Write the number 689,000,000,000,000 in scientific
notation.

Answers

Answer 1

Answer:

6.89 x 10^14

Step-by-step explanation:


Related Questions

x^2+5y^2+2y=75; dx/dt =14 when x= 6 and y=-3; find dy/dt

Answers

Answer:

7

Step-by-step explanation:

x² + 5y² + 2y = 75

2x + 10y * dy/dx + 2 dy/dx = 0

2x + (10y + 2) dy/dx = 0

x + (5y + 1) dy/dx = 0

when x = 6, y = -3

6 + (-15 + 1) dy/dx = 0

6 - 12 dy/dx = 0

dy/dx = 1/2

dy/dt = dy/dx * dx/dt = 1/2 * 14 = 7

Jude is arranging for a party to be held in the students' union. The use
of the hall will be free but security costs of £300 will have to be met.
The cost of the main band will be £2,500 and the supporting band will
cost £500. Tickets will be priced at £16 each. On arrival, every ticket
holder will be given a bottle of water, worth £1 per bottle. If Jude sells
400 tickets as he anticipates, what profit will he make?
19:08

Answers

The profit that Jude made during the party was £3700.

What is profit?

Profit is the difference between revenue and cost. It is given by:

Profit = Revenue - Cost

From the question:

The total cost = 300 + 2500 + 500 + (1 * 400 people) = £3700

Revenue = 400 ticket * £16 = £6400

Profit = Revenue - Cost = £6400 - £3700

The profit that Jude made during the party was £3700.

Find out more on profit at: https://brainly.com/question/23103804

Solve using quadratic formula for 2x^(2)-10x+5=0

Answers

Answer:

[tex]x=\frac{5+\sqrt{15}}{2},\:x=\frac{5-\sqrt{15}}{2}[/tex]

Step-by-step explanation:

[tex]\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}[/tex]

[tex]x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]

[tex]\mathrm{For\:}\quad a=2,\:b=-10,\:c=5[/tex]

[tex]x_{1,\:2}=\frac{-\left(-10\right)\pm \sqrt{\left(-10\right)^2-4\cdot \:2\cdot \:5}}{2\cdot \:2}[/tex]

[tex]\sqrt{\left(-10\right)^2-4\cdot \:2\cdot \:5}[/tex]

Apply exponent rule: (-a)^n=a^n, if n is even

[tex]\left(-10\right)^2=10^2[/tex]

[tex]=\sqrt{10^2-4\cdot \:2\cdot \:5}[/tex]

[tex]\mathrm{Multiply\:the\:numbers:}\:4\cdot \:2\cdot \:5=40[/tex]

[tex]=\sqrt{10^2-40}[/tex]

[tex]10^2=100[/tex]

[tex]=\sqrt{100-40}[/tex]

[tex]\mathrm{Subtract\:the\:numbers:}\:100-40=60[/tex]

[tex]=\sqrt{60}[/tex]

[tex]60\:\mathrm{divides\:by}\:2\quad \:60=30\cdot \:2[/tex]

[tex]=2\cdot \:30[/tex]

[tex]30\:\mathrm{divides\:by}\:2\quad \:30=15\cdot \:2[/tex]

[tex]=2\cdot \:2\cdot \:15[/tex]

[tex]15\:\mathrm{divides\:by}\:3\quad \:15=5\cdot \:3[/tex]

[tex]=2\cdot \:2\cdot \:3\cdot \:5[/tex]

[tex]2,\:3,\:5\mathrm{\:are\:all\:prime\:numbers,\:therefore\:no\:further\:factorization\:is\:possible}[/tex]

[tex]=2\cdot \:2\cdot \:3\cdot \:5[/tex]

[tex]=2^2\cdot \:3\cdot \:5[/tex]

[tex]=\sqrt{2^2\cdot \:3\cdot \:5}[/tex]

Apply Radical Rule:

[tex]=\sqrt{2^2}\sqrt{3\cdot \:5}[/tex]

Apply Radical Rule:

[tex]\sqrt{2^2}=2[/tex]

[tex]=2\sqrt{3\cdot \:5}[/tex]

[tex]\mathrm{Refine}[/tex]

[tex]=2\sqrt{15}[/tex]

[tex]x_{1,\:2}=\frac{-\left(-10\right)\pm \:2\sqrt{15}}{2\cdot \:2}[/tex]

[tex]\mathrm{Separate\:the\:solutions}[/tex]

[tex]x_1=\frac{-\left(-10\right)+2\sqrt{15}}{2\cdot \:2},\:x_2=\frac{-\left(-10\right)-2\sqrt{15}}{2\cdot \:2}[/tex]

[tex]\frac{-\left(-10\right)+2\sqrt{15}}{2\cdot \:2}[/tex]

Apply Rule -(-a)=a

[tex]=\frac{10+2\sqrt{15}}{2\cdot \:2}[/tex]

[tex]\mathrm{Multiply\:the\:numbers:}\:2\cdot \:2=4[/tex]

[tex]=\frac{10+2\sqrt{15}}{4}[/tex]

[tex]=\frac{2\left(5+\sqrt{15}\right)}{4}[/tex]

[tex]\mathrm{Cancel\:the\:common\:factor:}\:2[/tex]

[tex]=\frac{5+\sqrt{15}}{2}[/tex]

[tex]\frac{-\left(-10\right)-2\sqrt{15}}{2\cdot \:2}[/tex]

[tex]=\frac{10-2\sqrt{15}}{2\cdot \:2}[/tex]

[tex]\mathrm{Multiply\:the\:numbers:}\:2\cdot \:2=4[/tex]

[tex]=\frac{10-2\sqrt{15}}{4}[/tex]

[tex]=\frac{2\left(5-\sqrt{15}\right)}{4}[/tex]

[tex]\mathrm{Cancel\:the\:common\:factor:}\:2[/tex]

[tex]=\frac{5-\sqrt{15}}{2}[/tex]

[tex]\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}[/tex]

[tex]x=\frac{5+\sqrt{15}}{2},\:x=\frac{5-\sqrt{15}}{2}[/tex]

A bag contains ten tiles labeled B, C, D, E, F, G, H, I, J, and K. One tile will be randomly picked.
What is the probability of picking a letter that is not a vowel?

Answers

Answer:

4/5

Step-by-step explanation:

There are 10 tiles total, and E and I are vowels. This makes 2/10 of the tiles tiles. The other 8/10 are not vowels.

8/10 can be simplified down to 4/5.

There is a 4/5 probability of picking a letter that is not a vowel.

Find the value of x for which m || n.
The value of x for which m | n is
n

Answers

Answer:

x=40

Step-by-step explanation:

The angles of both expressions (4x-28) and (3x+12) are congruent (alternating exterior angles). So, you can set up the equation 4x-28 = 3x+12 because both expressions are equivalent, so it makes sense. Then solve for x.

4x - 28 = 3x + 12

x - 28 = 12

x = 40

4. You are given 20 boxes. 19 of the boxes each have 20 balls weighing 30kg per ball. However, one box has 20 balls weighing 29kg each. All the balls and boxes are identical in appearance. You are asked to determine which box contains the 29kg balls. You have a suitable scale, but may only take a single measurement. No other measurements may be taken (like trying to determine by hand). You may remove balls from the boxes but may still only take one measurement. How can you determine the box with 29kg balls.

Answers

To find out the box number the boxes, extract the same number of balls as the number of the box, calculate the total weight.

What are the steps to find the box with the 29 kg balls?

Considering you can only weigh the balls extracted once and you need to find the box with balls that are 1-kilo lighter; here are the steps you can follow:

Number the boxes from 1 to 19.Extract the same number of balls as the number given to the box. For example, from box 9 extract 9 balls.Weight all the balls together.Find out the box with the 29 kg balls. Here is an example:

The total weight using this method would be 6,300 kg which is the result of adding 30 kg (first box) + 60 kg (second box)... However, since there is a box with lighter balls the total weight will be less.

Let's imagine the weight is 6,290, this means there are 10 fewer kilos and therefore the box with the lighter balls is box 10 since this is the box number from which 10 balls were extracted.

Learn more about weight in: https://brainly.com/question/10069252

Use the given equation to find the missing coordinates of the points and then find the slope of the line for each equation.

y= -2/3x+1/6, A(..., 6), B(9,...)

Answers

A(-8.75, 6), B(9, -5 2/6). The slope of the function is -2/3.

look at picture need done asap!

Answers

Answer:

down

Step-by-step explanation:

c) 6 and 8

a) 7 and 1

b) 5 and 4

Aman borrowed $ 3000 from a bank for 3 months . A friend was cosigner of the man's personal note . The bank collected 3 1 2 \% simple interest on the date of maturity a ) How much did the man pay for the use of the money ? b Determine the amount he repaid to the bank on the due date of the note .

Answers

Answer:3500

Step-by-step explanation:

Convert the point-slope equation y - 8 = -(x - 4) into standard form.

Answers

Answer:

x+y=12

Step-by-step explanation:

Standard form is ax+by=c

Given, y-8 = -(x-4)

y-8=-x+4

x+y=4+8

x+y=12

Answer:

x + y = 12

Step-by-step explanation:

Standard form is Ax+By=C

so the goal is to get the y and the x on the same side without and negatives or fractions on that side.

y - 8 = - (x - 4)  first, start by simplifying

y - 8 = -x +4  next, because it is negative, we are going to add x to -x on the right side to get it to cancel out and we'll add x to y on the left side

x + y - 8 = 4  now we need to get rid of that eight so we'll add 8 to -8 so it cancels out and we'll add 8 to 4

x + y = 12 now it is in standard form

PLEASE HELP FAST

The Pythagorean theorem states that a² + b² = c² for a right triangle with leg lengths, a and b, and hypotenuse length, c.

The hypotenuse of a right triangle is 5 units long and has the points (3, 0) and (0, 4) as end points. One of the legs has length 3.

Use the Point and Segment tools to draw a right triangle at demonstrates the other leg length is 4.

Answers

Answer:

Uh how to use segmant tool

Step-by-step explanation:

not there

If out of 15 pencils 2 times of the one third are disributed as priza how many pencils are left there​

Answers

Answer:

Suppose there are x students,

a) 4 pencils  x students+20 (*=multiplication)

b) 5 pencilsx students+10

But a = b so

4x+20=5x+10

x=10

4 10+20 or 5 10+10 = 60 pencils.

Hope it helps!!!Brainliest pls!!!

what is the standard form of the linear equation of the line through (-7,8) with a slope of 3/4

Answers

Answer:

See below.

Step-by-step explanation:

When graphed, the line would have a y-intercept of 13.25.

So, the equation would be y=3/4x+13.25.

-hope it helps

Please help with factor trees
Pls there is a pic when u click here

Answers

Step-by-step explanation:

320 = 80 × 4

80 = 8 × 10

4 = 2 × 2

10 = 5 × 2

bold one's are answer.

hope this helps you.

Which is the best estimate for
written in scientific notation?

Answers

Answer:

3 x 10^4

(3rd option)

Step-by-step explanation:

8.9 divided by 3.3 is 2.69

8.9 is roughly 9

3.3 is roughly 3

9 divided 3 is 3

10^8 divided 10^4 is 10^4

when dividing numbers with exponents you subtract the exponents

so the best estimate is

3 x 10^4

List the prices for the first 8 carwashes of each package below.

Answers

Answer:

you might have to post a pic of the question

a candy company usually makes bags that have 100 candies in them? Each bag included 25 blue, 30 red, 25 green and 20 orange candies. If you had ten bags of candy in front of you and you reached into each one and grabbed just one candy how many red candies would you expect to have

Answers

The expected number of red candy that you will get out of 10 bags is 3 red candies.

How many red candies you would expect to get?

In each bag there are 100 candies, such that there are:

25 blue30 red25 green20 orange.

All the candies have the same probability of being randomly selected, so the probability of getting a red candy is equal to the quotient between the number of red candies in each bag and the total number of candy.

P = 30/100 = 0.3

Then if you draw one candy of each bag of 10 bags, the expected number of red candies that you will have is 10 times the above probability:

N = 10*P = 10*0.3 = 3

3 red candies.

If you want to learn more about probability, you can read:

https://brainly.com/question/251701

Find the HCF of the given pair of numbers using the prime factorization method 48 and 60.​

Answers

Answer:

12

Step-by-step explanation:

Given :-

Two numbers => 48 and 60

To Find :-

HCF of 48 and 60

Solving :-

Prime factorize the numbers.

48 = 2⁴ x 3

60 = 2² x 3 x 5

Solution :-

HCF (48, 60) = 2² x 3 = 12

What is the value of x? X
+ 4/9= 3/4

Answers

Answer:

X = 11/36

Step-by-step explanation:

First, find the common denominator of the fractions and convert them.

(4/9) x 4 = 16/36

(3/4) x 9 = 27/36

X + 16/36 = 27/36

Now you can solve for X

X = 11/36

The fraction cannot be simplified

Here are scores for two softball teams for seven innings. Rosie's Riveters beat The Susan Bees by how many runs?

Answers

Answer:

3

Step-by-step explanation:

Expand the polynomial.

(-1-2a^2b)(1-2a^2b)

Answers

Was it this instead? [tex](-1-2a^{2}b)(1-2a^{2}b)[/tex]

Answer:

[tex]4a^{4b}-1[/tex]

Step-by-step explanation:

I am assuming your question is this.

[tex](-1-2a^{2b})(1-2a^{2b})[/tex]

Apply the difference of 2 squares formula.

[tex](a-b)(a+b)=a^{2} -b^{2}[/tex]

So then we have.

[tex](-1-2a^{2b})(1-2a^{2b})=(-2a^{2b})^{2}-1^{2}[/tex]

Then simplify.

[tex]4a^{4b}-1[/tex]

[tex] \rm\int^{\infty}_{0} \frac{ \sqrt{x} \arctan(x) }{1 + {x}^{2} }\: dx\\ [/tex]​

Answers

Let

[tex]I(a) = \displaystyle \int_0^\infty \frac{\sqrt x \arctan(ax)}{1+x^2} \, dx[/tex]

Differentiate with respect to a :

[tex]I'(a) = \displaystyle a \int_0^\infty \frac{x^{\frac32}}{(1+x^2)(1+a^2x^2)} \, dx[/tex]

Substitute y = √x :

[tex]I'(a) = \displaystyle 2a \int_0^\infty \frac{y^4}{(1+y)(1+a^2y)} \, dy[/tex]

Polynomial division yields

[tex]\dfrac{y^4}{(1+y)(1+a^2y)} \\\\ = \dfrac1{a^2}y^2 - \left(\dfrac1{a^2} + \dfrac1{a^4}\right)y + \dfrac1{a^2} + \dfrac1{a^4} + \dfrac1{a^6} - \dfrac{\left(1+\frac1{a^2} + \frac1{a^4} + \frac1{a^6}\right)y + \frac1{a^2} + \frac1{a^4} + \frac1{a^6}}{(1+y)(1+a^2y)}[/tex]

Computing I'(a) isn't so difficult from here. You'd find (assuming a ≥ 0)

[tex]I'(a) = \displaystyle \frac\pi{\sqrt2\left(\sqrt a + a + a^{\frac32} + a^2\right)}[/tex]

Integrate both sides with respect to a. On the right side, substituting b = √a yields

[tex]\displaystyle \int \frac{da}{\sqrt a + a + a^{\frac32} + a^2} = \int \frac{2b}{b + b^2 + b^3 + b^4} \, db \\\\ = 2 \int \frac{db}{1 + b + b^2 + b^3} \\\\ = 2 \int \frac{db}{(1+b)(1+b^2)} \\\\ = \int \left(\frac1{1+b} + \frac{1-b}{(1+b^2)}\right) \, db \\\\ = \frac14 \left(2 \arctan(b) + 2 \ln(1 + b) - \ln(1 + b^2)\right) + C \\\\ = \frac14 \left(2 \arctan(\sqrt a) + 2 \ln(1 + \sqrt a) - \ln(1 + a)\right) + C[/tex]

Noting that a = 0 makes the integral I(a) vanish, we have

[tex]0 = \dfrac14 \left(2 \arctan(\sqrt0) + 2\ln(1 + \sqrt0) - \ln(1 + 0)\right) + C \implies C = 0[/tex]

and so

[tex]\displaystyle I(a) = \frac\pi{4\sqrt2} \left(2 \arctan(\sqrt a) + 2 \ln(1 + \sqrt a) - \ln(1 + a)\right)[/tex]

We recover the integral we want with a = 1, which gives a value of

[tex]\displaystyle \int_0^\infty \frac{\sqrt x \arctan(x)}{1 + x^2} \, dx = \boxed{\frac{\pi^2 + 2\pi\ln(2)}{4\sqrt2}}[/tex]

It looks like rsu might be a right angle is it?
Please help with A and B

Answers

Answer:

(b) NO

Step-by-step explanation:

It must have the square to to be a right angle

Answer:

A: It is obtuse

B: It is a right angle

Step-by-step explanation:

A: Angle RST equals 110*, if it is greater than 90*, it is obtuse

B: Right Angles are 90*, so this is simple, you subtract RST by UST, so 110-20=90

Here are scores for two softball teams for seven innings. Rosie's Riveters beat The Susan Bees by how many runs?
here is the score

Answers

13-10=3, they won by 3 runs.

Answer:

3

Step-by-step explanation:

Rosie's Riveters

1 + 3 + 4 + 2 + 1 + 0 + 2 = 13

Susan Bees

0 + 0 + 5 + 3 + 0 + 1 + 1 = 10

To find out how many they beat the Susan Bees by you need to subtract.

13 - 10 = 3

Rosie's Riveters beat the Susan Bees by 3 runs.

Determine whether the following represents a linear relationship or a nonlinear relationship.

Answers

Answer:

the answer to this is

A) nonlinear

Step-by-step explanation:

this is not linear because the line is not a line that goes in 1 direction. It has points of an increase and decrease so it is non linear

Answer:

it is not linear

Step-by-step explanation:

It is not a linear line because it is not going straight

Lines M and N are parallel. Name the relationship between ∠a and ∠b.

Answers

Answer:

alternate angled

Step-by-step explanation:

add up to 180

Define the type of sequence below.
2, 0, 2, 4, 6, ....
O A. neither arithmetic nor geometric
O B. geometric
O C. both arithmetic and geometric
O D. arithmetic

Answers

Answer: A. Neither arithmetic nor geometric

========================================================

Explanation:

Going from the first term to the second, we add on -2

Then going from the second term to the third, we add on +2

This inconsistency (-2 vs +2) means we don't have a common difference, and therefore the sequence is not arithmetic.

------------

Now let's divide each term by their previous term

term2/term1 = 0/2 = 0

term3/term2 = 2/0 = undefined

We can stop here and conclude that we don't have a common ratio either, so this sequence is not geometric.

------------

Side note: The subsequence 0,2,4,6,... is arithmetic with common difference d = 2 because we add 2 to each term. It's that first 2 in the original sequence that breaks everything.

A Because yeah it’s just a

Please help! Will give brainiest if correct

Answers

Answer:

Step-by-step explanation:

First Choice

true or false - Agriculture and trade influenced the growth of civilization in ancient Egypt.
True
False

Answers

Answer:

The answer is True.

Step-by-step explanation:

The earliest civilizations developed between 4000 and 3000 BCE, when the rise of agriculture and trade allowed people to have surplus food and economic stability.

Hope this helps you!

the table shows a relation between x and y.

is the relation a function, and why?

Answers

Function Definition

A function is a relation in which there is only one y-value for every x-value.

If we given an input of 3 for x, for example, we would only get one output for y, like 1, for example.

Answer

If we look at the table, we can see that the x-value of 3 gives us two outputs: 7 and 9.

Therefore, this relation is not a function.

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