You deposit $120 in an investment account that earns 6.4% annual interest compounded quarterly write a function that represents the balance y (in dollars) of the investment account after t years y= ? What is the balance of the account after 6 years

[tex]x {}^{(1)} = - 3 \: \: \: \: \: \: x {}^{(2)} = - 1[/tex]

Substitute [tex]u=x^2+4[/tex] and [tex]du=2x\,dx[/tex]. Then the integral transforms to

[tex]\displaystyle \int \frac{x\,dx}{(x^2+4)^3} = \frac12 \int \frac{du}{u^3}[/tex]

Apply the power rule.

[tex]\displaystyle \int \frac{du}{u^3} = -\dfrac1{2u^2} + C[/tex]

Now put the result back in terms of [tex]x[/tex].

[tex]\displaystyle \int \frac{x\,dx}{(x^2+4)^3} = \frac12 \left(-\dfrac1{2u^2} + C\right) = -\dfrac1{4u^2} + C = \boxed{-\dfrac1{4(x^2+4)^2} + C}[/tex]

None of the equation of the line is parallel because there slope are not equal.

Parallel line have the same slope.

Therefore, using slope intercept equation,

y = mx + b

where

Hence,

y = −5x − 5 , slope = -5

x + 12y = −4; y = -1 / 3 - 1 / 12 x, slope = 1 / 12

y = −2x + 4: slope = -2

y + 8 = -15x + 135; y  = -15x + 127, slope  = -15

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The expression that would be simplified to be a multiplicative identity is 2^0

The complete question is added as an attachment

Multiplicative identities are represented as:

a * 1 = a

This means that the definition of multiplicative identities is the product of a number and 1

From the list of options, we have

2^0

When the exponent of a non-zero number is 0, the result is 1.

This means that

2^0 = 1

Hence, the expression that would be simplified to be a multiplicative identity is 2^0

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Answer:

5:3:2

Step-by-step explanation:

see image

Jarek gets half. Then from the other half, Jerzy gets 3 pieces of 5 and Justyn gets the leftover 2 pieces. But Jarek's piece is all 5 pieces of the first half.

Jarek 5 parts:

Jerzy 3 parts:

Justyn 2 parts

5:3:2

see image

Answer:

the slope is 5 and the y intercept is 5

Step-by-step explanation:

I think that you meant to write y = 6x + 5.

y = mx + b

The number in in the m spot is the slope and the number in the b spot is the y intercept.

If the sample mean is 51,sample size is 21 , sample standard deviation is 15 and confidence level is 95% then the lower bound is 45.35 and upper bound is 56.65.

Given sample mean of 51, sample size of 21, sample standard deviation be 15 and confidence level be 95%.

We are required to find the upper bound and lower bound.

We have to use t test as the sample size is less than 30.

Margin of error is the difference between calculated figures and real figures.

Margin of error= standard deviation* critical value of t

Critical value of t at 0.05 significance level with degree of freedom 20   [21-1] is 1.7247.

Margin of error=1.7247*15/4.5826

(4.5826 is the square root of 21)

=5.6454

Upper bound=51+5.6454

=56.6454

Lower bound=51-5.6454

=45.3546

After rounding off they will be 56.65 and 45.35.

Hence if the sample mean is 51,sample size is 21 , sample standard deviation is 15 and confidence level is 95% then the lower bound is 45.35 and upper bound is 56.65.

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Answer:

-8 x^2
1.25 x^2
1/2 x^2

Step-by-step explanation:

They are like terms because they have the same variable x^2, yx^2 is not the same because it has the variable y

Answer:

the 2nd, 3rd and 4th options (all with x²)

Step-by-step explanation:

"like terms" means the exactly same variable(s) with exactly the same exponents of these variables.

constants in the terms can be different and even have different signs.

5yx² is not "like", because of the additional y variable.

The quantity of each concentrations of 3% and 9% needed to get the desired concentration is 54 milliliters and 27 milliliters respectively

Let

x + y = 81

0.03x + 0.09y = 81 × 5%

0.03x + 0.09y = 4.05

x + y = 81

0.03x + 0.09y = 4.05

From (1)

x = 81 - y

0.03x + 0.09y = 4.05

0.03(81 - y) + 0.09y = 4.05

2.43 - 0.03y + 0.09y = 4.05

- 0.03y + 0.09y = 4.05 - 2.43

0.06y = 1.62

y = 1.62/0.06

y = 27

x = 81 - y

x = 81 - 27

x = 54

Simultaneous equation:

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The value of x according to the given task is; 12.

It follows from the task content that the value of x is to be determined.

Since, lines AB and BC are both tangent to the circle and they both share a point of intersection; it follows that;

5x = 3x +24

2x = 24

x = 24/2

x = 12.

