You can see the steps below to make up 500 ml of 50 mM phosphate buffer, pH 7.21, starting with 1.00 M H3PO4 and either 10.0 M HCl or 10.0 M NaOH and make up 500 ml of 50 mM phosphate buffer, pH 7.60, starting from your 50mM phosphate buffer at pH 7.21.
a) To make 500 ml of 50 mM phosphate buffer at pH 7.21, starting with 1.00 M H₃PO₄ and either 10.0 M HCl or 10.0 M NaOH, we need to calculate the amounts of H₃PO₄ and Na₂HPO₄ needed.
Step 1: Calculate the moles of H₃PO₄ required:
Moles of H₃PO₄ = (Desired concentration in moles/liter) * (Volume in liters)
Moles of H₃PO₄ = (0.050 mol/L) * (0.500 L) = 0.025 mol
Step 2: Calculate the volume of 1.00 M H₃PO₄ needed:
Volume of 1.00 M H₃PO₄ = (Moles of H₃PO₄) / (Concentration in mol/L)
Volume of 1.00 M H₃PO₄ = 0.025 mol / 1.00 mol/L = 0.025 L = 25 ml
Step 3: Prepare the phosphate buffer using the calculated volumes of H₃PO₄ and Na₂HPO₄:
a) Add 25 ml of 1.00 M H₃PO₄ to a container.
b) Adjust the pH to 7.21 by adding either 10.0 M HCl or 10.0 M NaOH dropwise until the desired pH is reached.
c) Once the pH is stable at 7.21, adjust the final volume to 500 ml using distilled water or buffer solution.
b) To make 500 ml of 50 mM phosphate buffer at pH 7.60, starting from the 50 mM phosphate buffer at pH 7.21, we need to adjust the pH using either 10.0 M HCl or 10.0 M NaOH.
Step 1: Measure 500 ml of the 50 mM phosphate buffer at pH 7.21.
Step 2: Adjust the pH to 7.60 by adding either 10.0 M HCl or 10.0 M NaOH dropwise until the desired pH is reached. It is important to monitor the pH carefully during this process.
Note: When adjusting the pH, it is recommended to make small incremental additions of the acidic or basic solution while continuously monitoring the pH with a pH meter or indicator paper until the desired pH is achieved.
Ensure that the final volume remains at 500 ml after adjusting the pH.
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A solution contains 7.8% W/V ethanol. Express this in units of g/mL.
A solution that contains 7.8% W/V ethanol is equivalent to 0.078g/mL. Details about weights per volume can be found below.
How to convert W/V% to g/mL?Weights per volume is a unit for measuring density of a substance. It can be converted to g/mL using the following expression:
w/v% = g/100mL
According to this question, a solution contains 7.8% W/V ethanol. The equivalent of this in g/mL is as follows:
7.8% W/V = 7.8g/100mL
= 0.078g/mL
Therefore, a solution that contains 7.8% W/V ethanol is equivalent to 0.078g/mL.
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is glycine mono functional?
Answer:
Yes
Explanation:
Answer:it act as a precursor to proteins
Explanation:
Is copper and silver nitrate a physical change or Chemical change
Explanation:
One of the most fascinating chemical experiments is the reaction between silver nitrate and copper wire in water. Characterised by fractal-like precipitates, this experiment is a stunning example of a simple redox reaction.
Copper reacting with silver nitrate is a chemical change. In a chemical change, new substances are formed with different chemical properties.
Copper (Cu) is a metal, and silver nitrate is a compound made of silver (Ag), nitrogen (N), and oxygen (O).When copper is added to silver nitrate, a reaction occurs. The copper atoms react with the silver nitrate molecules, resulting in the formation of new substances.
The reaction produces copper nitrate and silver (Ag) as products.Copper nitrate is a compound formed by the combination of copper, nitrogen, and oxygen, while silver remains unchanged.
