what volume (in l) will 50.0 g of nitrogen gas occupy at 2.0 atm of pressure and at 65 oc?

Answers

Answer 1

To solve this problem, we need to use the ideal gas law:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

First, we need to convert the given temperature of 65°C to Kelvin:

T = 65°C + 273.15 = 338.15 K

Next, we need to calculate the number of moles of nitrogen gas:

n = m/M

where m is the mass of the gas (in grams) and M is the molar mass (in grams/mol).

Molar mass of N2 = 28.02 g/mol

n = 50.0 g / 28.02 g/mol = 1.783 mol

Now we can rearrange the ideal gas law to solve for volume:

V = nRT/P

V = (1.783 mol)(0.08206 L·atm/mol·K)(338.15 K) / (2.0 atm)

V = 65.5 L

Therefore, 50.0 g of nitrogen gas will occupy a volume of 65.5 L at 2.0 atm and 65°C.

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Related Questions

an ambulance with a siren emitting a whine at 1600Hz overtakes and passes a cyclist pedaling a bike at 2.44 m/s. After being passed the cyclist hears a frequency of 1590 Hz. How fast was ambulance moving

Answers

The speed of the ambulance is 4.61 m/s.

Calculation:

Doppler's effect formula is used, which is

[tex]f' = f (\frac{v + vo}{v + vs})[/tex]

Where,

f' = observer frequency of sound

f = actual frequency of sound waves

v = speed of sound waves

vo = velocity of observer

vs = velocity of source

Here, observer is the cyclist and source is the ambulance.

Given,

f' = 1590 Hz

f = 1600 Hz

v = 343 m/s

vo = 2.44 m/s

Now put the given values in the above formula,

[tex]f' = f (\frac{v + vo}{v + vs})[/tex]

[tex]1590 = 1600 (\frac{343 + 2.44}{343 + vs})[/tex]

[tex]1590 = 1600( \frac{345.44}{343 + vs})[/tex]

[tex]1590 = \frac{552,704}{343+vs}[/tex]

[tex]343+vs = \frac{552,704}{1590\\}[/tex]

[tex]343 + vs = 347.61\\[/tex]

[tex]vs = 347.61 - 343[/tex]

[tex]vs = 4.61 m/s[/tex]

Hence, the speed of the ambulance is 4.61 m/s.

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Two students measure the time constant of an RC circuit. The first student charges the capacitor using a 12 V battery, then lets the capacitor discharge the resistor. The second student repeats the experiment using a 5 V battery. Which student measures the longer time constant

Answers

Answer: Two students measure the time constant of an RC circuit. The first student charges the capacitor using a 12 V battery, then lets the capacitor discharge the resistor. The second student repeats the experiment using a 5 V battery. The student who charged the capacitor using 5V will measures the longer time constant.

Explanation: To find the correct answer, we need to know about the time constant of RC circuit.

What is the time constant of the RC circuit?The time constant of a RC circuit can be defined as, the time taken by the charge in the capacitor to grow or decay.It can be expressed as,

                             [tex]T=CR[/tex]

How to solve the problem?We have T=CR, and we know that,

                             [tex]C=Q/V[/tex]

Thus, the lesser voltage will have more C.when C increases, CR will increase.

Thus, we can conclude that, the lesser voltage source will take longer time constant.

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According to the Hubble classification scheme, an E4 galaxy has a(n) Group of answer choices irregular shape. round or spherical shape with a smooth light distribution and no disk or central bulge. disk and central bulge with a smooth light distribution and no spiral arms. moderately elliptical shape (a flattened circle) with a smooth light distribution.

Answers

According to the Hubble classification scheme, an E4 galaxy has-moderately elliptical shape (a flattened circle) with a smooth light distribution.

