Which of the following inequalities matches the graph?
Ox=-7
Oxs-7
Oys-7
Oyz-7

The exponential equation is [tex]y = \frac23(3)^{-x+0.74} + 2[/tex]

An exponential function is represented as:

[tex]y = b^x[/tex]

The base is 3.

So, we have:

[tex]y = 3^x[/tex]

It is stretched vertically by 2/3.

So, we have:

[tex]y = \frac23(3)^x[/tex]

When reflected over the y-axis, we have:

[tex]y = \frac23(3)^{-x}[/tex]

An asymptote of y = 2, makes the function becomes

[tex]y = \frac23(3)^{-x} + 2[/tex]

Lastly, it passes through the point (0, 3.5).

So, we have:

[tex]y = \frac23(3)^{-x+h} + 2[/tex]

This gives

[tex]3.5 = \frac23(3)^{-0+h} + 2[/tex]

[tex]3.5 = \frac23(3)^{h} + 2[/tex]

Subtract 2 from both sides

[tex]1.5 = \frac23(3)^{h}[/tex]

Multiply by 3/2

[tex]2.25 = (3)^{h}[/tex]

Take the logarithm of both sides

log(2.25) = h * log(3)

Solve for h

h = 0.74

Substitute h = 0.74 in [tex]y = \frac23(3)^{-x+h} + 2[/tex]

[tex]y = \frac23(3)^{-x+0.74} + 2[/tex]

Hence, the exponential equation is [tex]y = \frac23(3)^{-x+0.74} + 2[/tex]

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The point has a real part of 0 and an imaginary part of 18, and thus corresponds to the point (0,18) in the complex plane.

Answer:

51

Step-by-step explanation:

Let c be the number of child tickets sold.

Let a be the number of adult tickets sold.

From the information given from the question, we can deduce:

6.10c + 9.70a = 1074.20 - Equation 1

c + a = 146 - Equation 2

From here, we can use the substitution method in solving simultaneous equations to find a and c. We will use Equation 2 as the base.

c = 146 - a - Equation 2A

We will then substitute equation 2A into Equation 1 to find a.

6.10(146-a) + 9.70a = 1074.20

890.6 - 6.10a + 9.70a = 1074.20

890.6 + 3.6a = 1074.20

3.6a = 1074.20 - 890.6

3.6a = 183.6

a = [tex]\frac{183.6}{3.6}[/tex]

a = 51

Therefore we know that 51  adult tickets were sold that day.

After that you can substitute a into equation 2 to find c.

The time taken to the closest minutes for the pie to cool to 80∘F is 123 minutes

T(t) = 68e^−0.0174t + 72

80 = 68e^−0.0174t + 72

80 - 72 = 68e^−0.0174t

8 = 68e^−0.0174t

e^−0.0174t = 8/68

e^−0.0174t = 0.11764705882352

ln e (−0.0174t) = ln (0.11764705882352)

1 × −0.0174t = -2.1400661634962708

-0.0174t = -2.1400661634962708

t = -2.1400661634962708 / -0.0174

t = 122.9923

Approximately,

t = 123 minutes

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Answer:

iTS 6 2/3 OPTION 2.

Step-by-step explanation:

Because Area = L*B

SO L = A/b

L= 65/3 * 4/13(reciprocal and multiply)

L=20/3 = 6 2/3

Answer:

So answer is 6 2/3

because Look carefully

Area =length× width

length=Area÷ width

so

[tex]21 \frac{2}{3} \div 3 \frac{1}{4} = 6 \frac{2}{3} [/tex]

Answer:

y = 40

Step-by-step explanation:

y/8 = 5

———————————————————

Multiply both sides by 8:

8y/8 = 5 * 8

———————————————————

Simplify:

y = 40

Hope that helps! :)

Answer:

Y = 40

Step-by-step explanation:

Step 1:

y/8 = 5

Bring 8 to the right side changing its arithmetic sign to multiply.

Step 2:

y = 5 x 8

Now multiply 5 by 8 to get the answer.

Step 3:

y = 40

Therefore, y is equal to 40.

The coordinates of A exist (11, 0).

Let, the point A (-5, -2) exists reflected over the line y = -1, and then stand reflected over the line x = 3.

