Rectilinear motion of light is shown in picture. The wavelengths of light that are visible to humans fall into a relatively small range within that wide spectrum.
What is light?Electromagnetic radiation that the human eye can detect as light. From radio waves with wavelengths measured in meters to gamma rays with wavelengths shorter than roughly 1 1011 meter, electromagnetic radiation occurs throughout a very broad range of wavelengths.
The wavelengths of light that are visible to humans fall into a relatively small range within that wide spectrum, ranging from about 700 nanometers (nm; billionths of a meter) for red light to roughly 400 nm for violet light. Infrared and ultraviolet are two spectral bands that are close to the visible region and are repeatedly alluded to as light as well. Rectilinear motion of light is shown in picture.
Therefore, rectilinear motion of light is shown in picture.
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Need help please !!!! Hurry
Answer:
4
Explanation:
Waves that are squished have higher frequency. It has short wavelength.
Answer:
4
Explanation:
frequency and wavelength are inverses, so since this has the smallest wavelength it has the highest frequency. The smaller the wavelength, the more waves (more/high frequency) fit in a certain area in comparison to larger wavelengths fit fewer waves (less frequent).
Describa con sus palabras que fue lo que descubrio galileo en su legendario experimento en la torre inclinada de pisa
Answer:
En 1589 Galileo realizó un experimento lanzando dos bolas de diferentes masas desde la famosa Torre Inclinada de Pisa para demostrar que el tiempo de caída es independiente de la masa de la bola. A través de este experimento, Galileo descubrió que los cuerpos caían casi simultáneamente, refutando la teoría de Aristóteles de que la tasa de caída era proporcional a la masa del cuerpo.
Debido a la imperfección de los equipo de medición de esa época, la caída libre de los cuerpos era casi imposible de estudiar. En busca de una forma de reducir la velocidad de movimiento, Galileo reemplazó la caída libre por rodar sobre una superficie inclinada, donde había velocidades y resistencia del aire significativamente más bajas. Se notó que con el tiempo, la velocidad del movimiento aumenta: los cuerpos se mueven con aceleración. Se concluyó que la velocidad y la aceleración no dependen ni de la masa ni del material de la pelota.
Complete play the table by writing the location orientation size and type of image formed by the lenses below.
Please help me guyss!! :(
Answ
Explanation:
HOPE IT HELPS..
The image formed by the location of object is beyond 2F the image by convex lenses is between F and 2F and is inverted, smaller and and real image. If it is at 2F, the image is inverted with the same size and real.
What is a convex lens ?A convex lens is a type of lens that is projected outwards and shows the real image of an object. Whereas a concave lens is curved inwards and shows virtual image of objects.
The image formed at by the location of convex lenses beyond 2F is inverted, smaller and and real image. If it is at 2F, the image is inverted with the same size and real. If the lens is placed between F and 2F the image formed is beyond 2F and it will be inverted, enlarged and real.
If the object is at F , no image will be formed. If it at between F and the lens, then the image forms beyond 2 F which is upright, enlarged and virtual.
The object be at any position with respect to the focal length of lens, the image formed by a concave lens is between F and the lens and upright, small and virtual.
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An object with a potential energy of 981 J is placed at a height of 2m. What is the mass of the object?
Answer:
the mass of object is 2000
Typical Pressurized Water Reactors can produce 1100 to 1500
megawatts, or about _______
Joules/second.
Answer: about 1,100,000,000 to 1,500,000,000 Joules/second
Explanation:
1 MW (megawatt) = 1,000,000.00 J/s (joules per second)
1100(1,000,000) = 1,100,000,000
1500(1,000,000) = 1,500,000,000
How much force must be applied to a 4 kg to get it to accelerate at 3
m/s^2?
Answer:
12 g i think
Explanation:
brainliest pls
anyone know the answer ?
Yes. Many people either know the answer, or can figure it out using the information in the picture.
What is the best example of a compound machine A ax. B ramp. C car D screw
Answer: I believe the answer is C
Explanation:
Cars are composed of hundreds of simple machines
A 0.15 kg baseball flies rightward at 15m/s to hit a tennis ball flying at it from the opposite direction at 22m/s.
The baseball and the tennis ball have final speeds of
1.2m/s and 13m/s, respectively, both to the right.
What is the mass of the tennis ball?
Answer:0.060
Explanation:
The mass of the tennis ball is equal to 0.23 Kg.
What is law of conservation of linear momentum?According to the law of conservation of linear momentum, the sum of the momentum of the bodies which are collided with each other must be equal before and after the collision.
m₁ .u₁ + m₂.u₂ = m₁ .v₁ + m₂.v₂
where m₁ and m₂ is the masses, u₁ and u₂ are initial speed while v₁ & v₂ is their final speed of the collieded objects.
