The present value of the tax benefits from depreciation which is a non cash expenditure under capital budgeting decisions is $10432.80
What is Depreciation?According to the prudence concept of accounting convention, Depreciation is a non cash expenditure that has been charged against the profit. Depreciation is value that amortized over useful life of tangible fixed asset. The absolute decline in the value of asset due to obsolesce, usage of asset, wear & tear of fixed asset is referred as depreciation.
As per accounting standard on property, plant & equipment depreciation can be computed by straight line method and written down value method.
While analyzing the capital budgeting decision from the equipment to be acquired the cash inflows and outflows during the currency of the project shall be accounted for.
The tax benefit from depreciation expenses will be consider as cash inflow. The same shall be calculated by the present value annuity factor for the as follows:
cost of capital = 12 %
Depreciation = $10000
Life of the project = 8 years
Tax rate = 21%
Present value annuity factor (PVAF) at 12% for 8 years will be:
0.893 0.797 0.712 0.636 0.567 0.507 0.452 0.404
Grand total of the (PVAF) at 12% = 4.968
Now multiply the PVAF with depreciation amount
Present Value of Depreciation = 4.968 × 10000 = $49,680
Tax benefit from depreciation = $49,680 × 21% = $10432.8
Thus the tax Tax benefit from depreciation is $10432.80
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Consider the composite function g(f(x)) =x√6.
If f(x) = 3x², what is g(x)?
O g(x)=√2x
Og(x)=√x+3
Og(x)=√6x
O g(x)=√9-x
So on solving the provided question, we can say that the function g(x) is equal to g(x) = [tex]\sqrt{2x}[/tex]
A composite function is what?The mathematical procedure known as "function composition" takes two functions, f and g, and creates a function, h = g f, such that h(x) = g. This process involves applying the function g to the outcome of applying the function f to x. When the result of one function is utilized as the input for another, this is known as a composite function. The function f g (x) fg(x) fg(x) fg(x), also known as "f of g of x" or "f g fg fg of x," is the composition of the two functions if we have a function f and another function g.
f(f(x)) = [tex]\frac{x}{\sqrt{6} }[/tex]
f(x) = 3x^2
g(f(x)) = [tex]\frac{3x^2}{\sqrt{6} }[/tex]
g(x) = [tex]\sqrt{2x}[/tex]
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Question: 33 of 39 Lesson 17
Using the info given, solve for the missing value of the right triangle. Round each angle to the nearest degree, each length to the nearest tenth, & each trigonometric value to four decimal places, if necessary.
tan θ = 0.7536
Hypotenuse = 29 miles
Opposite side = ?
Choice 'A' opp = 13.7 miles
Choice 'B' opp = 15.2 miles
Choice 'C' opp = 12.4 miles
Choice 'D' opp = 17.5 miles
Answer:
17.5 miles
Step-by-step explanation:
right!!
7 - 13a = 27 solve for A
Answer:
a = -20/13
Step-by-step explanation:
7 - 13a = 27
-13a = 20
a = -20/13
Let's check
7 - 13(-20/13) = 27
7 + 260/13 = 27
7 + 20 = 27
27 = 27
So, a = -20/13 is the correct answer!
A concave lear of focal length of 20cm forms an image 1/2 the size of the object .The object distance?
Answer:
60cm
Step-by-step explanation:
given:
focal length (f) = 20cm
image height (v) = ½u
object height (u) = ?
(1÷v) + (1÷u) = (1÷20)
(1÷(½u)) + (1÷u) = (1÷20)
(2÷u) + (1÷u) = (1÷20)
(3÷u) = (1÷20)
u = 20 × 3
u = 60cm
Draw the following figure in your note book and find the perimeter or circumference show your solution.
1.) Triangle : s = 6cm ; P=
2.) Square : s = 7 cm ; P =
3.) Rectangle = W = 4cm , L = 8 cm ; P =
4.) Regular Heptagon : s = 3cm ; P =
5.) Circle : r = 12cm ; C =
1)Triangle : s = 6cm ; P= 18 cm
2.) Square : s = 7 cm ; P = 28 cm
3.) Rectangle = W = 4cm , L = 8 cm ; P = 24cm
4.) Regular Heptagon : s = 3cm ; P = 21 cm
5.) Circle : r = 12cm ; C = 24∏ cm.
What is circumference?
The circumference of a circle or ellipse in geometry is its perimeter. That is, if the circle were opened up and straightened out to a line segment, the circumference would be the length of the arc. The curve length around any closed figure is more often referred to as the perimeter.
Given that the length of each side of a triangle is 6 cm.
The perimeter of an equilateral triangle is 3a, where a is the length of the side of the equilateral triangle.
The perimeter of the triangle is 3 × 6 = 18 cm
The length of side of a square is 7 cm.
The perimeter of a square is 4a, where a is the length of the side of the square.
The perimeter of the square is 4 × 7 = 28 cm.
The length and breadth of a rectangle is W = 4 cm and L = 8 cm.
The perimeter of a rectangle is 2(L+ W)
The perimeter of the rectangle is = 2(8 + 4) = 2 × 12 =24 cm
The perimeter of Regular Heptagon is 7a, where a is the length of the side of the Regular Heptagon.
The perimeter of a Regular Heptagon is (7 × 3) = 21 cm
The perimeter of a circle with a radius r is 2∏r.
The perimeter of the circle is 2∏ × 12 = 24∏ cm.
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Which TWO scenarios can be represented by a ratio of 4 : 5?
I NEED AN ANSWER ASAP PLEASE
The two scenarios that can be represented by a ratio 4:5 are
1. The ratio of fiction books to the non fiction books, if there are 4 fiction books to 5 non fiction books
2. The ratio of marker to crayon , if there are 4 markers and 5 crayons. ( option A and D)
What is ratio?A ratio is an ordered pair of numbers a and b, written a / b where b does not equal 0. A proportion is an equation in which two ratios are set equal to each other. For example, if there is 1 boy and 3 girls you could write the ratio as: 1 : 3 (for every one boy there are 3 girls) 1 / 4 are boys and 3 / 4 are girls.
For a scenario that will give ratio of 4:5, it means the first entity will be 4 and the second entity will be 5.
Therefore the two statements that obey this in the option are
1. The ratio of fiction books to the non fiction books, if there are 4 fiction books to 5 non fiction books
2. The ratio of marker to crayon , if there are 4 markers and 5 crayons.
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Complete the two-way frequency table below, which shows the relationship between students who enroll in advanced algebra and physics in a particular high school. From a sample of 40 students, it is found that 29 are taking algebra, 14 are taking physics, and 5 are enrolled in both. How many students are enrolled in either algebra or physics?
Algebra Not in Algebra Total
Physics 5 9 14
Not in Physics 24 2 26
Total 29 11 40
it is found that 29 are taking algebra, 14 are taking physics, and 5 are enrolled in both using principle of inclusion-exclusion we can say 38 students are enrolled in either algebra or physics.
How to find the number of students enrolled in either algebra or physics?To find how many students are enrolled in either algebra or physics, you can use the principle of inclusion-exclusion, which states that the total number of elements in two sets can be found by adding the number of elements in each set and then subtracting the number of elements that are in both sets.
So, the number of students enrolled in either algebra or physics is:
29 (students enrolled in algebra) + 14 (students enrolled in physics) - 5 (students enrolled in both) = 38
So, 38 students are enrolled in either algebra or physics.
It is important to notice that in the table you provided is a two-way frequency table also known as a contingency table, it shows the relationship between two variables, in this case, Algebra and Physics and the frequencies of each combination.
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Simplify 3.5m(3m + 1.8) using the distributive property.
10.5m + 6.3m
10.5m + 1.8
10.5m2 + 6.3m
10.5m2 + 1.8
Answer:
3.5m(3m + 1.8)
10.5m^2+6.3m
Step-by-step explanation:
Davi, Gustavo, and Mariana each pack a rectangular blanket for their picnic. The measurements of their blankets are listed in the following table. If they want to use the blanket with the largest area for their picnic, which blanket should they choose?
Davi blanket your mom
The blanket that they should choose is the one for which the multiplication of dimensions result in the largest value.
How to calculate the area of a rectangle?The area of a rectangle of dimensions length and width is given by the multiplication of these dimensions, as follows:
Area = length x width.
Then, to obtain the area for each blanket, their dimensions must be multiplied.
Then the blankest with the greatest area is the one for which the multiplication of the dimensions will result in the largest value.
(applying the formula for the area of the rectangle).
Missing InformationThe problem is incomplete, as the dimensions were not given, hence the answer is given in general terms.
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Please help will mark Brainly
Answer:
x=4 and y=2
Step-by-step explanation:
You should use graph, point of intersection(for example point M(4,2) ) is solution
And we can conclude that x=4 and y=2
If an 8-foot pole casts a 6-foot shadow at the same time a nearby tree casts
a 33-foot shadow, how tall is the tree (in feet)?
Answer:
The tree is 44 feet
Step-by-step explanation:
[tex]\frac{8}{6}[/tex] is equivalent to [tex]\frac{4}{3}[/tex] (divide the numerator and denominator by 2)
[tex]\frac{4}{3}[/tex] = [tex]\frac{x}{33}[/tex]
3 x 1 = 33, so 4 x 11 = 44
Factor the expression using the GCF.
50+65h=
Greatest common factor (GCF) of 50 and 65 is 5.
How to find the GCF of 50 and 65?We will first find the prime factorization of 50 and 65. After we will calculate the factors of 50 and 65 and find the biggest common factor number .
Step-1: Prime Factorization of 50
Prime factors of 50 are 2, 5. Prime factorization of 50 in exponential form is:
50 = 21 × 52
Step-2: Prime Factorization of 65
Prime factors of 65 are 5, 13. Prime factorization of 65 in exponential form is:
65 = 51 × 131
Step-3: Factors of 50
1, 2, 5, 10, 25
Final Step: Biggest Common Factor Number
We found the factors and prime factorization of 50 and 65. The biggest common factor number is the GCF number.
So the greatest common factor 50 and 65 is 5.
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Solve the inequality -5<5y<15
Answer:
−1 < y < 3
Step-by-step explanation:
800 miles in 5 hours miles per hour
A particle moves with velocity function v(t) = −t2 + 5t − 3, with v measured in feet per second and t measured in seconds. Find the acceleration of the particle at time t = 3 seconds.
The acceleration of the particle is 1 foot per second square
How to determine the acceleration of the particle?From the question, we have the following parameters that can be used in our computation:
Velocity function v(t) = −t2 + 5t − 3
Express properly
So, we have
v(t) = -t² + 5t − 3
At time t = 3 seconds, we have
v(3) = -(3)² + 5(3) − 3
Evaluate
v(3) = 3
So, we have
Acceleration = v(3)/3
This gives
Acceleration = 3/3
Evaluate
Acceleration = 1 foot per second square
Hence, the acceleration is 1 foot per second square
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What is the range of the function with the graph given below ?
The graph in the question is a parabola that opens downwards.
What is function?A function is a block of organized, reusable code that is used to perform a single, related action. Functions provide better modularity for your application and a high degree of code reusing. As you already know, Python gives you many built-in functions like print(), etc. but you can also create your own functions. These functions are called user-defined functions.
This means that the range of the function is all real numbers less than or equal to the y-intercept of the parabola, which is 0 in this case. Therefore, the range of the function is all real numbers less than or equal to 0.
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-50 POINTS- if you guess you’ll be reported.
If P=(4,7) Find D2 (P)
You will be reported if you guess. The result is -1 if P=(4,7)on D2 (P). Consequently, P=(4,7) in D2 reports -1. (P).