The distance between the y value exists -1 - (-2)= 1

We move 1 unit beyond the line y = -1

After reflection over the line y = -1 the coordinates of A becomes (-5, 1-1) is (-5, 0)

It exists reflected over the line x = 3

The distance between -5 and 3 exists 3 - (-5) = 8

We move 8 units out from the line x = 3

The Point (-5, 0) becomes (3 + 8, 0) exists (11, 0).

Therefore, the coordinates of A exist (11, 0).

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The complete question:

The point A (-5, -2) is reflected over the line y = -1, and then is reflected over the line x = 3. What are the coordinates of A.

[tex]\begin{array}{c|c|c|c} p & q & \neg q & p \land \neg q \\ T & T & F & F \\ T & F & T & T \\ F & T & F & F \\ F & F & T & F \end{array}[/tex]

[tex]\begin{array}{c|c|c|c} t & s & \neg t & \neg t \implies s \\ T & T & F & T \\ T & F & F & T \\ F & T & T & T \\ F & F & T & F \end{array}[/tex]

[tex]\begin{array}{c|c|c}p\land \neg q & \neg t \implies s & (p \land \neg q) \implies (\neg t \implies s) \\T & T & T \\ T & F & F \\ F & T & T \\ F & F & T \end{array}[/tex]

The given logical statement is false when [tex]p\land\neg q[/tex] and [tex]\neg t\implies s[/tex] are true and false, respectively.

Answer:

Exact form: 7/143

Decimal form: /0.048951

Answer:

[tex]x=\frac{7}{143}[/tex]

Step-by-step explanation:

Simplify the right side of the equation. [tex]3x+21=432x[/tex]. Subtract 21 from both sides of the equation. [tex]3x=432x-21[/tex]. Subtract 432x from both sides of the equation, [tex]-429x=-21[/tex]. The negative signs cancel out to get [tex]429x=21[/tex]. Divide both sides but 429 to get [tex]x=\frac{21}{429}[/tex].  Reduce to get [tex]x=\frac{7}{143}[/tex].

The total interest on the mortgage loan  is $219,249.60

What is a mortgage loan?

It is a loan taken in order to purchase a property that requires periodic repayments such as monthly repayment since most mortgages are repaid monthly.

Our first task is to determine the monthly repayment using the present value formula of an ordinary annuity because the monthly payment becomes due at the end of each month.

PV=monthly repayment*(1-(1+r)^-N/r

PV=loan amount=$210,000

monthly repayment=unknown(assume it is X)

r=monthly interest rate=5.5%/12=0.00458333333333333

N=number of monthly payments in 30 years=30*12=360

$210,000=X*(1-(1+0.00458333333333333)^-360/0.00458333333333333

$210,000=X*(1-(1.00458333333333333)^-360/0.00458333333333333

$210,000=X*(1-0.19277525234572900)/0.00458333333333333

$210,000=X*0.80722474765427100/0.00458333333333333

$210,000=X*176.12176312456800000

X=$210,000/176.12176312456800000

X=monthly payment=$1,192.36

total repayments(360 months)=$1,192.36*360

total repayments(360 months)=$429,249.60

Total interest=total repayments(360 months)-loan amount

Total interest=$429,249.60-$210,000

Total interest=$219,249.60

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Answer:

D. g(x) is a reflection of f(x) over the x-axis.

Step-by-step explanation:

So when you have the equation: [tex]-2x^2[/tex] it's just negating the value of f(x), which is [tex]2x^2[/tex] and since f(x) represents the y-value, you're negating the y-value and the x-value is unchanged. So each point on f(x) was originally: (x, f(x)) and now it's (x, -f(x)). Since the y-value is changing, it's going to be reflecting across the x-axis. So g(x) is a reflection of f(x) over the x-axis.

The insurance cost for the second year from the information given will be $476.

The insurance cost for the second year will be:

= $14000 × 0.034

= $476

Therefore, the insurance cost for the second year will be $476

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The insurance cost for the second year from the information given will be $476.

How to calculate the insurance cost?

The insurance cost for the second year will be:

= $14000 × 0.034

= $476

Therefore, the insurance cost for the second year will be $476

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Answer:

(12 + n/3) = 2n + 1

Step-by-step explanation:

(12 + n/3) = 2n + 1

36 + n = 6n + 3

33 = 5n

n = 33/5

Answer:

the area would be 176.7

Step-by-step explanation:

You know the area of a circle is A = pi×r^2, so you need the radius.

