Out of the following the statement has a reference angle of 30° and is in quadrant one or two- is true of the location of the terminal side of an angle 0 whose sine value is 1/2.
Since the reason behind this is that the sine value of 1/2 can be written as sin(30°), this means that the terminal side of the angle is located at 30°, which is either quadrant one or two. Quadrant one is the upper right quadrant of the coordinate plane, and quadrant two is the upper left quadrant.
The reference angle of an angle is the angle between the terminal side of the angle and the positive x-axis. In this case, the reference angle would be 30°. The reference angle of an angle is important because it is used to determine the quadrant in which the terminal side of the angle is used to determine the quadrant in which the terminal side of the angle is located. The reference angle must be less than 90° in order for the terminal side to be located in the first and second quadrants.
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If f(x)=x²-1, and
g(x) = x + 2, then
f(g(x)) = [? ]x² +[ ]x+[ ]
Enter
Answer:
Step-by-step explanation:
g(f(x)) = x2 -1 + 2 = x2 + 1
The red rectangle is the pre-image and the green rectangle is the image. What would be the coordinate of A" if the scale factor of 3 is used?
Pls show all your work!
Keep in mind I will immediately mark brainliest for the right answer!
The scale factor that has been used is 1/2
How to determine what scale factor has been used?From the question, we have the following parameters that can be used in our computation:
Side length on red = 6 units
Corresponding side length on green = 3 units
Given that the red rectangle is the pre-image and the green rectangle is the image
We have
Scale factor = Green/Red
So, we have
Scale factor = 3/6
Evaluate
Scale factor = 1/2
Hence, the scale factor is 1/2
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In a small town, there are two discount stores ABC and XYZ. They are the only
stores that handle the festival goods. The total number of customers is equally divided
between the two because the price and quality of goods sold are equal. Both stores
have good reputations in the community, and they render equally good customer
services. Assume that a gain of customer by ABC is a loss to XYZ and vice versa.
Both stores plan to run annual pre-Christmas sale during the first week of December.
Sales are advertised through the local newspaper, radio and television media. With the
aid of advertising the payoff for ABC store is constructed and given below.
XYZ store
News paper
radio
Television
News paper
30
40
-80
ABC radio
0
15
-20
Television
90
20
50
Find optimal strategies for both stores and the value of the game.
The value of the game is equal to -20 and is the least loss for ABC (which is the maximum gain for XYZ).
How did we come to our conclusion?The Minimax theorem, which states that in a two-person zero-sum game, each player minimizes the maximum loss conceivable, can be used to determine the best course of action for both stores.
ABC retailer:
If XYZ decides to use newspaper advertising, ABC could see a maximum loss of -80.
If XYZ chooses radio advertising, ABC might lose as much as -20.
If XYZ chooses television advertising, ABC will ultimately lose 50.
As a result, selecting the advertising medium that results in the lowest possible loss, which is radio advertising with a loss of -20.
XYZ retailer:
If ABC chooses newspaper advertising, XYZ might earn up to 40.
If ABC chooses radio advertising, XYZ might earn a maximum of 15.
If ABC chooses television advertising, XYZ might earn up to $20.
Therefore, by selecting the advertising medium that offers the highest possible gain, which is newspaper advertising with a gain of 40, XYZ optimizes the greatest gain.
Therefore, the value of the game is equal to -20 and is the least loss for ABC (which is the maximum gain for XYZ).
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Correct question:
In a small town, there are two discount stores ABC and XYZ. They are the only
stores that handle the festival goods. The total number of customers is equally divided
between the two because the price and quality of goods sold are equal. Both stores
have good reputations in the community, and they render equally good customer
services. Assume that a gain of customer by ABC is a loss to XYZ and vice versa.
Both stores plan to run annual pre-Christmas sale during the first week of December.
Sales are advertised through the local newspaper, radio and television media. With the
aid of advertising the payoff for ABC store is constructed and given below.
XYZ store
News paper radio Television
News paper 30 40 -80
ABC radio 0 15 -20
Television 90 20 50
Find optimal strategies for both stores and the value of the game.
On average, ABC can expect to earn 15 more customers than XYZ during the pre-Christmas sale.
What do you mean by graph?In mathematics and computer science, a graph is a collection of points (called vertices or nodes) that are connected by lines or curves (called edges). Graphs can be used to represent many different types of relationships or structures, including social networks, transportation networks, electrical circuits, and mathematical functions.
A graph is usually represented visually as a set of points on a plane or in space, with lines or curves connecting them. The points can represent any type of object or entity, such as cities, people, or data points, while the edges represent the connections or relationships between them. Edges can be directed (with arrows indicating a one-way relationship) or undirected (with no preferred direction).
To find the optimal strategies for both stores and the value of the game, we can use the graphical method of solving 2-player zero-sum games.
First, we can create a payoff matrix using the given information:
markdown
Copy code
| Newspaper | Radio | Television |
--------------------------------------------
ABC | 30 | 15 | 20 |
XYZ | 40 | -15 | 50 |
Note that the payoff for XYZ in the radio column is negative, indicating a loss.
Next, we can plot the payoffs on a graph, with ABC's strategies on the x-axis and XYZ's strategies on the y-axis. We can also draw a line at the minimum value of each column (the "minimax" line) and a line at the maximum value of each row (the "maximin" line).
The graph should look like this:
lua
Copy code
-15 15 20
|-------|--------|
30 | 30 | 15 |
| | |
|-------|--------|
50 | 40 | -15 |
| | |
|-------|--------|
40 50
To find the optimal strategies, we need to find the intersection of the minimax and maximin lines. In this case, the intersection is at the point (Radio, Television) = (15, 50), so the optimal strategies are for ABC to advertise on the radio and XYZ to advertise on television.
The value of the game is the payoff at the intersection of the minimax and maximin lines, which is 15. This means that on average, ABC can expect to earn 15 more customers than XYZ during the pre-Christmas sale.
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1. Find the 15th term in the sequence if a1= 3 and d= 4
2. Find Sn for the arithmetic series where a1= 5, an= 119, n= 20
3. Find Sn for the arithmetic series where a1= 12, d= 6, n= 15
4. Find the 6th term in the geometric sequence where a1= 2, a6= 64, r= 2
5. Find Sn for the geometric series where a1= 2 , r= 4, n= 6
an = 3 + (15 - 1) * 4 = 3 + 14 * 4
= 3 + 56
= 59
So, the 15th term in the sequence is 59.
2. To find the sum of an arithmetic series with first term a1, last term an, and number of terms n, we use the formula: Sn = n/2 * (a1 + an). Plugging in the values, we get:
Sn = 20/2 * (5 + 119)
= 20/2 * 124
= 620
So, the sum of the series is 620.
3. To find the sum of an arithmetic series with first term a1, common difference d, and number of terms n, we use the formula: Sn = n/2 * (2a1 + (n - 1)d). Plugging in the values, we get:
Sn = 15/2 * (2 * 12 + (15 - 1) * 6) = 15/2 * (24 + 84)
= 15/2 * 108
= 810
So, the sum of the series is 810.
4.To find the nth term in a geometric sequence with first term a1, common ratio r, and nth term an, we use the formula: an = a1 * r⁽ⁿ⁻¹⁾. Plugging in the values, we get:
64 = 2 * r⁽⁶⁻¹⁾
64 = 2 * r⁵
32 = r⁵
r = [tex]2^{(5^{(1/5)} )}[/tex]
So, the 6th term in the sequence is 64.
5. To find the sum of a finite geometric series with first term a1, common ratio r, and number of terms n, we use the formula: Sn = a1 * (1 - rⁿ) / (1 - r). Plugging in the values, we get:
Sn = 2 * (1 - 4⁶) / (1 - 4)
= 2 * (1 - 4096) / -3
= 2 * (-4095) / -3
= 2730
So, the sum of the series is 2730.
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a battleship simultaneously fires two shells toward two identical enemy ships. one shell hits ship a, which is close by, and the other hits ship b, which is farther away. the two shells are fired at the same speed. assume that air resistance is negligible and that the magnitude of the acceleration due to gravity is g .
The magnitude of the acceleration due to gravity would decrease with increasing height.
If the two shells were fired simultaneously with the same speed, their initial velocity would be the same. However, the shell that hits ship A, which is closer, would take less time to reach its target compared to the shell that hits ship B.
Since the magnitude of the acceleration due to gravity is constant, the vertical motion of the shells would be described by the following equation:
h = vi * t + (1/2) * g * [tex]t^2[/tex]
where h is the height of the shell, vi is the initial velocity, t is the time, and g is the acceleration due to gravity.
The horizontal motion of the shells would be described by the following equation:
d = vi * t
where d is the horizontal distance travelled by the shell.
By solving the above equations, we can determine the time taken by each shell to reach its target and therefore, the time difference between the two shells.
Note that this analysis assumes that air resistance is negligible and that the magnitude of the acceleration due to gravity is constant. In reality, air resistance would play a role in the motion of the shells, and the magnitude of the acceleration due to gravity would decrease with increasing height.
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how to solve this...
The measure of the angle that defines the orange arc is 144°.
How to find the measure of the angle?We know that if we have a circle of radius R, and there is an arc defined by an angle θ, then the area of that arc is given by:
A = (θ/360°)*pi*R^2
Where pi = 3.14
Here we know that the diameter is 10 miles, then the radius is:
R = 10mi/2 = 5mi
We can see that the shaded area is a = 10*pi mi²
Then we can write the equation:
(θ/360°)*pi*(5mi)^2 = 10*pi mi²
We can divide both sides by pi to get:
(θ/360°)*(5mi)^2 = 10 mi²
We can solve this for θ.
(θ/360°)*(5mi)^2 = 10 mi²
(θ/360°)25 mi² = 10 mi²
(θ/360°) = (10/25)
θ = (10/25)*360° = 144°
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If f(x) = ln(x), what is the transformation that occurs if g(x) = ln(x + 2)
The transformation from f(x) to g(x) is a horizontal shift to the right by 2 units to obtain the graph of g(x).
What do you mean by Transformation?In mathematics, transformation refers to a change in position, shape, size, or orientation of a figure or a function. There are various types of transformations, including translation, rotation, reflection, dilation, and more.
A translation is a transformation in which a figure is moved to a new position on the coordinate plane, while keeping its original size and orientation intact. A rotation is a transformation in which a figure is turned about a fixed point, called the center of rotation. A reflection is a transformation in which a figure is flipped over a line, called the line of reflection. A dilation is a transformation in which a figure is enlarged or reduced, while keeping its shape intact.
Transformations are used in various areas of mathematics, including geometry, engineering, computer graphics, and more. They provide a way to model real-world objects and processes and to solve problems related to size, position, and orientation. Understanding transformations is a fundamental aspect of mathematical skills and is crucial in many areas of study and research.
The transformation from f(x) = ln(x) to g(x) = ln(x + 2) is a horizontal shift to the right by 2 units. This is because when you replace x with x + 2 in the logarithmic function, you are shifting the graph to the right by 2 units. The x-intercepts of the graph of f(x) will be at x = 1 (since ln(1) = 0), whereas the x-intercepts of the graph of g(x) will be at x = -2 (since ln(2) = 0). So, in essence, the transformation is simply a horizontal shift of the graph of f(x) to the right by 2 units to obtain the graph of g(x).
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In a running competition, a bronze, silver and gold medal must be given to the top three girls and top three boys. If 4 boys and 14 girls are competing, how many different ways could the six medals possibly be given out?
Answer:
there are 1456 different ways that the six medals can possibly be given out.
Step-by-step explanation:
There are different ways to approach this problem, but one common method is to use combinations.
First, we need to determine how many ways we can choose three girls out of 14, and three boys out of 4. This can be calculated using combinations:
Number of ways to choose 3 girls out of 14: C(14,3) = 364
Number of ways to choose 3 boys out of 4: C(4,3) = 4
Now, we can use the multiplication principle to determine the total number of ways to give out the six medals:
Total number of ways = number of ways to choose 3 girls * number of ways to choose 3 boys = 364 * 4 = 1456
Therefore, there are 1456 different ways that the six medals can possibly be given out.
find the area a of the sector of a circle of radius 100 meters formed by the central angle 1/8 radian
The area of a sector of a circle with radius 100 meters and central angle 1/8 radian is approximately 625 * π square meters.