What does Hubble classification descrbes?Galaxies were first categorized by Edwin Hubble into four categories: spirals, barred spirals, ellipticals, and irregulars. According to the size of the central bulge and the makeup of the arms, he further divided spiral and barred spiral galaxies.A corresponds to a huge central bulge and wide central arms, while c is a modest central bulge with well-defined spiral arms. It is a common practice to categorize galaxies using the Hubble classification, sometimes known as the tuning fork diagram.A book titled "The Realm of the Nebulae" that was published in 1936 contained Hubble's original taxonomy of galaxy types. His initial plan has since undergone a number of adjustments and additions, but the fundamental concept of his "tuning fork diagram" has remained helpful for astronomers. Elliptical galaxy, which is roughly egg-shaped and lacks many features. The only thing that is typically visible is a drop in surface brightness as one moves away from the galaxy's core. The apparent shapes have long axes that are four times longer than their short axes, and range from very circular (E0) to fairly elliptical (E6).Disc galaxies feature a central bulge that resembles an elliptical galaxy very much, but they also have a thin disc of stars surrounding it. The disc typically resembles a circle quite a bit.

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An electric heater,rated 15 volts 40 watts fitted into a metal block supplies heat to the block of mass 1.5kg and specific heat capacity of 460. calculate the temperature rise of in the block if the current flows for 10 minutes

Answers

The temperature rises of in the block if the current flows for 10 minutes is, 34.78K.

To find the answer, we need to know about the power of the electric heater.

How to find the temperature rise of in the block if the current flows for 10 minutes?We have given with the variables,

                           [tex]P=40 W\\m=1.5kg\\S=460\\t=10minutes=10*60s=600s[/tex]

We have an expression the heat given to the system as,

                             [tex]P*t= mS[/tex]ΔT

We have to find the temperature rise ΔT,

                           ΔT [tex]=\frac{P*t}{mS} =\frac{40*600}{1.5*460} =34.78K[/tex]

Thus, we can conclude that, the temperature rises in the block if the current flows for 10 minute is 34.78K.

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If the current flows for 10 minutes, the temperature in the block rises by 34.78 K.

We must understand the electric heater's power in order to determine the solution.

How can you determine the block's temperature increase if the current flows for ten minutes?With the variables that we have provided,

              [tex]P=40Watts\\m=1.5kg\\s=460\\t=10 min=600s[/tex]

The heat supplied to the system is referred to as,

                    [tex]Pt=ms[/tex]ΔT

We must determine the increase in temperature, T.

             ΔT[tex]=\frac{Pt}{ms} =34.78 K[/tex]

Thus, we can infer that if the current flows for 10 minutes at 34.78K, the temperature in the block will increase.

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After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 55.0 cmcm. She finds that the pendulum makes 110 complete swings in a time of 145 ss.

Answers

Hi there!

First, let's find the period of the pendulum. This can be found by solving for the amount of time it takes for the pendulum to make ONE complete swing.

[tex]T = \frac{\text{Total time}}{\text{Number of complete swings} }\\\\T = \frac{145}{110} = 1.318 s[/tex]

Now, let's use the equation for the period of a simple pendulum:
[tex]T = 2\pi \sqrt{\frac{L}{g}}[/tex]

T = Period (1.318 s)
L = length of string (0.55 m)

g = acceleration due to gravity on planet (? m/s²)

Let's solve for 'g' doing some quick rearranging of the equation:
[tex]T^2 = 4 \pi^2 (\frac{L}{g})\\\\g = \frac{4\pi^2 L}{T^2}\\\\[/tex]

Solving for 'g' by plugging in values:
[tex]g = \frac{4\pi^2 (0.55)}{(1.318)^2}\\ \\= \boxed{12.496 \frac{m}{s^2}}[/tex]

An interstellar spacecraft, far from the influence of any stars or planets, is moving at high speed under the influence of fusion rockets when the engines malfunction and stop. The spacecraft will

Answers

An interstellar spacecraft, far from the influence of any stars or planets, is moving at high speed under the influence of fusion rockets when the engines malfunction and stop. The spacecraft will keep moving forever at the same speed.

What is Interstellar spacecraft:

Interstellar travel refers to the idea of interstellar probes or crewed spacecraft moving between stars or planetary systems in a galaxy.

here, An interstellar spacecraft, far from the influence of any stars or planets, is moving at high speed.

According to Newton’s first law:

Newton’s first law states that, without any external force, if a body is at rest, it will remain at rest and if the body is moving with constant velocity, it will continue to do so.

Since here there is no external force present,

Therefore the spacecraft will keep moving forever at the same speed.

