Which of the following statement(s) is/are correct? 1) The energy change when 10 is (hypothetically) formed from 8 protons and 8 neutrons is known as the energy defect. ii) The splitting of a heavier nucleus into two nuclei with smaller mass numbers is known as nuclear fission. iii) The first example of nuclear fission involved bombarding 92 235 U with He nuclei.

18.26 g of Al can be recovered.

The equation that follows is:

2Al₂O₃ → 2Al + 3O₂

The atomic mass of Al = 27 g

The molecular mass of Al₂O₃ = 102 g

From the stoichiometric equation, 102g of Al₂O₃ yields 54 g of Al

Therefore,

34.5 g of Al₂O₃ will give = [tex]\frac{54 (34.5)}{102}[/tex]

                                        = 18.26 g

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To calculate the molar mass of substance, divide the number of moles by the given mass of substance.

The quantity of a substance is known as a mole. You can measure it in terms of grams, liters, atoms, molecules, or particles.

Use the substance's molar mass to convert between grams and moles. Divide the given mass by the number of moles to convert from moles to molar mass.

Using the formula, Number of moles = Given mass/ molar mass

The molar mass of a substance can be calculated as-

Molar mass = Given mass/number of moles

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Answer:

3.2 g O₂

Explanation:

To find the mass of O₂, you need to (1) convert grams H₂O to moles H₂O (via molar mass), then (2) convert moles H₂O to moles O₂ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles O₂ to grams O₂ (via molar mass). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 2 sig figs to reflect the sig figs of the given value (3.6 g).

Molar Mass (H₂O): 2(1.008 g/mol) + 15.998 g/mol

Molar Mass (H₂O): 18.014 g/mol

2 H₂O -----> 2 H₂ + 1 O₂

Molar Mass (O₂): 2(15.998 g/mol)

Molar Mass (O₂): 31.996 g/mol

3.6 g H₂O         1 mole               1 mole O₂           31.996 g
----------------  x  ---------------  x  ---------------------  x  ---------------  = 3.2 g O₂
                         18.014 g          2 moles H₂O          1 mole

Answer:

All except 2nd one

Explanation:

Answer:

CB. Two different compounds mixing and remaining separate is not correct!

Answer:

heat energy is released into the surrounding

Answer:

Any base with an ability to dissolve in water are called alkalis. All alkalis are bases, however, not all bases are alkalis.

Nitrogen gas reacts with oxygen gas to form dinitrogen tetroxide. When the equation is written and balanced, the sum of the coefficients is 3.

By catalytically oxidizing ammonia, nitrogen tetroxide is produced; steam is employed as a diluent to lower the combustion temperature. The ammonia is converted into nitric oxide in the initial step:

 4 NH3 + 5O2   →    6 H2O  + 4 NO

The gases are further cooled and the majority of the water is condensed; the created nitric oxide is then converted to nitrogen dioxide, which is dimerized into nitrogen tetroxide:

2 NO + O2 →2 NO2

2 NO2 ⇌ N2O4

Dinitrogen tetroxide is the chemical molecule N2O4, also known as nitrogen tetroxide (NTO) and occasionally amyl (typically among ex-USSR/Russian rocket engineers). It is a helpful reagent in the synthesis of chemicals. It and nitrogen dioxide combine to form an equilibrium combination. It has a 92.011 g/mol molar mass.

Dinitrogen tetroxide is a potent oxidizer that spontaneously reacts when it comes into touch with different types of hydrazine, making it the two popular bipropellants for rockets.

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The freezing point of a solution is -1.16°C

Calculation,

The equation which give relation between freezing point depletion and molality is,

Δ[tex]T_{f} = K_{f} .m[/tex]      ... (i)

Moles of the solute = 22.0 g / 114.23 g/mole = 0.193 mole

Mass of the solvent in g = 148 g

Mass of the solvent in kg = 0.148 kg

Molality = 0.193 mole/ 0.148 kg = 1.3 m

Now, after putting the value of  [tex]K_{f}[/tex] and m in equation (i) we get

Δ[tex]T_{f} = K_{f} .m[/tex]  

Δ[tex]T_{f}[/tex]= 5.12°C/m×1.3 m = 6.66°C

Δ[tex]T_{f}[/tex]=  [tex]T_{f}[/tex] (solvent) - [tex]T_{f}[/tex] (solution)

[tex]T_{f}[/tex] (solution) = [tex]T_{f}[/tex] (solvent)  -Δ[tex]T_{f}[/tex]= 5.5 °C - 6.66°C = -1.16°C

The freezing point of a is -1.16°C

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Answer:

TRUE

Explanation

Negative punishment's or  reinforcement .

