When an object is raised vertically, work is done against _gravitational force _________
What is gravitational force ?The force of attraction between all masses in the universe; especially the attraction of the earth's mass for bodies near its surface is called gravitational force .
On every body there is a force acting named gravitational force which attracts the body downward .
If a object / body is thrown up it always comes downward if only gravitational force is acting on it which act due to earth's gravity .
When an object is raised vertically, work is done against _gravitational force _________
learn more about gravitational force :
https://brainly.com/question/12528243?referrer=searchResults
#SPJ2
What are characteristics of wide-angle lenses?
If a spring extends by 3 cm when a 4 N weight is suspended from it, find the extension
when the weight is changed to
(a) 8 N
(b) 10 N
(c) 14
How much power does motor provides an elevator in a building when the total mass when loaded is 500 kg to a height of 3m in 25 seconds?
19. In a turtle race, a 20 kg turtle moves with a velocity of 0.1 m/s. What is the kinetic energy of the turtle?
A. 20 J
B. 0.2 J
C. 0.1 J
The (BLANK) island were where Darwin made many important observations.
Answer:
I know theirs South American coast he was there a lot
What is the weight of a 25 kg object on Earth with an acceleration due to gravity of 9.8m/s/s?
2.45 n
24.5 n
245 n
2450 n
Please help me with this 29 points
Answer:
)Give the definition of poverty line as defined by the World Bank.
An alumium rod when measured with a steel scale both being at 25 degree celcius appears to be 1 meter long. If the scale is correct at 0 degree celcius, what is the true length of the rod at 25 degree celcius? What wull be the length of rod at 0 degree celcius?
If your water heat has an efficiency of 95 percent, how much energy would it take to heat 45kg of water from 23 C to 60 C. (The specific heat of water is 4.18 J/g/C.) Please show your work
Answer: 6611.715 joules
Explanation:
Q = MxCxdeltaT = 6959.7 which is 100%
95% = 6611.715
An official major league baseball has a mass of 0.14 kg. A pitcher throws a 40 m/s fastball which is hit by the batter straight back up the middle at a speed of 46 m/s.
a) What is the change in momentum of the ball during the collision with the bat?
b) If this collision occurs during a time of 0.012 seconds, what is the average force exerted by the bat on the ball?
Answer:
(a) The change in momentum is 12.04 kg-m/s
(b) The force exerted by the bat is 1003.33 N
Explanation:
Given that,
The mass of a ball, m = 0.14 kg
Initial speed of the ball, u = 40 m/s
Final speed of the ball, v = -46 m/s
(a) The change in momentum of the ball during the collision with the bat is given by :
[tex]\Delta p=m(v-u)\\\\=0.14(-46-40)\\\\=-12.04\ kg-m/s[/tex]
(b) Time for collision, t = 0.012 s
Now the force can be calculated as follows :
[tex]F=\dfrac{\Delta p}{t}\\\\F=\dfrac{12.04}{0.012}\\\\=1003.33\ N[/tex]
Hence, this is the required solution.
Answer:
a. = 12.04 kg*m/s
b. = 1,003.3N
Explanation:
The answer above is correct.
Astronauts living on the International Space Station have zero gravitational acceleration.
True
False
An instructor wishes to determine the wavelength of the light in a laser beam. To do so, she directs the beam toward a partition with two tiny slits separated by 0.180 mm. An interference pattern appears on a screen that lies 5.30 m from the slit pair. The instructor's measurements show that two adjacent bright interference fringes lie 1.60 cm apart on the screen. What is the laser's wavelength (in nm) ?
Answer:
λ = 5.434 x 10⁻⁷ m = 543.4 nm
Explanation:
To solve this problem we can use the formula provided by Young's Double Slit experiment:
[tex]\Delta x = \frac{\lambda L}{d}\\\\\lambda = \frac{\Delta xd}{L}[/tex]
where,
λ = wavelength of light = ?
Δx = distance between adjacent bright fringes = 1.6 cm = 0.016 m
d = slit separation = 0.18 mm = 0.00018 m
L = Distance between slits and screen = 5.3 m
Therefore,
[tex]\lambda = \frac{(0.016\ m)(0.00018\ m)}{5.3\ m}[/tex]
λ = 5.434 x 10⁻⁷ m = 543.4 nm
Which word best completes the sentence?
Select the word from the drop-down menu
He is quite
Choose...
despite never having left his smalL TOWEN
Answer:
it’s cosmopolitan
Explanation:
k12
it takes a cheetah just 3s to reach its top speed of 30m/s what is it's acceleration
Given values are:
Speed,
v = 30 m/sTime,
t = 3 sAs we know,
→ [tex]Acceleration = \frac{Speed}{Time}[/tex]
or,
→ [tex]a = \frac{v}{t}[/tex]
By substituting the values,
[tex]= \frac{30}{3}[/tex]
[tex]= 10 \ m/s^2[/tex]
Thus the above solution is correct.
Learn more about acceleration here:
https://brainly.com/question/2325876
The potential energy of an apple is 6.0 joules. The apple is 3m high. What is the mass of the apple?
Answer:
0.204 kg
Explanation:
6/(9.8*3)
6/29.4=0.204
9.8 represents gravity
Each vertical line on the graph is 1 millisecond (0.001 s) of time. What is the period and
frequency of the sound waves?
Help me!!!!!
Answer:
1000 Hz
Explanation:
please mark me as brainliest
6xy from -12xy
please give me a answer this question
6 floors down from 12 floors underground = 18 floors underground.
6 degrees colder than 12 degrees below zero = 18 degrees below zero
6 brown cows taken away from -12 brown cows = -18 brown cows
6 cars sold from a dealer that 12 cars were stolen from = 18 cars gone
6xy taken away from -12xy = -18xy
Help please :)
X-ray waves are transmitted by ....... ?
Answer:
im not sure maybe viberation
Explanation:
Answer:
X-ray waves are transmitted by ....... body tissues with very little absorption
Hope it helps
Please mark me as the brainliest
Thank you
Which subatomic particle identifies the element?
A.
protons
B.
electrons
C.
neutrons
D.
atomic mass
Answer:
A. Protons
Explanation:
Atomic number is an indicator of how many protons an element possesses in its nucleus. We use atomic number to identify an element. For example, carbon has 6 protons and an atomic number of 6.
Help please :)
Infrared waves are transmitted by ....... ?
it takes 840s to walk completely around a circular track, moving at a speed of 1.20m/s? what is the radius of the track?
Answer:
160.43 meters
Explanation:
T=(2*pi*r)/v
840=(2*pi*r)/1.2
1008=2*pi*r
504=pi*r
160.43=radius
The distance around the circular track is equal to its circumference. If it takes840 s to complete the path with a velocity of 1.20 m/s then the radius of the path will be 160 m.
What is velocity?Velocity is a physical quantity measuring the distance traveled by unit time. It is a vector quantity thus, characterized by its magnitude and direction. Velocity is usually expressed in m/s.
Velocity is the ratio of distance to the time taken to complete the travel. Thus, greater distance within short time indicates greater velocity.
Given that the time take to complete the circular path = 840 s
velocity = 1.20 m/s
distance = circumference of the circular path = 2πr.
distance = time × velocity
2πr = 840 s × 1.20 m/s
= 1008 m.
Therefore, the radius r of the circular path = 1008 m/ 2 π = 160 m.
Hence, the radius of the circular path 160 m.
To find more on velocity, refer here:
https://brainly.com/question/18084516
#SPJ2
when is an object considered to be in motion
Answer:
An object is considered to be in motion only when its position changes over time with reference to a point which will be known as orgin
Which statement best describes this situation
Answer:
what situation?
Explanation:
You push a 1.5 kg ball across a desk for 2 seconds, so that 10 J of work have been done. How much power was produced?
Answer
Answer:
i need help with the same question
Explanation:
What x rays travel at the speed of
A screw-jack used to lift a bus is a
A) first order lever
B) second order lever
C) pulley
D) screw
In what way does water change when condensation occurs?
from gas to liquid
from liquid to solid
from liquid to gals
from solid to liquid
Netwtons 1st law of motion
Answer:
Newton's first law states that, if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force. This postulate is known as the law of inertia.
Explanation:
During a circus act, an elderly performer thrills the crowd by catching a cannon ball shot at him. The cannon ball has a mass of 39.0 kg and its horizontal component of velocity is 6.50 m/s just before the 65.0 kg performer catches it. If the performer is initially motionless on nearly frictionless roller skates, what is his speed immediately after catching the cannon ball
Answer:
[tex]2.4375\ \text{m/s}[/tex]
Explanation:
[tex]m_1[/tex] = Mass of cannon ball = 39 kg
[tex]m_2[/tex] = Mass of performer = 65 kg
[tex]u_1[/tex] = Initial horizontal component of cannon ball's velocity = 6.5 m/s
[tex]u_2[/tex] = Initial horizontal component of performer's velocity = 0
v = Velocity of combined mass
As the momentum of the system is conserved we have
[tex]m_1u_1+m_2u_2=(m_1+m_2)v\\\Rightarrow v=\dfrac{m_1u_1+m_2u_2}{m_1+m_2}\\\Rightarrow v=\dfrac{39\times 6.5+0}{39+65}\\\Rightarrow v=2.4375\ \text{m/s}[/tex]
The speed of the performer immediately after catching the cannon ball is [tex]2.4375\ \text{m/s}[/tex].
Suppose that a uniform rope of length L resting on a frictionless horizontal surface, is accelerated along the direction of its length by means of a force F, pulling it at one end. A mass M is accelerated by the rope. Assuming the mass of the rope to be m and the acceleration is a. Stated in terms of the product ma, what is the tension in the rope at the position 0.3 L from the end where the force F is applied if the mass M is 1.5 times the mass of the rope m?
Answer:
2.2 ma
Explanation:
Given :
Length of the rope = L
Mass of the rope = m
Mass of the object pulled by the rope = M
M = 1.5 m
So, L [tex]$\rightarrow$[/tex] m
For unit length [tex]$\rightarrow \frac{m}{L}$[/tex]
∴ 0.3 L = [tex]$0.3 \ L \left(\frac{m}{L}\right)$[/tex]
= 0.3 m
And for remaining 0.7 L = [tex]$0.7 \ L \left(\frac{m}{L}\right)$[/tex]
= 0.7 m
By Newtons law of motion,
F - T = ( 0.3 m) a .........(1)
T = ( M + 0.7 m) a
T = ( 1.5 m + 0.7 m) a
T = ( 2.2 m ) a ..............(2)
So from equation (1) and (2), we have
Tension on the rope
T = 2.2 ma