You know C = 2pi×r, so r = C/(2pi)

r = 15pi / 2pi = 7.5

A = pi(7.5)^2 = 56.25pi ~ 176.715 square inches.

The area of the circle is about 176.7 square inches.

The radius of the circle is 7.5 inches. Therefore, the area of the circle will be 56.25π square inches.

Let r be the radius of the circle. Then the area of the circle will be given as,

A = πr² square units

The circumference of the circle will be given as,

C = 2πr units

The circumference of a circle is 15π inches. Then the radius of the circle is calculated as,

15π = 2πr

r = 7.5 inches

The area of the circle is calculated as,

A = π x 7.5²

A = 56.25π square inches

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The critical values are 0.622, 0.707, 0.789 and 0.834

The sample size is given as:

n = 8

Calculate the degrees of freedom using

df = n - 2

So, we have:

df = 8 - 2

df = 6

Using the table of values of critical values, we have:

Critical values = 0.622, 0.707, 0.789 and 0.834

By comparing the critical values and the linear correlation coefficient, we can conclude that there is no significant linear correlation.

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Okay, it's very simple, to solve this triangle you need to understand what the other angles are. We know that angle A is 90º, as it is represented as a square.

We now need to solve for angle B. angle B can be solved for by

Sin (x) = Opposite / Hypotenuse = 3 / 3√5 = 2.24ish
sin(x) = 2.24

x = [tex]sin^{-1}[/tex](2.24)

Use sin.

Answer:

Step-by-step explanation:

what's the answer

Answer:

[tex]y=-2.5x+8[/tex]

Step-by-step explanation:

Parallel lines have the same slope but different y-intercepts. So, first, transform the given equation into the slope-intercept form, [tex]y=mx+b[/tex].

[tex]5x+2y=6[/tex]

[tex]2y=-5x+6[/tex]

[tex]y=-\frac{5}{2} x+3[/tex]

Then, determine the equation of a line that has a slope of [tex]-\frac{5}{2}[/tex] and passes through (1, 5.5). Substitute all the known values and solve for b.

[tex]y=mx+b[/tex]

[tex]5.5 = -\frac{5}{2} *1+b[/tex]

[tex]5.5=-2.5+b[/tex]

[tex]b=8[/tex]

Therefore, the answer is [tex]y=-2.5x+8[/tex].

Linking each equation with its equivalent equation below:

Equivalent equation can be defined as an equation that has the same value with another equation.

Equivalent equation are not directly the same but can be transformed to look like each other.

In conclusion, The equivalent equations have been matched in the list above.

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The simplified expression of the given equation is  [tex]\frac{x^{2} + 4x + 6}{3x + 12}[/tex]

There are three basic steps for addition or subtraction of two fractions

The given expression :- [tex]\frac{x+6}{x+4} +\frac{x-3}{3}[/tex]

Taking LCM or making the denominators same we get,

= {3(x+6) + (x-3)(x+4)}/3(x+4)

= {3x + 18 + x² +x -12}/3(x+4)

={x² + 4x + 6}/3x + 12

= [tex]\frac{x^{2} + 4x + 6}{3x + 12}[/tex]

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Answer:

i believe its B

Step-by-step explanation:

Answer:

x = 14

Step-by-step explanation:

PMN forms a triangle and the sum of interior angles in a triangle is equal to 180 therefore we can use the following equation to find the value of x

32 + 64 + 6x = 180 add like terms

96 + 6x = 180 subtract 96 from both sides

6x = 84 divide both sides by 6

x = 14

[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]

[tex]\textsf{ \underline{\underline{Steps to solve the problem} }:}[/tex]

Area left for flowers = Area of flower garden - Area of bird bath.

Area of flower garden [ rectangle ] :

[tex]\qquad❖ \: \sf \:length \times width[/tex]

[tex]\qquad❖ \: \sf \:3 \times 2[/tex]

[tex]\qquad❖ \: \sf \: 6\: \: {m}^{2} [/tex]

Area of bird bath [ Circle ] :

[tex]\qquad❖ \: \sf \: \pi{r}^{2} [/tex]

[tex]\qquad❖ \: \sf \:3.14 \times ( \frac{1}{2} ) {}^{2} [/tex]

[tex]\qquad❖ \: \sf \:3.14 \times \frac{1}{4} [/tex]

[tex]\qquad❖ \: \sf \:0.785 \: \: m {}^{2} [/tex]

