which is better 9.95 for 30oz of coffee or 3.50 for 12oz of coffee

Answer:

64

Step-by-step explanation:

Given :

h α 1 / sqrtk

h = k/sqrt(d)

Obtain the value of k, when. d = 4 and h = 20

20 = k / sqrt(4)

20 = k / 2

20 * 2 = k

k = 40

Therefore, the value of d when h = 5

h = k/sqrt(d)

5 = 40 / sqrt(d)

Square both sides

25 = 1600/d

25d = 1600

d = 1600 / 25

d = 64

d = 64

Answer:

x=9

Step-by-step explanation:

these are vertical angles, so they equal eachother!

12x-3=105

move three to the other side of the equals sign

12x=108

divide both sides by 108

x=9

Answer: x=9

Step-by-step explanation:

These angles are equal, so you can set 105 equal to 12x-3. Add 3 and divide by 12 to get x=9.

Answer:

100/ 651 , or 0.15361

Step-by-step explanation:

this took so long

Answer:

0.15360983102

.......

Answer: 7

Step-by-step explanation: because 45 divided by 6 is 7.5

Answer:

p,q,r

Step-by-step explanation:

Answer:   512m³

Step-by-step explanation:

v = whl

The volume for left building:

v = w x h x l

v = 4 x 10 x 8

v = 320 m³

The volume for right and lower building:

v = w x h x l

v = 8 x 4 x 6

v = 192 m³

The total volume for the entire Charter School is: 320m³ + 192m³ = 512m³

Given:

The pair of expressions in the options.

To find:

The pairs which show a pair of equivalent expressions.

Solution:

Property of exponent:

[tex](\sqrt[n]{x})^m=x^{\frac{m}{n}}[/tex]

In option A,

[tex](\sqrt[4]{81})^5=81^{\frac{5}{4}}[/tex]

So, option A is correct.

In option B,

[tex]6^{\frac{7}{2}}=(\sqrt[2]{6})^7[/tex]

[tex]6^{\frac{7}{2}}=(\sqrt{6})^7[/tex]

So, option B is correct.

In option C,

[tex]5^{\frac{2}{3}}=(\sqrt[3]{5})^2[/tex]

[tex]5^{\frac{2}{3}}\neq (\sqrt{5})^3[/tex]

So, option C is incorrect.

In option D,

[tex]7^{\frac{5}{7}}=(\sqrt[7]{7})^5[/tex]

[tex]7^{\frac{5}{7}}\neq (\sqrt{7})^5[/tex]

So, option D is incorrect.

Answer:it’s a and b

Step-by-step explanation:

did the test

Answer:

The surface area of the rectangular prism is 748 ft2.

Step-by-step explanation:

formula for surface area: A=2(wl+hl+hw)

A=2(wl+hl+hw)=2(5x16+14x16+14x5)=748

Answer:

748 ft²

Step-by-step explanation:

For the surface area, you need to add up the area of all sides, six in this example, but it can be simplified into three by multiplying some of them by two as its presumed a rectangle

x1 = 5*14*2 = 140

x2 = 16*14*2 = 448

x3 =16*5*2 = 160

You find the sum of these; 140 + 160 + 448 = 300 + 448 = 748

Answer:

-8y° -7y

Step-by-step explanation:

Like terms:

13y-11y-9y= -7y

-8y°= -8y°

Simplified Expression:

-8y°-7y

Answer:

8

Step-by-step explanation:

Given that

19 + 7 divided by 2 - 5

So if we solve this we have to apply proper brackets

= (19 + 7) ÷ 2 - 5

= 26 ÷ 2 - 5

= 13 - 5

= 8

After solving this the answer is 8

Answer:

3 ft

Step-by-step explanation:

Because 6 divided by 2 equals 3. And two 1s equal 2.

Answer:3ft

Step-by-step explanation:6/2

Answer:

the graph on the bottom left

Step-by-step explanation:

outliers are points that are away from the cluster of points in the bottom left graph all of the points are grouped up therefor the bottom left graph is the correct answer

Answer:

Slope = -1/2

Y-Intercept = 2

Equation: Y=-1/2x+2

Step-by-step explanation:

Graph goes 2 units up at y=2, that's your y-intercept. From there, plot your second point by moving 1 down and 2 to the right from the y-intercept, landing on the point (2,1) to get your slope, written as -1/2.

Answer:

1 simple

Step-by-step explanation:

Answer:

im not sure but i think its e,c,f

Step-by-step explanation:

Answer:

55 °

Here's the way i got my answer :

Complementary angles are two angles that have a sum of 90° ,therefore 35° + X = 90°

X=55° .

to get ∠DBF

180° - 90° = 90 °

to get ∠EBF

∠CBD + ∠DBE + ∠EBF = 180°

35° + 90° + ∠EBF = 180°

∠EBF = 55°

Answer:

x = 15

Step-by-step explanation:

use pythagorean theorem (a^2+b^2=c^2)

you have c^2 and one of the sides so you just reverse the equation and do

17^2-8^2

and that gives you 225

when you [tex]\sqrt{225}[/tex], you get 15 as your answer

Answer:

Trevor is right

Step-by-step explanation:

The solution of system of equations are [tex](4,0)[/tex]

Therefore, Trevor conclusion is true.

