You are in the year where the earth has no more land available for houses you decide to build an apartment up and need things to survive in each earths 5 layers (troposphere,stratosphere, mesosphere, thermosphere, exosphere) Question: what things would you need to survive the thermosphere(really hot it is 2000 degrees fahrenheit)

PLS HELP PLS IMMA GET A BAD GRADE

Two clay pieces—one white and the other gray—are hurled through the air. The white clay has a momentum of 25 kg/m/s.

The momentum will be conserved in each direction separately for a collision if the moving objects are travelling in two dimensions (for example, x and y) (as long as there is no external impulse in that direction). In other words, both before and after the impact, the total momentum will be the same in the x direction.

The momentum of the cue ball is defined as mass times velocity. Because it isn't moving yet, the 8 ball has no momentum. Due to the conservation of momentum, if you strike it straight on and the cue ball stops at the point of collision, all of its momentum must transfer to the 8 ball.

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The four students have the same power output. As work done by four of them is same.

When an object is moved over a distance by an external force, at least a portion of that force must be applied in the direction of the displacement. This is known as work in physics.

Work = Force × Distance is the formula for calculating work. The joule (J), sometimes known as the Newton meter (N m), is the SI unit for work. When an object is moved across a distance of 1 m with 1 N of force, one joule is equal to the amount of work that is accomplished.

Power in physics is referred to as the rate of work. In other terms, it calculates the rate at which energy is changed or transported.

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Complete Question -

Hyperopia is the refraction abnormality does he have.

What is Hyperopia ?

Farsightedness (farsightedness) is a common visual impairment in which distant objects can be seen clearly, but near objects may be blurred.

See your eye doctor if your farsightedness is preventing you from doing your job, or if the quality of your vision is affecting your enjoyment of activities. He or she can determine your degree of farsightedness and advise you on how to correct your vision .The degree of farsightedness affects your ability to concentrate. People having severe farsightedness can only see distant objects and things clearly, while people with mild farsightedness can see near objects clearly . This condition can be easily corrected with glasses or contact lenses. Another treatment option is surgery.

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You would need to survive the thermosphere: The temperature ( 2000° C or more), the cosmic radiation and charged particles.

The layer of the Earth's atmosphere known as the thermosphere is situated above the mesosphere and under the exosphere. The thermosphere is the bigger portion of the ionosphere because ultraviolet energy inside this layer of the atmosphere promotes photoionization/photodissociation of molecules, creating ions.

The remaining atmospheric gases stratify at these high elevations according to molecular mass. As a result of the sun's intensely powerful energy being absorbed, atmospheric temperatures rise with altitude. Temperatures, which can reach 2,000 °C or higher, are largely reliant on solar activity.

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Part A Mark the points in which the magnetic field is zero.The points in which the magnetic field is zero are O 2 and O 4.

A magnetic field is a force field that is created by a magnet or a moving electric charge. It is characterized by the direction of the field lines, which show the direction of the magnetic force at a given point, and the magnitude of the field, which is determined by the strength of the magnet or the amount of electric charge. Magnetic fields are used in a variety of applications, including in electric motors, generators, and MRI machines. They can also be found in natural phenomena such as the Earth's magnetic field.

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The acceleration of the block is 7.8 m/s².

The rate at which an object's velocity with respect to time changes is referred to as acceleration. It is a vector quantity to accelerate (in that they have magnitude and direction).

To find the acceleration of the block, we can use the equation:

force = mass X acceleration + friction

Rearranging the equation, we can find the acceleration:

acceleration = (force - friction) / mass

The force of friction can be found using the equation:

friction = friction coefficient X normal force

The normal force is equal to the weight of the object, which can be found using the equation:

weight = mass X gravity

So, friction = friction coefficient X mass X gravity

We know that gravity is 9.8 m/s²

friction = .15 * 14 kg * 9.8 m/s²

Now we can substitute this value for friction and the known values for force and mass into the first equation and solve for acceleration:

acceleration = (112 N - 1.47 N) / 14 kg

acceleration = 7.8 m/s²

So, the acceleration of the block is 7.8 m/s².