Linear momentum can be defined as the product of the mass times the velocity of that object.
Given, the initial velocity of the baseball is u₁ = 15 m/s
The initial velocity of the tennis ball u₂ = 22 m/s.
The mass of baseball, m₁ =0.15 Kg
From the law of conservation of momentum, find the mass of the tennis ball:
m₁ u₁ + m₂ u₂ = m₁.v₁ + m₂.v₂
0.15 × 15 + m ×22 = 0.15 × 1.2 + m × 13
2.25 + 22 m = 0.18 + 13 m
9 m = 2.25
m = 0.23 Kg
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A solid wooden cube, 30cm on each side can be totally submerged in water if it is pushed downward with a force of 54N. What is the density of the wood?
Answer:
the density of the wooden cube is 204.1 kg/m³
Explanation:
Given;
applied force, F = 54 N
length of each side of the solid wooden cube, L = 30 cm = 0.3 m
mass of the wooden cube is calculated as;
F = mg
m = F/g
m = 54/9.8
m = 5.51 kg
The volume of the wooden cube is calculated as;
V = L³
V = (0.3)³
V = 0.027 m³
The density of the wooden cube is calculated as;
ρ = m/V
ρ = (5.51 kg) / (0.027 m³)
ρ = 204.1 kg/m³
Therefore, the density of the wooden cube is 204.1 kg/m³
A force of 500N Is applied to a steel wire of goss_sectional area 0.2m2 the tensele stress is a. 2.5x10 1nm-2 b. 1 0x102nm-2 c. 2.5x103nw-3 d. 1.0x103nm-2
Answer:
the tensile stress of the steel wire is 2.5 x 10³ Nm⁻².
Explanation:
Given;
applied force, F = 5000 N
cross sectional area of the steel wire, A = 0.2 m²
The tensile stress of the steel wire, is calculated as;
[tex]\sigma = \frac{F}{A} \\\\\sigma = \frac{500}{0.2} \\\\\sigma = 2500 \ N/m^2\\\\\sigma = 2.5 \ \times \ 10^3 \ Nm^{-2}[/tex]
Therefore, the tensile stress of the steel wire is 2.5 x 10³ Nm⁻².
3V battery is used with a 15 ohm resistance.What is the current?
Answer:
0.2 A
Explanation:
V= IR
3 = I × 15
I = 3/15
= 1/5 = 0.2 A
The flow of current in a battery will be "0.2 A". To understand the calculation, check below.
Current, Resistance and VoltageAccording to the question,
Voltage, V = 3 V
Resistance, R = 15 ohm
We know the relation,
→ Voltage (V) = Current (I) × Resistance (R)
or,
→ Current, I = [tex]\frac{V}{R}[/tex]
By substituting the values,
= [tex]\frac{3}{15}[/tex]
= 0.2 A
Thus the above answer is correct.
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Two free charges +q and +4q are a distance l apart. A third charge is placed so that the entire system is in equilibrium. Find the location, magnitude and sign of the third charge.
Answer:
the value of the charge is q₃ = [tex]- \frac{4}{9} q[/tex]- 4/9 q, in the position x= l/3
Explanation:
The forces in this system are given by Coulomb's law
F = [tex]k \frac{q_1 q_2}{ r^2}[/tex]
As the forces are vector, we must add them as a vector, also let us take that charges of the same sign repel and charges of the opposite sign attract, therefore for the system to be in equilibrium the third charge must be of the opposite sign, that is, NEGATIVE .
Let's analyze the situation for card charge, let's use the indexes 1 for the charge q₁ = + q located at the origin (x₁ = 0), index 2 for the face q₂ = + 4q located at x₂ = l and the index 3 for the third charge
Let's find the location of charge 3 so that it is in balance
∑ F = F₁₃ - F₂₃ = 0
F₁₃ = F₂₃
we seek every force
F₁₃ = k [tex]\frac{q_1q_3 }{x_{13}^2}[/tex]
F₂₃ = k [tex]\frac{q_2q_3}{ x_{23}^2}[/tex]
the distances are
x₁₃ = x-0 = x
x₂₃ = l -x
we substitute
k \frac{q_1q_3 }{x^2} = k \frac{q_2q_3 }{(l-x)^2}
we solve
(l-x)² = [tex]\frac{q_2}{q_1}[/tex] x²
l² - 2lx + x² = \frac{4q}{q} x²
3x² + 2l x - l² = 0
we solve the quadratic equation
x = [-2l ± [tex]\sqrt{4l^2 + 4\ 3\ l^2}[/tex] / (2 3)
x = [-2l + 2l [tex]\sqrt{1+3}[/tex]] / 6 = 2l [-1 ± 2] / 6
x₁ = -l
x₂ = l / 3
as charge 3 must be between the two charges the correct answer is
x = l / 3
with charge 3 in this location it remains in equilibrium regardless of the value of its NEGATIVE charge.
