Answer: C. Melting Ice
Explanation: The rest are chemical changes, the ice is the same substance (water), just changing physical forms, solid --> liquid
The law of conservation of mater states that
matter can both be destroyed and created.
matter can be created but not destroyed.
matter can be destroyed but not created.
matter cannot be created or destroyed.
The law of conservation of matter states that d. matter cannot be created or destroyed.
What is the law of conservation of matter?
The law of conservation of matter is a model well sustained by scientific evidence which indicated that matter and energy are interchangeable but they can't be created or destroyed under any type of circumstance in space.
Therefore, with this data, we can see that the law of conservation of matter indicated it is unique and therefore cannot be created in the universe under normal conditions.
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complete each of the following equations regarding diffusion of two gases, a and b.
Diffusion is the spontaneous movement, equations regarding diffusion of two gases, a and b like a into b or b into a or a and b into a container are as follows:-
1. Diffusion of gas a into gas b:
a (gas) → b (gas)
2. Diffusion of gas b into gas a:
b (gas) → a (gas)
3. Diffusion of gas a and gas b into a container with a partition:
a (gas) + b (gas) → a (gas) + b (gas) (on opposite sides of partition)
4. Diffusion of gas a and gas b through a membrane:
a (gas) + b (gas) → a (gas) + b (gas) (on opposite sides of the membrane)
5. Diffusion of gas a and gas b into a container without a partition:
a (gas) + b (gas) → mixture of a and b (gas)
It's worth noting that diffusion is the spontaneous movement of particles from an area of higher concentration to an area of lower concentration until equilibrium is reached.
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Question - complete each of the following equations regarding diffusion of two gases, a and b.
1. Diffusion of gas a into gas b
2. Diffusion of gas b into gas a
3. Diffusion of gas a and gas b into a container with a partition.
4. Diffusion of gas a and gas b through a membrane.
5. Diffusion of gas a and gas b into a container without a partition:
What mass of sodium hydroxide is required to make 200 cm^3 of sodium hydroxide solution of concentration 0.4 mol/dm^3.
0.4 g
3.2 g
8.0 g
16.0 g
The mass of sodium hydroxide required to make 200 cm³ of sodium hydroxide solution of concentration 0.4 mol/dm³ is 3.2 g/
The correct option is B.
What is the molar concentration of a solution?In terms of the amount of material per unit volume of solution, molar concentration is a measurement of the concentration of a chemical species, specifically a solute in a solution. The most frequent measure of molarity in chemistry is the number of moles per liter, denoted by the unit symbol mol/L or mol/dm³ in SI units.
Mathematically;
Molar concentration = number of moles/volume in liters
Hence: the number of moles = molar concentration * volume in liters
The number of moles of sodium hydroxide in the solution will be:
number of moles = 0.4 * 200 * 1/1000
number of moles = 0.08
The mass of sodium hydroxide required is obtained from the formula below:
mass = number of moles * molar mass
molar mass of sodium hydroxide = 40 g/mol
Mass of sodium hydroxide required = 0.08 * 40
Mass of sodium hydroxide required = 3.2 g
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draw the structure of the product of the enamine formed between acetophenone and pyrrolidine.
The product of the enamine formed between acetophenone and dimethyl pyrrolidine, as a nucleophile, dimethyl pyrrolidine attacks the carbonyl in this situation to produce the enamine.
How enamines are formed?Secondary amines react with carbonyl compounds to produce enamines as a byproduct. The secondary amines pyrrolidine, piperidine, and morpholine are frequently used to create enamines. Enamines act as nucleophiles and cause an alkylation at a position corresponding to a carbon atom in the original carbonyl compound.
Due to the absence of the additional nitrogen atom required for imine formation, secondary amines form a distinctly different functional group following nucleophilic addition. A hydrogen atom is taken out of a carbon next to it during this reaction, creating a C=C bond.
Structure of the product of the enamine formed between acetophenone and pyrrolidine is attached below.
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use appendix b in the textbook to calculate the binding energy of 2/1h (deuterium).
The nuclear binding energy per nucleon for deuterium, ab/A, can be calculated by multiplying the mass defect m by the mass-energy equivalent 8 931.4941 MeV u1 and dividing the result by two to account for the deuterium mass number A.