Thus,

from the above observation we conclude that,

option (D) is correct

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A vector is 14.4 m long and
points in a 133 degree
direction.
Find the x-component of the
vector.

Answers

The x-component of the given vector is determined as 10.53 m.

X component of the vector

The x-component of a vector is defined as the value of the vector or component of the vector in the x direction.

For a vector of 14.4 m long and pointing in a 133 degree direction.

The x-component of the vector is calculated as follows;

Vx = V cosθ

where;

θ is the angle of inclination measured from positive x axis

θ = 133⁰ - 90⁰ = 43⁰

Vx = 14.4 x cos(43)

Vx = 10.53 m

Thus, the x-component of the given vector is determined as 10.53 m.

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When driving in fog, A. low beam headlights. B. Use high beam headlights for better visibility. C. Use your hour at 10 second intervals. D. Turn on the heat in your vehicle.(1 Point)

Answers

The correct alternative is (a) use low beam headlights when driving in fog.

Use of low beam headlights is better than high beam headlights when driving in fog because high beams are aimed higher to maximize the seeing distance and their bright light doesn't provide the clear visibility through the fog. The high beam light bounces back and just reflect back into the eyes of driver resulting in a sharp glare making it difficult for the driver to see through the fog. Low beams are only directed sideward or downward which ensure that the light doesn't reflect back into the eyes while driving through fog. The low beam lights doesn't obscure the vision and prevent collisions by providing clear visibility through the fog.

Hence, it is a good idea to use only low beam headlights while driving through the fog to ensure the correct visibility.

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The amount of excess load that can be imposed on the wing of an airplane depends upon the:.

Answers

The amount of excess load that can be imposed on the wing of an airplane depends upon the speed of the airplane.

What is meant by wing loading?

Wing loading in aerodynamics is the ratio of the loaded weight of the aircraft and the area of each wing. It is given as:

W_L = W (weight of the aircraft) / S (gross wing area of the airplane)

The more speed an aircraft gains, the more lift is produced by each unit of wing area.

Thus, with a high value of wing loading the aircraft lands and takes-off at higher speeds with low maneuvering control. Generally, Airliners have high wing loading while smaller airplanes have lower wing loading.

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(a) A certain parallel-plate capacitor has plates of area 4.00m2 , separated by 0.0100 mm of nylon, and stores 0.170 C of charge. What is the applied voltage

Answers

The applied voltage is 1.41* 10⁴ kV.

Calculation of applied voltage-

The capacitance of parallel plates in the absence of a dielectric is:

C = ∈₀A/d

where, "d" = the spacing between the plates = 0.01 * 10⁻³ m

"A" = the area of the plates = 4 m²

"∈₀" = the constant = 8.85419*10⁻¹² C²/Nm²

So, C₀ = [tex]\frac{8.85419*10^{-12}*4 }{0.0100*10^{-3} }[/tex]

          = 3541.67 *10⁻⁹ F

The dielectric constant, κ= 3.4, is defined as:

κ = C/C₀

The effective capacitance (with the dielectric) is denoted by "C", whereas the original capacitance is denoted by "C₀". (without the dielectric).

As a result, the new capacitance is:

C = κC₀

However, capacitance is connected to a voltage by:

C = Q/V

utilizing the increased capacitance and accounting for "V":

κC₀ = Q/V

V = Q/κC₀ = [tex]\frac{0.170}{3.4 * 3541.67 *10^{-9} }[/tex] = 1.41* 10⁴ kV

Therefore the applied voltage is 1.41* 10⁴ kV.

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Which one of the following aqueous solutions would you expect to have the smallest conductance: _______
(a) 0. 060 m nacl,
(b) 0. 030 m nacl, or
(c) 0. 015 m nacl? explain your reasoning

Answers

(c) 0. 015 m NaCl of the following aqueous solutions would be expected to have the smallest conductance.

Conductance is the expression of the ease of the passing of the electrons. Conductivity is a numerical expression of the tendency of an aqueous solution to carry an electric current. Electricity is conducted through an electrolytic solution due to the movement of ions. In general, the greater the number of ions in the solution higher is the conductance.

