A battery is charged. The percentage of the battery’s capacity that is charged as a function of time (in minutes) is graphed.

a) The Name of the angle of elevation is ∠c = 83.3°

b) The Name of the Hypotenuse side is AC

c) The Name of the Opposite side is AB

The angle formed between the line of sight and the horizontal is known as the angle of elevation. The angle created is an angle of elevation if the line of sight is upward from the horizontal line.

We can use the tangent ratio to determine the angle of elevation:

tan(angle of elevation) = opposite/adjacent

tan(angle of elevation) = 29.25/4.75

tan(angle of elevation) = 6.157

The inverse tangent (tan⁻¹) both sides, we obtain:

angle of elevation = tan⁻¹(6.157)

Using a calculator, we get:

angle of elevation ≈ 81.3 degrees (rounded to the nearest tenth)

The elevation angle is roughly 81.3 degrees.

d) The Name of the Adjacent side is BC

e) The Trig Ratio I will be using is Tan θ = Sin θ/Cos θ because we are  

   given the side Opposite Side & Adjacent Side

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To answer the question, this equation has only one solution, which is x = 4.

An equation is a mathematical statement that shows the equality between two expressions. It usually consists of two sides, the left-hand side (LHS) and the right-hand side (RHS), separated by an equal sign (=).

The expressions on both sides can contain variables, constants, and mathematical operations such as addition (+), subtraction (-), multiplication (*), division (/), exponentiation (^), and others. The goal of an equation is to find the values of the variables that make both sides equal.

by the question.

Let's start by setting up the equation:

[tex]1/2x + 8 = 14 - x[/tex]

where x is the number, we're trying to find.

Now let's simplify the equation by combining like terms:

[tex]3/2x + 8 = 14[/tex]

Subtracting 8 from both sides:

[tex]3/2x = 6[/tex]

Multiplying both sides by 2/3:

[tex]x = 4[/tex]

So, the solution to the equation is x = 4.

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The induced emf in a region of the brain when a conducting loop is held near a person's head and the current in the loop is changed rapidly, is equal to -525 V.

The induced emf can be calculated using Faraday's law of electromagnetic induction, which states that the emf induced in a loop of wire is equal to the rate of change of magnetic flux through the loop.

The magnetic flux (Φ) is equal to the product of the magnetic field (B) and the area (A) through which it passes. Therefore, the induced emf (ε) is given by:

ε = -dΦ/dt ⇒ -B dA/dt.

Where the negative sign indicates that the emf is induced in a direction that opposes the change in magnetic flux.

In this problem, the magnetic field changes at a rate of 3.00 × 10^4 T/s over an area of 1.75 × 10^-2 m^2. Therefore, the induced emf is:
Plugging in our values, we get:
E = (-3.00 10^4 T/s)(1.75 10^(-2) m^2)/(1 s)
E = -525 V

Therefore, the induced emf, in this case, is -525 V. Here, the negative sign shows that the emf is induced in a direction that opposes the change in magnetic flux

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When one of the coin is flipped it lands on heads with probability 0.6 and when the other is flipped, it lands on heads with probability 0.3, then the probability that the coin lands on heads is 0.45 and the coin lands on heads but the probability that the chosen coin was the one that lands on heads with probability 0.6 is 0.67.

a) The probability of getting heads, we can use the law of total probability.

There are two coins, and each has a probability of landing on heads. So we can calculate the probability of getting heads by weighting each coin's probability by its probability of being chosen.

Therefore,

P(heads) = P(heads from coin 1) * P(choose coin 1) + P(heads from coin 2) * P(choose coin 2)

Plugging in the values, we have:

P(heads) = 0.6 * 0.5 + 0.3 * 0.5 = 0.45

Therefore, the probability of getting heads is 0.45.

b) The probability that the chosen coin was the one that lands on heads with probability 0.6, given that the coin lands on heads, we need to use Bayes' theorem. Specifically, we have:

P(choose coin 1 | heads) = P(heads from coin 1 | choose coin 1) * P(choose coin 1) / P(heads)

Plugging in the values, we have:

P(choose coin 1 | heads) = 0.6 * 0.5 / 0.45 = 0.67

Therefore, the probability that the chosen coin was the one that lands on heads with probability 0.6, given that the coin lands on heads, is 0.67.

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Answer:

Step-by-step explanation:

To write 0.246 as a fraction in simplest form, we need to remove the decimal and reduce the fraction to its lowest terms.

Step 1: Write 0.246 as the fraction 246/1000.

(Note: We get the denominator 1000 by counting the number of decimal places after the 6 in 0.246.)

Step 2: Simplify the fraction by dividing both the numerator and denominator by the greatest common factor.

The greatest common factor (GCF) of 246 and 1000 is 2.

246/2 = 123

1000/2 = 500

Therefore, 0.246 written as a fraction in simplest form is 123/500.

Answer:if I’m correct I think you would put it like this 123/500

It can’t be reduced because the denominator is at it’s simplest form

Step-by-step explanation:

By using the Lagrange multipliers, the two points on the cone that is closest to (14, 8, 0) are:

(7, 4, √65) and (7, 4, -√65)

We want to minimize the distance between the point (14, 8, 0) and the points on the cone z^2 = x^2 + y^2. The distance squared between two points (x_1, y_1, z_1) and (x_2, y_2, z_2) is given by:

d^2 = (x2 - x1)^2 + (y2 - y1)^2 + (z2 - z1)^2

In our case, we want to minimize the distance squared between (14, 8, 0) and a point (x, y, z) on the cone z^2 = x^2 + y^2:

d^2 = (x - 14)^2 + (y - 8)^2 + z^2

Subject to the constraint z^2 = x^2 + y^2. We can use Lagrange multipliers to solve this constrained optimization problem. Let L be the Lagrangian:

L = (x - 14)^2 + (y - 8)^2 + z^2 - λ(z^2 - x^2 - y^2)

Taking the partial derivatives of L with respect to x, y, z, and λ, and setting them to zero, we get:

2(x - 14) - 2λx = 0.....(1)

2(y - 8) - 2λy = 0.....(2)

2z - 2λz = 0.....(3)

z^2 - x^2 - y^2 = 0.....(4)

Simplifying the third equation, we get z(1 - λ) = 0. Since we want to find points where z is not zero, we must have λ = 1. Then, from the first two equations, we get x = 7 and y = 4. Substituting these values into the fourth equation, we get:

z^2 = x^2 + y^2 = 65

So the two points on the cone that is closest to (14, 8, 0) by using  Lagrange multipliers are:

(7, 4, √65) and (7, 4, -√65)

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In solving the given question, we can say that ∠ZEFI and ∠ZJIK are equal parallel lines  by  co-exterior angles property.

Geometry parallel lines are coplanar infinite lines that do not intersect anywhere. In a given three-dimensional space, parallel faces are faces that never intersect. Curves with a constant minimum distance between them and no tangents or intersections are said to be parallel. Two lines that lie in the same plane, are equally spaced, and never intersect are called parallel lines in geometry. Can be applied horizontally or vertically. Parallel lines are found in everyday objects such as railroad tracks, rows of books, and crosswalks.  

∠ZHIK and ∠ZEFI are equal by alternative angles property.

∠ZGFD and ∠ZEFD are equal by co-interior angles property.

∠ZGFD and ∠ZEFI are equal by interior alt. angles property.

∠ZEFI and ∠ZJIK are equal by  co-exterior angles property.

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Answer:

Step-by-step explanation:

Find ∠1:

  ∠2 + ∠1 = 180            (angles on a straight line are supplementary)

  138 + ∠1 = 180

            ∠1 = 42°

Find ∠4:

  ∠4 =∠2 = 138°            (vertically opposite angles are equal)    

Find ∠3:

  ∠3 = ∠1 = 42°              (vertically opposite angles are equal)  

These expression is not true .

What is a mathematical expression?

A mathematical expression is a sentence that consists of at least two numbers or variables, the expression itself, at least one arithmetic operation, and the expression itself. Any one of the following mathematical operations could be used: addition, subtraction, multiplication, or division.

                                  For instance, the expression x + y is an expression with the addition operator placed between the terms x and y. Mathematicians utilize two different sorts of expressions: algebraic and numeric. Numeric expressions only contain numbers; algebraic expressions additionally incorporate variables.

-0.5(3x + 5) and -1.5x + 2.5 equivalent.

  by distributing the 0.5  = -1.5x + 2.5

                                       = -1.5x + 2.5

                       = 0.5(3*2 + 5 )

                     = - 1.5 * 2 + 2.5

                     = - 3 - 2.5  = -3 + 2.5

                         - 5. 5  = 0.5

this is not true. these expression is not true .

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The approximate probability that the mean credit card debt for a sample of 50 US households will exceed $7,500 is , based on a normal distribution with a mean of $7,115 and a standard deviation of $2,160.

What is the z-score formula?

The z-score formula is a statistical method used to calculate the standard deviation of a raw score or data point relative to the mean of the group of raw scores or data points. It is given as:

[tex]z = \frac{x - \mu}{\sigma}[/tex]

where z is the z-score, x is raw score, μ is the mean, and σ is the standard deviation.

The approximate probability can be calculated as follows:

First, find the standard error of the mean: [tex]SE = \frac{\sigma}{\sqrt{n}}[/tex]

[tex]SE = \frac{2,160}{\sqrt{50}}\\\\SE = 305.39[/tex]

Secondly, find the z-score: [tex]z = \frac{\overline{x} - \mu}{SE}[/tex]

[tex]z = \frac{7,500 - 7,115}{305.39}\\\\z = 1.263[/tex]

The probability that a z-score will be greater than 1.263 is 0.1038 from the standard normal table or calculator.

Therefore, the approximate probability is 0.1038 or 10.38%.

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Answer:

Step-by-step explanation:

Refer to attached diagram

∠CAD = 180 - (110 + 35) = 35°    (angle sum triangle = 180°)

∠BCA = 180 -110 = 70°                 (straight angle = 180°)

∠BAC = 180 - (55 + 70) = 55°      (angle sum triangle = 180°)

∠CAD + ∠BAC = 90° (complementary)

The distance between car A and the airplane is changing at a rate of 148.38 km/hr.

To better understand this answer, we can draw a sketch of the scenario and label the variables accordingly.

Let x represent the horizontal distance from P to the airplane, y the vertical distance from P to car A, and z the altitude of the airplane. The equation that relates the distance from car A to the plane can be written as:

[tex]d^2 = (x^2 + y^2 + z^2)[/tex]

We can use implicit differentiation to solve for the derivative of this equation with respect to time, which answers the “how fast” question. The derivative of the equation is:

x = 185t (horizontal distance from P to airplane)

y = 15 - 55t (vertical distance from P to car)

z = 2 (altitude of airplane)

Now we can substitute these expressions into our equation for the distance between the car and the airplane, and take the derivative with respect to time:

distance between car and airplane = sqrt((185t)^2 + (15 - 55t)^2 + 2^2)

d/dt(distance between car and airplane) = d/dt(sqrt((185t)^2 + (15 - 55t)^2 + 2^2))

= 1/2 * (185^2 * 2t + (15 - 55t)(-55)) / sqrt((185t)^2 + (15 - 55t)^2 + 2^2)

Evaluating this expression at t = 0 (the time when the car is at its closest point to the airplane), we get:

d/dt(distance between car and airplane) = 1/2 * (185^2 * 2(0) + (15 - 55(0))(-55)) / sqrt((185(0))^2 + (15 - 55(0))^2 + 2^2)

= 1/2 * (-825) / sqrt(15^2 + 2^2)

= -412.5 / sqrt (229)

The negative sign indicates that the distance between the car and the airplane is decreasing, as expected. Finally, we can take the absolute value of this expression to get the speed at which the distance is changing:

d/dt (distance between car and airplane)| = 412.5 / sqrt (229) ≈ 148.38 km/hr.