A neutron weighs 1.6749 x 10-27 kg and a proton weighs 1.6726 x 10-27 kg, respectively. 2) Subtract the known nucleus mass. = 36 x 10-14 J = 3.6 x 10-13 J E. One deuterium nucleus and one tritium nucleus combine to form deuterium-tritium fusion, a type of nuclear fusion that releases one helium nucleus, one free neutron, and 17.6 MeV of energy. The binding energy is the amount of energy necessary to disassemble the nucleus into its component parts.
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The process by which solute dissolves in solvent is typically a chemical change: Determine whether this statement is true or falsel True False
Yes, it is adjust since when salute may be a break up when salute is broken down into the dissolvable, then it'll frame the arrangement, at that point it'll frame the arrangement. So it has changed the chemical property.
May be a solute dissolving in a dissolvable a chemical change?The dissolution of a solute in a dissolvable to create a arrangement does not include a chemical change (that it could be a physical alter). Disintegration of a solute in a dissolvable to create a arrangement does not include a chemical change.
What is the method of dissolving solute to the solvent?Solvation, or disintegration, is the method by which a solute breaks up into a dissolvable.
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Which of the following solvents would be good to use for 1H NMR analyses? A. chloroform-d B. dimethyl sulfoxide C. acetone D. deuterium oxide E. acetone-d6.
Options (c), (d), and (e) are correct. The solvent that can be used for proton NMR analyses would be chloroform-d, acetone-d6, and deuterium oxide. This is because all the above solvents are deuterated.
What is 1H NMR analyses?The use of nuclear magnetic resonance in NMR spectroscopy with respect to hydrogen-1 nuclei within a substance's molecules in order to ascertain the structure of its molecules is known as proton nuclear magnetic resonance (proton NMR, hydrogen-1 NMR, or 1H NMR). In terms of NMR interpretation, it is crucial to comprehend the chemical shift trend. Nearness to electronegative atoms (O, N, halogen) and unsaturated groups (C=C, C=O, aromatic) affects the proton NMR chemical shift. Moving to the down field are electronegative groupings (left; increase in ppm).Alternatives (c), (d), and (e) are accurate. Chloroform-d, acetone-d6, and deuterium oxide are suitable solvents for proton NMR studies. Because all of the aforementioned solvents are deuterated, this is.To learn more about 1H NMR analyses refer to:
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When an air bubble rises in water, what happens to its mass, volume, and density?
When an air bubble rises in water, it's mass remains same whereas density decreases and volume increases.
What happens to mass, volume, and density when an air bubble rises in water?When an air bubble rises in the water, then mass of the air in the bubble does not change. The volume of bubble increases as the pressure on it decreases. Volume of the bubble becomes almost 1.6 times to initial volume of bubble.
Pressure decreases as as it ascends, less water is above it that is pressing down on it. As, the mass is unchanging but volume is increasing, then the density decreases.
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draw a structure, with a formula of c4h10o, which has an integration of 6h, 2h, 1h, and 1h.
Hydrocarbons 6H, 2H, 1H, and 1H are all present as constituents of the molecule C4H10O.
What does a double bond equate to using an example?The double bond equivalent, to put it simply, is the ratio of the number of double bonds and triple bonds present in organic compounds. Consider the case of benzene, which has four double bonds, or three double bonds and one ring.
a type of chemical connection when two atoms within the same molecule share two pairs of electrons (see single bond, triple bond).
We must first determine the double bond equivalent, which is equal to C – H/2 + 1.
To C4H10O
Double-bond equivalent: 4 - 10/2 + 1
equivalent of a double bond is zero
Both rings and the double bond don't exist.
So it is an aliphatic molecule with four different proton kinds.
The compound given is attached below with its structure.
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Use bond energies to predict Δ H for the isomerization of methyl isocyanide to acetonitrile. C H 3 N ≡ C ( g ) → C H 3 C ≡ N ( g )
The isomerization of methyl isocyanide to acetonitrile is an exothermic process with a predicted enthalpy change of -287 kJ/mol.
Write about isomerization of methyl isocyanide.The isomerization of methyl isocyanide to acetonitrile is a complex process that involves breaking several bonds and forming new ones. The enthalpy change (ΔH) for this process can be estimated by considering the bond energies of the bonds that are broken and formed during the reaction.
