Which organelle in the table is correctly matched with its function?
which one is it??

Answer:

a. Endothermic

b. 26.37kJ/mol

Explanation:

a. As we can see, the temperature of the water is decreasing when the reaction is occurring, that means the reaction is absorbing heat and is endothermic

b. To find the enthalpy we must find the change in heat when 12.1g of KCl are dissolved. Using the equation:

Q = -m*ΔT*C

Where Q is change in heat

m the mass of solution (250g + 12.1g = 262.1g)

ΔT is change in heat (17.1°C - 21.0°C = -3.9°C)

And C is specific heat of the solution (4.184J/g°C assuming is the same than the specific heat of water).

Replacing:

Q = -262.1g*-3.9°C*4.184J/g°C

Q = 4277J = 4.28kJ

As reaction enthalpy is the change in heat per mole of reaction, we must find the moles of 12.1g of KCl:

Moles KCl -Molar mass: 74.55g/mol-:

12.1g KCl * (1 mol / 74.55g) = 0.1623 moles KCl

The reaction enthalpy us:

4.28kJ / 0.1623mol = }

Answer:

The Gulf Stream is influential on the climate of the Florida peninsula.East winds moving over this warm water move warm air from over the Gulf Stream inland, helping to keep temperatures milder across the state than elsewhere across the Southeastern United States during the winter.

Explanation:

hope this helps!

Answer:

The Gulf Stream is influential on the climate of the Florida peninsula.East winds moving over this warm water move warm air from over the Gulf Stream inland, helping to keep temperatures milder across the state than elsewhere across the Southeastern United States during the winter.

Explanation:

Hope This Helps!

Answer:

yes solution is always a mixture but not all mixtures are solution

Explanation:

A solution.is a homogeneous mixture of substance that have uniform composition throughout

And a mixture hVe twoo or more substances that are not chemically.combine

Answer:

Answer is explained in the explanation section below.

Explanation:

Definitely, before the invention of spectroscopy, Korner's absolute method had been in use. So, the proposed structure is a diagram, that we can not draw here. Therefore, I have drawn it separately and attached in the attachment below. Please for this answer, refer to the diagram which is a proposed structure attached in the attachment below.

Proposed Structure is:

1,3-Dibromo Benzene.

In the Korner's method, 1,3- Dibromo benzene undergoes nitration process in the presence of HNO3/H2SO4.

The original compound that undergoes nitration is a meta disubstituted aromatic compound.

After nitration, 1,3-Dibromo benzene yields three having chemical formula C6H3Br2NO2.

Answer:

I would be if I do it your no learning anything but I would but I don't have insta yet

Explanation:

sorry

Answer:

k

Explanation:

Answer:

Compound Formula. 1, Carbon dioxide, CO2. 2, Carbon monoxide, CO. 3, Diphosphorus pentoxide, P2O5. 4, Dinitrogen monoxide, N2O.

Explanation:

dont even know by thoAnswer:

Explanation:

Answer:

3.955*10^48

Explanation:

1 mole of a substance gives 6.02*10^23/6.57*10^24 will give x then cross multiply the answer. is 3.955*10^48

Answer:

A. Beginning of the spring

Explanation:

Pa like, Pa follow, Pa rate

Answer:

se que la imaje es un poco confusa con la materia pero

desiaria ayudarte pero CREO que con mi TÉCNICA  es la A

Answer:

D

Explanation:

the charges need to balence out

so finding the LCM which is 12 we find we need 3x's

and 4 zs

so that makes the formula X3Z4 which is D

Answer:

Boiling point in kelvin is 373.1 \

boiling point of liquid hydrogen in kelvin is 21.15

Explanation:

Answer:

0.10 m Al(NO3)3

Explanation:

Let us note that the substance that has the highest freezing point will have the lowest freezing point depression. Since;

ΔTf = Kf m i

ΔTf  = freezing point depression

Kf = freezing point constant

m = molality

i = Van't Hoft factor

Given that the freezing point depression depends on the molality and the Van't Hoft factor (number of particles), we can see that 0.10 m Al(NO3)3 has the least freezing point depression and highest freezing point temperature because it gives the least value of m * i. That is 0.10 m * 4 = 0.4

Answer:

B

Explanation:

Answer:

Well if you want to kiss them go for it, but if you don't then say sorry but I don't feel comfortable with that.

Hope everything goes well <3

Answer:

Exothermic Reaction

Explanation:

Burning wood in air is an exothermic process (it releases heat), but there is an energy barrier, so it requires a bit of heat in the beginning to get the reactions started.

Wood reacts with oxygen in the air to form (mostly) carbon dioxide and water vapor. The process involves many different individual chemical reactions, and it requires some energy to initiate the reactions. This is because it's usually necessary to break some chemical bonds (endothermic) before new stronger bonds can be formed (exothermic). Overall, though, more heat is released in forming the final products than is consumed in starting new reactions.

Have a great day <3

In the given question, a burning log is an exothermic event if the log is the system.

An exothermic reaction releases energy to the surroundings, usually in the form of heat. The change in enthalpy is negative.

When a log burns, it reacts with oxygen in the air to produce carbon dioxide, water vapor, and heat. This heat is released to the surroundings, making the burning log an exothermic event.

Therefore, a burning log is an exothermic event if the log is the system. This is due to the fact that the reaction emits heat into the environment, making it an exothermic reaction.

Learn more about exothermic reaction here:

https://brainly.com/question/28546817

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Answer:

1.39x10⁻⁶ mol

Explanation:

First we convert the gallon of juice to liters:

Then we calculate the mass of antimony that would be in 3.785 L, using the given concentration:

Then we convert mass into moles, using the molecular mass:

Finally we convert μmol into mol:

Answer:

Q = 32,007.6 J

Explanation:

Hello there!

In this case, since the energy involved during a heating/cooling process is:

[tex]Q=mC(T_f-T_i)[/tex]

Thus, given the mass, specific heat of water, initial temperature and final one, we plug in obtain:

[tex]Q=450g*4.184\frac{J}{g\°C} (37.0\°C-20.0\°C)\\\\Q=32,007.6J[/tex]

Best regards!

Answer:

Higher temperature will cause more collisions.

Lower temperature will cause less collisions.

Higher temperature provides more activation energy!

Explanation:

pls mark brainliest :)

Answer:

performing

Explanation:

Answer:

a. pH raises

b. pH neutral

c. pH raises

Explanation:

First of all we need to dissociate these compounds.

Ca(OH)₂ →  Ca²⁺  +  2OH⁻

This is the calcium hydroxide, a strong base.

In this case, we are giving OH⁻ to medium, so the pH will be increased.

OH⁻  +  H⁺  ⇄  H₂O

Hydroxides will neutralize the protons in order to make water, but if we have many OH, we talk about a basic solution where pH is lower than 7.

b. CuBr → Cu⁺  +  Br⁻

This is similar to NaCl, a ionic salt which is neutral.

The ions from this salt, do not make hydrolisis, that's why pH does not change.

c. Ca₃(PO₄)₂ → 3Ca²⁺  +  2PO₄⁻³

Calcium cathion comes from a strong base. It means, that the ion can not make hydrolisis because it is the conjugate weak acid.

Phosphate anion comes from a weak acid, it can gives OH⁻ to medium so pH will increase; the PO₄⁻³ anion is the conjugate strong base of the phosphoric acid, that's why it can react:

PO₄⁻³ + H₂O  ⇄  H₂PO⁻²  +  OH⁻

Answer:

Explanation:

D or b

Sorry if wrong

Answer:

temporal

Explanation:

Answer:

C - Extrusive igneous

Explanation:

Rhyolite is an extrusive igneous due to the high silica content, the lava is very dangerous.