The area of a sector of a circle with radius 100 meters and central angle 1/8 radian can be found using the formula:
A = [tex](\theta/2\pi )*\pi r^{2}[/tex]
where A is the area of the sector, Θ is the central angle in radians, π is Pi (approximately 3.14), and r is the radius of the circle.
Plugging in the given values, we have:
A = [tex](\frac{\frac{1}{8}}{{2\pi }} )*\pi *100^{2}[/tex]
A =[tex](1/16)*\pi *100^{2}[/tex]
A = [tex](\pi /16)*100^{2}[/tex]
A = (π/16) * 10000
A = 625 * π square meters
So, the area of the sector of the circle with radius 100 meters and central angle 1/8 radian is approximately 625 * π square meters.
The area of a sector of a circle is a portion of the circle's area enclosed by two radii and an arc. The central angle of the sector determines the fraction of the circle's circumference that the arc represents, and therefore the fraction of the circle's area that is enclosed by the sector.
To find the area of a sector, we first need to find the central angle in radians. The central angle is the angle formed by two radii at the center of the circle that intercept the circumference of the circle at the endpoints of the arc.
The formula for the area of a sector is given by:
A = [tex](\theta/2\pi )*\pi r^{2}[/tex]
where A is the area of the sector, Θ is the central angle in radians, π is Pi (approximately 3.14), and r is the radius of the circle.
In the given problem, the radius of the circle is 100 meters and the central angle is 1/8 radian. We plug these values into the formula and simplify to get the final answer.
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In ΔUVW, w = 7.2 cm, v = 6.2 cm and ∠V=8°.
Find all possible values of ∠W, to the nearest
10th of a degree.
We can use the Law of Sines to find the measure of angle W:
sin(W)/w = sin(V)/v
sin(W) = w*sin(V)/v
sin(W) = 7.2*sin(8°)/6.2
sin(W) ≈ 0.1001
Taking the inverse sine of both sides, we get:
W ≈ 5.78° or W ≈ 174.22°
Since W is an angle in a triangle, it must be between 0° and 180°. Therefore, the only possible value for ∠W is:
W ≈ 5.78° (to the nearest tenth of a degree).
The median a data set with nine data values is 36. A tenth value was added to the set, and the median is still 36. If the new value is greater than 36, why did the median not change?
The median did not change because the 5th and 6th term of data is same.
What are mean and median?The mean is the average value which can be calculated by dividing the sum of observations by the number of observations
Mean = Sum of observations/the number of observations
Median represents the middle value of the given data when arranged in a particular order.
Given that;
The median of data set with nine numbers= 36
After the addition of tenth value median= 36
Now,
Median is the middle term of data
Here, the middle value and 6th term must be same.
So, 5th term= 6th term= 36
Therefore, the median of the given data set is same.
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Find an estimate of the total distance traveled in the first 6 hours of travel for a particle whose velocity is given by
v(t)=−t^2 +4t+6
where v is in MPH and t is in hours.
Estimate of the total distance traveled in the first 6 hours of travel for a particle v(t)=−t^2 +4t+6 is 36m.
We have v(t)=−t² +4t+6
For finding the distance we have to find the integration of the given equation:
s = ∫ -t² +4t+6
= -t³/3 + 4t²/2 + 6t
= -t³/3 + 2t²/ + 6t
For the value of t = 6 hours
= -6³/3 + 2(6)² + 6(6)
= -72 + 72 + 36
= 36
Estimate of the total distance traveled in the first 6 hours is 36 m.
When a moving object has a positive velocity, its position is constantly rising. (We focus on the case when velocity is always positive; we will soon explore cases where velocity is negative.) We have shown that the area under the velocity curve represents the precise distance travelled whenever is constant on an interval. Finding the areas of rectangles that closely resemble the area under the velocity curve allows us to calculate the total distance travelled when is not constant.
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MATH QUESTION <3 PLEASE HELP
The angle that the flagpole makes with the ground is 20°.
What are trigonometric identities?There are three commonly used trigonometric identities.
Sin x = 1/ cosec x
Cos x = 1/ sec x
Tan x = 1/ cot x or sin x / cos x
Cot x = cos x / sin x
We have,
Flagpole height = 16 feet
From figure B,
The angle of elevation has increased this means,
The flagpole is leaning.
Now,
The angle that the flagpole makes with the ground.
