What is the measure of angle A?

Answer:

x is equal to 5

Step-by-step explanation:

Answer:

All you need to do is suppose x = 3x :

[tex] \tt \: g(x) = \boxed{ \tt{2^{3x} }} [/tex]

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Answer: [tex](x,y)=\{(-1,1), (0,4) \}[/tex]

Step-by-step explanation:

[tex]3x^2 +6x+4=-3x^2 +4\\\\6x^2 +6x=0\\\\x^2 +x=0\\\\x(x+1)=0\\\\x=-1, 0\\\\x=-1 \longrightarrow y=1\\\\x=0 \longrightarrow y=4\\\\\therefore (x,y)=\{(-1,1), (0,4) \}[/tex]

The solution of the quadratic equations will be ( 0, 4 ) and ( -1, 1).

A quadratic equation is a polynomial with a degree of 2 or the maximum power of the variable is 2 in quadratic equations. It has two solutions as its maximum power is 2.

Given quadratic equations are given as below:-

y = 3x² + 6x + 4

y = -3x² + 4

Equate the equations and solve for the value of x.

3x² + 6x + 4 = -3x² + 4

6x² + 6x = 0

x² + x = 0

x ( x + 1 ) = 0

x = 0 and x = -1

At x=0 and x=-1 the values of y are calculated as below:-

y = -3x² + 4

y = 0+ 4 = 4

y = -3 + 4 = 1

Therefore, the solution of the quadratic equations will be ( 0, 4 ) and ( -1, 1).

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The numerical values of the mean and standard deviation are 4 and 1.55, respectively

The given parameters are:

n = 10

π = 0.4

The probability is then calculated as:

[tex]P(x) = ^nC_x * \pi^x *(1-\pi)^{n-x}[/tex]

So, we have:

[tex]P(6) = ^{10}C_6 * 0.4^6 *(1-0.4)^4[/tex]

Apply the combination formula

[tex]P(6) = \frac{10!}{6!4!} * 0.4^6 *0.6^4[/tex]

So, we have:

[tex]P(6) = 210 * 0.4^6 *0.6^4[/tex]

Evaluate

P(6) = 0.1115

Hence, the numerical value of the probability that x = 6 is 0.1115

The mean value is:

[tex]\bar x = n\pi[/tex]

This gives

[tex]\bar x = 10 * 0.4[/tex]

[tex]\bar x = 4[/tex]

The standard deviation value is:

[tex]\sigma = \sqrt{\bar x(1-\pi)[/tex]

This gives

[tex]\sigma = \sqrt{4(1-0.4)[/tex]

[tex]\sigma = 1.55[/tex]

Hence, the numerical values of the mean and standard deviation are 4 and 1.55, respectively

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The volume of the figure to the nearest whole number = 756π m³.

The figure shown exists composed of a cone and a cylinder.

The volume of the figure = volume of cone + volume of the cylinder

Height of cone = 12 - 8 = 4

Radius (r) of cone = 18/2 = 9 m

The volume of the cone V = 1/3hπr²

= 1/3 [tex]*[/tex] 4π [tex]*[/tex] 9² = 108π

The volume of the Cylinder = πr²h

radius (r) = 18/2 = 9 m

height (h) = 8 m

Volume of cylinder = π [tex]*[/tex] 9² [tex]*[/tex] 8 = 648π m³

Volume of the figure = 108π + 648π = 756π

The volume of the figure to the nearest whole number = 756π m³.

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La relación dada es una función si x = 4 y y = - 1. La representación de la función es f= {(2, 8), (4, 5), (- 2, 9), (3, 9), (5, 4)}.

Las relaciones están formadas por dos conjuntos relacionados entre sí, un conjunto de entrada denominado dominio y uno de salida denominado rango. Una función es una relación cuyos elementos del dominio solo están asociados a un solo valor del rango.

Bajo estas consideraciones, tenemos que (2, 8) = (2, x² - 2 · x) y (3, 9) = (3, y + 4), cuyas ecuaciones algebraicas se resuelven a continuación:

x² - 2 · x = 8     (1)

y + 4 = 9     (2)

By (1):

x² - 2 · x - 8 = 0

(x - 4) · (x + 2) = 0

x = 4 ∨ x = - 2

By (2):

y = 5

Si sabemos que x = 4 y y = - 1, entonces la representación de la función es:

f= {(2, 8), (4, 5), (- 2, 9), (3, 9), (5, 4)}

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Using the binomial distribution, we have that:

a) There is a 0.2111 = 21.11% probability that a six will occur exactly twice.

b) The expected number of sixes is of 3.2.

c) The variance of the number of sixes is of 2.35.

The formula is:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

The parameters are:

For this problem, the parameters are given by:

p = 8/30 = 0.2667, n = 12.

Item a:

The probability is P(X = 2), hence;

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 2) = C_{12,2}.(0.2667)^{2}.(1-0.2667)^{10} = 0.2111[/tex]

Item b:

The expected number of the binomial distribution is:

E(X) = np.

Hence:

E(X) = 12 x 8/30 = 3.2.

Item c:

The variance of the binomial distribution is:

V(X) = np(1-p).

Hence:

E(X) = 12 x 8/30 x 22/30 = 2.35.

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Answer:

D. 5/72

Step-by-step explanation:

The non-zero digits are 1 through 9.

There are 9 different non-zero digits.

p(A) = 1/9

There are 5 odd digits.

p(B) = 5/8

p(A and B) = p(A) × p(B) = 1/9 × 5/8 = 5/72

I think the answer is

A: 1/18

Climate is the long-term weather pattern that can be seen in an area over a period of years.

Earth’s climate changing as the Earth's atmosphere heats up, it collects, retains, and drops more water, thereby changing weather patterns and making wet areas wetter and dry areas drier.

The factors that affect climate includ deforestation, desertification, urbanization, etc.

Scientists know that recent climate change is largely caused by human activities from an understanding of basic physics by comparing observations with models, and then fingerprinting the detailed patterns of climate change caused by different human and natural influences

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Answer:

2

Step-by-step explanation:

[tex]\frac{3[2(-2)-6] + (-2)^{2} +4[2(-2)+1]}{3[(-2)-5]+2}[/tex]

[tex]\frac{3(-10) - 4 + 4(-3)}{-16}[/tex]

[tex]\frac{-30-4-12}{-16}[/tex]

[tex]\frac{-46}{-16}[/tex]

okay you know what i dont know what im doing but i know the answer is for sure 2..

13) 120 + 1.5 + 0.25 = 121.75 pounds

14) 4 - 1.5 = 2.5 pints

15) (2.25)(32)= $72

13. Mrs. Smith's current weight is 121.75 pounds.

14. The students should consume an additional 2.5 pints of water.

15. The nurse's overtime earnings amount to $72.00.

Given are words problems based on mixed numbers:

13. To find Mrs. Smith's current weight, we need to add the weight gained over the last two months to her weight last month.

Weight gained in the first month: 1 1/2 pounds

Weight gained in the second month: 1/4 pounds

Total weight gained over the last two months: 1 1/2 + 1/4 = 1 3/4 pounds

Now, to find Mrs. Smith's current weight, we add the total weight gained to her weight last month:

Current weight = Weight last month + Total weight gained

Current weight = 120 pounds + 1 3/4 pounds

Hence, Mrs. Smith's current weight is 121.75 pounds.

14. To calculate the additional water the students should consume to meet the school nurse's recommendation of at least 4 pints daily, we need to find the difference between the recommended amount and the average amount the students currently drink.

The recommended amount is 4 pints, and the average amount the students currently drink is 1 1/2 pints, which can be written as 1.5 pints.