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The runtime stack for dynamic scoping at the end of the block would be:

Under static scoping, the value of z in line 12 will be 7. Under dynamic scoping, the value of z in line 12 will be the value of y in line 2, which is equal to f(x+1)+1. The values of y and z in the end of the block will differ depending on the parameter passing method used.

For call-by-name, the value of y at the end of the block will be f(x+1)+1 and the value of z will be f(x+1)+1+1. For call-by-need, the value of y will be f(x+1)+1 and the value of z will be f(x+1)+1+1.

It might be instructive to draw the runtime stack for different times of the execution, but it is not strictly required. The runtime stack for static scoping at the end of the block would be:

The runtime stack for dynamic scoping at the end of the block would be:

We divide the number of boys by the total number of students (1200) and multiply by 100. Percentage of boys = (420/1200) x 100% = 35%.

To find the percentage of boys in the school, we need to subtract the number of girls from the total number of students, then divide by the total number of students and multiply by 100 to get the percentage.

Number of boys = total number of students - number of girls

Number of boys = 1200 - 780

Number of boys = 420

Percentage of boys = (number of boys / total number of students) x 100

Percentage of boys = (420 / 1200) x 100

Percentage of boys = 35

Therefore, the percentage of boys in the school is 35%.

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In a 5x5x5 cube, 125-unit cubes are formed by assembling. According to the pattern shown, nine-unit squares are painted on each of the six faces of the cube.  So the number of unit cubes that have no paint on them is 71.

     To calculate the total number of unit cubes, multiply the number of unit cubes in each dimension.

                  Thus, 5 × 5 × 5 = 125 cubic units.

      Since there are 6 faces to be painted, and each face has nine painted unit cubes, the total number of painted cubes is

                  6 × 9 = 54.

         Each painted cube has three faces painted since the cube has three faces of the same size.

          There are eight cubes on each of the edges that have three faces painted, so there are

                 8 × 12 = 96 of them that have three faces painted.

           There are 12 edge cubes in total, all of which have two painted faces, for a total of

                 12 × 2 = 24 cubes that have two painted faces.

            There are 6 center cubes in the cube, all of which have one painted face, for a total of 6 cubes with one painted face.

            Each painted cube contributes one face to the total. As a result, the number of unpainted cubes is

                 125 - 54 = 71.

       The number of unit cubes that have no paint on them is 71.

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The line [tex]12x + 6y = 432[/tex] is represented by the red line, and the line equation [tex]9x + 3y = 270[/tex]is represented by the blue line. The point where these two lines intersect is (36,0).

In mathematics, an equation is an assertion that affirms the equivalence of two factors. An algebraic equation (=) separates two sides of an equation. For instance, the assertion [tex]"2x + 3 = 9"[/tex]states that the word "2x + 3" corresponds to the number "9". The goal of solution solving is to figure out which variable(s) must still be adjusted for the equations to be true. It is possible to have simple or intricate equations, recurring or complex equations, and equations with one or more components. For example, in the equations" [tex]x^2 + 2x - 3 = 0[/tex]," the variable x is lifted to the powercell. Lines are utilised in many areas of mathematics, include algebra, arithmetic, and geometry.

To plot these lines on a graph, we first need to solve for y in terms of x for each equation.

can plot these lines

[tex]12x+6y 4326y=-12x+432y = -2x+729x+3y=2703y=9x+270y=-3x+90[/tex]

[tex]|100|_ | . | . 90|_ . | . | .80|_ . | . | .70|_ . | . | .60 |___________________________________________ 0 30 60 90 120 150 180 210 240 270 300[/tex]

The line[tex]12x + 6y = 432[/tex]is represented by the red line, and the line 9x + 3y = 270 is represented by the blue line. The point where these two lines intersect is (36,0).

