Answer:
400.7886829 rad/s
Explanation:
First we have to turn our 0.35 rev/s into rad/s using the equation
(Xrev/s)*2pi=Xrad/s we can plug in .35*2pi=.7pi rad/s
Now we can us the equation m_1*v_1*r_1^2=m_1*v_2*r_2^2 we can plug in the given. Because the mass remains the same we can cross it off of both sides giving us just: v_1*r_1^2=v_2*r_2^2
(.7pi)*(.54)^2=(v_2)*(.04)^2
(.20412pi)=(v_2)*(.0016) [.20412pi=.6412618925]
then using division on both sides we get
(.6412618925/.0016)=v_2=400.79rad/s(This answer is rounded to the nearest hundreth)
See you in Mr.K's class tomorrow! -Ruben
The marble's angular speed as it passes through the neck of the funnel is 36.225 rev/s.
What is the conservation of angular momentum?The conservation of angular momentum states that the angular momentum of an object is conserved when there is no external torque acting on it.
We have,
The marble is rolling in a large circular orbit around the rim of the funnel. The angular momentum of the marble can be expressed as:
L = Iω
where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.
Now,
Since the marble is rolling in a circular orbit around the rim of the funnel, we can approximate its moment of inertia as a point mass rotating around a fixed axis.
The moment of inertia of a point mass rotating around an axis is given by:
I = mr²
where m is the mass of the marble and r is the radius of the circular orbit.
At the top of the funnel,
The radius of the circular orbit is equal to the internal radius of the funnel,
r = 0.54 m.
At the bottom of the funnel,
The radius of the circular orbit is equal to the internal radius of the funnel's neck,
r = 0.040 m.
Now,
Using the conservation of angular momentum,
We can equate the angular momentum of the marble at the top of the funnel to the angular momentum of the marble at the bottom of the funnel.
[tex]I_1W_1 = 1_2W_2[/tex]
Substituting the expressions for the moment of inertia at the top and bottom of the funnel, and solving for [tex]W_2[/tex].
[tex]W_2[/tex] = [tex](I_1/I_2)[/tex][tex]W_1[/tex]
[tex]W_2[/tex] = (m[tex]r_1^2[/tex])/(m[tex]r_2^2[/tex]) [tex]W_1[/tex]
[tex]W_2[/tex] = (r1/r2)^2[tex]W_1[/tex]
[tex]W_2[/tex] = (0.54/0.040)²(0.35 rev/s)
[tex]W_2[/tex] = 36.225 rev/s
Therefore,
The marble's angular speed as it passes through the neck of the funnel is 36.225 rev/s.
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What is a material that electricity cannot flow through called?
Answer:
Things that electricity cant flow through are called insulators.
10. A student walking in the hallway sees a spill. When this happens, they slow down from 8.3 ft/s to a pace of 3.3 ft/s in 4 seconds. What is their acceleration?
Answer:
Acceleration = -1.33ft/s²
Explanation:
Given the following data;
Initial velocity = 3.3ft/s
Final velocity = 3.3ft/s
Time, t = 4s
To find the acceleration;
In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.
This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.
Mathematically, acceleration is given by the equation;
[tex]Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}[/tex]
Where,
a is acceleration measured in [tex]ms^{-2}[/tex]v and u is final and initial velocity respectively, measured in [tex]ms^{-1}[/tex]t is time measured in seconds.Substituting into the equation, we have;
[tex]a = \frac{3.3 - 8.3}{4}[/tex]
[tex]a = \frac{-5.3}{4}[/tex]
Acceleration = -1.33ft/s²
The value is negative because the final velocity is lesser than the initial velocity i.e the student is decelerating.
