The equation that can be used to find y, the year in which both bodies of water have the same amount of mercury is 0.05 + 0.1y = 0.12 + 0.06y. Hence, the 3rd option is the right choice.
In the question, we have been asked for the equation that can be used to find y, the year in which both bodies of water have the same amount of mercury.
First, we will find the equations showing the level of mercury in each body of water.
For the first water body:
Initial measure of mercury = 0.05 ppb.
Rate of rising = 0.1 ppb each year.
Number of years = y.
Thus, the equation showing level of mercury = 0.05 + 0.1y.
For the second water body:
Initial measure of mercury = 0.12 ppb.
Rate of rising = 0.06 ppb each year.
Number of years = y.
Thus, the equation showing level of mercury = 0.12 + 0.06y.
We are looking for the equation, to find y, the year in which both bodies of water have the same amount of mercury.
As they will have the same amount of mercury, their respective equations showing the level of mercury should be equal, that is:
0.05 + 0.1y = 0.12 + 0.06y, which is the required equation.
Thus, the equation that can be used to find y, the year in which both bodies of water have the same amount of mercury is 0.05 + 0.1y = 0.12 + 0.06y. Hence, the 3rd option is the right choice.
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For the complete question, refer to the attachment.
What is the slope of a line perpendicular to the line whose equation is 4x−y=9. Fully reduce your answer.
Answer:
slope of given line is 4.
so slope of line perpendicular to it will be -1/4
PLZ HELP!!! WILL GIVE HIGHEST POINTS IF THE ANSWER IS CORRECT!!!
Answer: -5 Hope this helps :)
Step-by-step explanation:
Brainlist Plz?
can someone help me, file attached
Answer:
C. log 10m is the correct answer.
Step-by-step explanation:
The laws of logarithm states that if you have:
[tex] log(a) + log(b ) = log(a \times b) = log(ab) [/tex]
So, comparing that to your question,
[tex] log(m) + log(10) = log(10m) .[/tex]
In circle O, AC and BE are diameters. The measure of arc DC is 50°. What is the measure of EBC?
Answer:
The angle measure would be 40°
Step-by-step explanation:
Right angles have a measure of 90. Since DC is 50, 90-50 is 40.
The angle measure of ∠EBC would be 40°.
What is arc?The arc is a portion of the circumference of a circle
Right angles have a measure of 90°.
∵∠BOD=90°
Since ∠DC is 50°,
∠EBC = ∠BOD-∠DC
∠EBC = 90°-50° is 40°.
The angle measure of ∠EBC would be 40°.
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PLEASE HELP WILL MARK BRAINLY
Use a ratio box to solve this problem: Five hundred fifty students attended the assembly. If the ratio of boys to girls in the assembly was 6 to 5, how many girls attended the assembly?
Answer:
250 girls
Step-by-step explanation:
Please let me know if you want me to write an explanation for my answer :)
!!!!!!PLEASE HELP WILL GIVE BRAINLIEST!!!!!!!
which of the following is a irratinol number
A. 1 squared
B. 41 squared
C.- 9 squared
D.-64 squared
What’s 12 times 12divided by 58 ?
Answer:
2.48........is your answer
Step-by-step explanation:
12×12 =144
144÷58
Can someone please help me with this? Right answer gets brainliest!!
Answer:
Part 1: y= 49
Part 2: y=12
Step-by-step explanation:
Part 1: The y is going up by 7, so if you add 7 to 42, you get 49
Part 2: The y is going up by 4, so if you add 4 to 8, you get 12
3.5 m = ______cm
PLEASE HELP ME!!!!!!!
Answer:
Formula *10
Step-by-step explanation:
35
Let
cos
(
2
∘
)
≈
0.9994
What is the the value of
x
, in degrees, for
sin
(
x
)
≈
0.9994
?
Answer:
can write it again soon as you can do it again
survey of a company's employees explored the relationship between employee status and support of a new workplace safety policy The results are displayed in the following two-way frequency table. Workplace Safety Policy For Against Total Part-Time
Employee 20 60 80 Full-Time Employee 100 20 120 Total 120 BO 200 used on the table above, which of the following statements are true? There are twice as many part-time employees against the workplace safety policy than full-time employees against the workplace safety policy IL There are more employees for the workplace safety policy than against the workplace safety policy There is an equal number of part-time employees and full-time employees.
Answer:
ll and lll
Step-by-step explanation:
Julie has $80,000 to invest. She invests part at 5%, one fourth this amount at 6%, and the balance 7%. Her total annual income from interest is $4,700. Find the amount invested at each rate.
Answer:
Julie invested $ 25,000 at 7%, $ 20,000 at 6%, and $ 35,000 at 5%.
