Answer: 12/4
Step-by-step explanation: whole number = 3. given denominator = 4. 4/4 = 1. 1 times 3 = 3. 4 plus 4 plus 4 = 12. therefore answer is 12/4
question in the picture below
The doubling time after 4 and 7 years is 400 months and 700 months respectively
How to determine the doubling timeThe formula for finding doubling time is given as;
Doubling time = [tex]t \frac{In 2}{In 1 + \frac{r}{100} }[/tex]
Where t = time = 4 and 7 years
r = rate
For 4 years, we have
Doubling time = [tex]4 * \frac{In 2}{In ( 1 + \frac{0.7}{100}) }[/tex]
⇒ [tex]4 * \frac{In 2}{In 1. 0074}[/tex]
⇒ [tex]4 * \frac{0. 6931}{0. 0074}[/tex]
⇒ [tex]4[/tex] × [tex]93. 66[/tex]
⇒ 374. 65
⇒ 400 months in the nearest hundredth
For 7 years
⇒ [tex]7[/tex] × [tex]93. 66[/tex]
⇒ [tex]655. 62[/tex]
⇒ 700 months in the nearest hundredth
Thus, the doubling time after 4 and 7 years is 400 months and 700 months respectively
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Assume a = b and c ≠ 0
Which of the following sentences is not true?
1) a+c=b+c
2) a-c=b-c
3) ac = bc
4) a/c = b/c
5) none of these
Answer:
None of these is not true
An exponential function f ( x ) = a b x f ( x ) = a b x passes through the points (0, 10000) and (3, 2160). What are the values of a and b ?
The values of a and b of the exponential function are 10000 and 0.6 respectively
How to solve exponential functions?We are given that the exponential function is expressed in general form as; f(x) = abˣ
where;
a is a non-zero real number called the initial value
b is any positive real number such that
b ≠ 1.
The domain of f is all real numbers.
The range of f is all positive real numbers if a > 0.
The range of f is all negative real numbers if a < 0.
The y-intercept is (0, a)
The horizontal asymptote is; y = 0.
We are told that this exponential function passes through the coordinate points (0, 10000) and (3, 2160).
At coordinate point (0, 10000), we have;
10000 = ab⁰
a = 10000
Now, at the coordinate point (3, 2160), we have;
2160 = 10000(b)³
2160/10000 = b³
0.216 = b³
b = ∛0.216
b = 0.6
Thus, we can conclude that the values of a and b of the given exponential function are respectively 10000 and 0.6.
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Anyone know the answer please teach me
Answer: Look at step by step
Step-by-step explanation:
(a) There are 119 stocks that increased in price out of 246 stocks so the probability of selecting a stock that is increased in price is 119/246 = 48.37%
(b) There are 112 stocks where it pays dividends so the probability so the probability of selecting a stock that pays dividends is 112/246 = 45.53%
(c) There are 49 stocks which satisfy the question so the probability is 49/246 = 19.92%
(e) There are 34 stocks which increase in price and pay dividends out of the 119 stocks that increase in price so the probability is 34/119 = 28.57%
(f) Using the same logic as (e), the probability is 85/134 = 63.43%
(g) From the requirements, we see that 49 stocks don't satisfy the requirements, so the probability is (246-49)/246 = 80.08%
Otto builds and sells model cars. He made a graph to compare the number of days to the number of model cars. Three of the points form a proportional relationship, but one does not. Which point does not fit in the proportional relationship? Coordinate plane with Number of Days on the x-axis and Number of Model Cars on the y axis. 4 points are plotted in the plane: 2, 1; 4, 2; 6, 2; and 8, 4. A (2, 1) B (4, 2) C (6, 2) D (8, 4)
\
Need HELP ASAP
Answer:
I have attached a really rough graph!!
Step-by-step explanation:
The point that does not fit in the proportional relationship is (6,2) when we plot the other three points and join the points they will give us a staright line but the point (6,2) isnt lying on that staright line.. Therefore, it does not fit in the proportional relationship!
Answer:
(6,2)
Step-by-step explanation:
ABCD is a rectangle, with M the midpoint or BC and N the midpoint of CD. If CM=4 and NC=5, what percent of the area of the rectangle is shaded
Answer:
87.5%
Step-by-step explanation:
Given:
⇒ ABCD is a rectangle, with M the midpoint of BC and N the midpoint of CD.⇒ CM = 4 and NC = 5.Area of triangle NCM
⇒ 1/2 × base × height
⇒ 1/2 × CN × CM
⇒ 1/2 × 5 × 4
⇒ 10cm²
Length of rectangle ⇒ 10
Breadth of the rectangle ⇒ 8
↓
Area of rectangle ⇒ Length × Breadth
Area of rectangle ⇒ 10 × 8 = 80cm²
Area of shaded region ⇒ Area of rectangle - Area of triangle
Area of shaded region ⇒ 80 - 10 = 80cm²
Percentage of the shaded region = Shaded/complete rectangle × 100
⇒ 70/80 × 100 = 87.5
⇒ The percent of the area of the rectangle shaded is therefore 87.5%.
46.Find the quotient and remainder
Answer:
30624; 1514,6; a1,6.
Your last five customer interactions lasted 2, 3, 6, 8, and 4 minutes."
Employee: "That means I've averaged __________ minutes across those 5 interactions."
Answer:
4.6 minutes
Step-by-step explanation:
Average = the sum of the numbers/ the number of numbers
Plug in the numbers: 2+3+6+8+4/5 = 23/5 = 4.6 minutes
In 2016, Alberta had about 4.2 million people.
Assuming they follow the same population
growth rate, it is predicted they will have 6.65
million people in 20 years. At what rate is the
province's population growing?
The province's population is growing at the rate of 58.34 %
Rate of change is used to mathematically describe the percentage change in value over a defined period of time, and it represents the momentum of a variable. The calculation for ROC is simple in that it takes the current value of a stock or index and divides it by the value from an earlier period.
Given:
Initial Population = 4.2 million
Population after 20 years = 6.65 million
Change in population = 6.65 - 4.2 = 2.45 million
Rate at which the province's population growing is
= [tex]\frac{Change in population}{Inital Population}[/tex] x100 %
= [tex]\frac{2.45}{4.2}\\[/tex] x 100%
= 58.34 %
Thus the province's population is growing at the rate of 58.34 %
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A university is interested in whether there's a difference between students who live on
campus and students who live off campus with respect to absenteeism. Over one
semester, researchers take random samples of on-campus and off-campus students and
record the following number of missed classes over a semester:
On-campus: (3, 4, 0, 6, 2, 1, 3, 3, 5, 2, 4, 4, 6, 5, 2)
Off-campus: (6, 5, 2, 6, 2, 0, 7, 8, 1, 7, 2, 6, 5, 3, 2)
A. Would we use a t confidence interval or a z confidence interval to determine
whether there's a significant difference between the two groups? What are
the conditions for using this kind of confidence interval? Do these data meet
the necessary conditions? Use sketches of modified box-and-whisker plots to
support your decision. (2 points)
B. What are the degrees of freedom (k) for this test using the conservative
method? (Hint: Don't pool and don't use your calculator.) (1 point)
C. What are the sample statistics for this test? Consider on-campus students to
be sample one and off-campus students to be sample two. (2 points)
D. Compute a 95% confidence interval for the difference between the number of
classes missed by each group of students. (2 points)
E. Compute a 90% confidence interval for the difference between the number of
classes missed by each group of students. (2 points)
F. Based on the two confidence intervals you computed in parts d and e, draw a conclusion about the differences between the means of the two groups.
It is to be noted that the determination of whether or not there is a significant difference between the two groups will be done using a t test.
What is a t test?
A t-test is a statistical test that juxtaposes two samples' means. It is used in hypothesis testing, using a null hypothesis that the variance in group means is zero and an alternative hypothesis that the difference is not zero.
What are the conditions for using this kind of confidence interval?The conditions to use the t test are:
The sample must be independentThe mean of the population and variance must be unknown.The Box plot is attached.What are the degrees of freedom (k) for this test using the conservative method?The degrees of freedom (k) to be utilized for this text will be derived using the conservative method given below:
df = [(s₁²/n₁) + (s₂²/n²)/[((s₁²/n₁)²/((n₁-1)) + (s₂²/n₂)²/((n₂-1))]
= [(3.0952/15) + (6.4095/15)]² / [((3.0952/15)²/14) + ((6.4095/15)²/14)]
= 24.965
Hence,
df ≈ 24 (if approximated to the floor)
What are the sample statistics for this test?Recall the the standard deviation of the population are unequal and unknown. This thus requires that we utilize the two-sample unpooled t-test.
Here, H₀ is given as;
[tex]t = \frac{\bar{x_{1} -\bar{x_{2}}}}{\sqrt{\frac{s_{1}^{2} }{n_{1} } + \frac{S_{2}^{2} }{n_{2}} } } \sim t_{df}[/tex]
t = [(3.33333 - 4.13333)]/√[(3.0952/15) + (6.4095/15)]
= - 0.8/√0.6337
t = - 1.005
What is the 95% confidence interval for the difference between the number of classes missed by each group of students?
The 95% confidence interval is computed using the following formula:
[tex](\bar x_{2} - \bar x_{1}) \pm t_\alpha_/_2_,_df \left({\sqrt{\frac{S_{1}^{2} }{n_{1} } + \frac{S_{2}^{2} }{n_{2}} } } \right)[/tex]
= - 0.8 ± t₀.₀₂₅,₂₄ (√0.6337)
= - 0.8 ± 2.064 (√0.6337)
= -2.4429, 0.8429
What is the a 90% confidence interval for the difference between the number of classes missed by each group of students?To derive the 90% interval, we state:
[tex](\bar x_{2} - \bar x_{1}) \pm t_\alpha_/_2_,_df \left({\sqrt{\frac{S_{1}^{2} }{n_{1} } + \frac{S_{2}^{2} }{n_{2}} } } \right)[/tex]
= - 0.8 ± t₀.₀₅₀,₂₄ (√0.6337)
= - 0.8 ± 0.685 (√0.6337)
= -2.162, 0.562
Based on the two confidence intervals computed in parts d and e, what is the conclusion about the differences between the means of the two groups?
From the intervals computed, we must fail to reject H₀
H₀ : μ₁ = μ₂
It is clear from the above intervals computed from that the differences between the mean of both groups is significant. This is because, zero is included on the two intervals.
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The RLX Company just paid a dividend of $2.85 per share on its stock. The dividends are expected to grow at a constant rate of 4.5 percent per year, indefinitely. Assume investors require a return of 10 percent on this stock. What is the current price?
The current stock price is $54.15.
Given that RLX Company just paid a dividend of $2.85 per share on its stock and dividends are expected to grow at a constant rate of 4.5 percent per year, indefinitely.
Stock valuation alludes to the valuation of the natural worth per portion of an organization's stock which can help the organization in deciding its reasonable worth in case of twisting up or consolidation. One of the models used to esteem the stock cost is the profit development model. It expects the cost of the stock to be the current worth representing things to come profits of the stock accepted to develop at a consistent rate.
Dividend (D0) = $2.85
Growth rate (g) = 4.5%
Required return (r) = 10%
Firstly, we have to calculate the value of the current stock price.
The current stock price can be calculated by using the dividend growing model.
[tex]\begin{aligned}\text{Current stock price}&=\frac{D_{0}\times(1+g)}{r-g}\\ &=\frac{2.85\times (1+0.045)}{0.10-0.045}\\ &=\frac{2.85\times 1.045}{0.055}\\ &=\frac{2.97825}{0.055}\\ &=54.15\end[/tex]
Hence, the current stock price when dividend of $2.85 are expected to grow at a constant rate of 4.5 percent per year, indefinitely is $54.15.
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Solution for the attached question below
The solution to the question is 265.
What is the logarithm of a number?Logarithm of a number A is the exponent or power or index n, a given number called the base B would be raised to give the number A.
So n is the logarithm of A to base B.
Analysis:
log 2( log2(x-9)) = 3
log2(x-9) = [tex]2^{3}[/tex]
log2(x-9) = 8
x-9 = [tex]2^{8}[/tex]
x-9 = 256
x = 256 + 9
x = 265
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HELPP WILL GIVE BRAINLIEST
which graph represents the function f(x) = sqrt(x) + 3
Answer:
the real answer is 2 I hope that
A pitcher originally contains a juice drink with 20 percent cranberry juice. After 4 ounces of cranberry juice is added, the new drink is one-fourth cranberry juice. How many total ounces of juice drink are in the pitcher after the addition of the cranberry juice?
Given the coordinates below, what is the midpoint of AB?
A(-6, -10)
B(2,5)
Given :
[tex] \: [/tex]
A(-6, -10)B( 2, 5)
[tex] \: [/tex]
[tex] \gray{ \frak{The \: given \: two \: \: points \: are(x_{1 },y_{1})=(−6 , -10)and(x_{ 2 },y_{2} )=( 2,5 )\:}}[/tex]
[tex] \: [/tex]
Let's solve by using midpoint formula :
[tex] \: [/tex]
[tex] \bf \boxed{\color{red}\frak{Midpoint \: \: Formula : {( \: x ,\:y \: ) = }( \frak{ \frac{x_{1 } + y_{1}}{2} , \frac{x_{2 } + y_{2}}{2} )}}}[/tex]
[tex] \: [/tex]
[tex] \large \gray{ \frak{( \: x ,\:y \: ) = }( \frak{ \frac{ -6 + 2}{2} , \frac{ - 10 + 5}{2} )}}[/tex]
[tex] \: [/tex]
[tex] \: \large \gray{ \frak{( \: x ,\:y \: ) = }( \frak{ \frac{ -4}{2} , \frac{ - 5}{2} )}}[/tex]
[tex] \: [/tex]
[tex]\large \gray{ \frak{( \: x ,\:y \: ) = }( \frak{ \cancel\frac{ -4}{2} , \cancel\frac{ - 5}{2} )}}[/tex]
[tex] \: \: [/tex]
[tex] \underline{ \boxed{ \large \red{ \frak{option \: d }( \frak{ - 2, - 2.5)}}}}✓[/tex]
Hope Helps! :)
Last PreCalc Question, Need help with writing piecewise functions with graphs. Giving brainliest!
The piece-wise linear functions can be written as follows:
[tex]f(x) = x, x \leq -2[/tex].[tex]f(x) = -x - 7, -2 < x \leq 1[/tex].[tex]f(x) = 2x - 9, x > 1[/tex].What is a linear function?A linear function is modeled by:
y = mx + b
In which:
m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.For x equal or less than -2, the line passes through (-3,-3) and (-2,-2), hence the rule is:
[tex]f(x) = x, x \leq -2[/tex].
For x greater than -2 up to 1, the y-intercept is of -7, and the line also passes through (1,-8), hence the rule is:
[tex]f(x) = -x - 7, -2 < x \leq 1[/tex].
For x greater than 1, the function goes through (2,-5) and (3,-3), hence the slope is:
m = (-3 - (-5))(3 - 2) = 2.
The rule is:
y = 2x + b.
When x = 2, y = -5, hence:
-5 = 2(2) + b
b = -9.
Hence:
[tex]f(x) = 2x - 9, x > 1[/tex].