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Answer:

A=100

B= 80

C=80

D=100

E=80

F=80

G=100

Step-by-step explanation:

The first term of the given sequence is 6, and the recursion formula for the remaining terms is 6, 6.333, 6.444, 6.481, 6.4938, 6.4988, 6.5007, 6.5018, 6.5024, 6.5026.

We are given a recursive formula: [tex]a_{n+1} = an + (1/3^n)[/tex] with [tex]a_{1} = 6.[/tex]

Using this formula, we can calculate the first few terms of the sequence as follows:

[tex]a_{1}= 6[/tex]

[tex]a_{2} = a_{1} + (1/3^1) = 6 + 1/3 = 6.333[/tex]

[tex]a_{3} = a_{2} + (1/3^2) = 6.333 + 1/9 = 6.444[/tex]

[tex]a_{4} = a_{3} + (1/3^3) = 6.444 + 1/27 = 6.481[/tex]

[tex]a_{5} = a_{4} + (1/3^4) = 6.481 + 1/81 = 6.4938[/tex]

[tex]a_{6} = a_{5} + (1/3^5) = 6.4938 + 1/243 = 6.4988[/tex]

[tex]a_{7} = a_{6} + (1/3^6) = 6.4988 + 1/729 = 6.5007[/tex]

[tex]a_{8} = a_{7} + (1/3^7) = 6.5007 + 1/2187 = 6.5018[/tex]

[tex]a_{9} = a_{8} + (1/3^8) = 6.5018 + 1/6561 = 6.5024[/tex]

[tex]a_{10} = a_{9} + (1/3^9) = 6.5024 + 1/19683 = 6.5026[/tex]

Therefore, the first 10 terms of the sequence are: 6, 6.333, 6.444, 6.481, 6.4938, 6.4988, 6.5007, 6.5018, 6.5024, 6.5026.

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Answer: 30 cm^2.

Step-by-step explanation:

Let the original length of the rectangle be l and its width be w. Then, according to the problem:

(l - 4) = (w + 5) (equation 1)

Also, the area of the square is 40 cm^2 more than the area of the rectangle. Mathematically, we can represent this as:

(l - 4 + 5)^2 = lw + 40

Simplifying the left-hand side and substituting equation 1, we get:

l^2 - 2lw + w^2 = lw + 40

l^2 - 3lw + w^2 - 40 = 0

(l - 8)(l - 5) = 0

Therefore, l = 8 or l = 5. If we substitute l = 8 into equation 1, we get:

w = (l - 4) - 5 = -1

This is not a valid solution since the width cannot be negative. Therefore, the only valid solution is l = 5, which gives:

w = (l - 4) + 5 = 6

So the area of the rectangle is:

A = lw = 5 x 6 = 30 cm^2.

Answer:

steps explanations: x - 4 = y + 5 (sides of a square)

(x - 4)(y + 5) = 40

Which gives;

(y + 5) (y + 5) = 40

y² + 10y + 25 = 40

y² + 10y + 25 - 40 = 0

y² + 10y - 15 = 0

a=1 b=10 and c=-15

Mr. Ferrell can cut 6 and 2/3 pieces that are one-eighth foot long from a 5/6 foot long piece of cardboard.

A number is said to be a common factor if it can divide two or more integers without producing a residue. Common factors are used in fraction operations to simplify fractions and carry out operations like addition, subtraction, multiplication, and division.

Finding a common denominator is necessary, for instance, when adding or subtracting fractions. A multiple of all the fractions' denominators is referred to as a common denominator. We can determine the shared characteristics of the denominators and utilise the lowest common multiple (LCM) as the common denominator to obtain a common denominator.

Given that, one-eighth foot long pieces can be cut from a 5/6 foot long piece of cardboard.

First, we need to convert 5/6 feet into eighths of a foot:

5/6 feet = (5/6) * 8 eighths = 40/48 eighths

Next, we need to divide 40/48 by 1/8 to find the number of one-eighth foot long pieces that can be cut:

(40/48) ÷ (1/8) = (40/48) * (8/1) = 320/48 = 6 2/3 pieces

Hence, Mr. Ferrell can cut 6 and 2/3 pieces that are one-eighth foot long from a 5/6 foot long piece of cardboard.

