You have available three blocks of different material, at various temperatures. They are, respectively, a 2 kg block of iron at 600 K, a 3 kg block of copper at 800 K and a 10 kg block of granite at 300 K. The heat capacities for the three materials are 0.460 (iron), 0.385 (copper), and 0.790 (granite), in kj/(kg*K), all independent of temperature. For solids, the heat capacities at constant pressure and constant volume can be assumed to be equal, Cp=Cv. what is the minimum temperature that could be obtained in any one of the block? what is the maximum temperature that could be obtained? no heat or work interactions with the enviroment are allowed.

Answers

Answer 1

Answer:

max temp = 711.32 k

mini temp = 331.29 k

Explanation:

Given data:

2kg block of Iron : temperature = 600k , C = 0.460 kJ/kgk

3 kg block of copper : temp = 800k ,  C = 0.385 KJ /kgk

10 kg block of granite : temp = 300k , C = 0.790 KJ/kgk

Cp = Cv at constant pressure and constant volume

Determine the minimum temperature that is obtained in any one of the block

considering the heat transfer equation

Q = mC ( T2 - T1 )

attached below is a detailed solution of the problem

You Have Available Three Blocks Of Different Material, At Various Temperatures. They Are, Respectively,

Related Questions

QUESTION 4:
4.1
Name FOUR principles of kinetic friction ​

Answers

Answer:

The force of friction always acts in a direction, opposite to that in which the body is moving.

The magnitude of kinetic friction bears a constant ratio to the normal reaction between the two surfaces. ...

For moderate speeds, the force of friction remains constant.

Answer:

Explanation:Kinetic friction is a force that acts between moving surfaces. An object that is being moved over a surface will experience a force in the opposite direction as its movement. The magnitude of the force depends on the coefficient of kinetic friction between the two kinds of material.

The steam requirements of a manufacturing facility are being met by a boiler whose rated heat input is 5.5 x 3^106 Btu/h. The combustion efficiency of the boiler is measured to be 0.7 by a hand-held flue gas analyzer. After tuning up the boiler, the combustion efficiency rises to 0.8. The boiler operates 4200 hours a year intermittently. Taking the unit cost of energy to be $4.35/10^6 Btu, determine the annual energy and cost savings as a result of tuning up the boiler.

Answers

Answer:

Energy Saved = 6.93 x 10⁹ Btu

Cost Saved = $ 30145.5

Explanation:

The energy generated by each boiler can be given by the following formula:

[tex]Annual\ Energy = (Heat\ In)(Combustion\ Efficiency)(Operating\ Hours)[/tex]

Now, the energy saved by the increase of efficiency through tuning will be the difference between the energy produced before and after tuning:

[tex]Energy\ Saved = (Heat\ In)(Efficiency\ After\ Tune - Efficiency\ Before\ Tune)(Hours)[/tex][tex]Energy\ Saved = (5.5\ x\ 3\ x\ 10^{6}\ Btu/h)(0.8-0.7)(4200\ h)[/tex]

Energy Saved = 6.93 x 10⁹ Btu

Now, for the saved cost:

[tex]Cost\ Saved = (Energy\ Saved)(Unit\ Cost)\\Cost\ Saved = (6.93\ x\ 10^{9}\ Btu)(\$4.35/10^{6}Btu)\\[/tex]

Cost Saved = $ 30145.5

A contractor excavates 10,000 m3 soil at moist unit weight of 17.5 kN/m3 and moisture content of 10% from a borrow pit and transports it to a project site. The project has an area of 20,000 m2 to be filled with this compacted soil. If the required dry unit weight and moisture content of the compacted soil are 18.3 kN/m3 and 12.5% (assume there is no soil loss during transportation and compaction), what is the thickness of the compacted soil and how much water needs to be added?

Answers

Answer:

Part A

The thickness of the compacted soil is approximately 4.3467 × 10⁻¹ m

Part B

The weight of water to be added is approximately 19886.[tex]\overline{36}[/tex] kN, the volume of the water added is approximately 2,027.77 m³

Explanation:

The parameters of the soil are;

The volume of sol the excavator excavates, [tex]V_T[/tex] = 10,000 m³

The moist unit weight, W = 17.5 kN/m³

The moisture content = 10%

The area of the project, A = 20,000 m²

The required dry unit weight = 18.3 kN/m³

The required moisture content = 12.5%

Part A

Therefore, we have;

The moist unit weight = Unit weight = ([tex]W_s[/tex] + [tex]W_w[/tex])/[tex]V_T[/tex]

The moisture content, MC = 10% = ([tex]W_w[/tex]/[tex]W_s[/tex]) × 100

∴ [tex]W_w[/tex] = 0.1·[tex]W_s[/tex]

∴ The moist unit weight = 17.5 kN/m³ = ([tex]W_s[/tex] + 0.1·[tex]W_s[/tex])/(10,000 m³)

1.1·[tex]W_s[/tex] = 10,000 m³ × 17.5 kN/m³ = 175,000 kN

[tex]W_s[/tex] = 175,000 kN/1.1 = 159,090.[tex]\overline{09}[/tex] kN

For the required soil, we have;

The required dry unit weight = 18.3 kN/m³ = [tex]W_s[/tex]/[tex]V_T[/tex] = 159,090.[tex]\overline{09}[/tex] kN/[tex]V_T[/tex]

[tex]V_T[/tex] = 159,090.[tex]\overline{09}[/tex] kN/(18.3 kN/m³) ≈ 8,693.4923 m³

The total volume of the required soil ≈ 8,693.4923 m³

Volume [tex]V_T[/tex] = Area, A × Thickness, d

∴ d =  [tex]V_T[/tex]/A

d = 8,693.4923 m³/(20,000 m²) ≈ 4.3467 × 10⁻¹ m

The thickness of the compacted soil ≈ 4.3467 × 10⁻¹ m

Part A

The moisture content, MC = 12.5% = ([tex]W_w[/tex]/[tex]W_s[/tex]) × 100

[tex]W_w[/tex] = [tex]W_s[/tex] × MC/100 = 159,090.[tex]\overline{09}[/tex] kN × 12.5/100 = 19886.[tex]\overline{36}[/tex] kN

The weight of water to be added, [tex]W_w[/tex] = 19886.[tex]\overline{36}[/tex] kN

Where the density of water, ρ = 9.807 kN/m³

Therefore, we have;

The volume of water, V = [tex]W_w[/tex]/ρ

∴ V = 19886.[tex]\overline{36}[/tex] kN/(9.807 kN/m³) ≈ 2027.77 m³

The volume of water, V ≈ 2027.77 m³

Another name for a load-center distribution system is a A. primary radial system. B. complex radial system. C. split-radial system. D. dual-radial system.

Answers

Answer:

A

Explanation:

Primary radial system

pls help me it’s due today

Answers

Answer:

C. 14.55

Explanation:

12 x 10 = 120

120 divded by 10 is 12

so now we do the left side

7 x 3 = 21 divded by 10 is 2

so now we have 14

and the remaning area is 0.55

so 14.55

A frequenter of a pub had observed that the new barman poured in average 0.47 liters of beer into the glass with a standard deviation equal to 0.09 liters instead of a half a liter with the same standard deviation. The frequenter had used a random sample of 47 glasses of beer in his experiment. Consider the one-sided hypothesis test for volume of beer in a glass: H0: u=0.5 against H1: u<0.5. Determine the P-value of this test.
Round your answer to four decimal places (e.g. 98.7654).

Answers

Answer:

P-value = 0.0011

Explanation:

Formula for the test statistic is;

z = (x¯ - μ)/(σ/√n)

We have;

Sample mean;x¯ = 0.47

Population mean; μ = 0.5

Standard deviation; σ = 0.09

Sample size; n = 47

Thus;

z = (0.46 - 0.5)/(0.09/√47)

z = -3.05

From z-distribution table attached, the p-value corresponding to z = -3.05 is;

P = 0.00114

To four decimal places gives;

P-value = 0.0011

Build a 32-bit accumulator circuit. The circuit features a control signal inc and enable input en. If en is 1 and inc is 1, the circuit increments the stored value by an amount specified by an input A[31:0] on the next clock cycle. If en is 1 and inc is 0 the circuit decrements the stored value by the amount specified in the input A on the next clock cycle. If en is 0, the circuit simply stores its current value without modification. The circuit has the following interface:______.
Input clock governs the state transitions in the circuit upon each rising edge.
Input clear is used as a synchronous reset for the stored value.
Input inc controls whether the value stored is to be incremented or decremented.
Input en is a control signal that activates the values increment/decrement
Input A determines how much to increment or decrement by
Output value is a 32-bit signal that can be used to read the stored value at any time.
* Note: Use any combination of combinational or sequential logic. It may be helpful to look into D Flip Flops and Registers.

