What is the common denominator of

Please ignore my choice I had to click one of them

Answer:

Prat two of e) 6/12 Both the numerator and denominator were multipled by three, the number of boxes we split each box into.

F) we can multiply both the numerator and denominator without changing the values, so 2a/2b or 10a/10b

Step-by-step explanation:

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Answer:

[tex]2 \sqrt{35} [/tex]

Answer:

y=1/4x - 1

Step-by-step explanation:

going off of the picture, I'd say this is your answer

Step-by-step explanation:

Hey there!

The given function is; f(x) = 2x-4.

To find: f'(X)

Let f(X) be y, then;

y = 2x - 4

Interchanging"X" and "y" we get;

x = 2y - 4

or, X+4 = 2y

or, y = (X+4)/ 2

Therefore, f'(X) = (X+4)/2.

Hope it helps!

Answer:

Kindly check explanation

Step-by-step explanation:

H0 : quality does not vary among shift

H1 : quality varies among shift

The expected values :

(Row * column) / grand total

Given the data:

Observed values :

_________________total

_______467 191 42 __700

_______445 171 34 __650

_______254 129 17 _ 400

Total __ 1166 491 93 _ 1750

Expected value count using the formula :.

Expected Values:

466.4 ____196.4 ______37.2

433.086 _182.371___ 34.5429

266.514_ 112.229____ 21.2571

The Chisquare statistic (χ²) :

χ² = (observed - Expected)²/ observed

χ² = 5.76045

The degree of freedom = (row - 1) * (column - 1)

Degree of freedom = (3-1)*(3-1) = 2*2 = 4

Pvalue = 0.2178

Pvalue > α ; We foal to reject H0 ; Hence, we conclude that quality does not vary among shift

Answer:

5.23%

Step-by-step explanation:

See Image below:)

Given:

The frequency distribution table is:

Values of variable X        Frequency

              32                                2    

              37                                5

              46                                3

              48                                9

To find:

The mode of the given data set.            

Solution:

We know that mode is the most frequent value of the data set.

In the given data set highest frequency is 9 that is corresponding to the value 48.

Therefore, the mode of the given data set is 48. Hence, the correct option is (b).

Answer:

Option D, 55.45 to 70.95

Step-by-step explanation:

Alpha = 1 – confidence interval  

Alpha = 1 – 0.98 = 0.02

Sample size = n = 8

t (alpha/2) ; (n-1) = t (0.02/2) ; (8-1) = t 0.01, 7 = 2.998

Mean = sum of all frequencies /total number of frequency = 505.6/8 = 63.2

s = 7.309

E = t (0.01;7) * s/sqrt n

Substituting the given values, we get –  

E = 2.998 * 7.309 /sqrt  (8)

E = 7.75  

98% confidence interval  

Mean – E  and Mean + E

63.2 – 7.75 and 63.2 + 7.75  

(55.45, 70.95)

Answer: 55.45 to 70.95

Step-by-step explanation:

Cosine(angle) = adjacent leg/ hypotenuse

Cosine( angle ) = 18/20

Angle = arccos(18/20)

Angle = 26 degrees

Answer:

26°

Step-by-step explanation:

For a right triangle, we can use trigonometry equations :-

In this case we need to use cosine equation .

cos A = adjacent side / hypotenuse

cos A = 18 / 20

A = cos × 18/20

A = arccos × 18/20

A = 26°

Answer:

The numbers of ways to permute letters of the word Illinois if the two Ls must be consecutive is 7.

The word ILLINOIS contains 7 letters.

To estimate the number of different permutations, consider the total number of letters factorial and divide by the frequency of each letter factorial. The little n's exist the frequencies of each various (different) letter.

We will use the formula for the number of permutations with imperceptible objects. Since the two L's must be consecutive, we consider them to be a single letter LL. Then the word ILLINOIS contains n = 7 letters: 3 I's, 1 LL, 1 N, 1 O, and 1S.

Hence the number of methods to permute letters of the word ILLINOIS if the two L's must be consecutive exists:

[tex]$\frac{7 !}{3 ! 1 ! 1 ! 1 ! 1 !}=7 \cdot 6 \cdot 5 \cdot 4=840 \text {. }$$[/tex]

The word ILLINOIS contains 7 letters.

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Answer:

[tex]\frac{9}{3x + 2} = 1 - \frac{1}{3}(x - \frac{7}{3}) + \frac{1}{9}(x - \frac{7}{3})^2 - \frac{1}{27}(x - \frac{7}{3})^3 ........[/tex]

The interval of convergence is:[tex](-\frac{2}{3},\frac{16}{3})[/tex]

Step-by-step explanation:

Given

[tex]f(x)= \frac{9}{3x+ 2}[/tex]

[tex]c = 6[/tex]

The geometric series centered at c is of the form:

[tex]\frac{a}{1 - (r - c)} = \sum\limits^{\infty}_{n=0}a(r - c)^n, |r - c| < 1.[/tex]

Where:

[tex]a \to[/tex] first term

[tex]r - c \to[/tex] common ratio

We have to write

[tex]f(x)= \frac{9}{3x+ 2}[/tex]

In the following form:

[tex]\frac{a}{1 - r}[/tex]

So, we have:

[tex]f(x)= \frac{9}{3x+ 2}[/tex]

Rewrite as:

[tex]f(x) = \frac{9}{3x - 18 + 18 +2}[/tex]

[tex]f(x) = \frac{9}{3x - 18 + 20}[/tex]

Factorize

[tex]f(x) = \frac{1}{\frac{1}{9}(3x + 2)}[/tex]

Open bracket

[tex]f(x) = \frac{1}{\frac{1}{3}x + \frac{2}{9}}[/tex]

Rewrite as:

[tex]f(x) = \frac{1}{1- 1 + \frac{1}{3}x + \frac{2}{9}}[/tex]

Collect like terms

[tex]f(x) = \frac{1}{1 + \frac{1}{3}x + \frac{2}{9}- 1}[/tex]

Take LCM

[tex]f(x) = \frac{1}{1 + \frac{1}{3}x + \frac{2-9}{9}}[/tex]

[tex]f(x) = \frac{1}{1 + \frac{1}{3}x - \frac{7}{9}}[/tex]

So, we have:

[tex]f(x) = \frac{1}{1 -(- \frac{1}{3}x + \frac{7}{9})}[/tex]

By comparison with: [tex]\frac{a}{1 - r}[/tex]

[tex]a = 1[/tex]

[tex]r = -\frac{1}{3}x + \frac{7}{9}[/tex]

[tex]r = -\frac{1}{3}(x - \frac{7}{3})[/tex]

At c = 6, we have:

[tex]r = -\frac{1}{3}(x - \frac{7}{3}+6-6)[/tex]

Take LCM

[tex]r = -\frac{1}{3}(x + \frac{-7+18}{3}+6-6)[/tex]

r = -\frac{1}{3}(x + \frac{11}{3}+6-6)

So, the power series becomes:

[tex]\frac{9}{3x + 2} = \sum\limits^{\infty}_{n=0}ar^n[/tex]

Substitute 1 for a

[tex]\frac{9}{3x + 2} = \sum\limits^{\infty}_{n=0}1*r^n[/tex]

[tex]\frac{9}{3x + 2} = \sum\limits^{\infty}_{n=0}r^n[/tex]

Substitute the expression for r

[tex]\frac{9}{3x + 2} = \sum\limits^{\infty}_{n=0}(-\frac{1}{3}(x - \frac{7}{3}))^n[/tex]

Expand

[tex]\frac{9}{3x + 2} = \sum\limits^{\infty}_{n=0}[(-\frac{1}{3})^n* (x - \frac{7}{3})^n][/tex]

Further expand:

[tex]\frac{9}{3x + 2} = 1 - \frac{1}{3}(x - \frac{7}{3}) + \frac{1}{9}(x - \frac{7}{3})^2 - \frac{1}{27}(x - \frac{7}{3})^3 ................[/tex]

The power series converges when:

[tex]\frac{1}{3}|x - \frac{7}{3}| < 1[/tex]

Multiply both sides by 3

[tex]|x - \frac{7}{3}| <3[/tex]

Expand the absolute inequality

[tex]-3 < x - \frac{7}{3} <3[/tex]

Solve for x

[tex]\frac{7}{3} -3 < x <3+\frac{7}{3}[/tex]

Take LCM

[tex]\frac{7-9}{3} < x <\frac{9+7}{3}[/tex]

[tex]-\frac{2}{3} < x <\frac{16}{3}[/tex]

The interval of convergence is:[tex](-\frac{2}{3},\frac{16}{3})[/tex]

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Answer:

  8%

Step-by-step explanation:

The fraction donated was $632/$7900.

As a percentage, that is ...

  632/7900 × 100% = 0.08 × 100% = 8%

The store donated 8% of sales to charity.

Answer:

This is the whole process I guess

Step-by-step explanation:

[tex] \sqrt{15} = 3.872983346 = 3.88[/tex]

Answer:

Because this gravity of. The earth

Answer:

D. An exponential parent function

Step-by-step explanation:

The basic parent function of any exponential function is f(x) = bx, where b is the base. Using the x and y values from this table, you simply plot the coordinates to get the graphs. The parent graph of any exponential function crosses the y-axis at (0, 1), because anything raised to the 0 power is always 1.

The parent function that represents the graph is exponential.

A function is a relation between a dependent and independent variable. We can write the examples of function as -

y = f(x) = ax + b

y = f(x, y, z) = ax + by + cz

Given is a function as shown in the image. It is asked to identify the parent function of this graph.

The parent function will be quadratic if the plotted graph is a parabola.

The parent function will be linear if the plotted graph is a straight line.