The process involves breaking a C-N triple bond and forming a C-C single bond, and a C-N single bond. The bond energies of these bonds are:
C-N triple bond: 945 kJ/mol
C-C single bond: 347 kJ/mol
C-N single bond: 311 kJ/mol
To predict the enthalpy change for the reaction, we can use the following equation:
ΔH = (bonds formed) - (bonds broken)
The bonds that are broken are the C-N triple bond and the bonds that are formed are the C-C single bond and the C-N single bond.
ΔH = (347 kJ/mol + 311 kJ/mol) - (945 kJ/mol) = -287 kJ/mol.
Therefore, the isomerization of methyl isocyanide to acetonitrile is an exothermic process with a predicted enthalpy change of -287 kJ/mol.
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3. A certain atom in the 2nd period has an unusually high 3rd ionization energy. Name this
element. Draw a Bohr diagram and use it to illustrate why you were able to identify this
atom.
Answer:
he element is Neon (Ne).
Neon's unusually high third ionization energy is due to its stable electron configuration. On a Bohr diagram, Neon has two electrons in the 1s orbital, eight electrons in the 2s and 2p orbitals, and two electrons in the 3s orbital, giving it a complete shell of eight electrons (a stable configuration). This means that it takes more energy to first remove an electron from the third orbital, accounting for its unusually high 3rd ionization energy.
Neon (Ne), which is in the second period and possesses an incredibly high third ionization energy, is the element.
What is neon?The persistent electron structure of neon contributes to its very high third ionization energy. Neon has two electrons in the 1s orbital, eight electrons in the 2s and 2p orbitals, two electrons in the 3s orbital, and a total of eight electrons in the entire eight-element shell on a Bohr diagram (a stable configuration).
As a result, the explanation for the exceptionally high third ionization energy is that it requires more energy to first remove an electron from the third orbital.
Chemically speaking, neon is an element with the symbol Ne and atomic number 10. Noble gas describes it. Under normal circumstances, neon is a colorless, odorless, inactive monatomic gas, with roughly two-thirds of its mass.
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Draw the structure of 3-lodo-2,2,4,4-tetramethylpentane.
• Show stereochemistry only if given in the name.
• You do not have to explicitly draw H atoms.
• If a group is achiral, do not use wedged or hashed bonds on it.
• In cases where there is more than one answer, just draw one.
the structure of 3-lodo-2,2,4,4-tetramethylpentane is shown in the below image.
Tetramethylpentane is a hydrocarbon compound with the molecular formula C8H18. It is a saturated aliphatic compound, which means it is composed of only carbon and hydrogen atoms and has no double or triple bonds. It is also a branched-chain compound, meaning that its carbon atoms are connected in a branching pattern. It is a liquid at room temperature and is used as a reference fuel in engine research.A hydrocarbon is a compound that is composed of only carbon and hydrogen atoms. Hydrocarbons can be classified into two main categories: saturated and unsaturated. Saturated hydrocarbons are compounds that have only single bonds between carbon atoms and are therefore considered "fully saturated" with hydrogen atoms.
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Q3 Compare the pH of the milk sample and the pH at which the casein solid forms. Q4 How does a change in pH affect the structural levels of a protein?
Milk — pasteurized, canned, or dry — is an acid-forming food. Its pH level is below neutral at about 6.7 to 6.9. This is because it contains lactic acid.
What is the pH of the milk?However, keep in mind that more essential than the precise pH level is whether it is acid-forming or alkaline-forming. Additionally acid-forming dairy products include butter, hard cheeses, cottage cheese, and ice cream. Despite having low pH values between 4.4 and 4.8, yoghurt and buttermilk are foods that contribute to alkalinity.
Raw milk is another exception, according to the American College of Healthcare Sciences, as it may generate an alkaline environment. However, drinking untreated milk might not be a good idea.
The taste of milk is not acidic. It's even suggested as a treatment for heartburn or acid reflux. Milk might provide symptom relief momentarily. This is so that the oesophagus and stomach can be protected by the fat in milk.
Milk consumption, however, could exacerbate heartburn symptoms. Milk increases stomach production.
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Draw the structure of:
5,5-dibromo-2-methyloctane
The bond line and condensed formulae for 3-methyloctane are provided below.
What is meant by methyl octane?Pentane is an alkane that has a methyl group replaced at position 3 to make 3-methylpentane. It serves as a lubricant, a solvent in the synthesis of organic compounds, and a starting point for the production of carbon black. It serves as an allelochemical, a non-polar solvent, and a human metabolite.
Condensed structural formula: This is a formula where the atoms are also shown and no lines are used to indicate where bonded atoms are located. Straight lines are used to write it.
The line-angle formula, also known as the bond line formula, represents the carbon atoms at the corners and ends of the lines with an angle while concealing the hydrogen atoms. Below are the bond line and condensed formulas for 3-methyloctane.
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The following is part of a molecular orbital energy-level diagram for MOs constructed from 1s atomic orbitals. For which of the following molecules or ions could this be the energy-level diagram: Check all that apply. H2 He2 H^+2 He^+2 H^-2
According to the theory behind molecular orbitals, molecule orbitals are created by combining atomic orbitals with similar energies and symmetry. Combining atomic and molecular orbitals equals the number of orbitals in an atom.
What is meant by molecular orbital energy-level?Atomic and molecular orbitals resemble one other greatly: They are filled in order of lowest to maximum energy (Aufbau principle). They can hold up to two electrons with opposing spins in each orbital (Pauli exclusion principle). Similar to how electrons in an atom are filled in an energy state known as atomic orbitals, molecules have new energy states called molecular orbitals that house their electrons. The molecular orbital predicts the likelihood that an electronic distribution would be found around a collection of nuclei in a molecule. The number of manufactured molecular orbitals is equal to the number of atomic orbitals that were employed to produce them.In[tex]$\mathrm{H}_2^{-}$[/tex]each hydrogen atom contains one electrons and one electron is counted from negative charge, thus total number of electrons present in [tex]$\mathrm{H}_2^{-}$[/tex]is 3. The bonding molecular orbital consists of two electrons, while in antibonding molecular orbital, one electron is present.
The bond order of molecules is calculated by respective formula:-
Bond order [tex]$=\frac{1}{2}\left[\mathrm{~N}_{\mathrm{B}}-\mathrm{N}_{\mathrm{A}}\right]$[/tex]
Where,
[tex]- $\mathrm{N}_{\mathrm{B}}=$[/tex] Number of electrons present in bonding molecular orbital.
Bond order of [tex]f $\mathrm{H}_2^{-}=\frac{1}{2}\left[\begin{array}{ll}2 & -1\end{array}\right]$[/tex]
Bond order of [tex]$\mathrm{H}_2^{-}=\frac{1}{2}$[/tex]
Bond order of[tex]$\mathrm{H}_2^{-}=0.5$[/tex]
[tex]- $\mathrm{N}_{\mathrm{A}}=$[/tex] Number of electrons present in anti-bonding orbital.
The molecular orbital diagram [tex]$\mathrm{H}_2^{-}$[/tex] is shown below-
When light is used to treat [tex]$\mathrm{H}_2^{-}$[/tex], the electron in the bonding molecular orbital becomes excited and travels toward the antibonding molecular orbital. As a result, one electron is present in the bonding molecular orbital and two electrons are present in the antibonding molecular orbital following electron excitation. This is not stable since the bond order is negative.H 2's molecular orbital diagram when light is present,
Bondorderof [tex]$\mathrm{H}_2^{-}=\frac{1}{2}\left[\begin{array}{ll}1 & -2\end{array}\right]$[/tex]
Bondorderof [tex]$\mathrm{H}_2^{-}=\frac{-1}{2}$[/tex]
Bondorderof [tex]$\mathrm{H}_2^{-}=-0.5$[/tex]
Since the value of bond order is negative, the [tex]$\mathrm{H}_2^{-}$[/tex]ion is not stable in the presence of light.
The complete question is,
Sketch the molecular orbitals of the[tex]$\mathrm{H}_2{ }^{-}$[/tex]ion and draw its energy level diagram. Suppose that the ion is excited by light, so that an electron moves from a lower-energy to a higher-energy molecular orbital. Would you expect the excited-state [tex]$\mathrm{H}_2{ }^{-}$[/tex]ion to be stable?
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a sample of n2(g) effuses through a tiny hole in 38 s. What must be the molar mass of a gas that requires 64 s to effuse under identical conditions?
Therefore, 450.56 g/mol is the molar mass of the unidentified gas.