What is the value of D2 (P)?Given p= (4,7)
The answer to 4 p+7 is 4(-2)+7=-8+7=-1
The value of the denominator (d2), a weighting factor, is depends on the control chart's subgroup size, n. Based on a subgroup size of 5, the value of d2 in the case is 2.326. Following is a brief list of the d2 values for other subgroup sizes.
The table of constants below contains the d2 value, which is determined by the subgroup size. The average moving range, or MR-bar, will be used if your subgroup size is one. Model No. The average range is 0.220, and the mean is 0.8057 (X-bar). The D2 function gives the sample range of n independent, normally distributed random variables with the same mean and a standard deviation of 1 the anticipated value.
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Segment
B
D
‾
BD
bisects
∠
A
B
C
∠ABC. Solve for
x
x. Round to the nearest tenth, if necessary. (Image not necessarily to scale.)
The value of x on the line segment and the triangle is 17.3 units
How to determine the value of xFrom the question, we have the following parameters that can be used in our computation:
A triangle (see attachment for the triangle)
Also from the question, we understand that:
BD bisects ∠ABC
Using the bisector theorem, we have
x/13 = 20/15
Multiply both sides of the equation by 13
So, we have the following representation
13 * x/13 = 20/15 * 13
Evaluate the products
So, we have the following representation
x = 20/15 * 13
Evaluate the other products
So, we have the following representation
x = 52/3
This gives
x = 17.3
Hence, the length x is 17.3 units
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The amount Y (in dollars) Of money in your savings account after X months is represented by the equation Y equals 12.5 X +100 a. graph the linear equation b. how many months will it take for you to save a total of $237.50[QUICK ITS HOMEWORK AND ITS LATE]
The graph of the linear equation is attached below. After 11 months, the total savings will be $237.50.
What is a saving account?
An account in a retail bank is a savings account. Common characteristics include having a finite number of withdrawals allowed, not having check or connected debit card facilities, having few transfer choices, and not being able to become overdrawn.
Given equation is
y = 12.5x + 100
To find points on the linear equation, putting x = 0, 1 and 2 in the given equation:
y(0) = (12.5 × 0) + 100
y(0) = 100
y(1) = (12.5 × (1)) + 100
y(1) = 12.5 + 100
y(1) = 112.5
y(2) = (12.5 × 2) + 100
y(2) = 25 + 100
y(2) = 125.
The points on the linear equation are (0,100), (1, 112.5), (2,125).
Plot the points and join the points to draw the line to get graph the linear equation.
Putting y = 237.50 in the given equation y = 12.5x + 100:
237.50 = 12.5x + 100
Subtract 100 from both sides:
237.50 - 100 = 12.5x + 100 - 100
137.50 = 12.5x
Divide both sides by 12.5:
x = 137.50/12.5
x = 11
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Solve this inequality for x.
Answer:
A. x ≥ 21[tex]\frac{2}{3}[/tex]
Step-by-step explanation:
81 - 1[tex]\frac{1}{5}[/tex] x ≤ 55
-1[tex]\frac{1}{5}[/tex] x ≤ 55-81
-[tex]\frac{6}{5 }[/tex] x ≤ -26
x ≥ -26(-[tex]\frac{5}{6}[/tex]) **flip the inequality when you divide by a negative number
x ≥ 21[tex]\frac{2}{3}[/tex]
On the first day of spring, an ențire field of flowering trees blossoms. The population of locusts consuming these flowers rapidly increases as the trees blossom. The relationship between the elapsed time, t, in days, since the beginning of spring, and the total number of locusts, Nday (t), is modeled by the following function: Nday (t) = 300.(1.2)^t
Complete the following sentence about the weekly rate of change in the locust population.
Round your answer to two decimal places.
Every week, the number of locusts grows by a factor of
Answer:
3.58
Step-by-step explanation:
You want to know the weekly growth factor if the daily growth factor is 1.2.
