Answers
Answer:
C
Explanation:
i think its C, not too sure
Related Questions
The potential energy stored in the compressed spring of a dart gun, with a spring constant of 32.50 N/m, is 0.640 J. Find by how much is the spring is compressed. Submit Answer Tries 0/20 A 0.050 kg dart is fired straight up. Find the vertical distance the dart travels from its position when the spring is compressed to its highest position. Submit Answer Tries 0/20 The same dart is now fired horizontally from a height of 3.90 m. The dart remains in contact until the spring reaches its equilibrium position. Find the horizontal velocity of the dart at that time. Submit Answer Tries 0/20 Find the horizontal distance from the equilibrium position at which the dart hits the ground.
Answers
Answer:
A
[tex]x = 0.198456 \ m [/tex]
B
[tex]h = 1.3061 \ m [/tex]
C
[tex] v = 5.06 \ m/s [/tex]
D
[tex]d = 4.0273 \ m [/tex]
Explanation:
Considering the first question
From the question we are told that
The spring constant is [tex]k = 32.50 N/m[/tex]
The potential energy is [tex]PE = 0.640 \ J[/tex]
Generally the potential energy stored in spring is mathematically represented as [tex]PE = \frac{1}{2} * k * x^2[/tex]
=> [tex]0.640= \frac{1}{2} * 32.50 * x^2[/tex]
=> [tex]x = \sqrt{0.03938}[/tex]
=> [tex]x = 0.198456 \ m [/tex]
Considering the second question
From the question we are told that
The mass of the dart is m = 0.050 kg
Generally from the law of energy conservation
[tex]PE = mgh[/tex]
=> [tex]0.640 = 0.050 * 9.8 * h[/tex]
=> [tex]h = 1.3061 \ m [/tex]
Considering the third question
The height at which the dart was fired horizontally is [tex]H = 3.90\ m[/tex]
Generally from the law of energy conservation
[tex]PE = KE [/tex]
Here KE is kinetic energy of the dart which is mathematical represented as
[tex]KE = \frac{1}{2} * mv^2[/tex]
=> [tex]0.640 = \frac{1}{2} * 0.050 * v^2 [/tex]
=> [tex] v^2 = 25.6 [/tex]
=> [tex] v = 5.06 \ m/s [/tex]
Considering the fourth question
Generally the total time of flight of the dart is mathematically represented as
[tex]t = \frac{ 2 * H }{g}[/tex]
=> [tex]t = \frac{ 2 * 3.90 }{9.8 }[/tex]
=> [tex]t = 0.7959 \ s [/tex]
Generally the horizontal distance from the equilibrium position to the ground is mathematically represented as
[tex]d = v * t[/tex]
=> [tex]d = 5.06 * 0.7959[/tex]
=> [tex]d = 4.0273 \ m [/tex]
Amoving object is in equilibrium. Which best describes the motion of the object if no forces change?
a. It will change directions.
b. It will slow down and stop.
c. It will maintain its state of motion.
d. It will speed up and then slow down.
Answers
PLEASE PROVIDE EXPLANATION.
THANK YOU!!
Answers
Answer:
11,000 kg
(a) 11.2 m/s
(b) 1.6 m/s
Explanation:
Momentum is conserved.
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
(2200 kg) (60.0 km/h) + m (0 km/h) = (2200 kg) (10 km/h) + m (10 km/h)
132,000 kg km/h = 22,000 kg km/h + m (10 km/h)
110,000 kg km/h = m (10 km/h)
m = 11,000 kg
Momentum is conserved.
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
(m) (-v) + (2m) (5v) = (m) (v₁) + (2m) (v₂)
-mv + 10mv = m v₁ + 2m v₂
9mv = m (v₁ + 2 v₂)
9v = v₁ + 2 v₂
Since the collision is elastic, kinetic energy is also conserved.
½ m₁u₁² + ½ m₂u₂² = ½ m₁v₁² + ½ m₂v₂²
m₁u₁² + m₂u₂² = m₁v₁² + m₂v₂²
(m) (-v)² + (2m) (5v)² = m v₁² + (2m) v₂²
mv² + 50mv² = m v₁² + 2m v₂²
51mv² = m (v₁² + 2 v₂²)
51v² = v₁² + 2 v₂²
We know v = 1.60 m/s. So the two equations are:
14.4 = v₁ + 2 v₂
130.56 = v₁² + 2 v₂²
Solve the system of equations using substitution.