Which gases will quickly effuse via a tiny hole?The average kinetic energy of all gaseous molecules is equal at a given temperature. The lowest mass of these gases, hydrogen gas, will have the highest average velocity. As a result, it will escape the small opening more quickly than the other gases.
The rate of diffusion is the change in molecules that diffuse over time. Inverse to the square root of the volume is the diffusion rate of a gas (density). The formula for rate of diffusion is hence rate of diffusion 1density.
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What volume of 12.0 M HCl is required to make 75.0 mL of 3.50 M HCI? 21.9 mL B) 0.560 mL C) 257 mL D) 560. mL E) none of the above Answer: A Show your calculations below:
To make 75.0 mL of 3.50 M HCI, 21.9 mL of 12.0 M HCl must be added. The letter A, 21.9 mL, is the right response among the options.
What is the straightforward meaning of volume?The space consumed within an object's borders in three dimensions is referred to as its volume. It is sometimes referred to as the object's capacity.
What is volume, for instance?The potential of an object is gauged by its dimensions. For instance, a cup's capacity is stated to really be 100 ml if it can accommodate 100 ml of distilled water in its brim. The quantity of volume occupied by a three-dimensional object can also be used to describe volume.
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Will the following bases favor an E1 or E2 mechanism? Sort them into the appropriate boxes below. Table Bases (6 items)(Drag and drop into the appropriate area below) a. NaH b. H20 c. CH3CH2OH d.NH2 e. tBuo f. CH3CO2
The number of stages in the mechanism is the easiest method to tell the difference between E1 and E2.
What favors an E2 reaction?Strong bases support the E2 mechanism while merely a weak base is necessary for the E1 mechanism. 2) The solvent: Effective ionising solvents (polar protics) support the E1 process by stabilising the intermediate carbocation.
The base's composition plays a crucial role in an E2 reaction since it is involved in the step that determines rate. More reactive bases will encourage an E2 reaction.
Steps in the process. Counting the steps in the mechanism is the most straightforward approach to tell E1 from E2 in a system. In contrast to E2, which occurs in a single step without an intermediate step, E1 involves two stages and a carbocation intermediate.
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2. In step 1 of the procedure we will use 10 mL of cold water (20 °C) to dissolve the salt. Will any benzoic acid dissolve in this water? How can this be detected with litmus paper?
Answer:
Explanation:
Benzoic acid is a weak acid and is slightly soluble in water. It will dissolve in cold water to a certain extent, but not completely. This can be detected by using litmus paper. Blue litmus paper will turn red when it comes into contact with an acidic solution, indicating the presence of benzoic acid. Therefore, it can be detected that benzoic acid will dissolve in cold water to a certain extent but not completely.
Write the balanced nuclear equation for the formation of 203 83 Bi through a decay.
The balanced nuclear equation for the formation of ²⁰³Bi (83) through a decay is ²⁰⁷At(87) → ²⁰³Bi(83) + ⁴He(2)(alpha)
What exactly is a nuclear equation?In nuclear fusion, nuclear fission, and radioactive decay, the reactants and products are represented by nuclear equations. Nuclear reactions show the conservation of atomic mass and proton number rather than the different number of elements as in chemical equations.
Nuclear reactions can be divided into three categories:
Nuclear fusion is the joining of two tiny atomic nuclei to form a single larger nucleus.
Nuclear fission is the division of an enormous atomic nucleus into smaller pieces.
The transformation of a less stable nucleus into a more stable nucleus is known as radioactive decay.
²⁰⁷At(87) → ²⁰³Bi(83) + ⁴He(2)( alpha )
final product mass = 243-4-0-4 = 235
final product atomic number = 95-2+1-2 = 92
hence final product 235U(92)Â.
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Calculate the ratio of imidazole to the imidazolium ion in a solution at pH 7.4.
2.5 to 1. Imidazolium ion will deprotonate to imidazole at pH 7.4 because it is more basic than pKa, which results in more imidazole being present overall.
What is imidazole used for?Imidazole becomes charged when it is protonated (i.e., in acid or HA+ form). It is uncharged when it is in its deprotonated (basin or A) form. Therefore, the uncharged:charged species ratio is [A][HA+], or 10:1.
The chromatography column's beads that are coated with nickel ions to which tagged proteins are bound are eluted using imidazole. In order to release the His-tagged proteins from nickel coordination, too much imidazole is delivered through the column. This causes the His-tag to be dislodged from nickel coordination.