Negative reinforcement comes as a result of failing to take the necessary precautional measures , whether intentional or unintentional .

Forgetting is a natural circumstance hence if one forgets it means in the first place he has by passed the protocols anyway and he has to take the consequences  .

Sometimes it may be ignorance since it is in common knowledge to turn off  any machine and if possible you should unplug it from the power supply to avoid any shocks which may even be fatal if the source of power does not have mechanisms to control such situations i.e. shocks and power surges .

Psychological when one gets such a punishments he will always remember the ordeal since it inflicted pain on him and he will always take precautional measures before handling an electronic or power sources .

Answer:false

Explanation:

The equilibrium constant K is 17.78 × 10²⁷ at 255 K for the following reaction under acidic conditions.

4H⁺ (aq) + MnO₂ (s) + 2Fe⁺² (aq) → Mn⁺² (aq) + 2Fe⁺³ (aq) + 2H₂O (l)

The relation between standard electrode potential and equilibrium constant is as follows:

G = -2.303 RT log K

-nFE° = -2.303 RT logK

[tex]\log K = \frac{nFE^{\circ}_{\text{cell}}}{2.303RT}[/tex]

Here,

n = 2

F = 96500

[tex]E^{\circ}_{\text{Cell}} = E^{\circ}_{\text{reduced}} - E^{\circ}_{\text{oxidized}}[/tex]

        = 0.77 V - 1.51 V

        = -0.74 V

R = 8.314 J/K mole

T = 255 K

Now put the values in above formula we get

[tex]\log K = \frac{nFE^{\circ}_{\text{cell}}}{2.303RT}[/tex]  

[tex]\log K = \frac{2 \times 96500 \times (-0.74)}{2.303 \times 8.314\ \text{J/K mole} \times 255\ K}[/tex]  

[tex]\log K = \frac{-142820}{4882.521}[/tex]

log K = 29.25

K = 17.78 × 10²⁷

The equilibrium constant K is 17.78 × 10²⁷ at 255 K for the following reaction under acidic conditions.

4H⁺ (aq) + MnO₂ (s) + 2Fe⁺² (aq) → Mn⁺² (aq) + 2Fe⁺³ (aq) + 2H₂O (l)

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Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: Use the appropriate standard reduction potentials below to determine the equilibrium constant at 255 K for the following reaction under acidic conditions.

4H⁺ (aq) + MnO₂ (s) + 2Fe⁺² (aq) → Mn⁺² (aq) + 2Fe⁺³ (aq) + 2H₂O (l)

The equation that relates equilibrium constants with cell potentials is

[tex]\log K = \frac{nFE^{\circ}_{\text{cell}}}{2.303RT}[/tex]

Use this formula, along with the information in the appendix of your book to solve for K.  

If the reaction has reached equilibrium and then the sealed reaction vessel expands, increasing the volume, the reaction would increase.

The equilibrium will change to favor the direction that produces more moles of gas when the volume is increased.

Equilibrium is a state of balance between opposing forces or actions that can be static (such as when forces are applied to a body and the resultant is zero) or dynamic (such as during a reversible chemical reaction when the velocities in both directions are equal). It can also be a state of equilibrium between the mind and the body.

In terms of economics, equilibrium occurs when supply and demand are equal. When you are composed and steady, you are in an equilibrium state.

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The reduction potential chart for metals, we can see that the most easily reduced metal in the list is Ag^+. Option C

A redox reaction is one that involves an oxidation and a reduction taking place simultaneously. This is because, the processes of electron loss and electron gain has to occur at the same time. A specie looses the electron that is gained by the other specie.

