Will the answer to the subtraction problem below be odd or even?
5291 - 4070 = ?

[tex]W = \displaystyle \int^{5}_{2} F(x) ~ dx\\\\\\= \displaystyle \int^{5}_{2} \left(12x^2 +7\right) ~dx\\\\\\= 12\displaystyle \int^{5}_{2} x^2 ~dx + \displaystyle \int^{5}_{2} 7~ dx\\\\\\=12 \left[\dfrac{x^3}3 \right]^{5}_{2} + 7\left[x\right]^{5}_{2}\\\\\\=4(5^3-2^3) + 7(5-2) = 468 + 21 = 489~ J[/tex]

Answer:

16 I guess.

Step-by-step explanation:

lolololololol?

Answer:

x equals -2 and y equals−4

Answer:

Area = 23.12 cm²

perimeter = 24.28 cm

Step-by-step explanation:

top shaded region is circular arc with 90° sector angle

so perimeter of arc is 90 / 360 * 2πr

here radius of arc is half the length of square side

r = 6.8/2 = 3.4

top area shaded perimeter = 90/360 * 2 * 3.14 * 3.4

= 1/4 * 2 * 3.14 * 3.4

= 5.338

bottom region perimeter is also same

total perimeter of shaded region is = side + side + two arcs

= 6.8 + 6.8 + 2 * 5.338

= 13.6 + 10.676

= 24.276

= 24.28

Area of top shaded region is 90/360 * πr²

A = 1/4 * 3.14 * 3.4²

= 9.0746

bottom shaded region area is half of area of square - area of bottom arc

= 6.8 * 3.4  - 9.0746

= 23.12 - 9.0746

= 14.0454

so total area of shaded region is 9.0746 + 14.0454

= 23.12

or you can just calculate area as half of area of total square = 6.8² / 2

= 23.12

Check the picture below.

now, notice the triangles made, 3 right triangles with legs of 5 and 4 each.

looking at quadrilateral (1), from the leg 5 units long, we have a line with a run of -1 and a rise of 3, from the leg 4 units long, we have a line with a run of 4 and a rise of -1.

Now, quadrilaterals (2) and (4) display the same lengths and rise and runs, which means they're all congruent, quadrilateral (3) has no equal.

so 1 ≅ 2 and 1 ≅ 4.

Answer:

319 books

Step-by-step explanation:

345+179=524

524-205 = 319

Answer:

0.032

Step-by-step explanation:

Answer:  0.03284281007

Step-by-step explanation:

Answer:

its the first one

Step-by-step explanation:

Answer:

49

Step-by-step explanation:

If there's 60 beads in total and 11 are round and the rest aren't all you have to do is subtract 11 from 60.

Like This: 60-11=49

To check your answer you can add them to see if you get 60. Like this: 11+49=60

Answer:

probably about 3.5

Step-by-step explanation:

Answer:

Place the numbers in their places. b=base h=height.

Step-by-step explanation:

Answer:

-sin x

Step-by-step explanation:

sin(3π/3+x)=sin (π+x)=-sin x

or

sin (π+x)=sin πcos x+cos π sin x=(0)cos x+(-1)sin x=0-sin x=-sin x

Answer:

Step-by-step explanation:

Hi sorry if I’m bugging just trying to help out by getting Them B bye

Answer:

x=25

Step-by-step explanation:

5x-5+  2x+10 =180

2x-5x = 10+5

3x= 15

x=5

5(5)-5+ 2(5) +10 =180

Answer:

18

Step-by-step explanation:

18 is the constant term since it contains no variable.

Answer:

-1

sorry if this is wrong I really am

Answer:

m= -1

Step-by-step explanation:

Have a nice day

Think of it this way, a function must pass the vertical line test.  There may not be 2 outputs for one input for example  (0, 1) (0, 2)  However, you can have something like this (1, 0) (2, 0)

This is indeed a function as it meets those criterion.  There are no two outputs for one input.

Three to Ten  3:10

...................................................

Answer:

No

No

Yes

Yes

No

Step-by-step explanation:

In this case we are looking at substitution, so any where you find x put three(3) in replace of it.

And remember the answer should be 36,

I find it difficult to type the answer so I will take a picture instead.

These are answers of the second page. but I don't the answer to question 5

Answer:

I'm guessing the answer is sec³θ

Step-by-step explanation:

I tried this problem and I got 1/cos³θ and clicked cos³θ, but that answer was incorrect. In my lesson, there were the options:

1. sec³θ

2. cos³θ

3.  secθ

I didn't have options 1 + sinθ or 1 as answers. If sec³θ is not the correct answer, please correct me.

Answer:

It takes 3/4 of an hour to go 1 mile

Step-by-step explanation:

You can do this by setting up a proportion and by using decimals for some fractions

2/3 = 0.66667 Miles

1/2 = 0.5  hours

0.66667/0.5 = 1/x                         Cross multiply

0.66667 * x = 0.5 * 1                     Simplify

0.66667 * x = 0.5                         Divide both sides by 0.66667

x = 0.5 / 0.66667

x =  0.74999625                           Notice when rounded this is 0.75

x = 0.75                                         Now notice that 0.75 as a fraction is 3/4

x = 3/4

Jeremy can row 2/3 of a mile in 1/2 hour then it will take him 3/4 hour to row 1 mile.

If Jeremy can row 2/3 of a mile in 1/2 hour, then the time it takes him to row 1 mile can be found by setting up a proportion:

(2/3 mile) / (1/2 hour) = 1 mile / (x hours)

Cross-multiply:

(2/3) × x = 1 × (1/2)

Now solve for x:

x = (1/2) / (2/3)

x = 3/4

So, it will take Jeremy 3/4 of an hour (or 45 minutes) to row 1 mile.