The color of the solution changes, indicating a chemical reaction has taken place. Copper nitrate is usually a blue-green color, while silver is a metallic silver color.The chemical properties of the substances involved in the reaction are altered. Copper, being a metal, is malleable and conducts electricity, whereas copper nitrate is a compound and does not possess these properties.
Thus, the reaction between copper and silver nitrate is a chemical change because new substances with different properties are formed.
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How much more uranium is there diffused in our oceans compared to what we can mine on land?
There is nearly 1000 times more uranium diffused in our oceans as compared to mine on land.
The world ocean contain more than 4 billion metric tons of dissolved uranium . Uranium is removed from ocean by diffusion across the sediment-water interface of organic-rich sediments.
Mining of Uranium on land.Uranium ore is deposits are economically recovered within earth crust. The uranium elements is common elements present in earth crust as it found 40 times more as compare to silver and 500 times more as compare to gold. It can found in everywhere in the rock , soil, river, and ocean.
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A compound has an empirical formula of CH₂O. What is its molecular formula, if its molecular mass is 90 g/mol?
(C=12.01 amu, H=1.008 amu, O=16.00 amu)
A: C3H6O3
B: C9H1809
i need help asap, will give brainliest and 50 points, as this is on my final :)
Empirical formula mass
[tex]\\ \tt{:}\dashrightarrow 12+2+16[/tex]
[tex]\\ \tt{:}\dashrightarrow 30g/mol[/tex]
n:-
[tex]\\ \tt{:}\dashrightarrow \dfrac{Molecular\:mass}{Empirical\:mass}[/tex]
[tex]\\ \tt{:}\dashrightarrow \dfrac{90}{30}[/tex]
[tex]\\ \tt{:}\dashrightarrow 3[/tex]
Molecular formula
[tex]\\ \tt{:}\dashrightarrow n\times Empirical\: formula [/tex]
[tex]\\ \tt{:}\dashrightarrow 3(CH_2O)[/tex]
[tex]\\ \tt{:}\dashrightarrow C_3H_6O_3[/tex]
What is the total pressure of a mixture of he and h2 if the partial pressures are 320 mm hg and 800 mm hg respectively
Answer:
1120 mm Hg
plus give brainliest
Explain one way that God showed precision in his creation. (use complete sentences)
One way in which God showed precision in his creation was his mighty love on the he has on his creation
The book of John made us to know that: For God do love the world that he gave his only begotten son that whosoever believeth in him shall not perish but have everlasting life.
What is creation?Creations is the art of producing or making something out of something
So therefore, one way in which God showed precision in his creation was his mighty love on the he has on his creation
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Use the following, balanced equation for the question below:
2Al(s) + 3CuCl₂(aq) → 3Cu(s) + 2AlCl3(aq)
How many moles of aluminum are needed to produce 50.0 grams of aluminum chloride?
Answer:
0.375 moles Al
Explanation:
To find the moles Al, you need to (1) convert grams AlCl₃ to moles AlCl₃ (via molar mass) and then (2) convert moles AlCl₃ to moles Al (via mole-to-mole ratio from equation coefficients). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value (50.0 g).
Molar Mass (AlCl₃): 26.982 g/mol + 3(35.453 g/mol)
Molar Mass (AlCl₃): 133.341 g/mol
2 Al(s) + 3 CuCl₂(aq) -----> 3 Cu(s) + 2 AlCl₃(aq)
50.0 g AlCl₃ 1 mole 2 moles Al
-------------------- x ------------------ x ----------------------- = 0.375 moles Al
133.341 g 2 moles AlCl₃
If a reaction occurs, what will be the products of the unbalanced reaction below?Zn(s) + HCl(aq) -->
A. No reaction will occur
B. ZnH(s) + Cl2(g)
C. ZnCl2(s) + H2(g)
D. HZnCl(s)
The products will be [tex]ZnCl_2(s) + H_2(g)[/tex]
Chemical reactionsZn is higher than hydrogen in the reactivity series. Thus, it will be able to displace hydrogen from the acid.
