What is the name of the compound shown here
ethane is the compound of the answer you are asking help
c) If nitrogen diffuses at a rate of 0.0069 m/s, how fast does carbon dioxide diffuse?
Answer:
it defuse at a rate of 0.0002 m/s
Which substance has a molar mass of 33.99 g/mol?
Answer:
PH₃.
Explanation:
Hello.
In this case, among the options:
PH₃, GaF₃, SF₂ and CO₂
We compute their molar masses by adding the atomic masses of the constituting elements by their subscripts:
[tex]M_{PH_3}=m_P+3*m_H=30.97+3*1.01=34.00g/mol\\\\M_{GaF_3}=m_{Ga}+3*m_F=69.72+3*19.00=126.72g/mol\\\\M_{SF_2}=m_{S}+2*m_F=32.07+2*19.00=70.07g/mol\\\\M_{CO_2}=m_{C}+2*m_O=12.01+2*16.00=44.01g/mol[/tex]
Thus, the answer is PH₃.
Best regards.
An element that is considered to be unreactive
because it has a filled outer energy level is
1. silver.
2. hydrogen.
3. helium.
4. lithium.
Answer:
3
helium
Explanation:
Among all the given options, the correct option is option 3. An element that is considered to be unreactive because it has a filled outer energy level is helium.
What is element?Any compound that cannot be broken down into simpler chemicals by regular chemical processes is referred to as a chemical element or element. The building blocks of which every matter is made are called elements.
There are 118 chemical elements that are currently recognized. About 20% of them have only been created synthetically in the lab and are only known because they do never exist in nature or are only present in trace levels. An element that is considered to be unreactive because it has a filled outer energy level is helium.
Therefore, among all the given options, the correct option is option 3.
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Number of electrons for all of these even the ones with a number by them ? Will give brainlist!!!!
Explanation:
s=2
p=6
d=10
f=14
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7. The youngest part of the ocean floor is found ____.
a. along deep-sea trenches
b. where ocean sediments are thickest
c. near ocean ridges
d. where Earth’s magnetic field changes polarity
Answer:
The answer is Near The Ocean Ridges.
A sample is found to contain 66.5% NaHCO3 by mass. What is the mass of NaHCO3 in 4.25g of the sample?
Answer:
2.83 grams NaHCO₃ in the 4.25g Sample.
Explanation:
Given 4.25g Sample is 66.5% NaHCO₃
=> mass of NaHCO₃ = 0.665(4.25g) =2.83grams NaHCO₃.
The mass of NaHCO₃ in 4.25 g of the sample is 2.83 g
From the question given above, the following data were obtained:
Mass of sample = 4.25 g
Percentage by mass of NaHCO₃ = 66.5%
Mass of NaHCO₃ =?[tex]Percentage = \frac{mass of substance}{total mass} X 100[/tex]
66.5% = [tex]\frac{Mass of NaHCO_{3} }{4.25}\\\\[/tex]
Cross multiply
Mass of NaHCO₃ = 66.5% × 4.25
Mass of NaHCO₃ = 0.665 × 4.25
Mass of NaHCO₃ = 2.83 gTherefore, the mass of NaHCO₃ in 4.25 g of the sample is 2.83 g
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A 5.0g sample of O2 is in a container at STP. What volume( liters) is the container? Round to the tenths place
(Need help asap)
A 5.0g sample of O₂ is in a container at STP, then the volume of the container is 3.49 L.
How do we calculate volume?Volume of oxygen sample at STP will be calculated by using the ideal gas equation as:
PV = nRT, where
P = pressure = 1 atm
V = volume of gas = ?
R = universal gas constant = 0.082 L.atm/K.mol
T = temperature = 273K
n is the moles of oxygen sample and it will be calculated as:
n = W/M, where
W = given mass = 5g
M = molar mass of O₂ = 32g/mol
n = 5/32 = 0.156 moles
On putting all values on above equation, we get
V = (0.156)(0.082)(273) / (1)
V = 3.49 L
Hence required volume of gas sample is 3.49 L.
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1) The equilibrium constant Kc of the reaction
I2 (g) ⇔ 2I (g)
is 5.6 × 10-12, at 500 K. In a system maintained at 500 K, the concentration of I2 is 0.020 mol / L and that of I is 2.0 × 10-8 mol / L. Is the reaction in balance? If not, in what sense does the reaction advance to reach equilibrium?
2) Given the concentrations below, how much is Q worth?
If Kc = 1.0, which side of the reaction is favored with this value of Q?