The conductance of a solution depends on 1) the concentration of the ions it contains, 2) on the number of charges carried by each ion, and 3) on the mobilities of these ions.

In an aqueous solution , charged particles that conduct electricity are ions , because of free ions electricity can be conducted in the solution. So , conductance depend upon concentration of the solution , more the concentration of solution more will be the conductance .

out of given solution , options a) 0.060 m solution of NaCl will be the most conducting solution as it is most concentrated option c) 0.015 m solution of NaCl  will be the least conducting solution as it is the least concentrated solution .

correct option will be (c) 0. 015 m NaCl of the following aqueous solutions would be expected to have the smallest conductance.

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Work is best described as?

Answers

Answer:

Explanation:

In physics, work can be described as force multiplied by the displacement of the object (distance caused by the force acted on the object).

Work is a form of energy, therefore, it is measured in joules.

If Alex pushed on an object with 10N of force, and the object moved 2 meters, the work of Alex will be equal to:

W = Ft

W = 10N * 2m

W = 20 Joules

But, if we have John, that pushed on an object with 2N of force, but, since the object was way smaller, therefore it had way less inertia, the object moved a distance equal to 10 meters. Let's also calculate his work.

W = Ft

W = 2N * 10m

W = 20 Joules

And we got the same result.

Work can also be used to calculate power.

Power is equal to P = Work / time

It can also be written as P = delta Work / delta time

Power is measured in joules per second.

With power you can make the difference between someone that got a 2 kg object up in 2 second, and someone that got a 2 kg object up in 5 second.

The more powerful one would be the one who managed to make the same work in less time.

Hope it Helped!

Work is described as: the measure of energy transfer resulting from the application of force over a displacement.

What is Work?

In the field of physics, work is most accurately defined as the outcome of multiplying the force exerted on an object by the distance the object is displaced in the same direction as the force.

This calculation serves to quantify the energy transferred to or from the object. For instance, if an individual applies a 50 Newton force to push a box across a 5-meter distance in the force's direction, the work done on the box would equal 250 Joules (50 N × 5 m).

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Is it possible to code the impact force using an accelerometer?

Answers

Yes, it possible to code the impact force using an accelerometer.

Accelerometers can be used to measure vibration on cars, machines, buildings, process control systems and safety installations

What is an Accelerometer ?

An accelerometer is a device that measures the vibration, or acceleration of motion of a structure.

The force caused by vibration or a change in motion (acceleration) causes the mass to "squeeze" the piezoelectric material which produces an electrical charge that is proportional to the force exerted upon it.

They can also be used to measure seismic activity, inclination, machine vibration, dynamic distance and speed with or without the influence of gravity.

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The _______________ is the point in an object where there is as much weight on one side as on the other side. This is also called the center of balance.

Answers

The center of gravity is the point in an object where there is as much weight on one side as on the other side. This is also called the center of balance.

what do you mean by center of balance and center of gravity ?

A location where an object is balanced in relation to applied forces is known as the center of balance (COB).

The average location of an object's weight is known as its center of gravity. Any object's travel through space may be completely explained in terms of how its center of gravity moves from one location to another and, if it is free to spin, how it rotates around that center of gravity.

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A planetary nebula glows because Choose one: A. it is heating up the interstellar medium around it. B. light from the central star causes emission lines. C. fusion is happening in the nebula. D. it is hot enough to emit UV radiation.

Answers

Emission lines are created by the star in the center's brightness.

A star in this kind of nebula uses UV radiation to energise the cloud's atoms. These atoms release radiation as they revert to lower energy states. It works in a manner like to a neon light. The nebula glows as a result of this.

What is Planetary nebula ?

The expelled shell of an evolved massive star is a planetary nebula.

It has a spherical shell-like shape and is made of relatively cool gas that was previously the star's outer layer. A low mass star's demise is linked to the formation of a planetary nebula. You recently reviewed 15 terms.

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obtain the temperature when the degree of the celsius scale will be one fifth of the corresponding degree of the Fahrenheit scale ​

Answers

Heat is necessary to warm 500g of water from 20°C to 65°C is 50 Fahrenheit heat required.

What is Fahrenheit scale degree?

