Which of the following equations is equivalent to 4x+2y=12
A. 2x+2y=6
B. 8x+2y=24
C. 2x+y=6
D. 4x+4y=24

A

Step-by-step explanation:

Answer:

the second graph

Step-by-step explanation:

Step-by-step explanation:

The equation of the line is y = 279.

sale price of the television is c

Answer:

140

Step-by-step explanation:

By inscribed angles, arc FPI = 2<FLI = 2*110 = 220. Since the entire arc of a circle is 360, we know that arc FLI + arc FPI = 360. Solving, we get arc FLI = 360 - 220 = 140.

I hope this helps!

Answer:

Slope=2

y intercept= Length of spring without any weight

15 lbs= 38 inches

Step-by-step explanation:

slope=

18-12/5-2= 6/3 = 2

y intercept= 0=x and x=amount of weight

equation= 2x+8=y

2(15)+8=38

Answer:

You need to insert different x values and plot the point. So let's say x=1 the answer would be 10 and for 2 it would be 17

Answer:

So the slope is rise over run. You need the y intercept and the slope to write an equation. To find the y intercept, use the formula : 0=4(slope)*3+b and you get 0=12+b then you subtract twelve from both sides, getting b=-12. Thats your y intercept. So your equation will be y=4x-12

Answer:

The probability that five of the eight students exhibit an higher IQ than the median of the general population is 0.21875

Step-by-step explanation:

The given parameters are;

The number of students in the sample, n = 8

The number of the students, x, that exhibit higher IQ's than the median = 5

The probability of obtaining the given result by chance is given as follows;

P(x) = n!/((n - x)!x!) × pˣ × qⁿ⁻ˣ

The probability that a student exhibit higher IQ's than the median = 0.5 = p

Similarly, we have, the probability that a student exhibit lower IQ's than the median = 0.5 = q

Substituting the known values, gives;

P(5) = (8!/((8 - 5)!×5!)) × 0.5^(5) × 0.5^(8 - 5) = 0.21875

Therefor, the probability that 5 of the 8 students exhibit an higher IQ than the median of the general population, P(5) = 0.21875.

Answer:

[tex]\dfrac{1 - 6 \ln y}{2}[/tex]

Step-by-step explanation:

[tex] \ln \dfrac{\sqrt{e}}{y^3} = [/tex]

[tex] = \ln \dfrac{e^\frac{1}{2}}{y^3} [/tex]

[tex] = \ln e^\frac{1}{2} - \ln y^3 [/tex]

[tex]= \dfrac{1}{2} \ln e - 3 \ln y[/tex]

[tex]= \dfrac{1}{2} - 3 \ln y[/tex]

[tex]= \dfrac{1 - 6 \ln y}{2}[/tex]

The given logarithmic expression can be written as [tex]\frac{1-6ln\ y}{2}[/tex]

Given that,

Based on the above information, the calculation is as follows:

[tex]= ln \frac{\sqrt{e} }{y^3}\\\\= ln \frac{e^{1/2}}{y^3} \\\\= ln \e^{1/2} - lny3\\\\= \frac{1}{2}ln e - 3 ln y\\\\= \frac{1}{2} - 3 ln \ y \\\\= \frac{1- 6ln \y}{2}[/tex]

Therefore we can conclude that the given logarithmic expression can be written as [tex]\frac{1-6ln\ y}{2}[/tex]

Learn more: brainly.com/question/24169758

Answer:

The shadow of the pole is 1.2 feet long

Step-by-step explanation:

A little girl standing next to a telephone pole at 10 AM.

From the above question

Height of the girl = 4'6" tall = 4 feet and 6 inches tall

We convert to feet

= 12 inches = 1 foot

6 inches = x

Cross Multiply

12 × x = 6 × 1

x = 6/12 = 1/2 = 0.5 feet

Hence, the total height of the girl =

4 feet + 0.5 feet = 4.5 feet

The height of the telephone pole = 40 feet high.

The shadow of the telephone pole

= 8' 32 foot shadow

= 8 feet, 32 inches

We convert the inches to feet

12 inches = 1 foot

32 inches = x

Cross Multiply

12 × x = 32 × 1

x = 32/12 = 8/3 = 2.67 feet

Total length of the pole = 8 feet+ 2.67 feet = 10.67 feet

how long is a little girl shadow?

This is calculated using proportion

Shadow/Height

Shadow of the girl = x

Hence:

Shadow of the girl/Height of the girl = Shadow of the pole/Height of the pole

x/4.5 feet = 10.67 feet/40 feet

Cross Multiply

40 × x= 4.5 × 10.67

x = 4.5 × 10.67/40

x = 1.200375 feet

Approximately = 1.2 feet

Hence, the shadow of the pole is 1.2 feet long

Answer:

[tex]y=\frac{5}{3}x+\frac{10}{3}[/tex]

Step-by-step explanation:

Firstly we rewrite the equation that is parallel to the line we need because parallel lines have the same slope by the rule

[tex]m_1=m_2[/tex]

so we rewrite the equation in slope-intercept form:

[tex]5x-3y=17\\-3y=-5x+17\\y=\frac{-5x+17}{-3}\\\\y=\frac{-5x}{-3}+\frac{17}{-3} \\\\y=\frac{5}{3}x-\frac{17}{3}[/tex]

and now we compare it with our slope-intercept form equation:

[tex]y=mx+b[/tex]

the coefficient of x which is m is the slope and since parallel lines have equal slopes the line that we need would also have the same slope which is 5/3.

now the next step is the line that we need passes through the point (-2,0) so it means that it should satisfy that specific point so we insert that point into our slope-intercept form and insert the slope which is 5/3 which is m.