Area left for flowers :

[tex]\qquad❖ \: \sf \:6 - 0.785[/tex]

[tex]\qquad❖ \: \sf \:5.215 \: \: m {}^{2} [/tex]

[tex]\qquad❖ \: \sf \: \approx5.22 \: \: m {}^{2} [/tex]

[tex] \qquad \large \sf {Conclusion} : [/tex]

Answer: -5

Step-by-step explanation:

[tex]h(4)=\frac{1}{2}(4)-5=-3\\\\f(4)=3h(4)+4=3(-3)+4=-5[/tex]

250 grams of dragon alloy #11 and 750 grams of dragon alloy #35 is needed to make 1000 grams (1 kg) of Dragon alloy #17.

An equation is an expression that shows the relationship between two or more numbers and variables.

Let x represent the amount of alloy #11 and y represent the amount of alloy #15, hence:

(0.36x) + (y * 0.36) = 1(0.36)   (1)

Also:

0.28x + 0.64y = 1(0.55)    (2)

From both equations:

x = 0.25, y = 0.75

250 grams of dragon alloy #11 and 750 grams of dragon alloy #35 is needed to make 1000 grams (1 kg) of Dragon alloy #17.

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Using the z-distribution, the critical value for a confidence level of 90% is of Z = 1.65.

In this problem, we have a 90% confidence level, hence[tex]\alpha = 0.9[/tex], z is the value of Z that has a p-value of [tex]\frac{1+0.9}{2} = 0.95[/tex], so the critical value is z = 1.65.

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Answer:

Step-by-step explanation:

3 things of triangle are given.

2 sides + 1 angle

so, possible triangles = 1 ans

The value of x has a z-score of three is 20

The given parameters are:

Mean = 2

Standard deviation = 6

z = 3

The z-score is calculated as:

[tex]z = \frac{x - \mu}{\sigma}[/tex]

So, we have:

[tex]3 = \frac{x -2}{6}[/tex]

Multiply through by 6

18 = x - 2

Add 2 to both sides

x = 20

Hence, the value of x has a z-score of three is 20

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This is a simple harmonic motion exercise. The proof that the resultant force on the particle, at time t, is -225 Newtons is indicated below.

Note that we have been given the following:

Mass = 9kg,

Y = 45 N

ζ = 0.4 m

Then, Y/ζ  = 45N/0.4m

= 112.5 N/m

Hence, the spring constant =

K = 112. 5N/m

From this point we can resolve the Amplitude (A):
Amplitude is given as:

A = CB - PB

= 0.6 - 0.5

A = 0.1m

I) So because one spring is elongated by x and the other is compressed by x, Hence, the spring force is:

F[tex]_{net}[/tex] = - Kₓ - Kₓ

= - 2Kₓ
= -2 x 112.5 x* X

F[tex]_{net}[/tex] = -225x Newton ..........Lets call this expression 1

From equation 1 above, we know that

Ma = -225x

a = (-225/m) x

⇒ a ∝ - x,

Hence, the motion is is simple harmonic in nature.

The time period, T = 2 π√m/K[tex]_{eq}[/tex]

Where, K[tex]_{eq}[/tex] = 2K

= 2π√(9/225)

= 2π * 3/15

= 2(22/7) * (3/15)

= 1.25714285714; thus

T ≈ 1.26 secs...............lets call this expression 2

Note that Angular Frequency is = 2π/T

= 2π/1.26

= 4.9866550057

ω = 4.99 rad/s

Since the velocity at any point x from the mean position is given by

V = ω √ (A² - x²); hence

V = 4.99 √[(0.1)² - (0.05)²

V = 4.99 x 0.0866
V = 0.432134

V ≈ 0.432..........Lets call this expression 3

Along the x-axis, A simple harmonic motion can be depicted as:

x = A sin (ωt + Ф) ..........lets call this expression 4

where, Ф = Phase constant

At t = 0; x = A

A = A sinФ

⇒ SinФ = 1

⇒ Ф = π/2

Expression 4 becomes:

x = A sin (ωt + π/2)

Inserting the values of ω and A, we have

x = 0.1 sin (4.99t + π/2).........Lets call this expression 5a

or  x  = 0.1 cos (4.99t).......Lets call this expression 5b

Hence,

Sin(π/2  + Ф) = CosФ

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