130.56 = (14.4 − 2 v₂)² + 2 v₂²
130.56 = 207.36 − 57.6 v₂ + 4 v₂² + 2 v₂²
0 = 6 v₂² − 57.6 v₂ + 76.8
0 = v₂² − 9.6 v₂ + 12.8
v₂ = [ 9.6 ± √(9.6² − 4(1)(12.8)) ] / 2(1)
v₂ = 1.6 or 8
If v₂ = 1.6 m/s, then v₁ = 14.4 − 2 v₂ = 11.2 m/s.
If v₂ = 8 m/s, then v₁ = 14.4 − 2 v₂ = -1.6 m/s.
We know v₁ can't be -1.6 m/s, since that would mean puck A didn't change speeds after the collision. Therefore, v₁ = 11.2 m/s and v₂ = 1.6 m/s.
How far away is the light away in meters
Answers
299,792,458 is the right answer
) The square plates of a 5000-pF parallel-plate capacitor measure 50 mm by 50 mm and are separated by a dielectric that is 0.23 mm thickand totally fills the region between the plates. The voltage rating (the maximum safe voltage) of the capacitor is 400 V. What is the maximum energy that can be stored in this capacitor without damaging it
Answers
Answer:
4 x 10⁻⁴ J
Explanation:
C = 5000 pF, V = 400 V
Energy = CV²/2 = 5000 x 10⁻¹² x 400²/2 = 4 x 10⁻⁴ J
Which of the following is a description of the Remote Associates Test (RAT)?
Answers
Answer:
The description is outlined throughout the clarification section following, and according to the given word.
Explanation:
Throughout the 1960s, Sarnoff Mednick created the RAT as a tool used for testing imaginative convergent thought. Through each RAT test query lists a set of terms, which demands that we have a single additional term that will tie any of the others around. Those other words may also be related in something like a variety of ways, such as through creating a compound word or perhaps a semantic connexon.Why is a very small fraction (0.001%) of the water found in the atmosphere?
Answers
There is a very small fraction (0.001%) of the water found in the atmosphere due to evaporation of water.
What is Atmosphere?This is defined as mixture of gases surrounding the Earth or other celestial body, held in place by gravity.
A very small fraction (0.001%) of the water in the form of water vapor gas exist in the atmosphere due to evaporation by heat from the Sun.
Read more about Atmosphere here https://brainly.com/question/24925283
what is the diffrence between scalar and vector physical quantites write all examples that you know about each of them
Answers
Answer:
Scalar quantity is defined as the physical quantity with magnitude and no direction.
There are plenty of scalar quantity examples, some of the common examples are:
Mass
Speed
Distance
Time
Area
Volume
Density
Temperature
A vector quantity is defined as the physical quantity that has both direction as well as magnitude.
Vector quantity examples are many, some of them are given below:
Linear momentum
Acceleration
Displacement
Momentum
Angular velocity
Force
Electric field
Polarization
metal sphere having an excess of +5 elementary charges has a net electric charge of
Answers
Answer:
[tex]q=+8.01\cdot 10^{-19}\ coulombs[/tex]
Explanation:
Elementary charge
The elementary charge, denoted by the symbol e is the electric charge carried by a proton or, equivalently, the magnitude of a negative electric charge carried by an electron, which has charge −e.
The value of the elementary charge is a fundamental constant in physics:
[tex]\mathbf{e}=1.60217662 \cdot 10^{-19}\ coulombs[/tex]
If a metal sphere has an excess of +5 elementary charge, then it has a net charge of:
[tex]q=5*\mathbf{e}=+5*1.60217662 \cdot 10^{-19}\ coulombs[/tex]
[tex]\boxed{q=+8.01\cdot 10^{-19}\ coulombs}[/tex]
Define kinetic Energy and thermal energy. Describe what happens to each as the temperature of a substance is increases.
Answers
Explanation:
Kinetic energy is the energy by virtue of
object's motion whereas Thermal energy is
the internal energy of an object due to the
kinetic energy of its atoms.