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19) Write the scientific notation of 1
Answer:
1.0 x 10^0
Step-by-step explanation:
The above works because 10^0 = 1, and 1 x 1 = 1.
Brainliest, please :)
Write an equation of the line that passes through the point (4, –5) with slope 2.
answers:
A. y−4=2(x+5)
B. y+5=−2(x−4)
C. y−4=−2(x+5)
D. y+5=2(x−4)
Answer:
D. y+5=2(x−4)
Step-by-step explanation:
The point-slope form of the equation of a line is useful for writing an equation for a line through a given point with a given slope.
Point-slope formThe point-slope form of the equation of a line is ...
y -k = m(x -h) . . . . . . line through point (h, k) with slope m
ApplicationWe want a line through point (h, k) = (4, -5) with slope m = 2. Putting these numbers into the form gives ...
y -(-5) = 2(x -4)
y +5 = 2(x -4) . . . . . . simplifying the signs
The following table shows Jace's earnings based on the number of hours that he works.
Number of hours 111 222 333
Jace's Earnings \$20$20dollar sign, 20 \$30$30dollar sign, 30 \$40$40dollar sign, 40
Are Jace's earnings proportional to the number of hours that he works?
Answer:
no
Step-by-step explanation:
because no
The board of education has decreed that a maximum student teacher ratio in a classroom be 18:1
If the current school has 235 total students then what is the minimum number if teachers that must be working in your school ?
Answer:
235÷18=
how many classes of 18 students for each teacher
Step-by-step explanation:
A rectangle is 6 meters long and 4 meters wide. What is the area
of the rectangle?
Answer:
the rectangles area is 24 meters
Step-by-step explanation:
area = length x width
length is 6 using the words long and width is 4
Answer:
area = 24 cm²
Step-by-step explanation:
The area of a rectangle can be found using the formula:
[tex]\boxed {area = length \times width}[/tex].
Substituting the values into the equation:
[tex]area = 6 \space\ cm\times 4 \space\ cm[/tex]
⇒ [tex]\bf 24 \space\ cm^2[/tex]
An agriculture company is testing a new product that is designed to make plants grow taller. This can be thought of as a hypothesis test with the following hypotheses.
H0: The product does not change the height of the plant.
Ha: The product makes the plant grow taller.
Is the following an example of a type I or type II error?
The sample suggests that the product does not change the height of the plant, but it actually does make the plant grow taller.
It is an example of Type I error.
About Type I error
The rejection of a null hypothesis (H0) when it is actually true is a Type I error. It is represented by the following condition,
Failure to reject a null hypothesis when it is true that it is false which is a Type II error.
How is this an example of Type I error?
The given case's hypothesis is described as follows:
H₀: The product has no effect on the plant's height.
Hₐ: The substance causes the plant to enlarge.
The sample claims that the product causes the plant to grow taller, however in reality, it has no effect on the plant's height.
Therefore, the sample recommends rejecting the null hypothesis even though it is true. Consequently, a result, this error is a Type I error.
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What are the length and width of a rectangle if the length is
3 inches longer than twice the width and the area of the
rectangle is 5 in2?
The length and width of the rectangle are 5 inches and 1 inches respectively.
How to find the length and width of a rectangle?The length and width of the rectangle can be found as follows;
l = 3 + 2w
area of a rectangle = lw
where
l = lengthw = widthTherefore,
5 = lw
5 = (3 + 2w)w
5 = 3w + 2w²
2w² + 3w - 5 = 0
Hence,
2w² + 3w - 5 = 0
Therefore,
w = 1 and w = - 5 / 2
width = 1 inches
length = 3 + 2(1) = 5 inches
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Name the figure below in two different ways.
Y
Symbol:
and
M
A
The line segment in the figure can be named as: IYM and MYI.
How to Name a Line Segment?If we have three points on a line segment, the point on the middle will be the alphabet in the center when naming the line, while the alphabets of both endpoints can be written either at the beginning or ending.
