Answer:
6x+7y=2/5
im not entirely sure if its correct sorry if u get it wrong-
2) (x+3)
2) Correct the error:
There is an error in the students' work shown below:
Question: Simplify (x-3)(x-7)
Solution: (x-3)(x-7)
x-x-3(x)-7(x) - 21
x²-10x-21
What is the error? Explain how to solve the problem.
The expression x²-10x-21 is wrong since the product of two negative signs is equal to positive.
Simplifying factorsQuadratic equations are equations that has a leading degree of 2. The standard quadratic equation is given as;
f(x) = ax^2+bx+c
Given the product of the expression below;
f(x) = (x-3)(x-7)
Expand
f(x) = x(x) - 7x - 3x -3(-7)
f(x) = x^2 - 7x - 3x + 21
f(x) = x^2 - 10x + 21
Hence the expression x²-10x-21 is wrong since the product of two negative signs is equal to positive.
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the function f(t) = 5 cos(pi/4*t) + 11 represents the tide in dark sea. it has a maximum of 16 feet when time (t) is 0 and a minimum of 6 feet. the sea repeats this cycle every 8 hours. after six hours, how high is the tide?
The height of the tide after eight hours is 16 feet.
How to illustrate the function?From the information given, the function is given as 5cos (π/4)t + 11.
In this case, the time is given as eight hours. This will be:
f(8) = 5 × cos (π/4) × 8 + 11
f(8) = 5 × cos(2π) + 11
= (5 × 0.999) + 11
= 16 feet
The height is 16 feet.
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Can anyone help me find all the calculations to these cups?
The volume of the glasses is as follows;
glass 1 = 170 cm³glass 2 = 141 cm³glass 3 = 60 cm³How to find volume ?The volume of cylinder glass 1 = πr²h
The volume of cylinder glass 1 = 3.14 × 3² × 6
The volume of cylinder glass 1 = 3.14 × 9 × 6
The volume of cylinder glass 1 = 169.56 cm³ = 170 cm³
The volume of the glass 2 = 2 / 3 π r³ + πr²h
The volume of the glass 2 = 2 / 3 × 3.14 × 3³ + 3.14 × 3² × 3
The volume of the glass 2 = 56.52 + 84.78
The volume of the glass 2 = 141.3 cm³ = 141 cm³
The volume of conical glass 3 = 1 / 3 πr²h
The volume of conical glass 3 = 1 / 3 × 3.14 × 3² × (√7² - 3² = √40)
The volume of conical glass 3 = 9.42 × √40
The volume of conical glass 3 = 59.5773111176
The volume of conical glass 3 = 60 cm³
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What is the length of the apothem of the regular pentagon shown below? Round to one decimal place
Answer:
A
Step-by-step explanation:
Draw a diagonal line connecting the centre to a vertex at the bottom. This makes a triangle. It is a regular pentagon so the base of that triangle is 7.6 / 2, which is 3.8. You also know that the angle from the apothem to the base is 90 degrees. You also know that you could split the centre angle into 5 triangles. 360 / 5 = 72 and we have half of it so it is 36 degrees.
Let's see what we have so far:
The base of the triangle is 3.8
The angle at the bottom is 90
The angle at the top is 36
We now have the tan and the opposite and we need the adjacent so rearrange for adjacent.
This gives you adjacent = opposite / tan(angle)
adjacent = 3.8 / tan(36)
adjacent = 5.2m
Two sides of a triangle have lengths 18m and 23m. Describe the possible length of the thired side
The possible length of the third side will be values that are less than 41 and greater than 5
Triangular theoremFor three sides to be the sides of a triangle, the sum of any two sides of the triangle must be greater than the third.
Given the two sides of a triangle have lengths 18m and 23m, the sum of the sides is given as:
sum = 18 + 23
Sum = 41
Let the third side be x, such that;
x + 18 >23
23 + x > 18
x > 23 - 18
x > 5
Similarly
x > -5
Hence the possible length of the third side will be values that are less than 41 and greater than 5
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QUICK I need help on what the answer is and an explanation would be much appreciated too thank you
The nonreal solutions to the polynomial equation are: (2 + i√11, 2 - i√11).
How to determine the nonreal solutions?By critically observing the graph given, we can logically deduce that the real solutions of the polynomial are -1 and 4. This ultimately implies that, the given polynomial expression can be evaluated as follows:
(x + 1)(x - 4) = x² - 3x - 4.
x⁴ - 7x³ + 23x² - 29x - 60 = x² - 3x - 4.
Also, the nonreal solutions can be determined by dividing the polynomial expression by the real solutions as follows:
Nonreal solutions = (x⁴ - 7x³ + 23x² - 29x - 60)/(x² - 3x - 4)
Nonreal solutions = (2 + i√11, 2 - i√11).
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Molly wants to buy a dress that costs $20. She has a coupon for 40% off, and there is a 10% sales tax. how much will she pay all together
1. after using the coupon what is the sale price of the dress Show Your Work
2.how much is th 10% tax on the sale price Explain how you found your answer
Answer:
$13.50
Step-by-step explanation:
If I am taking off 40%, that means that the dress now cost 60% of the original cost. .6 x 20 is 12.
You could also calculate the 20% off and subtract that from the original cost. .4 x 20 =8. Now 20 - 8 is also 12.
Now, we have to calculate the tax. 10% of 12 is .1 x 12 or $1.20. We add the tax to the 12 to get 13.50.
The point (–1, 0.5) lies on the graph of
f –1(x) = 2x. Based on this information, which point lies on the graph of f(x) = log2x?
The point which would lie on the graph of f(x) = log2x is; (1, 0.301).
Which point would lie on the graph of f(x) = log2x?Since it follows from the task content that the given point (–1, 0.5) lies on the graph of f –1(x) = 2x.
The subsequent graph of f(x) = log2x would result from taking logarithms in which case, we have the graph passing through points determined as follows;
f(x) = log2^x
f(x) = x log2
Hence, when x = 1;
f(1) = 1log 2
Hence, we have point; (1, 0.301).
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n an element’s square on the periodic table, the number with the greatest numerical value represents the
−6 + 3 = −21 pls can uhelp me with this
Answer:
No Solution
Step-by-step explanation:
1) Simplify -6 - 3 to -3.
-3 = -21
2) Since -3 = -21 is false, there is no solution.
No solution
Lines a and b are parallel and lines e and f are parallel what is the value of x
The value of x using the alternate exterior angle theorem is 82°
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables.
An angle is formed from the intersection of two or more lines. Types of angles are acute, obtuse and scalene.
From the diagram:
x = 82° (alternate exterior angles)
The value of x using the alternate exterior angle theorem is 82°
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Linda is training to be an assistant at the local animal shelter. To become an assistant she needs to complete 48 h of training. Linda keeps a graph of the number of hours of training left to be completed. What is the rate of change of the number of hours remaining with respect to the number of days? Remember to include units.
The equation between the number of days remaining and number of hours is given as y= -5x+50.
How to illustrate the equation?Let y be the number of days remaining and x be the no.of hours.
From the graph the slope of the line is given by m.
m=(y2 - y1)/(x2 - x1)
m=(30 - 40)/(4 - 2)
m= -10/2 = -5.
The above slope is in between points 2 and 4. As the line has a constant rate of growth the slope is the same between any points of the line.
Therefore the equation between the no.of days remaining and no.of hours is given by
y=mx +c.
y=-5x+c
Now to find the value of c. This can be determined by substituting the x and y values at a particular instant. For x=0,y=50. Therefore by these values, we get,
50= -5(0)+c
c=50.
Therefore the relation between the number of days remaining and number of hours is given as y= -5x+50.
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PLEASE HELP! And thank you so much! I will mark you brainliest. I just need an urgent response! Thank you for your time
Answer:
A)
x + y = 80
y = x + 20
B) x = 30 minutes
C) No. If Pam dances for 60 minutes, and dances for 20 minutes longer than she does math, then she does math for 40 minutes. This means she spends 100 minutes total. 100 minutes is not 80 minutes, thus this is not possible.