7 daysThe weekly growth factor will be the growth factor over 7 days:
(1.2)^7 ≈ 3.58
Every week, the number of locusts grows by a factor of 3.58.
__
Additional comment
The exponential model is ...
number = (initial number)(growth factor)^t
The period of time associated with the growth factor is the units associated with t. Since 1 week = 7 days, the multiplier for 7 days is ...
weekly growth factor = (daily growth factor)^7
<95141404393>
“Find 3.4 x 2.6 by drawing an area diagram. Show your reason (I need help on this-
The area is 8.84 sq. units
What is area?Area is defined as the total space taken up by a flat (2-D) surface or shape of an object.
To find the area we will find the product of 3.4 x 2.6, we can break each length into its base-ten units,
3.4 = 3+0.4
2.6 = 2+0.6
We can rewrite the product and solve it,
= (3+0.4) × (2+0.6)
= (3+0.4) × 2 + (3+0.4) × 0.6
= 3 × 2 + 0.4 × 2 + 3 × 0.6 + 0.4 × 0.6
This expression represents the partial product, each of the expression gives the area of sub rectangles (A, B, C and D). the sum of the partial product will give the area of the main rectangle.
Therefore,
3 × 2 + 0.4 × 2 + 3 × 0.6 + 0.4 × 0.6
= 6+0.8+1.8+0.24
= 8.84
Hence, the required area is 8.84 sq. units.
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Please help I was sick and missed out on class thank you.
On solving the value of provided question we can say that - the value of the slope intercept y = -3.
what is slope intercept?The point on the y-axis where the slope of the line passes is known as the intersection point in mathematics. the location on a line or curve where the y-axis crosses that point. This is demonstrated by putting y = mx+c as the equation for the straight line, where m denotes the slope and c the y-intercept. In the intercept form of the equation, the slope (m) and y-intercept (b) of the line are highlighted. The slope is m, and the y-intercept is b for equations in the intercept form (y=mx+b). Additionally, certain equations may be recast to seem like slope intercepts. For instance, if y=x is rewritten as y=1x+0, the slope becomes 1 and the y-intercept becomes 0.
as we can see from graph that,
line passes through origin, so x= 0
the, y = -5x - 3
y = -3
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A raffle for 4 prizes is taking place. each person had to purchase a ticket to enter the raffle. If Lebron bought 4 tickets, Kobe 6 tickets, Jordan 7 and Diana Taurasi 7.
Round answer to the nearest thousandths (3 decimal places)
A). If the ticket gets put back into the raffle after each selections, what is the probability that Kobe wins the first prize and Dianna wins the second?
B) If each ticket can only be used once what is the probability that Kenton win first two prizes
C) What is the probability that Oberon wins first prize, Kobe the second, Jordan the 3rd and Diana the 4th, without replacement?
Raffles are chance-based contests in which participants compete to win exciting prizes.
How does a raffle work?To participate, all you need is a ticket with a number on it. Following the sale of all tickets, a drawing is conducted during which a random selection of tickets is made. If you chance to have the winning ticket, congratulations! a lot of engagement.
Raffles elicit a great deal of interest and support because people enjoy playing games of chance, especially when they have the possibility to win a significant prize.
high income. Your organisation has a strong possibility of making some big money from ticket sales if engagement is high!
low price. A virtual free raffle can be found online! A virtual raffle is the most cost-effective type of fundraising because you won't need to print actual tickets, reserve a location for the drawing, or buy refreshments.
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In a equation is it true that when a variable is alone you have to add a number 1 to it?
I’m wondering since I have to add it to my notes.
a particular dress requires 3 1/4 yards of fabric for manufacturing. if the matching jacket requires 1/6 yards less fabric, how much fabric is needed for both pieces?
Answer: The matching jacket requires 1/6 yards less fabric than the dress, which is 3 1/4 - 1/6 = 3 1/4 - 2/12 = 3 1/4 - 1/6 = 3 1/4 - 1/6 = 3 1/4 - 1/6 = 3 3/12 yards of fabric.
