When N,N-Dimethylaniline is treated with bromine, ortho and para products are observed. However, when N,N-Dimethylaniline is treated with a mixture of nitric and sulfuric acid, only the meta product is observed. Explain these results. (Hint: what can happen to the nitrogen atom in the presence of the strong acids

Answers

Answer 1

Answer:

See explanation below

Explanation:

To get a better understanding watch the picture attached.

In the case of the reaction with Bromine, the -N(CH₃)₂ is a strong ring activator, therefore, it promotes a electrophilic aromatic sustitution, so, in the mechanism of reaction, the lone pair of the Nitrogen, will move to the ring by resonance and activate the ortho and para positions. That's why the bromine wil go to the ortho and para positions, mostly the para position, because the -N(CH₃)₂ cause a steric hindrance in the ortho position.

In the case of the reaction with HNO₃/H₂SO₄, the acid transform the -N(CH₃)₂ in a protonated form, the anilinium ion, which is a deactivating of the ring, and also a strong electron withdrawing, so, the electrophile will go to the meta position instead.

Hope this helps.

When N,N-Dimethylaniline Is Treated With Bromine, Ortho And Para Products Are Observed. However, When

Related Questions

Convert −319 ∘F to kelvins.

Answers

Answer:

it is 78.15 Kelvins

Explanation:

-319 Fahrenheit to 78.15 Kelvins

somebody please explain how to determine the relative abundance of isotopes.im having trouble understaning the rule :)​

Answers

Answer:

isotopes have the SAME number of protonsbut DIFFERENT number of neutrons . to find out the neutrons you need to subtract atomic number from the mass "m-a=n"

How many grams of P2O5 are formed from 3.4 moles of O2? SHOW the math below

Answers

Answer:

I will do it again soon to open the door to my house with a new year sa imo lang mam kay I have a great time to go to work for the last time

The mass of the P₂O₅ formed from 3.4 moles of O₂ gas is equal to 386.1 g.

What is a mole?

A mole can be described as a unit for measurement of a huge number of quantities of atoms, molecules, ions, or other particles. The atomic mass can be expressed as the one mole of any element.

The number of particles present in one mole was to be equal to 6.023 × 10 ²³ which is Avogadro’s constant.

Given, the number of moles of O₂ gas = 3.4 moles

The balanced chemical reaction of phosphorous and oxygen gas can be given as:

4 P  +  5 O₂   →   2 P₂O₅

5 mol of Oxygen reacts with moles of P₂O₅ = 2 mol

3.4 mol of O₂ gas reacts with moles of P₂O₅ = (2/5) × 3.4 = 1.36 mol

The mass of the 1.36 mol of P₂O₅ = 1.36 × 283.89 = 386.1 g

Learn more about the mole, here:

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How are you finding the moles of the unknown substance when you are only given the grams of the unknown molecular compound?

Answers

Answer:

Determine the moles of unknown (the solute) from the molality of the solution and the mass of solvent (in kilograms) used to make the solution. Determine the molar mass from the mass of the unknown and the number of moles of unknown.

How many liters of a 15% NaCl solution should be mixed with 2 L of a 20% NaCl solution to obtain a 16%
NaCl solution?

Answers

Answer:

8 liters of 15% NaCl solution should be mixed with 2 L of a 20% NaCl solution to obtain a 16%  NaCl solution

Explanation:

The method employed here is known as alligation technique.

Alligation is a method used to calculate the proportion of any two solutions to be mixed to prepare final solution of required concentration.

Let the number of liters of the 15% NaCl solution be X

A mixture of X liters of 15% NaCl + 2 liters of 20% NaCl gives X + 2 liters of a solution whose concentration is 16%

X  * 15% + 2 * 20% = 16% * X + 2

0.15X + 2 * 0.2 = 0.16 X + 0.16 * 2

0.15X + 0.4 = 0.16X + 0.32

0.16X - 0.15X = 0.4 - 0.32

0.01X = 0.08

X = 0.08/0.01

X = 8 liters

Therefore, 8 liters of 15% NaCl solution should be mixed with 2 L of a 20% NaCl solution to obtain a 16%  NaCl solution

There are four conditions an atom needs to meet to participate in hydrogen bonding. It needs to be_______ enough not to bump into other atoms when approaching the 1s orbital of the hydrogen, it needs to carry at least one________ atom, it needs to be_________enough to create a delta on the connected hydrogen, and it needs to have at least one________.