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a) The standard free energy (ΔG°) for the reaction CO2(s) CO2(g) at -90.0 oC is -28,853 J/mol, and at -100.0 oC is -32,142 J/mol

b) The temperature of a dry ice bath at which the vapor pressure of CO2 is 1 atm is estimated to be around -78 °C.

In part a) of the question, we were asked to determine the standard free energy (ΔG°) for the reaction CO2(s) CO2(g) at -90.0 oC and -100.0 oC.

To do this, we used the Clausius-Clapeyron equation, which relates the change in vapor pressure with temperature to the enthalpy and entropy of sublimation (ΔH° and ΔS°). By rearranging the equation, we were able to calculate the values of ΔH° at -90.0 oC and -100.0 oC to be -28,853 J/mol and -32,142 J/mol respectively.

We then used the same equation to calculate the ΔS° values, which are needed to calculate ΔG° = ΔH° - TΔS°

Now, from Clausius-Clapeyron equation, dP/dT = ΔH°/TΔS°

We can rearrange this equation to solve for ΔH° and ΔS°:

ΔH° = T(dP/dT)ΔS°

At -90.0 oC and 280 torr, ΔH° = -90.0 oC * (105 torr - 280 torr) / (105 torr) = -28,853 J/mol

At -100.0 oC and 105 torr, ΔH° = -100.0 oC * (105 torr - 280 torr) / (105 torr) = -32,142 J/mol

The ΔS° can be calculated using the same equation by substituting the ΔH° values.

In part b) of the question, we were asked to estimate the temperature of a dry ice bath at which the vapor pressure of CO2 is 1 atm. To do this, we used the Clausius-Clapeyron equation again, but this time we used the known value of 1 atm as the vapor pressure and solved for the temperature. P = P₀ * e^(-ΔHₒ/RT)  where,

Solving for T, we get T = ΔHₒ / R * ln(P₀/P)

The temperature to the nearest degree Celsius is about -78 °C.

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So, the initial temperature of the gas in kelvins is 375.6 K.

Hi! Here I will help you to solve the problem about the relationship between volume and temperature of the gas in a closed system. Look again at the sentence in the problem. It states that gas has a constant pressure in every condition. In other words, this is an isobaric process that also indirectly leads to Charles' Law. Charles' Law states the proportionality between the volume of a gas in a closed system and its absolute temperature. The general equation of Charles' Law in general, is expressed in the equation:

[tex] \boxed{\sf{\bold{\frac{V}{T} = C}}} [/tex]

With the following condition:

In this case, we can calculate the relationship between changes in temperature and changes in gas volume in a closed system with the following equation:

[tex] \boxed{\sf{\bold{\frac{V_i}{T_i} = \frac{V_f}{T_f}}}} [/tex]

With the following condition:

What was asked?

Step by step:

[tex] \sf{\frac{V_i}{T_i} = \frac{V_f}{T_f}} [/tex]

[tex] \sf{\frac{2.40}{T_i} = \frac{2.00}{313}} [/tex]

[tex] \sf{2.00(T_i) = 2.40(313)} [/tex]

[tex] \sf{T_i = \frac{2.40(313)}{2.00}} [/tex]

[tex] \sf{T_i = 1.20(313)} [/tex]

[tex] \sf{\bold{T_i = 375.6 \: K}} [/tex]

So, the initial temperature of the gas in kelvins is 375.6 K.

Answer:

No

Explanation: An opinion is a judgment, viewpoint, or statement that is not conclusive, rather than facts, which are true statements.

Weight and mass are measurements of the amount of substance and the gravitational pull, respectively, on an item. The quantity of matter in an item is its mass. Kilograms are used to measure mass (kg).

Weight is the force of gravity acting on an object, whereas mass is the quantity of "matter" (though "matter" may be difficult to define) in an object.  To put it another way, a 1.0 kilogram object weighs about 9.81 newtons on the surface of the Earth, which is equal to its mass times the gravitational field's strength. The object weighs the same amount whether it is on Mars, where gravity is weaker, Saturn, where gravity is stronger, or space, where gravity is light and the object is very far from any important sources of gravity.