CO (g) + H2O (g) ⇄ CO2 (g) + H2 (g)
[CO (g)] = [H2O (g)] = 1.0 M
[CO2 (g)] = [H2 (g)] = 15 M
Explanation:
1) Find the reaction quotient:
Qc = [I]² / [I₂]
Plug in the Kc value and the I₂ concentration.
Q = [2.0×10⁻⁸]² / (0.020)
Q = 2.0×10⁻¹⁴
Since Qc < Kc, the reaction moves to the right (favors the products).
2) Find the reaction quotient:
Qc = [CO₂] [H₂] / ([CO] [H₂O])
Qc = (15) (15) / ((1.0) (1.0))
Qc = 225
Since Qc > Kc, the reaction moves to the left (favors the reactants).
Which two variables determine the gravitational force between two objects?
A) their densities and the distance separating them
B) their masses and the distance separating them
C) their volumes and magnetic strengths
D) their masses and relative densities
Answer:
B
Explanation:
I did the test
Volume is
A. The amount of space an object takes up
B. the amount of matter in an object
C. a measure of the pull of gravity on an object
D. a special state of matter
Answer:
the amount of matter in an object
A refrigerator uses_________________________ energy to move the_________________________ through the refrigerator pipes.
Answer:
thermal; coolant
Explanation:
A refrigerator transfers thermal energy from the cool air inside the refrigerator to the warm air in the kitchen. I hope this helps! ^-^
For the reaction shown, calculate how many grams of each product form when the following amounts of reactant completely react to form products. Assume that there is more than enough of the other reactant.
2Al(s)+Fe2O3(s)→Al2O3(s)+2Fe(l)
a) Calculate the mass of Al2O3 formed when 4.1 g of Al completely reacts.
Express your answer using two significant figures.
b)Calculate the mass of Fe formed when 4.1 g Al completely reacts.
Express your answer using two significant figures.
c)Calculate the mass of Fe formed when 4.1 g Fe2O3 completely reacts.
Express your answer using two significant figures.
According to the given balanced equation:
a) 4.1 g of Al form 7.7 g of Al₂O₃.b) 4.1 g of Al form 8.5 g of Fe.c) 4.1 g of Fe₂O₃ form 2.9 g of Fe.We want to calculate the mass of products when certain amounts of reactants react. This is a stoichiometry problem.
What is stoichiometry?Stoichiometry refers to the relationship between the quantities of reactants and products before, during, and following chemical reactions.
Let's consider the following balanced equation.
2 Al(s) + Fe₂O₃(s) → Al₂O₃(s) + 2 Fe(l)
a) Calculate the mass of Al₂O₃ formed when 4.1 g of Al completely reacts.
The mass ratio of Al to Al₂O₃ is 53.96:101.96.
4.1 g Al × 101.96 g Al₂O₃/53.96 g Al = 7.7 g Al₂O₃
b) Calculate the mass of Fe formed when 4.1 g Al completely reacts.
The mass ratio of Al to Fe is 53.96:111.70.
4.1 g Al × 111.70 g Fe/53.96 g Al = 8.5 g Fe
c) Calculate the mass of Fe formed when 4.1 g Fe₂O₃ completely reacts.
The mass ratio of Fe₂O₃ to Fe is 159.69:111.70.
4.1 g Fe₂O₃ × 111.70 g Fe/159.69 g Fe₂O₃ = 2.9 g Fe
According to the given balanced equation:
a) 4.1 g of Al form 7.7 g of Al₂O₃.b) 4.1 g of Al form 8.5 g of Fe.c) 4.1 g of Fe₂O₃ form 2.9 g of Fe.Learn more about stoichiometry here: https://brainly.com/question/16060223
Can someone please help me? (Answer the question only if you are going to help). Thanks
Explanation:
a is the answer ok write it easily bye
What is a strong electrolyte?
What is a weak electrolyte?
Provide examples of each one of these categories.
Answer:
An electrolyte is medium containing ions that is electrically conducting through the movement but not conducting electrons . Strong electrolytes are electrolytes that completely ionizes in a solution . Weak electrolytes that partially ionize in a solution .
Explanation:
Strong electrolytes fully dissociate In a solution such as NH4Cl , KOH(Potassium hydroxide) and HCl ( Hydrochloric acid)
Weak electrolytes partially dissociate In a solution such as HC2H3O2 (acetic acid), H2CO3 (carbonic acid), NH3 (ammonia), and H3PO4 (phosphoric acid) .
How many ml of ethyl alcohol are presented in 50 ml bottle of an 70%
Answer:
35ml
Explanation:
please give brainliest
What is true for ALL of the examples of electromagnetic waves?
Given what we know, we can confirm that the one property listed that is universal for all of the electromagnetic waves listed is that they all move at the same speed in a vacuum.