Now we know that metals are arranged in order of increasing reducing ability and decreasing reactivity. This arrangement is called the activity series of elements.

Looking at the reduction potential chart for metals, we can see that the most easily reduced metal in the list is Ag^+. Option C

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Answer:

45.82 gm O2

Explanation:

From your balanced equation in the first part, you can see that 2 moles propane  need 7 moles O2

Find the number of moles of propane in 18 gm

   mole wt of propane = ~  12 * 3 + 8 *1 = 44 gm/mole

      18 gm /  44 gm/mole  =  9/22 gm/mole  propane

            we need 7/2 of this as O2 moles    7/2 * 9/22 = 1.432moles of O2

 O2   mole weight =~ 32

       1.432 moles * 32 gm/mole = 45.82 gm O2

The difference between the calculated voltage (based on standard potentials) and the actual voltage required to cause electrolysis is called overvoltage.

Electrolysis is the technique of causing a chemical change in a substance by passing an electric current through it. The substance either loses or gets an electron during the chemical transition (oxidation or reduction). The procedure is carried out in an electrolytic cell, a device made up of positive and negative electrodes that are kept apart and submerged in a solution with ions that are both positively and negatively charged. The chemical that needs to be converted might either be dissolved in the solution or could form the electrode. The negatively charged electrode (cathode) receives electrical current (i.e., electrons), which travels there and combines with the components of the solution to convert them (reduced).

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The total atmospheric pressure of the final product in the flask is 18.36atm

Atmospheric pressure can be defined as the force exerted on a surface by the air above it as gravity pulls it to earth.

Furthermore, the standard atmosphere is a unit of pressure which is also defined as:

101,325 Pa =760mmHg

So therefore, the total pressure of the final product in the flask is 18.36atm

Complete question:

Gaseous iodine pentafluoride, IF₅, can be prepared by the reaction of solid iodine and gaseous fluorine:

I₂(s) + 5F₂(g) → 2IF₅(g)

A 10.00 L flask is charged with 19.0 grams of I₂ and 2.00 atm of F₂ at 25°C. The flask is heated to 100°C until one of the reagents is completely consumed. What will be the total pressure (in atm) of the final products in the flask at 100°C? (Assume ideal gas behavior)

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Orbits do the proton complete:

A proton exits the cyclotron 1. 0 ms after starting its spiral trajectory in the center of the cyclotron and 1.8 x [tex]10^{4}[/tex] orbits does the proton complete during this 1. 0 ms

Calculation:

(a) The kinetic energy of the proton is given by, K.E. = [tex]\frac{1}{2} m v^{2}[/tex]

v = [tex]\sqrt{\frac{2(K E)}{m}}[/tex]

v = [tex]\sqrt{\frac{2(6.5 \mathrm{MeV})\left(1.6 \times 10^{-19} \mathrm{~J} / \mathrm{eV}\right)}{1.672 \times 10^{-27} \mathrm{~kg}}}[/tex]= 3.5 [tex]\times 10^{7} \mathrm{~m} / \mathrm{s}[/tex]

The radius of the orbit is given by,

r = [tex]\frac{m v}{B q}=\frac{1.672 \times 10^{-27} \mathrm{~kg}\left(3.5 \times 10^{7} \mathrm{~m} / \mathrm{s}\right)}{(1.2 \mathrm{~T})\left(1.6 \times 10^{-19} \mathrm{C}\right)}[/tex] = 0.30 m

Hence, the diameter of the largest orbit just before the proton leaves the orbit is 0.60 m.

(b) The time required to complete one revolution is given by, T=[tex]\frac{2 \pi m}{B q}=\frac{2 \pi\left(1.672 \times 10^{-27} \mathrm{~kg}\right)}{(1.2 \mathrm{~T})\left(1.6 \times 10^{-19} \mathrm{C}\right)}[/tex] =5.48 x [tex]10^{-8}[/tex] s

The number of revolutions made by the proton is given by,

Tn = t

Therefore, n = t/T = [tex]\frac{1 \mathrm{~ms}}{5.48 \times 10^{-8} \mathrm{~s}}[/tex] = 1.8 x [tex]10^{4}[/tex]

Note: your question is incomplete, but most probably your full question was, A medical cyclotron used in the production of medical isotopes

accelerates protons to 6.5 MeV. The magnetic field in the

cyclotron is 1.2 T.

a. What is the diameter of the largest orbit, just before the protons

exit the cyclotron?

b. A proton exits the cyclotron 1.0 ms after starting its spiral

trajectory in the center of the cyclotron. How many orbits

does the proton complete during this 1.0 ms?

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All three types of charge can be separated by the use of electrostatic field.

There are three kinds of rays that are basically discussed when we talk about radioactivity and they are alpha, beta and gamma rays.

Now we know that an alpha ray is positively charged, a beta ray is negatively charged while a gamma ray is not charged. This means that all three types of charge can be separated by the use of electrostatic field.

The gamma rays passes through the field without deflation , the alpha ray is deflated towards the negative part of the field, the beta rays is deflated towards the positive part of the filed.

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A photon has an energy of 2.88 × 10⁻¹⁸ J. The energy into eV is 17.97 eV.

The energy which is carried by a single photon is called Photon energy.

It is expressed as:

E = hf

where,

E = Photon energy

h = Planck's energy

f = Wave frequency

To convert J into eV

E(eV) = E(J) × 6.241509 × 10¹⁸

         = 2.88 × 10⁻¹⁸ × 6.241509 × 10¹⁸

         = 17.97 eV

Thus from the above conclusion we can say that A photon has an energy of 2.88 × 10⁻¹⁸ J. The energy into eV is 17.97 eV.

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Answer:

1.8 x 10²⁴ atoms Ag

Explanation:

You can find the amount of silver (Ag) atoms by multiplying the moles by Avogadro's number. It is important to arrange the conversion in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 2 sig figs to match the sig figs of the given value.

Avogadro's Number:

6.022 x 10²³ atoms = 1 mole

3.0 moles Ag           6.022 x 10²³ atoms
----------------------  x  --------------------------------  = 1.8 x 10²⁴ atoms Ag
                                           1 mole

Answer:

R = 8.314 pKa*L/mol*K

The value for the ideal gas constant (R) is approximately 8.314 kPa·L/(mol·K).

To determine the value for the ideal gas constant (R) when pressure (P) is in kilopascals (kPa), temperature (T) is in kelvins (K), volume (V) is in liters (L), and amount of gas (n) is in moles, we need to use the appropriate units for R based on these measurements.

The ideal gas constant, R, can be expressed in various units. The most common units for R are:

R = 0.0821 L·atm/(mol·K) (atmospheres, liters, moles, and kelvins)

However, since you provided the measurements in kilopascals, liters, moles, and kelvins, we need to use a different value for R that is consistent with these units:

R = 8.314 kPa·L/(mol·K)

Therefore, when pressure is in kilopascals, volume is in liters, amount of gas is in moles, and temperature is in kelvins, the value for the ideal gas constant (R) is approximately 8.314 kPa·L/(mol·K).

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Inert gas does not affect the equilibrium position:

It is because the partial pressures of the reaction components remain the same.

What is Inert Gas?

The equilibrium position won't change if an inert gas is added. A volume change won't change the equilibrium position if the total moles of gas in the products and reactants are the same. When the volume is reduced, the process changes to create fewer moles of gas.

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Answer:

Iron ore, coke and lime stone are some raw materials used for extracting iron.

Hope it helps! :)

All light being the same whether it comes from the sun a light bulb or

anywhere is False.

This is a type of kinetic energy which makes light to be visible to the eyes.

There are different sources of light which include:

• Electric bulb

Light from bulbs and Sun involve photons being emitted at different intensities which is why the light from both sources are different.

The Sun has more intensity and a different

intensities which is why the light from both sources are different.

The Sun has more intensity and a different source than the Light bulb.

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Seconds (s)

Liters (L)

SI units relate to the International System of Units. These units are the base, metric units that are most commonly accepted for different measurements.

Common SI Units

The most common SI units are as follows:

*Note that gram (g) is not an SI unit

Each type of measurement will only have 1 SI unit. This is the unit that will be expected for most answers. Sometimes this means converting an answer into a different unit so it is more widely accepted.

