Answer: c opinion is something ppl just suggest but a theory needs proof before it is confirmed
Need help ASAP
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1.Cell phones convert sound waves into______waves.
-light waves
-sound waves
-radio waves
2.Electromagnetic waves used in cell phone communications are called?
-microwave
-radio wave
-infrared
-all of the above
3.To send out a radio signal far and wide...it is called?
-broadcast
-casting
-antenna
Answer:
Explanation:
1.electric
2.radio wave
3.broadcast
Hope it helped you.
If a car is moving backward and has negative acceleration, what can be said about the speed of the car?
a. its speed is degreasing
b. its speed is increasing
c. its speed can either increase or decrease
d. its speed does not change
After 24.0 days 2.00 milligrams of an original 128.0. Milligram sample remain what is the half life of the sample
Answer:
4 days
either multiply 128 by .5 until you get to 2 counting each time or use 2 formulas ln(n2/n1)=-k(t2-t1) to get k then input k into ln(2)=k*t1/2
n2 is final amount and n1 is beginning and t is either time elapsed as in the first formula or the actual half life that is t1/2
Explanation:
The half life of the sample will be "4 days".
According to the question,
Let,
The number of half life = n→ [tex]\frac{N}{N_o} = (\frac{1}{2} )^n[/tex]
By substituting the values, we get
→ [tex]\frac{2}{128} = (\frac{1}{2} )^n[/tex]
→ [tex]\frac{1}{64} = (\frac{1}{2} )^n[/tex]
→ [tex](\frac{1}{2} )^6= (\frac{1}{2} )^n[/tex]
→ [tex]n=6[/tex]
So,
It takes 6 half life just to reduce from 128 mg - 2mg which is also "24 days".
→ [tex]6 \ half \ life = 24 \ days[/tex]
Hence,
→ [tex]Half \ life = \frac{24}{6}[/tex]
[tex]= 4 \ days[/tex]
Thus the answer above is right.
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Derivation
law of
conservation
of momentum
Applying Newton's third law, these two impulsive forces are equal and opposite i.e. If the time of contact is t, the impulse of the force F21 is equal to the change in momentum of the first object. The impulse of force F12 is equal to the change in momentum of the second object.
MARK ME BRAINLISTPLEASE HELP WILL MARK BRAINLIEST
In the formula Q = m x C x ΔT, which symbol represents specific heat?
A. Q
B. ΔΤ
C. m
D. с
Explanation:
Q = energy applied
m = mass
C = specific heat
ΔT = delta T = change in temperature
PLS ANSWER FAST WILL GIVE BRAINLEST!!
Answer using mass m= F divided by a
And also kilograms {kg}
A 7.5 N force is applied to a football generating an initial acceleration of 15 m / s2. Calculate the mass of the football.
Answer:
from
force =mass x acceleration
mass = force/acceleration
m = f/a
m = 7.5/15
m=0.5kg
[tex]\huge\bf{\pink{\underline{\underline{\mathcal{AnSwer࿐}}}}}[/tex]
Given:-acceleration = 1000 m/s²
force = 5000 N
To find:-Mass of the cannonball
Formula to be used:-[tex]\longrightarrow[/tex] [tex]\underline{\boxed{\sf mass = \dfrac{force}{acceleration}}}[/tex]
Solution:-:[tex]\implies[/tex] [tex]\sf mass = \dfrac{5000}{1000}[/tex]
:[tex]\implies[/tex] [tex]\sf mass = 5 kg [/tex]
hence, the required answer is 5kg.
______________________________
A force of 30 N is used to push a box along the floor a distance of 5 meters. How much workwas done
Answer:
the answer for how much work was done is 90
Work done to push a box is 150 J.
What is work?a force appearing upon an item to purpose a displacement.WORK = FORCE * DISPLACEMENTmechanical conservation of energy is the change in kinetic energy is equal to the work done.work energy theorem states that total energy change is equal to work done.
force= 30N
displacement= 5 meters.
work done= 30 * 5
⇒ 150 joule.
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A string of density 0.01 kg/m is stretched with a tension of 5N and fixed at both ends. The length of the string is 0.1m. What is the first four resonance frequencies in the string?
Answer:
The first four resonance frequency in the string are;
1) 50·√50 Hz
2) 100·√50 Hz
3)150·√50 Hz
4) 200·√50 Hz
Explanation:
The given parameters of the string are;
The density of the string, ρ = 0.01 kg/m
The tension force on the string, T = 5 N
The length of the string, l = 0.1 m
Therefore the mass of the string, m = Length of string × Density of the string
∴ m = 0.01 kg/m × 0.1 m = 0.001 kg
The formula for the fundamental frequency, f₁, is given as follows;
[tex]f_1 = \dfrac{\sqrt{\dfrac{T}{m/L} } }{2 \cdot L} = \dfrac{\sqrt{\dfrac{T}{\rho} } }{2 \cdot L}[/tex]
Where;
f₁ = The fundamental frequency in the string
T = The tension in the string = 5 N
m = The mass of the string = 0.001 kg
L = The length of the string = 0.1 m
ρ = The density of the string = 0.01 kg/m
By plugging in the values of the variables, we have;
[tex]f_1 = \dfrac{\sqrt{\dfrac{5}{0.01} } }{2 \times 0.1} = 50 \cdot \sqrt{5}[/tex]
The first four harmonics are;
f₁, 2·f₁, 3·f₁, 4·f₁
Therefore, we have the first four resonance frequency of the string are as follows;
1 × 50·√50 Hz = 50·√50 Hz
2 × 50·√50 Hz = 100·√50 Hz
3 × 50·√50 Hz = 150·√50 Hz
4 × 50·√50 Hz = 200·√50 Hz
If you use the same force to push a motorcycle as you would push a bike which one would have more acceleration and why explain using Newton's second law
Answer:
The bike would have more acceleration
Explanation:
Accourding to newtons first law a force is equal to its mass multiplied by its acceleration (f=ma) therefore an object with a higher mass compared to an object with a lower mass would experience less acceleration.
Eg.
F=50N
Motorbike M=200kg
F=ma
50=200 x a
50/200=a
0.25m/s/s =a
Bike M=35kg
F=ma
50=35 x a
50/35= a
1.43m/s/s=a
Answer:
the bike
Explanation:
it has less mass than the motorcycle so so it would have more acceleration
A 1600 kg car with the brakes applied comes to a stop in 4.20 seconds. During these 4.20 seconds the force of friction slowing down the car is 3900 N. What is the change in momentum of the car?
Answer:
The change in momentum of the car is 16380.8 kg.m/s
Explanation:
Given;
mass of the car, m = 1600 kg
time of motion, t = 4.20s
force of friction on the car, F = 3900 N
final velocity of the car after the brakes were applied, v = 0
The initial velocity of the car during the motion is calculated as;
[tex]F = ma = \frac{mu}{t} \\\\mu = Ft\\\\u = \frac{Ft}{m} \\\\u = \frac{3900\times 4.2}{1600} \\\\u = 10.238 \ m/s[/tex]
The change in momentum of the car is calculated as;
ΔP = mu
ΔP = 1600 x 10.238
ΔP = 16380.8 kg.m/s
Afootball is kicked at avelocity of 15 m/s at angle of 25 degree to the horizontal. What is the total flight time
Answer:
the total flight time is 1.29 s
Explanation:
The computation of the total flight time is given below:
The initial velocity is 15 m/s = v
And, the angle from horizontal is [tex]\theta = 25\ degrees[/tex]
Now the total time is
[tex]t = \frac{2\times v\times \sin \theta }{g} \\\\= \frac{2\times 15\times sin 25^{\circ}}{9.8} \\\\= 1.29 s[/tex]
Hence, the total flight time is 1.29 s
A car weighing 16,170 newtons is placed on a hydraulic lift. Piston B has an area of 5,005 cm?
and piston A has an area of 65 cm². What force must be exerted on piston A to lift the car?
P = F/A where Pequals pressure, Fequals force, and A equals area
Answer:
210N
Explanation:
According to pascal principle
Fb/Ab = Fa/Aa
Given
Fb = 16,170N
Ab = 5,005cm²
Fa = ?
Aa = 65 cm².
Fa is the force that must be exerted on piston A to lift the car
Substitute
16170/5005 = Fa/65
Cross multiply
5005Fa = 65 * 16170
5005Fa = 1,051,050
Fa = 1,051,050/5005
Fa = 210N
Hence the required force is 210N
The force which must be exerted on piston A to lift the car is equal to 210 Newton.
Given the following data:
Force on piston B = 16,170 newtonsArea of piston B = 5,005 [tex]cm^2[/tex]Area of piston A = 65 [tex]cm^2[/tex]To determine the force which must be exerted on piston A to lift the car:
Mathematically, the pressure acting on an area is given by the formula:
[tex]Pressure = \frac{Force}{Area}[/tex]
Since, the weight of the car remains constant, the pressure on piston A must be equal to the pressure on piston B.
Pressure A = Pressure B
Mathematically, this given by:
[tex]\frac{F_A}{A_A} = \frac{F_B}{A_B}[/tex]
Making [tex]F_A[/tex] the subject of formula, we have:
[tex]F_A =\frac{A_AF_B}{A_B}[/tex]
Substituting the given parameters into the formula, we have;
[tex]F_A = \frac{65 \times 16170}{5005} \\\\F_A = \frac{1,051,050}{5005}\\\\F_A = 210\;Newton[/tex]
Therefore, the force which must be exerted on piston A to lift the car is equal to 210 Newton.
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ms
2. The half-life of radium-226 is 1600 years. If a sample of radium-226 has an original activity of
200 Bq, what will it's activity be after:
i) 3200 years?
4800 years
iii) 6400 years
an atom with an atomic number of 12 and a mass number of 25 can best decided by which of these
Answer:
An atom that contains 12 protons
Explanation:
Atomic number is the same as how many protons and electrons an atom has. The mass is how many protons and neutrons there are together. In this case it would be 25 (mass) - 12 (protons) = 13 (neutrons).
How far must a spring with a spring constant of 64N/m be stretched to
store 0.32J of potential energy?
Answer:
0.1m
Explanation:
k = 64N/m
Ep = 0.32J
x = ?
Ep = 1/2 * kx²
make x the subject of the formula
x² = 2Ep/k
x = √(2Ep/k)
x = √(0.64/64)
x = √0.01
x = 0.1m
The first charge is pulling on the second. Is the second pulling on the first? Explain your reasoning
Answer:
law of action and reaction.
Explanation:
In Newton's three laws it is established that forces act in pairs, if one body interacts with another the second interacts with the first, this is the so-called law of action and reaction.
In this case, when the first load pulls on the second, the second pulls on the first, the two forces are not canceled because each one is applied to a different body.
Therefore the magnitude of the forces is the same, but the direction is opposite and each one is applied in a body
An electric force is an attractive or repulsive interaction. Newton's laws of motion define how it affects things, just like any other force. Yes, the second pulling on the first.
How does Newton's third law explain in terms of electricity?An electric force is an attractive or repulsive interaction between any two charged things. Newton's laws of motion define how it affects things, just like any other force.
The motion of objects under the influence of such a force or combination of forces is studied using Newton's laws.
The analysis generally starts with the creation of a free-body diagram in which the kind and direction of the various forces are represented by vector arrows.
Newton's laws of motion define how it affects things, just like any other force. Hence Yes, the second pulling on the first.
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Ultraviolet rays from the sun are dangerous because they can damage skin. Why do ultraviolet rays cause damage?
Answer:
Skin damage
Explanation:
exposure can lead to sunburn, and long term exposure can lead to aged skin and much more
The lamp has a resistance of 10Ω
Each resistor has a resistance of 10Ω (resistors are connected in parallel)
What is the total resistance of the circuit?
Tick one box
Between 20 and 30Ω?
Exactly 20Ω?
Exactly 30Ω?
Less than 20Ω?
D) Less than 20.
Explanation:
Equivalent resistance in a parallel combination is less than their individual value.
3. Why is static electricity not useful as a power
source?
A. Because electrons aren't transferred in bursts of
static electricity
B. Because all energy is released at once in static
electricity
C. Because static electricity is not a real form of
electricity
D. Because static electricity only occurs in lightning
Static electricity is not useful as a power source primarily because it releases all of its energy at once rather than providing a continuous and controlled flow of electrical energy. The correct answer is B.
When static electricity is discharged, such as in a spark or a sudden discharge of stored charge, it happens in a rapid and uncontrolled manner, resulting in a brief burst of energy rather than a steady and sustained flow.
Power sources typically require a continuous and controllable flow of electrical energy to be useful for various applications. Static electricity, in its nature, does not provide this continuous flow but instead releases energy in an instantaneous manner. Therefore, it is not suitable for most practical power needs and applications.
Option A is not correct because electrons can be transferred in bursts of static electricity. Option C is not correct because static electricity is a real form of electricity, even though it has unique characteristics. Option D is not correct because static electricity can occur in various circumstances, not just in lightning.
Therefore, Static electricity is not useful as a power source primarily because it releases all of its energy at once rather than providing a continuous and controlled flow of electrical energy. The correct answer is B.
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If a droplet has three extra electrons, what is its measured charge?
A. One-One-third third of of an an elementary elementary charge
B. One elementary charge
C. Two elementary charges
D. Three elementary charges
Answer:
The answer is d
Explanation:
Because he is from the same species
Answer:
D
Explanation:
40 mi/hr south is:
a displacement
a speed
a velocity
Answer:
Velocity
Explanation:
Since velocity is magnitude and direction, 40mph south is velocity.
When do websites collect personal and private information?
when a person turns on a computer
when an account is made on the website
whenever someone watches a video
when a person connects to the internet
Answer:
when an acount is made online i can also give you the other awnsers
Explanation:
A bear scratches his claws on a big pine tree. Does the bear do work on the tree? why or why not?