The attractive force between two objects is given by the equation F = G * (m1 * m2) / r^2, where F is the force, G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between the objects.

Given that F = 0.0053 N, m1 = 730 kg, and r = 0.088 m, we can solve for m2:

0.0053 N = (6.67 x 10^-11 N*(m^2)/(kg^2)) * (730 kg) * m2 / (0.088 m)^2

Therefore, m2 = 0.0053 N * (0.088 m)^2 / (6.67 x 10^-11 N*(m^2)/(kg^2) * 730 kg)

m2 = 0.0053 N * (0.088 m)^2 / (6.67 x 10^-11 N*(m^2)/(kg^2) * 730 kg)

m2 = 0.0053 / (6.67 * 10^-11 * 730) = 0.0053 / (4.6*10^-9) = 1144.78 kg

So the mass of the second object is approximately 1144.78 kg.

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A + B are displayed in vector C in the second row. The vectors A and B are displayed in the first row when they are at the origin.

Two vectors, A and B, are provided for our consideration.

We must choose the vector that represents vectors A and B from the possibilities shown.

Therefore, we first reposition vector A so that the tail of it begins with the head of vector B.

Its magnitude and direction ought to stay the same even if we alter the location.

The resultant vector now begins at the head of vector A and ends at the tail of vector B after utilizing triangular vector addition.

We simply follow all of the vectors till we find it.

The sum of these two vectors is represented by the vector C.

Hence C = A+B

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D. produced a photograph that showed the creation of two particles when a particle of light was destroyed.

In 1933, Irène and Frédéric Joliot-Curie produced a photograph that showed the creation of two particles when a particle of light was destroyed, which was Einstein's prediction in the concept of pair production, which was a process in which two particles are created when a photon is absorbed. This photograph was the first experimental evidence of this process, which was a significant discovery in the field of nuclear physics.

During a full breath, the person's lung expends a total of 8.3 joules of energy.

The SI unit of energy, the joule (symbol J), measures a substance's ability to produce heat or do work. The work (or energy wasted) by a force of one newton (N) operating over an one-meter long distance is equivalent to one joule (m).

For every Coulomb of charge that a 12-volt battery transfers from a low energy position to a high energy location, it produces 12 Joules of energy. Therefore, a battery's voltage rating only quantifies the energy change of each coulomb of charge that is transferred between terminals.

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How much heat is transferred in order to raise the silver to its melting point.

The amount of heat needed to raise a substance's temperature by one degree Celsius in one gram, also known as specific heat.

Typically, calories or joules per gram per degree Celsius are used as the units of specific heat. For instance, water has a specific heat of 1 calorie (or 4.186 joules) per gram per degree Celsius.

The notion of specific heat was developed by the Scottish scientist Joseph Black in the 18th century as a result of his discovery that equal masses of different substances required varying quantities of heat to raise them through the same temperature range.

Therefore, How much heat is transferred in order to raise the silver to its melting point.

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The voltages V2, V3, V4 and V1 are ranked in decreasing order of voltage value as follows: V2 > V3 > V1 >V4

The difference in potential or pressure that pushes or ignites the passage of electrical current in a conducting loop is known as a voltage.

The following formula can be used to determine the current flowing through the circuit:

I = V/ R

The conductivity formula is presented as follows;

σ = l / RXA

Where;

σ = The material's conductivity

| = The length

R stands for electrical resistance.

A is the conductor's cross-sectional area.

Therefore;

R = V/I

R = l / A σ

V/I = l × L / A × σ

Based on the cylinders' dimensions, which were discovered using a similar query, we discover;

V1 = 3V4

V2 = 8 V4

V3 = 4 V4

The rank is -  V2 > V3 > V1 >V4

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Explanation:

normal force = mass times gravity

Fn = MG

Fn=?