The parent function will be an absolute function if it is V - shaped.

So, none of the options other than the exponential parent function represents the graph.

Therefore, the parent function that represents the graph is exponential.

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Answer: [tex]32.36\ ft[/tex]

Step-by-step explanation:

Given

Ladder is leaned and make an angle of [tex]68^{\circ}[/tex]

Electric box is 30 ft up the ground.

Suppose x is the length of ladder

From the figure, we can write

[tex]\Rightarrow \sin 68^{\circ}=\dfrac{30}{x}\\\\\Rightarrow x=\dfrac{30}{\sin 68^{\circ}}\\\\\Rightarrow x=32.36\ ft[/tex]

The Sine or Sinθ in a right angle triangle is the ratio of its perpendicular to its Hypotenuse. The length of the ladder is 32.356 feet.

The Sine or Sinθ in a right angle triangle is the ratio of its perpendicular to its Hypotenuse. it is given as,

[tex]\rm{Sine(\theta) = \dfrac{Perpendicular}{Hypotenuse}[/tex]

where,

θ is the angle,

Perpendicular is the side of the triangle opposite to the angle θ,

The hypotenuse is the longest side of the triangle.

As it is given that the height of the electric box from the bottom is 30 feet, while the ladder makes an angle of 68° with the ground.

The length of the ladder can be found using the trigonometric functions, therefore, the length of the ladder can be written as,

[tex]\rm Sine(\theta) = \dfrac{Perpendicular}{Hypotenuse}\\\\\\Sine(\angle C) = \dfrac{AB}{\text{Length of the ladder}}\\\\\\{\text{Length of the ladder}}= \dfrac{AB}{Sine(\angle C) }\\\\\\{\text{Length of the ladder}}= \dfrac{30}{Sine(68^o) }\\\\\\{\text{Length of the ladder}}= 32.356\ feet[/tex]

Hence, the length of the ladder is 32.356 feet.

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Answer:

The desired distance is √5

Step-by-step explanation:

Recall that the distance from a point to a line is measured along a path perpendicular to the line.  Thus, given the line y = -2x + 5, the slope of any line perpendicular to it is the negative reciprocal of -2:  +1/2.

The line perpendicular to y = -2x + 5 and passing through (4, 2) is

y - 2 = (1/2)(x - 4), or

2y - 4 = x - 4, or 2y = x, or y = (1/2)x.

Now our problem becomes "find the length of the line connecting (4, 2) and the intersection of y = -2x + 5 and y = (1/2)x."  

Equating these, we get (1/2)x = -2x + 5, which, if multiplied through by 2, becomes x = -4x + 10, or 5x = 10, or x = 2.  If x = 2, then y = (1/2)(2) = 1.

Finally, find the distance between (2, 1) and (4, 2):

Using the Pythagorean Theorem, d = √(2^2 + 1^2) = √5

The distance from (4, 2) to the line y = -2x + 5 is √5

C.(f-g)(x) = 4x^3 +5x²-7x-1

Step-by-step explanation:

Given information :

[tex]f(x) = 4 {x}^{3} + 5 {x}^{2} - 3x - 6 \\ g(x) = 4x - 5[/tex]

Find :

[tex](f - g)(x) = \\ (4 {x}^{3} + 5 {x}^{2} - 3x - 6) \\ - 4x -5[/tex]

Open bracket and Simplify

[tex]4 {x}^{3} + 5 {x}^{2} - 3x - 6 - 4x + 5 \\ 4 {x}^{3} + 5 {x}^{2} - 7x - 1[/tex]

Answer:

Step-by-step explanation:

I=∫e^2x dx

put 2x=t

2dx=dt

dx=dt/2

I=1/2∫e^t dt

=1/2 e^t+c

=1/2 e^{2x}+c

Answer:

first option is the correct answer.

Step-by-step explanation:

Step-by-step explanation:

6/5 this is the answer hopes this help

Answer:

A: 9:5  B: 5:14

Step-by-step explanation:

cos 36 × cos 72 = 0.25

cos 36 × cos 72 =

0.309 x 0.809 = 0.249 = 0.25

Answer:

The average rate of change in the number of public library visits from 1993 to 1997 was of 0.1 billion an year.

Step-by-step explanation:

Average rate of change:

Division of the subtraction of the final value by the initial value, divided by the length of time.

The number of visits to public libraries increased from 1.3 billion in 1993 to 1.7 billion in 1997.

Initial value: 1.3 billion

Final value: 1.7 billion

1997 - 1993 = 4 years.

Thus:

[tex]A = \frac{1.7 - 1.3}{4} = \frac{0.4}{4} = 0.1[/tex]

The average rate of change in the number of public library visits from 1993 to 1997 was of 0.1 billion an year.

Answer:

0.837

Step-by-step explanation:

3850*4.65%=179.025

150/179.025=0.837

0.837

Answer:

B for first one.

75 for second.

Hope this helps !

Step-by-step explanation: