Equation

32 J = (4.0 g) x c x (40 K)                     <----- Insert variables

32 J = (160) x c                                      <----- Multiply 4.0 and 40

0.2 = c                                                   <----- Divide both sides by 160

(b)

To find the energy of the same sample, you can use the same equation. This time, you know the specific heat capacity, have a different change in temperature, and are solving for energy (Q).

Q = ? J                           c = 0.2 J/g°K

m = 4.0 g                       ΔT = 344 K - 314 K = 30 K

Q = mcΔT                                         <----- Given equation

Q = (4.0 g)(0.2 J/g°K)(30 K)             <----- Insert values

Q = 24                                              <----- Multiply

Can someone please help me with this question also explain the answers I am so confused thank you.

Answers

The theoretical yield of H₂S is 13.5 g.

The percent yield is 75.5 %.

What is the theoretical yield of H₂S from the reaction?

The equation of the reaction is given below:

FeS + 2 HCl → FeCl₂+ H₂S

Moles of FeS reacting = mass/molar mass

Molar mass of FeS = 88 g/mol

Moles of FeS reacting = 35/88 = 0.398 moles

Moles of H₂S produced = 0.398 moles

Molar mass of H₂S = 34 g/mol

Mass of H₂S produced = 0.398 * 34 = 13.5 g

Theoretical yield of H₂S is 13.5 g.

Percent yield = actual yield/theoretical yield * 100%

Actual yield of H₂S = 10.2 g

Percent yield = 10.2/13.5 * 100%

Percent yield = 75.5 %

In conclusion, the actual yield is less than the theoretical yield.

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What is the molar mass of an unknown gas
with a density of 4.95 g/L at 1.00 atm and
25.0 °C?

Answers

Answer:

121 g/mol

Explanation:

To find the molar mass, you first need to calculate the number of moles. For this, you need to use the Ideal Gas Law. The equation looks like this:

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = moles

-----> R = constant (0.0821 L*atm/mol*K)

-----> T = temperature (K)

Because density is comparing the mass per 1 liter, I am assuming that the system has a volume of 1 L. Before you can plug the given values into the equation, you first need to convert Celsius to Kelvin.

P = 1.00 atm                         R = 0.0821 L*atm/mol*K

V = 1.00 L                             T = 25.0. °C + 273.15 = 298.15 K

n = ? moles

PV = nRT

(1.00 atm)(1.00L) = n(0.0821 L*atm/mol*K)(298.15 K)

1.00 = n(0.0821 L*atm/mol*K)(298.15 K)

1.00 = (24.478115)n

0.0409 = n

Now, we need to find the molar mass using the number of moles per liter (calculated) and the density.

0.0409 moles           ? grams           4.95 grams
----------------------  x  ------------------  =   ------------------
        1 L                       1 mole                     1 L

? g/mol = 121 g/mol

**note: I am not 100% confident on this answer

27.2 kg of a solution containing 18.7 % KCl by mass
Express your answer in kilograms using three significant figures.

Answers

The amount of potassium chloride (KCl) in 27.2 kg of a solution containing 18.7% KCl by mass solution is 5.086 kg.

How to find the mass of solute ?

Mass of solute = Mass percent of solute x  Mass of the solution

Here,

Mass percent of solute = 18.7 %

Mass of the solution = 27.2 kg

Now put the value in above formula we get

Mass of solute = Mass percent of solute x  Mass of the solution

                         = [tex]\frac{18.7}{100} \times 27.2\ kg[/tex]

                         = [tex]\frac{508.64}{100}[/tex]

                         = 5.086

Thus from the above conclusion we can say that The amount of potassium chloride (KCl) in 27.2 kg of a solution containing 18.7% KCl by mass solution is 5.086 kg.

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Fill in the chart below to identify the properties of shape and volume for each type of matter. Shape Volume Solid Liquid Gas

Answers

The properties are given below:

Shape: Solids have definite shape; liquids take the shape of their container; gases have no shape.Volume: Solids have definite volume; liquids have definite volume; gases do not have a definite volume

What are the properties of solids, liquids and gases?

The property of solids, liquids, and gases refers to those features which are used to identify solids, liquids and gases.

Some property of solids, liquids and gases are shape and volume.

Shape: Solids have definite shape; liquids take the shape of their container; gases have no shape.

Volume: Solids have definite volume; liquids have definite volume; gases do not have a definite volume

In conclusion, solids, liquids and gases have unique properties in their shape and volume.

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For each pair of molecules given in the table below, identify the correct relationship.

Answers

For each pair of molecules given in the table below, the correct relationships are identified as follows.

The relationships between the molecules are given as?

These are structural isomers. This is because, they have the same molecular formula (C₆H₁₂) but possess varying structures.The given pair of molecules posses similar formula (C₄H₁₀O) and can be superimposed on one another via rotation of the entire molecule, hence they are identical isomers.In this case the pair of molecules possess similar molecular formula (C₄H₁₀O) and similar arrangement of atoms. Hence, they are identical isomers.This case also features structural isomers. They both contain the same carbon chain with similar formula - C₃H₆BrClThese pair as identical isomers. They are also derived from  C₃H₆BrCl.This pair are called stereoisomers isomers. This is because they contain the same about of molecules but are different in the position of the alcohol (-OH) group. But more importantly, the position of the bonding is the same.This set is a functional pair. This is because the composition of the molecules present in each case are different.This is also a functional pair.

What is a molecules?

A molecule is a bonded collection of atoms that represents the smallest fundamental unit of a chemical compound that may participate in a chemical process.

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PLEASE HELP!!!

A sample of xenon occupies a volume of 715 mL at 8.01 atm and 67 °C. If the volume is changed to 963 mL and the temperature is changed to 52 °C, what will
be the new pressure?

Answers

Answer:

4.62 atm

Explanation:

To find the missing pressure, you need to use the Combined Gas Law equation:

P₁V₁ / T₁ = P₂V₂ / T₂

In this equation, "P₁", "V₁", and "T₁" represent the initial pressure, volume, and temperature. "P₂", "V₂", and "T₂" represent the final pressure, volume, and temperature.

P₁ = 8.01 atm                      P₁ = ? atm

V₁ = 715 mL                        V₁ = 963 mL

T₁ = 67 °C                           T₁ = 52 °C

P₁V₁ / T₁ = P₂V₂ / T₂

(8.01 atm)(715 mL) / 67 °C = P₂(963 mL) / 52 °C

85.47985 = P₂(963 mL) / 52 °C

4444.952 = P₂(936 mL)

4.62 atm = P₂

I need help with my work

Answers

Answer:

2 the mass is greater than 10.0gram

Explanation:

2 the mass is greater than 10.0gram

You need to calculate the enthalpy change (AH) of the reaction A + 2B → C.
How can the enthalpies given for the reaction steps below be combined to
give the overall change in enthalpy?
D+B
D+3B
A. AH = AH2-A H₁
B. AH=2AH₁+AH²₂
OC. AH AH ₁ +AH²₂
D. AH = A H₁-AH₂
A
C
A
AH°,
A Hº

Answers

The enthalpy change of the reaction:  A + 2B → C is determined as follows: ΔH = ΔH₁ +  ΔH₂; option C

What is enthalpy change?

Enthalpy change refers to the change in heat content as reactant molecules combine to form products.

The enthalpy change of a multistep reaction is calculated from by summing the enthalpy changes of the intermediate steps that leads to the overall reaction.

Thus, the enthalpy change of the reaction:  A + 2B → C is determined as follows:

ΔH = ΔH₁ +  ΔH₂

In conclusion, the enthalpy change of the reaction is determined from the summation of the enthalpy changes that occur in the intermediate steps.

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27.2 kg of a solution containing 18.7 % KCl by mass
Express your answer in kilograms using three significant figures.

Answers

The amount of potassium chloride (KCl) in 27.2 kg of a solution containing 18.7% KCl by mass solution is 5.086 kg.

How to find the mass of solute ?

Mass of solute = Mass percent of solute x  Mass of the solution

Here,

Mass percent of solute = 18.7 %

Mass of the solution = 27.2 kg

Now put the value in above formula we get

Mass of solute = Mass percent of solute x  Mass of the solution

                         = [tex]\frac{18.7}{100} \times 27.2\ kg[/tex]

                         = [tex]\frac{508.64}{100}[/tex]

                         = 5.086

Thus from the above conclusion we can say that The amount of potassium chloride (KCl) in 27.2 kg of a solution containing 18.7% KCl by mass solution is 5.086 kg.

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Question 9
What pressure will be exerted by 15 g of carbon dioxide gas in a 20 L container at 0 °C?

Answers

Answer:

0.382 atm

Explanation:

In order to find the pressure, you need to know the moles of carbon dioxide (CO₂) gas. This can be found by multiplying the mass (g) by the molar mass (g/mol) of CO₂. It is important to arrange the conversion in a way that allows for the cancellation of units.

Molar Mass (CO₂): 12.011 g/mol + 2(15.998 g/mol)

Molar Mass (CO₂): 44.007 g/mol

15 grams CO₂               1 mole
----------------------  x  ------------------------  =  0.341 moles CO₂
                                44.007 grams

To find the pressure, you need to use the Ideal Gas Law equation.

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = moles

-----> R = Ideal Gas Constant (0.08206 atm*L/mol*K)

-----> T = temperature (K)

After you convert Celsius to Kelvin, you can plug the given and calculated values into the equation and simplify to find the pressure.

P = ? atm                              R = 0.08206 atm*L/mol*K

V = 20 L                               T = 0 °C + 273.15 = 273.15 K

n = 0.341 moles

PV = nRT

P(20 L) = (0.341 moles)(0.08206 atm*L/mol*K)(273.15 K)

P(20 L) = 7.64016

P = 0.382 atm

A sample of flammable liquid is placed into an enclosed cylinder which is then fitted with a movable piston. Initially the cylinder maintains a volume of 1.7 L. The sample is ignited producing gas and releasing 439.6 J of energy. To what volume will the cylinder expand to if it must expand against a pressure of 738.52 mmHg. Assume all the energy released is converted to work used to push the piston? Answer to 1 decimal space.

Answers

Cylinder will expand to 6.08 Lit by assuming that all the energy released is converted to work used to push the piston.

Concept of work :If we  apply force on an object and if the object moves and changes it's position, then product of the force and the displacement of an object in the direction of applied force is called work.

Given,

Pressure= P= 738.52 mm Hg = 0.97 atm. (∵ 760 mm Hg = 1 atm)

Initial volume =V1= 1.7 L

Work done = W = 439.6 J

As we need our answer in litters ..

let's convert the work done into suitable units

∴work done = W = 4.26 L-atm (∵ 1 J = 101.3 L-atm)

As given all the energy is assumed to converted into work so we need not to worry About heat loss or entropy.

work done = pressure * difference in volume

W = PΔV

ΔV = 4.26÷ 0.97

∴ΔV = 4.38 LIt

There for, the volume expanded = 4.38 Lit

So, total volume = 4.38+ 1.7 = 6.08 Lit.

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The solubility of the ionic compound MX3, having a molar mass of 288 g/mol, is 3.60 x 10-2 g/L. Calculate the KSP of the compound.

Answers

[tex]K_{sp}[/tex] of the compound is found to be  5.04 ×[tex]10^{-10}[/tex].

Solubility :Solubility can be define as the amount of a substance that dissolves or mixes in a given amount of solvent at specific conditions.

Solubility equilibrium

Ksp = [tex][A^{+} ]^{a}[/tex] [tex][B^{-} ]^{b}[/tex]

Ksp = solubility product constant

A+ = cation in an aquious solution

B- = anion in an aqueous solution

a, b = relative concentrations of a and b

Given,

Solubility = s = 3.60 × [tex]10^{-2}[/tex] g/L

molar mass = 288 g/ mol

∴ s= 3.60 × [tex]10^{-2}[/tex] g/L ÷ 288 g/ mol = 1.25 ×[tex]10^{-4}[/tex] mol/ L

Reaction:

MX3 ⇄ M + 3X

           s       3s

[tex]K_{sp}[/tex] =[ [tex]M^{+3}[/tex]] [ [tex]X^{-1}[/tex][tex]]^{3}[/tex] = solubility product

∴ [tex]K_{sp}[/tex] =[tex][s]^{} [3s]^{3}[/tex]

∴ [tex]K_{sp}[/tex] = 3 [tex]s^{4}[/tex]

∴ [tex]K_{sp}[/tex] = 3 × (3.60 × [tex]10^{-2}[/tex] [tex])^{4}[/tex]

[tex]K_{sp}[/tex] = 503.8848 ×[tex]10^{-8}[/tex]  = 5.04 ×[tex]10^{-10}[/tex]

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which celsius temperature is equal to 298k

Answers

Answer:

298-273 = 25°C is correct answer!

pls help i need this ASAP​

Answers

Answer:

a. 54 calories burnt

b. multiplied by 9

When ATP breaks down to ADP, potential energy stored in bonds is released. This energy stored in bonds is

Answers

In all forms of chemical bonds,the energy stored is chemical energy

Using the balanced equation below.
how many grams of cesium fluoride
would be required to make 73.1 g
of
cesium xenon heptafluoride?
CSF + XeF6 - CsXeF7
A

Answers

Answer:

28.0 grams CsF

Explanation:

To find the mass of CsF, you need to (1) convert grams CsXeF₇ to moles CsXeF₇ (via molar mass), then (2) convert moles CsXeF₇ to moles CsF (via mole-to-mole ratio from equation coefficients), and then (3) convert moles CsF to grams CsF (via molar mass). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value.

Molar Mass (CsF): 132.91 g/mol + 18.998 g/mol

Molar Mass (CsF): 151.908 g/mol

Molar Mass (CsXeF₇): 132.91 g/mol + 131.29 g/mol + 7(18.998 g/mol)

Molar Mass (CsXeF₇): 397.186 g/mol

1 CsF + XeF₆ -----> 1 CsXeF₇

73.1 g CsXeF₇             1 mole                 1 mole CsF              151.908 g
----------------------  x  --------------------  x  ------------------------  x  ------------------  =
                                  397.186 g           1 mole CsXeF₇             1 mole

=  27.958 g CsF

=  28.0 g CsF

What is the [H3O+] if the [OH-] is 1 x 10 -8?

Answers

From the calculation, the concentration of the oxonium ions is 1 * 10^-6 M

What is concentration?

The term concentration refers to the amount of substances present in the solution. There are several units that can be used to show the concertation of a substances such as moles/liter, gram per liter, parts per billion, parts per billion, percentage etc.

Now we know that water is composed of the hydrogen and the hydroxide ions and the product of the both is generally known as the ion product of water and have a value of 1 * 10^-14.

If that be the case, we are in order to write the expression;

[H3O+]  [OH-] = 1 * 10^-14

[H3O+] = 1 * 10^-14/ [OH-]

[H3O+] = 1 * 10^-14/ 1 x 10^ -8

[H3O+] = 1 * 10^-6 M

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1. Consider the unbalanced equation:

Mg (s) + HCl (aq) ---> MgCl2 (s) + H2 (g)

If 4.59 mol of Mg and 4.59 mol of HCl are reacted, how many moles of MgCl2 are produced?

Hint: Write the balanced equation first.

Answers

Answer:

2.30 moles MgCl₂

Explanation:

First, you need to balance the chemical equation. An equation is balanced when there is an equal amount of each element on both sides of the reaction. These values can be modified by adding coefficients in front of the molecules.

