Which activities demonstrate ability the most?

Answer:

not understanding meaning of your question

Step-by-step explanation:

sooooooooooooorrrrrrrrrrrrrrrrrryy

Answer: 18

Step-by-step explanation: Substitute the value of the variable into the equation and simplify.-Have a nice day

Answer:

Step-by-step explanation:

Answer:

use math\/\/ay

Step-by-step explanation:

Answer:

nty

Step-by-step explanation:

Answer:

I hope I can help

Step-by-step explanation:

welcome po

Answer:

Not Equivalent

Step-by-step explanation:

Good Luck If you need any other answers just comment and post your question

Step-by-step explanation:

Ans no.1

-2(y-4)

= -2y+4

=4-2y

Ans no.2

a=4 and b=6

6a+3b²

=6*4+3*6²

=24+108

=132

Ans no.3

65%of 180

= 65/100*180

=1170

Ans no.4

The absolute number is 7 because it is 7unit away from zero.

Ans no.5

The area of triangle= 1/2*base*height

=1/2*6*7

=21.

answer:

Answer:

268

Step-by-step explanation:

If a  garden table and a bench cost $618 combined. The garden table costs $82 less than the bench then the cost of the bench is $350.

Let's denote the cost of the bench as "x."

According to the given information, the garden table costs $82 less than the bench, so its cost can be represented as "x - 82."

The total cost of the garden table and bench combined is $618. Therefore, we can set up the following equation:

x + (x - 82) = 618

Simplifying the equation:

2x - 82 = 618

Next, we isolate the term with "x" by adding 82 to both sides of the equation:

2x - 82 + 82 = 618 + 82

2x = 700

Divide both sides by 2:

x=350

Therefore, the cost of the bench is $350.

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Answer:

C

Step-by-step explanation:

two quarters=half

4/8=1/2

Answer: It would be  2 1/2 liters

Step-by-step explanation:

There can be 2 and a half litres of water will be filled in 1 bottle.

Division is breaking a number up into an equal number of parts.

Given that,  3 litres of water can fill 1 ⅕ bottles,

Since, there are 3 litres in 6/5 bottles

so, 1 litre = 6/5×3 = 2 ¹/₂

Hence, There can be 2 and a half litres of water will be filled in 1 bottle.

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Answer:

[tex]\dfrac{3}{5}[/tex]

Step-by-step explanation:

We need to find the value of the following expression i.e.

[tex]\dfrac{(\dfrac{3}{5})^3}{(\dfrac{3}{5})^2}[/tex]

We know that,

[tex]\dfrac{\dfrac{a}{b}}{\dfrac{c}{d}}=\dfrac{a}{b}\times \dfrac{d}{c}[/tex]

So,

[tex]\dfrac{(\dfrac{3}{5})^3}{(\dfrac{3}{5})^2}=(\dfrac{3}{5})^3\times (\dfrac{5}{3})^2\\\\=\dfrac{3}{5}[/tex]

So, the value of the given expression is equal to [tex]\dfrac{3}{5}[/tex].

We know that they are using 7500 gallons of fuel for 1500 miles

we can do 7500 / 1500 = 5

Meaning that for every 5 gallons of fuel they travel 1 mile

Answer:

Use calculator soup while i was in college i used it and it helped SOOO much

Step-by-step explanation:

Answer:

x = 4

Step-by-step explanation:

The equation comes out to be:

3x + 11 = 5x + 3

Move the variables to the left-hand side and change its sign

And move the constant to the right-hand side and change its sign:

3x - 5x = 3 - 11

Combine like terms to get:

-2x = -8

Isolate x by dividing -2 on both sides:

-2x/-2 = -8/-2

x = 4

The number of bottles in the pack is 4.

The expression that can be used to represent the number of bottles bought by Andre is 3p + 11.

The expression that can be used to represent the number of bottles bought by Jillian is 5p + 3

Where:

p = number of bottles in the packs bought

If both Andre and Jillian have the same number of bottles, their expressions would be equal

3p + 11 = 5p + 3

In order to determine the value of p, take the following steps:

Combine similar terms

5p - 3p = 11 - 3

2p = 8

Divide both sides of the equation by 2

p = 4

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Answer:

7:3

Step-by-step explanation:

63:27

Divide both sides by 9

63 ÷ 9 : 27 ÷ 9

7:3

And you cannot simplify it anymore.

Hope this helped!

Have a superclaifragilisticexpialidocious day!

Answer:

7/3

Step-by-step explanation:

Divide both the numerator and denominator by the GCD

67:27 gcd: 9

63 ÷ 9

27 ÷ 9

Reduced fraction:

7/3

Therefore, 63/27 simplified to lowest terms is 7/3.