Answers

Sorry need.points I'm new

Other Questions
Which of these happens last?Nina hits a drum.Nina hears the sound of her drum.Sound waves travel through the air.The surface of the drum vibrates, creating sound waves. t help pls its ixl am in 84 pls help help I am bad at geometry please help What type of cat would be the best control to compare with Calix? A recipe for pizza sauce calls for 7 cans of tomatoes and 21 teaspoons of oregano. How many teaspoons of oregano would you need for a single can of tomatoes? I just need to know if its correct what the answer please tell me? In a chemical reaction1 pointThe atoms of the reactants unbond, rearrange and then rebond to form the productsSome atoms disappear while others multiply to form the productsThe atoms of the reactants always stay together to form the productsNew atoms are formed which combine to make the products The %20 tip on a $73 meal need answers asap write about a time when you moved to a new home or school. what was it like? how did it make you feel? if you have never moved imagine how you would feel if you did have to move You are working on a school project with several class mates and all of your school supplies gets mixed together. Write five sentences IN GERMAN telling which supplies belongs to which person A mineral has which of the following characteristics Al abrir su alcanca Beatriz encontr que entre monedas de 5, 10 y 25 centavos completaba $ 9.50. Encontr igualmente que el nmero de monedas de 10 centavos era el triple de las de 25 centavos y que las de 5 centavos era el doble de las de 10 centavos. Cuntas monedas de cada denominacin haba en la alcanca?} Help me please please help me 3. A kite is aloft at the end of a 1500 foot string. The string make an angle of 43 with theground. How far above the ground is the kite?Do not calculate! Please provide your answer in calculator ready form. For example: h -237cos(3129) The points D(9, 8)and E(3, 13) are on a coordinate plane. What is theapproximate distance between points D and E? Olivia, the food stand manager, spends $210 per week on vegetable sandwich ingredients. She wants to earn $1870 per week.Write an equation that can be used to determine x, the number of vegetable sandwiches Olivia needs to sell in order to earn $1870 per week. Required:1. & 2. Prepare journal entries to record the transactions for April and post them to the ledger accounts in Requirement 6b. The company records prepaid and unearned items in balance sheet accounts.3. Using account balances from Requirement 6b, prepare an unadjusted trial balance as of April 30.4. Journalize the adjusting entries for the month and prepare the adjusted trial balance.5a. Prepare the income statement for the month of April 30, 2017.5b. Prepare the statement of retained earnings for the month of April 30, 2017.5c. Prepare the balance sheet at April 30, 2017.6a. Prepare journal entries to close the temporary accounts and then post to Requirement 6b.6b. Post the journal entries to the ledger.7. Prepare a post-closing trial balance.April 1 Nozomi invested $47,000 cash and computer equipment worth $40,000 in the company in exchange for common stock 2 The company rented furnished office space by paying $2,200 cash for the first month's (April) rent 3 The company purchased $2,000 of office supplies for cash 10 The company paid $2,200 cash for the premium on a 12-month insurance policy. Coverage begins on April 11 14 The company paid $1,300 cash for two weeks' salaries earned by employees 24 The company collected $14,000 cash on commissions from airlines on tickets obtained for customers 28 The company paid $1,300 cash for two weeks salaries earned by employees 29 The company paid $300 cash for minor repairs to the company's computer 30 The company paid 1,100 cash for this month's telephone bill 30 The company paid $2,000 cash in dividends. The company's chart of accounts follows: 101 Cash 106 Accounts Receivable 124 office Supplies 128 Prepaid Insurance 167 Computer Equipment 168 Accumulated Depreciation-Computer Equip 209 Salaries Payable 307 Common Stock 318 Retained Earnings 319 Dividends 405 Commissions Earned 612 Depreciation Expense Computer Equip 622 Salaries Expense 637 Insurance Expense 640 Rent Expense 650 Office Supplies Expense 684 Repairs Expense 688 Telephone Expense 901 Income Summary Use the following information: a. Two-thirds (or $122) of one month's insurance coverage has expired b. At the end of the month, $600 of office supplies are still available c. This month's depreciation on the computer equipment is $400. d. Employees carned $580 of unpaid and unrecorded salaries as of month-end e. The company carned $2,250 of commissions that are not yet billed at month-end What is the importance of social dance ? Give a brief example of an Impression Management. How do you know the example is Impression Management?