Write relational expressions to express the following conditions (using variable names of your choosing): a. The distance is equal to 30 feet. b. The ambient temperature is 86.4 degrees. c. A speed is 55 mph. d. The current month is 12 (December). e. The letter input is K. f. A length is greater than 2 feet and less than 3 feet. g. The current day is the 15th day of the 1st month. h. The automobile's speed is 35 mph and its acceleration is greater than 4 mph per second. i. An automobile's speed is greater than 50 mph and it has been moving for at least 5 hours. j. The code is less than 500 characters and takes more than 2 microseconds to transmit.

Answers

Answer 1

Trelational expressions to express the following conditions are:
a. distance = 30 feet
b. ambient temperature = 86.4 degrees

Trelational expressions to express the following conditions are:
a. distance = 30 feet
b. ambient temperature = 86.4 degrees
c. speed = 55 mph
d. current month = 12 (December)
e. letter input = "K"
f. length > 2 feet AND length < 3 feet
g. current day = 15 AND current month = 1
h. automobile speed = 35 mph AND acceleration > 4 mph per second
i. automobile speed > 50 mph AND time moving >= 5 hours
j. code < 500 characters AND transmission time > 2 microseconds

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Related Questions

A wall is in the shape of a trapezoid. The lengths of the parallel bases are 8 feet and 20 feet. The height of the room is 8 feet. How much paint is needed to cover the wall? 80 ft2 112 ft2 160 ft2 224 ft2

Answers

The amount of paint needed to cover the wall is 112 square feet

How to determine the amount of paint?

The given parameters are:

Parallel bases = 8 feet and 20 feet

Height = 8 feet

The area is calculated as:

Area = 0.5 * (Sum of parallel bases) * Height

So, we have;

Area = 0.5 * (8 + 20) * 8

Evaluate

Area = 112

Hence, the amount of paint needed to cover the wall is 112 square feet

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Determine the perimeter of the figure.

Answers

Answer: 2x + 6y + 22 units

Step-by-step explanation:

The perimeter of a figure is the total length of all the sides of a figure.

Therefore, the perimeter can be found by adding up all the lengths of the figure.

Suppose that P is the perimeter of this figure, then

[tex]P = x+4+x+4+3y+7+7+3y\\[/tex]

Combining like terms, we get

[tex]P = 2x + 6y + 22[/tex]

Since we do not have any information on what the variables are, this is the perimeter of the figure.

[tex]\sqrt15-x +\sqrt3-x=6[/tex]

Answers

As currently written, solving for [tex]x[/tex], we have

[tex]\sqrt{15} - x + \sqrt3 - x = 6[/tex]

[tex]2x = \sqrt{15} + \sqrt3 - 6[/tex]

[tex]x = \dfrac{\sqrt{15} +\sqrt3 - 6}2[/tex]

I suspect you meant to write

[tex]\sqrt{15 - x} + \sqrt{3 - x} = 6[/tex]

Move one of the roots to the other side, then take squares on both sides.

[tex]\sqrt{15 - x} = 6 - \sqrt{3 - x}[/tex]

[tex]\left(\sqrt{15 - x}\right)^2 = \left(6 - \sqrt{3 - x}\right)^2[/tex]

[tex]15 - x = 36 - 12 \sqrt{3 - x} + (3 - x)[/tex]

[tex]12 \sqrt{3 - x} = 24[/tex]

Take squares again

[tex]\left(12\sqrt{3-x}\right)^2 = 24^2[/tex]

[tex]144 (3 - x) = 576[/tex]

[tex]432 - 144x = 576[/tex]

[tex]144x = -144[/tex]

[tex]\boxed{x = -1}[/tex]

Find the interval in which the function is positive.
f(x)=x²-7x + 10
1. (-∞0, 2)
II. (2,5)
III. (5,00)
O I, II
O I, III
O II, III
O II only

Answers

Answer:

  (b)  I, III

Step-by-step explanation:

The correct answer can be chosen based on your knowledge of the shape of the graph of f(x).

General shape

The leading coefficient of this quadratic function being positive tells you the graph will be a parabola that opens upward. The left branch of the parabola will extend to positive infinity, as will the right branch.

If there are x-intercepts, the x-values between those will be where the graph has crossed the x-axis and function values are negative.

Specific shape

The answer choices suggest that x=2 and x=5 are x-intercepts of the function's graph. These can be checked, if you like, by evaluating f(2) and f(5).

  f(2) = 2² -7·2 +10 = 4 -14 +10 = 0

  f(5) = 5² -7·5 +10 = 25 -35 +10 = 0

This means the function will be positive for x < 2 and for x > 5. These intervals are described by I and III.

PLEASE HELP FAST!!! Find the surface area of the composite figure. Round your answer to the nearest tenth if necessary.

Answers

The surface area of the composite figure is 524 square meters

Surface area of a figure

The given composite figure is made up of a triangular prism and a rectangular prism. The surface area of the figure is given as:

Surface area = 2(16*5+5*4+16*4) + (16*6) + 2(50)

Take the sum

Surface area = 2(80+20+64) + 96 + 100

Surface area = 2(164) +196

Surface area = 328 + 196

Surface area = 524 square meters

Hence the surface area of the composite figure is 524 square meters

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Briefly, describe the distribution in context. Recall, categorical variables are summarized by counts and/or percents

Answers

Thus, distribution is a function that shows the possible values for a variable and how often they occur and categorical values are summarized by counts and/or percents

In statistics, the distribution is a function that shows the possible values for a variable and how often they occur.

The distribution of a data set is the shape of the graph when all possible values are plotted on a frequency graph. Usually, we are not able to collect all the data for our variable of interest. Therefore we take a sample. This sample is used to make conclusions about the whole data set.

The categorical variable is a data in which individuals are placed into groups or categories.

One way to summarize categorical data is to simply count (frequency), or tally up, the number of individuals that fall into each category. Another way is to show the percentage of individuals who fall into each category, thereby creating a relative frequency.

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A machine manufactuers 300 nails a day. how many did it produce in the month of april 2007

Answers

The machine produces 3000 nails in the month of April 2007.

Production of Nails in the Month of April

According to the given information,

Number of nails manufactured per day by the machine, x = 300  

And, we know that April is the fourth month of a year which has total 30 days.

Hence, number of days the machine is manufacturing nails in the month of April, y = 30

So, the number of nails that will be produced by the machine in the month of April is given by,

N = Number of nails produced per day × Number of days in April

N = xy

N = 300 × 30

N = 9000

Therefore, the machine produces 9000 nails in the April month of year 2007.

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Write the standard form of the equation of the line trough the given point with the given slope.

Answers

Step-by-step explanation:

we use the point-slope approach :

y - y1 = m(x - x1)

m is the slope, and (x1, y1) is a point on the line.

so,

1.

y - 2 = 7(x - 1) = 7x - 7

y = 7x - 5

2.

y - -1 = -1×(x - 3) = -x + 3

y + 1 = -x + 3

y = -x + 2

3.

y - 5 = -4(x - -2) = -4x - 8 (3x a "-" is a "-" for 8)

y = -4x - 3

4.

y - 5 = 5/3 × (x - 3) = 5x/3 - 5

y = 5x/3 or 5/3 × x

Answer:

1. [tex]7x-y=5[/tex]

2. [tex]x+y=2[/tex]

3. [tex]4x+y=-3[/tex]

4. [tex]5x-3y=0[/tex]

Step-by-step explanation:

Since we already know the slope and the coordinates of one point, first use the point-slope form to create an equation.

[tex]y-k=m(x-h)[/tex]

[tex]y-2=7(x-1)[/tex]

[tex]y-2=7x-7[/tex]

[tex]7x-y=5[/tex]

[tex]y+1=-1(x-3)[/tex]

[tex]y+1=-x+3[/tex]

[tex]x+y=2[/tex]

[tex]y-5=-4(x+2)[/tex]

[tex]y-5=-4x-8[/tex]

[tex]4x+y=-3[/tex]

[tex]y-5=\frac{5}{3} (x-3)[/tex]

[tex]y-5=\frac{5}{3}x-5[/tex]

[tex]3y-15=5x-15[/tex]

[tex]5x-3y=0[/tex]

Use the following information to answer the question. The economic impact of an industry, such as sport fishing, can be measured by the retail sales it generates. In 2006, the economic impact of great lakes fishing in states bordering the great lakes had a mean of $318 and a standard deviation of $83.5. Note that all dollar amounts are in millions of dollars. Assume the distribution of retail sales is unimodal and symmetric. (Source: National Oceanic and Atmospheric Administration). For what percentage of great lakes states would you expect the economic impact from fishing to be between $234.5 and $401.5 (in millions of dollars)? ( Hint use the empirical rule)

Answers

The percentage of great lakes states would we expect the economic impact from fishing to be between $234.5 and $401.5 is 50%.

Given that mean is $318 , standard deviation is $83.5 and confidence interval is $234.5 and $401.5.

We have to calculate the percentage of great  lakes that we would expect the economic impact from fishing to be between $234.5 and $401.5.

Because we have not given the sample size taken so we will use any test.We are using z test.

We know that,

z=X-μ/σ

where μ is population mean and σ is population standard deviation.

We cannot find p value between $234.5 and $401.5. We have to find the p value between $234.5 and $318 and then add the p value between $318 and $401.5 by calculating.

P value between $234.5 and $318:

z=234.5-318/83.5

=-83.5/83.5

=-1

p value of -1 is 0.1587

P value between $318 and $401.5:

z=401.5-318.5/83.5

=83.5/83.5

=1

p value of z=1 is 0.3413

Total p value=0.1587+0.3413

=0.5

Total percentage=0.5*100

=50%

Hence the percentage that we would expect the impact to be between $234.5 and $401.5 is 50%.

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am bad at this type of geomtry
pls haIp

x =x=x, equals
^\circ

degrees

Answers

Answer:

15

Step-by-step explanation:

The blue angle and the yellow angle form a linear pair, so they are supplementary (angle measures add up to 180).

180 - 165 = 15

If f(x)=2x-6, which of these is the inverse of f(x)?
○ A. f-¹(x) = 1 +6
X-6
○ B. f-¹(x) = x=6
2
○ C. f-¹(x) = X+6
2
○ D. f¹(x) = -6

Answers

Answer:

f-¹(x) = (x + 6)/2

Step-by-step explanation:

Replace f(x) with y.

y = 2x – 6

Interchange x and y.

x = 2y – 6

Solve for y.

y = (x + 6)/2

Replace y with  f-¹(x)

f-¹(x) = (x + 6)/2

what is the scale factor from ABC to DEF

Answers

Answer:

the scale factor from triangle ABC to triangle DEF would be 8

Step-by-step explanation:

the triangle DEF was actually flipped from triangle ABC

1.line AB corresponds to line EF

AB = 6 , and EF = 48

we multiply 6 by "8" to get to 48

2.line BC corresponds to line ED

BC = 6 , and ED = 48

we multiply 6 by "8" to get to 48

3.line AC corresponds to line FD

AC = 6 , and FD = 48

we multiply 4 by "8" to get to 32

I hope this help

the diffrence of 3-7p^2+11(4+n)

Answers

The expression 3 - 7p² + 11(4 + n) to find an example of each kind of expression is;

The first value is a number, 3 = constantThe second value, -7p² = factorThe third value, 11(4 + n) = binomial and monomial values

Expression

3 - 7p² + 11(4 + n)

The expression has 3 parts

3-7p²11(4 + n)

3 - 7p² + 11(4 + n)

= 3 - 7p² + 44 + 11n

= 47 + 7p² + 11n

Complete question:

Use the expression 3 — 7p2 + 11(4 + n ) to find an example of each kind of expression

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If f is greater than 0 but less than or equal to 90, and cos(22f-1)=sin(7f+4), what is the value of f?

Answers

The value of f from the given expression is 3

Sine and cosine function

Given the expression below

cos(22f-1) = sin(7f+4),

This can also be expressed

cos(22f-1) = cos(90-7f-4)

cos(22f-1) = cos(86-7f)

22f - 1 = 86 - 7f

Collect the like terms

22f+7f = 86 + 1

29f = 87

f = 3

Hence the value of f from the given expression is 3

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Can someone please help me

Answers

Answer:-2.4+3.2t

Step-by-step explanation:

-3.6+1.2-1.9t+5.1t

= -2.4+3.2t

Am what I’m writing is correct? I put 2+-2=0

Answers

The diagram ends at -2

The equation would be 2-4 = -2

Answer:

Step-by-step explanation:

Start on point 2

Ends on point -2

Then:

2 + a = -2

a = -2 - 2

a = -4

then the equation is:

2 + (-4) = 0

2 - 4 = 0

in this triangle, cosA/cosB =
AB = 4.24
BC= 3
AC = 3
<C 90deg.​

Answers

Answer:

1

Step-by-step explanation:

[tex]\cos A=\frac{3}{4.24} \\ \\ \cos B=\frac{3}{4.24} \\ \\ \frac{\cos A}{\cos B}=1[/tex]

How do I solve question 6 through 8?
Solve for me

Answers

The equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

How to determine the functions?

A quadratic function is represented as:

y = a(x - h)^2 + k

Question #6

The vertex of the graph is

(h, k) = (-1, 2)

So, we have:

y = a(x + 1)^2 + 2

The graph pass through the f(0) = -2

So, we have:

-2 = a(0 + 1)^2 + 2

Evaluate the like terms

a = -4

Substitute a = -4 in y = a(x + 1)^2 + 2

y = -4(x + 1)^2 + 2

Question #7

The vertex of the graph is

(h, k) = (2, 1)

So, we have:

y = a(x - 2)^2 + 1

The graph pass through (1, 3)

So, we have:

3 = a(1 - 2)^2 + 1

Evaluate the like terms

a = 2

Substitute a = 2 in y = a(x - 2)^2 + 1

y = 2(x - 2)^2 + 1

Question #8

The vertex of the graph is

(h, k) = (1, -2)

So, we have:

y = a(x - 1)^2 - 2

The graph pass through (0, -3)

So, we have:

-3 = a(0 - 1)^2 - 2

Evaluate the like terms

a = -1

Substitute a = -1 in y = a(x - 1)^2 - 2

y = -(x - 1)^2 - 2

Hence, the equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

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Which expressions are equivalent to 2(4f+2g)-
choose three answers
A. 8f+2g
B. 2f(4 + 2g)
C. 8f+4g
D. 4(2f+g)
E. 4f+4f+4g

Answers

The correct is 8f+4g because 2*4=8 and 2*2 is 4

3 quick algebra 1 questions for 50 points!

Only answer if you know the answer, quick shout-out to Mr.Royal, tysm for the help!

Answers

#1

h(t)=-16t²+58t+2

h(2.5)

-16(2.5)²+58(2.5)+2-16(6.25)+145+2147-10047ft

After 2.5s the ball was at 47ft

#2

g(x)=x²-9

g(0)

-9

g(4)

4²-9=16-9=6

g(7)

7²-949-940

Range

{-9,6,40}

#3

f(-3)=5f(0)=0f(1)=-3

Which rule describes the translation below? on a coordinate plane, triangle s t u is shifted 3 units down and 5 units to the left to form triangle s prime t prime u prime. (x, y) right-arrow (x minus 5, y minus 3) (x, y) right-arrow (x 5, y 3) (x, y) right-arrow (x minus 3, y minus 5) (x, y) right-arrow (x 3, y 5)

Answers

The units of the football are 7x-9 8(x)^2 because without the plain flying it would fall 3(6)^2+ 8~

Can someone help me on this pls? It’s urgent, so ASAP (it’s geometry)

Write formal proofs using HL Theorem.

Answers

Question 2

1) [tex]\overline{PR} \perp \overline{QS}[/tex], [tex]\overline{PQ} \cong \overline{PS}[/tex] (given)

2) [tex]\overline{PR} \cong \overline{PR}[/tex] (reflexive property)

3) [tex]\angle PRQ[/tex] and [tex]\angle PRS[/tex] are right angles (perpendicular lines form right angles)

4) [tex]\triangle PRQ[/tex] and [tex]\triangle PRS[/tex] are right triangles (a triangle with a right angle is a right triangle)

5) [tex]\triangle PRQ \cong \triangle PRS[/tex] (HL)

Question 3

1) [tex]\angle C[/tex] is a right angle, [tex]\overline{AC} \cong \overline{AE}[/tex], [tex]\overline{DE} \perp \overline{AB}[/tex] (given)

2) [tex]\angle DEA[/tex] is a right angle (perpendicular lines form right angles)

3) [tex]\triangle ACD[/tex] and [tex]\triangle DAE[/tex] are right triangles (a triangle with a right triangle is a right angle)

4) [tex]\overline{AD} \cong \overline{AD}[/tex] (reflexive property)

5) [tex]\triangle ACD \cong \triangle AED[/tex] (HL)

6) [tex]\angle CAD \cong \angle DAE[/tex] (CPCTC)

7) [tex]\overline{AD}[/tex] bisects [tex]\angle BAC[/tex] (if a segment splits an angle into two congruent parts, it is an angle bisector)

Lie is solving the quadratic equation by completing the square. 3x2 18x – 8 = 0 3x2 18x = 8

Answers

Answer: The answer is factor 3 out the variable terms

Step-by-step explanation:

POINTS!!!! PLS HELP LOOK AT PIC

Answers

Answer:

first option

Step-by-step explanation:

two solutions means 2 cutting points

help me w this pls thanks

Answers

Answer:

Perimeter: 4+[tex]\pi \\[/tex] mm

Area: [tex]\pi[/tex] mm^2

Step-by-step explanation:

Perimeter:

90/360 * 4[tex]\pi \\[/tex] +2 + 2 = 4+ [tex]\pi \\[/tex]

Area:

90/360 * 4[tex]\pi[/tex] = [tex]\pi[/tex]

Answer: 7.14 mm and 3.14 mm²

Step-by-step explanation:

The perimeter of a figure is the total length on the outside of the figure. A regular circle has a perimeter of [tex]2\pi r[/tex], where r is the radius and [tex]\pi[/tex] is an irrational constant, approximately 3.14.

Due to the right angle, we know that this is a quarter circle, as it is a quarter of 360°, or a full circle. Hence, the curved portion of the quarter circle is [tex]\frac{1}{4}* 2\pi r[/tex] or [tex]\frac{1}{2} \pi r[/tex]. The radius is 2 mm, so this value is

[tex]\frac{1}{2} \pi*2=\pi[/tex]

However, this isn't the total perimeter, as there are straight edges in the figure too. Both edges are radii of the whole circle, so both would be 2mm. Their total is

[tex]2+2=4[/tex]

By adding [tex]\pi[/tex] to 4 we get [tex]\pi +4[/tex] or 7.14 mm.

The  area is the total space enclosed by a figure. The total area of a whole circle is [tex]\pi r^2[/tex], where r is still the radius. Since this is a quarter circle, it would take up a quarter of the area, or [tex]\frac{1}{4} \pi r^2[/tex]. We can plug in 2 for r and solve to get the area.

[tex]\frac{1}{4}\pi*2^2\\\frac{1}{4}\pi*4\\\pi[/tex]

Hence, the area is [tex]\pi[/tex], or around 3.14 mm².

What is the slope of line m? please help

Answers

Here is the solution how to calculate slope

Find the missing angle.

Answers

The missing angle of the right trapezoid is 126°.

Quadrilaterals

There are different types of quadrilaterals, for example, square, rectangle, rhombus, trapezoid, and parallelogram.  Each type is defined accordingly to its length of sides and angles. The trapezoid is a quadrilateral that presents at least one set of parallel sides and the sum of the internal angles is 360°. The trapezoid classifications are:

Right trapezoid - it presents two right angles.Isosceles trapezoid - it presents the congruent non-parallel sides.Scalene trapezoid - it is one in which the non-parallel sides are not congruent.

From the figure, it is possible to see that the image has two right angles. Thus, you have a right trapezoid.

Therefore, from the sum of internal angles, you can find the missing angle:

u+54+90+90=360

u=360-234

u=126

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area of the ceiling of a room 4 metre high is 48 metre square if the area of four walls of the room is 112 m square calculate the length and breadth of a room.​

Answers

Answer:

Breadth=8

Length=6

OR

breadth = 6

length=8

Step-by-step explanation:

Area of 4 walls = 2(l+b)h

112=2.4(l+b)

112/8=l+b

14=l+b

l=14-b

Area of base or ceiling=l x b

48=(14-b).b

48=14b-b²

b²-14b+48=0

factorize it and we get

(b-6)(b-8)=0

taking b-6=0

b=6

l=14-6

l=8

PLEASE HELP HURRYYYYY

Answers

Answer:

See below

Step-by-step explanation:

Looks like positive linear to me....slope is up and to the right (positive) and the line drawn shows it ot be approx linear

An urn contains 11 balls, 3 white, 3 red, and 5 blue balls. Take out two balls at random, without replacement. You win $1 for each red ball you select and lose a $1 for each white ball you select. Let X be the random variable that notes the amount you win. Find the probability mass function (pmf) of X.

Answers

Let X be the number of times you win.

The total number of ways to select 2 balls (order does not matter) =>

The number of ways so that two balls are white:

= 3/55

The number of ways so that two balls are red:

= 3/55

The number of ways so that one ball is red, one is white:

= 9

The number of ways so that two balls are blue:

= 10

i.e. p = 10+9/55 = 19/55

The number of ways so that one ball is blue, one is white:

p = 15/55 = 3/11

The number of ways so that one ball is blue, one is red:

15/55 = 3/11

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