9514 1404 393

Answer:

  1. (256/3)π ft³

  2. 33.49 ft³

Step-by-step explanation:

1. Put 4 ft into the formula where r is, then simplify.

  V = (4/3)π(4 ft)³ = (256/3)π ft³

__

2. The radius is half the diameter, so is 2 ft. Put that in the formula, along with the value for π, and do the arithmetic.

  V = (4/3)(3.14)(2 ft)³ ≈ 33.49 ft³

Right format of question:

Plot two points that are 7 units from Point D and also share the same x-coordinate as Point D.

Answer:

[tex]D' = (-4,-6)[/tex] and [tex]D' = (-4,8)[/tex]

Step-by-step explanation:

Given

[tex]D(x,y) = (-4,1)[/tex]

Required

Determine a point 7 points from D and in the same x coordinate

Represent this point with D'.

From the requirement of the question, D' has two possible values and these values are:

[tex]D' = D(x,y-7)[/tex] ----> 7 units down and

[tex]D' = D(x,y+7)[/tex] ----> 7 units up

Substitute values for x and y in [tex]D' = D(x,y-7)[/tex] and [tex]D' = D(x,y+7)[/tex]

So, we have:

[tex]D' = D(x,y-7)[/tex]

[tex]D' = (-4,1 - 7)[/tex]

[tex]D' = (-4,-6)[/tex]

[tex]D' = D(x,y+7)[/tex]

[tex]D' = (-4,1+7)[/tex]

[tex]D' = (-4,8)[/tex]

Answer:

look at the screen shot

Step-by-step explanation:

Answer:

-10.64 is lesser and -5.35 i greater

Step-by-step explanation:

just did it on khan

Answer:

$8.75

Step-by-step explanation:

Let x = the amount the man originally had

The man has $x and says "if you give me $x, I will spend $10."

y = amount he has after 1st proposition = x + x - 10 = 2x - 10

He repeats this procedure, now with $2x-10 in his pocket...

z = amount he has after 2nd proposition = (2x - 10) + (2x - 10) - 10 = 4x - 30

He repeats this procedure, now with $4x-30 in his pocket...but this time he is left with zero dollars...

r = amount he has after 3rd proposition = (4x-30) + (4x-30) - 10 = 8x-70 = 0

8x - 70 = 0,

x = $8.75

Answer:

13.7 (nearest tenth)

Step-by-step explanation:

13.7142857143 is the full answer

Given, To make a strawberry shortcake for one person, we need :

▪︎[tex] \frac{1}{3} [/tex] cup of strawberry

▪︎one shortbread biscuit

Quantity of strawberries Elisa has = 3 cups

Number of shortbread biscuits she has = 12

Number of shortcakes she can make :

[tex] = \tt3 \div \frac{1}{3} [/tex]

[tex] = \tt\frac{3 \times 3}{1} [/tex]

[tex]\color{plum} =\tt 9 \: people[/tex]

Thus, Elisa can serve strawberry shortcakes to 9 people.

With 12 dozen shortbread biscuits she can serve 12 people.

Quantity of strawberries needed to serve 12 people :

[tex] =\tt \frac{1}{3} \times 12[/tex]

[tex] =\tt \frac{12}{3} [/tex]

[tex]\color{plum} = \tt4 \: cups[/tex]

▪︎Elisa can serve strawberry shortcakes to 9 people.

▪︎Elisa will need 4 cups of strawberries if she wants to use all dozen shortbread biscuits.

Answer:

0.30%

Step-by-step explanation:

Question:

If the nearest percentage is 0.30% what’s the nearest tenth of a percent?

Answer:

32-3n

Step-by-step explanation:

The formula for the nth term of a sequence is ' a+(n-1)d ' where a is the first term and d is the difference.

Here, a is 35 and d is -3.

a+(n+1)d

35+(n+1)(-3)

35-3n-3

32-3n

Step-by-step explanation:

........understood..............

Step-by-step explanation:

We have been investigating whether alloantigen-specific CD4(+)25+ regulatory T cells can be identified for use in treating graft-versus-host disease. CD150, which is upregulated on the surface of all activated T lymphocytes, was identified as a candidate marker for alloantigen-activated CD4(+)25+ regulatory T cells by gene chip analysis. Freshly isolated CD4(+)25+ cells had only low cell-surface expression of CD150, comparable to that of CD4(+)25- T cells. Increased CD150 expression was observed on all T cells after coculture with allogeneic stimulator cells. When purified CD4(+)25+ cells were precultured with allogeneic stimulator cells, then sorted into CD150+ and CD150- subsets, allosuppressive activity was contained primarily in the CD150+ fraction. These cells also suppressed the proliferation of alloantigen-activated autologous T cells, and they could be expanded in vitro without loss of their suppressive capacity. These results suggest that CD150 can be used as a marker for the identification of purified alloantigen-activated CD4(+)25+ regulatory T cells.

Answer:

A= [tex]R2[/tex] [tex]\pi[/tex]

Step-by-step explanation:

the building is 16 feet tall