(btw it has to do with physics) ITS NOT A GENERAL QUESTION.
Answer:
The bear is actually sharpening his claws. That's the only reason he scratches a tree with his claws
Explanation:
A sound wave produce by a chime 515 m away is heard 1.50 s later.What is the speed of the sound in air?
Answer:
the seed of the sound in the air is 343.3 m/s
Explanation:
The computation of the speed of the sound in the air is shown below:
As we know that
Speed = Distance divided by Time
So, here speed be 515m
And, the time is 1.50 second
So, the speed of the sound is
= 515m divided by 1.50 seconds
= 343.3 m/s
hence, the speed of the sound in the air is 343.3 m/s
What is the mathematical relationship between height, mass, gravity, and gravitational potential energy?
Two identical conducting spheres are charged with a net charge of +5.0 q on the first sphere and a net charge of −8.0 q on the second sphere. The spheres are brought together, allowed to touch, and then separated. What is the net charge on each sphere now?
Answer:
The net charge on each sphere is -1.5 q
Explanation:
Conductors are materials that allow the electrons which are the carriers of the charges to move between them, and when two conductors come in contact, the available charge is shared by the two conductors and the resultant like charges will spread on the surface of the conductor due to the repellent effect between similar charges such that if the conductors are identical, the resultant charge becomes evenly shared by the conductors when they become separated again
The given parameters of the conducting spheres meant to touch are;
The net charge on the first sphere, Q₁ = +5.0 q
The net charge on the second sphere, Q₂ = -8.0 q
The net charge on each sphere after touching and then separated, 'Q', is given as follows;
[tex]Q = \dfrac{Q_1 + Q_2}{2}[/tex]
Therefore, by substituting the known values of the variables, we have;
[tex]Q = \dfrac{5 \ q+ (-8 \ q)}{2} = -\dfrac{3 \ q}{2} = -1.5 \ q[/tex]
The net charge on each sphere, Q = -1.5 q.
The net charge on each sphere after spheres are brought together, allowed to touch is -1.5 q
What is charge?Conductors are materials that allow the electrons which are the carriers of the charges to move between them, and when two conductors come in contact, the available charge is shared by the two conductors and the resultant like charges will spread on the surface of the conductor due to the repellent effect between similar charges such that if the conductors are identical, the resultant charge becomes evenly shared by the conductors when they become separated again
The given parameters of the conducting spheres meant to touch are;
The net charge on the first sphere, Q₁ = +5.0 q
The net charge on the second sphere, Q₂ = -8.0 q
The net charge on each sphere after touching and then separated, 'Q', is given as follows;
[tex]Q=\dfrac{Q_1+Q_2}{2}[/tex]
Therefore, by substituting the known values of the variables, we have;
[tex]\dfrac{5q+(-8q)}{2}=-1.5q[/tex]
Hence the net charge on each sphere after spheres are brought together, allowed to touch is -1.5 q
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help plz i have until 4.20 plz
Answer:
Substance 1 because it became a liquid faster
Explanation:
On earth a bag of sugar weight 10N. on mars a bag of sugar weight 4N. suggest the weight of the sugar is different on earth and mars
Answer:
gravity
Explanation:
there eould be a different gravitational strenght on both of the planets causing it to weigh more, or less
In mars, the effect of gravity on the object is weaker compared to while on earth. This weakness is what causes the reduction in the weight of the bag of sugar while on mars.
We must understand that the mass of an object may differ depending on its location on the planet. This is due to the effect of gravity on the object.
Gravity is simply defined as any force which attracts an object towards the centre of the earth.
From the question given, we are told that the weight of sugar is 10N on the earth and 4N on Mars. This difference in their mass is attributed to the effect of gravity on the object.
In mars, the effect of gravity on the object is weaker compared to while on earth. This weakness is what causes the reduction in the weight of the bag of sugar while on mars.
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If two negative charges of -2 C and -2 C are put 32,692 m apart from each other how much force will push them apart?
Answer:
33.65 N
Explanation:
Force that will push them away is given from the equation;
F = Kq1•q2/r²
Where;
K is coulumbs constant = 8.99 × 10^(9) Nm²/C²
We are given;
q1 = q2 = -2 C
r = 32692 m
Thus;
F = 8.99 × 10^(9) × (-2) × (-2)/32692²
F ≈ 33.65 N
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AM radio waves have a
a. Shorter broadcast range than FM waves
b. Longer broadcast range than FM waves
C. Better quality sound than FM waves
d. More music options
FM radio travel a shorter distance than AM radio waves.
a.true
b.false
Radio stations, police radios, and amateur radios don't interfere because they
have different
a. volumes
b. music options
C. frequencies