Fahrenheit temperature scale, scale based on 32° for the freezing point of water and 212° for the boiling point of water, the interval between the two being separated into 180 equal parts.

How much heat required?

Heat transfer is a specialization of thermal energy that involves the generation, use, conversion, and deal of thermal energy between physical systems.

F = 9/5 C + 32     conversion from C to F

F = 9/5 × F/5 + 32

25 F = 9 F + 800

16 F = 800

F = 50

complete answer shown below

2. How much heat is necessary to warm 500g of water from 20°C to 65°C?​

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A ball is dropped from the top of a building. it initially moves at 4.0 m/s. after 0.5 seconds, it moves at 3.8 m/s. what force is responsible for the slowing of the ball? air resistance gravity normal tension

Answers

Air resistance (meeting space requirements)

Answer:

air resistance or A

Explanation:

A transformer is connected to 120 volts. find the current if the resistance is 4800-ohms.

Answers

Answer:

Explanation:

Formula

E = I * R                                      Substitute the givens into the formula

Givens

E = 120 volts

I = ?

R = 4800 0hms

Solution

Ohms law is a 3 letter equation that relates volts ohms (resistance) * current (in amperes)

E = i * R

120 V = I * 4800 ohms               Divide both sides by 4800  

120 V/4800 = I * 4800/4800     Divide

0.025 amps = I

Answer

I = 0.025 amps

If we ignore lift and drag forces as the squid flies through the air, what is the maximum horizontal range that the squid can achieve before splashing down?

Answers

The speed is 42 m/s at which squid rejects the water.

The maximum horizontal range that squid can achieve is 1.25 m

What is a drag force?

Drag force is a force acting opposite to the relative motion of any object moving concerning a surrounding fluid. This exists between two fluid layers or between a fluid and a solid surface.

Here,

mass of the water, m1 = 3.0 kg

mass of the squid, m2 = 36 kg

initial speed, v2 = 3.5 m/s

(a)

According to the conservation of momentum:

m1*v1 = m2*v2

3 * v1 = 36 * 3.5

v1 = 42 m/s

It is the speed at which the squid rejects the water.

(b)

The maximum range:

R(max) = (v2) ^2 / g

where,

g=9.8 m/s^2 and launch angle is 45°

R(max) = 3.5^2 / 9.8

R(max) =  1.25 m

Hence,

The speed is 42 m/s at which squid rejects the water.

The maximum horizontal range that squid can achieve is 1.25 m

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Your question is incomplete, but most probably the full question was:

We’ve seen that squid can escape from predators by ejecting water. Some squid do this at the surface of the ocean, thus launching themselves into the air—a particularly effective escape strategy. Suppose a 36 kg squid (not including water) at rest at the surface of the water brings in and quickly ejects 3.0 kg of water to achieve a takeoff speed of 3.5 m/s; these are typical numbers.

a. At what speed does the squid eject the water?

b. If we ignore lift and drag forces as the squid flies through the air, what is the maximum horizontal range that the squid can achieve before splashing down?

Are the acceleration and force vectors related? does the simulation show this relation?

Answers

The direction of the force vector and acceleration are identical (downwards) during the motion. The simulation also indicates the same relation.

Newton's 2nd regulation, F = ma is a vector equation. It says that the net force (a vector) acting on a mass m (a range of) causes an acceleration (a vector) of the object within the same path as the net force.

A simple mathematical relationship exists between the mass of an item (m), the net force at the item (f) and its acceleration (a). The acceleration of an object is without delay proportional to the net force and indirectly proportional to the item's mass (a = f/m).

For example, displacement, velocity, and acceleration are vector quantities, while speed (the magnitude of velocity), time, and mass are scalars. To qualify as a vector, a quantity having magnitude and direction must also obey certain rules of combination.

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2. If you want 0. 250 a (250 milliamps) to flow around a circuit with a resistance of 400 ohms, what voltage do you need?

Answers

Answer:

0.000625 V

Explanation:

The formula linking current , resistance and voltage is :

V = I/R

Voltage = Current / Resistance

Now we substitute values given in question :

Voltage = 0.250 / 400

Voltage (V) = 0.000625

Our final answer is 0.000625 V

Hope this helped and have a good day

You have discovered the planet Zoltron. It is 10.0 times farther from the Sun than Earth (10.0 AU). How long does it take this planet to go once around the Sun

Answers

Planet Zoltron takes 32 days to to go once around the Sun.

