What is the limiting reactant if 70. 0 g of c7h6o3 and 80. 0 g of c4h6o3 react?watersalicylic acidacetic anhydrideacetylsalicylic acid.

Answers

Answer 1

The limiting reactant if 70.0 g of C7H6O3 and 80.0 g of C4H6O3 react is salicylic acid (C7H6O3).

In this case, given that:

70g C7H6O3

80g C4H6O3

Molar mass of C7H6O3 = 138 g/mol

Molar mass of C4H6O3 = 102 g/mol

So, we need to convert C7H6O3 to C4H6O3 as below:

= 70g C7H6O3

= (molar mass of C4H6O3 / molar mass of C7H6O3) * mass of C7H6O3

= (102 / 138) * 70

= 51.74g C4H6O3

Thus, when 70.0 g of C7H6O3 and 80.0 g of C4H6O3 react, it will be:

80g C4H6O3 – 51.74g C4H6O3 = 28.26g C4H6O3

And, that means there are 28.26g C4H6O3 left after reacting it with C7H6O3.

Hence, the limiting reactant is salicylic acid (C7H6O3).

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Answer:

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:)

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Answers

Answer:

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Not My answer But I saw That You needed it.

Credit zeeshanfazil

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