A roller coaster has a loop in which the centripetal acceleration equals 9.8m/s2 . Of the tangential speed of the roller coaster cars is 15-7 m/s
Answer:
25.152mExplanation:
Compete question;
A roller coaster has a loop in which the centripetal acceleration equals 9.8m/s² . If the tangential speed of the roller coaster cars is 15.7 m/s, find its radius.
centripetal acceleration a = v²/r
v is the tangential speed
r is the radius
Given
v = 15.7m/s
a = 9.8m/s²
9.8 = 15.7²/r
9.8r = 15.7²
r = 15.7²/9.8
r = 246.49/9.8
r = 25.152m
Hence the radius of the coaster is 25.152m
Determine the increase in volume of 100m3 of mercury when it's temperature change from 10c to 45c the linear expansion coefficient is 6 x 10-5
Answer:
0.63m
Explanation:
Volume expansivity = change in volume/original volume×temp change
Volume expansivity p = 3x
p = ∆V/V∆t
x is the linear expansivity
Given
x = 6 x 10^-4
p = 3x
p = 3(6 x 10^-5)
p = 18×10^-5
Volume = 100m³
∆t = 45-10 = 35°C
Required
Change in volume ∆V
Substitute the given values into the formula
18×10^-5 = ∆V/100(35)
18×10^-5 =∆V/3500
∆V = 3500×0.00018
∆V = 0.63m
Hence the increase in volume of the Mercury is 0.63n
Antarctica's landscape is proof that ____.
A. a large amount of water does not make a continent habitable
B. it has the highest levels of precipitation in the world
C. humans cannot survive at extremely high altitudes
D. a continent covered in snow can be one of the driest on earth
Answer:
The answer to the equation is B hope this helps:)
Answer:
D. a continent covered in snow can be one of the driest on earth
Explanation:
Since the universe is infinite, the probability of events and reoccurrence is infinite. So that means that there is a chance, if not 100% chance, that SOMEWHERE there is another earth, with another you, living the same life, at the same time. What are your thoughts about this??? that's so crazy to me
Answer:
That insane it might be true because a planet sometimes quoted to be an Earth 2.0 or Earth's Cousin based on its characteristics; also known by its Kepler Object of Interest designation KOI-7016.01) is an exoplanet orbiting the Sun-like star Kepler-452 about 1,402 light-years (430 pc) from Earth in the constellation Cygnus.
Explanation:
A pitcher throws an overhand fastball from an approximate height of 2.65 m and at an angle of 2.5° below horizontal. The catcher catches the ball high in the strike zone, at a height of 1.02 m above the ground. If the pitcher's mound and home plate are 18.5 m apart, what is the initial velocity of the pitch?
Answer:
The initial velocity of the pitch is approximately 36.5 m/s
Explanation:
The given parameters of the thrown fastball are;
The height at which the pitcher throws the fastball, h₁ = 2.65 m
The angle direction in which the ball is thrown, θ = 2.5° below the horizontal
The height above the ground the catcher catches the ball, h₂ = 1.02 m
The distance between the pitcher's mound and the home plate = 18.5 m
Let 'u' represent the initial velocity of the pitch
From h = [tex]u_y[/tex]·t + 1/2·g·t², we have;
[tex]u_y[/tex] = The vertical velocity = u·sin(θ) = u·sin(2.5°)
h = 2.65 m - 1.02 m = 1.63 m
uₓ·t = u·cos(θ) = u·cos(2.5°) × t = 18.5 m
∴ t = 18.5 m/(u·cos(2.5°))
∴ h = [tex]u_y[/tex]·t + 1/2·g·t² = (u·sin(2.5°))×(18.5/(u·cos(2.5°))) + 1/2·g·t²
1.63 = 8.5·tan(2.5°) + 1/2 × 9.8 × t²
t² = (1.63 - 8.5·tan(2.5°))/(1/2 × 9.8) = 0.25691469087
t = √(0.25691469087) ≈ 0.50686752763
t ≈ 0.50686752763 seconds
u = 18.5 m/(t·cos(2.5°)) = 18.5 m/(0.50686752763 s × cos(2.5°)) = 36.5334603 m/s ≈ 36.5 m/s
The initial velocity of the pitch = u ≈ 36.5 m/s.
what is sound produced by
Answer:
Sound is produced by an object vibrating and creating a pressure wave.
