Which situation could the probability distribution table represent?

Answer:

Your simply dividing by 11

Step-by-step explanation:

0.008...

0.0007...

0.00006...

All you have to do is turn these numbers into fractions!

Answer:

1/121, 1/1331, 14641

Step-by-step explanation:

121, 11 ,1 , 1/11

We need to find the next three terms in the pattern

We are taking each term and dividing by 11

121/11 =11

11/11 =1

1/11 = 1/11

1/11 divided by 11

1/(11*11) = 1/121

1/121 * 1/11 = 1/1331

1/1331 * 1/11 = 14641

The area of the semicircle = 8π

A semicircle is formed when the panel passing through the center touches both ends of the circle. Therefore, if you connect two semicircles, you get a circle

If you cut them in half or divide the circumference of the circle by 2, you will get a semi-circle. Area of ​​semicircle The area of ​​the semicircle is half the area of ​​the circle. Because the area of ​​the circle is πr2. Therefore, the area of ​​the semicircle is 1/2 (πr2). Where r is the radius. The value of π is 3.14 or 22/7.

Semi-circular area = 1/2 (πr2)

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The box-and-whisker plot for the data can be seen in the attachment.

The data given to us is:

50, 51, 54, 55, 57, 61, 62, 63, 65, 66, 67, 68, 71, 71, 76, 76, 77.

As the data is already ordered from least to greatest, we can apply the formulas.

The sample size, n = 17.

Start point = 50.

First quartile, Q1 = (n + 1)/4 th observation = (17 + 1)/4 th observation = 18/4 th observation = 4.5 th observation = average of the 4th and the 5th observation = (55 + 57)/2 = 112/2 = 56.

Median, Q2 = (n + 1)/2 th observation = (17 + 1)/2 th observation = 18/2 th observation = 9th observation = 65.

Third quartile, Q3 = 3(n + 1)/4 th observation = 3(17 + 1)/4 th observation = 3*18/4 th observation = 54/4 th observation = 13.5 th observation = average of the 13th and the 14th observation = (71 + 71)/2 = 142/2 = 71.

End point = 77.

Thus, the box-and-whisker plot should be designed as follows:

The start of the first whisker is from 50, representing the start point.

The start of the box is from 56, representing the first quartile.

The line inside the box is at 65, representing the median.

The end of the box is at 71, representing the third quartile.

The end of the whisker is at 77, representing the endpoint.

The box-and-whisker plot can be seen in the attachment.

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The worth of the car in 10 years is $1,831.67 using an exponential equation approach.

What is an exponential equation?

An exponential equation is the one with exponents such X^3(the 3 is the exponent)

The exponential equation required here is the one where the future value would be lower than current value because the car reduces in value year-in-year-out.

FV=PV*(1-r)^N

FV=future worth of the car

PV=today's value=$25,000

r=depreciation rate=-23%

N=number of years=10

The fact that r is negative means the car is depreciating not appreciating.

FV=$25,000*(1-23%)^10

FV=$1,831.67

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The measure of the angle is 51 degrees.

If the sum of two angles is ninety levels, then we say that they may be complementary. thus, the supplement of an attitude is received by means of subtracting it from 90. as an example, the supplement of 40° is ninety° - forty° = 50°.

If two attitudes are complementary, the sum in their measure is ninety tiers. So, the measures of the 2 complementary angles are 51 degrees and 39 degrees.

While the sum of angles is equal to ninety ranges, they are known as complementary angles. For example, 30 stages and 60 stages are complementary angles.

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Answer: D

Step-by-step explanation:

Answer:

Step-by-step explanation:

380 rows in total

bcs

use sense

When the completing the square is applied, the rewritten function is (x + 2)^2 = 4

The equation is given as:

x^2 + 4x = 0

The above equation is a quadratic equation and the coefficient of x in the above equation is 4.

So, we have:

k = 4

Divide the variable k by 2

k/2 = 4/2

k/2 = 2

Square the above result

(k/2)^2 = 4

Next, we add 4 to both sides of x^2 + 4x = 0

x^2 + 4x + 4 = 4

Expand the equation by expressing 4x as 2x + 2x

This gives

x^2 + 2x + 2x + 4 = 4

Factorize the above equation

x(x + 2) + 2(x + 2) = 4

Factor out x + 2 from the above equation

(x + 2)(x + 2) = 4

Rewrite the equation as a perfect square of (x + 2)

(x + 2)^2 = 4

Hence, the rewritten function after completing the square is (x + 2)^2 = 4

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The criteria which CBR researchers might use to select and specify which units will be sampled as well as the sampling frame and methods to be used is the population.