2.5 to 1. Imidazolium ion will deprotonate to imidazole at pH 7.4 because it is more basic than pKa, which results in more imidazole being present overall.
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What are the types of plasma enzymes?
The following initial rates data were obtained for 5Br1- + BrO31- + 6H1+ 3Br2 + 3H2O EXP [Br1-]o [BrO31-]o [H1+]o -[Br1-]/ t (M/s) 1 0.130 0.150 0.270 8.10e-03 2 0.195 0.150 0.270 1.22e-02 3 0.130 0.300 0.270 1.62e-02 4 0.130 0.150 0.675 5.06e-02 What are the reactant orders? Order of Br1- = Order of BrO31- = Order of H1+ = What are the units of the rate constant. Use exponents but no superscript. Separate M and s with a space. For example, use M-5 s-2 to indicate M-5·s-2. What is the value of the specific rate constant for the reaction (no units)? Hint: the rate constant for the reaction is not the same as the rate constant for the disappearance of Br1-. k =
The value of the specific rate constant for the reaction is 0.0426 (M/s)^3. To determine the reactant orders, we need to use the initial rate data and the method of initial rates.
The method of initial rates involves changing the concentration of one reactant while keeping the other reactants constant. From the initial rate data, we can see that when [Br1-] is changed, the rate of the reaction changes (experiments 1, 2, and 3). Therefore, the order of Br1- is not zero. When [BrO31-] is changed, the rate of the reaction changes (experiments 2 and 3). Therefore, the order of BrO31- is not zero. When [H1+] is changed, the rate of the reaction changes (experiments 1, 2, and 4). Therefore, the order of H1+ is not zero.
From this, we can conclude that the reactant orders are:
= Order of Br1- = 1
= Order of BrO31- = 1
= Order of H1+ = 1
The rate constant k is the proportionality factor between the rate of the reaction and the concentrations of the reactants. The units of k depend on the reactant orders. Since the overall order of the reaction is the sum of the individual reactant orders, in this case the overall order of the reaction is 1+1+1=3. Therefore, the unit of k is (M/s)^3.
To find the value of the specific rate constant for the reaction, we can use the following equation:
= -d[Br1-]/dt
= k[Br1-][BrO31-][H1+]
By substituting the experimental value of the initial rates, we can find the specific rate constant for the reaction.
= -d[Br1-]/dt
= k[Br1-][BrO31-][H1+]
= 8.10e-03
= k10.1300.1500.270
= k
= 8.10e-03/(10.1300.150*0.270)
= k
= 0.0426
The specific rate constant for the reaction is 0.0426 (M/s)^3. It's worth to mention that the rate constant for the disappearance of Br1- is not the same as the rate constant for the reaction because it only consider the disappearance of one of the reactants, but the rate constant for the reaction consider all the reactants.
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What is the purpose of cell respiration?
to breath in food
to expel unwanted oxygen
to produce energy from food
Answer:
To produce energy from food
Explanation:
It's pretty much an energy cycle
Use kinetic molecular theory to describe the changes in temperature, particle motion, and kinetic energy when thermal energy is added to solid chocolate. Be sure to explain the process by describing how the particles in chocolate move relative to each other in both the solid and liquid state, as well as what happens during the phase change. Then describe the changes in particle motion, temperature, and kinetic energy when liquid chocolate is poured into a mold.
Matter is said to be made up of particles that are constantly moving. All particles have energy, but the energy has a variation depending on the temperature the sample of matter is in.
What is kinetic energy?The kinetic energy of an object is the energy that it possesses due to its motion and is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity.
All particles have energy and in turn the phenomena determines whether the substance exists in the solid, liquid, or gaseous state. Molecules in the solid phase have the least amount of energy, while gas particles have the greatest amount of energy.
The temperature of a substance is a measure of the average kinetic energy of the particles.
With respect to the changes in particle motion, temperature, and kinetic energy when liquid chocolate is poured into a mold, we can say that a change in phase may occur when the energy of the particles is changed.
There are spaces between particles of matter of the chocolate. The average amount of empty space between the molecules gets progressively larger as the sample of matter moves from the solid to the liquid and gas phases. There are attractive forces between the chocolate molecules, and these become stronger as the particles move closer together.
In conclusion, the attractive forces are called intermolecular forces.