The equation of the reaction becomes: [tex]Zn(s) + HCl(aq) -- > ZnCl_2 (s) + H_2 (g)[/tex]
Hydrogen gas is released as a result. In fact, it is one of the ways of preparing hydrogen gas in the laboratory.
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To make a solution of lemonade, lemon juice and sugar are dissolved in water. the water is the ______ in this example.
To make a solution of lemonade, lemon juice and sugar are dissolved in water. the water is the Solvent in this example.
Solvent Examples. Common examples of solvents consist of water, ethanol, methanol, and acetone. The term 'solvent' may be defined as a substance that has the ability to dissolve a given solute to form a solution with it.
Solvents are substances that are used to dissolve the solutes used in the formulation. These solutes can be solids, liquids, or gaseous in nature. Thus solvents are used to get a solution upon interacting the solute with a suitable solvent.
Solvents are usually, however not usually, liquids. They can also be gases or solids. The material dissolved in the solvent is referred to as the solute. collectively, the solvent and solute comprise the solution.
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point
Which is the correct balanced equation for copper(II) sulfate + aluminium -->
aluminium sulfate + solid copper?
Answer: 2Al(s) + 3CuSO4(aq) → Al2(SO4)3(aq) + 3Cu(s)
Explanation: The quantities of aluminum and copper sulfate used as reactants will be such that the copper sulfate will be in excess. Thus, the aluminum will be the limiting factor in determining the number of moles (gram-atoms) of products that will be formed.
At a particular temperature, the solubility of Kr in water is 0.060 M when the partial pressure is 0.90 atm. What partial pressure (in atm) of Kr would give a solubility of 0.150 M
At a particular temperature, the solubility of He in water is 0.060 M when the partial pressure is 0.90 atm. 2.27 atm is the partial pressure of Kr would give a solubility of 0.150 M.
What is Henry's Law ?According to Henry's law, the weight of a gas dissolved by a liquid is proportional to the pressure of the gas onto the liquid.With very few exceptions, a solute molecule in an extremely diluted solution will only have solvent molecules as its close neighbors. This means that the likelihood that a specific solute molecule will escape into the gas phase is predicted to be independent of the total concentration of solute molecules.Solution:
The solubility of gas is directly proportional to partial pressure. It is expressed as:
S = [tex]K_ h \times P _g_a_s[/tex]
where, S = Solubility of gas
[tex]K_h[/tex] = Henry's Law constant
[tex]P_g_a_s[/tex] = Partial pressure of gas
Now, put the values in above expression we get
0.060M = [tex]K_h[/tex] × 0.9 atm
[tex]K_h[/tex] = = 0.066 M/atm
Now we have to find the partial pressure of He
0.150 M = 0.066 M/atm × [tex]P_g_a_s[/tex]
[tex]P_g_a_s[/tex] = 2.27 atm
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What is the concentration, in ppb, of
PCB's in a chemical spill, if there
are 6.0 x 10-5 g in 4,600 kg of soil?
Answer:
1ppm = 1 mg/kg
60460 = 0.13
0.13
Explanation:
Answer:0.013 ppb
Explanation:
Consider the balanced equation below.
N2H4 + 2H2O2 Right arrow. N2 + 4H2O
What are the mole ratios of hydrazine (N2H4) to hydrogen peroxide (H2O2) and hydrazine to water?
1:2 and 1:4
1:3 and 1:4
1:2 and 3:5
1:3 and 3:5
Answer:
Explanation: The reaction between hydrazine and hydrogen peroxide yields nitrogen and water. The balanced chemical reaction is:
N2H4 + 2H2O2 N2 + 4H2O
which means that the mole ratio between hydrazine and hydrogen peroxide is 1:2 and the mole ratio between hydrazine and water is 1:4.
Consider a 175.7 g sample of the compound manganese(IV) perchlorate.
Using the formula Mn(ClO₄)₄ (MM = 452.74), What quantity in moles of oxygen are in 175.7 g of manganese perchlorate?