now let's analyze the force on the other charges
charge 1 so that it is in balance
∑F = F₁₃ - F₁₂ = 0
F₁₃ = F₁₂
[tex]k \frac{q_1q_3}{(l/3)^2} = k \frac{q_1 q_2}{ l^2}[/tex]
l² q₃ = q₂ (l/3)²
q₃ = q₂ / 9
q₃ = 4q / 9
q₃ = [tex]\frac{4}{9} q[/tex]
in summary the value of the charge is q₃ = [tex]- \frac{4}{9} q[/tex]- 4/9 q
in the position x= l/3
OK so big sich. here so #relationships #BFGF
W. T. F does roly polying someone mean
Someone told me it means in a relationship that its when someone is dating someone but they find someone they also like but not fully dating them so its not 100% cheating so W T F DOES IT MEAN
Answer:
I have know idea what that means lol.
Thanks for the free points. Hope you have a fantastic rest of your life!
How do you prove you know which object has more momentum without calculating it?
Answer:
The momentum of an object varies directly with the speed of the object.
Explanation:
Two objects of different mass are moving at the same speed; the more massive object will have the greatest momentum. A less massive object can never have more momentum than a more massive object.
neon has 10 electrons, 2 in the inner level and 8 in it's outermost level. how many valence electrons do neon atoms have?
Answer:
It's very simple- 8 valence electrons
Answer:
it's 8
Explanation:
that the answer for the question
The momentum of a 3000 kg truck is 6.36 x 104 kg·m/s. At what speed is the truck traveling? m/s
472
19,080
2.1
21.2
19.6
24.5
Answer:
21.2m/s
Explanation
Given data
P=6.36 x 10⁴kg·m/s.
M=3000kg
From the momentum expression
P=mv
v=p/m
Substitute
v=63600/3000
v=21.2m/s
Hence the Velocity is 21.2m/s
The speed of the truck is 21.2 m /s
Momentum is the product of the mass of the object and the velocity of the object. Therefore,
p = mv
where
m = mass
v = velocity
m = 3000 kg
p = 6.36 x 104 kg·m/s.
lets find the velocity
6.36 x 10⁴ = 3000 × v
v = 6.36 x 10⁴ / 3000
v = 21.2 m / s
The speed of the truck is 21.2 m /s
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what is related to wave speed
A.How loud a wave is
B.Crest and Amplitudes
C.Frequency
D.Troughs and amplitudes
Answer:
c
Explanation:
A house of mass 500 kg is lifted 25 m by balloons.
Calculate the increase in gravitational potential energy, Ep.
(g = 10 N/kg)
Enter your answer as a number - NO units
Which of the following terms corresponds to #2 on the image?
Answer:
Trough
Explanation:
cuz physics you see
What are some of the objects found in space and their characteristics?
Answer:
meteor
Explanation:
big rock or metal maybe
Two spherical shells have a common center. A -1.50 × 10-6 C charge is spread uniformly over the inner shell, which has a radius of 0.050 m. A +4.50 × 10-6 C charge is spread uniformly over the outer shell, which has a radius of 0.15 m.Find the magnitude and direction of the electric field at a distance (measured from the common center) of______________.