Answer:

Its C

Explanation:

A P E X

Answer:

% recovery

MP range of product

mass of product

Explanation:

Liquid–liquid extraction (LLE) is a process of transferring one (or more) solute(s) which are present in a feed solution to another immiscible liquid (solvent). The other solvent that becomes enriched in the target solute(s) is called extract. The original feed solution that is depleted in solute(s) is subsequently referred to as the raffinate.

This method is used to purify compounds and  separate mixtures of compounds. This is very important when we want to isolate a product from a reaction mixture.

The percent recovery is the amount of solute that is transferred to the extract. This is the most important data to be recorded in an LLE experiment.

The melting point range necessarily helps us to identify the product and the mass of solid tells us the quantity of the solid obtained after extraction.

The question is missing some parts. Here is the complete question.

Carbon monoxide is a colorless, odorless gas that binds irreversibly to hemoglobin in our blood, causing suffocation and death. CO is formed during incomplete combustion of carbon. One way to represent this equilibrium is:

[tex]2CO_{(g)}[/tex] ⇄ [tex]2C_{(s)}+O_{2}_{(g)}[/tex]

we could also write this reaction three other ways listed below. The equilibrium constant for all of the reactions are related. Write the equilibrium constant for each new reaction in terms of K, the equilibrium constant for the reaction above.

1) [tex]2C_{(s)}+O_{2}_{(g)}[/tex] ⇄ [tex]2CO_{(g)}[/tex]       K₁ =

2) [tex]C_{(s)}+1/2O_{2}_{(g)}[/tex] ⇄ [tex]CO_{(g)}[/tex]    K₂ =

3) [tex]CO_{(g)}[/tex] ⇄ [tex]C_{(s)}+1/2O_{2}_{(g)}[/tex]    K₃ =

Answer: 1) [tex]K_{1}=\frac{1}{K}[/tex]

              2) [tex]K_{2}=\frac{1}{K^{1/2}}[/tex]

             3) [tex]K_{3}=K^{1/2}[/tex]

Explanation: A chemical reaction can be reversible, i.e., can proceed in both directions: to the right of the arrow (forward) or towards the left of the arrow (backward).

When the rates of forward and backward reactions are the same, the reaction is in equilibrium. In that state, we can determine the equilibrium constant, [tex]K_{c}[/tex].

For the first way to represent equilibrium of CO formed, the [tex]K_{c}[/tex] is calculated

[tex]2CO_{(g)}[/tex] ⇄ [tex]2C_{(s)}+O_{2}_{(g)}[/tex]

[tex]K=\frac{[O_{2}]}{[CO]^{2}}[/tex]

in which the symbol [ ] is concentration of the compound.

In equilibrium constant, solids are not included.

Equilibrium constants for the other reactions:

1) [tex]2C_{(s)}+O_{2}_{(g)}[/tex] ⇄ [tex]2CO_{(g)}[/tex]  

[tex]K_{1}=\frac{[CO]^{2}}{[O_{2}]}[/tex]

Comparing K₁ and K, the first one is the inverse of K, so writing in terms of K

[tex]K_{1}=\frac{1}{K}[/tex]

2) [tex]C_{(s)}+1/2O_{2}_{(g)}[/tex] ⇄ [tex]CO_{(g)}[/tex]

[tex]K_{2}=\frac{[CO]}{[O_{2}]^{1/2}}[/tex]

In terms of K, K₂ is

[tex]K_{2}=\frac{1}{K^{1/2}}[/tex]

3) [tex]CO_{(g)}[/tex] ⇄ [tex]C_{(s)}+1/2O_{2}_{(g)}[/tex]

[tex]K_{3}=\frac{[O_{2}]^{1/2}}{[CO]}[/tex]

This constant in terms of K will be

[tex]K_{3}=K^{1/2}[/tex]

In conclusion, K₁, K₂ and K₃ in terms of K is [tex]\frac{1}{K}[/tex],[tex]\frac{1}{K^{1/2}}[/tex] and [tex]K^{1/2}[/tex], respectively.

Answer:

C9H19 C5H12 C6H17 C7H20