Given system of equations;

                 [tex]x- 2y = 4\\\\y=4-x[/tex]

Substitute value of y from equation (2) in equation (1).

           [tex]x-2(4-x)=4\\\\x-8+2x=4\\\\3x=12\\\\\\x=12/3=4[/tex]

Substitute value of x in second equation.

 [tex]y=4-x=4-4=0[/tex]

Hence, the solution of system of equations are [tex](4,0)[/tex]

Learn more about the system of equations here:

https://brainly.com/question/13729904

The characteristics of the sinusoidal function can be found from the given

graph of the function.

The sinusoidal function is the sine function that has the following general equation;

a = The amplitude

b = Angular frequency

h = The horizontal shift

k = The vertical shift

The minimum value of the sinusoidal function.

From the given graph, we have;

The amplitude, a = 2

The period, T = 10 = 2·π/b

b = π/5

The vertical shift, k = 3

The horizontal shift = 0

The minimum value of the function = k - a

Therefore;

Learn more about sinusoidal functions here:

https://brainly.com/question/6666829

Answer:

[tex]\displaystyle 1[/tex]

Step-by-step explanation:

[tex]\displaystyle \boxed{y = 2cos\:(\frac{\pi}{5}x - \frac{\pi}{2}) + 3} \\ \\ y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 3 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{2\frac{1}{2}} \hookrightarrow \frac{\frac{\pi}{2}}{\frac{\pi}{5}} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{10} \hookrightarrow \frac{2}{\frac{\pi}{5}}\pi \\ Amplitude \hookrightarrow 2[/tex]

OR

[tex]\displaystyle \boxed{y = 2sin\:\frac{\pi}{5}x + 3} \\ \\ y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 3 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{10} \hookrightarrow \frac{2}{\frac{\pi}{5}}\pi \\ Amplitude \hookrightarrow 2[/tex]

You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the sine graph, if you plan on writing your equation as a function of cosine, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = 2cos\:\frac{\pi}{5}x + 3,[/tex] in which you need to replase "sine" with "cosine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the sine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the cosine graph [photograph on the right] is shifted [tex]\displaystyle 2\frac{1}{2}\:units[/tex]to the left, which means that in order to match the sine graph [photograph on the left], we need to shift the graph FORWARD [tex]\displaystyle 2\frac{1}{2}\:units,[/tex]which means the C-term will be positive, and by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{2\frac{1}{2}} = \frac{\frac{\pi}{2}}{\frac{\pi}{5}}.[/tex]So, the cosine graph of the sine graph, accourding to the horisontal shift, is [tex]\displaystyle y = 2cos\:(\frac{\pi}{5}x - \frac{\pi}{2}) + 3.[/tex]Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph approximately hits [tex]\displaystyle [-10, 3],[/tex]from there to the y-intercept of [tex]\displaystyle [0, 3],[/tex]they are obviously approximately [tex]\displaystyle 10\:units[/tex]apart, telling you that the period of the graph is [tex]\displaystyle 10.[/tex]Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 3,[/tex]in which each crest is extended two units beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

**Now, the minimum value is the lowest possible value the graph touches, and in this case, the graph's lowest peaks cycle around [tex]\displaystyle y = 1,[/tex]therefore the minimum of his sinusoidal function is [tex]\displaystyle 1.[/tex]

I am delighted to assist you at any time.

Answer:

nudaw HAHABSASASNA

Step-by-step explanation:[tex]x^{2} g[/tex]

hggggguuuuugs berte bhu jira yuwa

Answer:

118

Step-by-step explanation:

a triangle is 180 degrease and two sides that are equal to each other which means the angles across from them have the same thing.

so. 180-31-31=118

Answer: x = -7

Step-by-step explanation:

7 (x + 4) = -21

7x + 28 = -21

Subtract 28 from both sides

7x = -49

Divide both sides by 7

x = -7

Answer:

x = -7

Step-by-step explanation:

first distribute he 7 to get 7x + 28 = -21

then subtract 28 from both sides to get 7x = -49

lastly divide 7 from both sides to get x = -7

your answer would be 33.

step 1

2(+14)−1(2−5)

2+28−1(2−5)

step 2 distribute

2+28−1(2−5)

2+28−2+5

step 3 then add the numbers

2+28−2+5

2+33−2

combine

2+33−2

ANSWER IS

33

Answer:

d

Step-by-step explanation:

Answer:

Answer below

Step-by-step explanation:

right

acute

i believe this is correct :)

Answer:

there are not solutions because they never cross each other

Answer:

The points that fits the equation would be option D.