a: 0.20m
b: 0.10m
c: 0.025m
Answer:
a) At 0.20 m, the magnitude of the field is 675.0 kV
The direction of the field is acting outwards from the center of the charged spheres
b) At 0.10 m, the magnitude of the field is 135 kV
The direction is acting outwards from the center of the charged spheres
c) At 0.025 m
The magnitude of the field, V = -270.0 kV
The direction of the field is inwards, towards the center of the charged spheres
Explanation:
The charged spherical shell parameters are;
The charge on the inner sphere, q₁ = -1.50 × 10⁻⁶ C
The radius of the inner shell, R₁ = 0.050 m
The charge on the outer sphere, q₂ = +4.50 × 10⁻⁶ C
The radius of the outer shell, R₂ = 0.15 m
Let 'r', represent the distance at which the electric field is measured, the following relationships can be obtained;
When r < R₁ < R₂,
[tex]V = k \cdot \left( \dfrac{q_1}{R_1} + \dfrac{q_2}{R_2} \right )[/tex]
When R₁ < r < R₂,
[tex]V = k \cdot \left( \dfrac{q_1}{r} + \dfrac{q_2}{R_2} \right )[/tex]
When R₁ < R₂ < r,
[tex]V = k \cdot \left( \dfrac{q_1 + q_2}{r^2} \right )[/tex]
a) When r = 0.20 m, we have;
R₁ < R₂ < r, therefore
[tex]V = k \cdot \left( \dfrac{q_1 + q_2}{r^2} \right )[/tex]
By plugging in the values, we get;
[tex]V = 9 \times 10^9 \times \left( \dfrac{-1.50 \times 10^{-6} + 4.50\times 10^{-6} }{0.20^2} \right ) = 675.0 \ kV[/tex]
Therefore, the magnitude of the field, V = 675.0 kV
The direction of the field is outwards
b) When r = 0.10 m, we have;
When R₁ < r < R₂, therefore;
[tex]V = k \cdot \left( \dfrac{q_1}{r} + \dfrac{q_2}{R_2} \right )[/tex]
By plugging in the values, we get;
[tex]V = 9 \times 10^9 \times \left( \dfrac{-1.50 \times 10^{-6} }{0.10} + \dfrac{4.50\times 10^{-6}}{0.15} \right ) = 135 \ kV[/tex]
Therefore, the magnitude of the field, V = 135 kV
The direction of the field is outwards from the center
c) When r = 0.025 m, we have;
When r < R₁ < R₂, therefore;
[tex]V = k \cdot \left( \dfrac{q_1}{R_1} + \dfrac{q_2}{R_2} \right )[/tex]
By plugging in the values, we get;
[tex]V = 9 \times 10^9 \times \left( \dfrac{-1.50 \times 10^{-6} }{0.05} + \dfrac{4.50\times 10^{-6}}{0.15} \right ) = -270 \ kV[/tex]
Therefore, the magnitude of the field, V = -270.0 kV
The direction of the field is inwards, towards the center of the charged spheres.
does anyone have the same thing for the brainly app
mine said "this operation couldn't complete" an does anyone know how to fix it
i am on iphone
Answer:
PICK ONE
Explanation:
A gas has an initial volume of 24.6 L at a pressure of 1.90 atm and a temperature of 335 K. The pressure of the gas increases to 3.50 atm, and the volume of the gas increases to 31.3 L. What is the final temperature of the gas? 143 K 231 K 485 K 785 K
Answer:
the final temperature of the gas is 785.18 K
Explanation:
The computation of the final temperature of the gas is shown below:
Here we apply the gas law
= PV ÷ T
Given that
P1 = 1.9 atm
V1 = 24.6 L
T1 = 335 K
P2 = 3.5 atm
V2 = 31.3 L
T2 = ?
Now
P1V1 ÷ T1 = P2V2 ÷ T2
(1.9 × 24.6) ÷ 335 = (3.5 × 31.3)/T2
T2 = 785.18 K
hence, the final temperature of the gas is 785.18 K
Answer: D
Explanation: edge
The reaction between magnesium (Mg) and oxygen (O2) forms magnesium oxide (MgO).
a. Write a balanced chemical equation to represent this reaction.
b. Identify the type of reaction this represents.
Answer:
2 Mg + O2 = 2MgO
Type: Synthesis
How are magnets used in modern technology?
A body of mass 1kg is attracted by the earth with a force which is equal to
Answer:
9.8N
Explanation:
Given the following data;
Mass = 1kg
We know that acceleration due to gravity is equal to 9.8m/s²
To find the force:
Force = mass * acceleration
Substituting into the equation, we have:
Force = 1 * 9.8
Force = 9.8N
Epidemiologists sometimes us computers and artificial intelligence (AI) to help them analyze data. Why would this be helpful?
pls qmp
What is the purpose of the lab, the importance of the topic, and the question you are trying to answer?
Energy
Answer: I put the importance of the lab in the topic is to find how dense an object is and if it can sink or float and it's important to answer the question so you can also find mass and volume.
Explanation: I dunno haha...
if an object can make 10 revolutions in a minute, what's is period
Answer:
Period = 6 seconds.
Explanation:
Given the following data;
Number of oscillation, n = 10
Time = 1 minute to seconds = 60 seconds
To find the period;
A period is the number of revolutions in a minute.
[tex] Period = \frac {time}{number \; of \; oscillations}[/tex]
Substituting into the equation, we have;
[tex] Period = \frac {60}{10}[/tex]
Period = 6 seconds.