To find the answer, we need to know about the third law of Kepler.

What's the Kepler's third law?Kepler's third law says the square of time period is directly proportional to the cube of the radius of the orbit.Mathematically, T²∝a³What's the time period of planet Zoltron present at 10AU from sun?Let T1 , T2 are the time period of Earth and Zoltron. a1, a2 are radius of earth and Zoltron orbit respectively.As per Kepler's third law, (T1/T2)²= (a1/a2)³T2 = (a2/a1)3/2×T1

            = (10 AU/ 1AU)3/2 × 1day

             = 32 days.

Thus, we can conclude that the planet Zoltron has time period of 2 days.

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The innermost satellite of jupiter orbits the planet with a radius of 422 × 103 km and a period of 1.77 days. what is the mass of jupiter? (g = 6.67 × 10-11 n ∙ m2/kg2)?

Answers

The mass of Jupitar is obtained from the calculations as 5.8 * 10^-14 Kg.

What is the mass of Jupitar?

There are nine planets in the solar system and the sun lies at the enter of our solar system. This is the heliocentric model of the solar system.

Given that;

T^2 = GMr^3/4π

T = period

G = gravitational constant

r = radius

M = mass of Jupitar

Now;

1 day = 86400 seconds

1.77 days = 1.77 days *  86400 seconds/1 day

= 152928 seconds

Making M the subject of the formula;

M =4πT^2/Gr^3

M = 4 * 3.142 * (152928)^2/6.67 × 10^-11 * (422 × 10^9)^3

M = 2.9 * 10^11/5.0 * 10^24

M = 5.8 * 10^-14 Kg

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An 80. 0 kg person will need to climb a 30. 0 m stairway how many times to ""work off"" each excess cal (kcal) consumed?

Answers

The answer is 5.618928 kcal

The work done going up the stairway is the amount of gravitational potential energy that you gain.

GPE = m * g * h

= 80 * 9.8 * 30

=23,520J

converting to kcal

= 23520 * (0.2389 cal / 1J) * (1kcal / 1000cal)

= 5.618928 kcal

A calorie is a unit of energy. In nutrition, calories refer to the energy people get from the foods and drinks they eat, and the energy they use in physical activity. calories are indexed in the dietary records on all food packaging. Many weight loss programs center round reducing the consumption of calories.

There are many factors that go into determining your calorie needs. Your age, weight, height, and activity level all play a role. according to nutritional guidelines in the united states, adults 21 years old and older must consume anywhere between 1,600 and 3,000 calories per day.

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Question :
Which of the following has more inertia(mass)


(a) a rubber ball and a stone of the same size?
(b) a bicycle and a train?
(c) a five-rupees coin and a one-rupee coin?
[tex] \\ \\ \\ \\ \\ \\ \\ \\ \\ [/tex]
Please let ZzTheAmrcnNgtMareZz answer​

Answers

A rubber ball and a stone of the same size are examples which will have more inertia and is therefore denoted as option A.

What is Inertia?

This is referred to as the property exhibited by a body in which it has the tendency to remain at rest or in uniform motion.This property is dependent on the mass of the substance as we can deduce that the greater the mass, the greater the inertia and vice versa.

The size of a rubber ball and stone will have different masses in which that of the stone will be greater. This is as a result of the difference in the nature of the substances which are used to make both items mentioned above.

This is therefore the reason why  a rubber ball and a stone of the same size as having more inertia(mass) where chosen as the most appropriate choice in this scenario.

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Please help!
You release a pendulum of mass 1 kg from a height of 0.75 m.
A. If there is no air resistance, how fast is the pendulum going when it reaches the bottom?
B. If the pendulum loses 18% of its initial energy by the time it reaches the bottom, how fast is it going when it reaches the bottom?
C. If the pendulum loses another 7% of its remaining energy by the time it reaches the other side, how high does it go?
D. After a few minutes, the pendulum is no longer swinging at all explain why this happens, in terms of energy.