What are electromagnetic waves?These are a specific type of wave. These waves are the result of interactions between an electric field and a magnetic field. These waves have many properties and can be of many distinct types, however, one universal property of these waves is that all of them will move at the same speed whilst in a vacuum.
Therefore, we can confirm that the one property listed that is universal for all of the electromagnetic waves listed is that they all move at the same speed in a vacuum.
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At the same temperature, which of the following gases will effuse the slowest?
A) Hydrogen
B) Helium
C) Fluorine
D) Xenon
E) Bromine
Xenons at the same temperature, will effuse the slowest
The effusion rates is said to be inversely proportional to the square root of the molecular masses of the gases.
Hydrogen, helium, fluorine, and bromine effuses out of container earlier than Xenon because they have lower mass when compared to Xenon.At a set temperature, the average kinetic energy of all gaseous molecules is always equal.
Hydrogen gas has the lowest mass out of these gases, it will have the highest average velocity and as such, that it will exit out of the tiny hole at a rate faster than the other gases.
As the mass increases, the rate of effusion decreases. The gas with the lowest molecular weight will effuse the fastest.Conclusively, The rate of effusion for a gas is inversely proportional to the square-root of its molecular mass, this is Graham's Law.
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Answer: Bromine
Explanation: The rate of effusion is inversely proportional to the molar mass. Bromine (Br2) has a the highest molar mass of this group, and will therefore be the slowest
An atomic scientist was studying an atom which through experimentation found that the total negative charge of the area surrounding the nucleus is -9. which statement corretly describes this atom? A.the atom has 9 clouds. B.the atom has 9 electrons C.the atom has 9 neutrons. D.the atom has 9 protons.
Answer:
The answer is B
Explanation:
The area surrounding the nucleus is called the electron cloud which holds the electrons, so with the power of deduction its B. 0-0
Less massive molecules tend to escape from an atmosphere more often than more massive ones because:.
Since lighter molecules are moving faster, they escape from an atmosphere more often than more massive ones.
What is escape velocity?The escape velocity is the velocity that an object must be given in order to escape from the gravitational field of the earth. We must know that a less massive molecule moves faster than a more massive molecule.
Hence, less massive molecules tend to escape from an atmosphere more often than more massive ones because they are moving faster.
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who knows this......
The convergence of two oceanic plates can give rise to deep sea trenches, island arcs, and tall folded mountains, each of which is a distinctive geological feature resulting from the complex interplay of subduction, volcanic activity, and crustal compression. options A,C and D are correct.
When two oceanic plates converge, several geological features can develop as a result of the collision. One common feature is the formation of deep sea trenches. As the denser oceanic plate subducts beneath the other plate, it creates a deep trench in the ocean floor. The subduction process leads to the downward bending of the oceanic plate, forming a trench that can extend for hundreds or thousands of kilometers.
Another feature that can develop is the formation of island arcs. As the subducting oceanic plate sinks into the mantle, it releases water and volatiles, which cause the overlying mantle to melt. This molten material rises through the Earth's crust, creating a chain of volcanic islands known as an island arc. These islands are often characterized by active volcanism and can be seen in regions such as the Pacific Ring of Fire.
Additionally, the convergence of two oceanic plates can result in the formation of tall folded mountains. As the leading edge of one plate is compressed and pushed upwards, it forms a range of folded mountains. The collision and compression forces can cause the sedimentary layers to buckle and fold, leading to the creation of prominent mountain ranges. options A,C and D are correct.
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how would you separate a mixture of oil,water and sand?plz help
Answer:
1) Filter the mixture, Sand will remain on the filter paper. 2) Then pour the mixture of mustard oil and in separating funnel. Water will settle down at bottom and mustard oil will float on it. Then open the stopcock of the separating funnel and pour out the lower layer of water.
Explanation:
What is the mass in grams of 381 mL of ethylene glycol?
Has a density of 1.11 grams/cm^3
Answer:
The answer is 422.91 gExplanation:
The mass of a substance when given the density and volume can be found by using the formula
mass = Density × volumeFrom the question
volume = 381 mL = 381 cm³
density = 1.11 g/cm³
So we have
mass = 1.11 × 381
We have the final answer as
422.91 gHope this helps you
What is the pH of a solution with [ht] = 2.3 * 10-3?
A. 3.00
B. -2.64
O C. -0.36
O D. 2.64
Answer:
The pH of a solution with [H+] = 2.3 x 10^-3 is 2.64.