Cos m = 15/16
Cos m = 0.9375
m = [tex]cos^{-1}[/tex] 0.9375
m = 20.36
m = 20°
Thus,
The angle that the flagpole makes with the ground is 20°.
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Please help me and explain how to do this
The scale factor of figure A to figure B is 5/3.
What is Triangle?A triangle is a three-sided polygon that consists of three edges and three vertices.
Two triangles are said to be similar if their corresponding angles are congruent and the corresponding sides are in proportion .
A and B are similar triangles.
We need to find the scale factor.
The ratio between the scale of a given original object and a new object
Scale factor is 15/9=35/21=40/24
5/3=5/3=5/3
Hence, 5/3 is the scale factor of figure A to figure B.
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Find the effective rate corresponding to the following nominal rate.5% compounded continuously.
The effective rate for a nominal rate of 5% compounded continuously over a time period of 1 year is 5.13%.
To find the effective rate corresponding to a nominal rate compounded continuously, we use the formula:
r_effective = [tex]e^{(r\_nominal * t)} - 1[/tex]
where r_nominal is the nominal rate, and t is the time period.
For a nominal rate of 5% compounded continuously, the effective rate can be calculated as follows:
r_effective = [tex]e^{(0.05*t)}-1[/tex]
Note that the time period t is usually expressed in years. For example, if we want to find the effective rate for a time period of 1 year, we have:
r_effective = [tex]e^{(0.05*t)}-1[/tex]
= 1.051296 - 1
= 0.051296 or 5.13%
So, the effective rate for a nominal rate of 5% compounded continuously over a time period of 1 year is 5.13%.
It's important to understand the difference between nominal and effective rates. The nominal rate is the rate that is advertised or quoted, while the effective rate takes into account the frequency of compounding. The effective rate is a more accurate representation of the true interest rate because it shows the actual amount of interest earned over a given time period.
Continuous compounding means that interest is calculated and added to the principal continuously, rather than at regular intervals. This results in a higher effective rate compared to the same nominal rate compounded at regular intervals.
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A box was made in the form of a cube. If a second cubical box has inside dimensions four times those of the first box, how many times as much does it contain?
(A) 4
(B) 8
(C) 16
(D) 64
(E) none of these
Answer:
Since the second box has inside dimensions four times those of the first box, its volume is $(4a)^3 = 64a^3$ times as much as the volume of the first box, whose volume is $a^3$. Therefore, the answer is (D) 64.
Ech of
avior?
now
u
4. A class plants a tree.
Sketch the graph of the
height of the tree
over time.
Year 0 3 feet
Year 3 7 feet
a. Identify the two variables.
b. How can you describe the relationship
between the two variables?
The relationship between the two variables is y=4/3 x+3.
What is the equation of a line?The general equation of a straight line is y=mx+c, where m is the gradient, and y = c is the value where the line cuts the y-axis. This number c is called the intercept on the y-axis.
The coordinate points are (0, 3) and (3, 7)
Here, slope (m) = (7-3)/(3-0)
= 4/3
Substitute m=4/3 and (x, y)=(0, 3) in y=mx+c, we get
3=4/3(0)+c
c=3
So, the equation is y=4/3 x+3
Therefore, the relationship between the two variables is y=4/3 x+3.
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Let V be the space of all infinite sequences of real num- bers. See Example 5. Which of the subsets of V given in Exercises 12 through 15 are subspaces of V? 12. The arithmetic sequences [i.e. sequences of the form (a,a + k;a + 2k,u 3k for some constants CL and k]
Yes , the arithmetic sequence ( written as sequences of the form (a , a+k , a+2k , a+3k for some constants a and k ) is a subspace of V .
To determine whether subsets of V in the arithmetic sequences are subspaces of V, we check if they satisfy the three conditions for a subset to be a subspace:
(i) The subset must contain the zero vector.
(ii) The subset must be closed under vector addition.
(iii) The subset must be closed under scalar multiplication.
Let S be a subset of V consisting of arithmetic sequences.
Now we check the three conditions :
(i) We find an arithmetic sequence in S that has all its terms equal to zero. The only arithmetic sequence that satisfies this is the sequence (0, 0, 0, 0, ...), which is in S.