Answer:
6.21 moles O
Explanation:
To find the moles of oxygen, you need to (1) convert grams Mn(ClO₄)₄ to moles Mn(ClO₄)₄ (via molar mass) and then (2) convert moles Mn(ClO₄)₄ to moles O (via mole-to-mole ratio from formula subscripts). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units.
Molar Mass (Mn(ClO₄)₄): 452.74 g/mol
1 Mn(ClO₄)₄ = 1 Mn and 4 Cl and 16 O
175.7 g Mn(ClO₄)₄ 1 mole 16 moles O
--------------------------- x ------------------- x --------------------------- = 6.21 moles O
452.74 g 1 mole Mn(ClO₄)₄
State whether it would be worthwhile to investigate finding a catalyst to use in this reaction under standard conditions and explain why?.
Yes, it will be worthwhile to investigate finding a catalyst to use in this reaction under standard conditions because it is negative.
What is a Catalyst?This is a substance which speeds up the rate of a chemical reaction by lowering the activation energy.
ΔG being negative indicates a a slow reaction which is why a catalyst under standard conditions should be used.
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Explain why all the elements of period 3 is placed on the periodic table in period 3
Answer:
3 Electron shell/orbit
Explanation:
the number of shell an element has is what determines the period of that element.
You picked up a dirty test tube with a sticky substance on the outside. You get some of this substance on your hand. What is the first thing you should do
You picked up a dirty test tube with a sticky substance on the outside. You get some of this substance on your hand. The first thing that I should do is wash my hand and then tell the teacher.
Define the test tube.A test tube often referred to as a culture tube or sample tube, is a typical item of lab glassware that is made up of a finger-like length of clear plastic or glass tubing that is open at the top and closed at the bottom. Usually, test tubes are stored on dedicated racks.
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What part of the autonomic
nervous system calms you down
after an exciting event?
A. Somatic
B. Temporal lobe
C. Parasympathetic
Answer:
C. Parasympathetic
Explanation:
Suppose 110.0 mL110.0 mL of hydrogen gas at STP combines with a stoichiometric amount of fluorine gas and the resulting hydrogen fluoride dissolves in water to form 150.0 mL150.0 mL of an aqueous solution. What is the concentration of the resulting hydrofluoric acid
Suppose 110.0 mL of hydrogen gas at STP combines with a stoichiometric amount of fluorine gas and the resulting hydrogen fluoride dissolves in water to form 150.0 mL of an aqueous solution. 0.032 M is the concentration of the resulting hydrofluoric acid.
What is Balanced Chemical Equation ?The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.
Now write the balanced chemical equation
H₂ + F₂ → 2HF
What is Ideal Gas ?An ideal gas is a gas that obey gas laws at all temperature and pressure conditions. It have velocity and mass but do not have volume. Ideal gas is also called perfect gas. Ideal gas is a hypothetical gas.
It is expressed as:
PV = nRT
where,
P = Pressure
V = Volume
n = number of moles
R = Ideal gas constant
T = temperature
Here,
P = 1 atm [At STP]
V = 110 ml = 0.11 L
T = 273 K [At STP]
R = 0.0821 [Ideal gas constant]
Now put the values in above expression
PV = nRT
1 atm × 0.11 L = n × 0.0821 L.atm/ K. mol × 273 K
[tex]n = \frac{1\ \text{atm} \times 0.11\ L}{0.0821\ \text{L. atm/ K. mol} \times 273\ K}[/tex]
n = 0.0049 mol
How to find the concentration of resulting solution ?To calculate the concentration of resulting solution use the expression
[tex]C = \frac{n}{V}[/tex]
[tex]= \frac{0.0049}{0.15}[/tex]
= 0.032 M
Thus from the above conclusion we can say that Suppose 110.0 mL of hydrogen gas at STP combines with a stoichiometric amount of fluorine gas and the resulting hydrogen fluoride dissolves in water to form 150.0 mL of an aqueous solution. 0.032 M is the concentration of the resulting hydrofluoric acid.