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When a solution of lithium chloride and a solution of ammonium sulfate are mixed O a new salt is formed. O no reaction occurs. O a precipitate forms. O an acid and a base are formed.
Answer:
No reaction occurs
Explanation:
trust me on this one :)
What is the range of
the data?
Experimenter 1
Trial #
1
2
3
Average
Length (cm)
8.4
8.2
8.5
8.37
A. The range is 8.37 cm
B. The range is 25.1 cm.
C. The range is 0.13 cm
D. The range is 0.30 cm
The range of the set of data given in the question above is 0.30 cm (Option D)
How do I determine the range of the data?From the basic knowledge of statistics, we understood that the range of a given data is defined as the difference between the highest value and the lowest value in the data. This is written as follow:
Range = Highest value - lowest value
With the above formula, we can obtain the range of the data given in the question. Details below:
Trail 1 has length of 8.4 cmTrial 2 has length of 8.2 cmTrial 3 has length of 8.5 cmHighest length = 8.5 cmLowest length = 8.2 cmRange =?Range = Highest length - lowest length
Range = 8.5 - 8.2
Range = 0.30 cm
Thus, the range is 0.30 cm (Option D)
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draw the structure of the product of the enamine formed between cyclohexanone and morpholine.
Cyclohexanone (also known as oxocyclohexane, pimelic ketone, ketohexamethylene, cyclohexyl ketone or ketocyclohexane) is a six-carbon cyclic molecule with a ketone functional group.
What is the common name for cyclohexanone?The liquid cyclohexanone has a nice smell and is colourless to pale yellow in appearance. not as dense as water. 111 °F flash point. heavier than air vapours. utilised as a solvent, a chemical reaction media, and to produce nylon. A cyclic ketone called cyclohexanone is made up of cyclohexane with a single oxo group.
It serves as a xenobiotic metabolite for humans. Cyclohexanone is a six-carbon cyclic molecule having a ketone functional group. It is also known as oxocyclohexane, pimelic ketone, ketohexamethylene, cyclohexyl ketone, or ketocyclohexane.
It has an acetone-like scent and is an oily, colourless liquid. In heating systems, conductive liquids like boiler water and heat transfer fluids like morpholin are stabilised by morpholin. As a base that neutralises acid pollution in heat, morpholine serves as one of the main mechanisms by which it accomplishes this.
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What's another name for the magnitude (absolute value) of the change in chemical energy? a) energy output b) efficiency c) power output d) metabolic energy
Here, we'll see at a few sorts of vitality that are especially critical in organic frameworks, counting motor vitality, potential vitality, and chemical vitality (the potential vitality of chemical bonds).
Why does the body utilize chemical energy?They are broken down into fundamental atoms, like amino acids and glucose, which are either utilized as vitality or reassembled and put away in other shapes, like glycogen. The nearness of chemical vitality in nourishment is pivotal to giving our bodies with the vitality they ought to keep us moving and lively.
What sort of vitality is chemical energy?Chemical vitality is vitality put away within the bonds of iotas and atoms. Batteries, biomass, petroleum, normal gas, and coal are cases of chemical vitality. For case, chemical vitality is changed over to warm vitality when individuals burn wood in a chimney or burn gasoline in a car's motor.
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Indicate which orbitals overlap to form the σ bonds in the following molecules.
HgCl2
a.The two sigma bonds form between an s orbital on Hg and a hybrid sp orbital on Cl.
b.The two sigma bonds form between a hybrid sp2 orbital on Hg and a p orbital on Cl.
c.The two sigma bonds form between a hybrid sp3 orbital on Hg and a p orbital on Cl.
d.The two sigma bonds form between a hybrid sp orbital on Hg and a p orbital on Cl.
option d The two sigma bonds form between a hybrid sp orbital on Hg and a p orbital on Cl indicates the orbitals which overlap to form the σ bonds in the following molecules. HgCl2
Sigma bonds are the most powerful type of chemical bond. They are established by atomic orbitals overlapping head-on. For diatomic molecules, sigma bonding is most simply defined to use the language and techniques of symmetry groups. When one s and one p orbital within the same main atom's outer shell combine to form two new equivalent orbitals, this is made reference to as sp hybridization. The recently created orbitals are recognised as sp hybridised orbitals. It produces linear molecules with a 180° angle.
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