which of the following occurrences is not dependent on gravity?
A. the moon's orbiting the sun.
B. the earth's orbiting the sun.
C. Mar's orbiting the sun.
D. all of the above are dependent of gravity.

Answers

Answer 1

Answer:

D

Explanation:

it's all of the above because they all use for gravity


Related Questions

Hari drag a load of 60 kg along a distance of 12 metre what amount of work does he do also mention the type of work​

Answers

Answer:

W = 7056  J

Explanation:

Given that,

Mass of a load, m = 60 kg

Distance moved, d = 12 m

We need to find the amount of work. The work done by an object is given by :

W = Fd

So,

W = mg×d

W = 60 kg × 9.8 m/s²×12 m

W = 7056  J

So, the amount of work done is 7056  J.

An object that is speeding up is accelerating.
True
False

Answers

True. The speed of any object will have faster acceleration, and eventually slow down due to gravity.

A satellite moves in a circular orbit at a constant speed v0 around Earth at a distance R from its center. The force exerted on the satellite is F0. An identical satellite orbits Earth at a distance of 3R from the center of the Earth. How does the tangential speed, vT, of the satellite at distance 3R compare to the speed v0 of the satellite at R

Answers

Tangential speed vT, for the stallite that orbits the earth from a distance 3R is compared by  [tex]\bold {(vT)= \dfrac {(v0)}{3}}[/tex].

Given here,

Vo - Speed  

R - Distance of center of the earth

Fo - Force exerted on satellite

vT - Tangential speed

For satelite, Gravitational force (Fg)is equal to the centripetal force(Fc),

Fg = Fc = Fo

[tex]\bold {\dfrac {GMm}{R^2} = \dfrac {m(v0)^2}R}[/tex]

GM = (v0)²R.....................  (1)

Since, For satellite R = 3R

Thus,

[tex]\bold {\dfrac {GMm}{3R^2} = \dfrac {m(v0)^2}{3R}}[/tex]

[tex]\bold {\dfrac {GMm}{3R^2} = \dfrac {m(vT)^2}{3R}}\\\\\bold {\dfrac {GM}{27 R} = \dfrac {(vT)^2}{3R}}\\\\\bold {GM = \dfrac {27 R \times (vT)^2}{3R}}\\\\\bold {{GM}= 9 R \times (vT)^2}\\[/tex].........(2)

From equation 1 and 2,

(v0)²R = 9(vT)²R

Divide through R and then 9, we get

[tex]\bold {(vT)^2 = \dfrac {(v0)^2}{9}}[/tex]

Take the square root,

[tex]\bold {(vT)= \dfrac {(v0)}{3}}[/tex]

Therefore,  tangential speed, vT, for the stallite that orbits the earth from a distance 3R is compared by  [tex]\bold {(vT)= \dfrac {(v0)}{3}}[/tex].

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difference between light energy and heat energy​

Answers

Light energy can also be converted into thermal energy when for example the sun heats up your black shirt or a brick wall outside. There are many example we see in our routine life carrying light energy like lightened candle, flash light, fire, Electric bulb, kerosene lamp, stars and other luminous bodies etc.

Click through the images and select the model that best shows how J.J. Thomson envisioned the atom.

Answers

Answer:

The first one with the big plus in the middle and negatively charged electrons around.

Explanation:

The first image with the plus sign in the middle and negatively charged electrons around it shows how J.J. Thomson envisioned the atom.

J.J. Thomson proposed the "plum pudding" model of the atom. This model suggested that atoms were composed of a positively charged "pudding" with negatively charged electrons embedded within it.

1. Thomson conducted experiments with cathode rays, which are streams of negatively charged particles emitted from cathodes in vacuum tubes. Through his experiments, Thomson discovered that cathode rays were composed of negatively charged particles, which he named electrons. Based on his observations, Thomson proposed the "plum pudding" model, also known as the "raisin bread" model.

According to this model, atoms were made up of a positively charged substance, like a pudding, with negatively charged electrons scattered throughout it, like raisins in bread. Thomson suggested that the positive charge was evenly distributed throughout the atom, creating a uniform positive charge in the "pudding." This model was a significant departure from the previous understanding of the atom as an indivisible, homogeneous sphere.

Thomson's plum pudding model provided an early depiction of atomic structure, showing that atoms were not indivisible but composed of smaller subatomic particles. However, later experiments, particularly those conducted by Ernest Rutherford, led to the discovery of the atomic nucleus, which necessitated the revision of Thomson's model.

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A 1000 kg racecar, which is capable of a top speed of 125 m/s, is sitting in a
parking lot. How much KE does it have?

Answers

sitting = no movement
KE=0

What is the characteristic that allows an object to have kinetic energy?

Answers

kinetic energy is movement, thus movement would be a characteristic that allows an object to have kinetic energy

you will find the question in the pic

Answers

Answer:

8cm/sec

Explanation:

Number of cycle per second. Distance covered is 8cm in one cycle.

On average how fast does the radiation spread from an atom-bomb?

Answers

Answer:

around 30 grays

Explanation:

Hope this helps :)

30 grays on average ,

Turning A of the generator spins a magnet and creates an electric current that lights the bulb. Which of the following observations can be used to indicate the strength of the current created by the generator? *

A. The brightness of the bulb
B. The size of the magnet
C. The length of the handle
D. The mass of the generator

Answers

Answer:

A. The brightness of the bulb

Explanation:

An electric current through a circuit turns the lights bulb on. the strength of the current created by the generator will be indicated by the brightness of the bulb because in a closed circuit, the bulb is the only object that is representing that, circuit is properly placed and when bulb lights up only when electrical energy is generated.

More electrical energy generated through the generator means the brighter the bulb glow.

Hence, the correct answer is "A. The brightness of the bulb".

Q3. Recall the equation that links gravitational field
strength, mass and weight

Answers

Gravitational potential energy = mass x gravitational field strength (g) x height

Question 1 of 10
Whích three factors are used to calculate gravitational potential energy?
A. The height of an object
B. The chemical formula for an object
O C. The density of an object
O D. The acceleration of an object due to gravity
O E. The mass of an object
F. The velocity of an object

Answers

Answer:

A., D., and E.

Explanation:

Gravitational potential energy is mgh, the values represented by answers E., D., and E., respectively.

Have a wonderful day!

Answer:

Im late. A D and E

Explanation:

The factors that affect an object's gravitational potential energy are its height relative to some reference point, its mass, and the strength of the gravitational field it is in. The formula for potential energy depends on the force acting on the two objects. For the gravitational force the formula is P.E. = mgh, where m is the mass in kilograms, g is the acceleration due to gravity (9.8 m / s2 at the surface of the earth) and h is the height in meters.

According to Newton’s third law of motion, when a hammer strikes and exerts force on a nail, the nail...
A)creates a friction with the hammer
B) disappears into the wood
C) exerts an equal force back on the hammer
D) moves at a constant speed

Answers

Answer:

C) Exert an equal force back on the hammer

Explanation:

Every action has an equal and opposite reaction

also just trust me.

Make me brainlist

Waves that do not need a medium to transfer energy are called
A. Transverse Waves
B. Mechanical Waves
C.Electromagnetic Waves
D.Longitudinal Waves
(help for science Test)​

Answers

C. Electromagnetic waves
C electromagnetic waves


How will dropping a can from a higher or a lower elevation affect the impact it has on a clay ball?

Answers

When dropping it higher it will have a larger impact and dropping it lower will have a smaller impact.

Dropping a can from a higher elevation  affects greater impact compare to  dropping a can from a lower elevation.

What is potential energy?

Potential energy is a form of stored energy that is dependent on the relationship between different system components. When a spring is compressed or stretched, its potential energy increases.

If a steel ball is raised above the ground as opposed to falling to the ground, it has more potential energy. It is capable of performing more work when raised.

Potential energy is a system attribute, not a property of a single body or particle.

The potential energy of the can on higher elevation is greater than the potential energy of the can on  lower elevation. That is why, dropping a can from a higher elevation  affects greater impact compare to  dropping a can from a lower elevation.

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2. A car with mass 2,500 kg is travelling at 15 m/s. What is the car's kinetic energy?
a. 37,500 J
b. 563,000 J
c. 280,000 J
d. 350,000 J

Answers

Answer:

c, 280,000J

Explanation:

You should use the equation KE (Kinetic Energy) = [tex]\frac{1}{2} mv^2[/tex]

m = 2500

v = 15

KE = [tex]\frac{1}{2} * 2500 * (15)^2\\[/tex]

KE = 281250 Joules.