Step-by-step explanation:
A)
x + y = 80
y = x + 20
B) x = 30 minutes
Replacing y with x + 20 in the first equation ->
x + x + 20 = 80
2x + 20 = 80
2x = 60
x = 30
C) No. If Pam dances for 60 minutes, and dances for 20 minutes longer than she does math, then she does math for 40 minutes. This means she spends 100 minutes total. 100 minutes is not 80 minutes, thus this is not possible.
Q1. A man wants to paint his house in 3 colors. If he can choose 3 colors out of 6 colors, how many
different color settings can he make?
(A) 216 (B) 20 (C) 18 (D) 120
Beginning with the graph of f(x) x2, what transformations are needed to form g(x) = 3(x + 2)2 - 1?
O The graph of g(x) is narrower than f(x) and S shifted to the right 2 units and down 1 unit.
O The
graph of g(x) is narrower than f(x) and is shifted to the left 2 units and down 1 unit.
• The graph of g(x) is wider than f(x) and is shifted to the left 2 units and down 1 unit.
• The graph of g(x) is wider than f(x) and is shifted to the right 2 units and down 1 unit.
Answer: The graph of g(x) is narrower than f(x) and is shifted to the left 2 units and down 1 unit.
Step-by-step explanation:
See attached image.
The function f(x) = x² is transformed and became g(x) = 3(x+2)² -1 has the graph of g(x) is wider than f(x) and is shifted to the left 2 units and down 1 unit.
What are graph transformations ?By applying suitable graph transformation we can shift, stretch, shrink, a given graph along x and y axis.
According to the given question given a graph f(x) = x² and g(x) is 3(x+2)² - 1.
Let us break transformations of g(x) one by one.
g(x) = 3f(x) which implies it's amplitude or vertical stretch is increased by a factor of 3.
Now, g(x) = 3(x+2)² implies the graph is shifted towards left by 2 units as x + 2 = 0 is x = -2.
Now, g(x) = 3(x+2)² - 1 implies that the whole graph has been shifted 1 units down along the y axis.
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The equation T^2= A^3 shows the relationship between a planets orbital period, T, and the planets mean distance from the sun, A, in astronomical units, AU. if the orbital period of planet Y is twice the orbital period of planet x, by what factor is the mean distance increased?
The mean distance increased by a factor of 2^(²/₃)
How to find the factor of increase?
The given equation for the relationship between a planet's orbital period, T and the planet's mean distance from the sun, A is;
T² = A³.
Let the orbital period of planet X = T(X).
Let the orbital period of planet Y = T(Y).
Let the mean distance of planet X from the sun = A(X).
Let the mean distance of planet Y = A(Y).
Thus;
A(Y) = 2A(X)
Therefore;
[T(Y)]² = [A(Y)]³ = [2A(X)]^3
However, [T(X)]² = [A(X)]³
Thus;
[T(Y)]² = 2³[T(X)]² * [T(Y)]²/[T(X)]² = 2³T(Y)/T(X) = 2^(³/₂)
That's for orbital period but the mean distance will increase by 2^(²/₃)
Thus we conclude that, the mean distance increased by a factor of 2^(²/₃)
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Answer:
2 Superscript three-halves
Step-by-step explanation:
Edge
A sales agent gets 15%commission for each motivational book he sells. if he sold books worth #284000,how much commission will he get?
Answer:
$42,600
Step-by-step explanation:
284000 x .15
Calculate the distance between the points C = (0,-2) and L= (-4, 1) in the coordinate plane. Give an exact answer. (not a decimal approximation)
Answer: 5
Step-by-step explanation:
[tex]\sqrt{(-4-0)^2 + (1-(-2))^2}=5[/tex]
Find DE
3x - 28
3x - 30
D
G
E
F
33
Answer:
11
Step-by-step explanation:
(3x-28) + (3x-30) + x = 33
7x - 58 = 33
7x = 91
x = 13
DE = 3x - 28 = 3*13 - 28 = 11
A government buys `x`fighter planes at `z` dollars each, and `y` tons of wheat at w dollars each. It spends a total of `B`dollars, where `B=xz+yw`. Write an equation whose solution is the given quantity:
2. The price of a ton of wheat, given that a fighter plane costs 100,000 times as much as a ton of wheat, and that the government bought 20 fighter planes and 15,000 tons of wheat for a total cost of $90 million.
The equation whose solution is the given quantity is 90,000,000 = 2,000,000w + 15,000w where w = $44.67
EquationB = xz + yw
Where,
B = Total cost = 90x = number of fighter plane = 20y = tons of wheat = 15,000w = cost of each tons of wheatz = cost of fighter planez = 100,000wB = xz + yw
90,000,000 = (20 × 100,000w) + (15,000 × w)
90,000,000 = 2,000,000w + 15,000w
90,000,000 = 2,015,000w
w = 90,000,000 / 2,015,000
= 44.6650124069478
Approximately,
w = $44.67
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A couple deposits $20,000 into an account earning 5% annual interest for 30 years. Calculate the future value of the investment if the interest is compounded monthly. Round your answer to the nearest cent.
The future value of the investment if the interest is compounded monthly is $89,354.89.
What is the future value of the investment?Given that;
Principal P = $20,000Annual interest rate r = 5% = 5/100 = 0.05Time t = 30 yearsCompound monthly = 12Future value = A = ?Using the compound interest formula;
A = P( 1 + r/n )^(nt)
We plug in our values.
A = 20000( 1 + 0.05/12 )^(12 × 30)
A = 20000( 1 + 0.0041666666666667)^(360)
A = 20000( 1.0041666666666667)^(360)
A = 20000( 4.46774965 )
A = 89354.89
Therefore, the future value of the investment if the interest is compounded monthly is $89,354.89.
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Maria plots the following points on a coordinate grid. Then, she connects each plotted point to the previous one in the order shown to form a figure. What is the area, in square units, of the enclosed figure?
The area of the enclosed figure is 4 square units.
What is the area?The area is the amount of area occupied by an object's flat (2-D) surface or shape.
The triangle's area can be described as,
Area = 1/2 x base x height.
To find the area of the enclosed figure, we need to first plot the given points and then determine the shape of the figure.
Plotting the points A, B, and C on a coordinate grid, we get:
The image is given below.
Connecting points A, B, and C, we can see that the figure formed is a right triangle with legs of lengths 4 and 2.
Therefore, the area of the enclosed figure is:
Area = (1/2) x base x height
= (1/2) x 4 x 2
= 4 square units
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The complete question:
Maria plots the following points on a coordinate grid. Then, she connects each plotted point to the previous one in the order shown to form a figure. What is the area, in square units, of the enclosed figure?
Point A (1, 3)
Point B (5, 7)
Point C(5, 3)
Point A (1, 3)
A random sample of vehicle mileage expectancies has a sample mean of x¯=169,200 miles and sample standard deviation of s=19,400 miles. Use the Empirical Rule to estimate the percentage of vehicle mileage expectancies that are more than 188,600 miles. Round your answer to the nearest whole number (percent).