Explanation:
What is the gravitational potential energy of a 250 kg rock on top of a 200 meter cliff?
Answer:
500000 approx........
...
A child bouncing a ball. Which law of motion does the situation describe?
A pizza delivery person drives 3 miles North then 5 miles West and then 3 miles South to deliver a pizza. What is the distance driven?
A. 45 miles
B. 5 miles west
C. 8 miles
D. 11 miles
Answer:
The answer is...
Explanation:
If your counting the miles he went from the Pizza place and back it would be 22 if you were counting just the amount of miles he went from the pizza place then it would be D, or 11. Hope this helps.
:)
can u answer the two questions on the paper? (use the pictures for help obvi)
Answer:
1) E has the greatest mass because it has the most dots
2) B has the smallest mass because it has less dots.
We have a 10 m resistance wire of the isachrom 60 type. The resistance of this wire is 5.65 Ω / m at 20 ° C. The wire has a diameter of 0.50 mm.
a. Calculate the resistivity of isachrom 60 at 20 ° C.
Answer:
[tex]\rho=1.10\times 10^{-7}\ \Omega[/tex]
Explanation:
Given that,
The length of the resistance wire, l = 10 m\
The resistance of this wire is 5.65 Ω/m
The diameter of the wire, d = 0.5 mm
Radius, r = 0.25 mm = 0.00025 m
We need to find the resistivity of isachrom 60 at 20°C. The formula for the resistance of a wire is given by :
[tex]R=\rho\dfrac{l}{A}\\\\\rho=\dfrac{RA}{l}\\\\\rho=\dfrac{R\pi r^2}{l}\\\\\rho=\dfrac{5.65\times \pi \times (0.00025)^2}{10}\\\\\rho=1.10\times 10^{-7}\ \Omega[/tex]
The resistivity of the wire is [tex]1.10\times 10^{-7}\ \Omega[/tex].
Which scenario is the best example of matter absorbing energy from a wave?
A. Sound waves a echoing off smooth surface
B. Light shining onto a mirror
C. Ocean waves hitting a concrete barrier that reduces their energy
D. Sunlight reflecting from a white chalk line on a sidewalk
Ocean waves hitting a concrete barrier that reduces their energy, scenario is the best example of matter absorbing energy from a wave.
Common examples of absorption of wave energy: waves hitting the beach usually give most of their energy to the sand. sunlight landing on a face is mostly absorbed, warming the skin. sound waves hitting thick curtains give up their energy and the sound is muffled.
What is wave ?"A wave is a disturbance in a medium that carries energy without a net movement of particles. It may take the form of elastic deformation, a variation of pressure, electric or magnetic intensity, electric potential, or temperature."
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A train travels 100 km east and then 75 km west. What is the magnitude of
its displacement?
Answer:
displacement = 100 - 75 = 25 km east
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Fill in the blanks
Cobalt has 27 protons, 32 neutrons and 27 electrons. What is it's atomic mass?
Answer:
58.933195 u or 59 u
Explanation:
Atomic mass of cobalt is 58.933195 u
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The diagram below shows four parts of a wooden pencil.
Wood body
Plastic grip
Rubber eraser
Metal band
Of the labeled parts of the pencil, which is the best conductor
of electricity?
A. Wood body
B. Metal band
C. Plastic grip
D. Rubber eraser
what is fast carbon and what is slow carbon
please dont search it up need this right now extra points!
Answer:
the fast carbon cycle follows the movement of carbon through living (biotic) components of an ecosystem. This occurs faster because life moves more quickly. The fast carbon cycle focuses primarily on the biosphere, while the slow carbon cycle is more involved with the hydrosphere, lithosphere and atmosphere.
Explanation:
Car A has twice the mass of Car B; both travel at the same speed. Compared to Car B. Car A has:
o the same the energy
o four times the energy
Otwice the energy
one-half the energy
one-fourth the energy
Answer:
Car A has twice the energy of car B.