Answers

Answer:

The conditions are

1) Small enough

2) Electronegative atom

3) highly electronegative

4) lone pair of electrons

The correct statement therefore is

It needs to be small enough not to bump into other atoms when approaching the 1s orbital of the hydrogen, it needs to carry at least one electronegative atom, it needs to be highly electronegative enough to create a delta on the connected hydrogen, and it needs to have at least one lone pair of electrons.

Explanation:

Hydrogen bonding is a type of intermolecular bond that occurs between the partial positive charge (delta) on a hydrogen atom bonded to a small highly electronegative element (like nitrogen, oxygen or fluorine) and the free electrons on another electronegative element of another molecule.

The hydrogen atom with the partial positive charge (delta) is known as the hydrogen bond donor, while the electronegative element, carrying lone electrons is called the hydrogen bond acceptor.

Let's take a deeper look at these terms:

1) Hydrogen bond donor

Using water (H₂O) as an example, the high electronegativity of the oxygen atom covalently bonded to the hydrogen atom draws the lone electron in the 1s orbital of the hydrogen atom, creating a partial positive charge (d⁺) on the hydrogen atom. This is what happens within one water molecule

2) Hydrogen bond acceptor

When two or more molecules of water interact, the partial positive charge (d⁺) on the hydrogen atom of one molecule, is attracted to the valence or free electrons on the oxygen atom of a nearby molecule of water thus creating a dipole-dipole intermolecular bond known as a hydrogen bond.

             

For the hydrogen bond to be effective, the electronegative atom bonded to the hydrogen acting as the hydrogen bond donor in the first water molecule needs to be small enough so as not to disrupt the 1s orbital of the hydrogen atom. The smaller the size of the electronegative atom, the stronger the partial negative charge created on the hydrogen atom.

The valence or free pair of electrons on the electronegative (oxygen) atom of the second molecule of water (hydrogen bond acceptor) is what attracts the partial positive charge on the hydrogen atom to create the hydrogen bond

4. How many grams are there in 7.5 x 1027 formula units of Sr(OH)2?
5. How many grams are there in 9.30 x 1026 molecules of H2SO4?
PLEASE ANSWER I WILL MARK YOU BRAINLIEST

Answers

Answer:

  4) 1.52 × 10^6 g

  5) 1.51 × 10^5 g

Explanation:

4. There are 121.63 g/mol of Sr(OH)₂, and there are 6.02214·10^23 formula units per mol. Then the number of grams is ...

  (7.5×10^27 formula units) × (121.63 g)/(6.02214×10^23 formula units)

  = 7.5×121.63/6.02214 × 10^4 g

  ≈ 1.52 × 10^6 g

__

5. H₂SO₄ has a molar mass of about 98.079 g, so the given quantity has a mass of about ...

  (9.30×10^26 formula units)(98.079 g)/(6.02214×10^23 formula units)

  = 9.30×98.079/6.02214 × 10^3 g

  ≈ 1.51 × 10^5 g

Answer:

4. 1.52×10^6 g

5. 1.51×10^5 g

Explanation:

hope it helps

#CARRYONLEARNING

What is the molecular formula for hydrogen peroxide?

Answers

The answer is “H2O2” .....

How are the smallest ocean waves produced?

Answers

Answer:

The moon is not pulling the tide as hard

Explanation:

I suppose, I know it dills with the moon though

Explanation:

Normalmente, las olas se forman por el viento aunque su historia comienza muy lejos, en el Sol. ... Cuando el viento sopla sobre el mar, las partículas de aire rozan a las partículas de agua y se empiezan a formar pequeñas olas de pocos milímetros de longitud, llamadas ondas capilares.