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In the given diagram, the length of CD is 12.7 cm

From the question, we are to determine the length of CD

First, we will calculate the length of CB

From the Pythagorean theorem,

|CA|² = |CB|² + |BA|²

12² = |CB|² + 6²

144 = |CB|² + 36

|CB|² = 144 - 36

|CB|² = 108

|CB| = √108

|CB| = 6√3 cm

Now, to find CD

Using SOH CAH TOA

sin55° = |CB| / |CD|

sin55° = 6√3 / |CD|

|CD| = 6√3 / sin55°

|CD| = 12.7 cm

Hence, the length of CD is 12.7 cm

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Answer:

z=16

Step-by-step explanation:

10=z-6

10+6=z-6+6

16=z

Answer:

10=z-6

or, z= 10+6

or, z = 16

the vale of y is 16

2x3 i think maybe yes

The points on the circumference are (3, 5), (3, -9), (8, -2 + √24) and (8, -2 - √24))

The circle equation is given as:

(x-3)^2 +(y+2)^2= 49

Rewrite as:

(y+2)^2= 49 -(x-3)^2

Take the square root of both sides

y+2= ±√[49 -(x-3)^2]

Subtract 2 from both sides

y = -2 ± √[49 -(x-3)^2]

Next, we determine the points

Set x = 3

y = -2 ± √[49 -(3-3)^2]

Evaluate

y = -2 ± 7

Solve

y = 5 and y = -9

So, we have

(x, y) = (3, 5) and (3, -9)

Set x = 8

y = -2 ± √[49 -(8-3)^2]

Evaluate

y = -2 ± √24

Solve

y = -2 - √24 and y = -2 + √24

So, we have

(x, y) = (8, -2 + √24) and (8, -2 - √24)

Hence, the points on the circumference are (3, 5), (3, -9), (8, -2 + √24) and (8, -2 - √24)

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Answer:

The answer is circle.

Step-by-step explanation:

For all the rest of the shapes, we use certain base x height formulas.  Square uses base x height along with parallelograms and trapezoids. For a triangle, we use [tex]\frac{base x height}{2}[/tex]. Though, for a circle, we use the formula  [tex]\pi r^{2}[/tex] where r= radius.

The price elasticity of demand is 1.90.

Price elasticity of supply measures the responsiveness of quantity supplied to changes in price of the good. It is expected that quantity supplied would be positively related to the price of the good.

Price elasticity of supply = percentage change in quantity supplied / percentage change in price

55% / 29% = 1.90

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Answer:

150 student tickets and 375 adult tickets

Step-by-step explanation:

Let x = # of student tickets sold, and y = # of adult tickets sold.

Total of 525 tickets were sold, so the first equation is x + y = 525. The register gained $8325, so 10.50x + 18y = 8235 is the second equation.

x + y = 525

10.50x + 18y = 8325

18x + 18y = 9450

10.50x + 18y = 8325

7.5x = 1125

x = 150

150 + y = 525

y = 375

The story problem that aligns with the division problem is A. A whiteboard is 2/5 meter long and has an area of 1/2 square meter. How wide is the whiteboard?

From the information given, it can be seen that 1/2 is divided by 2/5.

In this case, the story that aligns with it is that a whiteboard is 2/5 meter long and has an area of 1/2 square meter. How wide is the whiteboard?

In this case, the length is multiplied by width to get the area.

Therefore, the correct option is A.

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Answer:

A. The reference angle measures 78 degrees

Answer: B

Step-by-step explanation: Trust me bro

Answer:

(I've marked the lines considered functions with a check mark)

Step-by-step explanation:

Answer:

A) 69

Step-by-step explanation:

• First , we put the numbers of the distribution in order:

60 , 66 , 72 , 78 , 80 , 82 , 88 , 90

• Notice that the set has 8 numbers which is an even number.

Then

→ the lower quartile is the mean of the set :

60 , 66 , 72 , 78

Which is the average of the two middle numbers 66 and 72.

Then

[tex]\text{the lower quartile}=\frac{66+72}{2} = 69[/tex]

Answer:

b)14/3 or 4 2/3  C) 256/15 or 14 1/15

Step-by-step explanation:

In the second fraction, the "of" means to multiply

Answer:

#b

[tex] \displaystyle{ \pmb{ \pink{3 \frac{1}{5} \times 3 \frac{1}{2} \div 2 \frac{2}{5} }}}[/tex]

[tex]\frak{SOLUTION:}[/tex]

[tex]\displaystyle \frak{Here,}[/tex]

[tex]\displaystyle{3 \frac{1}{5} \times 3 \frac{1}{2} \div 2 \frac{2}{5} }[/tex]

[tex] = \displaystyle{ \frac{16}{5} \times \frac{7}{2} \div \frac{12}{5} }[/tex]

[tex]=\displaystyle{ \frac{16}{5} \times \frac{7}{2} \times \frac{5}{12} \frak{(Performing division)} }[/tex]

[tex]\displaystyle{ = \frac{ \cancel{16} \: {}^{2} \times 7 \times \cancel5}{ \cancel5 \times \cancel 2 \times 12} }[/tex]

[tex]\displaystyle{ = \frac{8 \times 7}{12} }[/tex]

[tex] =\displaystyle{} \frac{56}{12} [/tex]

[tex]\displaystyle{ = \frac{ \cancel2 \times \cancel2 \times 2 \times 7}{ \cancel2 \times \cancel 2 \times 3} }[/tex]

[tex]\displaystyle{ = \frac{14}{3} \frak {\: or} \: 4 \frac{2}{3} } [/tex]

#c

[tex]\displaystyle{\pmb{ \pink{2 \frac{2}{3} \div \frac{1}{2} \: of \: 3 \frac{1}{5} }}}[/tex]

[tex]\displaystyle{ \frak{SOLUTION:}}[/tex]

[tex]\displaystyle \frak{Here,}[/tex]

[tex] \displaystyle{2 \frac{2}{3} \div \frac{1}{2} \: of \: 3 \frac{1}{5} }[/tex]

[tex]\displaystyle{ = \frac{8}{3} \div \left( \frac{1}{2} \times \frac{16}{5} \right)\frak{(Performing "of")}}[/tex]

[tex] = \displaystyle{ \frac{8}{3} \div \left( \frac{1 \times \cancel{16} \: {}^{8} }{ \cancel2 \times 5} \right) }[/tex]

[tex]\displaystyle{ = \frac{8}{3} \div \frac{8}{5} }[/tex]

[tex]\displaystyle{ = \frac{8}{3} \times \frac{5}{8} \frak{(Performing \: division)} }[/tex]

[tex]\displaystyle{ = \frac{ \cancel8}{3} \times \frac{5}{ \cancel8} }[/tex]

[tex] = \displaystyle{ \frac{5}{3} \frak{ \: or \: }1 \frac{2}{3} }[/tex]

Answered by :

[tex]\frak{\pink{seolleaphrodite}}[/tex]

The amount that will be in the account after 30 years is $162,272.32.

When an amount is compounded annually, it means that once a year, the amount deposited and the interest already accrued increases in value. Compound interest leads to a higher value of deposit when compared with simple interest, where only the amount deposited increases in value once a year.

The formula that can be used to determine the future value of the yearly deposit of $4,000 in 30 years is : annuity factor x yearly deposit

Annuity factor = {[(1+r)^n] - 1} / r

Where:

$4000 x [{(1.02^30) - 1} / 0.02] = $162,272.32

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Answer:

From least to most likely:

Event 4, Event 2, Event 3, Event 1

Step-by-step explanation:

Event 1 has a 100% chance because there are only red and orange marbles in the bag.

In event 2, there are 4 orange marbles in the bag, giving us a (4/20) chance. This is 20%

In event 3, there are 2 orange marbles of 8 total, giving us an (2/8) chance. This is 25%

Lastly, there are no purple marbles in either bag, giving us a 0% chance of this occurring.

Using the Fundamental Counting Theorem, it is found that:

The 2 people can arrange themselves in 40 ways.

It is a theorem that states that if there are n things, each with [tex]n_1, n_2, \cdots, n_n[/tex] ways to be done, each thing independent of the other, the number of ways they can be done is:

[tex]N = n_1 \times n_2 \times \cdots \times n_n[/tex]

With one people in the aisle and one in the normal seats, the parameters are:

n1 = 4, n2 = 7

With both in the aisle, the parameters is:

n1 = 4, n2 = 3

Hence the number of ways is:

N = 4 x 7 + 4 x 3 = 28 + 12 = 40.

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Answer:

Assume you are working with a standard deck of 52 cards. There are 13 cards (2, 3, 4, 5, 6, 7, 8, 9, 10, jack, queen, king, and ace) in each of four suits

and spades).

What is P(Jack Heart) if you draw one card? 13

Answer:  [tex]y=\frac{13}{2} x+3[/tex]

Step-by-step explanation:

Remember the point-slope equation which is [tex]y-y_{1} = m(x-x_{1} )[/tex]  where[tex](x_{1} , y_{1} )[/tex] is your point and [tex]m[/tex] is your slope.

Given that we substitute what you have:

[tex]y-(-10) =\frac{13}{2} (x - (-2))[/tex]

Minus and minus give us positive:

[tex]y+10 =\frac{13}{2} (x +2)[/tex]

Multiply slope into the parenthesis:

[tex]y+10= \frac{13}{2}x + \frac{13}{2}*2\\[/tex]

Calculate it:

[tex]y+10= \frac{13}{2}x +13[/tex]

Isolate the [tex]y[/tex] by subtracting 10 from both sides:

[tex]y=\frac{13}{2} x + 13 -10[/tex]

Your final equation is:

[tex]y=\frac{13}{2} x +3[/tex]

Hope this makes sense!

And here's the graph to prove that the line actually goes through the point [tex](-2,-10)[/tex]: