The C++ application that computes and outputs the first 100 elements.
class gfg {
public:
void printNos(unsigned int n) {
if(n > 0) {
printNos(n - 1);
cout << n << " "; }
return; }
};
int main() {
gfg g;
g.printNos(100);
return 0;
}
How do you compute the sum of 1 and 100?All natural numbers between 1 and 100 add up to 5050. In this range, there are 100 natural numbers in total. Thus, we obtain S=5050 by using this number in the formula: S = n/2[2a + (n 1) d].
How can 100 numbers in an array be printed?num[num] = num[num-1] +1; to round the previous number up by one before printing it. Now it prints perfectly. if (int a = 0; a > 100; a++) number[100] += number[a]; / add number[a] to result printf("%d\n",number[100]);
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starting a computer or computer embedded devices is called
Answer:
Booting
Explanation:
starting a computer is called booting. In addition restarting is known as rebooting.
Suppose you present a project and your supervisor comments that the graphics need to be a higher quality and suggests you replace a circuit board. To what circuit board is your supervisor referring?
graphics card
video card
sound card
system card
Answer:graphics card
Explanation:
Answer:
graphics card
Explanation:
Practice Question
What will be displayed after this
code segment is run?
count
0
REPEAT UNTIL (count = 3
count count + 1
DISPLAY
and"
DISPLAY count
"1 and 2 and 3"
"And 1 and 2 and 3"
"0 and 1 and 2"
"And 0 and 1 and 2"
Answer:
Follows are the code to the given question:
#include <stdio.h>//header file
int main()//main method
{
int count=0;//defining an integer variable
for(count=0;count<3;count++)//use for loop to count values
{
printf("%d\n",count);//print count values
}
return 0;
}
Output:
0
1
2
Explanation:
In this code, it declares the integer variable "count" which has a value of "0" and in the next step declares a loop, using the count variable to regulate count values, which is less than 3, and increases the count value, and prints its values. This variable is the count value.
The count variable holds a value of 0, and use a for loop that checks its value is less than 3, and print its value, that's why it will print the value that is 0,1, and 2.
The components of hardware include:
A) Monitor, CPU, Disk Drives, Printer, Keyboard/Mouse
B) Monitor, CPU, Disk Drives, Touch Screen, Keyboard/Mouse
C) Monitor, CPU, Software, Printer, Keyboard/Mouse
D) None of the above
Answer:
A
Explanation:
Monitor, CPU, Disk Drives, Printer, Keyboard/mouse
Answer:
B.monitor,cpu,disk drives,touch screen,keyboard/Mouse
A local real estate company can have its 25 computers upgraded for $1000. If the company chooses only to upgrade 10 systems, how much will the upgrade cost if the same rate is used?
Answer:
it is
Explanation:
400 dollars for 10 systems and 200 dollars for 5 systems
explanation
first
find the price of 1 system or computer which is done by dividing 1000 by 25
25)1000(40
100
____
00
00
__
0
then multiple it by 10 =40 ×10=$400
Answer:
400!!
Explanation:
Computers has done more harm than good
Explanation:
Teueeeeeeeeeeeeeeeeeee
the _ and _ services help us to keep in touch with our family and friends
Answer:
Internet and communication technology
Write code to take two words from the user. The program should convert these to lower case, then compare them: printing a positive number if string1 appears after string2 alphabetically, a negative number if string1 appears before string2 alphabetically and zero if the two strings are identical. Make sure your program does not produce any additional numerical output other than this number or it may not be graded correctly.
Answer:
Use compareTo.
Explanation:
import java.util.Scanner;
public class U2_L3_Activity_Three{
public static void main(String[] args){
Scanner scan = new Scanner(System.in);
System.out.println("Enter first word: ");
String word1 = scan.nextLine();
System.out.println("Enter second word: ");
String word2 = scan.nextLine();
//I had to make the string all lowercase or all uppercase for when I did this
word1 = word1.toLowerCase();
word2 = word2.toLowerCase();
System.out.println("Result: " + word1.compareTo(word2));
}
}
Following are the program to converting string value into lowercase and compare with an input string value.
Program Explanation:
Import package.Defining a class Dat.Inside the class defining the main method, and in the method, two string variable "string1, string2" is declared.After input, the value a "toLowerCase" method is used that converts string value into lower case. After converting value into the lower case a "compareTo" method is used that compares value and prints its value.Program:
import java.util.*;//import package for input
public class Dat //defining a Dat
{
public static void main(String[] ax)//main method
{
String string1 ,string2; //defining String variable
Scanner sc = new Scanner(System.in);//creating Scanner class object to input value
System.out.println("Enter values: ");//print message
string1= sc.next();//input value
string2= sc.next();//input value
string1= string1.toLowerCase();//convert string value into LowerCase
string2 = string2.toLowerCase();//convert string value into LowerCase
System.out.println("Result: " + string1.compareTo(string2));//using compareTo method
}
}
Output:
Please find the attached file.
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What are the three types of networks?
A) Internet, PowerPoint, Excel
B) Internet, LAD, WAN
C) Internet, WAN, LAN
D) None of the above
Answer:
Local Area Network (LAN)
Metropolitan Area Network (MAN)
Wide area network (WAN)
(So C, I'm pretty sure.)
Answer:
LAN,MAN,WANExplanation:
are the three types of network1, How can technology serve to promote or restrict human rights? [2 points]
Answer:
Examples of how technology can be used as a powerful tool for human rights are ever expanding. Newer technologies such as artificial intelligence, automation, and blockchain have the potential to make significant positive contributions to the promotion and protection of human rights.
What are the two choices for incorporating or removing changes when reviewing tracked changes made to a document?
Edit or Apply
Revise or Accept
Accept or Reject
Incorporate or Edit
Answer:
Accept or Reject
Explanation:
The only way to get tracked changes out of the documents is to accept or reject.
So, the correct option is - Accept or Reject
Answer:
C. Accept or reject
Explanation:
Consider the security of a mobile device you use
(a) Explain how transitive trust applies to your use of an operating system on a
mobile device (e.g. smartphone). Then, explain how an attacker can exploit this
transitive trust to violate the CIA properties of the software and data on your
device
Answer:
keep it private
Explanation:
3. Given the following total revenue functions, find the corresponding demand functions:
a) TR = 50Q-4Q²
b) TR = 10
a)TR=50Q4Q2 I hope.this helps
A) The demand function for the total revenue function TR = 50Q - 4Q² is;
P = 50 - 4Q
B) The demand function for the total revenue function TR = 10 is; 10/Q
We are given total revenue functions as;
TR = 50Q - 4Q²
TR = 10
A) TR = 50Q - 4Q²
Formula for revenue function if Q represents the units demanded is;
TR = P × Q
Where P is the demand function
Thus;
50Q - 4Q² = PQ
Divide both sides by Q to get the demand function;
P = 50 - 4Q
B) TR = 10
Formula for revenue function if Q represents the units demanded is;
TR = P × Q
Where P is the demand function
Thus;
10 = P × Q
Divide both sides by Q to get the demand function;
P = 10/Q
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Define 'formatting'
Answer:
Formatting refers to the appearance or presentation of your essay.
Explanation:
Most essays contain at least four different kinds of text: headings, ordinary paragraphs, quotations and bibliographic references.
In order to enhance the training experience and emphasize the core security goals and mission, it is recommended that the executives _______________________.
Answer:
vg
Explanation:
kiopoggttyyjjfdvhi
Write a program that asks the user to enter five test scores. The program should display a letter grade for each score and the average test score. Write the following methods in the program: calcAverage: This method should accept five test scores as arguments and return the average of the scores. determineGrade: This method should accept a test score as an argument and return a letter grade for the score, based on the following grading scale:
Answer:
See comment for complete question
#include <iostream>
using namespace std;
double calc_Average(double sc1, double sc2, double sc3, double sc4, double sc5){
return (sc1 + sc2 + sc3 + sc4 + sc5)/5;
}
char determine_Grade(double score){
char grade;
if(score >= 90 && score <=100){
grade = 'A';}
else if(score >= 80 && score <90){
grade = 'B';}
else if(score >= 70 && score <80){
grade = 'C';}
else if(score >= 60 && score <70){
grade = 'D';}
else if(score <60){
grade = 'F';}
return grade;
}
int main(){
double sc1,sc2, sc3, sc4, sc5;
cout<<"Enter 5 scores: ";
cin>>sc1>>sc2>>sc3>>sc4>>sc5;
cout<<"Score: "<<sc1<<" Grade: "<<determine_Grade(sc1)<<endl;
cout<<"Score: "<<sc2<<" Grade: "<<determine_Grade(sc2)<<endl;
cout<<"Score: "<<sc3<<" Grade: "<<determine_Grade(sc3)<<endl;
cout<<"Score: "<<sc4<<" Grade: "<<determine_Grade(sc4)<<endl;
cout<<"Score: "<<sc5<<" Grade: "<<determine_Grade(sc5)<<endl;
double Ave = calc_Average(sc1,sc2,sc3,sc4,sc5);
cout<<"Average: "<<Ave<<" Grade: "<<determine_Grade(Ave)<<endl;
return 0;
}
Explanation:
The program was written in C++. Because of the length of the explanation, I've added the explanation as an attachment where I used comments to explain the lines of the code.
list out various computer generation long with their basic characteristic
Answer:
1940 – 1956: First Generation – Vacuum Tubes. These early computers used vacuum tubes as circuitry and magnetic drums for memory. ... 1956 – 1963: Second Generation – Transistors. ... 1964 – 1971: Third Generation – Integrated Circuits. ... 1972 – 2010: Fourth Generation – MicroprocessorsExplanation:
there are 4 generations ok
please mark me as brainlist
when working with smart which tab would provide the ability to change the shape or size of the smart art shapes
Answer:
B) Format
Explanation:
It is important to create a strong password because it will
let someone steal your personal information
allow your friends to easily guess it
keep your private information safe and secure
give your computer a virus
You are working with an online tech service to fix a problem with installation of a program on your machine. You grant them remote access to your computer to enable them to act as you to fix situation. What type of must be installed on your machine to allow this type of action by another person
Answer:
Single User OS.
Explanation:
An operating system is a system software pre-installed on a computing device to manage or control software application, computer hardware and user processes.
This ultimately implies that, an operating system acts as an interface or intermediary between the computer end user and the hardware portion of the computer system (computer hardware) in the processing and execution of instructions.
Some examples of an operating system on computers are QNX, Linux, OpenVMS, MacOS, Microsoft windows, IBM, Solaris, VM etc.
There are different types of operating systems (OS) used for specific purposes and these are;
1. Batch Operating System.
2. Multitasking/Time Sharing OS.
3. Multiprocessing OS.
4. Network OS.
5. Mobile OS.
6. Real Time OS .
7. Distributed OS.
8. Single User OS.
A Single User OS is a type of operating system that only allows one user to perform a task or use a system at any time.
In this scenario, you are working with an online tech service to fix a problem with installation of a program on your machine. You grant them remote access to your computer to enable them to act as you to fix situation. Therefore, the type of OS which must be installed on your machine to allow this type of action by another person is called a Single User OS.
Which of the following algorithms is the same as the flowchart shown below?
Start
mylum - RANDOM(1,10)
false
DISPLAY("Done
DISPLAY()
O Amylum - RANDOM (1, 19)
IF (byllum > 8)
(
DISPLAY("Done")
ELSE
(
DISPLAY(myNum)
}
OB. myllum - RANDOM(1, 18)
REPEAT UNTIL (byllum > 8)
{
DISPLAY(myNum)
myllum - RANDOM(1,18)
}
DISPLAY("Done")
Octylum - RANDOM(1, 18)
IF (myllum < 8)
{
DISPLAY("Done")
ELSE
{
DISPLAY(myllum)
)
O D. myllum - RANDOM(1, 18)
REPEAT UNTIL (myNun > 8)
{
DISPLAY("Done")
DISPLAY(byllum)
Answer:
choice b
Explanation:
The algorithms are the same as the flowchart shown below is myllum - RANDOM(1, 18), REPEAT UNTIL (byllum > 8) { DISPLAY(myNum)myllum - RANDOM(1,18)} DISPLAY("Done"). The correct option is B.
What is an algorithm?The definition of algorithms in computer science. An algorithm is a list of instructions used in computer science to solve problems or carry out activities based on knowledge of potential solutions.
Think of a "black box," or a container where nobody can see what is occurring within. The box accepts our input and produces the output we require, but the process by which input is transformed into the intended output—and which we may need to understand—is an ALGORITHM.
Therefore, the correct option is B. myllum - RANDOM(1, 18)REPEAT UNTIL (byllum > 8){DISPLAY(myNum)myllum - RANDOM(1,18)}DISPLAY("Done").
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Hello! So I have been practising some coding, however, there seems to be an error in my code. I have been trying to figure out what is wrong, however, I just can't seem to find it. There is no syntax error but, there seems to be a problem with my input. I am currently using repl.it and I am making a calculator. I would input something like "multiply" however, the calculator would only square. I have tried changing the variables but it just keeps coming back to the first "if" statement. I would appreciate some help.
Answer:
You OR expressions are wrong.
Explanation:
Rather than writing:
if method == "Square" or "square":
You should write:
if method == "Square" or method == "square":
The expression should evaluate to something that is true or false.
In the above case, the expression is method == "Square" or method == "square" which can are actually two sub-expressions with an or in between them:
subexpr1 or subexpr2
each of the sub-expressions should evaluate to true or false.
method == "Square" is one of those sub-expressions.
That is how an expression is broken down by the compiler.
TIP: If you would add method = method.lower() right after the input, you could simplify all the if statements by removing the uppercase variants.
Cole has to edit and resize hundreds of photographs for a website. Which Adobe
software program would be the best choice to complete this task?
a.) Animate b.) Dreamweaver c.) Illustrator d.) Photoshop
A school has 100 lockers and 100 students. All lockers are closed on the first day of school. As the students enter, the first student, denoted S1, opens every locker. Then the second student, S2, begins with the second locker, denoted L2, and closes every other locker (i.e. every even numbered locker). Student S3 begins with the third locker and changes every third locker (closes it if it was open, and opens it if it was closed). Student S4 begins with locker L4 and changes every fourth locker. StudentS5 starts with L5 and changes every fifth locker, and so on, until student S100 changes L100.After all the students have passed through the building and changed the lockers, which lockers areopen? Write a program to find your answer.(Hint: Use an array of 100 boolean elements. each of which indicates whether a locker is open (true) or closed (false). Initially, all lockers are closed.)
Solution :
public class NewMain {
public_static void main_(String[] args) {
boolean[] _locker = new boolean_[101];
// to set all the locks to a false NOTE: first locker is the number 0. Last locker is the 99.
for (int_i=1;i<locker_length; i++)
{
locker[i] = false;
}
// first student opens all lockers.
for (int i=1;i<locker.length; i++) {
locker[i] = true;
}
for(int S=2; S<locker.length; S++)
{
for(int k=S; k<locker.length; k=k+S)
{
if(locker[k]==false) locker[k] = true;
else locker[k] = false;
}
}
for(int S=1; S<locker.length; S++)
{
if (locker[S] == true) {
System.out.println("Locker " + S + " Open");
}
/* else {
System.out.println("Locker " + S + " Close");
} */
}
}
}
can anyone teach me the basics of lua scripts 50 points
like how do i tell lua to move a object or send me a prompt asking me to do something
Answer:
are you talking about about a game, or coding?
Write a program that asks the user to enter a date in MM/DD/YYYY format that is typical for the US, the Philippines, Palau, Canada, and Micronesia. For the convenience of users from other nations, the program computes and displays this date in an alternative DD.MM.YYYY format. Sample run of your program would look like this: Please enter date in MM/DD/YYYY format: 7/4/1776 Here is the formatted date: 04.07.1776 You can assume that the user will enter correctly formatted date, but do not count on having 0s in front of one-digit dates. Hint: you will need to use string addition (concatenation) here.
Answer:
In Python:
txt = input("Date in MM/DD/YYYY format: ")
x = txt.split("/")
date=x[1]+"."
if(int(x[1])<10):
if not(x[1][0]=="0"):
date="0"+x[1]+"."
else:
date=x[1]+"."
if(int(x[0])<10):
if not(x[0][0]=="0"):
date+="0"+x[0]+"."+x[2]
else:
date+=x[0]+"."+x[2]
else:
date+=x[0]+"."+x[2]
print(date)
Explanation:
From the question, we understand that the input is in MM/DD/YYYY format and the output is in DD/MM/YYYY format/
The program explanation is as follows:
This prompts the user for date in MM/DD/YYYY format
txt = input("Date in MM/DD/YYYY format: ")
This splits the texts into units (MM, DD and YYYY)
x = txt.split("/")
This calculates the DD of the output
date=x[1]+"."
This checks if the DD is less than 10 (i..e 1 or 01 to 9 or 09)
if(int(x[1])<10):
If true, this checks if the first digit of DD is not 0.
if not(x[1][0]=="0"):
If true, the prefix 0 is added to DD
date="0"+x[1]+"."
else:
If otherwise, no 0 is added to DD
date=x[1]+"."
This checks if the MM is less than 10 (i..e 1 or 01 to 9 or 09)
if(int(x[0])<10):
If true, this checks if the first digit of MM is not 0.
if not(x[0][0]=="0"):
If true, the prefix 0 is added to MM and the full date is generated
date+="0"+x[0]+"."+x[2]
else:
If otherwise, no 0 is added to MM and the full date is generated
date+=x[0]+"."+x[2]
else:
If MM is greater than 10, no operation is carried out before the date is generated
date+=x[0]+"."+x[2]
This prints the new date
print(date)
A data science experiment you are conducting has retrieved two historical observations for the price of Bitcoin(BTC) on December 2, 2017 of 11234 and 12475. Create a Python script that stores these two historicalobservations in a list variable namedbtcdec1.
Answer:
In Python:
btcdec1 = []
btcdec1 = [11234, 12475]
print(btcdec1)
Explanation:
First, create an empty list named btcdec1
btcdec1 = []
Next, insert the two data (11234 and 12475) into the list
btcdec1 = [11234, 12475]
Lastly, print the list
print(btcdec1)
Write your own printArray() function found in Processing for the Arduino. For simplicity, you can limit printArray() to integer arrays and you will also pass the size of the array to your function. For example, given the following code:
int terps[5] = {7, 9, 12, 1, 46};
void printArray(int arrayToPrint[], int arraySize) { // YOUR CODE HERE }
void setup()
{ // put your setup code here, to run once:
Serial.begin(9600);
}
void loop() {
// put your main code here, to run repeatedly:
printArray(terps,sizeof(terps)/sizeof(int)); delay(1000);
}
You should repeatedly see the following in the serial monitor:
[0]: 7
[1]: 9
[2]: 12
[3]: 1
[4]: 46
Answer:
Follows are the method definition to this question:
void printArray(int arrayToPrint[], int arraySize) //defining a method printArray that accepts two array in its parameters
{
for (int j = 0; j < arraySize; j++)//defining for loop print Serial numbers
{
Serial.print("[");//use print method to print square bracket
Serial.print(j);//use print method to print Serial numbers
Serial.print("]: ");//use print method to print square bracket
Serial.println(arrayToPrint[j]);//printing array value
}
}
Explanation:
In the above code, a method "printArray" is declared that holds two arrays "arrayToPrint and arraySize" as a parameter, and inside the method is used for loop to print the values.
In the loop, first, it uses the square bracket to print the serial number and in the last step, it prints array values.