Normally, waves are formed by the wind, although their history begins very far away, in the Sun. ... When the wind blows over the sea, the air particles brush against the water particles and small waves of few millimeters in length, called capillary waves.

Which process is used to separate soluble compounds from insoluble compounds?
Select one:

a. Sublimation
b. Extraction
c. Decantation

Answers

Answer:

the answer is b extraction

Answer: Decantation

Explanation:

Decantation is a method used to separate mixtures of immiscible liquids or soluble compounds from insoluble compounds.

The procedure follows that the solids are mixed together and water is added. The soluble solid dissolves and the insoluble solid settles at the bottom of the flask. Now the soluble solid is poured out gently leaving the insoluble solid behind using a glass rod.

The disadvantage of Decantation is that it does not perfectly separate the mixture and Filtration is often a preferred method to separate soluble compounds from insoluble compounds

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What is the molar mass of KOH?

Answers

Answer:

56.11 g/mol

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Chemistry

Atomic Structure

Reading a Periodic TableExplanation:

Step 1: Define

[Compound] KOH

Step 2: Identify

[PT] Molar Mass of K - 39.10 g/mol

[PT] Molar Mass of O - 16.00 g/mol

[PT] Molar Mass of H - 1.01 g/mol

Step 3: Find

39.10 + 16.00 + 1.01 = 56.11 g/mol

whats a Natural Selection?

Answers

Answer:

Natural selection is the differential survival and reproduction of individuals due to differences in phenotype. It is a key mechanism of evolution, the change in the heritable traits characteristic of a population over generations.

Explanation:

I hope this helps :) Thank you. Plz mark brainliest.

Natural selection is the differential survival and reproduction of individuals due to differences in phenotype. It is a key mechanism of evolution, the change in the heritable traits characteristic of a population over generations.

How are acids and alkalis
similar?

Answers

Answer:h

Explanation:

Answer:

Acids and alkalis both contain ions. Acids contain lots of hydrogen ions, which have the symbol H+. Alkalis contain lots of hydroxide ions, symbol OH-. Water is neutral because the number of hydrogen ions is equal to the number of hydroxide ions.

Which process is not a state of matter change

A.melting
B.freezing
C.stirring
D.evaporation

Answers

The answer is C. stirring.

Answer:

C. sterling hope it helps

What is the ratio
amount (mol) Fatoms
amount (mol) Xe atoms
Enter your answer as an integer.
Pls help

Answers

Answer:

Empirical formula

Explanation:

The empirical formula of a compound is the simplest whole number ratio of atoms of each element in the compound. It is determined using data from experiments and therefore empirical.

describe how zinc oxide is made from zinc sulfide

Answers

CO2 adsorbed onto the ZnO, which is progressively lost during the experiment ? Are you sure about the quality of your ZnO ? If it is not a fresh one, it might be carbonated, and decompose into ZnO + CO2, thus losing weight. Alternatively, you can check if you produced ZnS through the expected reaction ZnO + H2S → ZnS + H2O : Take a small part of your sorbent on a lab tile, add a few drops of H2SO4 (4 mol/L), observe and smell. If ZnS is present, then a little amount of H2S gas will be produced: you will see it or at least smell it, as the nose is sensitive to 3 ppm of H2S in air. Then you'll conclude whether the expected reaction occurred or not.

What mass (g) of magnesium nitride (Mg3N2) can be made from the reaction of 1.22 g of magnesium with excess nitrogen? __Mg + __N2__Mg3N2
a. 1.69 b. 15.2
c. 5.07 d. 5.02 e. 3.38
I’ll give brainest

Answers

Answer:

1.69 g Mg₃N₂

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Chemistry

Atomic Structure

Reading a Periodic Table

Stoichiometry

Using Dimensional AnalysisReactions RxNExplanation:

Step 1: Define

[RxN - Unbalanced] Mg + N₂ → Mg₃N₂

[RxN - Balanced] 3Mg + N₂ → Mg₃N₂

[Given] 1.22 g Mg

[Solve] grams Mg₃N₂

Step 2: Identify Conversions

[RxN] 3 mol Mg → Mg₃N₂

[PT] Molar Mass of Mg - 24.31 g/mol

[PT] Molar Mass of N - 14.01 g/mol

Molar Mass of Mg₃N₂ - 3(24.31) + 2(14.01) = 100.95 g/mol

Step 3: Stoich

[DA] Set up:                                                                                                      [tex]\displaystyle 1.22 \ g \ Mg(\frac{1 \ mol \ Mg}{24.31 \ g \ Mg})(\frac{1 \ mol \ Mg_3N_2}{3 \ mol \ Mg})(\frac{100.95 \ g \ Mg_3N_2}{1 \ mol\ Mg_3N_2})[/tex][DA] Multiply/Divide [Cancel out units]:                                                         [tex]\displaystyle 1.68873 \ g \ Mg_3N_2[/tex]

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

1.68873 g Mg₃N₂ ≈ 1.69 g Mg₃N₂

1.
Draw the Dot Structure for Na!

Answers

Answer:

Na ·

Explanation:

Hello!

In this case, since the Lewis dot structure of any element illustrates the number of valence electrons at the outer shell; we can set up the electron configuration of sodium to obtain:

[tex]Na^1^1\rightarrow 1s^2,2s^2,2p^6,3s^1[/tex]

We can see there is only one valence electron, for that reason the Lewis dot structure is:

Na ·

Whereas the dot represents the valence electron.

Best regards!

The following pieces of evidence were found at separate explosion sites. For each item, indicate whether the explosion was more likely caused by low or high explosive, and explain your answer.
a. Lead azide residues
b. Nitrocellulose residues
c. Ammonium nitrate residues
d. Scraps of primacord
e. Potassium chlorate residues

Answers

Explanation:

The major difference between low and high explosives is the rate of detonation. Low explosives detonate very slowly (less than 1,000 meters per second), whereas high explosives detonate very quickly (from 1,000 to 8,500 meters per second).

High explosives among the given list are Lead azide residues, Ammonium nitrate residues, and  Scraps of primacord. Whereas Nitrocellulose residues and, Potassium chlorate residues are low explosives.

Calculate the molarity of 0.300 mol of Na2S in 1.75 L of solution.


Calculate the molarity of 31.3 g of MgS in 955 mL of solution

Answers

Answer:

Molarity[Na2S] = 0.1714

Molarity[Mgs] = 0.5811

Explanation:

Given:

0.300 mol [Na2S in 1.75 L]

31.3 g [MgS in 955 mL]

Find:

Molarity

Computation:

Molarity = Number of mole / volume in liter

Molarity[Na2S] = 0.300 / 1.75

Molarity[Na2S] = 0.1714

Molar mass of Mgs = 56.38 g/mol

Number of mole = 31.3 / 56.38

Number of mole = 0.555

Molarity[Mgs] = Number of mole / volume in liter

Molarity[Mgs] = [0.555 / 955]1000

Molarity[Mgs] = 0.5811

The formation of tert-butanol is described by the following chemical equation: Suppose a two-step mechanism is proposed for this reaction, beginning with this elementary reaction: Suppose also that the second step of the mechanism should be bimolecular. Suggest a reasonable second step. That is, write the balanced chemical equation of a bimolecular elementary reaction that would complete the proposed mechanism.

Answers

Answer:

(CH3)3C^+ + OH^-  --------> (CH3)3COH

Explanation:

This reaction has to do with SN1 reaction of alkyl halides. Here tert-butanol is formed from tert-butyl bromide.

The first step in the reaction is the formation of a carbocation. This is a unimolecular reaction. The rate of reaction depends on the concentration of the alkyl halide. This is a slow step and thus the rate determining step in the mechanism.

(CH3)3CBr -------> (CH3)3C^+ + Br^-

The second step is a fast step and it completes the reaction mechanism. It is a bimolecular reaction as follows;

(CH3)3C^+ + OH^-  --------> (CH3)3COH

Which molecule has a high specific heat?

a) C2H6
b) C2H6O
c) H2O

Answers

H2O is the correct answer :)



What type of tide would this arrangement of earth-moon-sun create?*


O full moon tide

O neap tide

O new moon tide

Ospring tide


HURRY!!!

Answers

Answer:

neap tide

Explanation:

There are two different types of tides, which are the spring tide and the neap tide.

Neap tides are weak tides which occur when the gravitational forces of the sun and the moon are at right angles to each other with respect to the earth. Since the sun and moon are at right angles, it causes a difference between the low and high tide.

The spring tide are strong tides which occur when the moon, sun and earth are in straight line. The spring tide occur during full moon and new moon.

Answer:

Neap Tides  

The result is a neap tide. The same effect happens during third quarter. These occur during first and last quarter moons. The gravitational pull is not as strong.

Explanation:

the first answer is correct

Infer: Naos is a star in the Argos constellation. It has a very deep blue color. What do you think is the approximate temperature of Naos?

Answers

Answer:

Being an extreme blue supergiant with 59 solar masses and a surface temperature of over 42000 kelvins, Naos is actually one of the brightest stars in the Milky Way. It's almost 800 000 times as bright as the Sun, although most of that light is ultraviolet.

Explanation:

Wien's displacement law to find the approximate temperature of a star, in this case the Naos temperature would be 64000K, the real temperature is 42000K

Wien's displacement law states that the product of the maximum wavelength emitted by a black body and its temperature is constant

          λ_{max} T = 2,898 10⁻³  [ m K]

A black body is a body that absorbs all the radiation that reaches it, which is why it looks black, the cavity inside the black body must be at a fixed mask and it was there so that a thermal equilibrium is established and the radiation can be emitted by the black hole.

The stars approach a black body in the sense that their mission has a similar maximum to that of the black holes, but the temperature is an effective temperature that does not take into account the different processes within the star.

With this wavelength of the emission maximum, the temperature of the stars is calculated, in this case the star Naos is a whitish-blue star, the surface temperature found in tables is 42000K

if we use Wien's displacement law the emission should be

            λ_{max}  = 2,898 10-3 / T

            λ_{max}  = 2,898 10-3 / 42000

           λ_{max}   = 690 nm

this emission corresponds to the color orange  

For a blue emission ranging from 450 nm to 500 nm, the temperature of a black body would be

              T = 64000K to 57000 K

therefore using wien's displament law the temperature of the star Naos should be approximately 64000k, the fact that the real temperature is lower is because there are several processes with different temperatures inside the star.

In conclusion, Wien's Displacement Law can be used to find the approximate temperature of a star, in this case the Naos Temperature would be 64000K

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A certain chemical reaction releases of heat energy per mole of reactant consumed. Suppose some moles of the reactant are put into a calorimeter (a device for measuring heat flow). It takes of heat energy to raise the temperature of this calorimeter by . Now the reaction is run until all the reactant is gone, and the temperature of the calorimeter is found to rise by . How would you calculate the number of moles of reactant that were consumed?
Set the math up. But don't do any of it. Just leave your answer as a math expression.
Also, be sure your answer includes all the correct unit symbols.

Answers

Answer:

The expression to calculate the number of moles reactants is:

n = 59.714 J / 368000 J/mole

Explanation:

Note: The question is missing some parts. The complete question is as follows:

A certain chemical reaction releases 368.kJ of heat energy per mole of reactant consumed. Suppose some moles of the reactant are put into a calorimeter (a device for measuring heat flow). It takes 4.09J of heat energy to raise the temperature of this calorimeter by 1°C. Now the reaction is run until all the reactant is gone, and the temperature of the calorimeter is found to rise by 14.6°C. How would you calculate the number of moles of reactant that were consumed?