Why SI Units are Important

SI units are important for the same reason that the metric system is used. It gives a standardized list of measurements that scientists across the world can use. Also, it makes it easier to compare scientific findings and studies when all of the measurements are given in the same units.

There are times when it is unrealistic to use SI units. For example, when discussing space, using meters will not be realistic due to the size of space. Also, when measuring the mass of small elements, kilograms are too large. But otherwise, SI units should be used.

Answer:

pH = 13.41

Explanation:

You can calculate the pH using the following formula:

pH + pOH = 14

You can plug the given pOH into the equation and simplify to find the pH.

pH + pOH = 14

pH + 0.59 = 14

pH = 13.41

The answer is 58.4 g of H₃PO₄

Given that mass of Ca₃(PO₄)₂ is 153g

mass of H₂SO₄ is 87.6g

We need to calculate the mass of H₃PO₄

So the balanced chemical reaction is

Ca₃(PO₄)₂  +  3H₂SO₄  ⇒   3CaSO₄  +  2H₃PO₄

Let us calculate the molar mass of the reactants

Ca₃(PO₄)₂ = (3 x 40) + (2 x 31) + (8 x 16)

= 120 + 62 + 128

= 310 g

H₂SO₄ = (1 x 2) + (32 x 1) + (16 x 4)

= 2 + 32 + 64

= 98 g

Now let us calculate the limiting reactant

The Theoretical Yield =  Ca₃(PO₄)₂ / H₂SO₄

= 310 / 3(98)

= 1.05

The Experimental yield

Ca₃(PO₄)₂ / H₂SO₄

= 153 / 87.6 = 1.74

Because the observed percentage was more than the predicted proportion, H2SO4 is the limiting reactant.

Let us Calculate the molar mass of H₃PO₄

H₃PO₄ = (1 x 3) + (31 x 1) + (16 x 4)

= 3 + 31 + 64

= 98 g

Now Calculate the mass of H₃PO₄

3(98) g of H₂SO₄ ------------------ 2(98) g of H₃PO₄

87.6 g of H₂SO₄ ------------------  x

x = ( 87.6 x 2 x 98) / (3 x 98)

x = 17169.6 / 294

x = 58.4g of H₃PO₄

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Answer:

is there an option for silver? if so, silver is the answer.

The reactants are not good a good substitute for sodium azide in airbags because sodium bicarbonate and acetic acid produces far less volume of gas than sodium azide.

The chemical equation of the reactions is given below:

The molar volume of all gases is 22.4 L

Based on the mole ratio, sodium bicarbonate and acetic acid produces far less volume of gas than sodium azide. Thus, the reactants are not good a good substitute for sodium azide.

In conclusion, the molar volume of gases is constant.

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Water cycle simply refers to the continuous movement or flow of water from the atmosphere to the earth and back to the atmosphere

These are the basic stages through which water passes. These stages are:

So therefore, water cycle simply refers to the continuous movement or flow of water from the atmosphere to the earth and back to the atmosphere

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The option that has little bearing on whether profitable opportunity exists is option c) How many companies in the industry have expanded their plant capacity since Year 10 because it is not detailed enough.

Decision making is known to be a term that connote the method or act that is based on making the right and best decision among the numbers of alternative available.

Note that  It includes the act of classifying and knowing the best on the use of preference, belief, and others.

Therefore, the option that has little bearing on whether profitable opportunity exists is option c) How many companies in the industry have expanded their plant capacity since Year 10 because it is not detailed enough.

See full question below

Which one of the following has little bearing on whether profitable opportunity exists to build additional plant capacity in the upcoming decision round?

a) Whether data in the most recent FIR indicates that unsold inventories of branded footwear were so disturbingly high that many of these unsold pairs were cleared from company inventories at money-losing prices.

b) Whether the most recent year's FIR shows that ample production capacity already exists to supply the combined demand for branded footwear and private-label footwear three years from now.

c) How many companies in the industry have expanded their plant capacity since Year 10.

d) How potential global supply of footwear in the upcoming year compares with expected global demand

e) Whether the branded pairs available for sale in the most recent year (as reported in FIR)

exceeded global branded demand and, if so, by how much.

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