The unbalanced equation:

Mg (s) + HCl (aq) ---> MgCl₂ (s) + H₂ (g)

Reactants: 1 magnesium, 1 hydrogen, 1 chlorine

Products: 1 magnesium, 2 hydrogen, 2 chlorine

The balanced equation:

Mg (s) + 2 HCl (aq) ---> MgCl₂ (s) + H₂ (g)

Reactants: 1 magnesium, 2 hydrogen, 2 chlorine

Products: 1 magnesium, 2 hydrogen, 2 chlorine

Now, you need to use the mole-to-mole ratios from the balanced equation to convert between moles. Since we were not given a limiting reactant, the easiest way to find the actual moles of MgCl₂ is to start from both reactants.

4.59 moles Mg            1 mole MgCl₂
-------------------------  x  ------------------------  =  4.59 moles MgCl₂
                                       1 mole Mg

4.59 moles HCl           1 mole MgCl₂
-------------------------  x  ------------------------  =  2.30 moles MgCl₂
                                     2 moles HCl

Since HCl produces the smaller amount of product, it must be the limiting reactant. In other words, HCl runs out before all of the Mg is completely used up. Therefore, the actual amount of MgCl₂ produced in 2.30 moles.

What is the initial volume, in milliliters, needed to prepare each of the following diluted solutions? 330mL of 7.5% (m/v) HCl from 17% (m/v) HCl

Answers

Taking into account the definition of dilution, the initial volume needed to prepare each of the diluted solution is 145.59 mL.

Dilution

When it is desired to prepare a less concentrated solution from a more concentrated one, it is called dilution.

Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution at the same amount of solute.

In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

A dilution is mathematically expressed as:

Ci×Vi = Cf×Vf

where

Ci: initial concentrationVi: initial volumeCf: final concentrationVf: final volume

Final volume

In this case, you know:

Ci= 17% (m/v)Vi= ?Cf= 7.5% (m/v)Vf= 330 mL

Replacing in the definition of dilution:

17% (m/v)× Vi= 7.5% (m/v)× 330 mL

Solving:

Vi= (7.5% (m/v)× 330 mL)÷ 17% (m/v)

Vi= 145.59 mL

In summary, the initial volume needed to prepare each of the diluted solution is 145.59 mL.

Learn more about dilution:

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6. Which of the following is an electrical hazard?
OA. A machine without guards in place
OB. A welding cylinder without a safety cap
OC. A broken ground post on a plug
O D. An ingoing nip point
+

Answers

I believe the answer is C because the first two are mechanical hazards and C mentions plug which is electrical.

What is an orbital in chemistry

Answers

A mathematical function known as an orbital is used to describe the wave-like behavior of an electron, an electron pair, or (less frequently) nucleons.

Atomic orbitals outline the potential locations of electrons within an atom. In molecules, molecular orbitals play the same function.

Each atomic orbital has three quantum numbers, n, l, and ml, attached to it. The wave function was used to calculate these numbers.

The square of the wave function 2 can be used to calculate the size and form of an orbital.

All atomic orbitals are centered on the atomic nucleus and have unique forms.

The s, p, and d orbitals—orbitals that correspond to the s, p, and d subshells—are the orbitals that are most frequently encountered in introductory quantum chemistry.

F orbitals can be found in the ground states of heavier atoms as well.

For a detailed study about orbital refer given link https://brainly.com/question/17371976.

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Answer:

In chemistry, an orbital is related to also a wave function. An Orbital is a practical region or part that is around the nucleus in a molecule and maybe an atom. It can contain up to two electrons, electrons form themselves around the nucleus.

Explanation:

No Explanation

4.50 moles of glucose in 3.50 L of a glucose solution

Answers

Answer:

Molarity = 1.28

Explanation:

[tex]m= n/v[/tex]

M = molar concentration

n = moles of solute

v = liters of solution

Molarity = moles of solute / litres of solution.

]

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