When a car burns gas most of the energy is lost as heat. This inefficiency of energy transfer is an example of which law of energy?

A. second
B. fourth
C. first
D. third

Answers

Answer 1

Answer:

C) first

Explanation:


Related Questions

5. Calculate the time required to deposit 0.37g of Silver from a silverNitrate solution using a current of 2.5A( Charge of Ag in AgNO3 is + 1)​

Answers

Time required : 132.2 s

Further explanation

Given

mass of Silver = 0.37 g

current = 2.5 A

Required

time do deposit

Solution

Faraday's Law :

[tex]\tt W=\dfrac{e.i.t}{96500}[/tex]

e = ar/valence (valence Ag = 1)

i = current

t = time = s

[tex]\tt 0.37~g=\dfrac{108/1\times 2.5~A\times t }{96500}\\\\t=132.2~s[/tex]

help me please... tyy if you do :))

Answers

Answer:

a) HCl

Explanation:

As we know, that HCl or Hydrogen Chloride is a diatomic compound. It is formed due to the Chemical reaction of Hydrogen and Chlorine. As both Hydrogen and Chlorine have valencies of 1, the Net Valency of the Compound HCl is 1 itself. This separates it from the rest of the compounds. The rest of the compounds need to have more than 2 atoms of each kind and have different valencies too.

Examine the EM spectrum chart. Describe what is happening as the EM spectrum goes
from Radio Waves to Gamma rays,
Vight
Uno
Somme
Morowaves
Infrared
Radio Waves
Woman
w
w
Wavelength
The amplitude increases
The wavelength increases
The wavelength decreases
The amplitude decreases

Answers

Answer:

The wavelength decreases

Explanation:

As you go along the EM spectrum from radio waves to gamma rays, the wavelength decreases as the wave's energy and frequency increase.

Consider the reaction: 2AB2 → A2 + 2B2 You start with one mole of AB2 and the reaction is done at constant pressure of 3.7 atm and 28.2 °C. Assume all gases behave like ideal gases. What is the value of the work (in J)?

Answers

Answer:

-2503.2J

Explanation:

At constant pressure, change in work follows the equation:

W = -P*ΔV

Where W is work, P is pressure (3.7atm) and ΔV is change in volume

We can obtain change in volume using ideal gas low:

ΔV = ΔnRT/P

Where Δn is change in moles (3moles of products - 2 moles of reactants = 1)

R is gas constant (0.082atmL/molK)

T is absolute temperature (28.2°C + 273.15 = 301.35K)

P is pressure (3.7atm)

ΔV = ΔnRT/P

ΔV = 1mol*0.082atmL/molK*301.35K/3.7atm

ΔV = 6.69L

And work is:

W = -3.7atm*6.69L

W = -24.71atmL

1atmL = 101.3J

-24.71atmL * (101.3J / 1atmL) =

-2503.2J

Nitrogen gas is cooled and its volume went
from 375 mL to 255 mL. If the final
temperature is -45 °C, what was the original
temperature?

Answers

V1/T1 = V2T2
375 mL/ x = 255 mL/ 228 K
x = 335K = 62 degree Celsius

Please select the word from the list that best fits the definition left standing after the collapse of a sea arch

Answers

Answer:

Sea Stack

Explanation:   :)

Answer:

A

Explanation:

What signs of a chemical reaction did you observe during the lab? Check all that apply.

color change

temperature change

mass change

formation of a gas

formation of a solid

formation of a liquid

Answers

Answer:

1, 4, 5

Explanation:

1 - Color Change

4 - Formation of Gas

5 - Formation of Solid

(correct on ed)

Answer: A, D , E

Explanation:

What is the percent composition by mass for sodium (Na) in sodium phosphate (Na3PO4)? % Na = (______/______)x100% = _______% NNA​

Answers

The percent composition by mass for sodium (Na) in Sodium phosphate (Na₃PO₄) : 42.07%

Further explanation

Given

Compound of Sodium phosphate (Na₃PO₄)

Required

The percent composition by mass for sodium (Na)

Solution

The Comparative Law (Proust ) : compounds are formed from elements with the same Mass Comparison

MW Na₃PO₄ = 163,94 g/mol

Ar Na=22,989769g/mol

[tex]\tt \%mass~Na=\dfrac{3.Ar~Na}{MW~Na_3PO_4}\times 100\%\\\\\%mass~Na=\dfrac{3\times 22.99}{163.94}\times 100\%\\\\\%mass~Na=42.07\%~Na[/tex]

If a cake recipe requires 25g of sugar, how much sugar will the baked cake contain

Answers

The same amount of sugar which is 25g of sugar.

If a sample of air in a closed, rigid container was heated, would the partial pressure of oxygen increase, decrease or remain the same?