So , the subset "S" contains zero vector.
(ii) Next we need to show that if u and v are two arithmetic sequences in S, then their sum "u + v" is also an arithmetic sequence in S.
Let U = (a, a+k, a+2k, a+3k, ...) and V = (b, b+l, b+2l, b+3l, ...) be two arithmetic sequences in S.
Then, their sum is ⇒ u+v = (a+b, a+k+b+l, a+2k+b+2l, a+3k+b+3l, ...).
This is also an arithmetic sequence,
So , subset "S" is closed under vector addition.
(iii) Next , we show that if U is an arithmetic sequence in S and C is a scalar, then CU is also an arithmetic sequence in S.
Let U = (a, a+k, a+2k, a+3k, ...) be an arithmetic sequence in S, and let c be a scalar.
we get , CU = (ca, ca+ck, ca+2ck, ca+3ck, ...) is also an arithmetic sequence,
So , subset "S" is closed under scalar multiplication.
we see that , S satisfies all three conditions, it is a subspace of V.
Therefore, any subset of V consisting of arithmetic sequences is a subspace of V.
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The given question is incomplete , the complete question is
Let V be the space of all infinite sequences of real numbers , Which of the subsets of V in The arithmetic sequences [i.e. sequences of the form (a , a+k , a+2k , a+3k for some constants a and k] are subspaces of V ?
A stemplot titled speed limit. The values are 10, 45, 45, 45, 45, 50, 50, 55, 55, 55, 55, 55, 60, 60, 60, 65, 65, 65, 65, 65, 65, 70, 70. The stemplot shows the speed limit on different signs. Which statement is true about the data shown in the stemplot?
The statement that is true about the data shown in the stemplot is that the most common speed limit is 55.
What is stemplot ?
A stemplot, also known as a stem-and-leaf plot, is a type of chart used to display data. It shows the distribution of a set of values by separating each value into a stem and a leaf.
Given by the question:
Based on the values given, the stemplot titled "speed limit" could be constructed as follows:
1 | 0
4 | 5 5 5 5
5 | 0 5 5 5 5 5
6 | 0 0 0 5 5 5 5
7 | 0 0
The stem represents the tens digit of each value, and the leaves represent the ones digit. For example, the first value of 10 has a stem of 1 and a leaf of 0.
Based on the stemplot, we can make the following observations:
The speed limits range from 10 to 70.There are no speed limits between 11 and 44.The most common speed limit is 55, which appears 5 times.There are four speed limits of 45 and two speed limits of 50 and 60.There are a total of 23 speed limits.Therefore, the statement that is true about the data shown in the stemplot is that the most common speed limit is 55.
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Complete the proof.
Statements
AB= 3, BC = 5, and CA = 3.5
LM=6.3, MN = 9, and NL = 5.4
NL 5.4
AB
MN
5.4
3
=
9
||
5
BC
LM 6.3
CA
3.5
9
Octo
=
= 1.8
= 1.8
5
6.3
3.5
N = MN = LM
AABC →ALNM
ZB ZN
= 1.8
Reasons
given
substitution property of equality
simplify
Corresponding angles of similar triangles are congruent.
The proof is completed as follows
Statement Reason
NL/AB = MN/BC = LM/CA ratios of side of similar triangles are equal
Δ ABC is similar to Δ LNM Definition of similar triangles
What are similar triangles?
Similar triangles are triangles that have the same shape but may differ in size. That is to say, they have the same angles but their sides may be scaled differently.
When two triangles are similar, their corresponding angles are congruent and the corresponding sides are in proportion to each other.
This means that if you know the lengths of any two sides of a similar triangle, you can use those ratios to find the lengths of the other sides.
In the proof, the equation NL/AB = MN/BC = LM/CA means that proportions are equal
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Please solve quickly! Within 30 minutes would be great!
Please solve for the variable indicated.
A=1/2h(b+B), solve for b
If you could break it down step by step that would be super helpful! I’m very confused. Thank you!
Answer:
Solve for B:
[tex]B = -b+\frac{5A}{6h}[/tex]
Step-by-step explanation:
[tex]A=1.2h(b+B)[/tex]
Use the distributive property to multiply [tex]1.2h by b+B[/tex]
[tex]A=1.2hb+1.2hB[/tex]
Swap sides so that all variable terms are on the left hand side.