The percentage of vehicle mileage expectancies that are more than 188,600 miles is 93%
How to determine the percentage?The given parameters are:
Mean = 169200
Standard deviation = 19400
x = 188600
Calculate the z value using:
[tex]z = \frac{x - \mu}{\sigma}[/tex]
So, we have:
[tex]z = \frac{188600 - 169200}{19400}[/tex]
Evaluate
z = 1
Using the Empirical Rule, we have:
P(x > 188600) = P(z > 1.5)
From z table of probability, we have:
P(x > 188600) = 0.93319
Express as percentage
P(x > 188600) = 93.319%
Approximate
P(x > 188600) = 93%
Hence, the percentage of vehicle mileage expectancies that are more than 188,600 miles is 93%
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Please help me with this math quickly
The area of the shaded part is 52 sq. inches. The correct option is b. 52 sq. inches
Calculating AreaFrom the question, we are to determine the area of the shaded part
In the given diagram, the shaded part is a rectangle
Area of a rectangle = Length × Width
Length of the shaded part = 18 inches - 4 inches - 1 inch = 13 inches
Width of the shaded part = 6 inches - 2inches = 4 inches
Then,
Area of the shaded part = 13 inches × 4 inches
Area of the shaded part = 52 sq. inches
Hence, the area of the shaded part is 52 sq. inches. The correct option is b. 52 sq. inches
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Question 10 (2.5 points) ✓ Saved
Write the comparison below as a ratio in simplest form using a fraction, a colon (:), and the word to.
15 dollars to 27 dollars
find the value of x
a) 2:5=8:x
Step-by-step explanation:
solution:
given,
or, 2:5 = 8:x
or, 2/5 = 8/x [ changing into fraction form ]
or, 2x = 40 [ doing cross-multiplication ]
or, x = 20 [ dividing both sides with 2]
Need help on these trig homework
8. The length of the support is 7. 9 m
9. The length of the conveyer is 12m
3. a = 59m
A = 44°
B = 52°
4. c = 88. 6 mm
b = 49. 1 m
B = 34°
How to solve the trigonometry
8. We have the angle to be 20 degrees
Opposite side = x
hypotenuse = 23m
Using the sine ratio
sin θ = opposite/ hypotenuse
[tex]sin 20 = \frac{x}{23}[/tex]
Cross multiply
[tex]sin 20[/tex] × [tex]23 = x[/tex]
[tex]x = 0. 3420[/tex] × [tex]23[/tex]
x = 7. 9 m
The length of the support is 7. 9 m
9. The angle of elevation is 37. 3 degrees
Hypotenuse = 19 . 0m
Opposite = x
Using the sine ratio
sin θ = opposite/ hypotenuse
[tex]sin 37. 3 = \frac{x}{19}[/tex]
cross multiply
[tex]x = 0. 6059[/tex] × [tex]19[/tex]
x = 11.5
x = 12 m in 2 significant figures
The length of the conveyer is 12m
3. To determine the sides and angles, we use the sine rule;
[tex]\frac{a}{sin A} = \frac{b}{sin B} = \frac{c}{sin C}[/tex]
For side a, we use the Pythagorean theorem
[tex]c^2 = a^2 + b^2[/tex]
[tex]85^2 = a^2 + 67^2[/tex]
[tex]a = \sqrt{89^2-67^2}[/tex]
[tex]a = \sqrt{3432}[/tex]
a = 58. 58, a = 59m
To find angle A and B, use the sine rule
[tex]\frac{59}{sin A } = \frac{85}{sin 90}[/tex]
cross multiply
[tex]sin A[/tex] × [tex]85[/tex] = [tex]sin 90[/tex] × [tex]59[/tex]
make sin A subject of formula
[tex]sin A = \frac{59}{85}[/tex]
[tex]sin A = 0. 6941[/tex]
A = [tex]sin^-^1(0. 6941)[/tex]
A = 44°
[tex]\frac{67}{sin B} = \frac{85}{sin 90}[/tex]
cross multiply
[tex]sin B[/tex] × [tex]85[/tex] = [tex]sin 90[/tex] × [tex]67[/tex]
make sin b subject of formula
[tex]sin B = \frac{67}{85}[/tex]
[tex]sin B = 0. 7882[/tex]
B = [tex]sin^-^1( 0. 7882)[/tex]
B = 52°
4. To find the sides, we use the sine rule;
[tex]\frac{74. 0}{sin 56. 6} = \frac{c}{sin 90}[/tex]
Cross multiply
[tex]sin 56. 6[/tex] × [tex]c = sin 90[/tex] × [tex]74[/tex]
make 'c' subject of formula
[tex]c = \frac{74}{0. 8348}[/tex]
c = 88. 6 mm
To find length b, we use the Pythagorean theorem
[tex]c^2 = a^2 + b^2[/tex]
[tex]b^2 = c^2 - a^2[/tex]
[tex]b^2 = 88. 8^2 - 74^2[/tex]
[tex]b = \sqrt{7885. 44 - 5476}\\\\ b = \sqrt{2409. 44}[/tex]
b = 49. 1 m
[tex]\frac{74. 0}{sin 56. 6} = \frac{49. 1}{sin B}[/tex]
cross multiply
[tex]sin B = \frac{40. 99}{74. 0}[/tex]
B = [tex]sin^-^1(0. 5539)[/tex]
B = 34°
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A student is taking an exam with 40 questions on it.To pass the exam she needs to answer 70% of the questions correctly. Unfortunately she answered only 40% of the 15 questions correctly. What percent of the remaining 25 questions does she have to answer correctly to pass the exam?
The first step is to find out how question in total she is able to miss, while still passing.
We know that there are [tex]40\\[/tex] questions on the test and she must get [tex]70[/tex]% of the questions correct.
Let's calculate how many questions that is:
40 x 0.70
= 28.
Subtract
40 - 28
= 12.
She is able to get 12 answers incorrect.
Now we must find out how many questions she got wrong when she got 40% of the first 15 correct.
If she got 40% correct; She got 60% incorrect.
Let's do the math:
Multiply:
15 x 0.40
= 6
Subtract:
15 - 6
= 9
This means that she got 6 questions correct, and 9 questions incorrect.
With the total allotment of 12 incorrect answers allowed, she can only get 3 more questions wrong.
Now we must find the percentage of the remaining 25 questions she can get wrong.
She can only get 3 wrong and she must get 22 correct.
Multiply:
22 x 4
= 88.
This means that she has to get 88% of the remaining 25 questions correct.
A theater sells 2 types of fixed-price tickets - orchestra and balcony. Peter pays $50 for 1 orchestra and 4 balcony tickets. Justine pays $150 for 3 orchestra and 12 balcony tickets. А B The cost of 1 balcony ticket. The cost of 1 orchestra ticket. The quantity under A is greater than the quantity under B. The quantity under B is greater than the quantity under A. The quantities under A and B are equal. The information given is insufficient to make the comparison.
Using a system of equations, it is found that:
The cost of an orchestra ticket is of $10.The cost of a balcony ticket is of $10.The quantities are equal.What is a system of equations?A system of equations is when two or more variables are related, and equations are built to find the values of each variable.
In this problem, the variables are:
Variable a: Cost of an orchestra ticket.Variable b: Cost of a balcony ticket.Peter pays $50 for 1 orchestra and 4 balcony tickets, hence:
a + 4b = 50 -> a = 50 - 4b.
Justine pays $150 for 3 orchestra and 12 balcony tickets, hence:
3a + 12b = 150.
a + 4b = 50 -> a = 50 - 4b.
The equations are equal, hence we suppose that the costs are equal, that is:
a + 4b = 50 -> 5a = 50 -> a = 10.
Hence:
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The function f(x)=−4x4+3x3−2x2−x+5 is/has A. order 2 rotational symmetry about the origin
B. neither symmetry about the y-axis nor has order 2 rotational symmetry about the origin
C. even
D. odd
The answer choice which describes the function is; Choice B; neither symmetry about the y-axis nor has order 2 rotational symmetry about the origin.
What is rotational symmetry?Rotational symmetry, otherwise termed radial symmetry, is the characteristic of a shape when it looks the same after some rotation by a partial turn. On this note, since the function represents a quartic graph, it follows that the function has neither symmetry about the y-axis nor has order 2 rotational symmetry about the origin.
Therefore, the function f(x) = −4x⁴ + 3x³ − 2x² − x + 5 is neither symmetry about the y-axis nor has order 2 rotational symmetry about the origin.
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