A certain frictionless simple pendulum having a length l and mass m swings with period t. If both l and m are doubled, what is the new period?.

Answers

Answer 1

If l and m both are doubled then the period becomes √2*T

what is a simple pendulum?

It is the one which can be considered to be a point mass suspended from a string or rod of negligible mass.

A pendulum is a weight suspended from a pivot so that it can swing freely.

Here,

A certain frictionless simple pendulum having a length l and mass m

mass of pendulum = m

length of the pendulum = l

The period of simple pendulum is:

[tex]T = 2\pi \sqrt{\frac{l}{g} }[/tex]

Where k is the constant.

Now the length and mass are doubled,

m' = 2m

l' = 2l

[tex]T' = 2\pi \sqrt{\frac{2l}{g} }[/tex]

[tex]T' = \sqrt{2}* 2\pi \sqrt{\frac{l}{g} }[/tex]

[tex]T' = \sqrt{2} * T[/tex]

Hence,

If l and m both are doubled then the period becomes √2*T

Learn more about Simple Harmonic Motion here:

https://brainly.com/question/17315536

#SPJ4


Related Questions

Motion and acceleration may only be used to refer to physical objects moving or changing speed/direction

Answers

Answer:

True

Explanation:

It is TRUE that Motion and acceleration may only be used to refer to physical objects moving or changing speed/direction.

This is because if an object is not moving or changing speed/direction to a determined point of reference, the object is considered to be at rest or motionless, thereby, with no absolute point of reference, absolute motion or acceleration cannot be distinguished.

What is the SPEED of a train that travels 15000 meters in 1200 seconds (20 minutes)?

PLEASE SHOW WORK!!!! EASY POINTS!!!!

Answers

Answer:

27.9617 mi/h

Explanation:

Speed= distance/time

S= 15000/1200

If a storm is 7.5 kilometers away, how much time is expected between observations of lightning and thunder?

Answers

Answer. Time taken to hear the thunder is : 7500 / 343 = 21.88 Seconds.

Answer:

≈ 22 seconds

Explanation:

7,5 km = 7500 m

Speed of light 300 000 000 m/s (for lightning)

Speed of sound 343 m/s (for thunder)

time = distance / speed

lightning time = 7500 m / 300 000 000 m/s = 0.000025 s

thunder time = 7500 m / 343 m/s ≈ 22 s

thunder time - lightning time = 22 s - 0.000025 s ≈ 22 s

The electrostatic force between two charged metal spheres is 2N. If the charge on each sphere is doubled, what is the new force between the spheres?

Question 2 options:
A. 2N
B. 4N
C. 1N
D. 8

Answers

Answer:

8 N

Explanation:

The force between two charges is given by :

[tex]F=\dfrac{kq_1q_2}{d^2}[/tex]

Where

k is electrostatic constant

d is the distance between two charges

It means,

[tex]F\propto \dfrac{1}{d^2}[/tex]

When the distance is d, the force is 2 N. If the charge on each sphere is doubled, q₁' = q₂' = 2q₁ = 2q₂. New force will becomes:

[tex]F'=\dfrac{kq_1'q_2'}{d^2}\\\\F'=\dfrac{k2q_1\times 2q_2}{d^2}\\\\F'=4\times \dfrac{kq_1q_2}{d^2}\\\\F'=4\times 2\\\\F'=8\ N[/tex]

So, the new force becomes 8N. Hence, the correct option is (d).

5. A car accelerates from 0 to 72 km/hour in 8.0 seconds. What is the car's acceleration?

Answers

Answer:

2.5 m/s

Explanation:

There are calculators online that can help you easily calculate the accerlation.

6. Suppose the resistance of your body between your right and left hands is 500,000 N. What
would be the current flowing through your body if you touched the plus and minus terminals of
a 120 V battery? The threshold of sensation for electric current through your body is about
300 PA. Would you feel the current?


HELP PLS

Answers

Explain more please (lesson)

The ability of a halogen to react with a metals to form a salt is an example of a ________________ property.