Answers

Answer:

increase

Explanation:

To solve this problem, you simply have to apply the Ideal Gas Law. Using this equation, we know that the pressure is directly proportional to the temperature. Thus, as something is heated (i.e. its temperature is increasing), its pressure would increase as well.

In your own words, define the following terms.
1 Blood
2 Lymph
3 Alveoli

Answers

Answer:

BLOOD - the definition of blood is the fluid carries oxygen

Explanation:

sana po makatulong♡♡

I HAVE 5 minutes HELP!!

Which organelle accurately completes the chart?
O lysosome
O cell wall
O vacuole
O endoplasmic reticulum

Answers

Answer:

endoplasmic reticulum

Explanation:

Endoplasmic reticulum will complete the chart. The Endoplasmic reticulum is one type of organelle that is present in eukaryotic cells. They form a network that is interconnected with membrane-enclosed sacs or structures that are tube shaped and are called cisternae.

Last one hope this helps have a wonderful dayyy

Which statement is true about water's density and the survival of marine life? view attachment

Answers

Option a would be the correct answer

what is the boiling point of carbon?

Answers

Answer: 3915 K ​(3642 °C, ​6588 °F)

Answer:

8,721°F

OR

4,827°C.

Explanation:

Good Luck!

In order to determine if 2 atoms are cooper what must be the same for each

Answers

-number of electrons
-atom size
-charge of the atom
-number of protons

if hydrochloride tablets and MP4 format you find the attachment photograph and signature​

Answers

answer is attached in the image below

Answerme espanol amigo me

Explanation:

what about solids ? Do solids move around like liquids and gases ?​

Answers

Answer:

No, gases move freely all over the place, liquids move more freely but in a more contained area, and solids the molecules are rigid, at the most the movement is small vibration as the molecules put pressure on one another to hold their form and stay in place.

What is the percent composition by mass for hydrogen in water (H2O)?
% H =(_____/_____)x100%=______ % H​

Answers

Explanation:

Percentage composition = 2/18 = 11.11%.

Write your thoughts or ideas about the lesson on types of soil.

Answers

Answer:

There are different types of soil in the earth. Those different types of soil helps the earth stay healthy in many ways!! Just like the different layers in the earth. There are so many different layers in the earth so that the plants get the different nutrition they need. Not only that but it cleans the water that soaks in the ground.

There are 6 different types of soil, they are; sandy soil, clay soil, silt soil, peat soil, chalk soil, and loam soil.

Explanation:

Sandy soil

Sandy Soil is light, warm, dry and tend to be acidic and low in nutrients. Sandy soils are often known as light soils due to their high proportion of sand and little clay (clay weighs more than sand). These soils have quick water drainage and are easy to work with. They are quicker to warm up in spring than clay soils but tend to dry out in summer and suffer from low nutrients that are washed away by rain. The addition of organic matter can help give plants an additional boost of nutrients by improving the nutrient and water holding capacity of the soil.

Clay Soil

Clay Soil is a heavy soil type that benefits from high nutrients. Clay soils remain wet and cold in winter and dry out in summer. These soils are made of over 25 percent clay, and because of the spaces found between clay particles, clay soils hold a high amount of water. Because these soils drain slowly and take longer to warm up in summer, combined with drying out and cracking in summer, they can often test gardeners.

Silt Soil

Silt Soil is a light and moisture retentive soil type with a high fertility rating. As silt soils compromise of medium sized particles they are well drained and hold moisture well. As the particles are fine, they can be easily compacted and are prone to washing away with rain. By adding organic matter, the silt particles can be bound into more stable clumps.

Peat Soil

Peat soil is high in organic matter and retains a large amount of moisture. This type of soil is very rarely found in a garden and often imported into a garden to provide an optimum soil base for planting.

Chalk Soil

Chalk soil can be either light or heavy but always highly alkaline due to the calcium carbonate or lime within its structure. As these soils are alkaline they will not support the growth of ericaceous plants that require acidic soils to grow. If a chalky soil shows signs of visible white lumps then they can’t be acidified and gardeners should be resigned to only choose plants that prefer an alkaline soil.

Loam Soil

Loam soil is a mixture of sand, silt and clay that are combined to avoid the negative effects of each type. These soils are fertile, easy to work with and provide good drainage. Depending on their predominant composition they can be either sandy or clay loam. As the soils are a perfect balance of soil particles, they are considered to be a gardeners best friend, but still benefit from topping up with additional organic matter.

Those are the different types of soils with all of their many uses. I hope this helps!!!!! Have a wonderful day!!!

HELP PLSSS FASTTTTTT!!!!!!!!!!!!!!!!

Answers

Answer:

with what?

Explanation:

Oil and water placed in a jar will separate. Even when shaken and mixed, the oil still separates from the water.

Which best describes oil and water?