Step-by-step explanation:
Given that Julie has $ 80,000 to invest, and she invests part at 5%, one fourth this amount at 6%, and the balance 7%, knowing that her total annual income from interest is $ 4,700, to find the amount invested at each rate se you must perform the following calculation:
80,000 / 4 = 20,000
20,000 x 0.06 = 1,200
4,700 - 1,200 = 3,500
60,000 x 0.07 + 0 x 0.05 = 4,200
50,000 x 0.07 + 10,000 x 0.05 = 4,000
40,000 x 0.07 + 20,000 x 0.05 = 3,800
30,000 x 0.07 + 20,000 x 0.05 = 3,600
25,000 x 0.07 + 35,000 x 0.05 = 3,500
Thus, Julie invested $ 25,000 at 7%, $ 20,000 at 6%, and $ 35,000 at 5%.
Determine which fraction is smallest given 21/64, 5/16, 11/32, 1,2
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DIVIDING EXPONETS
Answer:
[tex]-0.5n^{4}[/tex] or [tex]-\frac{1}{2} n^{4}[/tex]
Step-by-step explanation:
To simplify a dividing exponent, use the "Quotient of Powers" law: [tex]\frac{a^{m} }{a^{n} } = a^{m-n}[/tex]. In this situation, the equation would be: [tex]\frac{-9}{18} n^{6} -n^{2}[/tex] or [tex]-0.5n^{4}[/tex] (-0.5 is also [tex]-\frac{1}{2}[/tex]).
Hope it helps and is correct!
The school that Stefan goes to is selling tickets to a choral performance. On the first day of ticket sales the school sold 3 senior citizen tickets and 1 child ticket for a total of $38. The school took in $52 on the second day by selling 3 senior citizen tickets and 2 child tickets. Find the price of a senior citizen ticket and the price of a child ticket
Answer:
senior citizen tickets are $10 and child tickets are $8
Answer:
senior is 10 and child is 8
Step-by-step explanation:
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Whoever can answer this I will make a brainliest
Answer:
djchdjcycuchrivivurtiytvivytivi8fr cgdyhcd8w
Can someone help me with this answer thank you
Answer: bro cmon this is simple m8 but i will still help :D
Step-by-step explanation:35x3=105 and 28x5=140 the outfit couldve been 245 dollars in total!
what is the HCF prime factorization of 30 and 36
Answer:
We found the factors and prime factorization of 30 and 36. The biggest common factor number is the GCF number. So the greatest common factor 30 and 36 is 6.
Step-by-step explanation:
I dont understand the work my teacher gave me and I Have 45 pages to do
Answer:
just send them here , I will answer the ones I know .
Quadrilateral JKLM has vertices at J(0,0), K(0,6), L(9,12), and M(12,0). Find the vertices of the quadrilateral after a dilation with scale factor 2/3.
Answer choices
J'(0, 0), K'(0, 9), L'(27/2, 18), and M'(18, 0)
J'(0, 0), K'(0, 4), L'(6, 8), and M'(8, 0)
J'(0, 0), K'(0, −4), L'(−6, −4), and M'(−8, 0)
J'(2/3, 2/3), K'(2/3, 20/3), L'(9/3, 38/3), and M'(38/3, 2/3)
Answer:
The vertices of the quadrilateral after a dilation with scale factor [tex]\frac{2}{3}[/tex] are [tex]J'(x,y) = (0,0)[/tex], [tex]K'(x,y) = (0,4)[/tex], [tex]L'(x,y) = (6, 8)[/tex] and [tex]M'(x,y) = (8,0)[/tex].
Step-by-step explanation:
Let suppose that center of dilation is located at origin, that is [tex]O(x,y) = (0,0)[/tex]. Vectorially speaking, dilation is described by following expression:
[tex]D'(x,y) = O(x,y) + r\cdot [D(x,y)-O(x,y)][/tex] (1)
Where:
[tex]O(x,y)[/tex] - Center of dilation.
[tex]D(x,y)[/tex] - Original point.
[tex]D'(x,y)[/tex] - Dilated point.
[tex]r[/tex] - Dilation factor.