Learn more about mile here:

https://brainly.com/question/29806974

#SPJ3

"Find all real solutions of" basically means solve for x. You're looking for the real numbers x such that the given equation is satisfied. "Zeros" is synonymous with "solutions".

It looks like the first equation is

3x³ + x² - 38x + 24 = 0

It's not immediately obvious whether this can be factorized, so we first carry out the rational zero test to see if there are any rational solutions. *If* this equation has any rational solutions, then they must take the form of (divisor of 24)/(divisor of 3). That is, take any divisor of the constant coefficient and divide it by any divisor of the leading term's coefficient.

We have

• divisors of 24 : ±1, ±2, ±3, ±4, ±6, ±8, ±12, ±24

• divisors of 3 : ±1, ±3

Sadly, there are 64 possible roots to test, but we only need one to make the rest of the problem easier.

• Let x = +1 / +1 = 1. Then plugging x = 1 into the equation gives

3•1³ + 1² - 38•1 + 24 = -10 ≠ 0

so x = 1 is *not* a solution

• Let x = +2 / +1 = 2. If x = 2, then

3•2³ + 2² - 38•2 + 24 = -24 ≠ 0

so x = 2 is *not* a solution.

• Let x = +3 / +1 = 3. If x = 3, then

3•3³ + 3² - 38•3 + 24 = 0

so x = 3 is a solution.

By the remainder theorem, this means that x - 3 divides 3x³ + x² - 38x + 24. Using long or synthetic division,

(3x³ + x² - 38x + 24) / (x - 3) = 3x² + 10x - 8

so that

3x³ + x² - 38x + 24 = 0

is the same as

(x - 3) (3x² + 10x - 8) = 0

We factorize the remaining quadratic to get

3x² + 10x - 8 = (3x - 2) (x + 4)

and so the original equation is equivalent to

(x - 3) (3x - 2) (x + 4) = 0

Solve for x :

x - 3 = 0   or   3x - 2 = 0   or   x + 4 = 0

x = 3   or   x = 2/3   or   x = -4

The other equations can be solved similarly, though some of the others you included are much simpler.

For the second problem (note that you left out an exponent), we solve the equation

x³ - 2x² - 23x + 60 = 0

Again, not immediately obvious how to factorize this. But using the rational root test, we have

• divisors of 60 : ±1, ±2, ±3, ±4, ±5, ±6, ±10, ±12, ±15, ±20, ±30, ±60

• divisors of 1 : ±1

If you follow the same steps as before, you'll find the first rational solution with x = 3. So x - 3 divides x³ - 2x² - 23x + 60, and long division gives

(x³ - 2x² - 23x + 60) / (x - 3) = x² + x - 20

and the resulting quadratic is easily factored,

x² + x - 20 = (x - 4) (x + 5)

So, we have

x³ - 2x² - 23x + 60 = (x - 3) (x - 4) (x + 5) = 0

which means

x - 3 = 0   or   x - 4 = 0   or   x + 5 = 0

x = 3   or   x = 4   or   x = -5

For the third problem, we can factor by grouping.

x³ - 4x² - x + 4 = 0

x² (x - 4) - (x - 4) = 0

(x² - 1) (x - 4) = 0

(x - 1) (x + 1) (x - 4) = 0

Then

x - 1 = 0   or   x + 1 = 0   or   x - 4 = 0

x = 1   or   x = -1   or   x = 4

For the fourth problem, we use the rational root test again, but twice this time.

x⁴ - 6x³ + 7x² + 6x - 8 = 0

• divisors of -8 : ±1, ±2, ±4, ±8

• divisors of 1 : ±1

We find that x = 1 and x = 2 are both rational roots, so both x - 1 and x - 2 divide x⁴ - 6x³ + 7x² + 6x - 8. By long division,

(x⁴ - 6x³ + 7x² + 6x - 8) / ((x - 1) (x - 2)) = x² - 3x - 4

and factoring this gives

x² - 3x - 4 = (x + 1) (x - 4)

So, we have

x⁴ - 6x³ + 7x² + 6x - 8 = (x - 1) (x - 2) (x + 1) (x - 4) = 0

which means

x - 1 = 0   or   x - 2 = 0   or   x + 1 = 0   or   x - 4 = 0

x = 1   or   x = 2   or   x = -1   or   x = 4

For the last problem,

x⁴ + 4x³ + 7x² + 16x + 12 = 0

we use the rational root test again.

• divisors of 12 : ±1, ±2, ±3, ±4, ±6, ±12

• divisors of 1 : ±1

We find that both x = -1 and x = -3 are rational solutions, and dividing gives

(x⁴ + 4x³ + 7x² + 16x + 12) / ((x + 1) (x + 3)) = x² + 4

which we cannot factorize further over the real numbers. So we end up with

x⁴ + 4x³ + 7x² + 16x + 12 = (x + 1) (x + 3) (x² + 4) = 0

so that

x + 1 = 0   or   x + 3 = 0   or   x² + 4 = 0

x = -1   or   x = -3

(We omit the third equation here because it has no real solution since x² + 4 ≥ 4 for all real x.)

Answer:

Step-by-step explanation:

27836?+_68_729+_8978

Answer:

£6.25

Step-by-step explanation:

2.25 x 15 = 33.75

40 - 33.75 = 6.25

Answer:

£6.25

Step-by-step explanation:

Hii,

So if each lesson is 2.25, you times this by 15 to get the total amount of payment. £2.25 x 15 = 33.75

To get change, you need to take away the amount you are giving by how much the bill is.

£40 - £33.75 = £6.25

I hope this helped :P