This is consistent with the answer B, as all of the parameters given to you are rounded to 2 significant figures so naturally, the answer should also be rounded to 2 sig figs.

KE = 280,000 J

Please help.
Lions used to hunt by themselves. Now, they hunt in packs. What type of adaptation is this?
A.structural adaptation
B.behavioral adaptation
C. functional adaptation

Answers

Answer:

I think it is behavioral

Where is most of Earth’s freshwater found?
in the ground
near the poles
in lakes and streams
in the air as water vapor

Answers

In lakes and streams

A spring has a spring constant k = 20N/cm. What load is needed to produce an extension of 2.5cm?

Answers

Answer:

50 N

Explanation:

We are given;

Spring constant; K = 20N/cm

Extension; Δx = 2.5 cm

We want to find the load which is the force. This is gotten from the equation;

F = k•Δx

F = 20 × 2.5

F = 50 N

Therefore the load needed is 50 N.


A sumo wrestler pushes another sumo wrestler back 3.41 meters, with a force of 120 N. How much work did he do? Round your answer to 2 decimal places.

Answers

Answer:

work=force* distance

Explanation:

cal it your self



A parallel-plate air capacitor is made from two plates 0.200{\rm m} square, spaced 0.800 {\rm cm} apart. It is connected to a 120 {\rm V} battery. If the plates are pulled apart to aseparation of 1.60 {\rm cm}, suppose the battery remains connected while theplates are pulled apart.

What is the capacitance?

C =2.21×10−11{\rm F}


Part B

What is the charge on each plate?

Enter your answer as two numbers,separated with a comma.

Part C

What is the electric field between theplates?

E =7500 {\rm V/m}

Part D

What is the energy stored in thecapacitor?

U =1.59×10−7{\rm J}

Answers

Answer:

A)  C = 4.425 10⁻¹³ F,  B) Q = 6.31 10⁻¹¹ C,  C)  E = 8.9 10⁴ N / C,  

D)  u_{E} = 3.19 10⁻⁹ J

Explanation:

Part A. Capacitance is

           C = ε₀ A / d

in this case distance is d = 0.800 cm = 0.800 10⁻² m and the area of ​​the plates is x = 0.200 cm= 0.2 10⁻² m, all the quantities must be in the SI system for the result to be in Farads

           A = x²

           A = (0.2 10⁻²)²

           A = 4 10⁻⁶ m

let's calculate

          C = 8.85 10⁻¹² 4 10⁻⁶ / 0.8 10⁻²

          C = 44.25 10⁻¹⁴ F

          C = 4.425 10⁻¹³ F

Part B. The charge on each plate is

          Q = C ΔV

           Q = 4.425 10⁻¹³ 120

           Q = 6.31 10⁻¹¹ C

Part C. the electric field of a plate is

           E = σ / 2ε₀

where the charge density is

            σ = Q / A

we substitute

             E =[tex]\frac{Q}{ 2\epsilon_o A}[/tex]

       

let's calculate

             E = [tex]\frac{6.31^{-11} }{ 2 \ 8.85^{-12} \ 4^{-6} }[/tex]

             E = 8.9 10⁴ N / C

Part D. stored energy

              [tex]u_{E}[/tex] = ½ C V²

               u_{E} = ½ 4.425 10⁻¹³ 120²

               u_{E} = 3.19 10⁻⁹ J

What is the net force acting on a 5.0 kg object that has a velocity of 15 m/s and is moving in a
circle of radius 1.6m?

Answers

The answer is going to be: 705N

The net force acting on the object is 703.125 N

In the case of circular motion, there is a centripetal acceleration acting on the object given by:

[tex]a_{r}=\frac{v^{2} }{r}[/tex]

where, v is the velocity of the object = 15 m/s,

and r is the radius of the path = 1.6 m

The net force F:

[tex]F=ma_{r}=m\frac{v^{2} }{r}[/tex]  

[tex]F=5*\frac{15^{2} }{1.6}\\F=703.125 N[/tex] is the net force acting on the object.