On Increasing temperature, they both
increases
how does energy transfer between objects
Answers
Answer:
Object A runs into Object B. The force that object A has will transfer from Object A to Object B. But during this transfer you will loose some energy, therefore object B will not travel as fast.
Explanation:
A ball is launched directly upward and ultimately reaches a height of 40 ft on a day when the wind is gusting in different directions. From the time the ball is launched until it reaches a height of 20 ft off the ground the wind is blowing at constant 20 mph to the right. From that time to the time the ball has reached the top and traveled back down to a height of 20 ft the wind is blowing at constant 20 mph to the left. As it travels from 20 ft high back to the ground the wind again blows at a constant 20 mph to the right, where will the ball land?
Answers
Recall that
v² - u² = 2 a ∆x
where u and v are initial and final velocities, respectively; a is acceleration; and ∆x is the change in position.
We can use this formula to determine the launch speed of the ball. In the vertical direction, the ball has acceleration g in the downward direction, where g = 32.2 ft/s². At its maximum height, the ball has 0 vertical velocity. So we have
0² - u² = 2 (-32.2 ft/s²) (40 ft)
==> u ≈ 50.75 ft/s
Now, the ball's height y at time t is given by
y = u t - 1/2 g t²
Find at which time t the ball covers the first 20 ft of its trajectory:
20 ft = (50.75 ft/s) t - 1/2 g t²
==> t ≈ 0.462 s
(there is a second solution, t ≈ 2.69 s, which corresponds to the time it takes for the ball to return to this height as it's falling back down)
During this first interval, the ball's horizontal position x is
x = (20 mph) t ≈ (29.33 ft/s) t
so that at the moment the ball reaches a height of 20 ft, it will have moved
x = (29.33 ft/s) (0.462 s) ≈ 13.5 ft
to the right. (So we've take the right to be positive and the left to be negative.)
In the upper half of its trajectory, when the wind changes direction, the ball's horizontal position is given by
x = 13.5 ft - (29.33 ft/s) t
Note that t = 0 here means we now take the ball's current position to be the "initial" one. So the time we found earlier for when the ball has a height of 20 ft as it's falling back down is actually t = 2.69 s - 0.462 s ≈ 2.23 s. At this point, the ball's horizontal position is
x = 13.5 ft - (29.33 ft/s) (2.69 s - 0.462 s) ≈ -51.8 ft
or about 51.8 ft to the left of where it started.
The wind changes direction again, so that the ball's position at time t is now
x = -51.8 ft + (29.33 ft/s) t
Solving y = 0 for t gives the time when the ball reaches the ground:
0 = (50.75 ft/s) t - 1/2 g t²
==> t ≈ 3.15 s
Again, this is the time it takes for the ball to reach the ground since it was launched, while the position function takes t = 0 to refer to the moment the ball is 20 ft above the ground. So once it hits the ground, it will be
x = -51.8 ft + (29.33 ft/s) (3.15 s - 2.69 s) ≈ -38.3 ft
which means the ball lands on the ground about 38.3 ft to the left of where it started.
2.27 A gas is compressed from V1= 0.3 m3, p1=1 bar to V2= 0.1 m3, p2 =3 bar. The pressure and
the volume are related linearly during the process. For the gas, find the
work, in kJ.
2.29 A gas expands from an initial state where p1=500kPa and V1=0.1m3 to a state
end where p2= 100 kPa. The relationship between pressure and volume during the process is
pV=constant. Schematize the process in a p-V diagram and determine the work, in
kJ.
Answers
Answer:
-40 kJ
80 kJ
Explanation:
Work is equal to the area under the pressure vs volume graph.
W = ∫ᵥ₁ᵛ² P dV
2.27) Pressure and volume are linearly related. When we graph P vs V, the area under the line is a trapezoid. So the work is:
W = ½ (P₁ + P₂) (V₂ − V₁)
W = ½ (100 kPa + 300 kPa) (0.1 m³ − 0.3 m³)
W = -40 kJ
2.29) Pressure and volume are inversely proportional:
pV = k
The initial pressure and volume are 500 kPa and 0.1 m³. So the constant is:
(500) (0.1) = k
k = 50
The final pressure is 100 kPa. So the final volume is:
(100) V = 50
V = 0.5
The work is therefore:
W = ∫ᵥ₁ᵛ² P dV
W = ∫₀₁⁰⁵ (50/V) dV
W = 50 ln(V) |₀₁⁰⁵
W = 50 (ln 0.5 − ln 0.1)
W ≈ 80 kJ
calculate the monentun pf 75 kg bicycle and boy who has ghe velocitg of 3m/s
Answers
Explanation:
n=75 kg
v=3m/s
m=n×v
m=75x3
m= 225n
we can see objecf in bright room because
Answers
Answer:
because there is a reflection due to light in the the room.