[tex]y=mx+b\\y=\frac{5}{3}x+b\\\\0=\frac{5}{3}(-2)+b\\\\0=\frac{-10}{3}+b\\\\b=\frac{10}{3}\\[/tex]

now we know that the y-intercept(b) of the line we need is 10/3 and slope(m) is 5/3 insert these values into our slope-intercept form:

[tex]y=mx+b\\y=\frac{5}{3}x+\frac{10}{3} \\[/tex]

so this is our given line.

Answer:

4:3 or 4 to 3

Step-by-step explanation:

Answer:

63/88

any more help just ask

Answer:

c

Step-by-step explanation:

bc it is

Answer:

The maximum height it reaches is 20 meters

The time taken by it to reach the height is 2 seconds

Step-by-step explanation:

The formula of the height of the stone is h = u t - [tex]\frac{1}{2}[/tex] g t², where

∵ A stone is thrown vertically upwards with an initial velocity of 20 m/s

∴ u = 20 m/s

∵ g = 10 m/s²

→ Substitute them in the equation above

∴ h(t) = 20t - [tex]\frac{1}{2}[/tex] (10) t²

∴ h(t) = 20t - 5t²

→ Arrange the terms of the right side according to the greatest power of t

∴ h(t) = -5t² + 20t

To find the maximum height and the time of it find the vertex of the quadratic function (m, k), where m = [tex]\frac{-b}{2a}[/tex] and k is the value of h at t = m, a is the coefficient of t² and b is the coefficient of t

∵ The coefficient of t² is -5

∴ a = -5

∵ The coefficient of t is 20

∴ b = 20

→ Use them to find h

∵ m = [tex]\frac{-20}{2(-5)}[/tex] = [tex]\frac{-20}{-10}[/tex] = h

∴ m = 2

→ Substitute it in the equation above to find k

∵ h(m) = k

∵ k = -5(2)² + 20(2)

∴ k = -5(4) + 40

∴ k = -20 + 40

∴ k = 20

∴ The coordinate of the vertex of the function are (2, 20)

→ m represents the time of the maximum height and k represents

  the maximum height

∴ The maximum height it reaches is 20 meters

∴ The time taken by it to reach the height is 2 seconds

Answer:

D.$79.89

Step-by-step explanation:

Cost of one yard of fabric = $6.99

Length of fabric bought = 8 yards

Cost of one bag of polyester filling = $7.99

Number of bags of polyester filling bought = 3

Total cost of fabric = [tex]6.99\times 8=\$55.92[/tex]

Total cost of polyester filling = [tex]7.99\times 3=\$23.97[/tex]

Total cost of materials bought = Total cost of fabric + Total cost of polyester filling

[tex]=55.92+23.97=\$79.89[/tex]

Total cost of materials bought is [tex]\$79.89[/tex].

Answer:

I’m guessing D

Step-by-step explanation:

As the perpendicular would be -4 the negative reciprocal. I just worked out the whole equation including the point it passes.

Answer:

-6

Step-by-step explanation:

Answer:

the length of the diagonal BD is 8 cm

Step-by-step explanation:

The computation of the length of diagonal BD is as follows

Here the trapezoid diagonals divides each other in an equivalent ratio

So, equation would be

AO ÷ OC = OB ÷ OD

Now put there values to the above equation

3 ÷ 1 = 6 ÷ OD

3OD = 6

Now divided it by 3 in both the sides

OD = 2

Now the BD would be

= BO + OD

= 6 +  2

= 8 cm

hence, the length of the diagonal BD is 8 cm

Answer:

slope = - [tex]\frac{3}{11}[/tex]

Step-by-step explanation:

Calculate the slope m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (- 5, 7) and (x₂, y₂ ) = (6, 4)

m = [tex]\frac{4-7}{6+5}[/tex] = [tex]\frac{-3}{11}[/tex] = - [tex]\frac{3}{11}[/tex]

Answer:

A. Increasing

Step-by-step explanation:

According to the graph, we see that as the x-values increase, the y-values also increase. Therefore, the entire graph is increasing.