M=800kg

G=4m/s

Fn = 800*4

Fn = 3200 N

Answer: 77.5 m/s

Explanation: We can use the following equation to calculate the velocity of the roller coaster car:

velocity = sqrt( (normal force + weight) * radius / mass)

where weight is the gravitational force acting on the car (mass * g)

Substituting the given values:

velocity = sqrt( (-12,000 N + (600 kg * 9.8 m/s^2)) * 6 m / 600 kg) = sqrt( -12,000 N + 5,880 N) * 6 m/s = sqrt( -6,120 N) * 6 m/s = 77.5 m/s (round to the nearest tenth)

The negative sign on the normal force indicates that it is acting in the opposite direction of the gravitational force. This can happen when the roller coaster car is upside down, which is the case in this problem

a. The period of the oscillation is 0.833 seconds.

b. The total energy in the system is 0.2646 J

c. The potential energy when the spring is stretched 0.253 m is 0.0162 J

d. The kinetic energy  when the spring is stretched 0.253 m is 0.0078 J

The displacement of the mass on the spring is given by the equation x(t) = 0.7cos(1.2t+4.3), where x is in meters and t is in seconds.

The potential energy of a spring-mass system is given by 1/2 kx^2, where

Using this equation, we can find the spring constant k by equating the equation for the potential energy to that of the displacement equation:

1/2 kx^2 = 1/2 * 0.7^2 * cos^2(1.2t+4.3)

Solving for k, we get k = 0.7^2 * 1.2^2

a. The period of the oscillation is given by the reciprocal of the frequency, which is 1/1.2=0.833 seconds.

b. The total energy in the system is given by the sum of the potential and kinetic energy.

As we know the spring constant we can calculate the potential energy when mass is at the extreme position,

Potential energy = 1/20.7^21.2^2*0.7^2 = 0.2205 J.

As we know, the mass of the system we can calculate the kinetic energy when mass is at the extreme position,

Kinetic energy = 1/20.31.2^2*0.7^2 = 0.0441 J.

Total energy = kinetic + potential = 0.2205 + 0.0441 = 0.2646 J

c. The potential energy when the spring is stretched 0.253 m can be calculated using the formula 1/2 kx^2, where x is the displacement from the equilibrium position.

Potential energy = 1/20.7^21.2^2*0.253^2 = 0.0162 J

d. The kinetic energy when the spring is stretched 0.253 m can be calculated by using the formula 1/2mv^2, where

v = dx/dt = -1.20.7sin(1.2t+4.3)

Kinetic energy = 1/20.3(-1.20.7sin(1.2t+4.3))^2 = 0.0078 J

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You would need to survive the thermosphere: The temperature ( 2000° C or more), the cosmic radiation and even solar activities, low air pressure and low air molecule.

The thermosphere is the layer of the atmosphere that is the thickest. It begins at a height of roughly 80 km and rises to about 550 km.

The thermosphere's highlights include the following:

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The magnitude of the load is 7037.98 N.

The original load supported by the bar is calculated by applying the formula for tensile strength of aluminum.

τ = 90 MPa

Original area of the aluminum = πd² / 4

A₀ = (  π x 0.01² / 4 )

A₀ = 7.854 x 10⁻⁵ m²

Original load of the aluminum bar;

P₀ = A₀ x τ

P₀ = 7.854 x 10⁻⁵  x 90 x 10⁶ N/m²

P₀ = 7068.58 N

The final area of the bar;

d' = 10 mm - 0.016 mm = 9.98 mm

A' = ( πd'² / 4 )

A' = ( π x 0.00998² / 4 )

A' =  7.82 x 10⁻⁵ m²

P₀/A₀ = P' / A'

P' = ( P₀ / A₀ )A'

P' = ( 7068.58 x  7.82 x 10⁻⁵ ) / ( 7.854 x 10⁻⁵ )

P' = 7037.98 N

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When the system performs mechanical work, internal energy decreases.

Explanation:

Likewise, U (internal energy) = Q (heat) + W (work completed). If the system performs work, then work is negative and internal energy declines.

If done quickly, the internal energy will drop, which will lead to a drop in temperature. Any internal energy loss, if gradual, is offset by heat entering the system to maintain the same temperature.

When mechanical work is done on a system, the internal energy of the system increases. The temperature of the system does not necessarily change.

What is temperature?
Temperature is a physical property of matter that quantitatively expresses the common notions of hot and cold. It is measured by a thermometer and usually expressed in units of degrees Celsius (°C) or Fahrenheit (°F). Temperature is an important parameter in many natural processes and is an essential component of weather forecasting. Temperature is related to the amount of energy in a system; the higher the temperature, the greater the average energy of the system's constituent particles. The average kinetic energy of the particles in a system is proportional to the absolute temperature. Temperature also has an effect on the physical properties of matter, such as its phase and viscosity. Heat transfer from one system to another is a major component of thermodynamics, and is dependent on the temperature difference between the two systems.

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The plunger's velocity at V0 is v(t) = vo - kx (t)

The direction of a body or object's motion is defined by its velocity. Speed is mainly a scalar quantity. Velocity is fundamentally a vector quantity. It is the pace at which distance changes. It is the displacement's rate of change.

a = -kv

dv/dt = -kv

dv/v = -k dt integrate, lnv(t) = -kt + lnC use v = vo when t = 0 C = vo v(t) = voe-kt

dx/dt equals voe-kt

dx = voe-kt dt integrate,

x(t) = (-vo/k)e-kt + C' usage C' = vo/k

since x(0) = 0 = -vo/k + C'.

x(t) = vo(1 - e-kt)/k

e-kt = 1 - kx(t)/v,

therefore v(t) = vo - kx (t).

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The Rank of the vectors is D A C B.

What is Vectors?

In contrast to a scalar number, a vector quantity also includes a direction component that aids in locating one point in relation to another. Here is more information on vectors. A vector in mathematics is a quantity that not only expresses magnitude but also motion or position of an object in relation to another point or object. In mathematics, a vector's magnitude is defined as the length of a segment of a directed line, and the vector's direction is indicated by the angle at which the vector is inclined.

A vector primarily consists of two elements, the horizontal component and the vertical component. The horizontal component's value is cos, and the vertical component's value is sin. Here is further information about vector components.

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Due to less information provided, The electric field at 1/5 of the way between two charges can be zero if the charges are of equal magnitude, or if the charges are of unequal magnitude but the distance between the two charges is an exact multiple of 5.

What is Electric Field?

A physical quantity associated with an electric charge or a charged particle is known as an electric field. It is a vector field that describes the force exerted by the first particle on another charged particle.  The electric potential of the charge, which is often measured in volts, defines the strength and direction of an electric field. A vector field is used to describe an electric field, with the electric field vector E at each point in space proportional to the force acting on a unit positive test charge at that point.

What does Magnatitude means?

Magnatitude is a term used to describe the strength or intensity of something, such as an emotion, a physical force, or an event. It is often used to describe the intensity of an earthquake, hurricane, or other natural disaster. In some cases, the term can also be used to describe the power of a person or group, such as the magnatitude of a leader's influence or the magnatitude of a corporation's reach.

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Coulomb's law, which states that the force between two charges is proportional to the product of the charges and inversely proportional to the square of the distance between them, can be used to determine the size of the electric field at point P.

E = k * Q / r2 is the formula for the electric field resulting from a single point charge. where Q is the point charge, r is the distance from the point charge, k is the Coulomb's constant (8.99 * 109 N*m2/C2), and E is the electric field.We must sum the electric fields resulting from each charge in order to determine the overall electric field at point P.

E equals k * (Q1/d1 + Q2/d2 ).where d1 = 1.50 m, d2 = 1.90 m, Q1 = 1.90 x 10-6 C, and Q2 = 1.10 x 10-6 C.E = 1.90 * 10-6 C / (1.50 m) + 1.10 * 10-6 C / (1.90 m) * (-1.90 * 10-6 C / (1.90 m)) * (-1.10 * 10-6 C / (1.90 m))

E = -1.07 * 10^6 N/C

Therefore, the electric field at point P is 1.07 * 106 N/C in size.