Additional water needed = Recommended amount - Current average amount

Additional water needed = 4 pints - 1.5 pints

Additional water needed = 2.5 pints

Therefore, the students should consume an additional 2.5 pints of water daily to meet the school nurse's recommendation.

15. To calculate the nurse's overtime earnings, you can use the formula:

Overtime Earnings = Overtime Hours × Overtime Pay Rate

First, let's convert the mixed number of overtime hours into an improper fraction:

2 1/4 hours = 2 + 1/4 = 9/4 hours

Now, we can calculate her overtime earnings:

Overtime Hours = 9/4 hours

Overtime Pay Rate = $32.00/hour

Overtime Earnings = (9/4) hours × $32.00/hour

To simplify the calculation, you can convert the fraction to a decimal:

Overtime Earnings = (9/4) hours × $32.00/hour

Overtime Earnings = 2.25 hours × $32.00/hour

Overtime Earnings = $72.00

So, the nurse's overtime earnings amount to $72.00.

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The possible zeros of f(x) = 3x^6 + 4x^3 -2x^2 + 4 are [tex]\mathbf{\pm\{1,2,4,\frac 13, \frac 23,\frac{4}{3}}\}[/tex]

The function is given as:

f(x) = 3x^6 + 4x^3 -2x^2 + 4

The leading coefficient of the function is:

p = 3

The constant term is

q = 4

Take the factors of the above terms

p = 1 and 3

q = 1, 2 and 4

The possible zeros are then calculated as:

[tex]\mathbf{Zeros = \pm\frac{Factors\ of\ q}{Factors\ of\ p}}[/tex]

So, we have:

[tex]\mathbf{Zeros = \pm\frac{1,2,4}{1,3}}[/tex]

Expand

[tex]\mathbf{Zeros = \pm\frac{1,2,4}{1},\pm\frac{1,2,4}{3}}[/tex]

Solve

[tex]\mathbf{Zeros = \pm\{1,2,4,\frac 13, \frac 23,\frac{4}{3}}\}[/tex]

Hence, the possible zeros of f(x) = 3x^6 + 4x^3 -2x^2 + 4 are [tex]\mathbf{\pm\{1,2,4,\frac 13, \frac 23,\frac{4}{3}}\}[/tex]

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Using the probability concept, the odds that the ticket is worth at least $25 are of 1:3.67.

A probability is given by the number of desired outcomes divided by the number of total outcomes.

Considering the probability, the odd is given by:

o = probability:(1 - probability)

From the given table, the probability that the ticket is worth at least $25 is:

p = 0.2 + 0.01 + 0.004 = 0.214.

Hence the odd is:

o = 0.214/(1 - 0.214) = 0.214/0.786 = 1:3.67.

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Given the length of both trail, Trail B is 7/4 miles longer than Trail B.

Given that;

To determine how many miles longer is Trail B more than Trail A, we subtract the length of tail A from Tail B.

Trail B - Trail A

17/2 - 27/4

17/2 is the same as; 34/4

34/4 - 27/4

We combine the numerators over common denominator

(34 - 27 )/4

7/4 miles

Given the length of both trail, Trail B is 7/4 miles longer than Trail B.

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The value of x in the trapezoid given, to the nearest tenth, is: 10.5.

A trapezoid is a quadrilateral that has two sides only that are parallel to each other.

To find the area of a trapezoid, the formula used is expressed as: 1/2(a + b) × h, where:

Given the following:

Area of trapezoid = 174 units²

AP = 6

PB = x + 3

CD = 2x + 6

AC = 10

Using the formula, we variables in the formula are:

a = AP + PB = 6 + x + 3 = x + 9

b = CD = 2x + 3

h = PC = √(AC² - AP²)

h = √(10² - 6²) = 8

Plug in the values into 1/2(a + b) × h:

174 = 1/2(x + 9 + 2x + 3) × 8

174 = 1/2(3x + 12) × 8

174 = (3x + 12) × 4

174 = 12x + 48

174 - 48 = 12x

126 = 12x

126/12 = x

10.5 = x

x = 10.5

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1. The amount of the adjusting entry for Uncollectible Accounts is $1,250.