This is defined as the total number of organisms found in a particular place at any given point in time and varies based on the number of variables present. In some cases, head counts are done to ascertain the exact value of individuals present.

The probability sampling method is ideal for a large population and involves random selection of the organisms so as to find out the statistical features of the group being used such as the range, mean etc. This tool is very important in the area of giving estimates for  ascertain type of activity or job.

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Answer:

25 miles

Step-by-step explanation:

2 inches represents 10 miles ( divide both parts by 2 )

1 inch represents 5 miles , then

5 inches represents 5 × 5 = 25 miles

The equations which are true for the values of x given are; x²-4 =0 and 4x²= 16.

The values of x given according to the task content are; x = –2 and x = 2.

By considering equation; x²-4 =0

x² = 4

x = ±2

Also, by considering 4x²= 16;

x² = 16/4 = 4

x = ±4.

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Answer:

B.

Step-by-step explanation:

A C and D are not functions as they are one - to - many  whereas B is many-to-one.

In a two-tailed hypothesis test the null hypothesis is rejected.

According to the statement

The test statistic is 3.06 and the critical values are /-2.086.

If we find the value of t by using the formula the then it comes with Negative sign and it lies under the critical region.

That's why In a two-tailed hypothesis test the null hypothesis is rejected.

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The solution set to the inequality 5.1(3 + 2.2x) > –14.25 – 6(1.7x + 4) gives x > -2.5

An equation is an expression that shows the relationship between two numbers and variables.

An independent variable is a variable that does not depend on any other variable for its value whereas a dependent variable is a variable that depend on any other variable for its value.

Inequality shows the non equal comparison of two or more numbers and variables.

Given the inequality:

5.1(3 + 2.2x) > –14.25 – 6(1.7x + 4)

Simplifying:

15.3 + 11.22x > –14.25 – 10.2x - 24

21.42x > -53.55

x > -2.5

The solution set to the inequality 5.1(3 + 2.2x) > –14.25 – 6(1.7x + 4) gives x > -2.5

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The correct form of vector v expressed as a linear combination of the unit vectors i and j is [tex]\vec v = 10\,\hat{i} + 100\,\hat{j}[/tex].

First, we need to determine the value of the vector u by subtracting two vectors whose initial points are at the origin:

[tex]\vec u = (19\,\hat{i} - 8\,\hat{j}) - (21\,\hat{i} + 12\,\hat{j})[/tex]

[tex]\vec u = - 2\,\hat{i} - 20\,\hat{j}[/tex]     (1)

According to the statement, vector v is antiparallel to vector u and its magnitude is five times as the magnitude of vector v, which means that (1) must be multiplied by two scalars:

[tex]\vec v = - 1 \,\cdot \, 5\cdot \vec u[/tex]      (2)

Please notice that antiparallelism is represented by the scalar - 1, whereas the dilation is represented by the scalar 5.

[tex]\vec v = 10\,\hat{i} + 100\,\hat{j}[/tex]

The correct form of vector v expressed as a linear combination of the unit vectors i and j is [tex]\vec v = 10\,\hat{i} + 100\,\hat{j}[/tex].

The statement presents typing mistakes, correct form is shown below:

Vector u has initial points at (21, 12) and its terminal point at (19, - 8). Vector v has a direction opposite that of u, whose magnitud is five times the magnitud of v. Which is the correct form of vector v expressed as a linear combination of the unit vectors i and j?

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The quantity with the fewest number of significant figures.

What is significant figures?

When multiplying two measured values the number of significant figures should be equal to the?

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The causes of variation that can be identified and eliminated are called; Assignable Causes.

There are two primary causes of variation in the quality of a product or process. These two primary causes are called;

Now, Common causes of variation are defined as random causes that we cannot identify. However, Assignable causes of variation are those that can be identified and eliminated.

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The inequality passing through (1, 4), (-2, -2), intersecting the y-axis at 2 units and intersects the x-axis at (-1, 0) to form shaded portions on the left side is y > 2x+2

An equation is an expression that shows the relationship between two or more variables and numbers.

An inequality shows the non equal comparison of two or more numbers and variables.

The inequality passing through (1, 4), (-2, -2), intersecting the y-axis at 2 units and intersects the x-axis at (-1, 0) to form shaded portions on the left side is y > 2x+2

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The equation of the line that is parallel to the given line and passes through the point (-2,2) is:

[tex]y = \frac{x}{5} + \frac{12}{5}[/tex]

A linear function is modeled by:

y = mx + b

In which:

When two lines are parallel, they have the same slope. In this problem, the given line passes through (-5,-4) and (0,-3), hence the slope is:

m = (-3 - (-4))/(0 - (-5)) = 1/5.

Hence the equation is:

[tex]y = \frac{x}{5} + b[/tex]

When x = -2, y = 2, then:

[tex]y = \frac{x}{5} + b[/tex]

[tex]2 = \frac{-2}{5} + b[/tex]

[tex]b = \frac{12}{5}[/tex]

Hence:

[tex]y = \frac{x}{5} + \frac{12}{5}[/tex]

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The events are independent events and probability of tossing a head and drawing a red marble is 1/7

a) The answer is present in the image attached below

b) Tossing of a coin and drawing of a marble are independent events as these two events do not interfere in the probability of each others events.

c) The probability of tossing a head and drawing a red marble is = [tex]\frac{1}{2}.\frac{2}{7}[/tex]=1/7 as we can see from the tree diagram that probability of tossing a coin and getting head is 1/2 and probability of drawing a red marble is 1/7. As they are independent events, their probability can be multiplied. Hence the probability of tossing a head and drawing a red marble is 1/7.

d) The probability of drawing two blue marbles if the first marble is not replaced and one at a time is 1/7. Probability of drawing first blue marble from the lot is 3/7 as favorable outcomes are 3 and total outcomes are 7. As the ball is not replaced the outcomes are changed. Now the number of blue balls are 2 and total number of balls are 6. So now the probability becomes 2/6. Hence the total probability becomes = 1/7

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Postulate: SAS

Similarity statement: [tex]\triangle CAB \sim \triangle EDF[/tex]

Answer:

x = 8

Step-by-step explanation:

[tex]\frac{9x}{4y}=1[/tex]

[tex]\frac{9x}{4*18} =1[/tex]

9x = 72

x = 8

Answer:

y is less than or equal to 2/3x + 1/5

Step-by-step explanation:

We know that ratios can be shown with both fractions and colons.

20:705

or

[tex]\frac{20}{705}[/tex]

It also looks like we can simplify this by dividing by 5.

20/5 = 4

705/5 = 141.

This means that for every 4 teachers, there are 141 students.

The ratio for teachers to students is:

4 : 141

Answer:

[tex]\frac{1}{256}[/tex]

Step-by-step explanation:

So generally a geometric sequence can be defined as: [tex]a_n=a_1(r)^{n-1}[/tex] which is the explicit form. The r, is what each previous term is being multiplied by to get the next value which is evident in the recursive form: [tex]a_n = r(a_{n-1})\\[/tex]. Knowing this we can take two values which are "next" to each other to find what r is. In this case I'll just is 1 and 1/4, given these two values we know that: [tex]\frac{1}{4} = 1 * r[/tex], 1*r is just r... so what each term is being multiplied by is 1/4. So let's plug the values into the explicit formula: [tex]a_n=(\frac{1}{4})^{n-1}[/tex] (I didn't put an a_1 value in front, since it's just 1... so it's a bit redundant). Anyways using this formula we simply plug in 5 as n into the equation to find the 5th term: [tex]a_5 = (\frac{1}{4})^{5-1} = (\frac{1}{4})^4 = \frac{1^4}{4^4} = \frac{1}{256}[/tex]

The vertices of abc given the transition rule (x,y)-->(x,y-3) are (-6, -10), (-3, -13) and (-5, -1)

The vertices are given as:

a (-6,-7)

b(-3,-10)

c(-5,2)

The transition rule is given as

(x,y)-->(x,y-3)

So, we have

a' = (-6, -7 - 3)

a' = (-6, -10)

b' = (-3, -10 - 3)

b' = (-3, -13)

c' = (-5, 2 - 3)

c' = (-5, -1)

Hence, the vertices of abc given the transition rule (x,y)-->(x,y-3) are (-6, -10), (-3, -13) and (-5, -1)

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