Given the figure above, Y will be at the center. The endpoints are I and M. Therefore, the line segment can be named as: IYM and MYI.
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A manufacturer knows that their items have a normally distributed lifespan, with a mean of 7.9 years, and standard deviation of 0.9 years.
If you randomly purchase one item, what is the probability it will last longer than 9 years?
If you randomly purchase one item, the probability it will last longer than 9 years is; 11.12%
How to find the probability from z-score?
The formula for Z-score is;
z = (x' - µ)/σ
where;
x' = sample mean
µ = population mean
σ = standard deviation
Thus;
z = (9 - 7.9)/0.9
z = 1.22
From online p-value from z-score calculator, we have;
probability = 0.1112 = 11.12%
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Find the sum of the geometric series given a1=−1, r=2, and n=7
A. -127
B. -116
C. 1
D. -118
Answer:
A
Step-by-step explanation:
the sum to n terms of a geometric series is
[tex]S_{n}[/tex] = [tex]\frac{a_{1}(r^{n}-1) }{r-1}[/tex] , then for n = 7
S₇ = [tex]\frac{-1(2^{7}-1) }{2-1}[/tex] = [tex]\frac{-1(128-1)}{1}[/tex] = - 1 (127) = - 127
Given the drawing, what would the value of x need to be in order
for it to be true that m ||n?
4x + 18
m
7x-21
Be sure to show all calculations and algebraic steps in your re-
sponse.
Hint: What must be true about alternate exterior angles in order
for lines to be parallel?
[tex]4x + 18 = 7x - 21 \\ 18 + 21 = 7x - 4x \\ 39 = 3x \\ x = \frac{39}{3} = 13 [/tex]
A new plasma TV was marked down 20%. The new sale price of the TV was $380. What is the TV’s regular selling price?
x=regular selling price
X×80/100=380
= X×8/10=380
= 8X=380×10=3800
X=3800/8
X=475
the regular selling price is 475
Before the 20% discount, the TV's regular selling price was $475 as per the concept of percentage.
Let's denote the regular selling price of the plasma TV as "x". When the TV was marked down by 20%, the sale price became $380.
To find the regular selling price, we can set up an equation using the information given:
Sale Price = Regular Selling Price - (Discount Percentage × Regular Selling Price)
$380 = x - (0.20x)
Now, let's solve for "x" (the regular selling price):
$380 = x - 0.20x
$380 = 0.80x
To isolate "x," we divide both sides of the equation by 0.80:
x = $380 / 0.80
x = $475
The regular selling price of the plasma TV is $475.
Therefore, before the 20% discount, the TV's regular selling price was $475. After the discount, the sale price was reduced to $380, which is 20% less than the regular price.
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f(x)=2x. If g(x) is a vertical stretch, compression, and or reflection of f(x) followed by a, what is the equation of g(x)?
The function g(x) is g(x)= (3x)^2
How to solve for g(x)?
The complete question is in the image
From the graph in the image, we have:
f(x) = x^2
The function f(x) is stretched by a factor of 3 to form g(x).
This means that:
g(x) = f(3x)
So, we have:
g(x)= (3x)^2
Hence, the function g(x) is g(x)= (3x)^2
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solve the system of equations. y=3x+2 y=x^2-4+2
The solutions to the system of equations are (4, 15) and (-1,-1)
How to solve the system of equations?The system of equations is given as:
y=3x+2
y=x^2-4+2
Substitute y=3x+2 in y=x^2-4+2
3x + 2=x^2-4+2
Simplify
x^2 - 3x - 4 = 0
Expand
x^2 + x - 4x - 4x = 0
Factorize
x(x + 1) - 4(x + 1) = 0
This gives
(x - 4)(x + 1) = 0
Solve for x
x = 4 and x = -1
Substitute these values in y=3x+2
y = 3(4)+2 = 15
y = 3(-1)+2 = -1
Hence, the solutions to the system of equations are (4, 15) and (-1,-1)
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