2. The adjusted balances of Accounts Receivable Allowance for Doubtful Accounts Bad Debt Expense are:

Accounts Receivable = $3,545,000

Allowance for Doubtful = $7,250

Accounts Bad Debt Expense = $1,250

3. The net realizable value of the accounts receivable is $3,537.750 ($3,545,000 - $7,250).

                               Accounts Receivable    Allowance for Doubtful Accounts

Beginning balance     $645,000 DR               $6,000 CR

Sales                          2,900,000

Bad Debt Estimate = $7,250 ($2,900,000 x 0.0025)

Ending balance      $3,545,000                     $7,250 CR

Bad Debts Expense = $1,250 ($7,250 - $6,000)

Thus, the net realizable value of the accounts receivable shows the amount that the company expects to recover from customers after allowing for doubtful accounts.

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1. Determine the amount of the adjusting entry for uncollectible accounts.

2. Determine the adjusted balances of Accounts Receivable, Allowance for Doubtful Accounts, and Bad Debt Expenses.

3. Determine the net realizable value of accounts receivable

Using the Poisson distribution, we have that:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]

The parameters are:

For this problem, the mean is given as follows:

[tex]\mu = 13[/tex]

The probability of having exactly 10 days of precipitation in the month of April is P(X = 10), hence:

[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]

[tex]P(X = 10) = \frac{e^{-13}13^{10}}{(10)!} = 0.0859[/tex]

There is a 0.0859 = 8.59% probability of having exactly 10 days of precipitation in the month of April.

The probability of having less than three days of precipitation in the month of April is:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

In which:

[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]

[tex]P(X = 0) = \frac{e^{-13}13^{0}}{(0)!} \ approx 0[/tex]

[tex]P(X = 1) = \frac{e^{-13}13^{1}}{(1)!} = 0.00003[/tex]

[tex]P(X = 2) = \frac{e^{-13}13^{2}}{(2)!} = 0.00019[/tex]

Then:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0 + 0.00003 + 0.00019 = 0.00022

There is a 0.00022 = 0.022% probability of having less than three days of precipitation in the month of April.

For more than 15 days, the probability is:

P(X > 15) = P(X = 16) + P(X = 17) + ... + P(X = 20)

Applying the formula for each of these values and adding them, we have that P(X > 15) = 0.2364, hence:

There is a 0.2364 = 23.64% probability of having more than 15 days of precipitation in the month of April.

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Probability someone chosen at random will not have brown hair = 1/6

The number of girls = 15

The number of boys = 15

The total number of children = 15 + 15 = 30

Probability that someone chosen at random will have a brown hair, P(Brown hair) = 5/6

P(Brown hair) + P(Not Brown hair) = 1

5/6  +  P(Not brown hair) = 1

P(not brown hair) = 1 - 5/6

P(not brown hair) = 1/6

Therefore, if someone is chosen at random, probability that they will not have brown hair = 1/6

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LHS = (1-sin² cos²)/(cos²)

= (sin² + cos² - sin² cos²)/(cos²)

= (sin/cos)² + 1 - sin²

= tan² + cos²

= RHS

Answer:

0.7

Step-by-step explanation:

Because 0.4 is $5 and 0.3 is $25. So 0.3+0.4=0.7

The centre and the radius of the circle is (-7, -1) and 6 units

The equation of the circle in standard from is expressed as:

x^2+y^2+2gx+2fy+C = 0

where;

(-g, -f) is the centre

r= √g²+f²-C

Given the equation below

x^2+y^2+14x+2y+14 = 0

2g = 14

g = 7

2f = 2

f =1

Hence the centre of the circle is (-7, -1)