Explanation:
The kinetic energy of an object is given by :
[tex]K=\dfrac{1}{2}mv^2[/tex]
Where
m is the mass
v is the speed of the object
Car A has twice the mass of Car B. Both travel at the same speed i.e.
[tex]m_A=2m_B[/tex]
So,
[tex]\dfrac{K_A}{K_B}=\dfrac{(1/2)m_Av^2}{(1/2)m_Bv^2}\\\\=\dfrac{2m_B}{m_B}\\\\\dfrac{K_A}{K_B}=2\\\\K_A=2\times K_B[/tex]
So, the kinetic energy of car A is twice of the kinetic energy of car B.
Answer:
Car A has twice the energy
Explanation:
2. A bullet was shot by a gun with an initial speed of 260 m/s and is fired at an angle of 30 to the ground. a. How much is the value Vy at the top of the bullet's trajectory? b. Calculate the time taken by the bullet to reach its maximum altitude. c. Deduce the total time taken by the bullet in the air. d. Calculate the range of the bullet.
Answer:
Explanation:
a )
the value Vy at the top of the bullet's trajectory will be zero . At the top , only the horizontal component Vx will exist .
b )
At the top Vy = 0
initial velocity will have vertical component = 260 sin30 = 130 m /s
acceleration = - g = - 9.8
v = u - gt
o = 130 - 9.8 t
t = 13.26 s .
c )
Total time = Time of ascent + time of descent
= 13.26 + 13.26 = 26.52 s
d )
Range R = u² sin2Ф / g , where u is initial velocity , Ф is angle of throw , g is acceleration due to gravity .
R = 260² sin 2 x 30 / 9.8
= 5973.8 m .
how do you increase the ideal mechanical advantage of an inclined plane?
Answer:
The mechanical advantage increases as the slope of the incline decreases. But the load will then have to be moved a greater distance. The ideal mechanical advantage (IMA) of an inclined plane is the length of the incline divided by the vertical rise, the so-called run-to-rise ratio.
Explanation:
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It is fine to wear maong pants when preforming physical activity write true or false
A rock is thrown horizontally off a cliff with an initial velocity of 15 m/s. How high was the cliff if the rock lands 22 m from the base of the cliff?
Answer:
22 m
Explanation:
Answer:
cliff height = 10.55 m
Explanation:
Remarks
This is one of those questions that defies belief. The final vertical velocity is the same as if you just dropped the rock, which is amazing.Another amazing fact is that the horizontal speed has no acceleration. And amazing fact number three is the the vertical initial speed is 0.And finally, the time taken to go horizontally = time to go vertically.Solution
Time
So the time taken is d = r * t
Remember, this formula can only be used when there is no acceleration.
d = 22 meters
r = 15 m/s
t = ?
t = d / r
t = 22 / 15
t = 1.467
Height of the Cliff
vi = 0 (vertially)
a = 9.8 m/s^2
t = 1.467 seconds The time horizontally and vertically is the same.
d = ?
Formula
d = vi*t + 1/2 a t^2
Solution
d = 0 + 1/2 * 9.8 * 1.467^2
d = 10.55 meters.
Which part of the drum (Instrument)vibrates when it produces sound?
Answer:
Striking the head of the drum changes its shape and compresses the air inside the shell. the compressed air presses on the bottom head and changes its shape. then these changes are transmitted to the drum shell and reflected back and this action is repeated created a vibration.
Explanation:
Hope this helped Mark BRAINLEST!!!