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The purchaser rejects 26.01% of the lots that contain five or more defective components, and the conditional probability of having four defective components given that the lot was rejected is 0.1653.

The percentage of defective lots that the purchaser rejects can be found by using the given formula. We can also calculate the conditional probability of having four defective components, given that the lot was rejected. Here's how to do it.

Let p be the probability that any component is defective. Then the probability that any component is non-defective is 1-p.

According to the given data, a lot is rejected if and only if there are at least five defective components in it. Let q be the probability that a lot is defective, i.e. the probability that there are five or more defective components in a lot.

Then, q = P(X ≥ 5), where X is the number of defective components in the lot. We can find the probability of rejecting a lot by subtracting the probability of accepting the lot from 1. So, we have:

P(reject) = 1 - P(accept)

P(accept) = P(X ≤ 4)

Now, we need to find q. We can do this by using the binomial distribution:

[tex]P(X = k) = C(n, k) * pk * (1-p)n-k[/tex]

where C(n, k) is the number of ways to choose k items out of n items. Here, n = 20 (the number of components in a lot). So,

[tex]q = P(X \geq  5) = 1 - P(X\leq  4) = 1 - [P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)][/tex]

[tex]q = 1 - [C(20, 0) * p0 * (1-p)20-0 + C(20, 1) * p1 * (1-p)20-1 + C(20, 2) * p2 * (1-p)20-2 + C(20, 3) * p3 * (1-p)20-3 + C(20, 4) * p4 * (1-p)20-4][/tex]

[tex]q = 1 - [1 * p0.2 * (1-0.2)20-0 + 20 * p0.2 * (1-0.2)20-1 + 190 * p0.2 * (1-0.2)20-2 + 1140 * p0.2 * (1-0.2)20-3 + 4845 * p0.2 * (1-0.2)20-4][/tex]

[tex]q = 0.2601[/tex] (rounded to four decimal places)

So, the purchaser rejects 26.01% of the lots that contain five or more defective components.

Now, we need to find the conditional probability that a lot contained four defective components given that it was rejected. Let R be the event that a lot is rejected, and let F be the event that a lot contains four defective components.

Then, we have to find P(F | R), the conditional probability of F given R. We can use Bayes' theorem to find this:

P(F | R) = P(R | F) * P(F) / P(R)

where P(R | F) is the probability of rejecting a lot given that it contained four defective components, P(F) is the prior probability of a lot containing four defective components, and P(R) is the overall probability of rejecting a lot.

[tex]P(F) = C(20, 4) * p4 * (1-p)20-4 = 0.186[/tex]

[tex][tex]P(R) = P(X \geq  5) = q = 0.2601[/tex][/tex]

[tex]P(R | F) = P(X \geq  5 | X = 4) = P(X = 5) / P(X = 4) = C(20, 5) * p5 * (1-p)20-5 / C(20, 4) * p4 * (1-p)20-4[/tex]

[tex]P(R | F) = 0.2308[/tex]

So, we have:

[tex]P(F | R) = P(R | F) * P(F) / P(R)[/tex]

[tex]P(F | R) = 0.2308 * 0.186 / 0.2601[/tex]

[tex]P(F | R) = 0.1653[/tex] (rounded to four decimal places)

Therefore, the conditional probability of having four defective components given that the lot was rejected is 0.1653.

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Answer:

a) We can use the given data to find the rate of change (slope) of the expenses over one year, and then use it to write the equation of a line in slope-intercept form:

Slope m = (Total Expenses in 2021-2022 - Total Expenses in 2020-2021) / 1 year

m = (23,500 - 21,211) / 1 = 2,289

Using the point-slope form of a line, we can write the equation as:

y - 21,211 = 2,289(t - t1), where t1 is the year 2020-2021.

