Which distance increases?

Answer:

14 Newtons

Explanation:

6N + 8N = 14N

Answer:

0.167 m

Explanation:

By the definition of the velocity if a wave ,

The velocity of light, v, is the product of its wavelength, λ , and its frequency, f.  

V= fλ

frequency - number of occurrences in a unit time

Wavelength - distance between corresponding points of two consecutive waves

(check the graph for wavelength)

Answer:

Neutrons do not carry an electrical charge so adding or removing them from the nucleus does not change the electrical charge of the nucleus. ... So, adding or removing protons from the nucleus changes what element that atom is! For example, adding a proton to the nucleus of an atom of hydrogen creates an atom of helium.

Answer:

1.5 A

Explanation:

V =I.R

18 = I × 12

I = 18/12

= 3/2 = 1.5 A

Answer:

cell pohnes convert sound waves into radio waves

electromagnetic waves used in cellphone communications are called: radio waves

To send out a radio signal far and wide.. it is called: broadcast

Explanation:

Answer:

1.radio wave

2. radio wave

3.broadcasting

Tangential speed vT, for the stallite that orbits the earth from a distance 3R is compared by  [tex]\bold {(vT)= \dfrac {(v0)}{3}}[/tex].

Given here,

Vo - Speed  

R - Distance of center of the earth

Fo - Force exerted on satellite

vT - Tangential speed

For satelite, Gravitational force (Fg)is equal to the centripetal force(Fc),

Fg = Fc = Fo

[tex]\bold {\dfrac {GMm}{R^2} = \dfrac {m(v0)^2}R}[/tex]

GM = (v0)²R.....................  (1)

Since, For satellite R = 3R

Thus,

[tex]\bold {\dfrac {GMm}{3R^2} = \dfrac {m(v0)^2}{3R}}[/tex]

[tex]\bold {\dfrac {GMm}{3R^2} = \dfrac {m(vT)^2}{3R}}\\\\\bold {\dfrac {GM}{27 R} = \dfrac {(vT)^2}{3R}}\\\\\bold {GM = \dfrac {27 R \times (vT)^2}{3R}}\\\\\bold {{GM}= 9 R \times (vT)^2}\\[/tex].........(2)

From equation 1 and 2,

(v0)²R = 9(vT)²R

Divide through R and then 9, we get

[tex]\bold {(vT)^2 = \dfrac {(v0)^2}{9}}[/tex]

Take the square root,

[tex]\bold {(vT)= \dfrac {(v0)}{3}}[/tex]

Therefore,  tangential speed, vT, for the stallite that orbits the earth from a distance 3R is compared by  [tex]\bold {(vT)= \dfrac {(v0)}{3}}[/tex].

To know more about tangential speed,

https://brainly.com/question/17689540

Answer:

c, 280,000J

Explanation:

You should use the equation KE (Kinetic Energy) = [tex]\frac{1}{2} mv^2[/tex]

m = 2500

v = 15

KE = [tex]\frac{1}{2} * 2500 * (15)^2\\[/tex]

KE = 281250 Joules.

This is consistent with the answer B, as all of the parameters given to you are rounded to 2 significant figures so naturally, the answer should also be rounded to 2 sig figs.

KE = 280,000 J

Answer:

around 30 grays

Explanation:

Hope this helps :)

Answer:Hey I just wanted to tell you that Jesus LOVES YOU SO MUCH He died on the cross for all your sins so you won’t have to suffer the consequences of your sin He paid for ALL OF IT! He loves you SO FREAKING MUCH like unconditionally... all you have to do is confess with your mouth and believe in your heart that Jesus is Lord and God raised Him from the dead 3 days later you will be saved ;)))))))) He wants an intimate relationship with you all you have to do is reach out to Him I love you AND ABOVE ALL JESUS LOVES YOU

Have a blessed day;))

Explanation:

Explanation:

The acceleration of the scooter is 2.5 m/s

Answer:

The position of the image from the camera lens is approximately 121.1 mm

Explanation:

The given parameters of the lens are;

The specification of the camera lens = 120 mm

Therefore, the focal length of the camera lens, f = 120 mm = 0.12 m

The distance of the object from the camera, [tex]d_o[/tex] = 13 m

The lens equation for finding the position of the image is given as follows;

[tex]\dfrac{1}{f} = \dfrac{1}{d_o} + \dfrac{1}{d_i}[/tex]

Where;

[tex]d_i[/tex] = The position of the image from the camera lens

Therefore, by plugging in the known values, we have;

[tex]\dfrac{1}{13} = \dfrac{1}{0.12} + \dfrac{1}{d_i}[/tex]

[tex]\dfrac{1}{d_i} = \dfrac{1}{0.12} - \dfrac{1}{13} = \dfrac{13 - 0.12}{0.12 \times 13} = \dfrac{12.88}{1.56} = \dfrac{322}{39}[/tex]

[tex]\therefore d_i = \dfrac{39}{322} \approx 0.1211[/tex]

The position of the image from the camera lens, [tex]d_i[/tex] = 0.1211 m = 121.1 mm

Answer:

8cm/sec

Explanation:

Number of cycle per second. Distance covered is 8cm in one cycle.