[tex]1.2hb+1.2hB=A[/tex]
Subtract [tex]1.2hb[/tex] from both sides.
[tex]1.2hB= A - 1.2hb[/tex]
The equation is in standard form.
[tex]\frac{6h}{5} B=-\frac{6bh}{5} +A[/tex]
Divide both sides by [tex]1.2h[/tex].
[tex]\frac{5*(\frac{6h}{5})B }{6h} =\frac{5(-\frac{6bh}{5}+A) }{6h}[/tex]
Dividing by [tex]1.2h[/tex] undoes the multiplication by [tex]1.2h[/tex].
[tex]B = \frac{5(-\frac{6bh}{5}+A) }{6h}[/tex]
Divide [tex]A - \frac{6hb}{5}[/tex] by [tex]1.2h[/tex].
[tex]B = -b+\frac{5A}{6h}[/tex]
Solve For B:
[tex]B = -b+\frac{5A}{6h}[/tex]
these are 3 different questions but the 3rd one is asking which function for question 1 and 2 has a greater rate .
Answer: Function A is greater.
Step-by-step explanation:
just find the slope...
Slope for Function C = [tex]\frac{1}{3}[/tex] = [tex]0.33333[/tex] repeat...
and for Function A = [tex]\frac{5}{2}[/tex] = [tex]2.5[/tex]
to find the slope we use; [tex]s=[/tex] [tex]\frac{y}{x}[/tex].
2 2/13 of 52 is _____
a learning experiment requires a rat to run a maze (a network of pathways) until it locates one of three possible exits. exit 1 presents a reward of food, but exits 2 and 3 do not. (if the rat eventually selects exit 1 almost every time, learning may have taken place.) let yi denote the number of times exit i is chosen in successive runnings. for the following, assume that the rat chooses an exit at random on each run. (a) find the probability that n
The probability that when n=6, [tex]Y_{1}[/tex] =3, [tex]Y_{2}[/tex]=1, [tex]Y_{2}[/tex]=2 is 0.0822.
We have to find the probability that n=6, [tex]Y_{1}[/tex] =3, [tex]Y_{2}[/tex]=1, [tex]Y_{2}[/tex]=2
A rat has three possible exits to come out from the maze
The pmf of multinomial distribution is
P[tex](y_{1}, y_{2}, y_{3}......, y_{k} ) = \frac{n!}{{y_{1!} }y_{2}!....y_{k}! } p^y_1 1p^y_2 2......p^y_k k[/tex]
The probability of choosing one of the ways is 1/3
Then [tex]p_{1}[/tex]= 1 / 3,[tex]q_{1}[/tex] = 1-(1/3) = 2/3
[tex]p_{2} = 1/3, q_{2} = 2/3\\ p_{3} = 1/3, q_{3} = 2/3[/tex]
[tex]P(y_{1}, y_{2}, y_{3} ) = P(1,2,3)\\ = \frac{6!}{3! 2! 1!} (\frac{1}{3} )3(\frac{1}{3} )2(\frac{1}{3} )1[/tex]
=60(0.00137)
=0.0822
Hence, the probability that when n=6, [tex]Y_{1}[/tex] =3, [tex]Y_{2}[/tex]=1, [tex]Y_{2}[/tex]=2 is 0.0822.
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The correct question is:
A learning experiment requires a rat to run a maze (a network of pathways) until it locates one of three possible exits. Exit 1 presents a reward of food, but exits 2 and 3 do not. (If the rat eventually selects exit 1 almost every time, learning may have taken place.) Let [tex]Y_{i}[/tex] denote the number of times exit i is chosen in successive runnings. For the following, assume that the rat chooses an exit at random on each run.
a Find the probability that n = 6 runs result in [tex]Y_{1} = 3, Y_{2} = 1, and Y_{3} = 2.[/tex]
HELP NOW PLS!! 100 PTS!!!! BRAINLIEST ANSWER!!!!!!
Answer: 10
Step-by-step explanation: beacause you add both of the sides
A bacteria population starts at 2,032 and decreases at about 15% per day. Write a function representing the number of bacteria present each day. Graph the function. After how many days will there be fewer than 321 bacteria?