Explanation:
if a gas is held in 3.60 L, 298 K AND 800. mmHg, what is the new pressure of the gas if the volume us decreased by half and the tempature is decreased to 250. K
Answer:
Explanation:
By Ideal Gas Law, P1*V1 / T1 = P2*V2 / T2
So new pressure = (P1*V1 / T1) / (V2 / T2)
= P1*V1*T2 / T1*V2
= 800*3.6*298 / 250*1.8
= 1907.2 mmHg
Apply combine gas law
[tex]\\ \rm\Rrightarrow \dfrac{P1V1}{T1}=\dfrac{P2V2}{T2}[/tex]
[tex]\\ \rm\Rrightarrow P2=\dfrac{P1V1T2}{V2T1}[/tex]
[tex]\\ \rm\Rrightarrow P2=\dfrac{800(3.6)(250)}{1.8(298)}[/tex]
[tex]\\ \rm\Rrightarrow P2=720000/536.4[/tex]
[tex]\\ \rm\Rrightarrow P2=1341.7 mmHg[/tex]
Observation
• Use your senses to make an observation about your environment.
Questions
• Create a hypothesis that can be tested in an experiment.
Remember, a hypothesis has a specific "if then" wording. It describes what will happen to the dependent variable
when changes are made to the independent variable. For example, "If a plant is fertilized (independent variable),
then it will grow faster (dependent variable)."
.
Design and plan an experiment.
Be sure to identify an independent variable, a dependent variable, and any controls. Remember, controls are factors
which stay the same. In an experiment designed to test the previously stated hypothesis, one control would be to
use the same kind of plant. Write a complete description of your experiment. Include a list of necessary materials. It
is a good idea to follow a step-by-step procedure format. Think of everything you need to do, then write it down in
the order it must be completed. Your description and procedure should be clear enough that another person could
duplicate your experiment exactly
Answer:
Hi...... I have this same question............
Biologists and other scientists use the scientific method to ask questions about. When possible, scientists test their hypotheses using controlled experiments. Test a hypothesis by making predictions about patterns that should be seen in. This variable is independent because it does not depend on what happens in the.
Explanation:
Explain the structural relationship between amino acids and proteins
Answer:
A protein is just a long chain of amino acids. So, one could say that the monomer of a protein is an amino acid. Here is a diagram of a protein and amino acid for reference:
Two bulbs are connected by a stopcock. The large bulb, with a volume of 6.00 L, contains nitric oxide at a pressure of 0.850 atm, and the small bulb, with a volume of 1.50 L, contains oxygen at a pressure of 2.50 atm. The temperature at the beginning and the end of the experiment is 22∘C .
After the stopcock is opened, the gases mix and react.
2NO(g)+O2(g)→2NO2(g)
1. Which gases are present at the end of the experiment?
2. What are the partial pressures of the gases? If the gas was consumed completely, put 0 for the answer.
Answer:
(I). The gases are present at the end of the experiment are O₂ and NO₂
(II). The pressure of O₂ is 0.158 atm.
The pressure of NO₂ is 0.681 atm
The Pressure of NO is zero.
Explanation:
Given that,
Volume of large bulb = 6.00 L
Pressure = 0.850 atm
Volume of small bulb = 1.50 L
Pressure = 2.50 atm
Temperature = 22°C = 295 K
We need to calculate the moles in NO
Using formula of moles
[tex]n=\dfrac{PV}{RT}[/tex]
Put the value into the formula
[tex]n=\dfrac{0.850\times6.00}{0.0821\times295}[/tex]
[tex]n=0.211\ moles[/tex]
We need to calculate the moles in O
Using formula of moles
[tex]n=\dfrac{PV}{RT}[/tex]
Put the value into the formula
[tex]n=\dfrac{2.50\times1.50}{0.0821\times295}[/tex]
[tex]n=0.155\ moles[/tex]
The balance equation for the reaction is
[tex]2NO+O_{2}\Rightarrow 2NO_{2}[/tex]
So, The gases are present at the end of the experiment are O₂ and NO₂
We need to calculate the remaining moles of O₂
Using formula for remaining moles
Moles of O₂ remaining = [tex]0.155-\dfrac{0.211}{2}[/tex]
[tex]Moles\ of \ O_{2}\ remaining =0.049\ moles[/tex]
Moles of NO₂ = 0.211 moles
Total volume [tex]V=V_{l}+V_{s}[/tex]
Put the value into the formula
[tex]V=6.00+1.50[/tex]
[tex]V=7.5\ V[/tex]
(2). If the gas was consumed completely
We need to calculate the pressure of O₂
Using formula of pressure
[tex]P=\dfrac{moles\times R\times T}{V}[/tex]
Put the value into the formula
[tex]P=\dfrac{0.049\times0.0821\times295}{7.5}[/tex]
[tex]P=0.158\ atm[/tex]
We need to calculate the pressure of NO₂
Using formula of pressure
[tex]P=\dfrac{moles\times R\times T}{V}[/tex]
Put the value into the formula
[tex]P=\dfrac{0.211\times0.0821\times295}{7.5}[/tex]
[tex]P=0.681\ atm[/tex]
If the gas was consumed completely
Then, Pressure of NO is zero.