Simplifying, we get:

y = 2,289t + 18,922

b) To estimate the Total Expenses for your first year of school, you need to know what year you will start. Let's say you will start in 2024-2025, which is 3 years from 2021-2022.

Then, plugging in t = 3 into the equation we just found, we get:

y = 2,289(3) + 18,922 = 23,789

So the estimated Total Expenses for your first year of school would be $23,789.

c) The graph of the function y = 2,289t + 18,922 is a straight line with a positive slope of 2,289. It passes through the point (0, 18,922) on the y-axis, and it will extend indefinitely in both directions.

d) The y-intercept of the graph is the point (0, 18,922), which represents the Total Expenses for the year 2020-2021. There are no vertical asymptotes, but the graph will approach a horizontal asymptote as t goes to infinity, since the expenses cannot increase indefinitely. The domain of the function is all real numbers, and the range is all values greater than or equal to 18,922. As t increases, the function increases without bound, so the end behavior is that the graph goes up to the right.

The given function f(x) = -11cos(πx/48 - 5π/12) + 28 models the height of water at point B between two locks, where x is the time in minutes beginning at 8:00 a.m.

The amplitude of the cosine function is 11, and the vertical shift is 28. The argument of the cosine function has a period of 96 minutes, which means that the function repeats itself every 96 minutes.

Therefore, the maximum water height at B is 39 feet and occurs at x = 120 minutes (10:00 a.m.), while the minimum water height at B is 17 feet and occurs at x = 0 minutes (8:00 a.m.). These heights occur because the cosine function attains its maximum value at x = 120 minutes and its minimum value at x = 0 minutes.

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Answer:

he cost to raise a child from birth to 17 years in a household is $194119.

Step-by-step explanation:

Important information:

The equation y = 1.55x + 110,419

The annual incoem is $54,000

Calculation of the cost:

y = 1.55(54,000) + 110419

y = 83700 + 110419

y = $194119

Answer:Write a equation for a parabola with a focus at (-2,5) and a directrix at x=3 format: x=

Step-by-step explanation:

A) The solution of the system x-y = 7, x+y = 5 is (6, -1)

B) The solution of the system 2x+5y = 3,  -2x-y= 5 is (-16/3, 13/3)

A) To solve by the elimination method , we add the left-hand sides and right-hand sides of the two equations separately, as follows,

(x - y) + (x + y) = 7 + 5

2x = 12

x = 6

(x + y) - (x - y) = 5 - 7

2y = -2

y = -1

Therefore, the solution to the system is (x, y) = (6, -1).

B) To solve by the method of elimination, we can multiply the first equation by 2 to eliminate the x term, as follows,

2x + 5y = 3

-4x - 2y = 10

Adding these two equations, we get,

3y = 13

y = 13/3

Substituting y = 13/3 into the first equation, we get,

2x + 5(13/3) = 3

2x = -32/3

x = -16/3

Therefore, the solution to the system is (x, y) = (-16/3, 13/3)

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The given question is incomplete, the complete question is:

Solve each of the following systems by the Method of Elimination A) x-y = 7, x+y = 5 B)  2x+5y = 3,  -2x-y= 5

Answer:

Step-by-step explanation:

so their is probably about 20 or 10 marbles in each bag so if they take them just kinda subtract the amount each kid got to see how many were left for emila to get I think that’s how you do if not then I was happy to help and I hope you get better help

The system of inequalities of the company with the better offer is 75 + 20x ≤ y and 15 + 65x ≤ y

Let's use A to represent the total cost (in dollars) of purchasing a pool membership from the Aquatics Club,

Let S represent the total cost of purchasing a pool membership from the Swimming Hole.

Then we can write the following system of inequalities:

A = 75 + 20x (total cost of Aquatics Club membership)

S = 15 + 65x (total cost of Swimming Hole membership)

Alfonso has no more than y dollars to spend

So, we have

75 + 20x ≤ y

15 + 65x ≤ y

Hence, the system is 75 + 20x ≤ y and 15 + 65x ≤ y

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