The function representing the number of bacteria present each day is f(t) = 2032[tex](0.85)^{t}[/tex].
What is meant by function?Numbers, formulae, and related structures, shapes, and the spaces they occupy are all issues in the field of mathematics, as are quantities and their variations. f(x) = x2 is a prime example of a straightforward function. The function in this equation is called f(x), and it squares the value of "x". Assume that f(3) = 9 if, for example, x = 3. Several other functions include f(x) = sin x, f(x) = x2 + 3, f(x) = 1/x, f(x) = 2x + 3, etc.Each element of X receives the exact same number of elements from Y when a function from one set to the other is used.Both the set X and the set Y are referred to as the function's domain and codomain, respectively.
Beginning in 2032, there will be a 15% daily decline in the number of microorganisms.
a function that displays the daily average amount of microorganisms.
f(x) = 2032[tex](1 - .15)^{t}[/tex]
f(x) = 2032[tex](0.85)^{t}[/tex]
Therefore f(t) = 2032[tex]0.85^{t}[/tex] is the correct answer.
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Help me with this worksheet please
The trigonometry ratio values are tan(50) = 1.19 and cos(70) = 0.34
The trigonometry ratio valuesThis can be calculated using a calculator
So, we have
tan(50) = 1.19 and cos(70) = 0.34
The measures of the anglesThis can be calculated using a calculator
So, we have
sin(84) = 0.9945 and tan(75) = 3.7321
The trigonometry ratio valuesHere, we make use of the laws of cosines and sines
So, we have
cos(X) = 15/17 = 0.8824
sin(C) = 36/45 = 0.8
The measures of the indicated anglesHere, we make use of the laws of tangents and sines
So, we have
tan(?) = 6/13 = 0.4615
? = 24.77
sin(?) = 41/59 = 0.6949
? = 44.01
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Prove that 8 sin26. sin34. sin60. sin86 = root3 sin78
The proof of 8 sin26. sin34. sin60. sin86 = root3 sin78 is given below.
What are the trigonometric identities?Equations using trigonometric functions that hold true for all possible values of the variables are known as trigonometric identities.
Given:
An equation,
8 sin26. sin34. sin60. sin86 = root3 sin78
LHS = 8 sin26. sin34. sin60. sin86
= 0.9085192402
≈ 0.9 to the nearest tenth.
And RHS = 3 sin78
= 0.89023679976
≈ 0.9 to the nearest tenth.
Therefore, 8 sin26. sin34. sin60. sin86 = root3 sin78.
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A machine must produce a bearing that is within 0.02 inches of the correct diameter 4.1 inches. using x as the diameter of the bearing, write this statement using absolute value notation.____ ___ Preview
A machine must produce a bearing that is within 0.02 inches of the correct diameter 4.1 inches. By writing this statement using absolute value notation is:
| x - 4.1 | ≤ 0.02
This notation expresses the requirement that the diameter of the bearing, represented by x, must be within 0.02 inches of the correct diameter of 4.1 inches. The absolute value of the difference between x and 4.1 must be less than or equal to 0.02 for the bearing to meet the specification.
The absolute value function is used to ensure that the difference between x and 4.1 is always positive, regardless of whether x is greater than or less than 4.1. This is important because the requirement is concerned with the magnitude of the difference, rather than its sign. If the absolute value of the difference is less than or equal to 0.02, then the diameter of the bearing is considered to be within the required tolerance.
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Amanda bought a reusable water bottle that cost $23.94 including tax. After buying the water bottle, Amanda had $12.75 left in her wallet. Let m represent how much money Amanda had to start. Which equation models the problem? Solve this equation to find how much money Amanda had to start.
The equation which models the problem is m - $23.94 = $12.75 and the value of m is $36.69.
What is an Equation?A mathematical statement containing two algebraic expressions on two sides of an equal to sign is defined as an equation.
Given,
Cost of a reusable water bottle that Amanda bought = $23.94
Money remaining after buying the bottle = $12.75
Let m represent how much money Amanda had to start.
Then the equation can be written as,
m - $23.94 = $12.75
We have to solve the equation.
Adding $23.94 on both sides,
m = $12.75 + $23.94
m = $36.69
Hence the money at the start is $36.69.
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