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6 N M 8N
What is the net force?​

Answers

Answer:

14 Newtons

Explanation:

6N + 8N = 14N

PLS ANSWER FAST WILL GIVE BRAINLSET!!!



Calculate the missing variables using the necessary formula and rules using "FORCE"



A tractor carrying hay bales a total mass of 9 100 kg. What force is required to reach acceleration of 4 m/ s2

Answers

Answer:Hey I just wanted to tell you that Jesus LOVES YOU SO MUCH He died on the cross for all your sins so you won’t have to suffer the consequences of your sin He paid for ALL OF IT! He loves you SO FREAKING MUCH like unconditionally... all you have to do is confess with your mouth and believe in your heart that Jesus is Lord and God raised Him from the dead 3 days later you will be saved ;)))))))) He wants an intimate relationship with you all you have to do is reach out to Him I love you AND ABOVE ALL JESUS LOVES YOU

Have a blessed day;))

Explanation:

Find the current in the 12 ohm resistor.

Answers

Answer:

1.5 A

Explanation:

V =I.R

18 = I × 12

I = 18/12

= 3/2 = 1.5 A

A scooter travelling at 10 m/s speed up to 20 m/s in 4 sec. Find the acceleration of scooter.

Answers

Explanation:

The acceleration of the scooter is 2.5 m/s

Need help ASAP
Thanks + BRAINLIST only for correct answer

1.Cell phones convert sound waves into______waves.
-light waves
-sound waves
-radio waves

2.Electromagnetic waves used in cell phone communications are called?
-microwave
-radio wave
-infrared
-all of the above

3.To send out a radio signal far and wide...it is called?
-broadcast
-casting
-antenna

Answers

Answer:

cell pohnes convert sound waves into radio waves

electromagnetic waves used in cellphone communications are called: radio waves

To send out a radio signal far and wide.. it is called: broadcast

Explanation:

Answer:

1.radio wave

2. radio wave

3.broadcasting

a sound wave has a frequency of 1192 hertz. all sound waves in air travel at 322m/s. find the wave length of the sound wave

Answers

Answer:

0.167 m

Explanation:

By the definition of the velocity if a wave ,

The velocity of light, v, is the product of its wavelength, λ , and its frequency, f.  

V= fλ

frequency - number of occurrences in a unit time

Wavelength - distance between corresponding points of two consecutive waves

(check the graph for wavelength)

If you add a neutron to an atom how does the properties of the atom change, the atoms identity? the atoms charge? the atoms size?

Answers

Answer:

Neutrons do not carry an electrical charge so adding or removing them from the nucleus does not change the electrical charge of the nucleus. ... So, adding or removing protons from the nucleus changes what element that atom is! For example, adding a proton to the nucleus of an atom of hydrogen creates an atom of helium.

You would like to know whether silicon will float in mercury and you know that can determine this based on their densities. Unfortunately, you have the density of mercury in units of kilogrammeter3 and the density of silicon in other units: 2.33 gramcentimeter3. You decide to convert the density of silicon into units of kilogrammeter3 to perform the comparison. By which combination of conversion factors will you multiply 2.33 gramcentimeter3 to perform the unit conversion?

Answers

Answer:

The fourth one

Explanation:

It's the only one to represent volume (cm³ vs. m³) and have kilograms in the denominator.

Have a wonderful weekend!

If we want to convert the density of the silicon from  2.33 gram/ centimeter3 to kilogram /meter3 unit we have to perform the operation

(1 kilogram/ 10³ grams) ×(1 centimeter/10⁻² meters)×(1 centimeter/10⁻² meters)×(1 centimeter/10⁻² meters)

Therefore the correct answer is option B.

What is density?

It can be defined as the mass of any object or body per unit volume of the particular object or body. Generally, it is expressed as in gram per cm³ or kilogram per meter³.

As given in the problem we have to convert the density of the silicon from  2.33 gram/ centimeter3 to kilogram /meter3 unit

1 kilograms = 1000 grams

1 meter = 100 cm

2.33 gram/ centimeter3 = 2.33×10 ⁻³kilogram / 10 ⁻⁶meter3 unit

                                       = 2.33×10³kilogram / 10 ⁻⁶meter3 unit

Thus, the correct answer is option B.

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