To add these two amounts of fabric together, you need to add the yards and the inches separately.
For the dress: 3 1/4 yards = 3 + 1/4 = 3 + 0.25 = 3.25
For the jacket: 3 3/12 yards = 3 + 3/12 = 3 + 0.25 = 3.25
So, for both pieces, the required fabric is 3.25 + 3.25 = 6.5 yards
Step-by-step explanation:
Which equations are true for x = –2 and x = 2? Select two options x2 – 4 = 0 x2 = –4 3x2 + 12 = 0 4x2 = 16 2(x – 2)2 = 0
The equations that are true for x = –2 and x = 2 are:
x^2-4=0 and 4x^2 = 16
How can the equation be known?We can determine the equations that are true for x = –2 and x = 2 by testing the given options:
After testing the options option 1 ; x^2-4=0 putting x = 2 or -2 into the equation will give zero.
(2^)2-4=0
(-2)^2-4=0
Then option 4: 4x^2 = 16
4(2)^2 = 16
4(-2)^2 = 16
Therefore, option 1st and 4th are correct.
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Show that 100 divided by 20 is 5, using at least five daily life examples.
The 5 life examples are:
You have 100 pieces of candy and you want to divide them equally among 20 people. Each person would get 100/20 = 5 pieces of candy.A pizza is cut into 100 slices, and you want to divide it evenly among 20 people. Each person would get 100/20 = 5 slices of pizza.You have 100 dollars and you want to spend them on 20 items at the same price. Each item would cost 100/20 = 5 dollars.You want to divide a 100-minute task into 20 equal parts. Each part would take 100/20 = 5 minutes.You are scheduling 100 appointments in a day and you want to divide them into 20-hour blocks. Each block would have 100/20 = 5 appointments.What are the Life examples about?In all these life examples that are listed above, the number 100 is divided by 20 giving 5 as the result. which is said to be:
100/20
= 5.
Therefore, reason behind this is that the number 20, in these life examples, is a representative of a whole value and the number 5 represents the number of parts it is being divided into, so when you multiply 20 by 5, you get 100, which represents the total of these five parts. So, 100 is related to 20 in this context as the multiple of 20 and 5.
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For the equation f(x)=1.9(0.41)*, state the initial value C, the growth or decay factor a, and percent change R for each unit increase in x.
C=(Type an integer or a decimal.)
Initial value C is 1.9, Decay factor =0.41 and Growth factor = 0.59 when the function f(x)=1.9(0.41)ˣ.
Given that,
The equation f(x)=1.9(0.41)ˣ.
We have to state the initial value C, the growth or decay factor a, and percent change R for each unit increase in x.
We know that,
What is growth and decay?In order to translate their graphs over the 2D coordinate plane, I will offer the vertex form of an exponential equation for both the growth and decay functions.
In the case of growth, f(x) = a(1+r[tex])^{x-h}[/tex]+k, where b = 1+r
Decay is defined as f(x)=a(1-r)(x-h[tex])^{x-h}[/tex]+k, where b=1-r.
Consider the function f(x)=1.9(0.41)ˣ.
We write as
f(x)=1.9(1-0.59)ˣ
So, initial value C is 1.9
Decay factor =0.41
Growth factor = 0.59
Therefore, Initial value C is 1.9, Decay factor =0.41 and Growth factor = 0.59 when the function f(x)=1.9(0.41)ˣ.
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What is the value of the expression below when x=2x=2?
8x^2 +6x-8
8x
2
+6x−8
The value of the expression 8x² + 6x - 8 below when x=2 is 36.
The value of the expression when x = 2The expression can be evaluated by following the steps below:
8x² + 6x - 8 in x = 2 means that the variable x will be replaced by the given number which is 2.
8*2² + 6*2 - 8
8*4 + 12 - 8
32 + 16 - 8 = 36
This therefore means that when x= 2 in 8x² + 6x - 8 , the value gotten will be 36.
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