If we know that [tex]O(x,y) = (0,0)[/tex], [tex]r = \frac{2}{3}[/tex], [tex]J(x,y) = (0,0)[/tex], [tex]K(x,y) = (0,6)[/tex], [tex]L(x,y) = (9,12)[/tex] and [tex]M(x,y) = (12,0)[/tex], then the dilated points are, respectively:
[tex]J'(x,y) = O(x,y) + r\cdot [J(x,y)-O(x,y)][/tex]
[tex]J'(x,y) = (0,0) +\frac{2}{3}\cdot [(0,0)-(0,0)][/tex]
[tex]J'(x,y) = (0,0)[/tex]
[tex]K'(x,y) = O(x,y) + r\cdot [K(x,y)-O(x,y)][/tex]
[tex]K'(x,y) = (0,0)+\frac{2}{3}\cdot [(0,6)-(0,0)][/tex]
[tex]K'(x,y) = (0,4)[/tex]
[tex]L'(x,y) = O(x,y) +r\cdot [L(x,y)-O(x,y)][/tex]
[tex]L'(x,y) = (0,0) + \frac{2}{3}\cdot [(9,12)-(0,0)][/tex]
[tex]L'(x,y) = (6, 8)[/tex]
[tex]M'(x,y) = O(x,y) +r\cdot [M(x,y)-O(x,y)][/tex]
[tex]M'(x,y) = (0,0) +\frac{2}{3}\cdot [(12,0)-(0,0)][/tex]
[tex]M'(x,y) = (8,0)[/tex]
The vertices of the quadrilateral after a dilation with scale factor [tex]\frac{2}{3}[/tex] are [tex]J'(x,y) = (0,0)[/tex], [tex]K'(x,y) = (0,4)[/tex], [tex]L'(x,y) = (6, 8)[/tex] and [tex]M'(x,y) = (8,0)[/tex].
Option B will be the correct option.
Dilation of a point about the origin by a scale factor 'k',If a point (a, b) is dilated by a scale factor 'k' about the origin, coordinates of the image point will be,
(a, b) → (ka, kb)
Following the rule for dilation,
If a quadrilateral J(0, 0), K(0, 6), L(9, 12) and M(12, 0) is dilated by a scale factor [tex]\frac{2}{3}[/tex], coordinates of the image points will be,
[tex]J(0,0)\rightarrow J'(0, 0)[/tex]
[tex]K(0,4)\rightarrow K'(0, 4)[/tex]
[tex]L(9,12)\rightarrow L'(6,8)[/tex]
[tex]M(12,0)\rightarrow M'(8,0)[/tex]
Therefore, Option B will be the correct option.
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Someone help please!
X+3y=-7 5x+6y=-8
Step-by-step explanation:
I have used substitution method here to find the value of x and y.
The speed limit on a road is 45 mph what is the rate in miles per minute
The rate in miles per minute is 320
I REALLY NEED HELP!!! THIS IS DUE AT 12!!!
Jeremiah scored 32 points in yesterday’s basketball game. He made a total of 19 baskets.Some of the baskets were field goals (worth two points) and the rest were free throws (worth one point). Write and solve a system of equations to find the number of field goals and the number of free throws that Jeremiah made. Let x represent Field Goals and y represent Free Throws.
Answer:
x=16
y=3
Step-by-step explanation:
32÷2=16
19-16=3
x=16
y=3
Martha spent $12.35 at the local farmer's market. She bought 3 bundles of collards and paid $4.30 for some fruit. How much did each bundle of collards cost?
Answer:
12.35-4.30=8.05
8.05÷3= 2.68333333333333....
≈2.68
Helpppp?? I need help on this cause I just don’t wanna solve it
Answer:
3 and 3/5
Step-by-step explanation:
A wire is attached to the top of a tower and to a point on the ground that is 35 m from the base of the tower. If the wire makes a 65 degree angle with the ground, how long is the wire? Round your answer to the nearest tenth.
Answer:
83
Step-by-step explanation:
The length of the wire is 83meter.
Given that,
A wire is attached to the top of a tower and to a point on the ground that is 35 m from the base of the tower.
If the wire makes a 65-degree angle with the ground.
We have to determine,
How long is the wire?
According to the question,
The computation of the length of the wire is shown below:
Let, the length of the wire be x,
There is 35m from the base of the tower,
And, the angle with the ground is 65 degree
Therefore,
The length of the wire is given by,
[tex]cos65 = \dfrac{35}{x}\\\\[/tex]
Substitute the value of cos65 in the equation,
[tex]cos65 = \dfrac{35}{x}\\\\x = \dfrac{35}{cos65}\\\\x = \dfrac{35}{0.42}\\\\x = 83.33 \ meter[/tex]
Hence, The length of the wire is 83meter.
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5+5-66564+6367347646-4848
Answer:
6367276244 6367276244
6367276244 6367276244
Answer:
6367276244
Step-by-step explanation:
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Answer:
Its C trust me cuh
Step-by-step explanation:
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mr. russell questions:
1: false.
2: false.
3: true
4: false.
5: true.
the last question: D.
A rental car company offers a rental package for a mid-size car. The cost is comprised of a fixed \$ 40$40 administrative fee for the cleaning and maintenance of the car plus a rental cost of \$ 45$45 per day. Using xx for the number of days and yy for the total cost in dollars, construct a linear function to model the relationship between the number of days and the total cost of renting a mid-size car.
Answer:
y = 40 + 45x
Step-by-step explanation:
Fixed administrative fee for the cleaning and maintenance of the car = $40
rental cost = $45 per day
x = number of days
y = total cost in dollars
y = 40 + 45x
This shows the relationship between the number of days and the total cost of renting a mid-size car.