Hence, (I). The gases are present at the end of the experiment are O₂ and NO₂
(II). The pressure of O₂ is 0.158 atm.
The pressure of NO₂ is 0.681 atm
The Pressure of NO is zero.
The gases that remained at the end of the experiment are nitrogen dioxide and nitric oxide. The partial pressure of nitric oxide has been 0.43 atm, nitrogen dioxide has been 1 atm, and oxygen has been 0 atm.
The balanced chemical equation has been given that, 2 moles of NO reacts completely with 1 mole of oxygen.
(1) According to the ideal gas equation:
PV nRT
n = [tex]\rm \dfrac{PV}{RT}[/tex]
The moles of NO;NO = [tex]\rm \dfrac{0.850\;atm\;\times\;6\;L}{0.0821\;L.atm/mol.K\;\times\;295\;K}[/tex]
Moles of NO = 0.211 moles
The moles of Oxygen:Oxygen = [tex]\rm \dfrac{2.50\;atm\;\times\;1.50\;L}{0.0821\;L.atm/mol.K\;\times\;295\;K}[/tex]
Moles of oxygen = 0.155 moles.
For 2 moles NO, 1 mole oxygen is used.
For 0.211 moles, Oxygen has been 0.422 moles.
The oxygen has been in a lesser quantity than requires, thus it has been the limiting reactant.
The gas that presents at the end of the reaction has been NO.
(2) The pressure of the gas has been calculated as:
After the complete consumption of the gas, NO remaining has been:
2 moles oxygen = 1 moles NO
0.155 moles oxygen = 0.0775 moles NO.
The moles of NO remaining = 0.211 - 0.0775 mol
The moles of NO remaining = 0.1335 mol.
The total volume of the solution will be 6 + 1.5 L = 7.5 L.
The moles of Nitrogen dioxide formed :
1 mole oxygen = 2 moles Nitric oxide
0.155 moles oxygen = 0.31 moles nitric oxide.
The partial pressure can be given by:
P = [tex]\rm \dfrac{nRT}{V}[/tex]
The pressure of NO:Pressure of NO = [tex]\rm \dfrac{0.1335\;\times\;0.08206\;\times\;295}{7.5}[/tex]
Pressure of NO = 0.43 atm.
The pressure of Oxygen = 0 atm.
The pressure of Nitrogen dioxide:
Pressure of nitrogen dioxide = [tex]\rm \dfrac{0.31\;\times\;0.08206\;\times\;295}{7.5}[/tex]
Pressure of nitrogen dioxide = 1.00 atm.
The gases that remained at the end of the experiment are nitrogen dioxide and nitric oxide. The partial pressure of nitric oxide has been 0.43 atm, nitrogen dioxide has been 1 atm, and oxygen has been 0 atm.
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A benzene ring with two substituents, a bromo and chloro substituent. Each substituent is placed on a carbon two carbons away from the other. The parent name is benzene and there is a chloro and bromo substituent. Disubstituted benzenes can be described using the terms ortho, meta and para, depending on their relative distance from each other. The terms are often just abbreviated as o, m and p. In addition, the IUPAC name can use locant numbers instead of the descriptor.
a. 1-bromo-3-chlorobenzene
b. 3-bromo-1-chlorobenzene
c. meta-bromochlorobenzene
d. o-bromochlorobenzene
e. ortho-bromochlorobenzene
f. m-bromochlorobenzene
The correct name of the structure given in the question is 1–bromo–3–chloro benzene (Option A)
How to name organic compoundsThe naming of organic compounds follows the standard of the international union of pure and applied chemistry (IUPAC).
To name a compound, we must
Locate the longest continuous carbon chain and determine the functional group of the compound. This gives the name of the compound. Locate the substituent groups attached Give the substitute group the lowest locate by naming alphabetically Combine the above to obtain the name of the compound. How name the compound The compound is a benzene ringThe substituent groups attached are bromo (Br) and Chloro (Cl) The Br is at carbon 1 while Cl is at carbon 3Therefore, the name of the compound is 1–bromo–3–chloro benzeneComplete question
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wha is the specific heat of aluminum at 72.9 °C