Answers

The answer is a CHEMICAL property.

what are the unique characteristics of romantic music which are not present in Original Pilipino Music (OPM)​

Answers

Answer:

ITU Sangat bermanfaaat

If a girl walks 6km due west changes directions and walk another 5km due north. Find her displacement in both magnitude and direction

Answers

Answer:

the girl's displacement in both magnitude and direction is 7.81 m at 50.2⁰ North west.

Explanation:

Given;

6km due west, and

5km due north

The magnitude of her displacement is calculated by forming a right angled triangle. The hypotenuse side of the triangle is the girl's displacement.

d² = 5² + 6²

d² = 25 + 36

d² = 61

d = √61

d = 7.81 m

The direction of the girl is calculated as;

[tex]tan \ \theta = \frac{6}{5} \\\\tan \ \theta = 1.2\\\\\theta = tan^{-1} (1.2)\\\\\theta = 50.2^0[/tex]

Therefore, the girl's displacement in both magnitude and direction is 7.81 m at 50.2⁰ North west.

how you would orient the magnets and what you would do with the magnets to achieve maximum repulsion

Answers

The orientation of the magnets that gives the strongest repulsion because these poles and facing each other that is then leaves highest flux density of the poles for a force of repulsion to be very high

A 2 kg ball is thrown down with 50J of energy from a height of 10m, what is its velocity before it strikes the ground (neglect air resistance).

Answers

Answer:

V=14

Explanation:

PE=KE

mgh=1/2mv^2

(2)(9.8)(10)=1/2(2)v^2

(radical) 196=(radical) v

V=14


Long Answer Type Questions
1 Can you differentiate between opaque, transparent and translucent objects
2 What is reflection of light?
3. What are the conditions for a shadow to be formed?
4. Prove through an experiment that light travels in straight lines.
5. What is pinhole camera? Explain its working with the help of a diagram
6. What are the main differences between a reflected image and shadows?​

Answers

(1).....opaque -object that not allow light to pass through it

we can't look through opaque objects

ex..wall

translucent... objects that all some light to pass through it

we can partially see through it

ex...coloured glass window

transparent... objects that wholly allow light to pass through it

we can clearly see through it

ex...glass of specs

(2)..the bouncing back of light from a smooth polished surface is called reflection of light

(3)/.....there must be a solid ,opaque to block light

there must be a source of light

there must be a surface to have shadow on it..

(6)...reflected images r formed by light reflection from a smooth polished surface while shadows are formed by blockage of light by an solid,opaque object...

Explanation:

we should talk here thanks

the Himalayas are the highest mountain in the world (positive)​. grammar question

Answers

Answer:

positive degree:

No other peak of the Himalayas is as high as Mount everest

what is equilibrium state​

Answers

Answer:

A state of rest or balance due to the equal action of opposing forces.

Answer:

a state of rest or balance due to the equal action of opposing forces. equal balance between any powers, influences,etc

Explanation:

what type of em waves is fm radio? And how it is used in wireless communication?​

Answers

Answer:

Radio waves are used for wireless transmission of sound messages, or information, for communication, as well as for maritime and aircraft navigation. The information is imposed on the electromagnetic carrier wave as amplitude modulation (AM) or as frequency modulation (FM) or in digital form (pulse modulation).

Explanation:

Two objects, A and B, are in contact with one another. Initially, the temperature of A is 50 °C and the temperature of B is 100 °C. 1. **The particles of which object (A or B) initially have a greater average kinetic energy? How do you know?​

Answers

Answer:

B

Explanation:

because kinetic energy is directly proportional to temperature so the hottor the object, the more kinetic energy.

what's 4 x 5
i need help with this question please

Answers

4 x 5 is equal to 20. Use a calculator it’s way faster :))

Answer:

4 × 5 = 5 + 5 + 5 + 5 = 20

Explanation:

Pick one factor and add it.

Ocean waves are hitting a beach with a frequency of 0.100 Hz. Their average wavelength is 15.0 m. What is their average speed?
What is the frequency of a pendulum that is moving at 30 m/s with a wavelength of 0.32 m?