You are given the following segment of code:Line 1: PROCEDURE printScorePairs()Line 2: {Line 3: count <-- 0Line 4: sum <-- 0Line 5: i <-- 1Line 6: scores <-- [73, 85, 100, 90, 64, 55]Line 7: REPEAT UNTIL ( i > LENGTH (scores) )Line 8: {Line 9: sum <-- scores[i] scores[i 1]Line 10: DISPLAY ( sum )Line 11: i <-- i 2Line 12: }Line 13: }The ABC company is thrifty when it comes to purchasing memory (also known as RAM) for its computers. Therefore, memory is of the utmost importance and all programming code needs to be optimized to use the least amount of memory possible. What modifications could be made to reduce the memory requirements without changing the overall functionality of the code?
Answer:
Move Line 10 to after line 12
Explanation:
Required: Modify the program
From the procedure above, the procedure prints the sum at each loop. Unless it is really necessary, or it is needed to test the program, it is not a good practice.
To optimize the program, simply remove the line at displays the sum (i.e. line 10) and place it at the end of the loop.
So, the end of the procedure looks like:
Line 10: i <-- i 2
Line 11: }
Line 12: DISPLAY ( sum )
Line 13:
You are asked to write a program that prompts the user for the size of two integer arrays, user input for the size must not exceed 50, you must validate this. We will use these arrays to represent our sets. These arrays will be randomly populated in the range that is 1 through double the size of the array. So if the array is of size 20, you will randomly populate it with values in the range 1-40 inclusive.
Answer:
In Java:
import java.util.*;
public class MyClass{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("Length of array 1: ");
int lent1 = input.nextInt();
while(lent1 <= 0 || lent1 > 50){
System.out.print("Length of array 1: ");
lent1 = input.nextInt();
}
int[] array1 = new int[lent1];
System.out.print("Length of array 2: ");
int lent2 = input.nextInt();
while(lent2 <= 0 || lent2 > 50){
System.out.print("Length of array 2: ");
lent2 = input.nextInt();
}
int[] array2 = new int[lent2];
for(int i =0;i<lent1;i++){
array1[i] = (int)(Math.random() * (lent1*2) + 1);
}
for(int i =0;i<lent2;i++){
array2[i] = (int)(Math.random() * (lent2*2) + 1);
}
System.out.print("Array 1: ");
for(int i =0;i<lent1;i++){
System.out.print(array1[i]+" ");
}
System.out.println("Array 2: ");
for(int i =0;i<lent2;i++){
System.out.print(array2[i]+" ");
}
}
}
Explanation:
This prompts the user for length of the first array
System.out.print("Length of array 1: ");
This declares and gets input for the length of the first array
int lent1 = input.nextInt();
This validates the length of first array
while(lent1 <= 0 || lent1 > 50){
System.out.print("Length of array 1: ");
lent1 = input.nextInt(); }
This declares the first array
int[] array1 = new int[lent1];
This prompts the user for length of the second array
System.out.print("Length of array 2: ");
This declares and gets input for the length of the second array
int lent2 = input.nextInt();
This validates the length of the second array
while(lent2 <= 0 || lent2 > 50){
System.out.print("Length of array 2: ");
lent2 = input.nextInt(); }
This declares the second array
int[] array2 = new int[lent2];
The following generates random integers between 1 and lent1*2 to array 1
for(int i =0;i<lent1;i++){
array1[i] = (int)(Math.random() * (lent1*2) + 1); }
The following generates random integers between 1 and lent2*2 to array 2
for(int i =0;i<lent2;i++){
array2[i] = (int)(Math.random() * (lent2*2) + 1); }
This prints the header Array 1
System.out.print("Array 1: ");
The following iteration prints the content of the first array
for(int i =0;i<lent1;i++){
System.out.print(array1[i]+" ");
}
This prints the header Array 2
System.out.println("Array 2: ");
The following iteration prints the content of the second array
for(int i =0;i<lent2;i++){
System.out.print(array2[i]+" ");
}