A tugboat is pulling a barge into a harbor. The barge is exerting a force of 3000 N against the tugboat. Which force would most likely allow the tugboat to move the barge into the harbor? –4500 N –2500 N 2500 N 4500 N
Answer:
the correct one is F’= 4500 N
Explanation:
To solve this problem we must use Newton's second law
where F₁ is the force of the barge F₁ = 3000N and the force of the tugboat is F '
F '- F₁ = m a
we substitute
F '- 3000 = m a
the mass is always a positive quantity, therefore if we want the tug to pull the barge
F ’-3000> 0
when you check it, you respect the correct one is F’= 4500 N
Answer:
The answer is -4500 N
Explanation:
I just got it right on the test
need help its do today
Answer:
the answers for the first 3 are
C
A
C
Explanation:
please help me answer this
A radio transfers 270 j of energy electrically, 94.5 j is transferred by sound. Work out the efficiency of this radio. Give your answer as a decimal
Answer:
35%
Explanation:
Given data
Amount of energy transferred (Input) = 270J
Amount of energy converted to sound (Output)= 94.5J
Efficiency = output/input*100
Efficiency= 94.5/270*100
Efficiency=0.35*100
Efficiency=35%
Hence the efficiency is 35%
TRUE OR FALSE
1. TRUE OR FALSE: The higher the frequency, the closer the waves are together and the LOWER the energy carried by the waves will be.
2. TRUE OR FALSE: The greater the force that produces a wave, the greater the amplitude of the wave and the greater the energy carried by the wave.
3. TRUE OR FALSE: In a transverse wave the higher the wave, the LOWER the amplitude
4. Wavelength is a measure of the distance from the crest on one wave to the crest on the very next wave.
5. TRUE OR FALSE: Speed is a measure of the distance a wave travels in an amount of time
6. TRUE OR FALSE: As a wave enters a different medium, the wave’s speed changes. Waves travel at different speeds in different media
7. TRUE OR FALSE: The highest point of a transverse wave is the crest and the lowest point is called a trough.
Answer:
Explanation:
true true fauls true fauls fauls
1 . The higher the frequency, the closer the waves are together and the LOWER the energy carried by the waves will be. FALSE
2. The greater the force that produces a wave, the greater the amplitude of the wave and the greater the energy carried by the wave. TRUE
3. In a transverse wave the higher the wave, the LOWER the amplitude FALSE
4.Wavelength is a measure of the distance from the crest on one wave to the crest on the very next wave, TRUE
5. Speed is a measure of the distance a wave travels in an amount of time TRUE
6. As a wave enters a different medium, the wave’s speed changes. Waves travel at different speeds in different media TRUE
7. The highest point of a transverse wave is the crest and the lowest point is called a trough. TRUE
What is Wave ?A wave is a disturbance in a medium that carries energy and as well as momentum. Energy can be transferred in the form of wave in the medium. there are two types of wave,
longitudinal wave : in which, vibration of the medium (particle) is parallel to propagation of the wave as shown in the fig.1. Sound wave is a longitudinal wave.
Transverse wave : in which, vibration of the medium (particle) is perpendicular to propagation of the wave as shown in the fig.2. Light wave is a longitudinal wave.
1. E = hυ where υ is a frequency which shows direct relation between Energy E and frequency υ. Hence it is false.
2. True
3. In a transverse wave the higher the crest in the wave, the higher the amplitude. FALSE
4. True
5. True, Speed = Distance÷Time
6. due to change in refractive index, velocity changes TRUE
7.True
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An airplane moving horizontally at 150 m/s drops a package from an altitude is 490 m. How long does it
take the package to reach the ground? How far, horizontally, from the spot over which it was dropped
does the package land?
Answer:
640
Explanation:
cause you should just add the 2
It takes 10 second the package to reach the ground.
The package reaches the ground after 10 second and it was dropped 1500 m far from the package landing.
Given parameters:
Altitude of the plane; h = 490 m.
Initial horizontal velocity of the plane; u = 150 m/s.
We have to find; time taken by the package to reach the ground: t =?
And, horizontal distance covered by the package before land; d = ?
We know that a free falling object has acceleration equal to acceleration due to gravity = g = 9.8 m/s².
So,
h = 1/2gt²
⇒ t = √(2h/g) = √(2×490/9.8) second = 10 second.
In this time,
horizontal distance covered by the package before land; d = ut
= 150 m/s × 10 s
= 1500 m.
Hence, the package reaches the ground after 10 second and it was dropped 1500 m far from the package landing.
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