Answers

Answer:

Average speed=1.5 m/s

Frequency of pendulum=93.75Hz

Explanation:

We are given

Frequency, [tex]f=0.100Hz[/tex]

Average wavelength =[tex]\lambda=15m[/tex]

Speed of pendulum, [tex]v=30m/s[/tex]

Wavelength, [tex]\lambda'=0.32m[/tex]

We have to find the average speed and frequency of pendulum.

We know that

Speed,[tex]v=\lambda f[/tex]

Using the formula

Average speed,[tex]v=15\times 0.1=1.5m/s[/tex]

Hence, the average speed =1.5m/s

Frequency, [tex]f=\frac{v}{\lambda'}[/tex]

Using the formula

[tex]f=\frac{30}{0.32}[/tex]

[tex]f=93.75Hz[/tex]

Hence, the frequency of a pendulum=93.75Hz

1. Compare the speed that light waves travel in air to the speed that sound waves travel in the air. How many times faster do light waves travel in air in comparison to sound waves in air?
Water-1500 meters per second
steel-5000 meters per second
Air-335 meters per second

Answers

Answer:

895522 times faster.

Explanation:

From the question given above, the following data were obtained:

Speed of sound in air (v) = 335 m/s

Speed of light in air (c) = 3×10⁸ m/s

How many times faster =.?

To obtain how many times faster light travels in air than sound, do the following

c : v => 3×10⁸ : 335

c/v = 3×10⁸ / 335

c/v = 895522

Cross multiply

c = 895522 × v

From the illustrations made above, we can see that the speed of the light in air (c) is 895522 times the speed of sound in air.

Thus, light travels 895522 times faster than sound in air.

write any four importance of pressure​

Answers

Answer:

Here is your ans

Explanation:

hope it helps you tq

A que profundidad esta nadando una persona dentro de una alberca si la presión absoluta sobre ésta es de 156kPa?

Answers

Answer:

La persona está nadando en la alberca a una profundida de 5.575 metros.

Explanation:

La presión absoluta ([tex]P_{tot}[/tex]) experimentada por la persona es la suma de la presión atmosférica ([tex]P_{atm}[/tex]) y la presión hidrostática de la columna de agua de la alberca ([tex]P_{h}[/tex]), medidas en kilopascales. Es decir,

[tex]P_{tot} = P_{atm}+P_{h}[/tex] (1)

[tex]P_{tot} = P_{atm} + \frac{\rho\cdot g \cdot z}{1000}[/tex] (2)

Donde:

[tex]\rho[/tex] - Densidad del fluido de la alberca, medida en kilogramos por metro cúbico.

[tex]g[/tex] - Aceleración gravitacional, medida en metros por segundo al cuadrado.

[tex]z[/tex] - Profundidad de la persona en la alberca, medida en metros.

Si sabemos que [tex]P_{atm} = 101.325\,kPa[/tex], [tex]\rho = 1000\,\frac{kg}{m^{3}}[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] y [tex]P_{tot} = 156\,kPa[/tex], entonces la profundidad de la persona en la alberca es:

[tex]156 = 101.325 +\frac{(1000)\cdot (9.807)\cdot z}{1000}[/tex]

[tex]54.675 = 9.807\cdot z[/tex]

[tex]z = 5.575\,m[/tex]

La persona está nadando en la alberca a una profundida de 5.575 metros.

calculate the pressure exerted on the floor when an elephant who weighs 2400N stands on one foot which has an area of 0.4m squared​

Answers

Answer:

6000pa

Explanation:

force= 2400N

area= 0.4m

pressure=?

now,

p= f/a

p= 2400/ 0.4

therefore,P=6000 pa.

state and explain the joules law​

Answers

Answer:

Joule’s law of heating states that when a current ‘i ' passes through a conductor of resistance ‘r’ for time ‘t’ then the heat developed in the conductor is equal to the product of the square of the current, the resistance and time.