Answer:

A. The brightness of the bulb

Explanation:

An electric current through a circuit turns the lights bulb on. the strength of the current created by the generator will be indicated by the brightness of the bulb because in a closed circuit, the bulb is the only object that is representing that, circuit is properly placed and when bulb lights up only when electrical energy is generated.

More electrical energy generated through the generator means the brighter the bulb glow.

Hence, the correct answer is "A. The brightness of the bulb".

Answer:

A., D., and E.

Explanation:

Gravitational potential energy is mgh, the values represented by answers E., D., and E., respectively.

Have a wonderful day!

Answer:

Im late. A D and E

Explanation:

The factors that affect an object's gravitational potential energy are its height relative to some reference point, its mass, and the strength of the gravitational field it is in. The formula for potential energy depends on the force acting on the two objects. For the gravitational force the formula is P.E. = mgh, where m is the mass in kilograms, g is the acceleration due to gravity (9.8 m / s2 at the surface of the earth) and h is the height in meters.

Answer:

A)  C = 4.425 10⁻¹³ F,  B) Q = 6.31 10⁻¹¹ C,  C)  E = 8.9 10⁴ N / C,  

D)  u_{E} = 3.19 10⁻⁹ J

Explanation:

Part A. Capacitance is

           C = ε₀ A / d

in this case distance is d = 0.800 cm = 0.800 10⁻² m and the area of ​​the plates is x = 0.200 cm= 0.2 10⁻² m, all the quantities must be in the SI system for the result to be in Farads

           A = x²

           A = (0.2 10⁻²)²

           A = 4 10⁻⁶ m

let's calculate

          C = 8.85 10⁻¹² 4 10⁻⁶ / 0.8 10⁻²

          C = 44.25 10⁻¹⁴ F

          C = 4.425 10⁻¹³ F

Part B. The charge on each plate is

          Q = C ΔV

           Q = 4.425 10⁻¹³ 120

           Q = 6.31 10⁻¹¹ C

Part C. the electric field of a plate is

           E = σ / 2ε₀

where the charge density is

            σ = Q / A

we substitute

             E =[tex]\frac{Q}{ 2\epsilon_o A}[/tex]

let's calculate

             E = [tex]\frac{6.31^{-11} }{ 2 \ 8.85^{-12} \ 4^{-6} }[/tex]

             E = 8.9 10⁴ N / C

Part D. stored energy

              [tex]u_{E}[/tex] = ½ C V²

               u_{E} = ½ 4.425 10⁻¹³ 120²

               u_{E} = 3.19 10⁻⁹ J

Answer:

W = 7056  J

Explanation:

Given that,

Mass of a load, m = 60 kg

Distance moved, d = 12 m

We need to find the amount of work. The work done by an object is given by :

W = Fd

So,

W = mg×d

W = 60 kg × 9.8 m/s²×12 m

W = 7056  J

So, the amount of work done is 7056  J.

The net force acting on the object is 703.125 N

In the case of circular motion, there is a centripetal acceleration acting on the object given by:

[tex]a_{r}=\frac{v^{2} }{r}[/tex]

where, v is the velocity of the object = 15 m/s,

and r is the radius of the path = 1.6 m

The net force F:

[tex]F=ma_{r}=m\frac{v^{2} }{r}[/tex]  

[tex]F=5*\frac{15^{2} }{1.6}\\F=703.125 N[/tex] is the net force acting on the object.

Learn more about circular motion:

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Answer:

work=force* distance

Explanation:

cal it your self

Answer:

I think it is behavioral

Answer:

D

Explanation:

it's all of the above because they all use for gravity

Work needed = 23,520 J

Given

height = 12 m

mass = 200 kg

Required

work needed by the crane

Solution

Work is the transfer of energy caused by the force acting on a moving object  

Work is the product of force with the displacement of objects.  

Can be formulated  

W = F x d  

W = Work, J, Nm  

F = Force, N  

d = distance, m  

F = m x g

Input the value :

W = mgd

W = 200 kg x 9.8 m/s²x12 m

W = 23520 J

Answer:

C) Exert an equal force back on the hammer

Explanation:

Every action has an equal and opposite reaction

also just trust me.

Make me brainlist

Dropping a can from a higher elevation  affects greater impact compare to  dropping a can from a lower elevation.

Potential energy is a form of stored energy that is dependent on the relationship between different system components. When a spring is compressed or stretched, its potential energy increases.

If a steel ball is raised above the ground as opposed to falling to the ground, it has more potential energy. It is capable of performing more work when raised.

Potential energy is a system attribute, not a property of a single body or particle.

The potential energy of the can on higher elevation is greater than the potential energy of the can on  lower elevation. That is why, dropping a can from a higher elevation  affects greater impact compare to  dropping a can from a lower elevation.

Learn more about potential energy here:

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