Answers

(A) The speed of the pendulum when it reaches the bottom is 3.83 m/s.

(B) The speed of the  pendulum when it reaches the bottom after losing 18% of its energy is 3.47 m/s.

(C) The height reached by the pendulum after losing another 7% of its energy is 0.57 m.

(D) When the pendulum stops swinging, it has used all its energy to overcome frictional force of air.

Speed of the pendulum when it reaches the bottom

Apply the principle of conservation of energy;

K.E = P.E

¹/₂mv² = mgh

v² = 2gh

v = √2gh

v = √(2 x 9.8 x 0.75)

v = 3.83 m/s

Speed pendulum after losing 18% of the its initial energy

K.E = (100 -  18)P.E

¹/₂mv² = 0.82mgh

V = √(0.82 x 2gh)

v = √(0.82 x 2 x 9.8 x 0.75)

v = 3.47 m/s

Height reached when its looses another 7%

K.E = 0.5(1)(3.47)² = 6.02 J

When it losses 7% = 6.02 - (0.07 x 6.02) = 5.598 J

Height reached:

mgh = 5.598

h = 5.598/mg

h = 5.598/(1 x 9.8)

h = 0.57 m

Final energy of the pendulum

When the pendulum stops swinging, it has used all its energy to overcome frictional force of air.

Thus, the speed of the pendulum when it reaches the bottom is 3.83 m/s.

The speed of the  pendulum when it reaches the bottom after losing 18% of its energy is 3.47 m/s.

The height reached by the pendulum after losing another 7% of its energy is 0.57 m.

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When heated in a flame, each element emits light that is unique to that
element. This light can be separated with a diffraction grating. Which of the
options below best explains why emission spectra occur?
A. When excited electrons return to their ground state, they emit
photons with specific wavelengths.
B. When electrons absorb energy to go into excited states, they
absorb all but the light that corresponds to the spectral lines.
C. When the elements are exposed to the flame, they undergo ad
chemical reaction that releases the specific lines of colored light.
D. When the elements are exposed to the flame, they undergo a
phase change, and the colors seen represent the element's color in
the gas phase.

Answers

i’ve done this before the answer is B

useful and inconvenience of frictional force of a soccor player running with soccer boots

Answers

They are useful in providing larger frictional force.

The force produced by two surfaces coming into contact and sliding against one another is referred to as frictional force.

The following variables impact the frictional force: Surface roughness and the amount of force pressing them together have the biggest impact on these forces.

Football shoes have spikes or studs because they offer more frictional force when running on grass than regular shoes do.

The studs make it easier for players to move faster and change directions rapidly without slipping while also preventing them from slipping on the grass.

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(a) What is the resistance of a lightbulb that uses an average power of 120 W when connected to a 60.0-Hz power source having a maximum voltage of 170 V

Answers

Resistance of a lightbulb is 240.8 ohm

Given:

Power = 120 W

Frequency = 60.0-Hz

Voltage = 170 V

To Find:

Resistance of a lightbulb

Solution: The electrical resistance of a circuit is the ratio between the voltage applied to the current flowing through it. Rearranging the above relation, R = V I. The unit of electrical resistance is ohms.

The resistance of the light bulb is given by the formula, R=V²/P

R = (170)^2/120

R = 240.8 ohm

Hence, the resistance of light bulb is R = 240.8 ohm

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Which element of the promotional mix is most helpful in inducing trial?

Answers

Sales Promotion, Income advertising publications to short-term and transient incentives to buy or result in trials of new items.

Sales advertising is an advertising approach in which an enterprise uses a transient campaign or provide to increase interest or demand in its service or product. There are numerous motives why a commercial enterprise may additionally choose to apply an income promotion (or 'promo'), however, the primary purpose is to reinforce income.

sales promotion is one of the elements of the promotional mix. The number one element within the promotional blend is advertising and marketing, private selling, direct marketing, and exposure/public relations.

Examples encompass contests, coupons, freebies, loss leaders, a factor of purchase shows, charges, prizes, product samples, and rebates. sales promotions may be directed at both the patron, sales group of workers, or distribution channel individuals (such as outlets).

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