Answer/Step-by-step explanation:

5. 21x + 4 = 22x - 2 (corresponding angles)

Collect like terms

21x - 22x = -4 - 2

-x = -6

divide both sides by -1

x = 6

6. (x + 72) + (x + 132) = 180 (linear pair)

x + 72 + x + 132 = 180

Add like terms

2x + 204 = 180

2x = 180 - 204

2x = -24

x = -12

7. 90 = 22x + 2 (vertical angles)

90 - 2 = 22x

88 = 22x

Divide both sides by 22

4 = x

x = 4

8. 12x + 10 = 13x + 3 (vertical angles)

Collect like terms

12x - 13x = -10 + 3

-x = -7

Divide both sides by -1

x = 7

9. 17x = 16x + 5 (alternate exterior angles)

17x - 16x = 5

x = 5

✔️17x

Plug in the value of x

17(5) = 85°

10. 21x - 6 = 20x (corresponding angles)

Add like terms

21x - 20x = 6

x = 6

✔️20x

20(6) = 120°

Answer:

[tex]\sqrt[3]{2y^3} * 7\sqrt{18y} = 21(y^{\frac{3}{2}})(2^{\frac{5}{6}})[/tex]

Step-by-step explanation:

The question is poorly formatted.

Given

[tex]\sqrt[3]{2y^3} * 7\sqrt{18y}[/tex]

Required

Derive an equivalent expression

[tex]\sqrt[3]{2y^3} * 7\sqrt{18y}[/tex]

Express 18 as 9 * 2

[tex]\sqrt[3]{2y^3} * 7\sqrt{9 * 2y}[/tex]

Split the expression as follows:

[tex]\sqrt[3]{2y^3} * 7\sqrt{9} * \sqrt{2y}[/tex]

Take positive square root of 9

[tex]\sqrt[3]{2y^3} * 7*3 * \sqrt{2y}[/tex]

[tex]\sqrt[3]{2y^3} * 21 * \sqrt{2y}[/tex]

[tex]21*\sqrt[3]{2y^3} * \sqrt{2y}[/tex]

The cube root can be rewritten to give:

[tex]21*\sqrt[3]{2}*\sqrt[3]{y^3} * \sqrt{2y}[/tex]

[tex]\sqrt[3]{y^3} = y^{3*\frac{1}{3}} = y[/tex]

So, we have:

[tex]21*\sqrt[3]{2} * y * \sqrt{2y}[/tex]

Rewrite as:

[tex]21y *\sqrt[3]{2} * \sqrt{2y}[/tex]

Split [tex]\sqrt{2y[/tex]

[tex]21y *\sqrt[3]{2} * \sqrt{2} * \sqrt{y}[/tex]

Collect Like Terms

[tex]21y*\sqrt{y} *\sqrt[3]{2} * \sqrt{2}[/tex]

Represent in index form

[tex]21y*y^{\frac{1}{2}} *2^\frac{1}{3} *2^\frac{1}{2}[/tex]

Apply law of indices

[tex]21*y^{1+\frac{1}{2}} *2^{\frac{1}{3} +\frac{1}{2} }[/tex]

[tex]21*y^{\frac{2+1}{2}} *2^{\frac{2+3}{6}}[/tex]

[tex]21*y^{\frac{3}{2}} *2^{\frac{5}{6}}[/tex]

[tex]21(y^{\frac{3}{2}})(2^{\frac{5}{6}})[/tex]

Hence:

[tex]\sqrt[3]{2y^3} * 7\sqrt{18y} = 21(y^{\frac{3}{2}})(2^{\frac{5}{6}})[/tex]

Answer:

e. 2

Step-by-step explanation:

Answer:

[tex]-8x^{2}+3x-6[/tex]

Step-by-step explanation:

The image below shows step-by-step on how to simplify the expression.

Hope this helps! :)

Answer:

Wind speed = 30 mph

Plane speed = 270 mph

Step-by-step explanation:

Given that :

Distance = 600 miles

Let speed of airplane = a ; speed of wind = b

Net speed ; with wind = a + b

Net speed against wind = a - b

Time taken with wind = 2 hours

Time taken against wind = 2.5 hours

Recall :

Speed = distance / time ; distance = speed * time

(a + b) * 2 = (a - b) * 2.5

2a + 2b = 600

a + b = 300 - - - (1)

a = 300 - b

2.5a - 2.5b = 600

a - b = 240 - - - (2)

300 - b - b = 240

300 - 2b = 240

-2b = - 60

b = 30

a = 300 - 30

a = 270

Wind speed = 30 mph

Plane speed = 270 mph

Answer:

is A B and D

Step-by-step explanation:

x= 6.32

y= 12

z= 18.97

I got my answer by; using the MCF and multiplying to see how many times 6/2 will go into x,y,z!

Hope this helps:)!

Answer:

x= 6.32

y= 12

z= 18.97

Answer:

72

Step-by-step explanation:

Based on the table, the left and the right side have a pattern. When 3 is added to the left side, the right side is multiplied by 6. Since 12 multiplied by 6 is 72, the missing number is 72.

Answer:

The scale factor is 18 to 1 for the painting

Step-by-step explanation:

Here we want to get the scale factor of the original to what is reproduced

Let us have same units first

Mathematically;

1 foot = 12 inches

3 feet = 36 inches

2 feet = 24 inches

So 36 to 2 and 24 to 1 1/3

That will be ratio 36/2 = 18 to 1

same as 25 divided by 1 1/3 = 18 to 1