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A substance crystallizes with one atom at each corner, one atom on 8 of the edges, and one atom on 6 of the faces. How many atoms are present in one unit cell
The number of atoms in one unit cell with one atom at each corner, one atom on 8 of the edges, and one atom on 6 of the faces are 4.6atoms.
There is one atom at each corner and there are 8 corners in a unit cell, so there is one atom in each of the eight corners.
Therefore, the number of atom from corners = 1 x 1/8 = 1atom
There are 12 edges, since there are one atom on 8 of the edges the number of atom = 1 x 8/12 = 0.6atom
There is one atom at each face and there are 6 faces in a unit cell, each atom shares two face.
Therefore, the number of atoms on face = 2 x 1/6 = 3
Total number of atoms in one unit cell = 1 + 0.6 + 3 = 4.6atoms
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The volume occupied by 0.4g of hydrogen gas at S.T.P is ________
{H=1.00, Molar volume at S.T.P =22.4dm^3
Answer:
4.48 dm^3
Explanation:
As given in the problem, the conversion factor for the molar volume of all gases is 22.4 dm^3/mole at STP. A mole of all ideal gases will occupy 22.4 liters (dm^3). Calculate the moles of hydrogen contained in 0.4 grams of the gas by dividing the mass by the molar mass of H2. H2 has a molar mass of 2 grams/mole.
(0.4 g)/(2 grams/mole) = 0.2 moles H2
(0.2 moles H2 at STP)*(22.4 dm^3/mole at STP) = 4.48 dm^3 (4.48 liters at STP)
A compound has a percent composition of 81.71% C and 18.29% H. What is the empirical formula of this compound?
Considering the definition of empirical formula, the empirical formula is C₃H₈.
Definition of empirical formulaThe empirical formula is the simplest expression to represent a chemical compound, which indicates the elements that are present and the minimum proportion in whole numbers that exist between its atoms, that is, the subscripts of chemical formulas are reduced to the most integers. small as possible.
Empirical formula in this caseIn this case, in first place you know the percent composition:
C: 81.71 %H: 18.29%Assuming a 100 grams sample, the percentages match the grams in the sample. So you have 81.71 grams of carbon and 18.29 grams of hydrogen H.
Then it is possible to calculate the number of moles of each atom in the molecule, taking into account the corresponding molar mass:
C: [tex]\frac{81.71 grams}{12\frac{grams}{mole} }[/tex]= 6.81 molesH:[tex]\frac{18.29 grams}{1\frac{grams}{mole} }[/tex]= 18.29 molesThe empirical formula must be expressed using whole number relationships, for this the numbers of moles are divided by the smallest result of those obtained. In this case:
C: [tex]\frac{6.81 moles}{6.81 moles}[/tex]= 1H:[tex]\frac{18.29 moles}{6.81 moles}[/tex]= 2.68 ≅ [tex]\frac{8}{3}[/tex]To express this relationship in the form of simple integers, it is necessary to multiply by a simple number to achieve this:
C: 1×3 =3 H:≅ [tex]\frac{8}{3}[/tex]×3= 8Therefore the C: H mole ratio is 3: 8
Finally, the empirical formula is C₃H₈.
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What type of cleaning agent should be used to clean a laminar flow hood?
a. 70% Isopropyl Alcohol.
b. 90% Ethyl Propyl alcohol.
c. 90% Isopropyl Alcohol.
d. 50% Ethyl Propyl alcohol.
The type of cleaning agent that should be used to clean a laminar flow hood is 70% Isopropyl Alcohol.
Isopropyl alcohol is mixed with water for use as a rubbing-alcohol antiseptic. It is also utilized in aftershave creams, hand lotions, and other cosmetics. In enterprise, it is used as a less expensive solvent for cosmetics, drugs, shellacs, and gums, in addition to denaturing ethanol (ethyl alcohol).
Isopropyl alcohol is a colorless, flammable chemical compound with a robust alcoholic smell. As an isopropyl institution related to a hydroxyl group, it's far the handiest example of a secondary alcohol, wherein the alcohol carbon atom is connected to 2 other carbon atoms.
Isopropyl alcohol is pure alcohol and is a colorless liquid with a musty, sharp odor. There are no other components in a bottle of isopropyl alcohol. through assessment, rubbing alcohol consists of isopropyl alcohol among different components, including water. maximum rubbing alcohol manufacturers incorporate 70% isopropyl alcohol.
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A 25.0 mL sample of 0.723 M HClO4 is titrated with a 0.273 M KOH solution. What is the [H ] (molarity) before any base is added
0.723 is the [H ] (molarity) before any base is added.
the balanced equation for the acid-base reaction is
KOH + HClO₄ ---> KClO₄ + H₂O
stoichiometry of KOH to HClO₄ is 1:1
The number of HClO₄ moles - 0.723 M / 1000 mL/L x 25.0 mL = 0.0181 mol
Number of KOH moles - 0.27 M/ 1000 mL/L x 80.0 mL = 0.0216 mol
KOH is a strong acid and HClO₄ is a strong base therefore complete dissociation takes place.
the acid reacts with base in a 1:1 molar ratio, there's excess base remaining.
excess OH⁻ ions - 0.0216 - 0.0181 = 0.0035 mol
concentration is calculated as the number of moles/volume
volume of solution - 25.0 + 80.0 = 105.0 mL
[OH⁻] = 0.0035 mol / 0.105 L = 0.033 M
pOH = -log [OH⁻]
pOH = -log(0.033 M)
pOH = 1.48
pH can be calculated by knowing the pOH
pH + pOH = 14
pH = 14 - 1.48 = 12.52
pH = -log [H₃O⁺]
[H₃O⁺] = antilog(-12.52)
[H₃O⁺] = 3.0 x 10⁻¹³ M
0.723 is the [H ] (molarity) before any base is added.
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What is the name of the molecule below?
G
O A. Ethyne
O B. Ethene
C. Methene
OD. Methyne
H-C=C-H
The name of the molecule above is Ethene
What are organic compounds?Organic compounds can be defined as compounds containing carbon and hydrogen.
Some classes of organic compounds are:
AlkanesAlkenesAlkanolsAlkanalsAlkynesSo therefore, he name of the molecule above is Ethene
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The metal which produces hydrogen gas on reaction with dilute hydrochloric acid as well as sodium hydroxide solution is _____.
Metal which produces hydrogen gas:
Aluminum metal produces hydrogen gas with dilute hydrochloric acid as well as sodium hydroxide.
What are amphoteric oxides?
Amphoteric oxides are the metal oxides which reacts with both acids and bases.
Some metals are also amphoteric, ie. on reaction with acid or base, the product will be salt and Hydrogen gas.
Amphoteric metal + acid/base → salt + hydrogen gas
Few metals of the periodic table are amphoteric in nature. Like Aluminum, Zinc etc.
Reactions:
Reaction with dilute NaOH:
2Al + 2NaOH + 2[tex]H_{2}[/tex]O → 2NaAl[tex]O_{2}[/tex] + [tex]H_{2}[/tex]
Reaction with dilute HCl:
2Al + 6HCl(aq) → 2Al[tex]Cl_{3}[/tex] + 3[tex]H_{2}[/tex]
Dilute and Aqueous (aq) means mixed with water ([tex]H_2O[/tex])
These reaction are balanced in order to follow the Law of conservation of mass.
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Calculate the number of molecules in 3 mol of carbon dioxide (CO2).
18.06 ₓ [tex]10^{23}[/tex] molecules in 3 mol of carbon dioxide (CO2).
What is Avogadro's number?The proportionality factor that connects the quantity of substance in a sample to the number of constituent particles in that sample is called the Avogadro constant. The reciprocal mole, which is its SI unit, is specified precisely as NA 6.02214076 × [tex]10^{23}[/tex] [tex]mol^{-1}[/tex]. It bears Amedeo Avogadro's name, an Italian scientist.
When dealing with very big quantities, chemistry uses Avogadro's number. It serves as the foundation for the mole, a unit of measurement that makes converting between moles, mass, and the number of molecules simple. The quantity, for instance, can be used to determine how many water molecules make up a single snowflake.
1 Mole is 6.02ₓ [tex]10^{23}[/tex] molecules.
Therefore 3 Moles of Carbon Dioxide ([tex]CO_{2}[/tex]) =3(6.02ₓ [tex]10^{23}[/tex])
3 Moles of Carbon Dioxide ([tex]CO_{2}[/tex]) =18.06 ₓ [tex]10^{23}[/tex]molecules of [tex]CO_{2}[/tex].
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Crude petroleum is a mixture of many different components. How might one separate out the components to begin the process of refining petroleum
Fractional distillation is used for the refining of crude petroleum.
How are the components of crude petroleum separated out?Fractional distillation is the procedure used to separate crude oil's numerous constituents.
A mixture is divided into several components, known as fractions, using fractional distillation.A combination of hydrocarbons makes up crude oil. The crude oil evaporates, and in the fractionating column, its vapors condense at various temperatures.The hydrocarbon molecules in each percent have a comparable number of carbon atoms and a comparable range of boiling points.The mixture is placed above a tall fractionating column that has multiple condensers coming off at various heights.The bottom of the column is warm, while the top is cool. High boiling point compounds condense at the bottom, whereas low boiling point substances condense as they ascend.Learn more about fractional distillation here:
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What is the balanced chemical reaction for Mg+H2=MgH, K+O2= KO, K+S= KS, Ba + Br2= BaBr, Ca + N2= CaN
(Giving brainliest for the answer that shows work) Please and thank you!
Answer:
1.) 2 Mg + H₂ ------> 2 MgH
2.) 2 K + O₂ -----> 2 KO
3.) K + S -----> KS
4.) 2 Ba + Br₂ -----> 2 BaBr
5.) 2 Ca + N₂ ------> 2 CaN
Explanation:
An equation is balanced when there is an equal amount of each element on both sides of a reaction. If there is an unequal amount, they can be altered by adding coefficients which modify the amount of an element/molecule. It is important that the coefficients are as small as possible while staying as whole numbers.
1.) ------------------------------------------------------------------------------------------------------
The unbalanced equation:
Mg + H₂ -----> MgH
Reactants: 1 magnesium, 2 hydrogen
Products: 1 magnesium, 1 hydrogen
The balanced equation:
2 Mg + H₂ ------> 2 MgH
Reactants: 2 magnesium, 2 hydrogen
Products: 2 magnesium, 2 hydrogen
2.) ------------------------------------------------------------------------------------------------------
The unbalanced equation:
K + O₂ -----> KO
Reactants: 1 potassium, 2 oxygen
Products: 1 potassium, 1 oxygen
The balanced equation:
2 K + O₂ -----> 2 KO
Reactants: 2 potassium, 2 oxygen
Products: 2 potassium, 2 oxygen
3.) ------------------------------------------------------------------------------------------------------
The unbalanced equation:
K + S -----> KS
Reactants: 1 potassium, 1 sulfur
Products: 1 potassium, 1 sulfur
This equation is already balanced with all the elements/compounds having coefficients of 1.
4.) ------------------------------------------------------------------------------------------------------
The unbalanced equation:
Ba + Br₂ -----> BaBr
Reactants: 1 barium, 2 bromine
Products: 1 barium, 1 bromine
The balanced equation:
2 Ba + Br₂ -----> 2 BaBr
Reactants: 2 barium, 2 bromine
Products: 2 barium, 2 bromine
5.) ------------------------------------------------------------------------------------------------------
The unbalanced equation:
Ca + N₂ ------> CaN
Reactants: 1 calcium, 2 nitrogen
Products: 1 calcium, 1 nitrogen
The balanced equation:
2 Ca + N₂ ------> 2 CaN
Reactants: 2 calcium, 2 nitrogen
Products: 2 calcium, 2 nitrogen