Explanation:
if if it's helped you please mark as brainliest and like and follow please
We can see objects in a bright room because, the object reflect the light falling on them
what is E=mc^2?
please explain..
Answers
Answer:
In physics, mass–energy equivalence is the principle that anything having mass has an equivalent amount of energy and vice ve
Two insulated copper wires of similar overall diameter have very different interiors. One wire possesses a solid core of copper, with a circular cross section of radius 1.53 mm. The other wire is composed of 19 strands of thin copper wire bundled together. Each strand has a circular cross section of radius 0.306 mm. The current density ???? in each wire is the same. ????=1750 A/m2 Two circles. One circle is solid, whereas the other contains 19 tightly packed smaller circles How much current does each wire carry? solid wire current: A stranded wire current: A The resistivity of copper is ????=1.69×10−8 Ω·m. What is the resistance of a 3.25 m length of each wire? solid wire resistance: Ω stranded wire resistance: Ω
Answers
Answer:
a
Solid Wire [tex]I = 0.01237 \ A [/tex]
Stranded Wire [tex]I_2 = 0.00978 \ A [/tex]
b
Solid Wire [tex]R = 0.0149 \ \Omega [/tex]
Stranded Wire [tex]R_1 = 0.0189 \ \Omega [/tex]
Explanation:
Considering the first question
From the question we are told that
The radius of the first wire is [tex]r_1 = 1.53 mm = 0.0015 \ m[/tex]
The radius of each strand is [tex]r_0 = 0.306 \ mm = 0.000306 \ m[/tex]
The current density in both wires is [tex]J = 1750 \ A/m^2[/tex]
Considering the first wire
The cross-sectional area of the first wire is
[tex]A = \pi r^2[/tex]
= > [tex]A = 3.142 * (0.0015)^2[/tex]
= > [tex]A = 7.0695 *10^{-6} \ m^2 [/tex]
Generally the current in the first wire is
[tex]I = J*A[/tex]
=> [tex]I = 1750*7.0695 *10^{-6}[/tex]
=> [tex]I = 0.01237 \ A [/tex]
Considering the second wire wire
The cross-sectional area of the second wire is
[tex]A_1 = 19 * \pi r^2[/tex]
=> [tex]A_1 = 19 *3.142 * (0.000306)^2[/tex]
=> [tex]A_1 = 5.5899 *10^{-6} \ m^2[/tex]
Generally the current is
[tex]I_2 = J * A_1[/tex]
=> [tex]I_2 = 1750 * 5.5899 *10^{-6} [/tex]
=> [tex]I_2 = 0.00978 \ A [/tex]
Considering question two
From the question we are told that
Resistivity is [tex]\rho = 1.69* 10^{-8} \Omega \cdot m[/tex]
The length of each wire is [tex]l = 6.25 \ m[/tex]
Generally the resistance of the first wire is mathematically represented as
[tex]R = \frac{\rho * l }{A}[/tex]
=> [tex]R = \frac{ 1.69* 10^{-8} * 6.25 }{ 7.0695 *10^{-6} }[/tex]
=> [tex]R = 0.0149 \ \Omega [/tex]
Generally the resistance of the first wire is mathematically represented as
[tex]R_1 = \frac{\rho * l }{A_1}[/tex]
=> [tex]R_1 = \frac{ 1.69* 10^{-8} * 6.25 }{5.5899 *10^{-6} }[/tex]
=> [tex]R_1 = 0.0189 \ \Omega [/tex]
A block is 10cm long, 5cm wide and 2cm high and weighs 100g. What is the volume of the block? What is the density?
Answers
Answer:
1gm/cm^3
Explanation:
its the answer
Assignment 1. Define Couple?
Answers
Question 4
5 pts
What is microscopic and floats in the ocean?
Plankton
Benthos
Nekton
© Fish
Answers
Answer:
Plankton is the correct answer I think
Think about the way your body works when you eat an ice cream cone. Provide an explanation of how organs are working together as a system to help you eat the cone. Describe one organ system and how its parts combine to get your body nutrition from the food.
PLZ HELP
Answers
Answer:
Explanation:
BAHAHAHAH karely omg HAHAHA un idke
22/22 is an even number greater than 20?
Answers
Answer:
yes
Explanation:
becuse it is an even that is 2 number then 20
Answer:
Yes
Explanation:
It is because 22 is greater than 20
If a car with a mass of 4000 kg is accelerating at a rate of 2 ms and hits a tree what force does it have
Answers
That depends on the car's speed at the moment of impact, and how long it takes to stop after the impact.
It is NOT 8,000N. That answer would come from a totally incorrect application of " F = m a " . 8,000 Newtons is what it takes to accelerate that car in the first place, long before it hits the tree.
Force can be described as either a pull or a push
Now when a body with mass and acceleration hits an object, we say a collision has taken place, hence there will be transfer of energy within the system
Give data
mass = 4000kg
acceleration = 2m/s^2
We know that force is given as
Force = mass x acceleration
Substitute our given data into the expression for force
Force = 4000 x 2Force = 8000N
For more information on force kindly visit
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Lana's class is studying the various kinds of energy found on a playground
Which of the following would be the BEST way to test for an equal transformation of energy on a playground?
СА
Using the slide, Lana could measure her kinetic energy when she was climbing up the ladder, measure her potential energy before she slid down, and her total energy used at the bottom of the slide. If the amount of potential
energy and kinetic energy added up to equal the total amount of energy used, it would show an equal transformation of energy
OB
Using the slido, Lana could measure her potential and kinetic energy sitting at the top of the slide, and then she could measure her kinetic and potential energy at various points while sliding to the bottom of the total value of
her potential energy and her kinetic energy were equal at every measuremont, it would show that there had been an equal transformation
C
Using the swing, Lana could measure her potential energy when she was sitting still on the swing, and she could measure her kinetic energy when the swing was in motion. If the kinetic energy was twice the amount of her
potential energy, it would show there had boon an equal transformation of potential energy to kinetic energy
D
Using the soesaw, Lana could measure her potential energy when she was in motion, and she could measure her kinetic energy when she was resting. If her kinetic and potential energy were equal, it would show that there
had been an equal transformation
Answers
If the amount of potential energy and kinetic energy added up to equal the total amount of energy used, it would show an equal transformation of energy.
What is Energy?This can be defined as the ability or capacity to do work. The potential and kinetic energy equals the total amount of energy involved when Lana was on the playground.
This depicts an equal transformation of energy which is why the most appropriate choice in this scenario is option A.
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The ratio of carbon-14 to nitrogen-14 is an artifact is 1:3. Given that half-life of carbon-14 is 5730years, how old is the artifact?
Answers
Answer:
9155 years old
Explanation:
We use the following expression for the decay of a substance:
[tex]N = N_0\,\,e^{-k*t}[/tex]
So we first estimate the value of k knowing that the half-life of the C14 is 5730 years:
[tex]N = N_0\,\,e^{-k*t}\\N_0/2=N_0\,\,e^{-k*5730}\\1/2 = e^{-k*5730}\\ln(1/2)=-k*5730\\k= 0.00012[/tex]
so, now we can estimate the age of the artifact by solving for"t" in the equation:
[tex]1/3=e^{-0.00012*t}\\ln(1/3)= -0.00012*t\\t=9155. 102[/tex]
which we can round to 9155 years old.
what are the applications of measurement?
Answers
5
Find the resultant of the following four forces.
A= 25 N due north
B = 50 N due east
C= 30 N due west
D=40 N due south
Answers
25+50-30-40 = 0
north and east are positive directions, south and west are negative
hope this helps
also hope u enjoy a pic of my crush lol
a strong inductive argument must have true premises
True
False
Answers
If electrons are added to an object the object becomes
charge.
negative
positive
neutral
nothing happens
Answers
Answer:
It can be either, depending on how much and how you add the electrons
The statement "All Romans are Italians" means the same as "If you are Roman, then you are Italian"
True
False