Set the math up. But don't do any of it. Just leave your answer as a math expression.

Also, be sure your answer includes all the correct unit symbols.

Step 1: Determine the quantity of heat required to raise the temperature of the calorimeter by 14.6°C

Quantity of heat required to raise the temperature of the calorimeter by 1°C = 4.09 J

Quantity of heat required to raise the temperature of the calorimeter by 14.6°C = 4.09 * 14.6 = 59.714 J

Step 2: Express the quantity of heat released per mole of reactant in J/mole

368 kJ/mole = 368 kJ/mole * 1000 J/kJ = 368000 J/mole

Step 3: Express the moles of reactant as n and equate it to the energy absorbed by the calorimeter

Let the number of moles of reactant be n

Assuming that there is no heat lost to the surrounding, from the law of conservation of energy, Heat released = Heat absorbed

Heat released = number of moles of reactant * quantity of heat released per mole of reactant

Heat released = n * 368000 J/mole

Heat absorbed by calorimeter = 59.714 J

From the relation above, n * 368000 J/mole = 59.714 J

n = 59.714 J / 368000 J/mole

Therefore, the expression to calculate the number of moles is n = 59.714 J / 368000 J/mole

When did Martin Luther king JR became a pastor/minister?

Answers

1954 to 1960 is the time period he was a pastor/minister

If 3.53 g of CuNO, is dissolved in water to make a 0.330 M solution, what is the volume of the solution in milliliters?

Answers

Answer:

84.8 mL

Explanation:

From the question given above, the following data were obtained:

Mass of CuNO₃ = 3.53 g

Molarity of CuNO₃ = 0.330 M

Volume of solution =?

Next, we shall determine the number of mole in 3.53 g of CuNO₃. This can be obtained as follow:

Mass of CuNO₃ = 3.53 g

Molar mass of CuNO₃ = 63.5 + 14 + (16×3)

= 63.5 + 14 + 48

= 125.5 g/mol

Mole of CuNO₃ =?

Mole = mass / Molar mass

Mole of CuNO₃ = 3.53 / 125.5

Mole of CuNO₃ = 0.028 moles

Next, we shall determine the volume of the solution. This can be obtained as follow:

Molarity of CuNO₃ = 0.330 M

Mole of CuNO₃ = 0.028 moles

Volume of solution =?

Molarity = mole /Volume

0.330 = 0.028 / Volume

Cross multiply

0.330 × Volume = 0.028

Divide both side by 0.330

Volume = 0.028 / 0.330

Volume = 0.0848 L

Finally, we shall convert 0.0848 L to millilitres (mL). This can be obtained as follow:

1 L = 1000 mL

Therefore,

0.0848 L = 0.0848 L × 1000 mL / 1 L

0.0848 L = 84.8 mL

Therefore, the volume of the solution is 84.8 mL.


Write the net ionic equation for the precipitation of calcium sulfide from aqueous solution

Answers

Answer:

Answer is Ca2+(aq)+S2-(aq)=>CaS(s)

Explanation:

I hope it's helpful!

The net ionic equation for the precipitation of calcium sulfide in solution is; Ca^2+(aq) + S^2-(aq)   -------> CaS(s)

Let me give a typical instance since your question is incomplete. Imagine an aqueous solution of H2S and CaCl2 from which calcium sulfide does precipitate.

The molecular reaction equation is;

H2S(aq) + CaCl2(aq) -------> CaS(s) + 2HCl(aq)

The complete ionic equation is;

2H^+(aq) + S^2-(aq) + Ca^2+(aq) + 2Cl^-(aq) -------> CaS(s) + 2H^+(aq) + 2Cl^-(aq)

The net ionic equation is;

Ca^2+(aq) + S^2-(aq)   -------> CaS(s)

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We use less than 1% of the water on Earth for

Answers

Answer: drinking, bathing.

Explanation:

Brushing teeth,washing face,washing hands

Is a bowling ball made of matter?

Answers

Answer:

Yes a bowling ball made of matter.

Explanation:

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