H = i 2 rt

The reason behind the heat produced is the collision of the free electrons with the lattice ions or atoms while accelerating in presence of the external electric field.

we know that

volt= work done/ total charge or v = w/q

from this we get w= vq

we know that current i = q / t

so q = it

putting this in prev equation

we get w = vit

from ohms law v = ir

putting it in prev eq we get

w = irit = i2rt joule as work is stored as heat soH = I2RT Joules

if a current carrying conductor having resistance (r) gets heated by to passing of current (i) for time (t) and the heat thereby produced be H

joules law states that

H propotional to i^ 2 when r and t are constant

H propotional to r when I and t are constant

H propotional to t when r and I constant

True or false. Your weight will change on the moon

Answers

The answer to this is true
hi! i searched online, and it says an object on the moon weighs less than it does on earth, so true.

hope this helps!:)

The change in frequency of a wave as its source moves in relation to an observer.
A)
Ultrasound
B)
Frequency
C)
Doppler Effect
D)
Echo

Answers

Answer: B) Frequency

Explanation:

All weather stations have to make weather observations at the same time of the day.

True
False

Answers

Answer:

false

Explanation:

Answer:

True

Explanation:

The answer is true do not listen to the other person they will get you wrong just look at the votes between mine and the other person's (hint like my answer and rate 5 stars so other people know what to pick)

a ball rolled a velocity of 20m/s after 5s it comes to stop what is the acceleration of the ball​

Answers

Answer:

please find the attached pdf

Explanation:

3. Gather data: Use the values above to fill in the first row of the table. Then run your own experiments to fill
in the last two rows.
f
d.
d,
h.
h,
ร”
S
d
de
2.0
h;
h.
2.0
s.
2.0
S
f
2.0
15
10
30

Answers

Answer:

urjshsus uevus e survey dydvd dydvdyd d dgdv gdyr yrgdvv yth yrhvthr

Explanation:

ydgdydvd yd dv ydvr dyve dysdvdyr gdvr

Please help (choose a b or c)
(the image is attached)

In the adjacent circuit, the voltage across the terminals of the dry cell is equal to 12 V.
The value displayed by the voltmeter is:

a- 0 V
b- 12 V
c- -12 V

The two terminals that correspond to the correct connection of a voltmeter in a circuit are:

a- A and COM
b- A and V
c- V and COM​

Answers

I GEUSS A and COM is correct answer to this question

Answer:

1. (a) =0

2.(c) = v and COM

Mercury has the most eccentric (least circular) orbit of all the planets in the Solar System. At aphelion it is 0.467 AU from the Sun while at perihelion it is only 0.308 AU from the Sun. What is Mercury's orbital period in Earth-days?

Answers

Answer:

Mercury's orbital period is approximately 88 days

Explanation:

Mercury's orbit parameters given in the question are;

Mercury's aphelion distance, Rₐ = 0.467 AU

Mercury's perihelion distance, [tex]R_p[/tex] = 0.308 AU

Therefore, the average distance from Mercury to the Sun, 'a', is given as follows;

[tex]a = \dfrac{R_a + R_p}{2}[/tex]

By plugging in the values of 'Rₐ' and '[tex]R_p[/tex]', we get;

[tex]a = \dfrac{R_a + R_p}{2} = \dfrac{0.467 \, AU + 0.308 \, AU}{2} = 0.3875 \, AU[/tex]

a = 0.3875 AU

According to Kepler's third law, we have;

P² = k·a³

Where;

P = The orbital period of the plane

a = The average distance from Mercury to the Sun

k = Constant

When k = 1, we have;

P² = a³

∴ P = √(a³)

From which we have;

P = √(0.3875 AU)³ ≈ 0.241216804711 years

P ≈ 0.2412168 years

1 year = 365 days

∴ 0.241216804711 years = 0.241216804711 years × 365 days/year ≈ 88.0441337 days

0.241216804711 years ≈ 88.0441337 days ≈ 88 days

Mercury's orbital period, P ≈ 88 days.

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