Radius = √49+1-14

Radius = √36 = 6 units

Hence the centre and the radius of the circle is (-7, -1) and 6 units

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The equation of the parabola is [tex]y=\frac{1}{24} x^2+3[/tex]

None of the given options is correct

Given:

Focus: (0, 3)

Directrix: y = -3

Note that:

f - k = k - (-3)

f - 3 = 3 + 3

f = 6 + 3

f = 9

The equation of the parabola is of the form:

[tex]y=\frac{1}{4(f-k)} (x-h)^2+k[/tex]

Substitute f = 9, k = 3, h = 0 into the equation

[tex]y=\frac{1}{24} (x-0)^2+3\\\\y=\frac{1}{24}x^2+3[/tex]

The equation of the parabola is [tex]y=\frac{1}{24} x^2+3[/tex]

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$1045 was invested at the interest rate 6% whereas $1,995 was invested at 14%

How is interest computed?

Interest is determined as the amount invested multiplied by the interest rate.

Let Y be the amount invested at 6%

Interest=Y*6%

Interest=0.06Y

The amount invested at 14%, which is $950 more , is Y+950

Interest=(Y+950)*14%

Interest=0.14Y+133

Total interest =0.06Y+0.14Y+133

Note that total interest is 342

342=0.06Y+0.14Y+133

342=0.20Y+133

342-133=0.20Y

209=0.20Y

Y=209/0.20

Y=$1,045(amount invested at 6%)

Amount invested at 14%=$1,045+$950

Amount invested at 14%=$1,995

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Answer:

Step-by-step explanation:

no idea tbh

x is 40 degrees

y is 40 degrees

Hope this helps!

The sequence pattern for 3¹/₃, 3¹/₄, 3¹/₅, ...... is; f(n) = 3 + 1/(2 + n)

We are given the sequence;

3¹/₃, 3¹/₄, 3¹/₅, ......

Now, we can see that;

First term is 3¹/₃.

However, for the second term, 1 has been added to the denominator.

Thus, we can suggest that the sequence pattern here is;

f(n) = 3 + 1/(2 + n)

where n is the nth term.

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The height of the leafy part will be 6m.

Other part of the question:

At the same time, a vertical pole 3m high vast s shadow 4m long.

Based on the information given, the height will be:

h/8 = 3/4

h = (3 × 8)/4

h = 6

Therefore, the height is 6m.

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Answer:

[tex]r=\sqrt{\frac{V}{\pi h}}[/tex]

Step-by-step explanation:

[tex]V = \pi r^{2} h \\ \\ r^{2} =\frac{V}{\pi h} \\ \\ r=\sqrt{\frac{V}{\pi h}}[/tex]

Answer:

(x - 5) ^2 + (y -2)^2 = 1

Step-by-step explanation:

This is for a circle.

We need to complete the square

(x^2 -10x      ) + ( y^2 -4y       )  = -28

(x^2 - 10x +25) + (y^2 - 4y 2y) = -28 + 25 + 4

(x-5)^2 + (y-2)^2 = 1

The center of this circle would be (5,2)  with a radius of 1.

Answer:

you have to put the formula of perimeter

Answer:

12a. L+8m + 14m

12b. 10m+8m +14m

12c. 66

12d.420m

12e.252m

quick questions

volume= 288cm cubed

I assume [tex]f(x)=0[/tex] otherwise. If [tex]f(x)[/tex] is indeed a proper PDF, then its integral over the support of [tex]X[/tex] is 1.

[tex]\displaystyle \int_{-\infty}^\infty f(x) \, dx = k \int_0^2 (2x + 3x^2) \, dx = 1[/tex]

Compute the integral.

[tex]\displaystyle \int_0^2 (2x + 3x^2) \, dx = (x^2 + x^3)\bigg|_{x=0}^{x=2} = (2^2 + 2^3) - (0^2 + 0^3) = 12[/tex]

Then

[tex]12k = 1 \implies \boxed{k=\dfrac1{12}}[/tex]