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A)If an iron atom has a magnetic dipole moment of about 1.8×10^−23A⋅m2.

B)Then the dipole is  3.4 x 10^-22 A.m^2 and should be 2.7 x 10^-22 N.m

Part A:

To determine the dipole moment of an iron bar, we need to know the number of atoms present in the bar and their individual magnetic dipole moments. The formula for dipole moment is given by:

dipole moment = number of atoms * individual atomic dipole moment

The volume of the bar is (9.9 cm) x (1.3 cm) x (1.0 cm) = 13.47 cm^3.

If we assume the density of iron is 7.87 g/cm^3, we can find the mass of the bar as:

mass = density x volume

= 7.87 g/cm^3 x 13.47 cm^3 = 106.07 g

Since the atomic mass of iron is about 55.847 g/mol, we can find the number of atoms present in the bar as:

number of atoms = mass / atomic mass

= 106.07 g / 55.847 g/mol = 1.91 x 10^22

Therefore, the dipole moment of the iron bar can be found as:

dipole moment = number of atoms x atomic dipole moment

= 1.91 x 10^22 x 1.8 x 10^-23 A.m^2 = 3.42 x 10^-22 A.m^2

The answer should be 3.4 x 10^-22 A.m^2

Part B:

The torque on a dipole in a magnetic field is given by the formula:

torque = dipole moment x magnetic field x sin(theta)

Where theta is the angle between the dipole moment and the magnetic field. Since the bar is placed at right angles to the field, theta is 90 degrees and the sine is 1.

Therefore, the torque can be found as:

torque = dipole moment x magnetic field

= 3.4 x 10^-22 A.m^2 x 0.8 T = 2.7 x 10^-22 N.m

The answer should be 2.7 x 10^-22 N.m

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The momentum of a 250 g ball travelling at 40 m/s is 10 kg m/s.

Velocity is a measure of the rate of change in a physical quantity over time. It is a vector quantity, meaning it is composed of both magnitude and direction. Velocity measures the speed of an object at a specific point in time, as well as the direction of its motion.

Momentum is a vector quantity, meaning it has both a magnitude and a direction. In this case, the magnitude of the momentum is 10 kg m/s and the direction is the same as the velocity, i.e. 40 m/s.

Momentum is a product of mass and velocity. It is calculated by multiplying mass (in kg) by velocity (in m/s) and then multiplying the answer by the direction of the velocity (1 for positive and -1 for negative). In this case, the momentum is calculated as follows:

Momentum = Mass x Velocity x Direction
= 250 g x 40 m/s x 1
= 10 kg m/s

In physics, the law of conservation of momentum states that the total momentum of a system remains constant. This means that if an object has a certain momentum, it will keep this momentum unless an external force acts on it to change it. The only way to change the momentum of the 250 g ball travelling at 40 m/s is to apply an external force to it, such as a collision or a frictional force.

In conclusion, the momentum of a 250 g ball travelling at 40 m/s is 10 kg m/s. This momentum can only be changed by applying an external force to the ball.

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Answer:

No its not, the correct option is A) It requires a medium

Explanation:

Sound can go anywhere even in space, so using a medium, is an option , but it doesn't only travel through them.

Have a wonderful day! :-)

Answer:

He is his choice to leave with

The de Broglie wavelength of the paramecium is 3.313 x 10^-19 m.

And the fraction of de Broglie wavelength of the paramecium represents about 2.2 x 10^-17 or 0.00000022% of its 150um leng

The de Broglie wavelength of a particle is given by the equation:

wavelength = h / (mass * velocity) where

So, wavelength = (6.626 x 10^-34 Js) / (2*10^16 kg * 10^-3 m/s) = 3.313 x 10^-19 m

To calculate the fraction of the paramecium's 150um length that this wavelength represents, you would divide the wavelength by the length and multiply by 100%

3.313 x 10^-19 / 150 x 10^-6 = 2.2 x 10^-17

So the de Broglie wavelength of the paramecium represents about 2.2 x 10^-17 or 0.00000022% of its 150um length.

Key points:

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