Oil and water are highly soluble because they have separate chemical properties.
Oil and water have a low solubility because they have separate chemical properties.
Oil and water are highly soluble because they exert different pressures.
Oil and water have a low solubility because they exert different pressures.

Answers

Answer:

Probably B?

Explanation:

I don't have one...

Hope it helps I guess..

Answer: i think is B

Explanation: HATE ME IF IM WRONG

Which has a higher melting point KF or NaF?

Answers

Answer:

NaF

Explanation:

Melting point of NaF is 993°C but Melting point of KF is 858°C

Answer:

I think naf

Explanation:

En un recipiente cerrado a 25°C disponemos de un gas sometido a una presión de 250.000 Pa. Luego, sin que cambie el volumen, conseguimos una presión de 350.000 Pa. ¿a qué temperatura habremos tenido que calentar el gas?.

Answers

Answer:

El gas se calentó a 35°C

Explanation:

Para resolver este problema es necesario aplicar la Ley de Gay Lussac donde en una situación en la que un gas no modifica su volumen, su temperatura será directamente proporcional a la presión.

Podemos pensar que se describe desde la Ley de Gases Ideales donde:

P . V = n . R . T

para la situacion 1

y P . V = n . R . T para la situacion 2

Como V, n y R son constantes:

P₁ / T₁ = P₂ / T₂

250000 Pa / 25°C = 350000 Pa / T₂

T₂ = 350000 Pa . 25°C / 250000 Pa → 35°C

QUICK
Which of these is a ball and stick model?

Answers

Figure 3 is a ball and stick model

A student mixes two chemicals in a test tube. She notices that the mixture starts to bubble and the test
tube feels very warm. The student most likely concludes that the mixture is-
F. a chemical reaction that happened too quickly.
G. an endothermic reaction that absorbed thermal energy.
H. an exothermic reaction that released thermal energy.
J. not a chemical reaction.

Answers

Answer:

H. an exothermic reaction that released thermal energy.

Explanation:

The student will most conclude that this is a chemical reaction in which thermal energy is released to the environment.

Such reactions accompanied by the release of thermal energy are exothermic reactions.

In an exothermic change, heat is liberated to the surrounding. The surrounding becomes hotter at the end of the changes. For such reaction we say that enthalpy change is negative.

For endothermic reactions, heat is absorbed. At the end of the reaction, the system is cold.

The element in group 4 and period 3

Answers

The three group 4 elements that occur naturally are titanium, zirconium, and hafnium. The first three members of the group share similar properties; all three are hard refractory metals under standard conditions.

What object do you think will take up
more space? Why do you think this?

Answers

Answer:

solids

Explanation:

BC they r heavier than liquid and gas

Which substance below has the greatest intermolecular forces?
O oxygen with a boiling point of -183°C
O water with a boiling point of 100°C
O gold with a boiling point of 2,970°C
O mercury with a boiling point of 357°C

Answers

I’m sure tbh I finna watch some tvd

Answer:

Oxygen with a boiling point of -183°C.

Explanation:

Higher the intermolecular forces between the liquid particles, more durable it's for it to flee into the vapor part,you would like a lot of energy to convert it from liquid to the vapor part, in different words, higher its boiling point.

Hope it helps!<3


Isaac Newton lived and developed his Laws of Motion during which time period?

Answers

Answer:

saac Newton was a physicist and mathematician who developed the principles of modern physics, including the laws of motion and is credited as one of the great minds of the 17th-century Scientific Revolution.

Education: The King's School, University of Ca...

Birth Date: January 4, 1643

Death Date: March 31, 1727

Explanation:

Isaac Newton was a physicist and mathematician who developed the principles of modern physics, including the laws of motion and is credited as one of the great minds of the 17th-century Scientific Revolution.

hope it helps have a great day

A sample of water with a mass of 27.56g and an unknown temperature loses 2443 Joules. If the final temperature is found to be 62.50 C. What was the initial temperature?

Answers

Answer:

41.3 °C

Explanation:

From the question given above, the following data were obtained:

Mass (M) of water = 27.56 g

Heat (Q) loss = 2443 J

Final temperature (T2) = 62.5 °C

Initial temperature (T1) =?

NOTE: The specific heat capacity (C) of water is 4.18 J/g°C

Thus, we can obtain the initial temperature of the water by using the following formula:

Q = MC(T2 – T1)

2443 = 27.56 × 4.18 (62.5 – T1)

2443 = 115.2008 (62.5 – T1)

Divide both side by 115.2008

2443 / 115.2008 = (62.5 – T1)

21.20645 = 62.5 – T1

Collect like terms

21.20645 – 62.5 = – T1

– 41.3 = – T1

Divide both side by – 1

– 41.3 /– 1= – T1 / –1

41.3 = T1

T1 = 41.3 °C

Thus, the initial temperature of the water was 41.3 °C

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